Answer:
given that
....the mass of the metal is 20g(0.02kg)
....specific heat capacity(c) is 0.4J/g°C
....ΔT=??
heat(Q)=3.9KJ(3900J)
Q=mcΔT
ΔT= Q/mc
.....=3900÷(20g x 0.4J/g°C)
.....=487.5°C
Using the heat transfer formula Q = mcΔT, the change in temperature is calculated to be 487.5 °C. The metal absorbs 3.9 kJ of heat and has a specific heat capacity of 0.4 J/g°C.
To find the change in temperature for the 20 g piece of metal, we'll use the heat transfer formula:
Q = mcΔTWhere:
Q = heat absorbed (in joules)m = mass (in grams)c = specific heat capacity (in J/g°C)ΔT = change in temperature (in °C)Given:
Q = 3.9 kJ = 3900 Jm = 20 gc = 0.4 J/g°CRearrange the formula to solve for ΔT:
[tex]\Delta T = \frac{Q} {mc}[/tex]Substitute the given values:
[tex]\Delta T = \frac{3900 \ J} {20 g \times 0.4 J/g^\circ C}[/tex][tex]\Delta T = \frac{3900 \ J} {8\ J/g^\circ C}[/tex]ΔT = 487.5 °CThe change in temperature for the metal piece, given the provided data, is 487.5 °C.
Solutions of sodium sulfate and silver nitrate are mixed together.
On a piece of scratch paper write a fully balanced double-replacement equation for this reaction.
Using the chemical equation you wrote; which answer correctly identifies the precipitate (if there is one) and the net ionic equation for the reaction that formed the precipitate?
a
Precipitate: silver sulfate
Net Ionic: 2Ag+ + SO42- --> Ag2SO4
b
There is no precipitate for the reaction; all products are soluble.
c
Precipitate: sodium nitrate
Net Ionic: Na+ + NO3- --> NaNO3
d
Precipitate: sodium nitrate
Net Ionic: Na2+ + 2NO3- --> Na(NO3)2
e
Precipitate: silver sulfate
Net Ionic: Ag+ + SO42- --> AgSO4
Final answer:
The correct option is (a), which states that the precipitate formed when sodium sulfate and silver nitrate solutions are mixed is silver sulfate, and it provides the correct net ionic equation for this precipitation reaction.
Explanation:
When solutions of sodium sulfate (Na2SO4) and silver nitrate (AgNO3) are mixed together, a double-replacement reaction occurs. The balanced chemical equation for this reaction is:
Na2SO4(aq) + 2AgNO3(aq) → Ag2SO4(s) + 2NaNO3(aq)
The precipitate formed in this reaction is silver sulfate (Ag2SO4). The net ionic equation for the formation of the precipitate is:
2Ag+(aq) + SO42-(aq) → Ag2SO4(s)
Answer (a) is the correct option, as it accurately identifies the precipitate and provides the correct net ionic equation for its formation.
1 Copy and complete using the words below:
electrons, full, Group, lose, noble, unreactive
The elements in____ 0 of the Periodic Table are called the____gases. They are generally ____. because they have a____outer shell of electrons. So they do not need to gain____or share ___ with other atoms.
Answer:
The elements in__Group_ 0 of the Periodic Table are called the_noble__gases. They are generally __unreactive_. because they have a__full_outer shell of electrons. So they do not need to gain__lose_or share _electrons_ with other atoms.
According to the following reaction, how many grams of hydrogen peroxide (H2O2) are needed to form 32.0 grams of oxygen gas?
Answer:
The answer to your question is 34 g of H₂O₂
Explanation:
Data
mass of H₂O₂ = ?
mass of O₂ = 32 g
Process
1.- Write the balanced chemical reaction
H₂O₂ ⇒ H₂ + O₂
2.- Calculate the molar mass of H₂O₂ and O₂
Molar mass H₂O₂ = (1 x 2) + (16 x 2) = 34 g
Molar mass of O₂ = 2 x 16 = 32 g
3.- Use proportions to calculate the mass of O₂
34g of H₂O₂ -------------- 32g of O₂
x -------------- 32g of O₂
x = (32 x 34) / 32
x = 34 g of H₂O₂
Draw the structure of the expected major organic product if this compound was to undergo monobromination with br2/febr3.
