5. A 28.4 g sample of aluminum is heated to 39.4 °C, and placed in a calorimeter containing 50.0 g of water. The
temperature of water increases from 21.00 °C to 23.00 °C. What is the specific heat capacity, C, of aluminum?​

Answer:

decrease

Explanation:

If the surface area of a substance increases, the rate of dissolving will increase due to more frequent and effective collisions between the solvent molecules and solute particles.

This effect happens because dissolution is a surface phenomenon, where solvent molecules must collide with the outer surface of the solute. More surface area means more opportunities for these collisions. For instance, powdered CaCO₃ will react faster with HCI than a lump of CaCO₃ because the increased surface area allows more particles to be in contact with the acid, leading to more frequent collisions. Furthermore, an effervescent tablet will dissolve more rapidly when broken into smaller pieces since the available surface area for reaction is increased.

Additionally, the rate of dissolution is influenced by factors such as agitation and temperature. Stirring or shaking a solution can facilitate solute particles contact with solvent, thus increasing dissolution rate. Similarly, dissolving a substance in a warmer solvent can lead to faster dissolution due to increased molecule's kinetic energy.

Answer:

The elements in__Group_ 0 of the Periodic Table are called the_noble__gases. They are generally __unreactive_. because they have a__full_outer shell of electrons. So they do not need to gain__lose_or share _electrons_ with other atoms.

Answer:

When heating, the temperature is increased, therefore, the average kinetic energy is increased so the molecules will start moving more rapidly.

Explanation:

Hello,

Kinetic molecular theory is based on a series of specific statements:

- Gases are constituted by a raft of particles that are considered as both hard and spherical bodies under a state of constant and random movement.

- The particles are constantly moving in a straight line until they collide to each other or against walls of the container.

- There is no force of attraction nor repulsion among gas particles or among the particles and the walls of the container.

- Collisions are said to be perfectly elastic.

- The average kinetic energy of a raft of gas particles is temperature-dependent only.

- The higher the temperature the higher the average kinetic energy of the gas and the other way around.

In such a way, considering the last two statements, when heating, the temperature is increased, therefore, the average kinetic energy is increased so the molecules will start moving more rapidly in comparison to the initial state.

Best regards.

The Michael drove 648,000 m.

Explanation:

It is given that the time taken by Michael, that is t = 36000 s

Speed is nothing but distance traveled by the time taken in seconds. Its unit is  m/s.

Here we have the speed in km/hr, we have to convert it to m/s as,

1 km = 1000 m

1 hr = 3600 s

So it is converted as,

[tex]$\frac{65 \times 1000}{3600}[/tex]  

= 18 m/s

Now we have the speed in m/s.

18 m/s = [tex]$\frac{x m}{36000s}[/tex]

We can find the distance x as = 18 m/s ×36000 s = 648,000 m

So the Michael drive 648,000 m.

Answer: 68.6 kPa

Explanation:

To calculate the new pressure, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

[tex]P_1V_1=P_2V_2[/tex]

where,

[tex]P_1\text{ and }V_1[/tex] are initial pressure and volume.

[tex]P_2\text{ and }V_2[/tex] are final pressure and volume.

We are given:

[tex]P_1=?\\V_1=13.81L\\P_2=261.1kPa\\V_2=3.63L[/tex]

Putting values in above equation, we get:

[tex]P_1\times 13.81L=261.1\times 3.63L\\\\P_1=68.6kPa[/tex]

Thus pressure  before its volume was decreased was 68.6 kPa

Final answer:

The correct option is (a), which states that the precipitate formed when sodium sulfate and silver nitrate solutions are mixed is silver sulfate, and it provides the correct net ionic equation for this precipitation reaction.

Explanation:

When solutions of sodium sulfate (Na2SO4) and silver nitrate (AgNO3) are mixed together, a double-replacement reaction occurs. The balanced chemical equation for this reaction is:

Na2SO4(aq) + 2AgNO3(aq) → Ag2SO4(s) + 2NaNO3(aq)

The precipitate formed in this reaction is silver sulfate (Ag2SO4). The net ionic equation for the formation of the precipitate is:

2Ag+(aq) + SO42-(aq) → Ag2SO4(s)

Answer (a) is the correct option, as it accurately identifies the precipitate and provides the correct net ionic equation for its formation.

Answer:

The answer to your question is 2 moles

Explanation:

Data

mass of H₂O = 36 g

moles of H₂O = ?

Process

1.- Calculate the molar mass of water (H₂O)

H₂O = (1 x 2) + (16 x 1) = 2 + 16 = 18 g

2.- Use proportions and cross multiplication to find the answer.

