A barometer reading of 29.8 inches of mercury is equivalent to 1012.8 millibars of atmospheric pressure.
Explanation:A barometer displaying a reading of 29.8 inches of mercury would be equivalent to 1012.8 millibars of atmospheric pressure.
To convert inches of mercury to millibars, you can use the conversion factor of 1 inch of mercury = 33.864 millibars. Multiply the given reading by the conversion factor to find the equivalent pressure in millibars.
Therefore, 29.8 inches of mercury = 29.8 inches * 33.864 millibars/inch = 1012.8 millibars.
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Which metal(s) can be oxidized with a sn2+ solution but not with an fe2+ solution? (hint: the reactions are occurring under standard conditions.)?
For this we have to consider the reactive series of metals in which metals are arranged according to their reactivity order.
Oxidation of a metal can be defined as ability to lose electrons to become positively charged metal and a metal will lose its electrons by reacting with a metal that is having low chemical reactivity as a higher reactive metal can lose its electrons to a low reactive metal. So here a metal should be one that is more reactive than tin so that it can lose its electrons to tin to become positively charged and less reactive than iron so that it will not give its electrons to iron to become positively charged. If we look into reactive series of metal than we will find that nickel is the example of a metal that is more reactive than tin and less reactive than iron.
Nickel and cadmium is the metal that can be oxidized with a sn2+ solution, but not with a fe2+ solution.
What is metal oxidization?An ionic chemical reaction occurs on the surface of metal in the presence of oxygen.
Metals that can be oxidized in solution must have a weaker oxidizing agent or be less reactive than tin.
With solution, the same metals cannot be oxidized.
Thus, the correct option is Nickel and cadmium.
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Compare the viscosity of n-hexane, ch3ch2ch2ch2ch2ch3, to the viscosity of n-heptane, ch3ch2ch2ch2ch2ch2ch3.
Final answer:
n-Heptane has a higher viscosity than n-hexane due to its longer carbon chain and greater molecular weight, which leads to stronger dispersion forces and hence more resistance to flow.
Explanation:
The viscosity of a liquid is a measure of its resistance to deformation or flow. In comparing the viscosities of n-hexane (CH₃(CH₂)₄CH₃) and n-heptane (CH₃(CH₂)₅CH₃), we must consider their molecular weights and the strength of their intermolecular forces. Because n-heptane has a longer carbon chain and greater molecular weight than n-hexane, it also has stronger dispersion forces. These dispersion forces increase with the molecular surface area, so the larger n-heptane molecules experience more significant intermolecular attractions. As a result, n-heptane has a higher viscosity compared to n-hexane.
Hydrogen peroxide, h2o2(aq), decomposes into water and oxygen. adding a small amount of fecl3(aq) increases the rate of gas evolution in this reaction. what is the best description of the role of fecl3?
Answer:
fecl₃ acting as catalyst-iron (III) chloride is acts as the catalyst for the reaction which takes place in the transformation of hydrogen peroxide, H₂O₂(aq) into the two main products mainly water,H₂O and oxygen,O₂.
The reaction is as follow:H₂O₂(aq)⇒ H₂O + O₂.Explanation:
Catalysts-A catalyst provide the best route or the easy path to start or initiate the reaction or the chemical transformation which leads to the speeding up the reactions.
What mass of h2o will be produced if 9.5 g of h2 reacts with 1.2 g of o2?
The mass of H₂O produced from the reaction of 9.5 g of H₂ with 1.2 g of O₂ is 1.3515 g. The calculation is based on the molar mass of the substances and the balanced equation for the formation of water.
The question asks for the mass of H₂O produced from the reaction of hydrogen (H₂) with oxygen (O₂). According to the balanced chemical equation of the formation of water, which is 2H₂ + O₂
ightarrow 2H₂O, 2 moles of H₂ react with 1 mole of O₂ to produce 2 moles of H₂O. The molar masses are as follows: H₂ (2.02 g/mol) and O₂ (32.0 g/mol). Since 1 mole of water (H₂O) has a molar mass of 18.02 g, we can use this information to calculate the mass of water produced.
