Answers
[tex]y(t) = h+v_0t - \frac{1}{2}gt^2 [/tex]
where
[tex]h=4.21 m[/tex] is the initial height from which the ball starts its motion
[tex]v_0=1.53 m/s[/tex] is the initial velocity of the ball
[tex]g=9.81 m/s^2[/tex] is the gravitational acceleration
The time in which the ball reaches the ground is the time t at which the vertical position y(t) becomes zero:
[tex]0= h + v_0 t - \frac{1}{2}gt^2[/tex]
Which means
[tex]0=4.21 + 1.53 t - 4.9 t^2 [/tex]
whose solutions are:
[tex]t=-0.78 s[/tex]
[tex]t=1.10 s[/tex]
Neglecting the negative solution (since it has no physical meaning), we can say that the ball reaches the ground after 1.10 s.
The time in which the ball will reach the ground is about 1.10 s
Further explanationAcceleration is rate of change of velocity.
[tex]\large {\boxed {a = \frac{v - u}{t} } }[/tex]
[tex]\large {\boxed {d = \frac{v + u}{2}~t } }[/tex]
a = acceleration ( m/s² )
v = final velocity ( m/s )
u = initial velocity ( m/s )
t = time taken ( s )
d = distance ( m )
Let us now tackle the problem !
This problem is about Kinematics.
We will solve it in the following way
Given:
initial speed = u = 1.53 m/s
initial height = H = 4.21 m
Unknown:
time taken = t = ?
Solution:
[tex]H = ut - \frac{1}{2}gt^2[/tex]
[tex]-4.21 = 1.53t - \frac{1}{2}(9.8)t^2[/tex]
[tex]-4.21 = 1.53t - 4.9t^2[/tex]
[tex]4.9t^2 - 1.53t - 4.21 = 0[/tex]
We will solve the above equation using the following quadratic function formula:
[tex]t = \frac{1.53 + \sqrt{1.53^2 - 4(4.9)(-4.21)}}{2(4.9)}[/tex]
[tex]t \approx 1.10 ~ s[/tex]
Learn moreVelocity of Runner : https://brainly.com/question/3813437Kinetic Energy : https://brainly.com/question/692781Acceleration : https://brainly.com/question/2283922The Speed of Car : https://brainly.com/question/568302Answer detailsGrade: High School
Subject: Physics
Chapter: Kinematics
Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate
Related Questions
When a rocket is traveling toward a mountain at 100 m/s, the sound waves from this rocket's engine approach the mountain at speed v. if the rocket doubles its speed to 200 m/s, the sound waves from the engine will now approach the mountain at speed?
Answers
Therefore, sound will approach the mountain at velocity v in both 100 m/s and 200 m/s of the rocket.
Answer:
The sound waves from the engine will approach the mountains at the same speed, no matter if the speed of the rocket is 100m/s or 200 m/s.
Explanation:
The sound wave is a property of the air, which means that the speed of the object producing sound does not matter to the sound of the waves, that is, they are always going to be the same.
So the sound waves from the engine will approach the mountains at the same speed, no matter if the speed of the rocket is 100m/s or 200 m/s.
What real-world examples show no work begin done? Can you think of examples other than resisting the force of gravity?
Answers
If no work is being done, then you're NOT resisting the force of gravity.
Example:
-- ball rolling on the floor . . . no work
-- ball rolling up a ramp . . . work being done
-- ball rolling down a ramp . . . work being done, BY gravity
Answer:
Explanation:
The work done is defined as the product of force in the direction of displacement and the displacement.
Work done = force x displacement x Cos Ф
Where, Ф be the angle between force and the displacement vectors.
Work may be positive, negative or zero depending on the values of angle Ф.
The work done is zero when force is zero or displacement is zero or angle Ф is 90 degree.
So, when we apply a force on a body and body does not displace, then the work done is zero.
A cello string 0.75 m long has a 220 hz fundamental frequency. find the wave speed along the vibrating string. answer in units of m/s.
Answers
1/2y = L, where L = length of the string, y = wavelength.
Therefore,
y = 2L = 2*0.75 =1.5 m
Additionally,
y = v/f Where v = wave speed, and f = ferquncy
Then,
v = y*f = 1.5*220 = 330 m/s
When a pendulum with a period of 2.00000 s in one location (g = 9.80 m/s2) is moved to a new location from one where the period is now 1.99863 s. what is the change in acceleration (in m/s2) due to gravity at its new location?
