The solutions for the equation 2x^2 + 9x + 8 = 0 are x = (-9 + √17)/(4) and x = (-9 - √17)/(4), which are approximately 0.44 and -4.94, respectively.
Explanation:To solve the equation 2x^2 + 9x + 8 = 0, we can use the quadratic formula. The quadratic formula states that the solutions for any quadratic equation of the form ax^2 + bx + c = 0 can be calculated using the formula:
x = (-b ± √(b^2 - 4ac))/(2a)
For the given equation, a = 2, b = 9, and c = 8.
Plugging these values into the formula, we get:
x = (-9 ± √(9^2 - 4*2*8))/(2*2)
Simplifying, we have:
x = (-9 ± √(81 - 64))/(4)
x = (-9 ± √17)/(4)
So, the solutions for the equation 2x^2 + 9x + 8 = 0 are x = (-9 + √17)/(4) and x = (-9 - √17)/(4), which are approximately 0.44 and -4.94, respectively.
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A worm travels 1250 mm how many meters did the worm
In △ABC, point M is the midpoint of AC , point D∈ BM so that MD:DB=1:4. If ACMD=7 ft2, find ABDC, AAMB, and AABC.
Note that
[tex]A_{CMD}=\dfrac{1}{2}\cdot MC\cdot h=7\ sq. ft.[/tex]
Let H be the height of triangle ABC. Since [tex]\dfrac{MD}{DB}=\dfrac{1}{2},[/tex] then
[tex]\dfrac{H}{h}=\dfrac{5}{1}, \\ \\H=5h.[/tex]
1.
[tex]A_{BDC}=A_{MBC}-A_{CMD}=\dfrac{1}{2}\cdot MC\cdot H-\dfrac{1}{2}\cdot MC\cdot h=\dfrac{1}{2}\cdot MC\cdot (5h-h)=\\ \\=4\cdot \dfrac{1}{2}\cdot MC\cdot h=4\cdot 7=28 sq. ft.[/tex]
2. M is midpoint of AC, then AM=MC.
[tex]A_{AMB}=\dfrac{1}{2}\cdot AM\cdot H=\dfrac{1}{2}\cdot MC\cdot 5h=5\cdot \dfrac{1}{2}\cdot MC\cdot h=5\cdot 7=35\ sq. ft.[/tex]
3.
[tex]A_{ABC}=\dfrac{1}{2}\cdot AC\cdot H=\dfrac{1}{2}\cdot 2MC\cdot 5h=10\cdot \dfrac{1}{2}\cdot MC\cdot h=10\cdot 7=70\ sq. ft.[/tex]
Answer:
[tex]A_{BDC}=28\ sq. ft,\ A_{AMB}=35\ sq. ft,\ A_{ABC}=70\ sq. ft.[/tex]
Answer:
28,35,70
Step-by-step explanation:
Find the value of x and y so that both proportions will be correct:
x:1 2 /3=y:3 1/3 and y:1.5=0.2:0.75
Note that a:b = c:d is the same as a/b = c/d
y:1.5=0.2:0.75 same as y/1.5 = 0.2/0.75
y = 0.4
x: 1 2/3=y:3 1/3 same as x/1 2/3 = y / 3 1/3
x = y/2 = 0.2
y:1.5=0.2:0.75
so y=1.5*0.2/0.75=0.4
x:1 2 /3=y:3 1/3
so x=1 2/3*0.4/3 1/3=0.2
Solve the inequality. 7x − 9 > 2x + 6
We can treat inequalities like standard algebraic equations.
7x - 9 > 2x + 6
Add 9 to both sides.
7x > 2x + 15
Subtract 2x from both sides.
5x > 15
Divide both sides by 5.
x > 3
Answer:
x>3 is the answer
Step-by-step explanation:
We are given one inequality
7x-9>2x+6
To solve this we can do additions and subtraction as we do for equations.
Only for multiplication if negative number is used inequality changes
So let us add 9 to both the sides
7x>2x+6+9
Now subtract 2x from both the sides
7x-2x >15
5x>15
We divide by a positive number 5 without disturbing inequality sign.
