4. Suppose you deposit $100 in a savings account that compounds annually at 2%. After 1 year at this rate, the bank changes its rates of compounding to 1.5% annually. Assuming the compounding rate does not change for 4 additional years, how much will your account be worth at the end of the 5 year period?

Answers

Answer 1

Answer:

The Final amount in the account after 5 years will be $108.26

Step-by-step explanation:

Hello, great question. These types are questions are the beginning steps for learning more advanced Equations.

Since we are talking about compounding interest we can use the Exponential Growth Formula to calculate the interest over the next couple of years. The formula is the following,

[tex]y = a*(1+r)^{t}[/tex]

Where:

y is the total amount after a given timea is the initial amountr is the interest rate in decimalst is the given time

We first need to calculate the 2% interest for the first year,

[tex]y = 100*(1+0.02)^{1}[/tex]

[tex]y = 100*1.02[/tex]

[tex]y = 102[/tex]

So after the first year the account will have $102. Now we can use the $102 to calculate the next 4 years of interest using the new interest rate of 1.5%

[tex]y = 102*(1+0.015)^{4}[/tex]

[tex]y = 102*(1.015)^{4}[/tex]

[tex]y = 102*1.0614[/tex]

[tex]y = 108.26[/tex]

The Final amount in the account after 5 years will be $108.26

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.


Related Questions

Write a function with a zero of 1/2. Explain how you know.

Answers

Answer:

Simplest function is f(x) = 2x - 1

Step-by-step explanation:

When a function has a zero, simply put, that point is where the graph goes through the x-axis.  At this point, the y value is 0.

If a function has a 0 of 1/2, that translates to x = 1/2 and also (1/2, 0).  That means that y = 0 when x = 1/2.

If x = 1/2 and is a zero, then x - 1/2 = 0 and 2x - 1 = 0 (notice that y = 0 here and solving for x would get you right back to x = 1/2).

The simplest function with a zero of 1/2 is

f(x) = 2x - 1

You know it is true that the zero is 1/2 for two reasons.  First one is to set the right side equal to 0 and solve for x.

The second one is to graph the line y = 2x - 1 and see that it goes through the x axis at 1/2 where y = 0.

The function g is defined by g(x)=2x^2-3.
Find g(2y)

Answers

Answer:

g(2y) = 8y^2 -3

Step-by-step explanation:

g(x)=2 x^2   -3

Let x=2y

g(2y) = 2 (2y)^2 -3

         = 2 (4y^2)  -3

         = 8y^2 -3

In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal distribution to estimate the requested probabilities. What's your favorite ice cream flavor? For people who buy ice cream, the all-time favorite is still vanilla. About 26% of ice cream sales are vanilla. Chocolate accounts for only 14% of ice cream sales. Suppose that 172 customers go to a grocery store in Cheyenne, Wyoming, today to buy ice cream. (Round your answers to four decimal places.)

Answers

Answer:

44.72 Vanilla

24.08 Chocolate

Step-by-step explanation:

26% of 172 choose vanilla

14% of 172 choose chocolate

Use the future value formula to find the indicated value.
n=27​; i=0.04​; PMT=$109​; FV=?

FV=

Answers

Answer:

The future value = $1780

Step-by-step explanation:

* Lets explain the formula of the future value

- Future Value of an annuity is used to determine the future value of a

 stream of equal payments.

- The future value of an annuity formula can also be used to determine

  the number of payments, the interest rate, and the amount of the

  recurring payments

- The future value formula is [tex]FV=\frac{PMT}{i}(1-\frac{1}{(1+i)^{n}})[/tex]

 where:

# FV = Future Value of the annuity

# PMT= Payment amount  

# i = Annual interest rate  

# n = Number of payments

* Lets solve the problem

- n = 27

- i = 0.04

- PMT = $109

- To find FV lets use the formula above

∵ n = 27 , i = 0.04 , PMT = 109

∴ [tex]FV=\frac{109}{0.04}(1-\frac{1}{(1+0.04)^{27}})[/tex]

∴ [tex]FV=2725(1-\frac{1}{(1.04)^{27}})=1779.9248[/tex]

∴ FV = 1779.92 ≅ 1780

∴ The future value = $1780

Final answer:

The future value is calculated using the formula FV = PMT * [(1+i)^n - 1] / i. With a regular payment of $109, an interest rate of 0.04, and 27 periods, you can compute the future value.

Explanation:

The future value (FV) of an annuity can be calculated using the formula: FV = PMT * [(1+i)^n - 1] / i, where PMT is the regular payment, i is the interest rate, and n is the number of periods. In this case, the interest rate (i) is 0.04, the number of periods (n) is 27, and the regular payment (PMT) is $109. Plugging these values into the formula, we get FV = $109 * [(1+0.04)^27 -1] / 0.04. After performing these computations, you can find the future value (FV).

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A player scored 100100 points in a single professional basketball game. He made a total of 6262 ​baskets, consisting of field goals​ (worth two​ points) and foul shots​ (worth one​ point). Find the number of field goals and the number of foul shots that the player made.

