2Na+Cl 2 ​ →2NaCl2, start text, N, a, end text, plus, start text, C, l, end text, start subscript, 2, end subscript, right arrow, 2, start text, N, a, C, l, end text How many grams of \text{NaCl}NaClstart text, N, a, C, l, end text will be produced from 18.0 \text{ g}18.0 g18, point, 0, start text, space, g, end text of \text{Na}Nastart text, N, a, end text and 23.0 \text{ g}23.0 g23, point, 0, start text, space, g, end text of \text{Cl}_2Cl 2 ​ start text, C, l, end text, start subscript, 2, end subscript?

Answer : The pH of the solution will be less than 7.

Explanation :

pH : It is defined as the negative logarithm of hydrogen ion or hydronium ion concentration.

Mathematically,

[tex]pH=-\log [H^+][/tex]

As per question, if there is a high concentration of hydrogen ions then its pH become less than 7 and the solution will be acidic.

Hence, the pH of the solution will be less than 7.

Answer:

low

Explanation:

The properties of elements and compounds.

2. A compound is either molecular or ionic in nature.

3. Most molecular compounds are composed of two or more atoms.

4. Molecules consisting of two atoms are diatomic molecules.

5. The chemical formula of a molecular compound is a molecular formula.

6. Molecular compounds tend to have low melting and boiling points.

7. Ionic compounds tend to have high melting and boiling points.

8. A molecular formula shows how many atoms of each element a molecular contains, but it does not indicate the structure of the molecule.

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Final answer:

The balanced chemical equation for the reaction between fluorine gas and aqueous iron (II) iodide is F₂ + 2 FeI₂ → 2 FeF₂ + I₂, indicating the direct combination of these substances to form new products.

Explanation:

The reaction between fluorine gas and aqueous iron (II) iodide to produce aqueous iron (II) fluoride and iodine liquid can be represented as a balanced chemical equation. When writing a balanced chemical equation, it is vital to ensure that the number of atoms of each element on the reactants side is equal to the number of atoms of that element on the products side, adhering to the law of conservation of mass.

The correct balanced chemical equation for this reaction is:

F₂ + 2 FeI₂ → 2 FeF₂ + I₂

Here, one mole of fluorine gas reacts with two moles of iron (II) iodide to produce two moles of iron (II) fluoride and one mole of iodine.

Explanation:

the answer and explanation is in the picture

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A student finds that 4700 J of heat are required to raise the temperature of 250.0 g of metal X from 22°C to 63°C. 0. 459J/g/C  is the identity of metal X.

The amount of heat required to raise the temperature of one gram of a substance by one Celsius degree is defined as specific heat.

Heat capacity, also known as specific heat, is the amount of heat required per unit mass to raise the temperature by one degree Celsius.

Specific heat is useful in determining processing temperatures and the amount of heat required for processing, as well as in distinguishing between two polymeric composites.

The specific heat capacity of a substance is typically determined by measuring the heat capacity of a sample of the substance, usually with a calorimeter, and dividing by the sample's mass.

Given:

Heat = 4700 J

M = 250.0 g

T = 63 - 22 = 41°C

4700 = 250 ×C× 41

4700 = 10250 × C

C = 459J/g/C

Thus, A student finds that 4700 J of heat are required to raise the temperature of 250.0 g of metal X from 22°C to 63°C. 0. 459J/g/C  is the identity of metal X.

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Answer:

The goal is to remove both heavy solids and floating oils

Explanation:

Primary treatment consists of temporarily holding the sewage in a quiescent basin where heavy solids can settle to the bottom while oil, grease and lighter solids float to the surface. The settled and floating materials are removed and the remaining liquid may be discharged.

Answer:

Explanation:

Chlorite anion, ClO₂⁻ has one atom of chlorine and two atoms of oxygen.

Chlorine atom has 7 valence electrons (group 17 of the periodic table) and oxygen has 6 valence electrons (group 16 of the periodic table).

Thus, in total the anion has 7 + 6×2 electrons, plus an additional electron indicated by the negative charge of the anion: 7 + 12 + 1 = 20 valence electrons, that must be distributed among the three atoms.

Being chlorine the most electronegative atom, you place it in the center. surrounded by the two oxygen atoms.

Thus, so far:

             O Cl  O (pending to place the valence electrons.