X>3 is the answer
In interval notation we can write this as open interval
(3,∞)
In number line this is the region to the right of 3, not includig 3
A quadrilateral has vertices at A (-5, 5), B (1, 8), C (4, 2), and D (-2, -2). Use slope to determine if the quadrilateral is a rectangle. Show your work. (Try to use point slope form)
Answer:
not a rectangle
Step-by-step explanation:
There are several ways to determine whether the quadrilateral is a rectangle. Computing slope is one of the more time-consuming. We can already learn that the figure is not a rectangle by seeing if the midpoint of AC is the same as that of BD. (It is not.) A+C = (-5+4, 5+2) = (-1, 7). B+D = (1-2, 8-2) = (-1, 6). (A+C)/2 ≠ (B+D)/2, so the midpoints of the diagonals are different points.
___
The slope of AB is ∆y/∆x, where the ∆y is the change in y-coordinates, and ∆x is the change in x-coordinates.
... AB slope = (8-5)/(1-(-5)) = 3/6 = 1/2
The slope of AD is computed in similar fashion.
... AD slope = (-2-5)/(-2-(-5)) = -7/3
The product of these slopes is (1/2)(-7/3) = -7/6 ≠ -1. Since the product is not -1, the segments AB and AD are not perpendicular to each other. Adjacent sides of a rectangle are perpendicular, so this figure is not a rectangle.
___
Our preliminary work with the diagonals showed us the figure was not a parallelogram (hence not a rectangle). For our slope calculation, we "magically" chose two sides that were not perpendicular. In fact, this choice was by "trial and error". Side BC is perpendicular to AB, so we needed to choose a different side to find one that wasn't. A graph of the points is informative, but we didn't start with that.
Q # 2 i need help please
Answer: First option. The slope is -4 and the y-intercept is 2.
Solution:
y=-4x+2
When the equation is in the form:
y=mx+b (y isolated)
The coefficient of the variable "x" is the slope "m" of the right line. In this case the coefficient of "x" is -4, then the slope "m" is -4.
The indeoendent term is the y-intercept "b". In this case the independent term is +2, then the y-intercept "b" is 2.
Solution:
Given equation of line [tex]y=-4x+2[/tex].
The given equation is in the form of y=mx+b, y is isolated. So the coefficient of x is the slope of the line.
The slope of the line y=-4x+2 is -4
To find the y-intercept of the equation, substitute [tex]x=0[/tex] in the equation,
[tex]\Rightarrow y=-4(0)+2\\\Rightarrow y=2[/tex]
So, y-intercept of the equation is [tex](0,2)[/tex].
Hence, the slope is -4 and y intercept is 2. (first option)
Graph ΔRST with vertices R(6, 6), S(3, –6), and T(0, 3) and its image after a reflection over the y-axis.
under a reflection in the y-axis
a point (x, y ) → (- x, y ), thus
R(6, 6 ) → R' (- 6, 6 )
S(3, - 6 ) → S'(- 3, - 6 )
T(0, 3 ) → T'(0, 3 )
Plot the sets of points and graph them
Answer: The graph is attached below.
Step-by-step explanation: Given that the co-ordinates of the vertices of ΔRST are R(6, 6), S(3, –6), and T(0, 3).
We are given to graph ΔRST and its image after a reflection over the Y-axis.
After reflection across Y-axis, the co-ordinates of the vertices of ΔRST will follow the following transformation :
(x, y) ⇒ (-x, y), because the sign before the x-coordinates of the vertices will get reversed.
Therefore, the co-ordinates of the vertices of the image of ΔRST will be
R'(-6, 6), S'(-3, -6) and T'(0, 3).
The graphs of both the triangles, ΔRST and its image after reflection R'S'T' is drawn in the attached figure.
We see that the vertices T and T' coincide with each other.
Thus, the graph is shown below.
How do you graph these?
Answer:
See the attached.
Step-by-step explanation:
A graph of f' is a graph of the slope of the function. Your function f(x) is piecewise linear, so different sections of its graph have different constant values of slope.
In the intervals (-5, -2) and (0, 2), the slope is -1. (The graph has a "rise" of -1 for each "run" of 1.) So, in those intervals, the graph of f' looks like a graph of y=-1.
In the interval (-2, 0), the rise is 2 for a run of 2, so the slope is 2/2 = 1. The graph of f' in that interval will look like a graph of y=1.
In the interval (2, 5), the rise of f(x) is 1 for a run of 3, so the slope in that interval is 1/3. There, the graph of f' will look like a graph of y=1/3.