Answer:
Explanation:
Bromine comes in handy with reactivity of organic compounds such as alkenes and arenes( aromatic hydrocarbon). In arenes , it is an electrophilic substitutional reaction where bromine becomes the electrophile to form a substituted aromatic ring. The use of bromine in monobromination (i.e substitution of one bromine atom) is due to the higher electronegative effect in bromine which makes it to be a strong electrophile.
In the diagram; the left hand side shows the arene compound and the right hand side shows the major product after it has undergo monobromination with Br₂/FeBr₃.
[tex]C_{12}H_{22}O_{11}(aq) + H_2O(l) \rightarrow 2C_6H_{12}O_6(aq)[/tex]
The chemical equation shown above represents the hydrolysis of sucrose. Under certain conditions, the rate is directly proportional to the concentration of sucrose. Which statement supports how a change in conditions can increase the rate of this reaction?
a. Increasing the amount of water in which the sugar is dissolved will increase the frequency of collisions between the sucrose molecules and the water molecules resulting in an increase in the rate of hydrolysis.
b. Decreasing the temperature will increase the frequency of the collisions between the sucrose molecules and the water molecules resulting in an increase in the rate of hydrolysis.
c. Increasing the concentration of sucrose will increase the rate of hydrolysis by increasing the frequency of the collisions between the sucrose and the water molecules.
d. Decreasing the concentration of sucrose will increase the rate of hydrolysis by increasing the frequency of the collisions between the sucrose and the water molecules.
Answer:
a
Explanation:
During which phase does earth see more than half of the moons surface?
Answer:
waxing crescent phase
Answer:
Waxing crescent
Explanation:
because i got the question right
HELP PLEASE (If you cant answer all, that okay! First to answer all will be mark BRAINLIEST!)
(They need to be matched to the correct definition!)
~~~~~~~~~~~~~~
Periodic table
~~~~~~~~~~~~~~
Antoine Lavoisier ~ used patterns to predict undiscovered elements
Dmitri Mendeleev ~ Divided elements into four categories
John Newlands ~created groups of three elements, each based on
Johann Wolfgang Dobereiner similar properties
~Arranged elements according to their atomic
mass
Antoine Lavoisier divided elements into four categories. Dmitri Mendeleev arranged elements by atomic mass and predicted undiscovered elements. Johann Wolfgang Dobereiner created groups of three elements based on similar properties, whereas John Newlands also arranged elements by atomic weights and predicted some properties of missing elements.
Explanation:The Periodic Table has been created thanks to several scientists who categorized elements by different methods. Antoine Lavoisier, known as the father of modern chemistry, divided elements into four categories: gases, non-metals, metals, and earths. Consequently, the scientist who divided elements into four categories was Antoine Lavoisier. Dmitri Mendeleev arranged elements according to their atomic mass and used this order to predict the properties of undiscovered elements. Hence, Dmitri Mendeleev is the scientist who used patterns to predict undiscovered elements. Johann Wolfgang Dobereiner, suggested a law of triads, where patterns among groups of three elements were identified based on their properties. Thus, Dobereiner is the scientist who created groups of three elements, each based on similar properties. Lastly, John Newlands arranged elements in order of atomic weights, predicting some properties of missing elements.
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For a reaction in which a diatomic molecule dis- sociates into atoms, what are the signs of ΔS and ΔH? Explain your answer. You may use the reaction N2(g) ⎯→ 2N(g) as an example of such a reaction.
Answer:
For the reaction N2 (g) and 2N (g) the energy is required to break the bond in N2 to from N atoms. This means AH is positive, is an endothermic reaction.
Explanation:
Entropy increases that is positive because atoms are now free to move.
__________ is a numerical value assigned to each element to indicate the number of electrons that might be lost, gained, or shared by an atom of that element when it bonds with an ion or an atom of another element to form a compound.
Answer:
oxidation number
Explanation:
Describes the degree of oxidation of an atom in a chemical compound.
Someone please help!!
A piece of iron with a mass of 56.2 grams is heated and placed into a calorimeter containing 93.64 grams of water at 7.0 degrees Celsius. The final temperature of the water and the iron is 90.5 degrees Celsius. Assuming no heat is lost to the surroundings, how much heat (in Joules) does the iron release? Round your answer to the nearest 0.1 Joules.