Answers

Answer:

Step-by-step explanation:

Paul has just purchased a $1.250.000 home and made a $400,000 down payment The balance can be amortized at 3% for 30 years What are the monthly payments? (5 marks) Tay

Answers

Answer:

The monthly payment is $3583.63 ( approx )

Step-by-step explanation:

Given,

The total cost of the home = $1,250,000

There is a downpayment of $400,000,

Thus, the present value of the loan, PV =  1250000 - 400,000 = $ 850,000

Annual rate = 3 % = 0.03,

So, the monthly rate, r = [tex]\frac{0.03}{12}=\frac{1}{400}[/tex]

And, time ( in years ) = 30

So, the number of months, n = 12 × 30 = 360

Hence, the monthly payment of the loan,

[tex]P=\frac{PV(r)}{1-(1+r)^{-n}}[/tex]

[tex]=\frac{850000(\frac{1}{400})}{1-(1+\frac{1}{400})^{-360}}[/tex]

[tex]=3583.6342867[/tex]

[tex]\approx \$3583.63[/tex]

How much money should you invest now in order to have $ 60 comma 000$60,000 in 2929 ?years? Assume that the money earns interest at 10.5 %10.5%?, compounded annually. Round to the nearest dollar amount.

Answers

Answer:

$3316 should be invested.

Step-by-step explanation:

Since, the amount formula in compound interest is,

[tex]A=P(1+r)^t[/tex]

Where, P is the principal amount,

r is the rate per period,

t is the time in years,

Here,

A = $ 60,000,

r = 10.5% = 0.105

t = 29 years,

By substituting value,

[tex]60000=P(1+0.105)^{29}[/tex]

[tex]P=\frac{60000}{1.105^{29}}=\$3316.23415377\approx \$3316[/tex]

Hence, $ 3316 should be invested.

The patient has an order for oxytocin (Pitocin) to infuse at 7 mu/minute. Available is oxytocin 10 units/1000 mL 0.9% NaCl. At what rate will the nurse set the infusion? ___ mL/hr (If needed, round to the nearest whole number.)

Answers

Answer:

see attachment

Step-by-step explanation:

Final answer:

The nurse will set the infusion of oxytocin at approximately 117 mL/hr.

Explanation:

To calculate the rate at which the nurse will set the infusion of oxytocin, we can use the formula:

Rate (mL/hr) = (Order dose × Volume ÷ Time)

Substituting the given values:

Order dose = 7 mu/minuteVolume = 1000 mLTime = 60 minutes (since 1 hour has 60 minutes)

After calculating, we find that the nurse will set the infusion at approximately 117 mL/hr.

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A fair coin is flipped forty times and the number of heads that occur is noted. A random variable X is defined as the number of heads. Find the expected value and the standard deviation.

Answers

Answer:

expected value of x  is 1 and standard deviation of x is 0.7071

Step-by-step explanation:

Given data

coin flip = 40 time

heads noted

to find out

the expected value and the standard deviation

Solution

we know coin is flipped 40 times and the number of heads is noted only

so we find standard deviation for x i.e.

standard deviation of  x = [tex]\sqrt{variance x}[/tex]   .......1

first we calculate variance x .i.e.

variance x = expected value of x² - (expected value of x)²   .............2

so now we calculate expected value of x

we know when x = 0 , p(x) = 1/4

x = 1 , p(x) = 1/2

x = 2 , p(x) = 1/4

so  expected value of x  =  [tex]\sum_{0}^{2}[/tex] x p(x)

i.e.   expected value of x  =  0 P(x) + 1 p(x) + 2 p(x)

expected value of x  = 0 (1/4) + 1 (1/2) + 2 (1/4)

expected value of x  =  0  +  (1/2) + (1/2)

expected value of x  =    1             ....................3

now calculate expected value of x²

so so  expected value of x²  =  [tex]\sum_{0}^{2}[/tex] x²p(x)

i.e.  expected value of x²  =   x² P(x) + 1² p(x) + 2² p(x)

expected value of x²  =    0 (1/4) + 1 (1/2) + 4 (1/4)

expected value of x² =   0  +  (1/2) + (1)

expected value of x²  = 1.5         .........................4

now put equation 3 and 4 value in equation 2 we get

variance x =  expected value of x² - (expected value of x)²

variance x =  1.5 - (1)²

variance x =  0.5

now put variance value in equation 1 we get

standard deviation of  x = [tex]\sqrt{variance x}[/tex]  

standard deviation of  x = [tex]\sqrt{0.5}[/tex]  

standard deviation of  x = 0.7071

so standard deviation of x is 0.7071

The expected value is 20 and the standard deviation is 3.16

The expected value

The given parameters are:

n = 40 ---- the number of flips

p = 0.5 --- the probability of obtaining a head

The expected value is calculated as:

[tex]E(x) = np[/tex]

This gives

[tex]E(x) = 40 * 0.5[/tex]

[tex]E(x) = 20[/tex]

Hence, the expected value is 20

The standard deviation

This is calculated as:

[tex]\sigma = \sqrt{np(1 - p)[/tex]

So, we have:

[tex]\sigma = \sqrt{40 * 0.5 * (1 - 0.5)[/tex]

[tex]\sigma = 3.16[/tex]

Hence, the standard deviation is 3.16

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a. Assume that a 0.01 significance level will be used to test the claim that p 1less thanp 2. Which is​ better: A hypothesis test or a confidence​ interval? A hypothesis test is better. b. In​ general, when dealing with inferences for two population​ proportions, which two of the following are​ equivalent: confidence interval​ method; P-value​ method; critical value​ method? ▼ are​ equivalent, in that they will always lead to the same conclusion. Both of these methods use a standard deviation based on ▼ estimated values of the population proportions, the assumption that the two population proportions are equal, whereas the other method uses a standard deviation based on ▼ estimated values of the population proportions. the assumption that the two population proportions are equal.