If you want to get technical about it, the slope is undefined at x=-2, x=0, and x=2. Therefore, the line segments that make up the graph of f' ought to have open circles at those points, indicating that f' is not defined.
Use the given conditions to write an equation for the line in point-slope form and in slope-intercept form. Passing through (minus−44,minus−88) and parallel to the line whose equation is y equals negative 3 x plus 3y=−3x+3 Write an equation for the line in point-slope form.
The equation of the line through the given point parallel to the given line ...
in point-slope formin slope-intercept formSolutionThe given line's equation is is slope-intercept form. The slope is -3, the coefficient of x.
In point-slope form, the equation of a line with slope m through point (h, k) is ...
... y -k = m(x -h)
For slope m=-3 and point (h, k) = (-4, -8) the equation of the line is ...
... y +8 = -3(x +4) . . . . equation in point-slope form
We can eliminate parentheses and add -8 to put this equation in slope-intercept form.
... y +8 = -3x -12
... y = -3x -20 . . . . equation in slope-intercept form
Answer:
Step-by-step explanation:
The answer is B
y=2x+11
For what value(s) of k will the relation not be a function?
A = {(3k−4, 16), (4k, 32)}
We won't have a function if for same value of x in (x,y) we get different values y.
So first step: figure out k so that the first coordinate (x) is the same:
3k-4=4k | solve for k
k = -4
no check the values y for the elements of the relation
x = 3k-4 = -12-4=-16
so at -16 we get (-16,16) and (-16, 32), which mean for k=-4 the relation is not a function.
Let me know if you have any questions.
Answer:
K= -4
Step-by-step explanation:
Since it isn't possible that (3k-4, 16) is going to be equal to (4k, 32) in terms of positive numbers, you will have to go to the negative side of the number line.
K has to equal 4 because 3 · -4 = -12, and -12 minus 4 is equal to -16.
And since 4 · -4 = -16, K has to equal - 4.
I need to prove that A’B’= A’D’ but i keep going in circles.
You have the figure in the picture, the hypothesis are:
AA’= (1/2)AB
BB’=(1/2)BC
CC’=(1/2)CD
DD’=(1/2)DA
These are all vectors!
It can't be proven because it isn't so.
You can show that A'B' = C'D' because each is half of AC (from the midsegment theorem).
How do u Graph Y<-1/4x-1
When you replace the comparison symbol (<) with an equal sign (=), you get the equation of a line in slope-intercept form:
... y = mx + b
where m is the slope, and b is the y-intercept.
Your equation has m = -1/4 and b = -1. To graph this line, find the point (0, -1) on the y-axis. To find another point on the line, you can use the slope value (rise/run = -1/4), which tells you the line "rises" -1 for each "run" of +4. That is, another point on the line will be 4 units to the right and 1 unit down, at (4, -2). Working in the other direction (to the left, instead of to the right), the -1/4 slope tells you the point 4 units left and 1 unit up (-4, 0) will also be on the line. Draw a dashed line through these points,
The dashed line you just drew is the boundary of the solution region. It is dashed because the line itself is not part of the solution. (Those points do not meet the requirement for "less than.")
Appropriate values of y are ones that are less than those on the line, so the solution region is indicated as being the half-plane below the line. You indicate this by shading the solution region. (See the attachment for an example of the way this can be graphed.)
_____
If the comparison is ≤ instead of <, then the line is solid (not dashed), indicating it is part of the solution region. If the comparison is > or ≥, then the shaded region is above the line, where y-values are greater than those on the line.
Graph f(x)=−23x−3 .
Lol plx i need help
Answer:
Points (0,-3) and (-3,-1) work, I got a 100% on the test.
Solve the quadratic equation. Show all of your steps.
x^2 + 3x - 5 = 0
The roots of equation are: x= -3+ √29/2 and x= -3-√29/2.
What is Quadratic Equation?Quadratic equation's roots The roots of a quadratic equation are the values of the variables that fulfil the equation. In other words, if f(a) = 0, then x = a is a root of the quadratic equation f(x). The x-coordinates of the sites where the curve y = f(x) intersects the x-axis are the real roots of an equation f(x) = 0.
given:
x² + 3x - 5 = 0
So, solving for x
x² + 3x - 5 = 0
D= (3)² - 4(1)(-5)= 9 + 20= 29
Now, using the quadratic equation
x= -b ± √ b² -4ac/ 2a
x= -3 ±√(3)² -4(1)(-5) / 2
x= -3±√29/2
x= -3+ √29/2 and x= -3-√29/2
Hence, the roots of equation are: x= -3+ √29/2 and x= -3-√29/2.