Answers
[tex]T=2 \pi \sqrt{ \frac{L}{g} } [/tex]
where L is the pendulum length and g is the gravitational acceleration.
Initially, the period of the pendulum is T=2.00 s while the gravitational acceleration is [tex]g=9.80 m/s^2[/tex]. If we re-arrange the previous equation, we can find the pendulum length:
[tex]L=g \frac{T^2}{(2 \pi)^2}=(9.80 m/s^2) \frac{(2.00s)^2}{4 \pi^2}= 0.994 m[/tex]
Then the same pendulum is moved to another location, and its new period is
[tex]T=1.99863 s[/tex]. Again, by re-arranging the same equation, we can find the value of g (gravitational acceleration) at the new location:
[tex]g=L \frac{(2 \pi)^2}{T^2}=(0.994 m) \frac{4 \pi^2}{(1.99863 s)^2}=9.814 m/s^2 [/tex]
An elephant can hear sound with a frequency of 15 hz. what is the wavelength of this wave if the speed of sound in air is 343 m/s?
Answers
The wavelength of a sound wave with a frequency of 15 Hz and a speed of sound in air of 343 m/s is approximately 22.87 meters.
Explanation:To calculate the wavelength of the sound wave, we can use the formula:
Speed of sound (v) = wavelength (λ) x frequency (f)
Given that the frequency of the sound wave is 15 Hz and the speed of sound in air is 343 m/s, we can substitute these values into the formula to solve for the wavelength:
343 m/s = λ x 15 Hz
Dividing both sides of the equation by 15 Hz, we get:
λ = 343 m/s / 15 Hz = 22.87 meters (rounded to two decimal places)
Therefore, the wavelength of the sound wave is approximately 22.87 meters.
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¿Cuál es la velocidad promedio de un hombre que camina 70m con una rapidez de 1m/s y luego corre 70m con una rapidez de 3m/s?
Answers
Respuesta:
[tex]1,5 \frac{m}{s} [/tex]
Explicación:
Para calcular la velocidad promedio, necesitamos conocer dos cosas:
1: Distancia total recorrida
2: Tiempo total del recorrido
Del enunciado tenemos los siguientes datos:
Primer tramo:
Distancia recorrida : 70 m
Velocidad: [tex] \frac{1m}{s} [/tex]
Segundo tramo:
Distancia recorrida:70 m
Velocidad: [tex]\frac{3m}{s}[/tex]
Utilizando la siguiente formula:
[tex]X=Xo + V.t[/tex]
Donde:
X: Distancia final
Xo: Distancia inicial
V: Velocidad
T: Tiempo
Para este ejercicio, nos es dada la distancia recorrida, es decir la diferencia entre la distancia final (X) y la distancia inicial (Xo), teniendo que:
[tex]X-Xo= V. t[/tex]
Sustituyendo los valores del primer tramo, tenemos:
[tex]70m= \frac{1m}{s} .t \\ t= \frac{70m}{ \frac{1m}{s \\ } } \\ t= 70s [/tex]
Sustutuyendo los valores del segundo tramo, tenemos:
[tex]70m= \frac{3m}{s} .t \\ t= \frac{70m}{ \frac{3m}{s \\ } } \\ t= 23,33 s[/tex]
Calculando ambos tiempos, tenemos un tiempo de recorrido total de:
[tex]Ttotal= [/tex] Tiempo en el tramo 1 + Tiempo en el tramo 2 [tex]= 93,33 s[/tex]
Para calcular la velocidad promedio, dividimos la distancia total del recorrido por el tiempo total recorrido. Esta viene dada por la siguiente formula:
[tex]Vprom= \frac{Distancia Total}{Tiempo Total} = \frac{140 m}{93,33s} = \frac{1,5m}{s} [/tex]
Que tengas un buen día!
A semiconductor can be made by adding atoms of other elements to
a.
aluminum.
b.
steel.
c.
silicon.
d.
zinc.
Answers
How much heat is required to melt 86.5 g of ice at its melting point?