Answer:
[tex]Q_{iron} = -32730.083\,J[/tex]
Explanation:
By the First Law of Thermodynamics, the piece of iron and water reach thermal equilibrium when both have the same temperature. The heat released by the piece of iron is received by the water. That is to say:
[tex]Q_{iron} = -Q_{w}[/tex]
[tex]Q_{iron} = (93.64\,g)\cdot \left(4.186\,\frac{J}{kg\cdot ^{\textdegree}C} \right)\cdot (7\,^{\textdegree}C-90.5\,^{\textdegree}C)[/tex]
[tex]Q_{iron} = -32730.083\,J[/tex]
How many molecules is 1.50 moles of CO2
Answer:
The answer to your question is 9.034 x 10²³ molecules
Explanation:
Data
number of molecules = ?
number of moles = 1.50
Process
To solve this problem, use Avogadro's number. This number relates 1 mol of a substance to 6.023 x 10²³ molecules.
1 mol of CO₂ --------------- 6.023 x 10 ²³ molecules
1.5 moles of CO₂ ---------- x
x = (1.5 x 6.023 x 10²³) / 1
x = 9.034 x 10²³ molecules
The normal boiling point of a substance is defined to be the temperature at which the liquid phase of the substance is in equilibrium with the gas phase at 1 atm pressure. The normal boiling point of methanol is 80oC and ∆H vap = 38 kJ/mol. What is the ∆Scrap value
Answer:
ΔSv = 0.1075 KJ/mol.K
Explanation:
Binary solution:
∴ a: solvent
∴ b: solute
in equilibrium:
μ*(g) = μ(l) = μ* +RTLnXa....chemical potential (μ)⇒ Ln (1 - Xb) = ΔG/RT
∴ ΔG = ΔHv - TΔSv
⇒ Ln(1 -Xb) = ΔHv/RT - ΔSv/R
∴ Xb → 0:
⇒ Ln(1) = ΔHv/RT - ΔSv/R
∴ T = T*b....normal boiling point
⇒ 0 = ΔHv/RT*b - ΔSv/R
⇒ ΔSv = (R)(ΔHv/RT*b)
⇒ ΔSv = ΔHv/T*b
∴ T*b = 80°C ≅ 353 K
⇒ ΔSv = (38 KJ/mol)/(353 K)
⇒ ΔSv = 0.1075 KJ/mol.K
What is the best method for removing water from a hydrated compound?
Answer:
Heating is the best method
Explanation:
When a mass of crystals containing Water of crystallization is heated sufiiciently to a high temperature, water vapor may be driven off the crystals by the action of heat alone.
Answer:
Heating to remove water of crystallizationPassing through a drying agent (deliquescent or hygroscopic substances)Explanation:
If solid/crystals, compound can be dried by applying heat to remove the water of crystallization.
Drying agents are also utile in removing moisture from compounds in a dessicator. Substances which absorb water from air can be used as drying agents for gases. For instance, [tex]CaCl_{2}[/tex], CaO or silica gel is suitable for drying gases, depending on reactivity of the substance.
The volume of a sample of N2 gas was decreased from 13.81 to 3.63 L. If the final pressure exerted by the N2 sample was 261.1 kPa, what pressure did the N2 exert before its volume was decreased?
Answer: 68.6 kPa
Explanation:
To calculate the new pressure, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.
The equation given by this law is:
[tex]P_1V_1=P_2V_2[/tex]
where,
[tex]P_1\text{ and }V_1[/tex] are initial pressure and volume.
[tex]P_2\text{ and }V_2[/tex] are final pressure and volume.
We are given:
[tex]P_1=?\\V_1=13.81L\\P_2=261.1kPa\\V_2=3.63L[/tex]
Putting values in above equation, we get:
[tex]P_1\times 13.81L=261.1\times 3.63L\\\\P_1=68.6kPa[/tex]
Thus pressure before its volume was decreased was 68.6 kPa
In these solutions, identify the solute and the solvent. Sea water, a solution composed of a variety of salts dissolved in water. The salt is the . Soda water, a solution composed of carbon dioxide gas dissolved in water. The water is the Air, a solution composed of 78% nitrogen and 21% oxygen. The nitrogen is the .