You can put two electrons between each chlorine and oxygen atoms to form the bonds:

     O : Cl : O

Also, complete the octets:

 . .      . .    . .

: O  :  Cl :  O :

 . .     . .     . .

That structure works because:

But you need to calculate the formal charges on each atom:

For chlorine:

For each oxygen:

The total charge of the anion is +1 -1 - 1 = -1.

And the complete structure with the charge is:

   . .      . .    . .

[ : O  :  Cl :  O : ] ⁻

   . .      . .     . .

The square bracketts comprise the entire anion and the negative charge is for the entire structure.

In this structure, the central atom (Cl) is surrounded by two bonding and two unshared pairs of electrons. (this is the answer to the question).

There is another structure which minimizes the formal charge, which will be preferred. It is by making a double bond between chlorine and one of the oxygen atoms, by moving two of the atoms beside one chlorine.

That structure is:

 . .      . .    . .

: O  :  Cl ::  O

 . .     . .     . .

There you have 20 valence electrons and complete octets too, but the formal charges are:

Chlorine:

The oxygen on the left is equal to the previous structure, thus - 1 forma charge.

The oxygen on the right:

Hence, this las structure minimizes the formal charges and is preferred.

This is:

 . .      . .    . .

: O  :  Cl ::  O

 . .     . .     . .  

But you must add the negative charge which belongs to the complete anion:

      . .      . .     . .

[     : O  :  Cl ::  O  ] ⁻

      . .     . .      . .

The square brackets comprise the entire anion and the negative charge is for it.

Hence, in this other structue the central atom, chlorine, is surrounded by six bonding electrons and four nonbonding electrons.

Answer:

The average atomic mass of an element is the sum of the masses of its isotopes, each multiplied by its natural abundance

Explanation:

To determine the average atomic mass, we require abundance of every isotope in the nature.

Average atomic mass is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Answer:

0.178 moles of oxygen gas molecules were collected.

Explanation:

Pressure at which oxygen gas collected = p= 1.00 atm

Vapor pressure of the water [tex]p'=34.5 Torr=\frac{34.5}{760} atm=0.0454 atm[/tex]

Pressure of the oxygen gas = P

p = p' + P

[tex]1.00 atm =0.0454 atm+P[/tex]

P = 1.00 atm -  0.0454 atm = 0.9546 atm

Volume of the oxygen gas = V = 4.56 L

Moles of oxygen gas = n

Temperature at which gas collected = T = [tex]25^oC=273+25=298 K[/tex]

[tex]PV=nRT[/tex] (ideal gas)

[tex]n=\frac{PV}{RT}=\frac{0.9546 atm\times 4.56 L}{0.0821 atm L/mol K\times 298 K}=0.178 mol[/tex]

0.178 moles of oxygen gas molecules were collected.

Answer: The change in entropy that occurs in the system is 36.3 J/Kmol

Explanation:

Given : 1 mole of isopropyl alcohol gives heat = 5.37 kJ

Thus 1.24 moles of isopropyl alcohol gives heat = [tex]\frac{5.37}{1}\times 1.24=6.66 kJ[/tex]

To calculate the temperature , we use the equation:

[tex]\Delta S_f=\frac{\Delta H_{f}}{T}[/tex]  

where,  

[tex]\Delta S_f[/tex] = Entropy of fusion = ?

[tex]\Delta H_{f}[/tex] = enthalpy of fusion  = 6.66 kJ/mol = 6660 J/mol     (1kJ=1000J)

T = melting point = [tex]-89.5^0C=(273-89.5)K=183.5K[/tex]

[tex]\Delta S_f=\frac{6660J/mol}{183.5K}=36.3J/Kmol[/tex]

Thus the change in entropy that occurs in the system is 36.3 J/Kmol

Answer:A

Explanation:Henry’s Law

Final answer:

Pressure has very little effect on the solubility of solids or liquids, but has a significant effect on the solubility of gases.

Explanation:

Pressure has very little effect on the solubility of solids or liquids, but has a significant effect on the solubility of gases. Gas solubility increases as the partial pressure of a gas above the liquid increases. For example, when carbonated beverages are packaged, they are done so under high CO₂ pressure so that a large amount of carbon dioxide dissolves in the liquid. When the bottle is open, the equilibrium is disrupted because the CO₂ pressure above the liquid decreases, causing bubbles of CO₂ to rapidly exit the solution and escape out of the top of the open bottle.

