A 1.10 kg block is attached to a spring with spring constant 13.5 n/m . while the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 36.0 cm/s . what are

The converted energy of [tex]324\;J[/tex] is the thermal energy created by the friction during his descent.

Explanation:

Given information:

Mass of justin [tex]=50 \; \text{kg}[/tex]

Height of water slide [tex]=8\;\text{m}[/tex]

Speed at the bottom [tex]= 12 \;\text{m/s}[/tex]

Now, the total mechanical energy is:

[tex]E_i=U=mgh\\E_i=50\times 9.81\times 8\\E_i=3924\;J[/tex]

And, the kinetic energy :

[tex]E_f=K=(1/2)mv^2\\E_f=0.50\times 50\times 12\\E_f=3600\;\text{J}[/tex]

So, the energy lost by the justin:

[tex]\Delta\;E=E_i-E_f\\\Delta\;E=3924-3600\\\Delta\;E=324J\\[/tex]

Hence, this converted energy of [tex]324\;J[/tex] is the thermal energy created by the friction during his descent.

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Final answer:

The power output of the horse is calculated by dividing the work done by the time taken. With 910 joules of work done in 380 seconds, the power output is approximately 2.4 watts after rounding to two significant figures.

Explanation:

To calculate the power output of the horse, you can use the formula for power, which is work divided by time.

Power (P) = Work (W) / Time (T)

Given the information, the horse does 910 joules (J) of work in 380 seconds. Using the formula:

P = 910 J / 380 s ≈ 2.395 W

Rounded to two significant figures, the power output of the horse is approximately 2.4 watts (W).

It comes out to be approximately 2.394736842 W, which is rounded to 2.4 W to two significant figures. The power output of the horse is calculated by dividing the work done by the time taken.

To calculate the power output of the horse, we use the formula for power (P), which is P = Work done (W) / Time taken (t).

The horse does 910 J of work in 380 seconds.

Therefore, the power output P is:

P = 910 J / 380 s = 2.394736842 J/s

Since 1 watt (W) is equivalent to 1 joule per second (J/s), the power output of the horse is approximately:

P = 2.394736842 W

Rounded to two significant figures, the power output of the horse is 2.4 W.

Answer:

black hole

Explanation:

A black hole is a region which is highly dense and very high gravitational field.

As the density of black hole is very high, so the mass of black g=hole is very large thus the force of gravitation is very large. So, even light cannot escape from the gravitational filed from the black hole.

Answer:

Liquid water is essential for life to exist. Water can occur in a liquid state only within a specific temperature range, so knowing the temperature range on a planet will help astronomers predict whether life exists on that planet.

Explanation:

Final answer:

Temperature is a critical criterion for finding Earthlike exoplanets because it determines the presence of liquid water, a requirement for life. The greenhouse effect of a planet's atmosphere can greatly influence its surface temperature, making it crucial to find planets within their star's habitable zone where conditions allow for liquid water.

Explanation:

Temperature is an excellent criterion for searching for Earthlike exoplanets because it is a fundamental factor that determines a planet's habitability. The presence of liquid water is crucial for life as we know it and water exists in liquid form within a specific temperature range - not too hot, not too cold, but “just right”. Planets with surface temperatures between the freezing and boiling points of water, such as Earth, are rare and special because they may house environments where life can thrive. Furthermore, a planet's temperature is deeply influenced by its atmosphere through the greenhouse effect, which can significantly modify surface conditions. Earth's atmosphere keeps it warm enough to sustain life, while Venus, with its thick carbon dioxide atmosphere, is much hotter, and Mars, with a very thin atmosphere, is much colder.

Astronomers have therefore determined that looking for exoplanets within the habitable zone of their star - where temperature conditions are favorable for liquid water - is essential in the quest to find life. This involves analyzing various attributes of exoplanets, including their size and distance from their star, as well as the atmospheric composition, which can alter temperature conditions beyond the expectations set by distance alone. So, temperature serves as a proxy for a multitude of critical conditions that collectively determine the possibility of life on other planets.

Answer:

heat transfer by convection

Explanation:

yeah the heat just goes to your hand like "hello" now your hand is warm just don't TOUCH the fire because then it will go "HELLO" and it will be painful

Have a fantastic life and just I don't know... live life and go outside it's beautiful.

Veins contain a network of valves to insure a one-way flow of blood but arteries do not. This is because veins must counteract the force of gravity on blood flow.

Veins must counteract the force of gravity on blood flow. Unlike arteries that carry blood away from the heart under high pressure, blood in veins is under much lower pressure after passing through capillaries.