               18 g of H₂O ---------------- 1 mol

               36 g of H₂O --------------- x

                     x = (36 x 1) / 18

                     x = 36/18

                     x = 2 moles

Answer:

The answer to your question is 34 g of H₂O₂    

Explanation:

Data

mass of H₂O₂ = ?

mass of O₂ = 32 g

Process

1.- Write the balanced chemical reaction

                   H₂O₂  ⇒   H₂  +  O₂

2.- Calculate the molar mass of H₂O₂ and O₂

Molar mass H₂O₂ = (1 x 2) + (16 x 2) = 34 g

Molar mass of O₂ = 2 x 16 = 32 g

3.- Use proportions to calculate the mass of O₂

                    34g of H₂O₂ -------------- 32g of O₂

                     x                   -------------- 32g of O₂

                          x = (32 x 34) / 32

                          x = 34 g of H₂O₂                                

Answer:

The answer to your question is 9.034 x 10²³ molecules

Explanation:

Data

number of molecules = ?

number of moles = 1.50

Process

To solve this problem, use Avogadro's number. This number relates 1 mol of a substance to 6.023 x 10²³ molecules.

                          1 mol of CO₂ ---------------  6.023 x 10 ²³ molecules

                          1.5 moles of CO₂ ----------   x

                                x = (1.5 x 6.023 x 10²³) / 1

                                x = 9.034 x 10²³ molecules

Answer:

0.0174 mol

Explanation:

Molarity is (moles of solute)/(liters of solvent).  So, to find moles you need to multiply liters by molarity.

0.0437 L × 0.400 M = 0.0174 mol

The number of moles of CH₃OH present is 0.01748 mole

From the question,

We are to determine the number of moles of CH₃OH that are in 43.7 mL of 0.400 M CH₃OH

Using the formula

Number of moles = Concentration × Volume

From the question

Concentration of CH₃OH = 0.400 M

Volume of CH₃OH = 43.7 mL = 0.0437 L

∴ Number of moles of CH₃OH present = 0.400 × 0.0437

Number of moles of CH₃OH present = 0.01748 mole

Hence, the number of moles of CH₃OH present is 0.01748 mole

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Answer:

HOFO = (0, 0, +1, -1)

Explanation:

The formal charge (FC) can be calculated using the following equation:

[tex] FC = V - N - \frac{1}{2}B [/tex]

Where:

V: are the valence electrons

N: are the nonbonding electrons

B: are the bonding electrons

The arrange of the atoms in the oxyacid is:

H - O₁ - F - O₂

Hence, the formal charge (FC) on each of the atoms is:

H: FC = 1 - 0 - 1/2*(2) = 0            

O₁: FC = 6 - 4 - 1/2*(4) = 0        

F: FC = 7 - 4 - 1/2*(4) = +1

O₂: FC =  6 - 6 - 1/2*(2) = -1

We can see that the negative charge is in the oxygen instead of the most electronegative element, which is the F. This oxyacid is atypical.  

I hope it helps you!

Answer:

The solvent is Nitrogen and the solute is oxygen

Explanation:

Normally the solvent always contains higher amount of substance than the solute in a particular solution

Answer:

Sea water, a solution composed of a variety of salts dissolved in water. The salt is the SOLUTE

Soda water, a solution composed of carbon dioxide gas dissolved in water. The water is the SOLVENT

Air, a solution composed of 78% nitrogen and 21% oxygen. The nitrogen is the  SOLVENT

Explanation:

its right on EDGE

1.95  or 2  is the molarity of a 45.3g sample of KNO3 (101g) dissolved in enough water to make a 0.225L solution.

The correct answer is option b

Explanation:

Data given:

mass of KN[tex]O_{3}[/tex] = 45.3 grams

volume = 0.225 litre

molarity =?

atomic mass of KNO3 = 101 grams/mole

molarity is calculated by using the formula:

molarity = [tex]\frac{number of moles}{volume of the solution}[/tex]

first the number of moles present in the given mass is calculated as:

number of moles = [tex]\frac{mass}{atomic mass of 1 mole}[/tex]

number of moles = [tex]\frac{45.3}{101}[/tex]

0.44 moles of KNO3

Putting the values in the equation of molarity:

molarity = [tex]\frac{0.44}{0.225}[/tex]

molarity = 1.95

It can be taken as 2.

The molarity of the potassium nitrate solution is 2.

Answer:

waxing crescent phase

Answer:

Waxing crescent

Explanation:

because i got the question right

Answer:

Explanation:

Glycolysis is the process of breakdown of  glucose into two 3-carbon molecules called pyruvate. The energy released during glycolysis is used to make ATP.

Enolase is the enzyme  which plays very important role in glycolysis. In the 9th step of glycolysis, Enolase converts  2-phosphoglycerate into phosphoenolpyruvate.

