A 14.01 g sample of n2 reacts with 3.02 g of h2 to form ammonia (nh3). if ammonia is the only product, what mass of ammonia is formed? 17.01 g 1.10 g 14.01 g 3.02 g 23.07 g

Explanation:

A polar covalent bond is formed due to unequal sharing of electrons between the combining atoms.

For example, HCl is a polar covalent compound.

This is because of the difference in electronegativities of both hydrogen and chlorine, partial opposite charges tend to develop on the hydrogen and chlorine atoms.

Whereas [tex]CHCl_{3}[/tex] is a non-polar compound and when HCl is added to it then HCl being polar in nature is unable to dissolve.

On the other hand, water is a polar compound and when HCl is dissolved in it then it will dissociate into hydrogen and chlorine ions.

As electricity is the flow of ions or electrons. Therefore, HCl in water is able to conduct electricity because it dissociates into ions.

Therefore, we can conclude that HCl in water exists as [tex]H^{+}[/tex] and [tex]Cl^{-}[/tex] ions. And, HCl in [tex]CHCl_{3}[/tex] exists as HCl.

Without the complete chemical equations for the synthesis of cryolite, it's not possible to calculate the mass of cryolite produced from the reactants Al2O3, NaOH, and HF.

To determine the mass of cryolite that will be produced, we need to look at the stoichiometry of the reactions involved. However, the given information does not provide a complete chemical equation for the reaction of Al2O3, NaOH, and HF to form cryolite, so we can't perform a straightforward stoichiometric calculation. Instead, we know from the provided context that aluminum oxide reacts with cryolite in the Hall-Heroult process, suggesting that cryolite acts as a solvent for Al2O3 during aluminum extraction.

In the industrial production of aluminum, cryolite serves as a solvent and does not get consumed in the process. Therefore, we cannot calculate the amount of cryolite produced without the specific chemical equations for its synthesis. One would typically start with a known amount of aluminum oxide and cryolite for the electrolysis process rather than producing cryolite during the reaction. Since we cannot calculate the mass of cryolite produced with incomplete information, we would need the actual synthesis reaction of cryolite to proceed.

Answer: This chemical reaction is defined as synthesis reaction.

Explanation:

Synthesis reaction is defined as the reaction in which two or more substances combine in their elemental state to produce a single compound.

The general chemical equation representing this reaction is:

[tex]A+B\rightarrow AB[/tex]

For the given chemical reaction:

[tex]2Na(s)+Cl_2(g)\rightarrow 2NaCl(s)[/tex]

Hence, this chemical reaction is defined as synthesis reaction.

Boyle's law of ideal gas: This law states that the volume of a gas is inversely proportional to its pressure at a constant temperature. Acc to this law we can write the relation of pressure and volume as:

[tex] PV=Constant [/tex]

That means:

[tex] P_{1}V_{1}=P_{2}V_{2} [/tex]

From that equation we can calculate Volume of gas at a certain pressure:

P₁=Initial pressure

V₁=Initial volume

P₂=Final pressure

V₂= Final volume

Here P₁, initial pressure is given as 85.0 kPa

V₁, initial volume is given as 525 mL

P₂, final pressure is 65.0 kPa

[tex] P_{1}V_{1}=P_{2}V_{2} [/tex]

so,

V_{2}=85\times 525\div 65

=686 mL

Volume of gas will be 686 mL.

To find the number of moles of air released by the time Gabor reaches the surface, we can use the ideal gas law equation PV = nRT. Given the temperature and volume of air in Gabor's lungs, we can calculate the number of moles using the molar gas constant. Approximately 1.945 moles of air must be released by the time Gabor reaches the surface.

To find the number of moles of air released by the time Gabor reaches the surface, we need to use the ideal gas law equation, PV = nRT. Given that the temperature in Gabor's lungs is 37°C (98.6°F) and the volume is 6L, we can calculate the number of moles. The molar gas constant (R) is given as 8.31 J/mol⋅K.

First, we need to convert the temperature to Kelvin by adding 273 to the Celsius value:

T = 37°C + 273 = 310K

Now, we can rearrange the ideal gas law equation to solve for moles (n):

n = PV / RT

Plugging in the given values:

n = (1atm * 6L) / (8.31 J/mol⋅K * 310K)

Simplifying the equation:

n = 1.945 moles

Therefore, approximately 1.945 moles of air must be released by the time Gabor reaches the surface.

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The rate of the dihydrogen production is 0.0175 kg/sec for the given reaction.

The given reaction

[tex]\bold {CH_4 + H_2O \rightarrow CO + 3H_2}[/tex]

One mole of Methane is react with one mole of water to form 1 mole of CO and 3 moles of Hydrogen.