The mass of 9.5 g of H₂ corresponds to 9.5 g / 2.02 g/mol =4.7 moles of H₂, and the mass of 1.2 g of O₂ corresponds to 1.2 g / 32.0 g/mol = 0.0375 moles of O₂. Since oxygen is the limiting reagent here, it will determine how much water can be produced. From the stoichiometry of the reaction, 1 mole of O₂ will produce 2 moles of H₂O. Therefore, 0.0375 moles of O₂ would produce 0.0375 moles * 2 = 0.075 moles of H₂O. To find the mass: 0.075 moles * 18.02 g/mol = 1.3515 g of H₂O.
Therefore, the mass of H₂O produced is 1.3515 g.
2C6H5COOH + 15O2 → 14CO2 + 6H2O which of the following options gives the correct product:product ratio? CO2:H2O = 14:6 CO2:H2O = 6:14 CO2:H2O = 1:1 O2:H2O = 15:6
Answer:
The Answer is a) CO2:H2O = 14:6
Explanation:
If the first half-life of a zero-order reaction is 200s, what will be the duration of the next half-life?
Provide the structure of the major product which results from 1,4-addition of br2 to the diene shown below.
100 POINTS Which energy source produces electricity at a hydroelectric dam? A. solar panels B. wind turning turbines C. falling water D. pressure from water on the dam
100 POINTS
The answer is C falling water hope this helps
Electricity at a hydroelectric dam is produced by falling water, which turns turbines to generate electricity. The ultimate source of this energy is solar energy that drives the hydrological cycle.
The energy source that produces electricity at a hydroelectric dam is C. falling water. This process involves the conversion of potential energy stored in the water behind the dam into kinetic energy as the water flows down. The kinetic energy turns the blades of turbines, which then drive a generator to produce electricity. The ultimate source of the electrical energy produced by a hydroelectric plant is solar energy, which drives the hydrological cycle that lifts water to high elevations through evaporation and precipitation.
Determine the melting point of an aqueous solution containing 101 mg of saccharin (c7h5o3ns) added to 1.00 ml of water (density of water = 1.00 g/ml, kf = 1.86°c/m).
The freezing point of the solution is - 0.74 °c.
First, we have to determine the mass of the water as follows;
Density of water = mass/ volume
Mass = Density of water × volume
Mass = 1.00 g/ml × 1.00 ml = 1.00 g or 0.001 Kg
Number of moles of solute = 101 × 10^-3 g/183 g/mol = 0.0004 moles
Molality = 0.0004 moles/0.001 Kg = 0.4 m
ΔT = K m i
K = freezing constant
m = molality
i = Van't Hoff factor
ΔT = 1.86°c/m × 0.4 m × 1 = 0.74 °c
Freezing point = 0 °c - 0.74 °c = - 0.74 °c
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What is the name of the species formed when a sodium atom loses an electron?
When a sodium atom loses an electron, it becomes a sodium ion (Na+).
Explanation:When a sodium atom loses an electron, it becomes a sodium ion (Na+).
For example, a sodium atom has 11 protons and 10 electrons. By losing one electron, it now has an overall charge of +1. This positive charge is denoted by the superscripted plus sign (Na+).
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Kemmi pipets 25.00 ml of pure 1-propanol (c3h7oh, a liquid organic alcohol) into a 100.0 ml volumetric flask. she dilutes it with di water. help her calculate the strength of her diluted solution. volumes: 25.00 ml volumetric pipet, 100.00 ml volumetric flask. molar mass of pure 1-propanol: 60.09 g/mol. density of pure 1-propanol: 0.803 g/ml calculate the number of moles in exactly 25.00 ml of 1-propanol. (3 significant digits; units of mol) [x] calculate the molarity of the diluted solution. (3 significant digits; units of m or mol/l) [y]
The number of moles of 1-propanol in 25.00 mL is 0.334 (to three significant digits). The molarity of the diluted 1-propanol solution in a 100.0 mL flask is 3.34 M (to three significant digits).