The presence of one-way valves in veins, particularly in the limbs, is crucial to ensure the unidirectional flow of blood back toward the heart. These valves, along with the help of muscle contractions, prevent backflow and assist venous return to the heart, overcoming the effects of gravity and the reduced pressure in the venous system.

By the time blood reaches the venules and veins, the pressure initially exerted by heart contractions has greatly decreased. The veins are equipped with thin walls, large lumens, and valves that work together with muscle contractions to promote the return of blood to the heart.

This system compensates for the low blood pressure and the pull of gravity that would otherwise hinder the upward movement of blood from the extremities.

Considering the Charles' law, the initial temperature was 390.34 K or 117.34 °C.

Definition of Charles's Law

Charles's Law consists of the relationship that exists between the volume and temperature of a certain amount of ideal gas, which is maintained at a constant pressure, by means of a proportionality constant that is applied directly. For a given amount of gas at a constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases because the temperature is directly related to the energy of the movement of the gas molecules. .

In summary, Charles's law is a law that says that when the amount of gas and pressure remain constant, the ratio between volume and temperature will always have the same value:

V÷T=k

Analyzing an initial state 1 and a final state 2, the following is true:

V₁÷T₁=V₂÷T₂

Initial temperature

In this case, you know:

Replacing in Charles' law:

2.30 L÷T₁= 1.75 L÷297 K

Solving:

2.30 L= (1.75 L÷297 K)× T₁

2.30 L÷ (1.75 L÷297 K)= T₁

390.34 K= 117.34 °C= T₁

Finally, the initial temperature was 390.34 K or 117.34 °C.

a. the maximum height reached by the ball is approximately 3.46 meters.

b.   the speed of the ball when it is at the highest point is approximately 21.19 meters per second.

c.   the ball lands  14.83 meters away from the launch point in the same direction as its horizontal component of velocity.

a)

Vertical component = Initial speed * sin(launch angle)

Vertical component = 23 m/s * sin(21°) = 8.23 m/s

The maximum height reached by the ball can be calculated using the equation:

Maximum height = (Vertical component²) / (2 * gravity)

Gravity = 9.81 m/s².

Maximum height = (8.23 m/s)² / (2 * 9.81 m/s²)

=  3.46 m

b)

At the highest point, the vertical component of velocity becomes zero  because the ball stops momentarily before falling back down.

Horizontal component = Initial speed * cos(launch angle)

Horizontal component = 23 m/s * cos(21°) =  21.19 m/s

c)

Time to fall = (2 * Maximum height) / gravity

Time to fall = (2 * 3.46 m) / 9.81 m/s² =  0.70 s

Horizontal distance = Horizontal component * Time to fall

Horizontal distance = 21.19 m/s * 0.70 s =  14.83 m

Explanation:

It is given that, two teams are playing tug of war.

Force applied by Team A, [tex]F_A=450\ N[/tex]

Force applied by Team B, [tex]F_B=415\ N[/tex]

We need to find the net force acting on the rope. It is equal to :

[tex]F_{net}=F_A-F_B[/tex]

[tex]F_{net}=450-415[/tex]

[tex]F_{net}=35\ N[/tex]

So, the net force acting on the rope is 35 N and it is acting toward right. Hence, this is the required solution.

Answer:

20 N to the left

Explanation:

The horizontal distance traveled by the spittle is 2.62 m.

The given parameters;

The time of motion is calculated as;

[tex]h = v_0_yt + \frac{1}{2} gt^2\\\\1.8 = (5.5\times sin(13))t + (0.5\times 9.8)t^2\\\\1.8 = 1.24t + 4.9t^2\\\\4.9t^2 + 1.24t - 1.8= 0\\\\solve \ the \ quadratic \ equation\ using \ formula \ method;\\\\a = 4.9, \ b = 1.24, \ c = -1.8\\\\t = \frac{-b \ \ +/- \ \ \sqrt{b^2 - 4ac} }{2a} \\\\t = \frac{-1.24 \ \ +/- \ \ \sqrt{(1.24)^2 - 4(4.9\times -1.8)} }{2(4.9)} \\\\t = 0.49 \ s[/tex]

The horizontal distance traveled by the spittle is calculated as;

[tex]X = v_0_x \times t\\\\X = 5.5\times cos (13) \times 0.49\\\\X = 2.62 \ m[/tex]

Thus, the horizontal distance traveled by the spittle is 2.62 m.

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Answer:

C. Photosphere

Explanation:

The lights shown in the figure comes from the outermost layer of the Sun. This layer is called photosphere.

This is the layer from where the light of the Sun is radiated, before travelling through space and reaching us.

The photosphere is the coldest layer of the Sun: its surface temperature is between 4500 and 6000 K. Its width is approximately 100 km.