Answers
[tex]Q=m L_f[/tex]
where
m is the mass of the ice
Lf is the latent heat of fusion of ice
For ice, [tex]L_f = 334 J/g[/tex], while the mass of this sample of ice is [tex]m=86.5 g[/tex], therefore the amount of heat needed to melt it is
[tex]Q=mL_f = (86.5 g)(334 J/g)=2.89 \cdot 10^4 J = 28.9 kJ[/tex]
What is a correct way to measure wavelength
Answers
A cyclist is going in the positive x-direction at 9m/s. A car initially at rest, accelerates for the first 10 seconds, then it goes with a constant velocity. If the car reaches the cyclist after 15 seconds from the moment the car started moving, find: (a) The acceleration of the car during the first 10 seconds, (b) The velocity of the cyclist with respect to the car when the car reaches the cyclist
Answers
[tex]d_1 = \frac{1}{2}at^2 = \frac{1}{2}a(10 s)^2 = 50 a [/tex]
The velocity the car has reached after these 10 seconds is
[tex]v=at = a (10 s)=10 a[/tex] (3)
Then the car moves for other 5 seconds with this constant velocity (v=10 a) before reaching the cyclist. During this time, the distance it covers is
[tex]d_2 = v t = 10 a \cdot (5 s) =50 a[/tex]
So the total distance covered by the car is
[tex]d=d_1 + d_2 = 50 a + 50 a =100 a[/tex] (1)
The cyclist is moving at constant speed of [tex]v=9m/s[/tex], so the distance it covered during the 15 seconds is
[tex]d=vt=(9m/s)(15 s)=135 m[/tex] (2)
And since the car covered the same distance during this time, we can use (1) and (2) to find the acceleration of the car during the first 10 seconds:
[tex]a= \frac{d}{100}= \frac{135}{100} = 1.35 m/s^2 [/tex]
2) The velocity of the car when it reaches the cyclist is given by (3):
[tex]v_1= 10 a= (10 s)(1.35 m/s^2) = 13.5 m/s[/tex]
The velocity of the cyclist is [tex]v_2 = 9m/s[/tex], therefore the velocity of the car relative to the cyclist is
[tex]v' = v_1 - v_2 = 13.5 m/s - 9m/s=4.5 m/s[/tex]
Two small objects each with a net charge of +q exert a force of magnitude f on each other: we replace one of the objects with another whose net charge is +4q: the original magnitude of the force on the +q charge was f; what is the magnitude of the force on the +q charge now?
Answers
where k ⇒ constant
d ⇒ distant between the 2 objects.
In this case, k and d are constants.
So, let k/d² = x
since q1=q2,
F = xq²
x = F/q²
After replacing q1 with 4q, the new force on +q will be:
F = xq.4q
= Fq4q/q²
= 4F
The new charge on +q is 4F.
Bats can detect small objects such as insects that are of a size on the order of a wavelength. if bats emit a chirp at a frequency of 69.3 khz and the speed of sound waves in air is 330 m/s, what is the smallest size insect they can detect? give your answer in mm (millimeters)
Answers
Their chirp has a frequency of
[tex]f=69.3 kHz=69.3 \cdot 10^3 Hz[/tex]
and the speed of the chirp is equal to the speed of sound in air:
[tex]v=330 m/s[/tex]
Therefore the wavelength of the chirp is
[tex]\lambda= \frac{v}{f}= \frac{330 m/s}{69.3 \cdot 10^3 Hz}=4.76 \cdot 10^{-3} m [/tex]
which corresponds to a size of 4.76 mm.
Explain how your battery works. What are some possible materials you could use to make your battery?
Answers
Typical materials of a battery are as follows
- Anode most often is made of zinc
- Manganese dioxide acting as Cathode.
- the electrolyte between and inside contains ions
You use energy to heat your home. what ultimately happens to the energy that you pay for in your heating bill?
Answers
The heat energy that you pay for in your heating bill releases and goes to the atmosphere.
Where heat energy goes?The heat energy that are used for warming of houses is releases and goes to the atmosphere and become a part of that atmosphere.
So we can conclude that the heat energy that you pay for in your heating bill releases and goes to the atmosphere.
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Energy paid for in your heating bill is converted into thermal energy to heat your home, distributing through power lines or pipelines. Some of the energy is lost to the environment, while the rest maintains a warm home temperature. Continuous payment is necessary to compensate for ongoing heat loss.
