a 3 kg piece of putty that is moving with a velocity of 10 m/s collides and sticks to an 8 kg bowling ball that was at rest. what is their velocity as they roll away together

Answer:

The mass of the earth is, M = 5.98 x 10²⁴ kg

Explanation:

Given data,

The acceleration due to gravity, g = 9.8 m/s²

The radius of Earth, R = 6400 km

                                    =6.4 x 10⁶ m

The universal gravitational constant, G = 6.67 x 10 ⁻¹¹ Nm²kg⁻²

Using the equation,

                         GM = gR²

                            M = gR² / G

Substituting the values,

                            M = 9.8 x (6.4 x 10⁶)² / 6.67 x 10 ⁻¹¹

                                = 5.98 x 10²⁴ kg

Hence, the mass of the earth is, M = 5.98 x 10²⁴ kg

Answer:

The time taken to travel is, t = 12 minutes

Explanation:

Given data,

The speed of the car, v = 60 km/h

The distance of travel, d = 12 km

The time taken for the travel is t = ?

The speed is defined as the distance divided by the time taken to travel. The formula for speed is,

                                  v = d/t

∴                                  t = d/v

                                    t = 12 km / 60 km/h

                                    t = 0.2 h

                                     t = 12 minutes

Hence, the time taken to travel is, t = 12 minutes.

Given that the average speed of the car is 60 km/hr and it needs to travel a distance of 12 km, it will take the car around 0.2 hours, which is equivalent to 12 minutes, to travel this distance.

This problem is related to the concept of speed, which in physics, is the distance covered per unit time. Here, we are asked to find the time so, we will use the formula for calculating time which is Time = Distance / Speed.

Given:

So, time needed can be calculated as:

Time = Distance / Speed

Time = 12 km / 60 km/hr

This gives Time = 0.2 hr.

But as we generally count time in minutes, we can convert hours into minutes. Since 1 hour = 60 minutes, therefore, 0.2 hr = 0.2 x 60 = 12 minutes.

So, it takes 12 minutes to travel 12 kilometers with an average speed of 60 kilometers per hour.

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The forces that act upon a baseball player diving head-first into second base and sliding on the infield dirt are the Normal Force, Gravity Force, and Friction Force.

When a baseball player dives head-first into second base and slows down while sliding on the infield dirt, several forces act upon the player. These forces include:

Therefore, the correct answers would be a. Normal Force, b. Gravity Force, d. Friction Force.

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Answer:

x-axis

Explanation:

when it is at rest, horizontal, on a graph it is the x-axis.

Hope this helped!

Answer:

v = 4t - t²/3

Explanation:

4 - k*6 = 0

k = 4/6 = 2/3

dv/dt = 4- 2/3 t

integral of dv = integral of (4-2/3 t) dt

v = 4t - t²/3

Answer:

look at the explanation

Explanation:

This pith-ball electroscope is used to detect the presence of a static electricity charge. The two lightweight “pith” balls suspended from the strings are attracted to objects with a static electric charge. The pith balls can also be charged by touching them to an object with a static electric charge.

Answer:

"The Sierra Nevada mountain range of western North America, running along the eastern edge of the U.S. state of California."

Explanation:

Block Mountains:

Due, to stress created in side the crust of the earth the blocks or pieces of land or mass of land is created. In the past due to natural disaster and events that occurred in the ancient world, left us with some natural phenomenons called as block mountains. As the natural forces like seismic waves and other volcanic eruptions leads to such a disastrous amount of force that uplifts the mass of land on which it is acted upon.

Characteristics of the Block Mountains:

Types:

There are two main types of the block mountains,which are as below:

Answer:

The change in momentum of the car is  30,000 kg m/s                  

Explanation:

Given,

The force exerted on the car to slow down, F = 7500 N

The time period of force, t = 4 s

The rate of change of momentum of the object is equal to the force acting on it.

