a 50kg box is being pushed along a horizontal surface. the coefficient of kinetic friction between the box and the ground is 0.35.what horizontal force must be exerted on the box for it to accelerate at 1.20m/s^2

Answers

Answer 1
For Newton's second law, the resultant of the forces acting on the box is equal to the product between the mass of the box m and its acceleration a:
[tex]\sum F = ma[/tex] 
We are interested only in what happens on the x-axis (horizontal direction). Only two forces act on the box in this direction: the force F, pushing the box along the surface, and the frictional force [tex]F_f = \mu m g[/tex] which has opposite direction of F (because it points against the direction of the motion). Therefore we can rewrite the previous equation as
[tex]F-F_f = ma[/tex]
and solve to find F:
[tex]F=ma+F_f =m(a+\mu g)=(50 kg)(1.2 m/s^2+(0.35)(9.81 m/s^2))=[/tex]
[tex]=232 N[/tex]
Answer 2

Answer:

Net horizontal force, [tex]F_{net}=231.5\ N[/tex]

Explanation:

It is given that,

Mass of the box, m = 50 kg

The coefficient of kinetic friction between the box and the ground is 0.35, [tex]\mu=0.35[/tex]

Acceleration of the box, [tex]a=1.2\ m/s^2[/tex]

We know that the frictional force acts in opposite direction to the direction of motion. The net force acting on it is given by :

[tex]F_{net}=f+ma[/tex]

[tex]F_{net}=\mu mg+ma[/tex]

[tex]F_{net}=m(\mu g+a)[/tex]

[tex]F_{net}=50\times (0.35\times 9.8+1.2)[/tex]

[tex]F_{net}=231.5\ N[/tex]

So, the net force acting on the box is 231.5 N. hence, this is the required solution.


Related Questions

When the metallic body of a car is moved into a painting chamber, a mist of electrically neutral paint is sprayed around the car. when the car is given a sudden electric charge, the mist is attracted to it, and the car is quickly and uniformly painted. what does the phenomenon of polarization have to do with this?

Answers

The appropriate response is the paint particles in the fog(mist) are polarized and thusly are attracted to the charged metallic body of the auto. The clarification behind this is the paint particles are at first neutral. So when the auto is charged, it makes the paint particles captivate. The polarized paint particles are then attracted to the auto.
Final answer:

Polarization is the phenomenon that allows electrically neutral paint particles to be attracted to a charged car's surface during the painting process.

Explanation:

The phenomenon of polarization is related to the process of car painting in a few ways. When the metallic body of the car is moved into the painting chamber, the paint is sprayed as a mist of electrically neutral particles. However, when the car is given a sudden electric charge, the mist of paint particles becomes polarized, meaning they acquire positive or negative charges.

The electric charge on the car creates an electric field around it, and the polarized paint particles are attracted to the opposite charge on the car. This attraction causes the paint particles to quickly and uniformly coat the car's surface.

Overall, polarization allows the electrically neutral paint mist to be attracted to the charged car, resulting in efficient and uniform painting.

You are holding a block of wood with dimensions 3 cm 6 cm 9 cm on the palm of your hand. Which side must be touching your hand for you to experience the greatest force?

Answers

The normal force of weight will not differ for different placements but the force of pressure applied to the surface of your hand is per unit area. So the side with the smallest area.. 3 cm x 6 cm will exert the most pressure on your hand.

The size of the gravitational force depends on the mass of the objects involved. The greater the mass, the greater the gravitational force.

The normal force of weight will not differ for different placements but the force of pressure applied to the surface of your hand is per unit area.

Since, Pressure is equal to the ratio of Force per unit area.  

Thus, the side with the smallest area i.e. 3 cm x 6 cm will exert the most pressure on your hand.

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Why is it important to practice a presentation?

A. To use large type and images
B. To plan the wardrobe
C. To point out the use of each medium
D. To ensure the smooth flow of the presentation

Answers

Your answer should be D
let me know if I got it wrong
Hope this helped!

Answer: D. To ensure the smooth flow of the presentation.