When you pay for energy to heat your home, you are essentially purchasing thermal energy to maintain a comfortable temperature inside. Here's a step-by-step explanation of what happens to the energy:
Generation: The energy you pay for is generated by power plants, which may use fossil fuels, nuclear energy, or renewable sources. This energy is then converted into electrical or thermal energy.Distribution: This energy is distributed through power lines or pipelines to your home.Use in Heating: Inside your home, energy is converted by your heating system into thermal energy (heat). This heat is then transferred to the air and materials in your home to maintain a warm temperature.Heat Transfer: Some of this thermal energy is inevitably lost to the outside environment due to heat transfer. The remaining energy stays within your home, ensuring a comfortable living space.Energy Dissipation: Over time, the thermal energy dissipates, balancing out with the environmental temperature unless continuously supplied.This process explains why you continuously pay for heating during colder months – it compensates for the continuous loss of heat to the outside environment.
A car has two horns, one emitting a frequency of 199 hz and the other emitting a frequency of 203 hz. what beat frequency do they produce?
Answers
That is, beat frequency is the absolute difference between two frequencies. Is is as a results of destructive and constructive inferences.
Therefore, in this case:
fb = 203 - 199 = 4 Hz
The beat frequency produced by two horns emitting frequencies of 199 Hz and 203 Hz is 4 Hz.
The question is regarding the production of beat frequency when two horns with different frequencies sound together. The two horns have frequencies of 199 Hz and 203 Hz, respectively.
To calculate the beat frequency, you subtract the smaller frequency from the larger frequency:
fbeat = |f1 - f2|
fbeat = |203 Hz - 199 Hz|
fbeat = 4 Hz
This means that the beat frequency produced by the two car horns is 4 Hz.
H e l p.. I have no idea what any of this is, what is the first step of the hydrogen fusion process
Answers
1_1H + 1_1H →2_1H + e^+ + v + energy
reflects this process. A hydrogen ion with a mass of one and number protons of 1 means a proton.
What can you infer from the fact that although CFC's have been banned, refrigerators and aerosol cans are still being sold?
Answers
Researcher must have found environmentally safer replacements for CFCs. That might be the reason aerosol cans and the refrigerators are still being sold. In aerosol cans liquefied petroleum gas is being popularly used in place of dangerous CFCs. Same is being done in refrigerators and other devices. The aerosol cans no longer hurt the ozone layer. Infact they have reduced the waste as they can be recycled now and has long life.
What happens when a person’s immune system is very weak?
a) The patient’s blood is unable to clot so he or she must take medication.
b) The patient is able to fight off more infections than normal.
c) The patient is unable to fight the infections a healthy person could resist.
d) The patient is unable to take antibiotics and must get a flu shot.
Answers
When a person's immune system is very weak, their body may be unable to fight off pathogens and diseases that a healthy immune system can resist. This can lead to increased risk of illness and vulnerability to infection.
(Option C)
Explanation:Immunodeficiency occurs when the immune system is not working properly, generally because one or more of its components are inactive. As a result, the immune system may be unable to fight off pathogens or cancers that a normal immune system would be able to resist. Immunodeficiency may occur for a variety of reasons.
The body's immune system would not be able to fight off pathogens like bacteria with fewer white blood cells. This can increase the risk of illness in HIV patients.
The person's immune system would not be able to distinguish self and non-self. This would make the person very vulnerable to infection.
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An empty parallel plate capacitor is connected between the terminals of a 16.7-v battery and charges up. the capacitor is then disconnected from the battery, and the spacing between the capacitor plates is doubled. as a result of this change, what is the new voltage between the plates of the capacitor?
Answers
_____
What are three benefits of being assertive and what are three tips to help you develop an assertive style of communication? (Site 1)
Answers
a. It improve one self image: When you choose to be assertive, you adopt a self realistic image.
b. It enhance how we understand others: Been assertive helps you to see others in a more realistic context.
c. Promote self awareness and self confidence: Been assertive helps you to develop a greater respect for your own points of view when dealing with issues.
d. Been assertive is a less stressful way of communicating.
2. The three steps needed to develop assertive communication, include:
a. Learn to 'no' more often: refuse to please everyone and do not behave according to people expectations of you. Be yourself.
b. Your tone must be properly turned when talking: Do not raise your voice or rush a communication. Be calm and cool when talking.
c. Be open to communication: Be willing to discuss issues until a suitable solution is found.
d. Pay attention to non-verbal communication of others: Keep eye contact when communicating and pay attention to other body gestures.