Answers

Answer:

a. A hypothesis test is better

b. confidence interval​ method; and critical value​ method will lead to the same conclusion

Step-by-step explanation:

a. A hypothesis test is better

b. confidence interval​ method; and critical value​ method will lead to the same conclusion

when samples are taken from a population, the mean values of these samples are approximately normally distributed,that is, the mean values forming the sampling distribution of means is approximately normally distributed. It is also true that if the standard deviations of each of the samples is found, then the standard deviations of all the samples are approximately normally distributed, that is, the standard deviations of the sampling distribution of standard deviations are approximately normally distributed.

Parameters such as the mean or the standard deviation of a sampling distribution are called sampling statistics, S.

Final answer:

When comparing two population proportions, a hypothesis test is favored at a 0.01 significance level. The confidence interval and P-value methods are equivalent when assuming equal population proportions.

Explanation:

Hypothesis Test vs. Confidence Interval:

When dealing with inferences for two population proportions, a hypothesis test is better to test the claim that one proportion is less than the other at a 0.01 significance level.

Equivalence of Methods in Statistic Testing:

The confidence interval method and the P-value method are equivalent in that they both rely on assumed equal population proportions to draw conclusions.

Prove:

For all sets A, B, and C, if A ⊆ B and B ⊆ Cc , then A ∩ C = ∅.

Answers

Step-by-step explanation:

Let's take "a" an element from A, a ⊆ A.

As A ⊆ B, a ⊆ A ⊆ B, so a ⊆ B.

Therefore, a ⊆ B ⊆ Cc, a ⊆ Cc.

Let's remember that Cc is exactly the opposite of C. That means that an element is in C or in Cc; it has to be in one of them but not in both.

As a ⊆ Cc, a ⊄ C.

As we can generalize this for every element of A, there is not element of A that is contained in C.  

Therefore, the intersection (the elements that are in both A and C) is empty.

The graph below shows the average daily temperatures on January 1 from 1900 to 1934 for city A

The mean of the temperatures in the chart is 24° with a standard deviation of 4°. Which temperature is within one standard deviation of the mean?
16°
18°
27°
29°

Answers

Answer:

27 degrees

Step-by-step explanation:

The standard deviation means it can be up or down by that many degrees. The temperatures can be between 20-28 degrees. 27 degrees is the only option in this set of numbers.

Answer:

your answer is C 27

Step-by-step explanation:


I'm supposed to write the following intervals as sets indescriptive form:

a. (t, infinity), t a fixed real number

b. (0, 1/n), n a fixed natural number

---

I think it is:
a. (t, infinity) = {x: t < x < infinity}
b. (0,1/n) = {x: 0 < x < 1/n}

Is this correct?
Also, how do you indicate that t is a fixed realnumber and n a fixed natural number?

Answers

Answer:

Is correct.

Step-by-step explanation:

If you don't write the n and t in the left part of the set (before the : ) we assume that are fixed.

(t, infinity) = {[tex]x \in \mathbb{R} : t<x<\infty, t\in \mathbb{R}[/tex]}

(0,1/n) =  {[tex]x \in \mathbb{R} : 0<x<\frac{1}{n}, n\in \mathbb{N}[/tex]}


WEEK 8 DISCUSSION 250 words in word file so i can copy

Closing â What class, knowledge, or lesson do feel would prepare you for this course? Should there be a prerequisite course or a prep course before this class? If so, what should it include? What did you feel was the most helpful part of this course in learning the material? What topic was the most interesting to you? It was a pleasure having you in class!

Answers

Give me robux on robloz

Step-by-step explanation:

.........sd.....

Cody buys a soda that offers another soda free if he is lucky. The cap reads '1 in 6 wins!', meaning that each soda has a 1/6 probability of winning. Cody sees this and buys six of these sodas, thinking he is guaranteed a seventh. What is the true probability he will win at least one more soda? Express your answer as decimal to the nearest hundredth.

Answers

Final answer:

The true probability of Cody winning at least one more soda is approximately 0.67.

Explanation:

Cody buys six sodas, each with a 1/6 probability of winning another soda. To find the probability of winning at least one more soda, we need to find the probability of not winning any sodas and subtract it from 1. The probability of not winning a soda with each individual purchase is 5/6. Since the purchases are independent events, we can multiply the probabilities together to find the probability of not winning any sodas in all six purchases: (5/6) * (5/6) * (5/6) * (5/6) * (5/6) * (5/6) = (5/6)⁶ = 0.3349. Finally, we subtract this probability from 1 to find the probability of winning at least one more soda: 1 - 0.3349 = 0.6651 (rounded to the nearest hundredth).

Find dy/dx and d2y/dx2. x = cos(2t), y = cos(t), 0 < t < π dy dx = Correct: Your answer is correct. d2y dx2 = Correct: Your answer is correct. For which values of t is the curve concave upward? (Enter your answer using interval notation.) Incorrect: Your answer is incorrect.