Therefore,

                                    (mv - mu) / t = F

Where v and u are the final and initial velocity of the car. The change in momentum of the car,

                                    mv - mu = F x t

                                                   = 7500 x 4

                                                   = 30,000 kg m/s

Hence the change in momentum of the car is  30,000 kg m/s                  

Answer:

The height of the hill is, h = 38.42 m

Explanation:

Given,

The horizontal velocity of the soccer ball, Vx = 15 m/s

The range of the soccer ball, s = 42 m

The projectile projected from a height is given by the formula

                             S = Vx [Vy + √(Vy² + 2gh)] / g

Therefore,

                            h = S²g/2Vx²                     (Since Vy = 0)

Substituting the values

                             h = 42² x 9.8/ (2 x 15²)

                                = 38.42 m

Hence, the height of the hill is, h = 38.42 m

Answer:

flexibility

Explanation:

Answer:

15N

Explanation:

According to Newton's Second Law of Motion

F = m*a

mass = m = 5Kg

acceleration = a = 3m/s^2

=> F = 5kg * 3m/s^2

=> F = 15 N

F = m a

The force is (5kg)x(3 m/s^2)= 15 Newtons, and it's still there.

If the force stops, the acceleration stops.

Answer:

Part 1.:  Work done by the force is 3461 J

Part 2: Work done by the force of friction is 972.8 J

Explanation:

part 1.

Since the displacement is horizontal, the only component of the 88.2 N force applied on the block is the horizontal component (which carries the cos(26.9) (the cosine of the angle with the horizontal). Then the component of the force acting on the 44 m displacement is: 88.2 * cos(26.9) . Then the work done by this component can be found by multiplying this quantity times the displacement (44 m), which gives:

88.2 * cos (26.9) * 44 = 3460.8878 J

which we can round to the nearest whole number as: 3461 J

Part 2.

The force of kinetic friction is the product of the normal force exerted by the surface on the block, times the coefficient of kinetic friction. Now the surface reacts with the normal force opposing the net vertical force applied by the block on the surface. Notice that in this case, the normal force doesn't just oppose the weight (m * g) of the object, since there is a vertical component of the external 88.2 N force ( the one that uses the sin(26.9) ) that is acting opposite to the gravitational force. This pointing upwards force component is going to subtract from the weight, thus making the normal force smaller than what it would be if just the object's weight was acting vertically. In magnitude, this is the normal force calculation:

Normal = Weight - 88.2 * sin(26.9)

Normal = [17.5 * 9.8 - 88.2 * sin(26.9) ] N

Normal = 131.6 N

At this point, we can calculate the value of the force of kinetic friction (product between the normal force and the coefficient of kinetic friction):

Kinetic friction force: 0.168 * 131.6 N = 22.1088 N

Now the product of this force times the displacement will give us the magnitude of the work done by the force of friction:

22.1088 N * 44 m = 972.7872 J

that we can round to 972.8 J

It is important to notice that the work done by the force of friction is negative due to the fact that the force acts opposite to the displacement of the block.

Answer:

B

Explanation:

F = ma , a = F/m

a1 = F/10 and a2 = F/4

Since Force is constant, a2 will we greater than a1

The current in the circuit is 5 A

Explanation:

The intensity of current is given by the equation:

[tex]I=\frac{q}{t}[/tex]

where

I is the current

q is the amount of charge passing through a given point of the circuit in a time interval of t

For the cell in this problem, we have

q = 150 C is the charge

t = 30 s is the time interval

Substituting into the equation, we f ind

[tex]I=\frac{150}{30}=5 A[/tex]

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Answer:

c. 75 joules

Explanation:

Work done(joules)=Force(newton)×Distance(meters)

Given: force=150-newton, Distance=0.5 meters

∴Work done=150×0.5=75 joules.

The amount of work done on the bucket will be 75 joules. Option C is correct.

Work done is defined as the product of applied force and the distance through which the body is displaced on which the force is applied.

Work may be zero, positive and negative.it depends on the direction of the body displaced. if the body is displaced in the same direction of the force it will be positive.

The given data in the problem is;

F is the force lift = 150-

d is the displacement = 0.5 meters

t is the time = 3 second

W is the amount of work done

The amount of work done on the bucket is found as;

[tex]\rm W = F \times d \\\\ W = 150 \times 0.5 \\\\ W=75 \ Joule[/tex]

Hence the amount of work done on the bucket will be 75 joules. Option C is correct.

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Answer:

Mass has total mechanical energy, which is the sum of kinetic and potential energy. as the mass is dropping, potential energy is converted into kinetic energy so mechanical energy is preserved If there is no friction. If there is friction, some of the mechanical energy is lost as heat energy so it changes.

Explanation:

Answer:

Temperature decreases because the number of collision of the molecules decreases as they escape or evaporate. Molecules are in constant motion. Increase in temperature leads to increase in average kinetic energy of the molecules.