The rate of hydrogen production can be calculated from ideal gas law

[tex]\bold {pV = nRT}[/tex]

Where,

p- pressure = 0,86 atm · 101,325 kPa/atm = 87,14 kPa.

V- volume of methane =  159 L

T -  temperature= 294°C = 567 K.

R - gas constant = 8,314 J/K·mol.

n - number of moles = ?

Put the values in the formula, sole it for n,

[tex]\bold{n(CH₄) = \dfrac {pV} {RT}}\\\\\bold {n(CH₄) = \dfrac {87,14 kPa \times 159 L} {8,314 J/K.mol \times 567 K}.}\\\\\bold {n(CH₄) = 2,93 mol}[/tex]

Since, the molar ratio of methane to hydrogen is 3:1.

SO,

[tex]\bold {n(H_2) = 2,93 mol \times 3 }\\\\\bold {n (H_2) = 8,79 mol.}\\[/tex]

Hence, the mass of the dihydrogen produced,

[tex]\bold{ m(H_2) = 8.79 mol \times 2 g/mol.}\\\\\bold {m(H_2) = 17.58 g \times 0.001 kg/g}\\\\\bold {m(H_2) = 0.01758 kg}[/tex]

Therefore, the rate of the dihydrogen production is 0.0175 kg/sec for the given reaction.

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A combination of sand, salt, and water is an example of a heterogeneous mixture, where you can distinguish between the different components - the sand settles at the bottom, the water above it, and the salt dissolves in the water but can still be separated.

A combination of sand, salt, and water is an example of a heterogeneous mixture. This is because in a heterogeneous mixture, the individual components can be visibly distinguished. Sand, salt, and water are each physically distinct within the mixture. For instance, if you look closely at such a mixture in a clear glass, you would see the sand settling at the bottom, the water above it, and the salt would have dissolved in the water but could still be separated by means of evaporation.

This is different from a homogeneous mixture, where all the components are evenly distributed and cannot be visually distinguished, such as salt fully dissolved in water. It's also not a compound, where different elements are chemically combined and cannot be separated by physical methods. Nor is it a pure substance which consists of only one type of atom, element, or compound. Finally, it's not just a solid because it contains both solid (sand, salt) and liquid (water) states of matter.

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Answer:

The correct answer is option C. "Displacement".

Explanation:

The displacement method for measuring volume consist in measuring the amount of water that an object displaces when is submerged in a defined amount of water. This is an indirect method which is particularly useful to measure the volume of irregularly shaped objects, such as the rock stated in the question.

Answer:

The percentage is 50.7%

Explanation:

The formula of chromium (III) carbonate is (Cr₂(CO₃)₃)

Let us calculate the molar mass of (Cr₂(CO₃)₃)

molar mass of (Cr₂(CO₃)₃) =

2X atomic mass of Cr + 3X atomic mass of C + 9X atomic mass of O

molar mass of (Cr₂(CO₃)₃) = 2X 52 + 3X12 +9X16 = 284g/mol

As per the formula there are nine moles of oxygen in each mole of (Cr₂(CO₃)₃).

so we can say that

In 284g of (Cr₂(CO₃)₃) the mass of oxygen = 144g

so 1 g of (Cr₂(CO₃)₃) the mass of oxygen = [tex]\frac{144}{284}=0.507g[/tex]

Therefore

the mass of oxygen in 100g of(Cr₂(CO₃)₃) =0.507X100=50.7

Thus percentage of Oxygen in (Cr₂(CO₃)₃) =50.7%

the correct

answer is D

Answer:

33 g

Explanation:

A 225 g sample of french fries supplies 460 kilocalories of energy. 65% (0.65) of those calories come from fat. The kilocalories coming from fat are:

460 kcal × 0.65 = 299 kcal

9 kilocalories of energy are supplied per gram of fat. The grams of fat that supply 299 kcal are:

299 kcal × (1 g fat/ 9 kcal) = 33 g

Formation of Y and Z directly depends on initial amount of X present.

Further Explanation:

Le Chatelier’s principle:

This states that any change in pressure, temperature or concentration in any reaction that is present in equilibrium tends to shift equilibrium in such direction that reverses the effect of changed quantity in reaction.

Given reaction occurs as follows:

[tex]2\text{X(g)}\rightleftharpoons\text{Y(g)}+\text{Z(g)}[/tex]

According to this reaction, two moles of X decompose to form one mole of Y and one mole of Z.

Amounts of Y and Z formed during the given reaction depend on initial amount of X present. More the amount of X, higher will be formation of products Y and Z and vice-versa. So if amount of X is increased, equilibrium will tend to shift in direction that reverses this effect. This is done only by increased consumption of X that results in more formation of products. Therefore more amounts of Y and Z are formed if initial amount of X is increased and formation of Y and Z decreases if initial amount of X is decreased.

