Question: You have an apple tree that produces high-quality apples in large numbers. The tree is also resistant to a number of harmful conditions and pests. Which is the best way to grow more such trees in your orchard?
Options:
A. grafting
B. greenhouse technology
C. layering
D. tissue culture
The best method for growing more trees with identical traits to an original apple tree would be grafting. This technique allows the same desirable traits, such as pest-resistance and high-quality fruit production, to be replicated in new trees.
Explanation:To produce more apple trees with the same high-quality fruit as your original tree, the best method would be A. grafting. Grafting is a horticultural technique where tissues of one plant are joined to those of another so that the two sets of vascular tissues may join together. This is commonly used in asexual propagation of apple trees and other commercially grown crops to replicate desired qualities. The grafted new apple trees would share the same genetic makeup and hence, inherit the desirable traits like pest-resistance, large amounts of high-quality fruit production as the original apple tree.
Methods like greenhouse technology, layering, and tissue culture can also be used to grow more trees, but grafting is most efficient and commonly used when you want to replicate the exact traits of a particular tree such as your high-yielding apple tree.
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How much electrical potential energy is stored in a capacitor that has 8.0 × 10-10 C of charge on each plate and a potential difference across the plates of 20.0 V?
A. 1.0 × 10-11 J
B. 8.0 × 10-9 J
C. 4.0 × 10-9 J
D. 2.0 × 10-11 J
The electrical potential energy stored in a capacitor is found using the formula U = QV / 2. For a charge of 8.0 × 10⁻¹⁰ C and a potential difference of 20.0 V, the energy stored is 8.0 × 10⁻⁹ J, which corresponds to option B.
To find the electrical potential energy (U) stored in a capacitor, we use the formula:
U = QV / 2
where
Q is the charge on one plate and
V is the potential difference across the plates.
Given a charge (Q) of 8.0 × 10⁻¹⁰ C (coulombs) and a potential difference (V) of 20.0 V (volts), we can calculate the energy stored as follows:
U = (8.0 × 10⁻¹⁰ C)
× (20.0 V) / 2
= 160 × 10⁻¹⁰ J / 2
= 80 × 10⁻¹⁰ J
= 8.0 × 10⁻⁹ J
Therefore, the correct option for the energy stored in the capacitor is B. 8.0 × 10⁻⁹ J.
Children and adolescents should do ____ hour or more of physical activity every day.
A 5
B 7
C 3
D 1
A raft with the area A , thickness= h and the mass 600 kg, Floats in still water with 7 cm
under the water surface. When Bubba stands on the raft it sinks down further in the water so
the raft is 8.4 cm under the water surface. What is Bubba's mass?,
In this problem, we need to solve for Bubba’s mass. To do this, we let A be the area of the raft and set the weight of the displaced fluid with the raft alone as ρwAd1g and ρwAd2g with the person on the raft, where ρw is the density of water, d1 = 7cm, and d2= 8.4 cm. Set the weight of displaced fluid equal to the weight of the floating objects to eliminate A and ρw then solve for m.
ρwAd1g = Mg
ρwAd2g = (M + m) g
d2∕d1 = (M + m)/g
m = [(d2∕d1)-1] M = [(8.4 cm/7.0 cm) - 1] (600 kg) =120 kg
This means that Bubba’s mass is 120 kg.
In the following diagram, the clockwise torque is equal to _____.
10 Nm
80 Nm
400 Nm
500 Nm
In the following diagram, the clockwise torque is equal to 80 N-m.
What is torque?The force that can cause an object to rotate along an axis is measured as torque. Similar to how force accelerates an item in linear kinematics, torque accelerates an object in an angular direction. A vector quantity is a torque.
Torque is defined as Γ=r×F=rFsin(θ). In other words, torque is the cross product of the force vector, where 'a' is the angle between r and F, and the distance vector (the distance between the pivot point and the place where force is applied).
In the following diagram, the clockwise torque is equal to 80 N-m.
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A tow can pull a car out of a ditch in 7.5 seconds. How many work is done if the truck has power of 5500 watts?
A charge of 50 µC is pushed by a force of 25 µN a distance of 15 m in an electric field. What is the electric potential difference? Recall that Fe = qE.
Answer:
ΔV = 7.5 V
Explanation:
Can you help me with a Chemistry question? I will give a medal and become a fan of the person with the BEST answer
Which of the following elements is most likely to form an ion that will then form an ionic bond with an ion of a Group 1A element?
A) Pt
B) I
C) Fr
D)Be,
Which phrase defines gross domestic product (GDP)
The temperature of a substance during an experiment can be modeled by the function f(x)=−7.5cos(πx30)+31.4 , where f(x) is the temperature °c and x is the number of minutes into the experiment. what is the greatest temperature the substance reached during the experiment?
Answer : [tex]f(x)=38.9^0\ C[/tex]
Explanation :
It is given that,
The temperature of a substance during an experiment is given by a function as :
[tex]f(x)=-7.5cos(\dfrac{\pi x}{30})+31.4[/tex]................(1)
Where,
f(x) is the temperature
and x is the time.
So, for getting a maximum temperature the substance reached during the experiment the value of [tex]cos( \dfrac{\pi x}{30})[/tex] should by minimum.
We know that the value of cos is minimum at [tex]\pi[/tex].
So, [tex]cos( \dfrac{\pi x}{30})=cos\pi[/tex]
We get, x = 30
Put the value of x in equation (1)
[tex]f(x) = -7.5cos(\dfrac{\pi \times 30}{30})+31.4[/tex]
Since, [tex]cos \pi=-1[/tex]
[tex]f(x)=38.9^0\ C[/tex]
So, the greatest value of temperature the substance reached during the experiment is [tex]f(x)=38.9^0\ C[/tex].