A characteristic of the photosphere is the presence of the sunspots, which appear as darker spots, and are regions of lower temperature caused by a concentration of magnetic flux.

The correct option is Option C( Photosphere).The photosphere is the layer of the sun responsible for producing the visible light we see. It has a temperature range of 4500 K to 6800 K. The photosphere is the sun's visible surface.

A typical cell membrane in an animal maintains a potential difference across the membrane of ΔV = 70 mV and the membrane has a thickness of about 8 nm. The capacitance of the membrane is about 1 microFarad per square cm. 

(B) If we model the membrane by a simple "two thin sheets of charge" model separated by 8 nm with nothing between them, what would be the electric field be between the sheets and what would the charge density on the sheets of the membrane? Explain your reasoning.

Now, notice that:

[tex]Q=C\Delta V\\ \Delta V=E.L[/tex]

Where L is the thickness of the membrane.

We then can get the electric field by just using:

[tex]E=\frac{\Delta V}{L}=\frac{70\times10^{-3}}{8\times10^{-9}}=8.75\times10^{6}N.C^{-1}[/tex]

Now using the charge expression and plugging the the expression for [tex]\Delta V[/tex] into it and then solving for [tex]E[/tex] we get:

[tex]E=\frac{Q}{CL}[/tex]

Now let's multiply both denominator and numerator by [tex]\frac{1}{A}[/tex] this yields:

[tex]E=\frac{\sigma}{C_{\sigma}L}[/tex]

Where 

[tex]\sigma=\frac{Q}{A}\\ C_{\sigma}=\frac{C}{A}[/tex]

Notice that the value in the wording of the problem is no actually the capacitance, but the capacitance per area [tex]C_{\sigma}[/tex], also [tex]\sigma[/tex] is the charge density.

Let's transform [tex]C_{\sigma}[/tex] to [tex]\frac{farad}{m^2}[/tex]:

[tex]\frac{1\mu F}{cm^2}=\frac{1\times10^{-2}F}{m^2}[/tex]

Solving for  [tex]\sigma[/tex] we get:

[tex]sigma=E.C_{\sigma}.L=7\times10^{-4}\frac{Coulomb}{m^2}=7\times10^{-8}\frac{Coulomb}{cm^2}[/tex]

The term mechanical advantage is used to described how effectively a simple machine works. Mechanical advantage is defined as the resistance force moved divided by the effort force used. In the lever example above, for example, a person pushing with a force of 30 lb (13.5 kg) was able to move an object that weighed 180 lb (81 kg). So the mechanical advantage of the lever in that example was 180 lb divided by 30 lb, or 6. The mechanical advantage described here is really the theoretical mechanical advantage of a machine. In actual practice, the mechanical advantage is always less than what a person might calculate. The main reason for this difference is resistance. When a person does work with a machine, there is always some resistance to that work. For example, you can calculate the theoretical mechanical advantage of a screw (a kind of simple machine) that is being forced into a piece of wood by a screwdriver. The actual mechanical advantage is much less than what is calculated because friction must be overcome in driving the screw into the wood.

Sometimes the mechanical advantage of a machine is less than one. That is, a person has to put in more force than the machine can move. Class three levers are examples of such machines. A person exerts more force on a class three lever than the lever can move. The purpose of a class three lever, therefore, is not to magnify the amount of force that can be moved, but to magnify the distance the force is being moved. As an example of this kind of lever, imagine a person who is fishing with a long fishing rod. The person will exert a much larger force to take a fish out of the water than the fish itself weighs. The advantage of the fishing pole, however, is that it moves the fish a large distance, from the water to the boat or the shore.

To find the initial speed of the bullet, we can use the conservation of linear momentum. By applying the conservation of momentum equation, we can solve for the initial velocity of the bullet. In this case, the initial velocity of the bullet is found to be 0 m/s.

To find the initial speed of the bullet, we need to consider the conservation of linear momentum. The initial momentum of the bullet is equal to the final momentum of the bullet and the block together.

The momentum of an object is given by the product of its mass and velocity. The bullet has a mass of 9.00 g and its velocity is the initial speed we want to find. The block has a mass of 1.20 kg and its velocity is 0 m/s initially.

Applying the conservation of momentum, we have: (mass of bullet) × (initial velocity of bullet) = (mass of bullet + mass of block) × (final velocity of bullet + block).

Since the bullet remains embedded in the block, the final velocity of the bullet and block together is 0 m/s. Plugging in the values, we can solve for the initial velocity of the bullet.

9.00 g × (initial velocity of bullet) = (9.00 g + 1.20 kg) × 0

(initial velocity of bullet) = 0 / (10.2 g)

(initial velocity of bullet) = 0 m/s