Answers

Final answer:

The first and second derivatives of the given functions can be found using the chain rule of differentiation. The slope of the curve can be determined using these derivatives and to find out where the curve is concave upwards, the second derivative should be greater than zero.

Explanation:

To find the first and second derivatives dy/dx and d2y/dx2, we first need to use the chain rule. The chain rule states that the derivative of a composite function is the derivative of the outside function multiplied by the derivative of the inside function.

For dy/dx = dy/dt * dt/dx. Since y = cos(t), dy/dt = -sin(t). And since x = cos(2t), dx/dt = -2sin(2t). Thus, dy/dx = [-sin(t)] / [-2sin(2t)].Now, let's find d2y/dx2 which is the derivative of dy/dx with respect to x. So, d2y/dx2 = d/dx (dy/dx). Here, please use the quotient rule and chain rule again for differentiation.

For a curve to be concave upward, the second derivative needs to be greater than zero. So, you need to set your second derivative function greater than zero and solve for t within the given interval 0 < t < π.

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The first derivative is  [tex]\frac{dy}{dx} =\frac{1}{2cos(t)}[/tex] , and the second derivative is [tex]\frac{d^2y}{dx^2} = \frac{-1}{4cos^2tsin(2t)}[/tex]. The curve is concave upward in the interval (0, π/2).

We begin by finding the derivatives of x and y with respect to t.

Given x = cos(2t), differentiate to get:

[tex]\frac{dx}{dt} = -2sin(2t)[/tex]

Given y = cos(t), differentiate to get:

[tex]\frac{dy}{dt} = -sin(t)[/tex]

Using the chain rule,

[tex]\frac{dy}{dx} =\frac{dy}{dt} \frac{dt}{dx} = -sin(t) \cdot \frac{(-1)}{2sin(2t)} = \frac{1}{2cos(t)}[/tex]

Next, we need to find d²y/dx².

Start by finding the derivative of dy/dx with respect to t:

Given, [tex]\frac{dy}{dx} =\frac{1}{2cos(t)}[/tex] differentiate to get:

[tex]\frac{d(\frac{dy}{dx}) }{dt} = \frac{sin(t)}{2cos^2t}[/tex]

Using the chain rule again:

[tex]\frac{d^2y}{dx^2}= \frac{\frac{d(\frac{dy}{dx})}{dt} }{\frac{dx}{dt}} = \frac{-1}{4cos^2tsin(2t)}[/tex]

To determine where the curve is concave upward, we need d²y/dx² > 0.

Since sin(2t) is periodic, we look for values of t where sin(2t) is positive.

This is true for the interval (0, π/2). Thus, the curve is concave upward in the interval (0, π/2).

Question 12 (1 point) Given P(A) 0.34, P(A and B) 0.27, P(A or B) 0.44, what is P(B)? Answer in decimal form. Round to 2 decimal places as needed. Your Answer: Answer

Answers

Answer:  The required probability of event B is P(B) = 0.37.

Step-by-step explanation:  For two events A and B, we are given the following probabilities :

P(A) = 0.34,    P(A ∩ B) = 0.27   and   P(A ∪ B) = 0.44.

We are to find the probability of event B, P(B) = ?

From the laws of probability, we have

[tex]P(A\cup B)=P(A)+P(B)-P(A\cap B)\\\\\Rightarrow 0.44=0.34+P(B)-0.27\\\\\Rightarrow 0.44=0.07+P(B)\\\\\Rightarrow P(B)=0.44-0.07\\\\\Rightarrow P(B)=0.37.[/tex]

Thus, the required probability of event B is P(B) = 0.37.


The following problem refers to strings in A, B, ..., Z.

How many three-letter strings are there that begin with J ?

Answers

Answer: There are 676 three-letter strings that begin with J .

Step-by-step explanation:

The number of letters in  English Alphabet = 26

If first letter is fixed as J , then the number of ways to make 3 letters strings [repetition is allowed ] is given by :-

[tex]1\times26\times26=676[/tex]

(The first place is occupied by J and the rest of the two place has 26 ways of getting any letter)

Now, there are 676 three-letter strings that begin with J .

using a graphical approach, to determine the type of the problem,suggest a strategy to avoid the problem( if any), maximize 10X+10Y subject to : 2X+4Y=< 16 2X=<10

4Y=<8 X=6

Answers

Answer:

No solution. Inconsistent.

Step-by-step explanation:

The equations are

[tex]2x+4y\leq 16\\x\leq 5\\y\leq 2\\x=6[/tex]

As we can see here that x=6 and x<=5 the solution area will not be bounded i.e., there will be no common area.

The lines do not intersect

Therefore there will be no solution.

Plotting the equations we get the graph below.

A strategy to avoid the question would be by just looking at the linear equations. It can be clearly seen that there are two lines that will never intersect and hence will have no solution.

The function h is defined below.
Find all values of x that are NOT in the domain of h.
If there is more than one value, separate them with commas.

h(x) = x^2 - 5x - 24 / x^2 + 6x +9

Answers

Hello!

The answer is:

The only value of "x" that IS NOT in the domain of the function h,  is -3.

Why?

Since we are working with a quotient (or division), we must remember that the only restriction for this kind of functions are the values that make the denominator equal to 0, so, the domain of the function will include all the values of "x" that are different than the zeroes or roots of the denominator.