To calculate the number of moles of 1-propanol in 25.00 mL, we use the density of 1-propanol (0.803 g/mL) to find the mass:
Mass = Volume × Density = 25.00 mL 0.803 g/mL = 20.075 g
Next, we convert this mass to moles using the molar mass of 1-propanol (60.09 g/mol):
Moles of 1-propanol = Mass / Molar Mass = 20.075 g / 60.09 g/mol
This calculation yields 0.334 moles of 1-propanol (to three significant digits).
For the molarity of the diluted solution, we take into account that the total volume is now 100.0 mL. Since molarity is moles per liter (mol/L), we must first convert the volume from mL to L:
Volume in L = 100.0 mL (1 L / 1000 mL) = 0.100 L
Molarity = Moles of 1-propanol / Volume in L = 0.334 mol / 0.100 L
The molarity of the solution is 3.34 M (to three significant digits).
Sodium chloride comprises 97%-99% of table salt. Given their location on the periodic table, identify the ionic charge for each element and predict the chemical formula of the compound formed. A) Sodium, Na, is an alkali metal and is in Group IA with an ionic charge of +1. While chlorine, Cl, is a halogen and is in Group VIIA with a charge of -1. These will form NaCl(s). B) Sodium, Na, is an alkaline earth metal and is in Group IA with an ionic charge of +2. While chlorine, Cl, is a halogen and is in Group VIIA with a charge of -1. These will form NaCl2(s). C) Sodium, Na, is an alkali earth metal and is in Group IA with an ionic charge of +2. While chlorine, Cl, is a noble gas and is in Group VIA with a charge of -2. These will form Na2Cl2(s). D) Sodium, Na, is an alkali earth metal and is in Group IA with an ionic charge of +1. While chlorine, Cl, is a diatomic gas and is in Group VIA with a charge of -2. These will form Na2Cl(s).
Answer is: A) Sodium, Na, is an alkali metal and is in Group IA with an ionic charge of +1. While chlorine, Cl, is a halogen and is in Group VIIA with a charge of -1. These will form NaCl(s).
Table salt is sodium chloride mixed with small amount of potassium iodide (KI), sodium iodide (NaI) or sodium iodate (NaIO₃).
Atomic level - sodium chloride (NaCl) has crystal cubic structure (lattice-type arrangement) with ionic bonds. Sodium is cation with charge 1+ and chlorine is an anion with charge 1-.
Macroscopic level - table salt is colorless crystal, soluble in water with high melting and boiling temperature.
Ionic compounds are good good electricity and heat conductors, because ionic compounds have mobile ions (cations and anions) that are able to transfer electrical charge.
What do you need to know describe the velocity of an object
Answer:
You need to know the speed, direction (displacement) and time to describe the velocity of an object.
A nuclide of 64/29 Cu absorbs a position. Which is the resulting atom?
A) 65/29 Cu
B) 63/29 Cu
C) 64/28 Ni
D) 64/30 Zn
When a nuclide of 64/29 Cu absorbs a positron, it undergoes a process called positron emission and the resulting atom is 63/29 Cu.
Explanation:When a nuclide of 64/29 Cu absorbs a positron, it undergoes a process called positron emission. During this process, one of the protons in the nucleus is transformed into a neutron, resulting in a new atom. The resulting atom will have the same number of protons as the original atom, but one less proton. Therefore, the resulting atom will be 63/29 Cu, which is option B.
A 42 kg sample of water absorbs 347 kJ of heat. If the water was initially at 23.2 ∘C, what is its final temperature?
which molecular formula is also an empirical formula?
1)C6h6
2)h2o2
3) n2h4
4) n2o5
The molecular formula which is also an empirical formula is Choice 4: N2O5
The molecular formula of a compound is always a multiple of the empirical formula.