This reaction of conversion of  2-phosphoglycerate to phosphoenolpyruvate is a reversible dehydration reaction.

Fluoride inhibits enolase, so when enolase is become non-functional then there is no convertion of 2-phosphoglycerate  to phosphoenolpyruvate, so the concentraion of 2-phosphoglycerate is increases by the addition of fluoride.

Answer:

a

Explanation:

Answer:Chemical reactions often involve changes in energy due to the breaking and formation of bonds. Reactions in which energy is released are exothermic reactions, while those that take in heat energy are endothermic. exothermicA description of a chemical reaction that releases heat energy to its surroundings.

Answer:

ΔSv = 0.1075 KJ/mol.K

Explanation:

Binary solution:

∴ a: solvent

∴ b: solute

in equilibrium:

⇒ Ln (1 - Xb) = ΔG/RT

∴ ΔG = ΔHv - TΔSv

⇒ Ln(1 -Xb) = ΔHv/RT - ΔSv/R

∴ Xb → 0:

⇒ Ln(1) = ΔHv/RT - ΔSv/R

∴ T = T*b....normal boiling point

⇒ 0 = ΔHv/RT*b - ΔSv/R

⇒ ΔSv = (R)(ΔHv/RT*b)

⇒ ΔSv = ΔHv/T*b

∴ T*b = 80°C ≅ 353 K

⇒ ΔSv = (38 KJ/mol)/(353 K)

⇒ ΔSv = 0.1075 KJ/mol.K

Answer:

[tex]Q_{iron} = -32730.083\,J[/tex]

Explanation:

By the First Law of Thermodynamics, the piece of iron and water reach thermal equilibrium when both have the same temperature. The heat released by the piece of iron is received by the water. That is to say:

[tex]Q_{iron} = -Q_{w}[/tex]

[tex]Q_{iron} = (93.64\,g)\cdot \left(4.186\,\frac{J}{kg\cdot ^{\textdegree}C} \right)\cdot (7\,^{\textdegree}C-90.5\,^{\textdegree}C)[/tex]

[tex]Q_{iron} = -32730.083\,J[/tex]

Answer:

Halogens are better oxidizing agents than their alkali metal counterparts within the same period

Halogens have a higher first ionization energy than their alkali metal counterparts within the same period.

Halogens have a higher electron affinity than their alkali metal counterparts within the same period.

Halogens have a higher effective nuclear charge than their alkali metal counterparts within the same period

Explanation:

Effective nuclear charge increases across a period and accounts for increase in ionization energy across a period. This explains why halogens in the same period with alkali metals have higher effective bucket charge as well as ionization energy than the alkali metals.

Similarly, electron affinity increased across a period, halogens have greater ekctron affinity than corresponding alkali metals in the same period.

Answer:

C-18

Explanation:

Step one follow order of operations

Add and subtract from left to right(-5)+(7)=2-(-4)+(12)

STEP 2

Apply negative Rule -(-4)=+4=2+4+(12)

then add 2+4+12=18

Answer:

For the reaction N2 (g) and 2N (g) the energy is required to break the bond in N2 to from N atoms. This means AH is positive, is an endothermic reaction.

Explanation:

Entropy increases that  is positive  because atoms are now free to move.

Tarnished silver ware is cleaned by placing it in an aluminium pan as E°cell is positive.

Explanation:

The tarnish silver due to silver sulphate is removed by placing the tarnished ware in an aluminium pan. Certainly, aluminium is a stronger reducing agent than silver. Hence, it reduces the silver ions(Ag+) to metallic silver. The silvery white white colour will slowly get deposited on the walls of silwer ware and then the tarnish will be removed.

Al(s)+ 3Ag+ (aq)→ Al3+ (aq)+ 3Ag(s)

E° cell = E ° cathode - E° anode

 = (-0.71)- (-1.66) = 0.95 V is positive.

Hence, the reaction is feasible and the tarnish will be removed.

The electrochemical principle behind the procedure is aluminum is a strong reducing agent.

Electrochemical reaction is the reaction in which the electrons flow between a solid electrode.

The reaction is [tex]Ag^2S (s) + 2e- 2Ag (s) + S-2 (aq) is -0.71 V[/tex]

E° cell = E ° cathode - E° anode

(-0.71)- (-1.66) = 0.95 V is positive.

Thus, the  electrochemical principle behind the procedure is aluminum is a strong reducing agent.

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Antoine Lavoisier divided elements into four categories. Dmitri Mendeleev arranged elements by atomic mass and predicted undiscovered elements. Johann Wolfgang Dobereiner created groups of three elements based on similar properties, whereas John Newlands also arranged elements by atomic weights and predicted some properties of missing elements.