Explanation:

A presentation is a narratative explanation of a topic. A practice of presentation is required before presenting it in the front of the audience. It will help in maintaining the desired flow and sequence of the content which an author want to present in a systematic way. It will help in reducing faults and breaks in the conversation.

what is the gravitational potential energy of a 150 kg object suspended 5m above the Earth's surface

Answers

The gravitational potential energy referred to the ground level is given by
[tex]U=mgh[/tex]
where m is the mass of the object, [tex]g=9.81 m/s^2[/tex] is the gravitational acceleration and h is the height of the object with respect to the ground.

Therefore in our problem the potential energy is
[tex]U=(150 kg)(9.81 m/s^2)(5 m)=7357.5 J[/tex]
Final answer:

The gravitational potential energy of the object is 7350 J.

Explanation:

The gravitational potential energy of an object suspended above the Earth's surface can be calculated using the equation:

PE = mgh

where PE is the gravitational potential energy, m is the mass of the object, g is the acceleration due to gravity (approximately 9.8 m/s²), and h is the height above the Earth's surface.

In this case, the mass of the object is 150 kg and the height is 5 m. Plugging these values into the equation:

PE = 150 kg * 9.8 m/s² * 5 m = 7350 J

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Which of the following is a useful tool in determining the genotype and phenotype of an organism?

Fossil Record
Punnett Square
Roots
Perfect Square

Answers

Hello,

Here is your answer:

The proper answer to this question is option B "Punnett square". Punnett Squares are used to determine the phenotype. 

Your answer is B.

If you need anymore help feel free to ask me!

Hope this helps!
the answer should be b have a nice day

The position of a 55 g oscillating mass is given by x(t)=(2.0cm)cos(10t), where t is in seconds. determine the velocity at t=0.40s. express your answer in meters per second to two significant figures.

Answers

The position of the mass is given by (in cm):
[tex]x(t)=2 \cos (10 t)[/tex]
The velocity is the derivative of the position:
[tex]v(t) = \frac{dx(t)}{dt} =-10\cdot 2 \sin (10t)=-20 \sin (10t)[/tex]
Substituting t=0.40 s, we can find the velocity at this time:
[tex]v(0.40 s)= -20 \sin (10 \cdot 0.4)=15 cm/s=15 \cdot 10^{-2}m/s[/tex]

The velocity of the oscillating particle at [tex]t=0.4\,{\text{s}}[/tex]  is [tex]\boxed{1.5\,{{{\text{cm}}}\mathord{\left/{\vphantom{{{\text{cm}}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}}[/tex]  or [tex]\boxed{1.5\times{{10}^{-2}}\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}}[/tex] .

Further Explanation:

The position of the oscillating mass is given by:

[tex]x\left(t\right)=\left({2.0\,{\text{cm}}}\right)\cos\left({10t}\right)[/tex]

Here, [tex]x\left(t\right)[/tex]  is the position of the particle at time [tex]t[/tex]  during the oscillation.

The velocity of the oscillating particle is defined as the rate of change of the position of the body. Thus, it can be expressed as the first derivative of the position of the body while it is oscillating.

The velocity of the particle can be expressed as:

[tex]\boxed{v=\frac{{dx\left(t\right)}}{{dt}}}[/tex]

Substitute the equation of the position in above expression.

[tex]\begin{aligned}v&=\frac{d}{{dt}}\left({\left({2.0\,{\text{cm}}}\right)\cos\left({10t}\right)}\right)\\&=-\left({2.0\,{\text{cm}}}\right)\sin\left({10t}\right)\\\end{aligned}[/tex]

Now, we are to obtain the velocity of the oscillating particle at time [tex]t=0.4\,{\text{s}}[/tex] . So, substitute [tex]0.4[/tex]  for  [tex]t[/tex] in above equation of velocity.

[tex]\begin{aligned}v&=-\left({2.0\,{\text{cm}}}\right)\sin\left({10\times0.4\,{\text{rad}}}\right)\\&=-2.0\times\left({-0.75}\right)\\&=1.5\,{{{\text{cm}}}\mathord{\left/{\vphantom{{{\text{cm}}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}\\\end{aligned}[/tex]

The velocity of the oscillating particle in [tex]{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}[/tex] while it oscillates is given as:

[tex]\begin{aligned}v&=1.5\,{{{\text{cm}}}\mathord{\left/{\vphantom{{{\text{cm}}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}\left({\frac{{1\,{\text{m}}}}{{100\,{\text{cm}}}}}\right)\\&=1.5\times{10^{-2}}\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}\\\end{aligned}[/tex]

Thus, the velocity of the oscillating particle at [tex]t=0.4\,{\text{s}}[/tex]  is [tex]\boxed{1.5\,{{{\text{cm}}}\mathord{\left/{\vphantom{{{\text{cm}}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}}[/tex] or [tex]\boxed{1.5\times{{10}^{-2}}\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}}[/tex] .