We have the function:

[tex]h(x)=\frac{x^2-5x-24}{x^2+6x+9}[/tex]

Where its denominator is :

[tex]x^2+6x+9[/tex]

Now, finding the roots or zeroes of the expression, by factoring, we have:

We need to find two numbers which product is equal to 9 and its addition is equal to 6, that number will be the same for both conditions (3):

[tex]3*3=9\\3+3=6[/tex]

So, the factorized form of the expression will be:

[tex](x+3)^2[/tex]

We have that the expression will be equal to 0 if "x" is equal to "-3", so, the only value of x that IS NOT in the domain of the function h,  is -3.

Hence, the domain will be:

Domain: (-∞,-3)U(-3,∞)

Have a nice day!

Final answer:

The only value that is not in the domain of the function h(x) is x = -3, since it makes the denominator of the function equal to zero, thus making the function undefined.

Explanation:

To determine the values that are not in the domain of the function h(x) = x² - 5x - 24}{x² + 6x +9}, we need to identify any values of x that would make the denominator equal to zero, since division by zero is undefined. To do this, we will factor the denominator and find its roots.

First, let's factor the denominator:

x² +6x + 9 = (x + 3)(x + 3)

Now, we set the factored denominator equal to zero to find the values of x that are not in the domain:

(x + 3)(x + 3) = 0

This equation has one distinct root, x = -3.

Therefore, the only value that is not in the domain of h is x = -3. If you substitute x = -3 into the original function, the denominator becomes zero, and the function is undefined.

All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be proficient in reading, 78% were found to be proficient in mathematics, and 65% were found to be proficient in both reading and mathematics. A student is chosen at random. a. What is the probability that the student is proficient in mathematics but not in reading? b. What is the probability that the student is proficient in reading but not in mathematics? c. What is the probability that the student is proficient in neither reading nor mathematics?

Answers

Answer:

a. 13%

b. 20%

c. 2%

Step-by-step explanation:

The best way to solve this problem is by drawing a Venn diagram.  Draw a rectangle representing all the fourth-graders.  Draw two overlapping circles inside the rectangle.  Let one circle represent proficiency in reading.  This circle is 85% of the total area (including the overlap).  And let the other circle represent proficiency in math.  This circle is 78% of the total area (including the overlap).  The overlap is 65% of the total area.

a. Since the overlap is 65%, and 78% are proficient in math, then the percent of all students who are proficient in math but not reading is the difference:

78% − 65% = 13%

b. Since the overlap is 65%, and 85% are proficient in reading, then the percent of all students who are proficient in reading but not math is the difference:

85% − 65% = 20%

c. The percent of students not proficient in reading or math is 100% minus the percent proficient in only reading minus the percent proficient in only math minus the percent proficient in both.

100% − 20% − 13% − 65% = 2%

See attached illustration (not to scale).

Final answer:

The probability of a student being proficient in mathematics but not in reading is 13%, in reading but not in mathematics is 20%, and in neither reading nor mathematics is 2%.

Explanation:

To solve the student's query, we'll use the principle that the probability of an event is the number of favorable outcomes divided by the total number of outcomes. We can apply the addition rule for probabilities, which states that the probability of either of two mutually exclusive events occurring is the sum of their individual probabilities, minus the probability of both events happening.

a. Mathematics but not Reading

Let P(M) be the probability the student is proficient in mathematics, P(R) be the probability the student is proficient in reading, and P(M & R) be the probability the student is proficient in both. The question asks for P(M) - P(M & R), the probability of being proficient in mathematics but not in reading. That is 78% - 65% = 13%.

b. Reading but not Mathematics

Similarly, the probability of a student being proficient in reading but not mathematics is P(R) - P(M & R), which equals 85% - 65% = 20%.

c. Proficient in Neither

To find the probability of a student being proficient in neither subject, we can find the probability of a student being proficient in at least one subject and then subtracting this from 100%. The probability of being proficient in at least one subject is P(R) + P(M) - P(M & R), or 85% + 78% - 65% = 98%. Thus, the probability of being proficient in neither is 100% - 98% = 2%.

Please help me with this

Answers

Answer: second option.

Step-by-step explanation:

By definition, the measure of any interior angle of an equilateral triangle is 60 degrees.

Based in this, we know that the measusre of the angle ∠SRT is:

[tex]\angle SRT=\frac{60\°}{2}=30\°[/tex]

The, we can find the value of "y":

[tex]y+12=30\\y=30-12\\y=18[/tex]

To find the value of "x", we must use this identity:

[tex]cos\alpha=\frac{adjacent}{hypotenuse}[/tex]

In this case:

[tex]\alpha=30\°\\adjacent=x\\hypotenuse=RU=RS=4[/tex]

Substituting values and solving for "x", we get:

[tex]cos(30\°)=\frac{x}{4}\\\\4*cos(30\°)=x\\\\x=\sqrt{12}[/tex]

Find the absolute maximum and minimum values of the function over the indicated​ interval, and indicate the​ x-values at which they occur. f left parenthesis x right parenthesisequalsx squared minus 6 x minus 9​; left bracket 0 comma 7 right bracket

Answers

Answer:

The absolute minimum value of the function over the​ interval [0,7] is -18.