Learn more:

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Chemical Equilibrium

Keywords: Le Chatelier’s principle, equilibrium, shift, direction, X, Y, Z, 2X, pressure, temperature, concentration, consumption, increase, decrease, two moles, one mole.

Final answer:

The initial amount of gas x does not affect the equilibrium quantities at a constant temperature. The concentration of solid z is constant and it is omitted from the equilibrium expression, meaning only gaseous reactants y and products are considered. The equilibrium position is dependent on the partial pressures of the gases, set by the equilibrium constant for given temperature conditions.

Explanation:

When a generic gas x decomposes in a sealed glass jar to form gaseous y and solid z following the reversible reaction 2x(g) ⇌ y(g) + z(s), the initial amount of x(g) does not affect the equilibrium quantities. This is established by Le Chatelier’s Principle and the concept of equilibrium constants. In a heterogeneous equilibrium like this, where a solid is involved, the concentration of the solid remains constant and it is omitted from the equilibrium expression. Only the concentrations of the gaseous reactants and products are variable and are included in the expression.

The equilibrium composition in the gas phase at a constant temperature remains the same, regardless of the initial amount of x(g). This is because the solid z(s) does not appear in the equilibrium constant expression and does not have a concentration that changes. What really matters for the position of equilibrium is the ratio of the concentrations (partial pressures) of the gaseous reactants and products, something that is fixed by the equilibrium constant at a given temperature.

Moreover, the system’s response to a change in volume or pressure depends on the stoichiometry of the gaseous components according to their molar quantities. In a reaction where the total molar amounts of reactants and products are equal, a change in volume does not shift the equilibrium. If the molar amounts are different, a volume change will shift the equilibrium in a direction that accommodates the volume change. However, as the temperature is held constant in this scenario, volume changes are not being considered, simplifying the analysis of the system.

In the Beer-Lambert Law equation, “b” represents[tex]\boxed{{\text{thickness of solution}}}[/tex].

Further explanation:

Spectrophotometry is a method that is applied for measurement of absorbance of light in terms of intensity of light when light is allowed to pass through the solution sample. Spectrophotometer is the equipment or instrument that is employed for this purpose.

Beer-Lambert’s Law:

This law describes the relationship of absorbance with concentration and path length of solution. According to this law, absorbance of any solution is directly related to its concentration and optical path length. The expression for Lambert-Beer’s law is as follows:

[tex]{\text{A}} = {{\varepsilon bc}}[/tex]                                                                          …... (1)

Where,

A is absorbance of species.

[tex]{{\varepsilon }}[/tex]  is molar absorptivity of species.

b is optical path length or thickness of solution.

c is concentration of species.

If graph is plotted between absorption and concentration of solution, a straight line or linear graph is observed. But this linearity is lost at extremely high concentrations. This non-linearity can be due to several factors. Some of these include use of non-monochromatic radiations, scattering of light, phosphorescence or fluorescence of sample.

According to equation (1),“b” represents the thickness of the solution.

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Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Beer-Lambert Law

Keywords: absorbance, Beer-lambert’s law, concentration, path length, solution, directly related, thickness of solution, molar absorptivity, A, b, c, spectrophotometry, spectrophotometer.

The most likely species of beetles to become extinct when existing conditions change is the Green-colored beetles, pesticide-resistant gene absent; option 3.

Favorable traits are those traits possessed by organisms which enables them to survive or gives them an advantage to adapt to their environment.

An example of a favorable trait is pesticide-resistance or being disease-resistant.

Therefore, the most likely species of beetles to become extinct when existing conditions change is the Green-colored beetles, pesticide-resistant gene absent.

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Answer:

Deoxyribose.

Explanation:

Hello,

On the attached picture, you will find the β-furanose structure of the deoxyribose which is the monosaccharide present in the DNA (deoxyribonucleic acid).

Deoxyribose is a sugar derived from ribose by replacement of a hydroxyl group by hydrogen. In addition, it is the five-carbon sugar molecule that helps form the phosphate backbone of DNA molecules

Best regards.

The concentration of chloride ions in a saturated lead solution can be calculated using the given solubility and the stoichiometry of the dissolution reaction. The concentration is determined to be 1.3 × 10-6 M.

The concentration of chloride ions in a saturated solution is determined by the solubility product constant, Ksp, and the solubility of the particular compound. Using the provided information, the concentration of chloride ions is given as [Cl] = 7.6 × 10-³ M initially. However, with further calculations by applying quadratic equation and taking into account the dissolution stoichiometry, it is found that the concentration of chloride ions in the solution is [Cl] = 1.3 × 10-6 M. The composition of chlorine in its isotopic form is also considered which consists of 75.76% 35Cl and 24.24% 37Cl. Hence, consider all these factors when calculating the concentration of ions in a solution.

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