The kinetic theory of matter states that all matter is made up of tiny particles that are constantly moving. The faster the particles are moving, the higher the temperature of the matter.

When a liquid evaporates, the fastest-moving particles are the ones that are most likely to escape from the surface of the liquid. This leaves behind the slower-moving particles, which means that the average temperature of the liquid decreases.

Another way to think about it is that evaporation is a cooling process because it removes the fastest-moving particles from the liquid. These particles have the most kinetic energy, so their removal lowers the average kinetic energy of the remaining particles and thus lowers the temperature of the liquid.

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Answer:

"What is the best advice a parent can give a child?"

Explanation:

The other answers have one clear response. Ex: Orange popsicles melt faster than grape popsicles. That would be a fact.

But parental advice can vary, depending on your opinion. I may say that all parents must teach their children not to talk to strangers, while someone else may say that parents should advice their kids to treat everyone fairly. Nothing can be proven as the only appropriate response.

Hope this helps!

Answer:

336.9520 atm

Explanation:

The Gas Equation is as follows;-

Pressure×Volume=Number of Moles × Universal Gas Constant ×Temperature(in Kelvin)

Given Parameters

Number of moles-0.614 mol

Temperature 12°C or 12+273.15 ie 285.15°F

Volume-4.32 L

Universal Gas Constant-8.314 J/mol·K

Pressure -?(in atm)

Plugging in all the values in the Gas Equation:-

Pressure=[tex]\frac{0.614 × 8.314× 285.15}{4.32}   atm[/tex]

Pressure=336.9520 atm

Answer:

The speed of a turtle is 4m/s

Explanation:

speed = distance/time

distance = 100m

time = 25s

s = 100/25

= 4m/s

Answer: 20m/s

Explanation:

Data;

Distance (s) = 100m

Time (t) = 25s

Velocity (v) = s/t

v = 100/25

v = 20m/s

The acceleration of the racing car is 2 m/s² and the displacement over the 11 seconds is 605 m.

The given physics problem involves calculating the acceleration and the displacement of a racing car that has increased its velocity from 44 m/s to 66 m/s in a time interval of 11 seconds.

To find the acceleration, we use the formula for average acceleration, which is the change in velocity divided by the time taken. The change in velocity (Δv) is 66 m/s - 44 m/s = 22 m/s. So, the acceleration (a) is 22 m/s divided by 11 s, which equals 2 m/s².

For the displacement, we can use the kinematic equation s = ut + 0.5at², where u is the initial velocity, a is the acceleration, and t is the time. With u = 44 m/s, a = 2 m/s², and t = 11 s, we get the displacement s = 44 m/s * 11 s + 0.5 * 2 m/s² * (11 s)², resulting in 484 m + 121 m, or a total displacement of 605 m.

The acceleration of the racing car is [tex]\( 2 \text{ m/s}^2} \)[/tex] and the displacement of the racing car during this time is [tex]\( 605 \text{ m}} \)[/tex].

To find the acceleration and displacement of the racing car, we will use the following kinematic equations:

1. Acceleration [tex](\(a\))[/tex]:

[tex]\[ a = \frac{\Delta v}{\Delta t} \][/tex]

2. Displacement [tex](\(s\))[/tex]:

[tex]\[ s = v_i t + \frac{1}{2} a t^2 \][/tex]

Step 1: Calculate the Acceleration

Given:

Initial velocity [tex](\(v_i\))[/tex]: 44 m/s

Final velocity [tex](\(v_f\))[/tex]: 66 m/s

Time interval [tex](\(\Delta t\))[/tex]: 11 s

The change in velocity [tex](\(\Delta v\))[/tex] is:

[tex]\[ \Delta v = v_f - v_i = 66 \text{ m/s} - 44 \text{ m/s} = 22 \text{ m/s} \][/tex]

Using the acceleration formula:

[tex]\[ a = \frac{\Delta v}{\Delta t} = \frac{22 \text{ m/s}}{11 \text{ s}} = 2 \text{ m/s}^2 \][/tex]

Step 2: Calculate the Displacement

Using the kinematic equation for displacement:

[tex]\[ s = v_i t + \frac{1}{2} a t^2 \][/tex]

Given:

Initial velocity [tex](\(v_i\))[/tex]: 44 m/s

Time [tex](\(t\))[/tex]: 11 s

Acceleration [tex](\(a\))[/tex]: [tex]2 m/s^2[/tex]