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Answer Details:

Grade: College

Subject: Physics

Chapter: Oscillation

Keywords:

Position, 55g particle9t, oscillating mass, velocity at, t=0.40 s, position of particle, rate of change of position, x(t)=(2.0 cm)cos(10t).

 Maglev trains, like the one shown in the picture, use magnet fields to travel up to 600 miles per hour. Magnets on the bottom of the train and on the tops of the rails have similar magnetic poles. Based on properties of magnets, how do these magnets affect the train?

A)The two magnetic fields repel each other, causing the train to levitate, or hover, above the rails.

B)The powerful magnets greatly reduce the force of gravity, resulting in less friction and greater speed.

C)The train is able to stop immediately because the magnets on the rails attract the magnets on the train.

D)Maglev trains have extremely powerful magnets, greatly decreasing the force of gravity and allowing them to float.

Answers

The correct answer is A) The two magnetic fields repel each other, causing the train to levitate, or hover, above the rails.
In fact, same magnetic poles repel each other, while opposite magnetic poles attract each other. the magnets on bottom of the train and on top of the railway have the same polarities, so they repel each other and this allows the train to levitate.

Answer:

Its C

Explanation:

thank me later

Which of the following is a dark sticky substance that is found in tobacco?

a.

tar

b.

nicotine

c.

nitrogen

d.

carbon monoxide

Answers

A. Tar.

But it's only found when tobacco is burned.

What is the purpose of the zigzag line on the periodic table

Answers

It separates the metals from the non metals

Answer : The purpose of the zigzag line on the periodic table is to separates the metal from the non-metal.

Explanation :

Metalloids : These are the elements that shows both the property of metals and non-metals.

For example : Boron, silicon, germanium, arsenic, antimony, tellurium, polonium and astatine are the metalloids.

Metalloids separates the metals from the non-metals.

The zigzag line on the periodic table represent the metalloids.

Non-metals are found to the right side of the zigzag line that gains electrons to attain stability.

Metals are found to the left side of the zigzag line that loses electrons to attain stability.

Hence, the purpose of the zigzag line on the periodic table is to separates the metal from the non-metal.

A gas in a cylinder with a moveable piston has an initial volume of 89.2 ml . if we heat the gas from 35 âc to 153 âc, what is its final volume (in ml)? express the volume to three significant figures and include the appropriate units.

Answers

Use Charles' Law: 
v1/T1 = v2/T2 
88.2/(273+35) = v2/(273+155) 
where v2 is the new volume.

I hope this helps!!!

Suppose you have a 150-kg wooden crate resting on a wood floor. (a) what maximum force (in n) can you exert horizontally on the crate without moving it?

Answers

Missing detail:
The coefficient of static friction is not specified in the problem. Searching online, I found that for wood-on-wood contact it is between 0.25-0.5. I assume here the maximum value, 0.5.

Solution:
When pushing the crate horizontally with a force F, only two forces act horizontally on the crate: F and [tex]F_f[/tex], the frictional force, which points into the opposite direction of F and whose magnitude is given by
[tex]F_f = \mu_S m g[/tex]
where [tex]\mu_S=0.5[/tex] is the coefficient of static friction, [tex]m=150 kg[/tex] is the mass of the crate and [tex]g=9.81 m/s^2[/tex] is the gravitational acceleration.

In order to start to move the crate, the force F applied must overcome the frictional force. This means that the minimum value of F necessary is equal to Ff:
[tex]F_{min}=F_f = \mu_S mg=(0.5)(150 kg)(9.81 m/s^2)=735.7 N[/tex]

Final answer:

In physics, the maximum static frictional force equals the coefficient of static friction times the normal force. Once the crate starts slipping, the force of kinetic friction applies, and acceleration can be calculated using Newton's second law of motion.