Answer:
The solvent is Nitrogen and the solute is oxygen
Explanation:
Normally the solvent always contains higher amount of substance than the solute in a particular solution
Answer:
Sea water, a solution composed of a variety of salts dissolved in water. The salt is the SOLUTE
Soda water, a solution composed of carbon dioxide gas dissolved in water. The water is the SOLVENT
Air, a solution composed of 78% nitrogen and 21% oxygen. The nitrogen is the SOLVENT
Explanation:
its right on EDGE
Due to the small and highly electronegative nature of fluorine, the oxyacids of the this element are much less common and less stable than those of the other halogens. Bonding theory, however, does allow one to propose structures for these acids and use formal charges for the evaluation of these structures. For a molecule of fluorous acid, the atoms are arranged as HOFO. (Note: In this oxyacid, the placement of fluorine is an exception to the rule of putting the more electronegative atom in a terminal position.) What is the formal charge on each of the atoms?
Answer:
HOFO = (0, 0, +1, -1)
Explanation:
The formal charge (FC) can be calculated using the following equation:
[tex] FC = V - N - \frac{1}{2}B [/tex]
Where:
V: are the valence electrons
N: are the nonbonding electrons
B: are the bonding electrons
The arrange of the atoms in the oxyacid is:
H - O₁ - F - O₂
Hence, the formal charge (FC) on each of the atoms is:
H: FC = 1 - 0 - 1/2*(2) = 0
O₁: FC = 6 - 4 - 1/2*(4) = 0
F: FC = 7 - 4 - 1/2*(4) = +1
O₂: FC = 6 - 6 - 1/2*(2) = -1
We can see that the negative charge is in the oxygen instead of the most electronegative element, which is the F. This oxyacid is atypical.
I hope it helps you!
A sample of a gas is contained in a closed rigid cylinder. According to the kinetic molecular theory, what occurs when the gas inside the cylinder is heated?
Answer:
When heating, the temperature is increased, therefore, the average kinetic energy is increased so the molecules will start moving more rapidly.
Explanation:
Hello,
Kinetic molecular theory is based on a series of specific statements:
- Gases are constituted by a raft of particles that are considered as both hard and spherical bodies under a state of constant and random movement.
- The particles are constantly moving in a straight line until they collide to each other or against walls of the container.
- There is no force of attraction nor repulsion among gas particles or among the particles and the walls of the container.
- Collisions are said to be perfectly elastic.
- The average kinetic energy of a raft of gas particles is temperature-dependent only.
- The higher the temperature the higher the average kinetic energy of the gas and the other way around.
In such a way, considering the last two statements, when heating, the temperature is increased, therefore, the average kinetic energy is increased so the molecules will start moving more rapidly in comparison to the initial state.
Best regards.
Which of the following best defines an acid?
An acid has a pH of 7.
An acid has hydroxide ions.
An acid has fewer positive ions in solution.
An acid has more hydrogen ions in solution.
Answer: An acid has more hydrogen ions in solution.
Explanation: Acids increase hydrogen/hydronium ion concentration in a solution, have pH's less than seven, have a low hydroxide concentration, and increase positive ions in a solution.
The correct definition of an acid is: An acid has more hydrogen ions in solution. Thus, the correct answer is option with 'An acid has more hydrogen ions in solution'.
An acid is characterized by its ability to increase the concentration of hydrogen ions (H⁺) when dissolved in water. This results in a pH lower than 7, indicating increased acidity. The pH scale measures the acidity or basicity of a solution; acids have pH values less than 7.
For example, hydrochloric acid and vinegar are common acids, and they taste sour.Let's understand other options given:
An acid has a pH of 7:
Incorrect. A pH of 7 is neutral. Acids have a pH less than 7.An acid has hydroxide ions:
Incorrect. Hydroxide ions (OH⁻) are associated with bases, not acids.An acid has fewer positive ions in solution:
Incorrect. This is not a defining characteristic of acids. Acids specifically have more hydrogen ions (H⁺), which are positive ions.Therefore, the defining characteristic of an acid is the presence of more hydrogen ions (H⁺) in solution.
Which traits explain the differences between halogens and alkali metals? Select all that apply Question 5 options: Halogens are better oxidizing agents than their alkali metal counterparts within the same period. Halogens have a larger van der Waal's radii than their alkali metal counterparts within the same period. Halogens have a higher effective nuclear charge than their alkali metal counterparts within the same period. Halogens have a higher first ionization energy than their alkali metal counterparts within the same period. Halogens have a higher electron affinity than their alkali metal counterparts within the same period.