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Help ASAP plsssssssssss
answer:
1. 24
2. -6
work:
1.
[tex]5n + 3n[/tex]
[tex]5 (3) + 3 (3)[/tex]
[tex]15 + 9[/tex]
24
2.
[tex]9 (x -7) - y[/tex]
[tex]9 ( (11) -7) - 19[/tex]
[tex]9 + 4 - 19[/tex]
[tex]13 - 19[/tex]
[tex]-6[/tex]
hope this helps! ❤ from peachimin
1. How to get answer:
5(3)+3(3) (now you don't have to use parenthesis but you need to multiply these two because the n represents the times.The answer for number one would be 15 + 9 equals 24.Answer is 242. How to get answer:
9(x-7)-y (you can use the distributive property for the first one but you figured out one of two of the variables so it should look like this 9(11-7)-19=9(11-7)-19 now you can use distributive property multiply 9 times 11 which equals 99 and then multiply 9 times 7 which equals 63.Now that you have the 9 out of the way it should look like this (99-63)-19 now we can use the order of operations 99-63 equals 36.The last step should be 36 - 19 = 17.The answer is 17.what's the difference between 1968 and 3000
Hey mate!!
Answer⤵
The difference between 1,968 and 3,000 is 1,032.
3,000-1,968=1,032.
Answer confirmed= 1,032
Hope it helps you! ヅ
To find the difference between 1968 and 3000, you need to subtract the smaller number from the larger one.
Step 1: Identify the larger number. In this case, 3000 is larger than 1968.
Step 2: Subtract the smaller number from the larger number.
3000 - 1968 = 1032
So, the difference between 1968 and 3000 is 1032.
Flannery used 30 lilies and 78 roses to create six identical flower arrangements. Write an equation to describe the relationship between l, the number of lilies, and r, the number of roses.
The equation to describe the relationship between the number of lilies and roses is l/30 = r/78. This equation represents the proportion between the number of lilies and roses used in each arrangement.
Explanation:The relationship between the number of lilies (l) and the number of roses (r) can be described by the equation l/30 = r/78. This equation represents the proportion between the number of lilies and roses used in each arrangement. By setting up this proportion, we can determine the ratio of lilies to roses in each arrangement.
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write a point-slope equation for the line that passes through the point (6,8) and is parallel to the line given by y=-5x+4
Answer:
y -8 = -5(x -6)
Step-by-step explanation:
The point-slope form of the equation for a line is generally written ...
y -k = m(x -h)
for slope m and point (h, k).
The slope of your parallel line is the same as the slope of the reference line, -5. So your equation is ...
y -8 = -5(x -6)
How would you solve 3x=18
Hi!
[tex]3x=18[/tex]
[tex]\frac{3x}{3}=\frac{18}{3}[/tex]
[tex]x=6[/tex]
Explanation: This question is super easy on this question. First you had to divide by 3 from both sides. And simplify, it gave us the answer is x=6 is the right answer. Hope this helps! And thank you for posting your question at here on Brainly. And have a great day. -Charlie
If f(x) = -4x^2 - 6x - 1 and g(x) = -x^2 - 5x + 3, find (f + g)(x).
B
note that (f + g)(x) = f(x) + g(x)
f(x) + g(x) = -4x² - 6x - 1 - x² - 5x + 3 ( collect like terms )
= - 5x² - 11x + 2
Answer:
The correct option is B.
Step-by-step explanation:
The given functions are
[tex]f(x)=-4x^2-6x-1[/tex]
[tex]g(x)=-x^2-5x+3[/tex]
Using the p addition property of functions (f + g)(x) can be written as
[tex](f+g)(x)=f(x)+g(x)[/tex]
Substitute the values of each function in the above equation.
[tex](f+g)(x)=-4x^2-6x-1-x^2-5x+3[/tex]
Combine like terms.
[tex](f+g)(x)=(-4x^2-x^2)+(-6x-5x)+(-1+2)[/tex]
[tex](f+g)(x)=-5x^2-11x+2[/tex]
Therefore the correct option is B.