Explanation:

The question involves concepts from Physics, specifically dealing with static friction and Newton's second law of motion. The maximum force that can be exerted on a wooden crate without moving it is equal to the maximum static frictional force. This force can be found by multiplying the coefficient of static friction (μ) between the wooden crate and the wood floor by the normal force, which, in this case, is equal to the gravitational force acting on the crate (mass × acceleration due to gravity, g).

If the static frictional force is overcome and the crate begins to slide, and assuming the applied force remains constant, we switch to dealing with kinetic friction. The magnitude of kinetic friction is usually lower than static friction. To find the acceleration of the crate once it starts moving, you would subtract the kinetic friction force from the applied force and then divide by the crate's mass, according to Newton's second law (F = ma).

For example, consider the question (a) What is the maximum force you can exert horizontally on a 120-kg wooden crate without moving it? The answer would be the product of the coefficient of static friction and the normal force, which equals the weight of the crate. If given (for example, μ=0.5), the calculation would be 588 N. For part (b), if the creates starts to slip, we then use Newton's second law to determine the magnitude of the crate's acceleration, which would be the net force divided by the crate's mass, resulting in an acceleration of 1.96 m/s².

A spaceship orbiting earth flies to the moon. How is the gravitational force pulling on the spaceship related to the distance that the spaceship is from the earth?

Question 25 options:

The gravitational pull of the earth is constant and therefore the gravitational pull on would not change.


As the distance from the earth decreases, the gravitational pull on the spaceship would decrease.


There is no gravity on the moon and therefore only the earth will exert gravitational force on the spaceship.


As the distance from the earth increases, the gravitational pull on the spaceship would decrease.

Answers

The correct answer is "As the distance from the earth increases, the gravitational pull on the spaceship would decrease."

In fact, the gravitational force (attractive) exerted by the Earth on the spaceship is given by
[tex]F=G \frac{Mm}{d^2} [/tex]
where G is the gravitational constant, M the Earth's mass, m the mass of the spaceship and d the distance of the spaceship from the Earth. As we can see from the formula, as the distance d between the spaceship and the Earth increases, the gravitational force F decreases, so answer D) is the correct one.

Suppose you had a parallel circuit with several identical light bulbs of equal resistance. if one bulb goes bad (or is disconnected), what happens to the brightness of the other bulbs?

Answers

Since this is in parallel circuit, if one bulb goes bad the brightness of the other bulbs should remain the same. The overall current did decrease but the resistance also decreased.
Final answer:

In a parallel circuit, the brightness of the remaining bulbs isn't affected when one bulb goes bad or is disconnected. This is because each bulb has its own path to the voltage source, and neither the voltage nor the redistributed current through each bulb is affected by the removal of one bulb. Contrarily, in a series circuit, all bulbs would go dark.

Explanation:

In a parallel circuit with several identical light bulbs of equal resistance, when one bulb goes bad or is disconnected, it doesn't affect the brightness of the other bulbs. This is because in a parallel circuit, each bulb has its own separate path to the voltage source. Therefore, the removal of one path (the bad or disconnected bulb) doesn't affect the potential difference or voltage across the other bulbs.

Let's take the two primary variables determining the brightness of a bulb - the voltage and current. In a parallel circuit, the voltage across each bulb remains the same, regardless of whether a bulb is removed or not. On the other hand, current, though different for each bulb depending on its resistance, isn't affected by the removal of one bulb because the total current just gets redistributed through the remaining paths, maintaining the original brightness of the other bulbs.

In contrast, if this were a series circuit, the scenario would be different. In a series circuit, the removal or failure of one bulb would disrupt the entire circuit (since there's only one path for the current to flow), causing all other bulbs to go dark.

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Give three ways you experience normal force throughout your day.

Answers

1. kicking a ball
2.pushing a door open
3.lifting something up ( like a box)

Answer: Static friction, sliding fiction, fluid fiction, and rolling friction

Explanation: static friction (friction that acts upon unmoving objects), sliding fiction (friction that occurs between two objects sliding past each other), fluid friction (is the force that resists motion when fluid is involved)and the last one is rolling friction (the force between a rolling object and a surface).

An astronaut has a mass of 74.0 kg. 1) how much would the astronaut weigh on mars where surface gravity is 38.0% of that on earth? (express your answer to three significant figures.)