A 170-lb man carries a 10-lb can of paint up a helical staircase that encircles a silo with radius 15 ft. if the silo is 40 ft high and the man makes exactly two complete revolutions, how much work is done by the man against gravity in climbing to the top? ft-lbs
Answers
Total weight = 170+10 = 180 lb
Vertical distance covered = 40 ft
Therefore,
Work done = 180*40 = 7200 lb-ft
The work is done by the man against gravity in climbing to the top with a 10 lb can of paint up a helical staircase that encircles a silo with a radius of 15 ft. If the silo is 40 ft high and the man makes exactly four complete revolutions is 670lb-ft.
What is Work done?
When an external force moves an object over a distance, at least a portion of that force must be exerted in the direction of the displacement .
Physics refers to this as work. If the force acting along the path is constant, the amount of work can be calculated by multiplying the length of the path by the force's component.
Formally, W = fd means that the work is equal to the force f times the length d. If the force is applied at an angle to the displacement, the work is W = fd cos.
Given:
The mass of man, m = 170 lb,
The mass of the can, M = 10 lb,
Calculate the work done y the following formula,
W = [tex]\int\limits^4_0 {170 -1 / 10y} \, dy[/tex]
Here W is work done
Integrate the above equation, and we get,
W = 670 lb ft.
Therefore, work is done by the man against gravity in climbing to the top with a 10 lb can of paint up a helical staircase that encircles a silo with a radius of 15 ft. If the silo is 40 ft high and the man makes exactly four complete revolutions is 670 lb ft.
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The range of audible frequencies is from about 20.0 hz to 2.00×104 hz . what is range of the wavelengths of audible sound in air? the speed of sound in air is 344 m/s.
Answers
[tex]\lambda= \frac{v}{f} [/tex]
where v is the wave speed and f is its frequency.
The speed of sound in air is v=344 m/s. The lowest frequency is f=20.0 Hz, so the corresponding wavelength is
[tex]\lambda_1 = \frac{v}{f_1}= \frac{344 m/s}{20.0 Hz}=17.2 m [/tex]
The highest frequency is [tex]f_2 = 2.00 \cdot 10^4 Hz[/tex], so the corresponding wavelength is
[tex]\lambda_2 = \frac{v}{f_2}= \frac{344 m/s}{2.00 \cdot 10^4 Hz}=0.017 m [/tex]
Therefore, the range of wavelengths of audible sound in air is
[0.017 m - 17.2 m]
How does natural selection result in adaptations in a species
Answers
A hot-air balloon plus cargo has a mass of 326 kg and a volume of 2310 m3 on a day when the outside air density is 1.22 kg/m3. the balloon is floating at a constant height of 9.14 m above the ground.
Answers
Solution:
The balloon is floating at constant height, and this means that the two forces acting on it (the weight and the buoyant force) are in equilibrium:
[tex]W=B[/tex]
where W is the weight of the balloon, which is sum of the weight of the balloon structure and of the hot air inside the balloon, and B is the buoyant force.
The buoyant force is given by:
[tex]B=Vd_ag[/tex]
where V is the volume of the balloon, d is the air density and g is the gravitational acceleration. Plugging numbers into the equation, we find
[tex]B=Vd_ag=(2310 m^3)(1.22 kg/m^3)(9.81 m/s^2)=2.76 \cdot 10^4 N[/tex]
This is equal to the weight of the balloon+hot air inside it:
[tex]2.76 \cdot 10^4 N = W = W_b + W_h[/tex]
where
[tex]W_b[/tex] is the weight of the balloon
[tex]W_h[/tex] is the weight of the hot air inside the balloon
The weight of the balloon is
[tex]W_b = mg = (326 kg)(9.81 m/s^2)=3199 N[/tex]
Which means that the weight of the hot air is
[tex]W_h = W-W_b = 2.76 \cdot 10^4 N - 3199 N =2.44 \cdot 10^4 N[/tex]
which corresponds to a mass of
[tex]m_h = \frac{W_h}{g}= \frac{2.44 \cdot 10^4 N}{9.81 m/s^2}=2487 kg [/tex]
And since the mass is the product between density and volume, we can find the density of the hot air:
[tex]d_h = \frac{m_h}{V}= \frac{2487 kg}{2310 m^3}=1.08 kg/m^3 [/tex]
given current spacecraft technology, which of the objects in the table do you think it would be possible for you to travel to in your life-time?