Find the quotient of 6/8 ÷ 3/-4
Step-by-step explanation:
6/8 / 3/4 = 1
Find the value of z such that 0.9544 of the area lies between −z and z. Round your answer to two decimal places.
Hello...
Z = total area (1)
___-z___0.9544___z
z = 0.0288
Normal,
z = 2
The value of z is 2. the probability that is closest to 0.0228, where the outliner is a -2 and z equals 2.
How to find the value of z?The decimal numeral system is widely used to express both integer and non-integer numbers. It is the expansion of the Hindu-Arabic numeral system to non-integer values. Decimal notation is the term used to describe the method of representing numbers in the decimal system.
A number that has been divided into a whole and a fraction is called a decimal. Between integers, decimal numbers are used to express the numerical value of complete and partially whole quantities.
The word decimus, which means tenth in Latin, is derived from the base word decem, or 10. As a result, the decimal system, often known as a base-10 system, has 10 as its fundamental unit. A number expressed using the decimal method is also referred to as being "decimal."
Given ,
0.9544/2= 0.4772
.5- 0 .4772=0.0228
the probability that is closest to 0.0228, where the outliner is a -2 and z equals 2.
Therefore value of z is 2.
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Is it possible to find an edge length that would be perfect for a cube with a volume of 30 cubic units? Explain!
Yes ,
side ×side×side= side^3 =volume of cube
=>side^3=30
=>side = 30^1/3-answer
im quite confused, please help :((
You need to pick from each column depending on what makes sense - they are mixed (some numbers are roots, some cubes, in the same column).
On the order:
3 - 27
4 - 64
5 - 125
512 - 8
8 - 2
729 - 9
216 - 6
1 - 1
Answer:
as>JDKFas;lkdjfsa;lkdfjas;kldfjlakdjfalsdkfjakdkdkdlddd
Step-by-step explanation:
On spring break, Mirna went to Florida. She collected 6 seashells. The following set of data shows the weight of each seashell in ounces. 16, 17, 13, 12, 18, 20 What is the mode of this set of data?
The set of seashell weights that Mirna collected (12, 13, 16, 17, 18, 20) does not have a mode because all values appear only once.
The mode of a set of data refers to the number that appears most frequently. In the case of the weights of the seashells Mirna collected in Florida, the data set is: 12, 13, 16, 17, 18, 20. To find the mode, we look for the value that occurs the most:
12 ounces - occurs once13 ounces - occurs once16 ounces - occurs once17 ounces - occurs once18 ounces - occurs once20 ounces - occurs onceSince all numbers occur only once, there is no number that appears more frequently than the others. Therefore, this set of data does not have a mode.
Wich product is equivalent to 25x2 -16
25x²-16 is the difference of two squares, so can be written as the product ...
... (5x -4)(5x +4)
or
... (5x +4)(5x -4)
Answer:
[tex](5x+4)(5x-4)[/tex]
Step-by-step explanation:
25x^2- 16
To find out the product that is equivalent to the given expression we need to factor the given expression
we write the numbers in square form
25 = 5*5 = 5^2
16 = 4*4 = 4^2
5^2x^2 - 4^2
[tex](5x)^2- 4^2[/tex]
we apply difference in square formula
a^2 - b^2 = (a+b)(a-b)
[tex](5x)^2- 4^2=(5x+4)(5x-4)[/tex]
Find the slope of the tangent line to the graph of f at the given point. f(x) = x√ at (36,6) 1/3 1/12 3 12
slope = [tex]\frac{1}{12}[/tex]
the slope is the value of f' (36)
f(x) = √x = [tex]x^{\frac{1}{2} }[/tex]
f'(x) = [tex]\frac{1}{2}[/tex] [tex]x^{-\frac{1}{2} }[/tex] = [tex]\frac{1}{2\sqrt{x} }[/tex]
f'(36) = [tex]\frac{1}{2(6)}[/tex] = [tex]\frac{1}{12}[/tex]
Answer:
[tex]slope = \frac{1}{12}[/tex]
Step-by-step explanation:
Here is another method to solve your problem. I am showing this method because this is the first method normally taught and a student might not of had the chance yet to learn the other methods
We can solve this problem by using limits and the following function
[tex]\lim_{h\to 0} \frac{f(x+h) - x}{h}[/tex]
[tex]\lim_{h\to 0} \frac{\sqrt{x+h} - \sqrt{x}}{h}[/tex]
Next multiply by the conjugate of the numerator.