Step-by-step explanation:

The given function is

[tex]f(x)=x^2-6x-9[/tex]

Differentiate f(x) with respect to x.

[tex]f'(x)=2x-6[/tex]

Equate f'(x)=0  to find the critical points.

[tex]2x-6=0[/tex]

[tex]2x=6[/tex]

[tex]x=3[/tex]

The critical point is x=3.

Differentiate f'(x) with respect to x.

[tex]f''(x)=2[/tex]

Since f''(x)>0 for all values of x, therefore the critical point is the point of minima and the function has no absolute maximum value.

3 ∈ [0,7]

Substitute x=3 in the given function to find the absolute minimum value.

[tex]f(3)=(3)^2-6(3)-9[/tex]

[tex]f(3)=9-18-9[/tex]

[tex]f(3)=-18[/tex]

Therefore the absolute minimum value of the function over the​ interval [0,7] is -18.

Final answer:

The maximum value of the function f(x) = x² - 6x - 9 over the interval [0, 7] is 2, which occurs at x = 7, and the minimum value is -9, which occurs at both x = 0 and x = 3.

Explanation:

The function given is f(x) = x² - 6x - 9. To find the maximum and minimum values of this function over the interval [0, 7], we first need to find the critical points of the function. These occur where the derivative of the function is zero or undefined. The derivative of f(x) is f'(x) = 2x - 6. Setting this equal to zero and solving for x gives x = 3. Since this value is within our interval, it is a critical point of the function.

Next, we evaluate the function at the endpoints of the interval and at our critical point. We have f(0) = -9, f(3) = -9, and f(7) = 2. This shows that the maximum value of the function over the interval is 2, which occurs at x = 7, and the minimum value is -9, which occurs at both x = 0 and x = 3.

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find the orthogonal projection of v= [19,12,14,-17] onto the subspace W spanned by [ [ -4,-1,-1,3] ,[ 1,-4,4,3] ] proj w (v) = [answer,answer,answer,answer]

Answers

Answer:

Hence, we have:

[tex]proj_W(v)=[\dfrac{464}{21},\dfrac{167}{21},\dfrac{71}{21},\dfrac{-131}{7}][/tex]

Step-by-step explanation:

By the orthogonal decomposition theorem we have:

The orthogonal projection of a vector v onto the subspace W=span{w,w'} is given by:

[tex]proj_W(v)=(\dfrac{v\cdot w}{w\cdot w})w+(\dfrac{v\cdot w'}{w'\cdot w'})w'[/tex]

Here we have:

[tex]v=[19,12,14,-17]\\\\w=[-4,-1,-1,3]\\\\w'=[1,-4,4,3][/tex]

Now,

[tex]v\cdot w=[19,12,14,-17]\cdot [-4,-1,-1,3]\\\\i.e.\\\\v\cdot w=19\times -4+12\times -1+14\times -1+-17\times 3\\\\i.e.\\\\v\cdot w=-76-12-14-51=-153[/tex]

[tex]w\cdot w=[-4,-1,-1,3]\cdot [-4,-1,-1,3]\\\\i.e.\\\\w\cdot w=(-4)^2+(-1)^2+(-1)^2+3^2\\\\i.e.\\\\w\cdot w=16+1+1+9\\\\i.e.\\\\w\cdot w=27[/tex]

and

[tex]v\cdot w'=[19,12,14,-17]\cdot [1,-4,4,3]\\\\i.e.\\\\v\cdot w'=19\times 1+12\times (-4)+14\times 4+(-17)\times 3\\\\i.e.\\\\v\cdot w'=19-48+56-51\\\\i.e.\\\\v\cdot w'=-24[/tex]

[tex]w'\cdot w'=[1,-4,4,3]\cdot [1,-4,4,3]\\\\i.e.\\\\w'\cdot w'=(1)^2+(-4)^2+(4)^2+(3)^2\\\\i.e.\\\\w'\cdot w'=1+16+16+9\\\\i.e.\\\\w'\cdot w'=42[/tex]

Hence, we have:

[tex]proj_W(v)=(\dfrac{-153}{27})[-4,-1,-1,3]+(\dfrac{-24}{42})[1,-4,4,3]\\\\i.e.\\\\proj_W(v)=\dfrac{-17}{3}[-4,-1,-1,3]+(\dfrac{-4}{7})[1,-4,4,3]\\\\i.e.\\\\proj_W(v)=[\dfrac{68}{3},\dfrac{17}{3},\dfrac{17}{3},-17]+[\dfrac{-4}{7},\dfrac{16}{7},\dfrac{-16}{7},\dfrac{-12}{7}]\\\\i.e.\\\\proj_W(v)=[\dfrac{464}{21},\dfrac{167}{21},\dfrac{71}{21},\dfrac{-131}{7}][/tex]

(1 point) If the joint density function of X and Y is f(x,y)=c(x2−y2)e−2x, with 0≤x<∞ and −x≤y≤x, find each of the following. (a) The conditional probability density of X, given Y=y>0. Conditional density fX|Y(x,y)= 4(x^2-y^2)e^(-2x)/(1-2y^2) (Enter your answer as a function of x, with y as a parameter.) (b) The conditional probability distribution of Y, given X=x. Conditional distribution FY|X(y|x)= 3/4(x^2-y^2) (for −x≤y≤x). (Enter your answer as a function of y, with x as a parameter.)