Answers

274.614N or 61.736lbs
74 kg * 0.38 * 9.8 m/s/s = 275.576 N
3 significant figures rounds to 276 N

A child bounces a 56 g superball on the sidewalk. the velocity change of the superball is from 20 m/s downward to 13 m/s upward. if the contact time with the sidewalk is 1 800 s, what is the magnitude of the average force exerted on the superball by the sidewalk? answer in units of n.

Answers

Using the impulse-momentum theorem and taking this down as positive, we will get: 
FΔt = Δp 

F = Δp / Δt 

= m(v - v₀) / t 

= 0.056kg [13m/s - (- 20m/s) / 0.00125s 

= 1478.4 N when properly rounded off is the answer we are looking for in this problem.

Suppose a heat source generates heat at a rate of 87.0 w (1 w = 1 j/s). how much entropy does this produce per hour in the surroundings at 27.4 °c? assume the heat transfer is reversible.

Answers

For a reversible process, the second law says that: 
dS = dq/T 
So 
dS/dt = (1/T)*dq/dt 
We are given that dq/dt = 87.0 J/s, and that T = 27.4°C  which is equal to 300.55 K, so: 
dS/dt = (1/300.55K)*(87.0 J/s) = 0.289 J/(K*s) which is equal to 1040.40 joules per hour

Isabel’s first car had a manual stick shift. After many years of driving an automatic car, she needs to use her sister’s car, which also has a stick shift. Isabel takes a few minutes to get used to shifting gears. Which memory system is she using to recall this information?

Answers

Final answer:

Isabel is using her implicit procedural memory, a form of long-term memory responsible for automatic skills, to recall how to use a manual stick shift after primarily driving an automatic car.

Explanation:

Isabel is utilizing her implicit procedural memory to recall how to shift gears in a stick shift car after having driven an automatic vehicle for many years. Procedural memory is a form of long-term memory that enables people to perform tasks without conscious awareness of the learned skills, such as riding a bike, typing on a keyboard, or driving. In this case, Isabel's ability to revert to using a manual stick shift despite the extended use of an automatic car illustrates the durability and automaticity of procedural memory.

What is the frequency of a clock waveform whose period is 750 microseconds?

Answers

The frequency f of a wave is defined as the inverse of the period T:
[tex]f= \frac{1}{T} [/tex]
The clock in the problem has a waveform with period [tex]T=750 ms=0.750 s[/tex]. Therefore, its frequency is
[tex]f= \frac{1}{0.750 s}=1.33 Hz [/tex]

Alice and Marge are studying the properties of matter. The girls placed some an iron nail in a beaker containing water. Iron is a solid metal at room temperature. Iron is a shiny and malleable; it can be formed into shapes like the nails the girls used. Iron will turn reddish-brown in the presence of air or water as it rusts. Iron is a good conductor of electricity and heat. After 48 hours, the girls checked the nail in the water and compared it to the nail they left on the lab bench. Based on the girls' experiment, what is a chemical property of iron?
A) Iron is malleable. B) Iron rusts in water. C) Iron is a strong metal. D) Iron is a good conductor.

Answers

Answer: B) Iron rusts in water.

Explanation:

Physical property is defined as the property of a substance which becomes evident during physical changes. Example: Melting point  , electrical conductivity, malleability,

Chemical property is defined as the property of a substance which becomes evident during chemical changes. Example: Reactivity with other substances

Rust is hydrated ferric oxide [tex](Fe_2O_3.xH_2O[/tex].

[tex]Fe\rightarrow Fe^{2+}+2e^-[/tex]

Corrosion of iron is called as rusting. Rust is hydrated ferric oxide [tex](Fe_2O_3.xH_2O[/tex].

[tex]Fe\righatarrow Fe^{2+}+2e^-[/tex]

[tex]O_2+4H^++4e^-\rightarrow 2H_2O[/tex]

[tex]4Fe^{2+}+O_2+4H_2O\rightarrow 2Fe_2O_3+8H^+[/tex]

Thus rusting of iron is a chemical property.

Answer: B) Iron rusts in water.

Assuming atmospheric pressure to be 1.01 x 10^5 Pa and the density of sea water to be 1025 kg/m^3, what is the absolute pressure at a depth of 15.0 m below the surface of the ocean?