Answers
for me to travel to the corner store in my lifetime.
what is an advantage of using coal power over solar power to generate electricity
Answers
Answer:
Coal power can be generated at night
Explanation:
An advantage of using coal power over solar power to generate electricity is Reliable Fuel.
Compared to solar power or wind energy, coal is a reliable, predictable, and dependable fuel. While it may not be at the forefront of national energy production, it can provide invaluable backup service and highly reliable fuel.
What is coal power ?"Coal-fired power plants burn coal to make steam and the steam turns turbines (machines for generating rotary mechanical power) to generate electricity." Many industries and businesses have their own power plants, and some use coal to generate electricity for their own use and mostly in combined heat and power plants.
What is solar power ?"Solar power works by converting energy from the sun into power." There are two forms of energy generated from the sun for our use – electricity and heat. Both are generated through the use of solar panels, which range in size from residential rooftops to 'solar farms' stretching over acres of rural land.
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Having landed on a newly discovered planet, an astronaut sets up a simple pendulum of length 1.38 m and finds that it makes 441 complete oscillations in 1090 s. the amplitude of the oscillations is very small compared to the pendulum's length. what is the gravitational acceleration on the surface of this planet? answer in units of m/s 2 .
Answers
[tex]T=2 \pi \sqrt{ \frac{L}{g} } [/tex]
where L is the pendulum length, and g is the gravitational acceleration of the planet. Re-arranging the formula, we get:
[tex]g= \frac{4 \pi^2}{T^2}L [/tex] (1)
We already know the length of the pendulum, L=1.38 m, however we need to find its period of oscillation.
We know it makes N=441 oscillations in t=1090 s, therefore its frequency is
[tex]f= \frac{N}{t}= \frac{441}{1090 s}=0.40 Hz [/tex]
And its period is the reciprocal of its frequency:
[tex]T= \frac{1}{f}= \frac{1}{0.40 Hz}=2.47 s [/tex]
So now we can use eq.(1) to find the gravitational acceleration of the planet:
[tex]g= \frac{4 \pi^2}{T^2}L = \frac{4 \pi^2}{(2.47 s)^2} (1.38 m) =8.92 m/s^2[/tex]
Calculate the energy transferred when 4.6g of ice is melted at 0.0c
Answers
The energy transferred when 4.6g of ice is melted at 0.0C can be calculated using the formula Q = mLf, where Q is the heat needed to melt the ice, m is the mass of the ice, and Lf is the latent heat of fusion of water. Substituting the given values, we find that 1536.4 Jules of energy gets transferred.
Explanation:To calculate the energy transferred when ice is melted, we use the formula Q = mLf, where Q is the heat necessary to melt the ice, m is the mass of the ice, and Lf is the latent heat of fusion of the substance (the energy needed to change the substance from solid to liquid state without changing its temperature). For water, Lf is 334 kJ/kg. So, to find the energy needed to melt 4.6g of ice we rearrange the formula and find: Q = (4.6/1000 kg) x 334,000 J/kg = 1536.4 J. Therefore, 1536.4 Jules of energy gets transferred when 4.6g of ice melts at 0.0C.
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In Figure 18.8 the grounding wire is removed first, followed by the rod, and the sphere is left with a positive charge. If the rod were removed first, followed by the grounding wire, would the sphere be left with a charge? Account for your answer.
Answers
If the charged rod is removed before the grounding wire, the sphere will not retain a net charge because any excess charge will flow back to ground. Only if the grounding wire is removed while the rod is still present does the sphere retain an excess charge.
Explanation:If the grounding wire is removed after the charged rod is taken away, the sphere would be left with no net charge. This is because during the process of charging by induction, if the rod is removed first, any excess charge on the sphere would have the opportunity to redistribute evenly across its surface. Since the sphere was initially neutral and the grounding wire is still connected, the excess charge would flow to the ground, effectively bringing the sphere back to a neutral state.
On the other hand, as described in your references, if the grounding wire is removed first while the charged rod is still present, the sphere retains an excess of electrons. This happens because by breaking the ground connection while the sphere is still influenced by the nearby positive charge of the rod (which repels the electrons), the redistributed electrons are trapped on the sphere, thus leaving the sphere negatively charged. When the positive rod is finally removed, the sphere remains negatively charged because the extra electrons have no path to escape.
If you live in Earth's Northern Hemisphere, you expect the length of days to change from short in the winter to longest around the summer solstice, June 21st. This is because?
Answers
the guy on the up is jason todd
hope this helps:)