The choices are analysed as follows;
For Choice 1;
The subscripts can further be divided. As such, C6H6 is a molecular formula but not an empirical formula.For Choice 2;
The subscripts can further be divided. As such, H2O2 is a molecular formula but not an empirical formula.
For Choice 3;
The subscripts can further be divided. As such, N2H4 is a molecular formula but not an empirical formula
However; For Choice 3;
The subscripts can not be further divided. As such, N2O5 is a molecular formula and also an empirical formula.
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Which of the following substances is considered to be a base? A. HCl B. HNO3 C. H2SO4 D. Ca(OH)2
Among the options given, Ca(OH)2 or calcium hydroxide is considered to be a base. Thus, the correct option for this question is D.
What do you mean by a base?A base in chemistry is defined as a type of chemical substance that can significantly accept hydrogen ions in water and can neutralize an acid. Bases feel soapy or slippery on the skin in texture and they have the ability to turn certain dyes blue.
According to the context of this question, H2SO4 or sulphuric acid is the strongest acid along with HNO3 (nitric acid) and HCl (hydrochloric acid). An example of a base is sodium hydroxide. Basicity is measured on a scale called the pH scale.
Therefore, Ca(OH)2 or calcium hydroxide is considered to be a base. Thus, the correct option for this question is D.
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If the calcium oxide were to be obtained by the heating of calcium hydroxide, how much hydroxide would be needed to obtain the 15.0 g?
A compound is found to contain 58.80 % xenon, 7.166 % oxygen, and 34.04 % fluorine by mass. what is the empirical formula for this compound?
An excess of Ba(No3)2 reacts with 250ml of H2SO4 solution to give 0.55g of BaSo4.determine The concentration in moles per litre of the Ba(No3)2 solution?
how many grams of NaCl will be needed to form 600 ml of a saturated solution at 100 degrees celsius ?
A reaction produces 74.10 g Ca(OH)2 after 56.08 g CaO is added to 36.04 g H2O. How should the difference in the masses of reactants and products be explained?
The difference in masses of reactants and products in the reaction CaO + H2O → Ca(OH)2 could be due to measurement errors, presence of impurities, incomplete reactions, or factors such as the absorption of water if the product mass is greater than that of the reactants.
Explanation:The 1:1 stoichiometry reaction you are referring to is CaO(s) + H2O(l) → Ca(OH)2(s). In this reaction, 56.08 g of CaO reacts with 36.04 g of H₂O to produce 74.10 g of Ca(OH)₂. The law of conservation of mass states that matter cannot be created or destroyed; hence the total mass of reactants should equal the mass of the products in a chemical reaction.
However, in realistic scenarios, there could be minor deviations due to aspects like measurement errors, the presence of impurities, or incomplete reactions. If the reaction goes to completion, and no gases are created (which may escape the reaction system), the masses should equal.
If the resulting mass of the product, Ca(OH)₂, is less than the combined mass of reactants, it suggests that there may be unreacted CaO or H₂O left. If the mass of Ca(OH)₂ is more than the reactants, it could suggest impurities, absorption of water, or some other factors at play.
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A 13.0 kg iron weightlifting plate has a volume of 1650 cm3 . What is the density of the iron plate in g/cm3?
Explanation:
It is known that density is the amount of mass divided by volume.
Mathematically, Density = [tex]\frac{mass}{volume}[/tex]
It is given that mass is 13.0 kg or 13000 g (as 1 kg = 1000 g). And, volume is 1650 [tex]cm^{3}[/tex].
Therefore, calculate the density as follows.
Density = [tex]\frac{mass}{volume}[/tex]
= [tex]\frac{13000 g}{1650 cm^{3}}[/tex]
= [tex]7.87 g/cm^{3}[/tex]
Thus, we can conclude that density of the given iron plate is [tex]7.87 g/cm^{3}[/tex].
A gas sample has a volume of 178 mL at 0.00oC.The temperature is raised at constant pressure until the volume reaches 211 mL. What is the temperature of that gas sample at this volume?