Answer:
Halogens are better oxidizing agents than their alkali metal counterparts within the same period
Halogens have a higher first ionization energy than their alkali metal counterparts within the same period.
Halogens have a higher electron affinity than their alkali metal counterparts within the same period.
Halogens have a higher effective nuclear charge than their alkali metal counterparts within the same period
Explanation:
Effective nuclear charge increases across a period and accounts for increase in ionization energy across a period. This explains why halogens in the same period with alkali metals have higher effective bucket charge as well as ionization energy than the alkali metals.
Similarly, electron affinity increased across a period, halogens have greater ekctron affinity than corresponding alkali metals in the same period.
How many moles of CH3OH are there in 43.7 mL of 0.400 M CH30
Answer:
0.0174 mol
Explanation:
Molarity is (moles of solute)/(liters of solvent). So, to find moles you need to multiply liters by molarity.
0.0437 L × 0.400 M = 0.0174 mol
The number of moles of CH₃OH present is 0.01748 mole
From the question,
We are to determine the number of moles of CH₃OH that are in 43.7 mL of 0.400 M CH₃OH
Using the formula
Number of moles = Concentration × Volume
From the question
Concentration of CH₃OH = 0.400 M
Volume of CH₃OH = 43.7 mL = 0.0437 L
∴ Number of moles of CH₃OH present = 0.400 × 0.0437
Number of moles of CH₃OH present = 0.01748 mole
Hence, the number of moles of CH₃OH present is 0.01748 mole
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*multiple choice*
What is the molarity of a 45.3g sample of KNO3 (101g) dissolved in enough water to make a 0.225L solution?
a) 0.45
b) 2
c) option 3
d) none of the above
1.95 or 2 is the molarity of a 45.3g sample of KNO3 (101g) dissolved in enough water to make a 0.225L solution.
The correct answer is option b
Explanation:
Data given:
mass of KN[tex]O_{3}[/tex] = 45.3 grams
volume = 0.225 litre
molarity =?
atomic mass of KNO3 = 101 grams/mole
molarity is calculated by using the formula:
molarity = [tex]\frac{number of moles}{volume of the solution}[/tex]
first the number of moles present in the given mass is calculated as:
number of moles = [tex]\frac{mass}{atomic mass of 1 mole}[/tex]
number of moles = [tex]\frac{45.3}{101}[/tex]
0.44 moles of KNO3
Putting the values in the equation of molarity:
molarity = [tex]\frac{0.44}{0.225}[/tex]
molarity = 1.95
It can be taken as 2.
The molarity of the potassium nitrate solution is 2.
What is the acronym used to remember if the anode/cathode are negative or positive (Acronym is like L.E.O says G.E.R) *
Answer:
Explanation:
The terms 'anode' and 'cathode' are applied to electrodes based on the chemistry occurring at a specified electrode. That is, the anode is ALWAYS the site of oxidation and the cathode is ALWAYS the site of the reduction reaction in electrochemical process. The charge (+ or -) results from the chemistry. In Voltaic Cells the anode is always the site of oxidation and is negative (-) and the cathode is the site of reduction and is always positive (+). However, in 'Electrolytic Cells' the charges are opposite at the electrodes. That is, at the electrode where oxidation is taking place in the electrolytic cell the charge on the electrode will be positive (+) and the charge on the electrode where reduction is taking place the charge will be negative (-).
As far as acronyms (or memory devices) one might consider each type cell separately...
Voltaic Cells
Anode => A Negative -ode (always site of oxidation) ... the other electrode is positive and site of reduction.
Electrolytic Cells
For electrolytic cells, just remember the electrode charges are opposite those of the Voltaic Cell but the chemistry is always the same. Charge is due to chemistry and type of cell, but anode is always oxidation and cathode is always reduction.
During a volcanic eruption, large amounts of poisonous gases and particles are released into the atmosphere. How do some of these gases eventually reach the Earth's surface?
A) through rain
B) through wind
C) through lava
D) through trees
The gases eventually reach the Earth's surface through rain. Hence option A is correct.