Answers

To solve for absolute pressure, you will need this formula:

[tex] P_{total} = P_{atm} + (rgh)[/tex]

Where: [tex] P_{total}[/tex] = absolute pressure
             [tex] P_{total}[/tex] = atmospheric pressure
             r (rho) = density
             g  = acceleration due to gravity constant [tex]9.8 \frac{m}{ s^{2} } [/tex]
             h = depth (in this case)

rgh is the formula for pressure of fluids

So with your given, we just need to insert it into the formula:

[tex] P_{total} = P_{atm} + (rgh)[/tex]
[tex] P_{total}[/tex] = 1.01 x [tex] 10^{5}[/tex] x (1,025 [tex]\frac{kg}{m^3} [/tex] x 9.8 [tex] \frac{m}{{s^2}} [/tex] x 15 m
[tex] P_{total}[/tex] = 1.01 x [tex] 10^{5}[/tex] + 150,675
[tex] P_{total}[/tex] = 1.01 x [tex] 10^{5}[/tex] + 1.51 x [tex] 10^{5}[/tex]

[tex] P_{total}[/tex] = 2.52 x [tex] 10^{5} [/tex] This is your absolute pressure.



Final answer:

The absolute pressure at a depth of 15.0m below the surface of the ocean is 150975 Pa.

Explanation:

To calculate the absolute pressure at a depth of 15.0m below the surface of the ocean, we need to consider the pressure due to the weight of the water column above that point.

The pressure due to the weight of a fluid is given by the equation P = ρgh, where P is the pressure, ρ is the density of the fluid, g is the acceleration due to gravity, and h is the depth.

Substituting the given values, we have P = (1025 kg/m3) × (9.8 m/s2) × (15.0m) = 150975 Pa.

Therefore, the absolute pressure at a depth of 15.0m below the surface of the ocean is 150975 Pa.

If a ball is given an initial speed of 15 m/s on a horizontal, frictionless surface, how fast will the ball be rolling in 5 seconds?

Answers

The surface is frictionless, so there is no frictional force acting on the ball. There are no other forces acting on the ball in the horizontal direction, so it's a uniform motion with constant speed. Therefore, the velocity of the ball will remain the same for the entire duration of the motion, and so after 5 seconds the velocity is still 15 m/s.

Answer:

15 m/s

Explanation:

Suppose that the resistance between the walls of a biological cell is 6.8 × 109 ω. (a) what is the current when the potential difference between the walls is 69 mv? (b) if the current is composed of na+ ions (q = +e), how many such ions flow in 0.86 s?

Answers

Final answer:

The current is 1.01 x 10^-11 A and 5.4 x 10^7 Na+ ions flow in 0.86 s.

Explanation:

In order to find the current, we can use Ohm's Law which states that current (I) is equal to the potential difference (V) divided by the resistance (R). So, the current can be calculated as:

I = V / R

Substituting the given values:
I = (69 mV) / (6.8 × 109 Ω)

I = 1.01 × 10-11 A

For part (b), we need to find the number of Na+ ions (q = +e) that flow in 0.86 s. We can use the equation:

q = I × t

Substituting the known values:
q = (1.01 × 10-11 A) × (0.86 s)

q = 8.7 × 10-12 C

Since 1 Na+ ion has a charge of +e, where e is the elementary charge (1.6 × 10-19 C), we can calculate the number of ions:

Number of ions = q / e = (8.7 × 10-12 C) / (1.6 × 10-19 C)

Number of ions = 5.4 × 107 Na+ ions

Resistors in parallel together contain less resistance than resistors in series together. Create an analogy to explain this phenomena and post it here.

Answers

An analogy to explain this phenomena is the traffic explanation: Imagine you are in rush hour of traffic in a major city. Now imagine that all the traffic is only on one lane instead of being spread out on all six lanes. With more paths, there is less resistance to flow.

Your answer is: Imagine you are in rush hour of traffic in a major city. Now imagine that all the traffic is only on one land instead of being spread out on all six lanes. With more paths, there is less resistance to flow. 

Have an amazing day mate!

