24 is what percent of 40?
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The atom consists of a tiny nucleus surrounded by moving electrons. The nucleus contains protons, which have a positive charge equal in magnitude to the electron's negative charge.

The total volume of pool is:

                      1040 cubic ft.

We know that the total volume of the pool is the sum of the volume of two rectangular prism.

Hence, the volume of first rectangular prism is:

                       20×10×4=800 cubic ft.

Volume of second rectangular prism is:

                      6×4×10=240 cubic ft.

Hence, total volume of pool is:

                 800+240=1040 cubic ft.

In this geometric scenario, angles are named and classified. Angle 1 is a right angle, angle 3 is a straight angle, angles 2 and 6 are obtuse, while angles 4 and 5 are acute.

Let's name each angle in four ways and classify them:

Angle ABC (B is 90 degrees):

1 (as labeled)

∠ABC (using the vertex B)

∠CBA (using the vertex C)

∠1 (angle 1)

Classification: Right angle

Angle DEF (E is also labeled as 2):

2 (as labeled)

∠DEF (using the vertex E)

∠FED (using the vertex F)

∠2 (angle 2)

Classification: Obtuse angle

On line LN with point M (labeled as 3):

3 (as labeled)

∠LNM (using the vertex N)

∠MNL (using the vertex M)

∠3 (angle 3)

Classification: Straight angle

Angle XYZ (Y is also labeled as 4):

4 (as labeled)

∠XYZ (using the vertex Y)

∠ZYX (using the vertex Z)

∠4 (angle 4)

Classification: Acute angle

Angle KLM (L is also labeled as 5):

5 (as labeled)

∠KLM (using the vertex L)

∠MLK (using the vertex M)

∠5 (angle 5)

Classification: Acute angle

Angle RSP (S is also labeled as 6):

6 (as labeled)

∠RSP (using the vertex S)

∠PSR (using the vertex P)

∠6 (angle 6)

Classification: Obtuse angle

So, to summarize:

Right angle: 1

Obtuse angles: 2, 6

Straight angle: 3

Acute angles: 4, 5

To know more about angle:

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For a better understanding of the explanation provided here please go through the diagram in the attachment given below.

As we can see from the diagram of the congruent triangles ABC and FGH, the vertices A,B,C of [tex] \Delta ABC [/tex] correspond to the vertices F,G,H of [tex] \Delta FGH [/tex], so the corresponding sides must correspond too. Thus, AB corresponds to FG, BC corresponds to GH and CA corresponds to GF.

Now, we know that BC=10.4. Therefore, it's corresponding side GH must be 10.4 too because they are corresponding sides of a congruent triangle.

Thus, GH=10.4 is the correct answer.

All statements are true. Ratio of corresponding angles, areas, perimeters, and altitudes is 2:1. No false statement exists.

To determine which statement regarding the two triangles is NOT true, let's analyze each option step by step.

Given:

- Two triangles are similar.

- The ratio of the lengths of each pair of corresponding sides is 2:1.

Let's denote the lengths of corresponding sides in the first triangle as [tex]\( a \)[/tex], [tex]\( b \)[/tex], and [tex]\( c \)[/tex], and in the second triangle as [tex]\( 2a \)[/tex], [tex]\( 2b \)[/tex], and [tex]\( 2c \),[/tex] respectively.

A. Their corresponding angles have a ratio of 2:1.

- This statement is true because corresponding angles in similar triangles are congruent, so their ratios would indeed be 2:1.

B. Their areas have a ratio of 4:1.

- The area of a triangle is proportional to the square of the length of its sides. So if the ratio of the lengths of corresponding sides is 2:1, the ratio of their areas would be [tex]\( (2:1)^2 = 4:1 \)[/tex]. Hence, this statement is also true.

C. Their perimeters have a ratio of 2:1.

- The perimeters of triangles are directly proportional to the lengths of their sides. Since the ratio of the lengths of corresponding sides is 2:1, the ratio of their perimeters would indeed be 2:1. So, this statement is also true.

D. Their altitudes have a ratio of 2:1.

- The ratio of the altitudes of two similar triangles is equal to the ratio of their corresponding sides. So, if the ratio of corresponding sides is 2:1, the ratio of their altitudes would also be 2:1. Therefore, this statement is true.

Since all the statements are true, the correct answer is NONE.

Final answer:

The first step of rationalizing the denominator of 7√11 is to multiply both the numerator and denominator by the conjugate of the denominator.

Explanation:

The first step of rationalizing the denominator of 7√11 is to multiply both the numerator and the denominator by the conjugate of the denominator. In this case, the conjugate of √11 is -√11. Therefore, we multiply both the numerator and denominator by -√11 to get:

7√11 * -√11 = -77

√11 * -√11 = -11

So, the rationalized denominator is -11. The denominator becomes -11, and the simplified expression is:

-77 / -11 = 7

Final answer:

After rearranging the formula and solving for the interest rate, the required rate is found to be approximately 4.7%.

Explanation:

The subject of this question is finding the required annual interest rate that will grow a principal amount of $5,200 to $6,500 when compounded quarterly over five years. To solve this, we shall use the compound interest formula:

A = P(1 + r/n)^(nt)

Where:A is the amount of money accumulated after n years, including interest.

P is the principal amount (the initial amount of money).

r is the annual interest rate (decimal).

n is the number of times that interest is compounded per year.

t is the time the money is invested for, in years.