What is volcanic eruption?Volcanic eruption is defined as when a volcano erupts, sometimes violently spewing lava and gas into the air. Volcanoes erupt with a powerfully destructive mixture of ash, lava, hot, toxic gases, and rock. Explosions from volcanoes have claimed lives. Volcanic eruptions can bring forth additional health risks such wildfires, floods, mudslides, electricity outages, and contaminated drinking water.
During a volcanic eruption, water vapor (H2O), carbon dioxide (CO2), and sulfur dioxide make up 90% of the gas molecules released (SO2). The remaining one percent is made up of trace amounts of hydrogen sulfide, carbon monoxide, hydrogen chloride, hydrogen fluoride, and other small gas species.
Thus, the gases eventually reach the Earth's surface through rain. Hence option A is correct.
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Briefly describe the solvation of sodium chloride to form aqueous solution.
Nascar fans love race day when they get a chance to cheer on there favorite racer if a driver was able to travel 600 miles in 3 hours what was his average speed ( in miles per hour
Answer:
200 mph
Explanation:
600/3=200
How many moles are in 36.0g of H20
Answer:
The answer to your question is 2 moles
Explanation:
Data
mass of H₂O = 36 g
moles of H₂O = ?
Process
1.- Calculate the molar mass of water (H₂O)
H₂O = (1 x 2) + (16 x 1) = 2 + 16 = 18 g
2.- Use proportions and cross multiplication to find the answer.
18 g of H₂O ---------------- 1 mol
36 g of H₂O --------------- x
x = (36 x 1) / 18
x = 36/18
x = 2 moles
Solid NaCl is added slowly to a solution containing 0.10M AgNO3 and 0.20M Pb(NO3)2. Ksp AgCl = 1.8 E-10 Ksp PbCl2 = 1.6 E-5 Write a net ionic equation and corresponding Ksp expression for the dissolution of solid i. Silver Chloride (AgCl) ii. lead (II) chloride (PbCl2) How do I do this?
Answer:
Ag+(aq) + Cl-(aq) <--->AgCl(s)
Ksp = [Ag+] [Cl-]
aii) Pb2+(aq) + 2Cl-(aq) <--->PbCl2(s)
Ksp = [Pb+] [Cl-]^2
Explanation:
In this question, we are to write the net ionic equation and corresponding Ksp expression for the salts in the question.
We proceed as follows;
Ag+(aq) + Cl-(aq) <--->AgCl(s)
Ksp = [Ag+] [Cl-]
aii) Pb+2(aq) + 2Cl-(aq) <--->PbCl2(s)
Ksp = [Pb+] [Cl-]^2
Final answer:
To write net ionic equations for AgCl and PbCl2, the equations are AgCl(s)
ightarrow Ag+(aq) + Cl-(aq) with Ksp = [Ag+][Cl-], and PbCl2(s)
ightarrow Pb2+(aq) + 2Cl-(aq) with Ksp = [Pb2+][Cl-]^2. These represent the dissolution of silver chloride and lead (II) chloride, respectively.
Explanation:
To write the net ionic equations and corresponding Ksp expressions for the dissolution of solid silver chloride (AgCl) and lead (II) chloride (PbCl2), you should consider both substances dissolving separately in water:
AgCl
Net ionic equation: AgCl(s)
ightarrow Ag+(aq) + Cl-(aq)
Ksp expression: Ksp = [Ag+][Cl-]
This represents the solubility product for silver chloride, which is given as 1.8 imes 10^-10.
PbCl2
Net ionic equation: PbCl2(s)
ightarrow Pb2+(aq) + 2Cl-(aq)
Ksp expression: Ksp = [Pb2+][Cl-]^2
This represents the solubility product for lead (II) chloride, which is given as 1.6 imes 10^-5. Note that because there are two chloride ions for every lead ion that dissolves, the concentration of chloride appears squared in the expression.
The pressure on a 200 milliliter sample of CO2 (g) at constant temperature is increased from
600 mmHg to 1200 mmHg. What is the new volume?
(1 Point)
100 mL
300 mL
400 ml
600 mL
The answer for the following problem is mentioned below.