[tex]\lim_{h\to 0} \frac{\sqrt{x+h} - \sqrt{x}}{h} * \frac{\sqrt{x+h} + \sqrt{x}}{\sqrt{x+h} + \sqrt{x}}[/tex]
[tex]\lim_{h\to 0} \frac{x + h - x}{h(\sqrt{x+h} + \sqrt{x})}[/tex]
Cancel the x - x
[tex]\lim_{h\to 0} \frac{h}{h(\sqrt{x+h} + \sqrt{x})}[/tex]
Divide out the h
[tex]\lim_{h\to 0} \frac{h}{h(\sqrt{x+h} + \sqrt{x})}[/tex]
[tex]\lim_{h\to 0} \frac{1}{(\sqrt{x+h} + \sqrt{x})}[/tex]
Plugin 0 where h is located
[tex]\lim_{h\to 0} \frac{1}{(\sqrt{x+h} + \sqrt{x})}[/tex]
[tex]\lim_{h\to 0} \frac{1}{(\sqrt{x+0} + \sqrt{x})}[/tex]
[tex]\lim_{h\to 0} \frac{1}{(\sqrt{x} + \sqrt{x})}[/tex]
Combine Like terms in denominator
[tex]\lim_{h\to 0} \frac{1}{(\sqrt{x} + \sqrt{x})}[/tex]
[tex]\lim_{h\to 0} \frac{1}{2\sqrt{x}}[/tex]
Now lets use our derivative and plugin 36 where x is located and solve
[tex]\frac{1}{2\sqrt{x}}[/tex]
[tex]\frac{1}{2\sqrt{36}}[/tex]
[tex]\frac{1}{2(6)}[/tex]
[tex]\frac{1}{12}[/tex]
Note, this is a harder method but it is normally the first method taught in Calculus 1.
If s = 1/4 unit and A = 80s^2, what is the value of A, in square units? ____ square unit(s). (Input whole number only.)
If s = 1/4 unit and A = 80s^2
A = 80 (1/4)^2
A = 80 (1/16)
A = 5
Answer
5 square units
5 square units
substitute s = [tex]\frac{1}{4}[/tex] into the equation
A= 80 × ([tex]\frac{1}{4}[/tex])² = 80 × [tex]\frac{1}{16}[/tex] = [tex]\frac{80}{16}[/tex]= 5 square units
Plz hurry A board 12 3/4 feet long is cut so that 9 7/8 feet are left. What length of the board was cut off? A) 21 2 ft B) 27 8 ft C) 31 2 ft D) 37 8 ft
2 7/8 ft
Explanation:We presume no length was lost in the cut, so that ...
... (remaining length) + (cut off length) = (original length)
Then ...
... (cut off length) = (original length) - (remaining length)
... = 12 3/4 - 9 7/8
... = (12 - 9) + (3/4 - 7/8)
... = 3 + (6/8 -7/8)
... = 3 - 1/8
... = 2 7/8
The cut off length was 2 7/8 feet.
what is the solution of the linear-quadratic system of equations?
will give brainliest and extra points!!!!!
Answer:
d. (1, 3) and (-3, -1)
Step-by-step explanation:
Equating the expressions for y, we have ...
... x² +3x -1 = y = x +2
Subtracting x+2 gives ...
... x² +2x -3 = 0
... (x +3)(x -1) = 0 . . . . . factored form
... x = -3, 1 . . . . . . . . . . .values that make the factors zero
The second equation tells us, y = x+2, so
... For x = -3, y = -3 +2 = -1. The solution is (-3, -1)
... For x = 1, y = 1 +2 = 3. The solution is (1, 3)
(- 3, - 1 ) or (1, 3 )
Since both equations express y in terms of x, equate both sides
x² + 3x - 1 = x + 2 ( subtract x + 2 from both sides )
x² + 2x - 3 = 0
(x + 3 )(x - 1 ) = 0
equate each factor to zero and solve for x
x + 3 = 0 ⇒ x = - 3
x - 1 = 0 ⇒ x = 1
Substitute these values into either of the 2 equations for y
y = - 3 : y = - 3 + 2 = - 1 ( using y = x + 2 )
x = 1 : y = 1 + 2 = 3
solutions are (- 3, - 1 ) or (1, 3 )