Substitute the values into the equation:

[tex]\[ s = 44 \text{ m/s} \times 11 \text{ s} + \frac{1}{2} \times 2 \text{ m/s}^2 \times (11 \text{ s})^2 \][/tex]

[tex]\[ s = 484 \text{ m} + \frac{1}{2} \times 2 \text{ m/s}^2 \times 121 \text{ s}^2 \][/tex]

[tex]\[ s = 484 \text{ m} + 1 \times 121 \text{ m} \][/tex]

[tex]\[ s = 484 \text{ m} + 121 \text{ m} \][/tex]

[tex]\[ s = 605 \text{ m} \][/tex]

Answer:

The acceleration of the train is 5 m/s².

Explanation:

Given:

let the initial velocity of a train = 5 m/s and

final velocity of a train = 45 m/s

time taken = 8 s

To find:

acceleration: ?

Solution:

We define acceleration as change in velocity per unit time that is the difference between the final velocity and initial velocity divided by time.

[tex]Acceleration = \frac{\textrm{final velocity} - \textrm{initial velocity}}{time} \\[/tex]

On substituting the above values we get the required acceleration

[tex]Acceleration = \frac{45 - 5}{8}\\ =\frac{40}{8}\\ =5\ m/s^{2}[/tex]

Therefore,the acceleration of the train is 5 m/s².

b) the net force on the car is zero.

Explanation:

Let's analyze each option one by one:

a) the force from the engine is greater than all the forces of friction.  --> FALSE. In fact, the car is moving at constant velocity: this means that its acceleration is zero,

a = 0

and so Newton's second law becomes

[tex]\sum F = ma = 0[/tex]

where [tex]\sum F[/tex] is the net force on the car and m is its mass. This means that the net force on the car is zero: so, the force from the engine cannot be greater than all the forces of friction, otherwise the net force cannot be zero.

b) the net force on the car is zero.  --> TRUE, for what we said at point A)

c) the inertia is changing.  --> FALSE. The inertia of an object just depend on the mass and the velocity of the object: as neither the mass nor the velocity are changing in this problem, then the inertia of the car is not changing.

d) the forces of friction are proportional to the acceleration of the car.  --> FALSE. Generally, the force of friction acting on an object moving on a flat surface is

[tex]F_f = \mu mg[/tex]

where [tex]\mu[/tex] is the coefficient of friction, m is the mass, and g the acceleration of gravity. Therefore, the force of friction does not depend on the acceleration of the car.

e) All of the above. --> FALSE

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An idea that is supported by some evidence, but is not yet the basis for a field of study is called a working theories.

Explanation:

The combined form of one’s skills, the work experiences from testing to reveal some truth about the issues or being involved one’s work in an experiment usually called as working theory.

These type of theories are more elaborate, interconnected, make some experiences with the solution to sort out the issues and seems to be useful in event monitoring. These can be supported with certain evidences but still not acting as the basement for the field study.

Final answer:

A hypothesis based on evidence that requires further investigation and testing before becoming a field of study.

Explanation:

A hypothesis is a suggested explanation based on evidence that can be tested through observation or experimentation. This idea is supported by some evidence but is not yet the basis for a field of study. Multiple strands of evidence are needed to potentially develop a verified theory.

Distance/ Time which means Distance is on horizontal and time is on vertical

Answer: An electroscope is a device that detects static electricity by using thin metal or plastic leaves, which separate when charged. ... Electrical charges move to the metal and down to the foil leaves, which then repel each other. Since each leaf has the same charge (positive or negative), they repel each other.

Answer:

An object with a suspected static electric charge is brought near the metal plate or ball of the electroscope. Electrical charges move to the metal and down to the foil leaves, which then repel each other. Since each leaf has the same charge (positive or negative), they repel each other.

Answer:

180

Explanation:

The Moon's surface gravity is about 1/6th as powerful or about 1.6 meters per second per second. The Moon's surface gravity is weaker because it is far less massive than Earth. A body's surface gravity is proportional to its mass, but inversely proportional to the square of its radius.

Answer:

160kg

Explanation:

Given m= 95kg g= 1.6345m/s²

Unknown Fg= ?