Therefore the final volume of the gas is 100 ml.Explanation:
Given:
Initial pressure ([tex]P_{1}[/tex]) = 600 mm of Hg
Final pressure ([tex]P_{2}[/tex]) = 1200 mm of Hg
Initial volume ([tex]V_{1}[/tex]) = 200 ml
To find:
Final volume ([tex]V_{2}[/tex])
We know;
According to the ideal gas equation,
P × V = n × R × T
Where;
P represents the pressure of the gas
V represents the volume of the gas
n represents the no of moles of the gas
R represents the universal gas constant
T represents the temperature of the gas
So,
From the above mentioned equation,
P × V = constant
[tex]\frac{P_{1} }{P_{2} }[/tex] = [tex]\frac{V_{1} }{V_{2} }[/tex]
Where,
([tex]P_{1}[/tex]) represents the initial pressure of the gas
([tex]P_{2}[/tex]) represents the final pressure of the gas
([tex]V_{1}[/tex]) represents the initial volume of the gas
([tex]V_{2}[/tex]) represents the final volume of the gas
So;
[tex]\frac{600}{1200}[/tex] = [tex]\frac{V_{2} }{200}[/tex]
[tex]V_{2}[/tex] = 100 ml
Therefore the final volume of the gas is 100 ml.
Final answer:
Using Boyle's Law, which states that the product of pressure and volume for a gas is constant at a fixed temperature, it is calculated that the new volume of the CO2 (g) sample when the pressure is doubled to 1200 mmHg at constant temperature is 100 mL.
Explanation:
The question asks about the change in volume of a gas sample when the pressure is increased while keeping the temperature constant. This scenario is described by Boyle's Law, which states that for a given mass of gas at constant temperature, the volume of the gas varies inversely with the pressure. The initial condition for the CO2 (g) is 200 mL at 600 mmHg, and after the pressure is increased to 1200 mmHg, we want to find the new volume.
Boyle's Law can be expressed as P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume, respectively. Using this relationship, when P1 = 600 mmHg, V1 = 200 mL, P2 = 1200 mmHg, we need to solve for V2. When we plug these values into the equation, we get V2 = (P1 * V1) / P2 = (600 mmHg * 200 mL) / 1200 mmHg = 100 mL.
Therefore, the new volume of the CO2 (g) sample when the pressure is increased to 1200 mmHg at constant temperature is 100 mL.
18.53 For CaO, the ionic radii for Ca2 and O2 ions are 0.100 and 0.140 nm, respectively. If an externally applied electric field produces a 5% expansion of the lattice, compute the dipole moment for each Ca2O2pair. Assume that this material is completely unpolarized in the absence of an electric field.
Answer:
[tex] = 1.92*10^-^3^0 C.m[/tex]
Explanation:
Given:
[tex] r_ca_^2_^+ = 0.100 nm[/tex]
[tex] r_o_^2_^- = 0.14 nm [/tex]
Let's find the distance of separation between cation and anion when there is no applied electric field with the formula:
[tex] d = r_ca_^2_^+ + r_o_^2_^- [/tex]
d = 0.100 nm + 0.140 nm
= 0.240 nm
Let's also calculate the distance of separation between anion and cation when there is an applied electric field.
We use the formula:
∆d = 5%d => 0.05d
= 0.05 * 0.024 nm
∆d = 0.0120 nm
[tex]0.120* 10^-^9m[/tex]
[tex]= 1.20*10^-^1^1m[/tex]
Given magnitude of each dipole= [tex]1.602*10^-^1^9 C [/tex]
Let's find the dipole moment, with the formula:
p = q∆d
Substituting figures in the formula, we have:
[tex]p = 1.602*10^-^1^9 * 12*10^-^2^1 [/tex]
[tex] = 1.92*10^-^3^0 C.m[/tex]
Answer:
Explanation:
Answer:
= 1.92*10^-^3^0 C.m
Explanation:
Given:
r_ca_^2_^+ = 0.100 nm
r_o_^2_^- = 0.14 nm
Let's find the distance of separation between cation and anion when there is no applied electric field with the formula:
d = 0.100 nm + 0.140 nm = 0.240 nm
Let's also calculate the distance of separation between anion and cation when there is an applied electric field.
We use the formula:
∆d = 5%d => 0.05d
= 0.05 * 0.024 nm
∆d = 0.0120 nm
0.120* 10^-^9m
= 1.20*10^-^1^1m
Given magnitude of each dipole= 1.602*10^-^1^9 C
Let's find the dipole moment, with the formula:
p = q∆d
Substituting figures in the formula, we have:
p = 1.602*10^-^1^9 * 12*10^-^2^1
= 1.92*10^-^3^0 C.m