Answers

Before you do anything, you have to find [tex]c[/tex] such that [tex]f_{X,Y}(x,y)[/tex] is a proper joint density function. Doing the math, you'll find that [tex]c=2[/tex].

Now, determine the marginal densities:

[tex]f_X(x)=\displaystyle\int_{-\infty}^\infty f_{X,Y}(x,y)\,\mathrm dy=\int_{-x}^x2(x^2-y^2)e^{-2x}\,\mathrm dy[/tex]

[tex]\implies f_X(x)=\dfrac83x^3e^{-2x}[/tex]

[tex]f_Y(y)=\displaystyle\int_{-\infty}^\infty f_{X,Y}(x,y)\,\mathrm dx=\int_0^\infty2(x^2-y^2)e^{-2x}\,\mathrm dx[/tex]

[tex]\implies f_Y(y)=\dfrac12-y^2[/tex]

a. Then the density of [tex]X[/tex] conditioned on [tex]Y=y[/tex] is

[tex]f_{X\mid Y}(x\mid Y=y)=\dfrac{f_{X,Y}(x,y)}{f_Y(y)}=\dfrac{4(x^2-y^2)e^{-2x}}{1-2y^2}[/tex]

b. The density of [tex]Y[/tex] conditioned on [tex]X=x[/tex] is

[tex]f_{Y\mid X}(y\mid X=x)=\dfrac{f_{X,Y}(x,y)}{f_X(x)}=\dfrac{3(x^2-y^2)}{4x^3}[/tex]

and so the distribution of [tex]Y[/tex] conditioned on [tex]X=x[/tex] is

[tex]F_{Y\mid X}(y\mid X=x)=\displaystyle\int_{-\infty}^uf_{Y\mid X}(y\mid X=x)\,\mathrm du[/tex]

[tex]F_{Y\mid X}(y\mid X=x)=\begin{cases}0&\text{for }y<-x\\\frac{2x^3+3x^2y-y^3}{4x^3}&\text{for }-x\le y\le x\\1&\text{for }y>x\end{cases}[/tex]

Final answer:

To find the conditional probability density of X, given Y=y>0, use Bayes' theorem. To find the conditional probability distribution of Y, given X=x, integrate the joint density over the range of y values.

Explanation:

To find the conditional probability density of X, given Y=y>0, we need to calculate the conditional density fX|Y(x,y). This can be done using Bayes' theorem. First, find the marginal density of Y by integrating the joint density over the range of y values:

fY(y) = ∫f(x,y) dx = c(e^(-2y) - e^(-2y)/3)

Then, use Bayes' theorem to find the conditional density:

fX|Y(x,y) = f(x,y)/fY(y) = 4(x^2-y^2)e^(-2x)/(1-2y^2)

To find the conditional probability distribution of Y, given X=x, we need to calculate the conditional distribution FY|X(y|x). This can be found by integrating the joint density over the range of y values:

FY|X(y|x) = ∫f(x,y) dy = 3/4(x^2-y^2)

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Two accounts each began with a deposit of exist10,000. Both accounts have rates of 6.5%, but one account compounds interest once a year while the other account compounds interest continuously. Make a table that shows the amount in each account and the interest earned after one year, five, years, ten years, and 20 years. (Round ALL values to the nearest Dollar AND DO NOT include Dollar Signs)

Answers

Answer:

Step-by-step explanation:

Given data

principal P = $10000

rate (r) = 6.5%

to find out

amount in account and the interest earned after one year, five, years, ten years, and 20 years

solution

we know the formula for compounds interest continuously i.e.

amount = principal [tex]e^{rt}[/tex]     ..............1

and

compounds interest annually i.e.

amount = principal [tex](1+r/100)^{t}[/tex]  ..................2

here put value principal rate and time period 1, 5 10 and 20 years

and we get the  amount for each time period        

than for interest = amount - principal we get interest    

as that we calculate all value

i put all value in table here

Final answer:

To calculate the future value of two accounts both starting with $10,000 at a 6.5% interest rate, one compounding annually and the other continuously, we use the formulas for annual and continuous compounding to compare the total amount and interest earned over 1, 5, 10, and 20 years. The continuous compounding results in higher amounts as shown in the provided table.

Explanation:

To compare the growth of two accounts with an initial deposit of $10,000 at an annual interest rate of 6.5%, with one account compounding annually and the other compounding continuously, we can use the following formulas:

For annual compounding: A = P(1 + r/n)^(nt)For continuous compounding: A = Pe^(rt)

Where:
A = the amount of money accumulated after n years, including interest.
P = the principal amount (the initial amount of money).
r = the annual interest rate (in decimal form).
n = the number of times that interest is compounded per year.
t = the time in years.
e = the base of the natural logarithm, approximately equal to 2.71828.

To make the calculations for both accounts after 1, 5, 10 and 20 years, we will round all values to the nearest dollar and not include dollar signs as per the student's request.

Annual Compounding

Here, n is 1 since interest compounds once per year.

Continuous Compounding

Using the formula for continuous compounding, we do not need a value for n.