Answer:

Your question is incomplete.

But what I can help you with is once a redox reaction occurs, one element oxidizes and another is reduced, generating the equilibrium of the reaction.

On the other hand, it is important to clarify all the redox reactions, reactions of reducing factors (positive protons) and oxygen that oxidize.

Explanation:

example:

Reduction half-reaction: {2 e ^ - + Cu ^ 2 + -> Cu} {2 e ^ - + Cu ^ 2 + -> Cu}

Half oxidation reaction: {Fe -> Fe ^ 2 + + 2 e ^ -} {Fe -> Fe ^ 2 + + 2 e ^ -}

or more frequently, also called general equation:

{Fe + Cu ^ 2 + -> Fe ^ 2 + + Cu} {Fe + Cu ^ 2 + -> Fe ^ 2 + + Cu}

Answer:

178.98 sq. feet

Explanation:

The path and the garden has been shown in the figure below. The green area is the garden and the area in brown is the path.

It has been given that,

Radius of garden = 8 feet

So, the area of garden = 3.14 × 8 × 8 = 200.96 sq. feet

The total radius of the land including garden and path = 8 + 3 = 11 feet

So, the total are of land including garden and path = 3.14 × 11 × 11 = 379.94 sq. feet

So, the area of path = Total area of the land - area of garden

Area of path = 379.94 - 200.96 = 178.98 sq. feet

Answer:

c 178.98 ft

Explanation:

Answer:

Nuclear energy

Explanation:

hope this helps

Answer:

For the first one it is x=π/3+2πn and 2π/3+2πn and for the second one it is π/2

Explanation:

Answer:

D

Explanation:

Matter are anything that is made up of atoms. The quantity of matter can be observed only on the basis of mass and volume calculation. Therefore, the correct option is option D.

Matter is a substance that has some mass and can occupy some volume. The matter is mainly used in science. Matter can be solid, liquid or gas.

Matter is anything that is made up of atoms. Anything around us that can be physically seen and touched are matter. Ice, water and water vapors are example of matter.

So as we saw that matter has some mass so mass can be measured in gram only. Mass can also be represented as number of molecules. We also saw that matter occupy some volume and that volume is measured only in liter.  Chemical property is a characteristic of matter that describes its ability to change into a different substance.

Therefore, the correct option is option D.

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Answer: Radioactivity

Explanation:

To calculate the pH of a 0.107 M NaHA solution, where HA is part of a diprotic acid with given Ka values, HA^-− dissociates in water according to its first ionization step. The pH is determined using the Ka1 value and is calculated to be approximately 1.80.

To calculate the pH for a 0.107 M solution of NaHA, where HA is a diprotic acid (H2A), given Ka1 = 2.3× 10–4 and Ka2 = 3.0× 10–12, we first need to consider what happens when NaHA dissolves in water.

NaHA will dissociate to form NA+ and HA−. Since the concentration of NaHA is relatively high and Ka1 is significantly greater than Ka2, we can assume that the HA− will primarily dissociate according to the first ionization step, while the second ionization can be neglected in this approximation.

The ionization can be represented as:
HA−(aq) + H2O(l) → A2−(aq) + H3O+(aq).

Writing the expression for Ka1 we have:
Ka1 = [H3O+][A2−]/[HA−].
Assuming that [H3O+] = [A2−], we can simplify this to:
Ka1 = [H3O+]^2/[HA−].

Rearranging and solving for [H3O+], we get:
[H3O+] = √(Ka1 × [HA−]). Substituting the given values in:
[H3O+] = √(2.3× 10–4 × 0.107) = √(2.461× 10–4) ≈ 1.57× 10–2.

Using the formula for pH, pH = -log[H3O+], we find:
pH = -log(1.57× 10–2) ≈ 1.80.

Thus, the pH of the 0.107 M NaHA solution is approximately 1.80.

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The pH of a 0.107 M solution of NaHA, derived from the diprotic acid H₂A, is calculated to be approximately 6.24.

To calculate the pH of a 0.107 M solution of NaHA, a salt derived from the diprotic acid H₂A, we will consider that NaHA will primarily exist as HA⁻ in the solution. This involves both the first and second ionization constants of the diprotic acid.