Formula Fg=mg

Fg=(95)(1.6345)

Fg= 155.2775

Fg=160kg

1) Mass of the continent: [tex]2.2\cdot 10^{21} kg[/tex]

2) Kinetic energy: 1118 J

3) Speed of the jogger: 5.3 m/s

Explanation:

1)

First of all, we calculate the volume of the continent. It is a slab of side

[tex]L=5100 km = 5.1\cdot 10^6 m[/tex]

and thickness

[tex]t=30 km = 3.0\cdot 10^4 m[/tex]

So its volume is

[tex]V=tL^2=(3.0\cdot 10^4)(5.1\cdot 10^6)^2=7.8\cdot 10^{17} m^3[/tex]

The density of the slab is

[tex]\rho = 2850 kg/m^3[/tex]

Therefore, we can calculate the mass using the relationship

[tex]\rho = \frac{m}{V}[/tex]

where m is the mass. And solving for m,

[tex]m=\rho V=(2850)(7.8\cdot 10^{17})=2.2\cdot 10^{21} kg[/tex]

2)

The kinetic energy of the continent is given by

[tex]K=\frac{1}{2}mv^2[/tex]

where

[tex]m=2.2\cdot 10^{21} kg[/tex] is its mass

v = 3.8 cm/year is its speed

We have to convert the speed into m/s. Keeping in mind that

1 cm = 0.01 m

[tex]1 year = 365\cdot 24\cdot 60 \cdot 60 =3.15\cdot 10^7 s[/tex]

We find

[tex]v=3.18 \frac{cm}{y} \cdot \frac{0.01}{365\cdot 24 \cdot 60 \cdot 60}=1.0\cdot 10^{-9} m/s[/tex]

So now we can find the kinetic energy:

[tex]K=\frac{1}{2}(2.2\cdot 10^{21})(1.0\cdot 10^{-9})^2=1118 J[/tex]

3)

The kinetic energy of the jogger is given by

[tex]K=\frac{1}{2}m'v'^2[/tex]

where

m' = 80 kg is the mass of the jogger

v' is the speed of the jogger

Here we want the jogger to have the same kinetic energy of the continent, so

[tex]K=1118 J[/tex]

And by re-arranging the equation, we can find what speed the jogger must have:

[tex]v'=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(1118)}{80}}=5.3 m/s[/tex]

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a) The frequency of the photon is [tex]7.16\cdot 10^{20}Hz[/tex]

b) The wavelength of the photon is [tex]4.19\cdot 10^{-13} m[/tex]

c) The wavelength of the photon is about 100 times larger than the nuclear radius

Explanation:

a)

The energy of a photon is given by

[tex]E=hf[/tex] (1)

where:

[tex]h=6.63\cdot 10^{-34} Js[/tex] is the Planck constant

f is the frequency of the photon

The photon in this problem has an energy of

[tex]E=2.5 MeV = 2.5\cdot 10^6 eV[/tex]

And keeping in mind that

[tex]1eV = 1.6\cdot 10^{-19} J[/tex]

we can convert to Joules:

[tex]E=(2.5\cdot 10^6)(1.9\cdot 10^{-19})=4.75\cdot 10^{-13} J[/tex]

And now we can use eq.(1) to find the frequency of the photon:

[tex]f=\frac{E}{h}=\frac{4.75\cdot 10^{-13}}{6.63\cdot 10^{-34}}=7.16\cdot 10^{20}Hz[/tex]

b)

The wavelength of a photon is related to its frequency by the equation

[tex]c=f\lambda[/tex]

where

[tex]c=3.0\cdot 10^8 m/s[/tex] is the speed of light

f is the frequency

[tex]\lambda[/tex] is the wavelength

For the photon in this problem,

[tex]f=7.16\cdot 10^{20}Hz[/tex]

Re-arranging the equation, we find its wavelength:

[tex]\lambda=\frac{c}{f}=\frac{3\cdot 10^8}{7.16\cdot 10^{20}}=4.19\cdot 10^{-13} m[/tex]

c)

The size of the nuclear radius is approximately

[tex]d \sim 10^{-15} m[/tex]

While we see that the wavelength of this photon is

[tex]\lambda=4.19\cdot 10^{-13} m[/tex]

Therefore, the ratio between the wavelength of the photon and the nuclear radius is

[tex]\frac{\lambda}{d}=\frac{\sim 10^{-13}}{\sim \cdot 10^{-15}}=100[/tex]

So, the wavelength of the photon is approximately a factor 100 times larger than the nuclear radius.

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