*stay happy : ) 

Shoutout to: @DavidB

Resistors in parallel act like a multi-lane highway which eases traffic, reducing the total electrical resistance compared to individual resistors. This is unlike resistors in series, which increase the total resistance like a single congested road.

When resistors are connected in parallel, the total resistance is lower than any individual resistor in the network. This phenomenon can be understood with a simple analogy: imagine a highway with multiple lanes. If only one lane is open, the traffic (current) has only one path to travel, leading to congestion (high resistance). Now, if all lanes (multiple resistors in parallel) are open, traffic can distribute across them, easing congestion (lowering resistance). The more lanes there are, the less the traffic is slowed down, analogous to the way adding resistors in parallel decreases the total resistance. In contrast, if you had a single long road (resistors in series), the traffic would have to follow one after another, which leads to increased congestion or resistance.

Furthermore, the formula for calculating total resistance for parallel resistors demonstrates that the total resistance (Rp) is always less than the smallest resistor's resistance in the network. By providing multiple paths for the electric current, the circuit allows for more current to flow without increasing resistance, different from a series setup where the total resistance is simply the sum of all resistor values.

Eddie the eagle, british olympic ski jumper, is attempting his most mediocre jump yet. after leaving the end of the ski ramp, he lands downhill at a point that is displaced 72.1 m horizontally from the edge of the ramp. his velocity just before landing is 33.0 m/s and points in a direction 30.0$^\circ$ below the horizontal. neglect any effects due to air resistance or lift. what was the magnitude of eddie's initial velocity as he left the ramp?

Answers

when he lands his horizontal velocity is 
28 cos40 = 21.45 m/s 

the time in flight comes from 
x = Vht 
58.8 = 21.45t 
t = 2.74 seconds 

his vertical velocity at landing is 
28 sin40 = -18 m/s 

his vertical velocity equation is 
v = V0 - gt 
-18 = V0 - 9.81(2.74) 
V0 = -18 + 9.81(2.74) 
V0 = 8.88 

his velocity magnitude was 
v = (8.88^2 + 21.45^2)^½ 
v = 23.2 m/s ANSWER 

his initial direction was 
tanθ = 8.88/21.45 
θ = 22.5 degrees above the horizontal ANSWER 

to find the time to the flight apex from launch 
v = gt 
8.88 = 9.81t 
t = 0.905 s 

in 0.905 s Eddie has risen how far above the edge 
y = ½(9.81)(0.905^2) 
y = 4 m 

the remainder of the flight is all drop and takes 2.74 - 0.905 = 1.85 seconds 

in 1.85 seconds he drops 
y = ½(9.81)(1.85^2) 
y = 16.7 m 

so the height from the edge to the landing point is 
16.7 - 4 = 12.7 m ANSWER
Final answer:

Eddie's initial velocity as he left the ramp is calculated as 28.61 m/s

Explanation:

This physics problem involves two-dimensional motion or projectile motion. We can solve it by using the principles of conservation of energy and kinematics. The final horizontal velocity (vxf) can be calculated using the final velocity (v) and the angle (θ) below the horizontal through the formula vxf = v * cos(θ), which in this case gives us 33 * cos(30°) = 28.6 m/s. Since there's no horizontal acceleration involved in Eddie's jump, the initial horizontal velocity (vxi) equals the final horizontal velocity (vxf), hence vxi = 28.6 m/s.

Now, we can use the horizontal displacement (Δx) and vxi to calculate the total time of flight using the formula Δx = vxi * t, so the time of flight (t) = Δx / vxi = 72.1 m / 28.6 m/s = 2.52 s. Finally, using the time of flight, final vertical velocity (vyf), and the acceleration due to gravity (g), we can find the initial vertical velocity (vyi) using the formula vyf = vyi + g * t. Substituting the given values, we get - 33 * sin(30) = vyi - 9.8 * 2.52, which gives us vyi = -1.1 m/s.

As the last step, we find the magnitude of the initial velocity from the resultant of its vertical and horizontal components using the Pythagorean theorem: vi = sqrt[(vxi^2) + (vyi^2)], which comes out to be sqrt[(28.6^2) + (-1.1^2)] = 28.61 m/s.