Given:

Step-by-step calculation:

Ka₂ = [H⁺][A²⁻] / [HA⁻]

Assume the initial concentration of HA⁻ is approximately equal to the initial concentration of NaHA (0.107 M) as the dissociation is minimal. Let the change in concentration be 'x.'

Hence:

Ka₂ = 3.0 × 10⁻¹² = (x)(x) / (0.107 - x) ≈ x² / 0.107

Solving for 'x':

x = [H⁺] = √(Ka₂ × 0.107) = √(3.0 × 10⁻¹² × 0.107) ≈ 5.7 × 10⁻⁷ M

pH = -log[H⁺] = -log(5.7 × 10⁻⁷) ≈ 6.24

Therefore, the pH of a 0.107 M solution of NaHA is approximately 6.24

Answer:

It is higher than that of water

Explanation:

Because we now know that through experimentation, the new compound has a higher and stronger hydrogen bonds than water, the specific heat capacity will be higher.

Specific heat capacity is the amount of heat needed to raise the temperature of a unit mass of as substance by 1°C.

Answer:

It is higher than that of water

Explanation:

i just finnished the quiz

Answer:

1,3,6

Explanation:

Answer:

1,3,6

Explanation:

If the water molecule was linear instead of bent the water would no longer produce hydrogen bonds.

Explanation:

Answer:

2 and 3 are correct

Explanation:

Answer:

if multiple choice e. d. a. if not e.

Explanation:

Answer : The partial pressure of [tex]H_2[/tex] at equilibrium is, 1.0 × 10⁻⁶

Explanation :

The partial pressure of [tex]HBr[/tex] = [tex]1.0\times 10^{-2}atm[/tex]

The partial pressure of [tex]H_2[/tex] = [tex]2.0\times 10^{-4}atm[/tex]

The partial pressure of [tex]Br_2[/tex] = [tex]2.0\times 10^{-4}atm[/tex]

[tex]K_p=4.2\times 10^{-9}[/tex]

The balanced equilibrium reaction is,

                                [tex]2HBr(g)\rightleftharpoons H_2(g)+Br_2(g)[/tex]

Initial pressure    1.0×10⁻²       2.0×10⁻⁴      2.0×10⁻⁴

At eqm.            (1.0×10⁻²-2p)   (2.0×10⁻⁴+p)  (2.0×10⁻⁴+p)

The expression of equilibrium constant [tex]K_p[/tex] for the reaction will be:

[tex]K_p=\frac{(p_{H_2})(p_{Br_2})}{(p_{HBr})^2}[/tex]

Now put all the values in this expression, we get :

[tex]4.2\times 10^{-9}=\frac{(2.0\times 10^{-4}+p)(2.0\times 10^{-4}+p)}{(1.0\times 10^{-2}-2p)^2}[/tex]

[tex]p=-1.99\times 10^{-4}[/tex]

The partial pressure of [tex]H_2[/tex] at equilibrium = (2.0×10⁻⁴+(-1.99×10⁻⁴) )= 1.0 × 10⁻⁶

Therefore, the partial pressure of [tex]H_2[/tex] at equilibrium is, 1.0 × 10⁻⁶

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Answer:

The air pressure is significantly less than 1 atm, so the boiling point of water is much lower than at sea level.

Explanation:

This has to do with Gay Lussac's Law (a.k.a pressure law) which in essence means that when pressure goes up, temperature goes up and when pressure decreases, temperature decreases. This is why when the air pressure is signifcantly less than 1 atm (the pressure at sea level), the boiling point of water is much lower than at sea level.

The best explanation for the scenerio is :  High in the mountains , the air pressure is significantly less than 1 atm, so the boiling point if water is much lower than at sea level.

The higher you go above sea level the lower the air pressure and this will significantly affect the temperature at which certain liquids ( water ) will boil. therefore the boiling point of water will be  much lower than at sea level.

In this scenerio the application of Gay Lussac's law comes in

Gay Lussac's law states that the pressure of gas is directly proportional to its temperature at constant volume

Hence we can conclude that The best explanation for the scenerio is :  High in the mountains , the air pressure is significantly less than 1 atm, so the boiling point if water is much lower than at sea level.

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Answer: Sufficient amount of energy and appropriate orientation.

Explanation:

A chemical reaction is most likely to occur when reactant particles collide with sufficient amount of energy needed to break bonds and

appropriate orientation .