We are given:

A = $6,500

P = $5,200

n = 4 (since interest is compounded quarterly)

t = 5 years

We need to solve for r. First, we rearrange the formula to isolate r:

(1 + r/n) = (A/P)[tex]^({1/(nt))}[/tex]

Then we can insert our known values and solve for r:

(1 + r/4) = ($6,500/$5,200)^(1/(4*5))
Calculate the right-hand side:

(1 + r/4) = (1.25)[tex]^({1/20)}[/tex]
Find the 20th root of 1.25:

(1 + r/4) ≈ 1.01168
Subtract 1 from both sides:

r/4 ≈ 0.01168
Multiply both sides by 4:

r ≈ 0.04672

Convert the decimal to a percentage:
r ≈ 4.672%
Round to the nearest tenth of a percent:

r ≈ 4.7%
Therefore, the required annual interest rate to the tenth of a percent for $5200 to grow to $6500 with interest compounded quarterly for five years is approximately 4.7%.

Answer:

x + 230 ≤ 500

Step-by-step explanation:

Given,

The time for which Tom used the phone = 230 minutes,

Let he further used the mobile for x minutes,

So, the total time for which he used the phone = ( x + 230 ) minutes,

According to the question,

For the extra minutes more than 500 minutes, the mobile phone carrier charges an extra fee,

Thus, if he wants to use the phone, without going over the 500-minute limit,

Then, the total time used by him ≤ 500 minutes,

⇒ x + 230 ≤ 500

Which is the required inequality.

Final answer:

The number 4,321,109,432 rounded to the nearest ten million is 4,320,000,000,hence the correct option is B.

Explanation:

To round the number 4,321,109,432 to the nearest ten million, we need to look at the digit in the ten million's place and the digit to the right of it, which are 3 and 1, respectively. The rule for rounding is that if the digit to the right is 5 or greater, we round up.

In this case, the digit is 1, so we do not round up and the ten million's place remains unchanged.

Therefore, the answer is 4,320,000,000 (Option B), as every digit after the ten million's place is replaced with zero.

Answer:

-18^x-45x on edge

Step-by-step explanation:

sorry if this is late just letting people know in the future

Answer:

Option a.

Step-by-step explanation:

Two rectangles are similar. Height of one rectangle is 3 inches and height of second rectangle is 9 inches.

Let width of rectangles are x inches and y inches.

Then width of the second rectangle will be in the same ratio as of their heights.

[tex]\frac{x}{y} =\frac{3}{9}[/tex]

[tex]\frac{x}{y} =\frac{1}{3}[/tex] ⇒ x = [tex]\frac{y}{3}[/tex]

Now perimeter of first rectangle P₁ = 3 + 3 + x + x  = 2x + 6

Perimeter of second rectangle P₂ = 9 + 9 + y + y = 18 + 2y

Ratio of P₁ and P₂ = [tex]\frac{2x+6}{18+2y}[/tex]

                             = [tex]\frac{2(\frac{y}{3})+6}{18+2y}[/tex]   [as [tex]x=\frac{y}{3}[/tex]]

                            = [tex]\frac{\frac{(2y+18)}{3} }{(18+2y)}[/tex]

                            = [tex]\frac{2y+18}{3(18+2y)}[/tex]

Ratio of P₁ and P₂ = ([tex]\frac{1}{3}[/tex]) ⇒ P₂ = 3P₁

Therefore, Option a is the answer.

To find the surface area of a cylinder sandwiched between one cone and half of a sphere, use the sum of the cylinder's lateral surface area, the cone's lateral surface area, and half the sphere's surface area. The formula is 2πrh + πrl + 2πr², excluding the base areas where the shapes intersect.

To determine the surface area of a cylinder sandwiched between one cone and half of a sphere, you should first consider the formulas for the surface area of these individual shapes. The shapes consist of simple geometrical forms: a cylinder, a cone, and a sphere. The surface area of these shapes can be described with established formulas within the geometry:

Therefore, the final formula to calculate the total surface area of the described complex shape is the sum of the surface area of the lateral side of the cylinder, the lateral surface area of the cone, and half of the surface area of the sphere. This could be written as:
Total Surface Area = 2πrh + πrl + 2πr².

Note that you would omit the area of the circle that is common between the cylinder and the cone, as well as the area that is common between the cylinder and the half-sphere, since they are internall and not part of the external surface area.

Final answer:

A triangle with two perpendicular sides could be scalene or isosceles if the non-perpendicular sides are unequal or equal, respectively. It cannot be equilateral because equilateral triangles have no right angles.

Explanation:

If a triangle has two sides that are perpendicular to each other, it could potentially be a scalene or isosceles triangle, but it cannot be equilateral. When two sides of a triangle are perpendicular, they form a right angle. Thus, if a triangle has a right angle, it is a right triangle by definition. According to Theorem 2, if two angles of a triangle are equal, the opposite sides are equal, and the triangle is isosceles.

In our case, this theorem would apply if the two non-perpendicular sides are of equal length, resulting in an isosceles right triangle. On the other hand, Theorem 3 states that in a triangle with unequal angles, the side opposite the greater of the angles is greater than the side opposite the smaller. Therefore, if the sides forming the right angle are of different lengths, the triangle would be scalene.