Learn more about Initial Velocity here:

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You are in a hot air balloon (yes, another balloon problem!) rising from the ground at a constant velocity of 2.00 m/s upward. to celebrate the takeoff, you open a bottle of champagne, expelling the cork with a horizontal velocity of 6.60 m/s relative to the balloon. when opened, the bottle is 5.90 m above the ground. what is the initial speed of the cork, as seen by your friend on the ground?

Answers

If all you need is the initial speed of the cork, you can solve this using only two of your given:
2.00 m.s upward and 6.60 m.s horizontally.

If you take in consideration the movement of the cork, you know that it was both going up and forward at the same time, this means that it was moving at a diagonal direction. Now you can solve this by using the Pythagorean theorem where: 

[tex]c = \sqrt{ a^{2} + b^{2} } [/tex]

Why? Because the vertical and the horizontal motion creates a movement that is diagonal, which when put in a free-body diagram, creates a right triangle. 

Going back to your problem, when applying this, the diagonal of a right triangle is the hypotenuse, so this is what you are looking for. The horizontal and vertical motion will represent the other 2 sides of the triangle. 

Now let's put that into your formula:

[tex]c = \sqrt{ a^{2} + b^{2} } [/tex]

[tex]Vi = \sqrt{ Vx^{2} + Vy^{2} } [/tex]

Where: Vx is your horizontal velocity
             Vy is your vertical velocity
             Vi  is your initial velocity

Now let's put in your given:

[tex]Vi = \sqrt{ Vx^{2} + Vy^{2} } [/tex]
[tex]Vi = \sqrt{ 6.60^2} + 2.00^{2} } [/tex]
[tex]Vi = \sqrt{ 43.56 + 4.00 } [/tex]
[tex]Vi = \sqrt{ 47.56 } [/tex]
[tex]Vi = 6.8964 m/s [/tex]

So your initial velocity is 6.8964 m/s or 6.90 m/s

A small air plane's takeoff speed is 30 m/s. With constant acceleration it takes 150 m of runway to become airbourne. How long does it take to become airbourne?

Answers

t=vf-vi/a
t=30-0/150m
t=0.2s
The plane moves at a constant rate of 30m/s

there are 150m in the runway

150/30 = 5

5 seconds is the time it takes for it to be airborne

hope this helps

Which statement is true about the electromagnetic spectrum? The visible spectrum includes radio waves, light, and gamma rays. The colors you can see have the same wavelength. It has a range of visible and invisible forms of radiation. The waves travel at the speed of 2.998×105 meters/second.

Answers

Answer: It has a range of visible and invisible forms of radiation.

Explanation:

Electromagnetic wave is defined as the wave which is associated with both electrical and magnetic component associated with them. They can travel in vacuum as well and travel with the speed of light i.e [tex]2.998\times 10^8ms^{-1}[/tex]

The electromagnetic radiations consist of radio waves, microwaves, infrared ,Visible , ultraviolet, X rays and gamma rays arranged in order of increasing frequency and decreasing wavelengths.

Only visible light is visible to naked eyes.

The relationship between wavelength and frequency of the wave follows the equation:

[tex]\nu=\frac{c}{\lambda}[/tex]

where,

[tex]\nu[/tex] = frequency of the wave

c = speed of light  

[tex]\lambda [/tex] = wavelength of the wave

From the above relation, it is visible that wavelength and frequency follow inverse relation. For increase in wavelength, the value of frequency decreases and vice-versa.

In a biological reaction involving an enzyme, what does not directly participate in the reaction?
A.) The active site of an enzyme
B.) The active site of the substrate
C.) The inactive sure of the substrate
D.) The reactant chdcmicals

Answers

Hello!

In a biological reaction involving an enzyme, the inactive site of the substrate does not directly participate in the reaction.

Most biological reactions involving an enzyme operate through the Induced fit mechanism. In this kind of mechanism,  the active sites of the substrate bind to the active sites of the enzyme by a geometrical conformational adjustment, forming an intermediate complex which lowers the activation energy for the reaction and speeds up the reaction rate. 

Only the active sites of the substrate and the enzyme are directly involved in the reaction, so the Inactive sites of the substrate will not participate in the reaction. 

In a uranium fission reaction the uranium splits into 2 smaller atoms an energy. Where did the energy come from?

Answers

When the uranium splits, mass and energy are created making the two new atoms. Next time please add the answers that are applicable to this question.
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