Let's look at the calculations:

TimeAnnual Compounded AmountContinuous Compounded AmountInterest Earned (Annual)Interest Earned (Continuous)1 year$10,695$10,709$695$7095 years$13,612$13,747$3,612$3,74710 years$18,504$18,907$8,504$8,90720 years$34,262$35,861$24,262$25,861

From the table, we can conclude that continuous compounding results in a higher total amount and interest earned over time compared to annual compounding for the same interest rate.

Listed below are the salaries, in $000, for a sample of 15 chief financial officers in the electronics industry. $ 516.0 $ 548.0 $ 566.0 $ 534.0 $ 586.0 $ 529.0 546.0 523.0 538.0 523.0 551.0 552.0 486.0 558.0 574.0 Click here for the Excel Data File Determine the mean, median, and the standard deviation.

Answers

Explained the mean, median, and standard deviation for a sample of CFOs' salaries in the electronics industry.

Mean: To find the mean, you add up all the salaries and divide by the number of salaries. For the CFOs, the mean salary is $544,773.

Median: To find the median, you arrange the salaries in order and find the middle value. For the CFOs, the median salary is $546,000.

Standard Deviation: The standard deviation measures the dispersion of data. For the CFOs, you can calculate it using the given formula to be approximately $29,534.

Convert 1000100 two to base sixteen

Answers

Answer:

(44)₁₆

Step-by-step explanation:

to convert it into hexa decimal we have select four pair of binary digit

(1000100)₂→(?)₁₆

  100  0100

to solve this we have to no the decimal conversion of

0100 which is '4'

so,

conversion of (1000100)₂→(44)₁₆

You want to have $ 150,000 in 18 years. How much do you have to deposit each month into an account that pays 3.5% APR?

Answers

Answer:

Total deposit in each month is $ 932.84

Step-by-step explanation:

Step 1:  Monthly interest rate.

Monthly Rate = (1+annual rate)112−1

we have  Annual rate = 3.5%

Monthly Rate = (1+0.035)112−1 = 0.0028709

Step 2:  monthly payment

Monthly payment can be determined by using below formula:

A=P×i×1−(1+i)−n

A = monthly payment amount

P = total pay amount

i = monthly interest rate

n = total number of payments

In this example we have

P=$150000 ,

i=0.0028709  and

n=12×18=216

Monthly payment = P×i×1−(1+i)−n

= 150000×0.00287091−(1+0.0028709)−216 = 430.6351−(1.0028709)−216

Monthly payment  =$ 932.84

Final answer:

To have $150,000 in 18 years with a 3.5% APR compounded monthly, you need to deposit approximately $499.58 each month. The formula for the future value of an annuity and the power of compound interest are key to understanding how regular savings can grow over time.

Explanation:

To determine how much you have to deposit each month to have $150,000 in 18 years with an account paying 3.5% APR, you'll need to use the formula for the future value of an annuity. The future value of an annuity formula is:

Future Value = [tex]Pmt * ((1 + r/n)^{(nt)} - 1) / (r/n)[/tex]

where:

Pmt = monthly payment

r = annual interest rate (decimal)

n = number of times the interest is compounded per year

t = number of years.

First, convert the APR to a monthly interest rate by dividing by 12, since there are 12 months in a year. The monthly interest rate is 0.035 / 12. The interest is compounded monthly, so n is 12. Let's solve for Pmt (monthly deposit) using the formula:

[tex]150,000 = Pmt * ((1 + 0.035/12)^{(12*18)} - 1) / (0.035/12)[/tex]

By using a financial calculator or algebra, you can find the monthly deposit required:

Pmt ≈ $499.58

Therefore, you would need to deposit approximately $499.58 each month into your savings account to have $150,000 in 18 years.

It's important to start saving money early and to let the power of compound interest work in your favor, as seen in the provided examples where initial investments grow significantly over time due to compound interest.

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Given the Homogeneous equation x^2ydy+xy^2dx=0, use y=ux, u=y/x and dy=udx+xdu to solve the differential equation. Solve for y.

Answers

Answer:

[tex] y=\frac{C}{x}[/tex].

Step-by-step explanation:

Given homogeneous equation

[tex] x^2ydy+xy^2dx=0[/tex]

[tex]\frac{\mathrm{d}y}{\mathrm{d}x}=-\frac{xy^2}{x^2y}[/tex]

Substitute y=ux , [tex]u=\frac{y}{x}[/tex]

[tex] \frac{\mathrm{d}y}{\mathrm{d}x}=-\frac{y}{x}[/tex]

Now,

[tex]u+x\frac{\mathrm{d}u}{\mathrm{d}x}=\frac{\mathrm{d}y}{\mathrm{d}x}[/tex]

[tex]u+x\frac{\mathrm{d}u}{\mathrm{d}x}=-u[/tex]

[tex]\frac{\mathrm{d}u}{\mathrm{d}x}=-2u[/tex]

[tex]\frac{du}{u}=-\frac{dx}{x}[/tex]

Integrating both side we get

lnu=-2lnx+lnC

Where lnC= integration constant

[tex]lnu+ln{x}^2=lnC[/tex]

[tex]lnux^2=lnC[/tex]

Cancel ln on both side

[tex]ux^2=C[/tex]

Substitute [tex]u=\frac{y}{x}[/tex]

Then we get

xy=C

[tex]y=\frac{C}{x}[/tex].

Answer:[tex]y=\frac{C}{x}[/tex].

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