The Periodic Table has been created thanks to several scientists who categorized elements by different methods. Antoine Lavoisier, known as the father of modern chemistry, divided elements into four categories: gases, non-metals, metals, and earths. Consequently, the scientist who divided elements into four categories was Antoine Lavoisier. Dmitri Mendeleev arranged elements according to their atomic mass and used this order to predict the properties of undiscovered elements. Hence, Dmitri Mendeleev is the scientist who used patterns to predict undiscovered elements. Johann Wolfgang Dobereiner, suggested a law of triads, where patterns among groups of three elements were identified based on their properties. Thus, Dobereiner is the scientist who created groups of three elements, each based on similar properties. Lastly, John Newlands arranged elements in order of atomic weights, predicting some properties of missing elements.

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Answer:49.3

Explanation:4.1j/g c * 25g * (t2-45c)=455j

T2-45c = 455j/4.1j/g c * 25g

455/104.6

45+4.3= 49.3 celsius

The final temperature of water if 455 J of heat is transferred to 25.0g of water at 45.0 degrees Celsius is 63.2°C.

The final temperature of water can be calculated using the following formula:

Q = m × c × ∆T

Where;

According to this question, 455 J of heat is transferred to 25.0g of water at 45.0 degrees Celsius.

455 = 25 × (T - 45)

455 = 25T - 1125

25T = 1580

T = 63.2°C

Therefore, the final temperature of water if 455 J of heat is transferred to 25.0g of water at 45.0 degrees Celsius is 63.2°C.

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Answer:

Explanation:

Bromine comes in handy with reactivity of organic compounds such as alkenes and arenes( aromatic hydrocarbon). In arenes , it is an electrophilic substitutional reaction where bromine becomes the electrophile to form a substituted aromatic ring. The use of bromine in monobromination (i.e substitution of one bromine atom) is due to the higher electronegative effect in bromine which makes it to be a strong electrophile.

In the diagram; the left hand side shows the arene compound and the right hand side shows the major product after it has undergo monobromination with Br₂/FeBr₃.

Answer:

Ag+(aq) + Cl-(aq) <--->AgCl(s)

Ksp = [Ag+] [Cl-]

aii) Pb2+(aq) + 2Cl-(aq) <--->PbCl2(s)

Ksp = [Pb+] [Cl-]^2

Explanation:

In this question, we are to write the net ionic equation and corresponding Ksp expression for the salts in the question.

We proceed as follows;

Ag+(aq) + Cl-(aq) <--->AgCl(s)

Ksp = [Ag+] [Cl-]

aii) Pb+2(aq) + 2Cl-(aq) <--->PbCl2(s)

Ksp = [Pb+] [Cl-]^2

Final answer:

To write net ionic equations for AgCl and PbCl2, the equations are AgCl(s)
ightarrow Ag+(aq) + Cl-(aq) with Ksp = [Ag+][Cl-], and PbCl2(s)
ightarrow Pb2+(aq) + 2Cl-(aq) with Ksp = [Pb2+][Cl-]^2. These represent the dissolution of silver chloride and lead (II) chloride, respectively.

Explanation:

To write the net ionic equations and corresponding Ksp expressions for the dissolution of solid silver chloride (AgCl) and lead (II) chloride (PbCl2), you should consider both substances dissolving separately in water:

AgCl

Net ionic equation: AgCl(s)
ightarrow Ag+(aq) + Cl-(aq)

Ksp expression: Ksp = [Ag+][Cl-]

This represents the solubility product for silver chloride, which is given as 1.8  imes 10^-10.

PbCl2

Net ionic equation: PbCl2(s)
ightarrow Pb2+(aq) + 2Cl-(aq)

Ksp expression: Ksp = [Pb2+][Cl-]^2

This represents the solubility product for lead (II) chloride, which is given as 1.6  imes 10^-5. Note that because there are two chloride ions for every lead ion that dissolves, the concentration of chloride appears squared in the expression.

The gases eventually reach the Earth's surface through rain. Hence option A is correct.

Volcanic eruption is defined as when a volcano erupts, sometimes violently spewing lava and gas into the air. Volcanoes erupt with a powerfully destructive mixture of ash, lava, hot, toxic gases, and rock. Explosions from volcanoes have claimed lives. Volcanic eruptions can bring forth additional health risks such wildfires, floods, mudslides, electricity outages, and contaminated drinking water.

During a volcanic eruption, water vapor (H2O), carbon dioxide (CO2), and sulfur dioxide make up 90% of the gas molecules released (SO2). The remaining one percent is made up of trace amounts of hydrogen sulfide, carbon monoxide, hydrogen chloride, hydrogen fluoride, and other small gas species.

Thus, the gases eventually reach the Earth's surface through rain. Hence option A is correct.

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