Answer:

There are 0.100 moles chlorine ions (Cl-) involved

Explanation:

Step 1: Data given

Volume of CaCl2 = 25.0 mL = 0.025 L

Molarity of CaCl2 = 2.00 M

Step 2: The balanced equation

CaCl2 (aq) + 2AgNO3 (aq) ⇆ Ca(NO3)2 (aq) + 2AgCI (s)

CaCl2 → Ca^2+ + 2Cl-

Step 3: Calculate moles CaCl2

Moles CaCl2 = molarity CaCl* volume

Moles CaCl2 = 2.00 M * 0.025 L

Moles CaCl2 = 0.050 moles

Step 4: Calculate moles chloride ions

CaCl2 → Ca^2+ + 2Cl-

For 1 mol CaCl2 we have 1 mol Ca^2+ and 2 moles Cl-

Moles Cl- ions = 2*0.050 moles

Moles Cl- ions = 0.100 moles

There are 0.100 moles chlorine ions (Cl-) involved

The reaction of 25.0 mL of a 2.00 M CaCl2 solution provides 0.100 moles of chloride ions for the reaction, based on the stoichiometry that shows each mole of CaCl2 gives two moles of chloride ions.

To calculate how many moles of chloride ions were involved in the reaction where 25.0 mL of a 2.00 M CaCl2 solution is used, we must first understand the stoichiometry of the reaction:

CaCl2(aq) + 2AgNO3(aq) → Ca(NO3)2(aq) + 2AgCl(s)

From the balanced equation, we see that each mole of CaCl2 provides two moles of Cl− ions. To find the moles of CaCl2, we use the concentration and volume of the solution:

(2.00 moles/L) × (0.025 L) = 0.050 moles of CaCl2

Since there are two moles of Cl− for every mole of CaCl2, we multiply the moles of CaCl2 by 2:

0.050 moles × 2 = 0.100 moles of chloride ions

Answer:

a) ΔG = 1688.5 J/mol = 1.7  kJ/mol

b) ΔG = 21673.3  J/mol = 21.7  kJ/mol

Explanation:

Step 1: Data given

Temperature = 20.0 °C = 293 K

Initial temperature = 1.0 bar = 0.986923 atm

Final temperature = 2.0 bar = 1.97385 atm

Step 2: Calculate

ΔG = RT * ln (Pt / Pi)

⇒with R = 8.314 J/K* mol

⇒with T = 293K

⇒with Pt = final pressure = 1.97385 atm

⇒with Pi = the initial pressure = 0.986923 atm

ΔG = 8.314 J/mol*K *293 K * ln (1.97385/0.986923)

ΔG = 8.314 J/mol*K *293 K * 0.693

ΔG = 1688.5 J/mol = 1.7  kJ/mol

(b) 0.000 27 atm

Step 3:

ΔG = RT * ln (Pt / Pi)

⇒with R = 8.314 J/K* mol

⇒with T = 293K

⇒with Pt = final pressure = 1.97385 atm

⇒with Pi = the initial pressure = 0.00027 atm

ΔG = 8.314 J/mol*K *293 K * ln (1.97385/0.00027)

ΔG = 8.314 J/mol*K *293 K * 8.897

ΔG = 21673.3  J/mol = 21.7  kJ/mol

The molar Gibbs energy change of carbon dioxide at 20°C when its pressure is changed from 1.0 bar to 2.0 bar is 4.08 kJ/mol, and when changed from 1.0 bar to 0.00027 atm is -34.65 kJ/mol.

The molar Gibbs energy change of a substance can be calculated using the equation ΔG = RT ln(Pf/Pi), where ΔG is the change in molar Gibbs energy, R is the universal gas constant, T is the absolute temperature, Pf is the final pressure, and Pi is the initial pressure.

Given that temperature (T) is 20°C or 293.15 K, R is 8.314 J/K/mol (universal gas constant), Pi is 1.0 bar, and the pressures Pf are (a) 2.0 bar and (b) 0.00027 atm respectively. We also note that 1 bar is roughly equivalent to 0.986923 atm.

(a) When Pf is 2.0 bar, ΔG = (8.314 J/K/mol)*293.15 K*ln(2.0/1.0) = 4.08 kJ/mol.

(b) When Pf is 0.00027 atm, ΔG = (8.314 J/K/mol)*293.15 K*ln(0.00027/0.986923) = -34.65 kJ/mol.

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