The temperature of the gas will be 324K or [tex]\rm \bold{51^\cdot C}[/tex] when volume reaches 211 mL.
Charle's law stated that the volume occupied by fixed amount of gas is directly proportional to the temperature,while pressure is constant.
[tex]\rm \bold{\frac{V_1}{T_1} =\frac{V_2}{T_2}}[/tex]
Where,
[tex]\rm \bold V_1[/tex] is initial volume = 178mL
[tex]\rm \bold {V_2}[/tex] is final volume = 211mL
[tex]\rm \bold{ T_1}[/tex] is initial temperature = [tex]\rm \bold{0.00^\cdot C}[/tex] = 273K
[tex]\rm \bold {T_2}[/tex] is final temperature = ?
Put the values,
[tex]\rm \bold{\frac{178}{273} =\frac{211}{T_2}}\\\\\rm \bold{T_2=324 K}[/tex]
Hence, we can conclude that the temperature of the gas will be 324K or [tex]\rm \bold{51^\cdot C}[/tex] when volume reaches 211 mL.
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What is the ph of a 0.015 m aqueous solution of hydrazoic acid (hn3) (ka = 1.9 x 10–5) at 25°c?
A ball-and-stick model of a molecule provides much the same information as a
Both the ball-and-stick and space-filling models are 3D molecular representations, with the former displaying the bonds and the latter showing the relative atom sizes and general shape.
A ball-and-stick model of a molecule provides much the same information as a space-filling model. Both are used to represent the three-dimensional structure of a molecule in different ways. The ball-and-stick model shows atoms as spheres and bonds as sticks, highlighting the bond angles and lengths between atoms.
In contrast, the space-filling model represents atoms by spheres that are sized proportionally to the atoms' radii, depicting the actual volume occupied by the atoms without showing the bonds explicitly.
While the ball-and-stick model may exaggerate the space between the atoms, it is beneficial for understanding the geometry of the chemical bonds. The space-filling model, however, allows for visualization of the molecule's general shape and the relative sizes of the atoms. Both models are simplifications and do not fully capture subtle variations in bond lengths and angles.
Be sure to answer all parts. identify and label the species in each reaction. (a) nh4+(aq) + h2o(l) ⇌ nh3(aq) + h3o+(aq) acid base acid base conjugate acid conjugate base conjugate acid conjugate base (b) cn−(aq) + h2o(l) ⇌ hcn(aq) + oh−(aq) acid base acid base conjugate acid conjugate base conjugate acid conjugate base
In the given reaction, label the species as acid, base, conjugate acid, and conjugate base. (a) Acid: NH4+, Base: H2O, Conjugate Acid: H3O+, Conjugate Base: NH3. (b) Acid: CN-, Base: H2O, Conjugate Acid: HCN, Conjugate Base: OH-
Explanation:(a) In the reaction: NH4+(aq) + H2O(l) ⇌ NH3(aq) + H3O+(aq), we have NH4+ as the acid and H2O as the base. After the reaction, NH3 becomes the conjugate base and H3O+ becomes the conjugate acid.
(b) In the reaction: CN-(aq) + H2O(l) ⇌ HCN(aq) + OH-(aq), we have CN- as the acid and H2O as the base. After the reaction, HCN becomes the conjugate acid and OH- becomes the conjugate base.
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Ethylene gas and steam at 320°c and atmospheric pressure are fed to a reaction process as an equimolar mixture. the process produces ethanol by the reaction: c2h4(g) + h2o(g) → c2h5oh(l)c2h4(g) + h2o(g) → c2h5oh(l) the liquid ethanol exits the process at 25°c. what is the heat transfer associated with this overall process per mole of ethanol produced?
Without specific enthalpy change (ΔH) values for the reactions in question, we cannot accurately calculate the heat transfer per mole of ethanol produced. However, if these values were provided, the general formula qp = ΔH(T2-T1)/T1*T2 could be used to determine this, where qp represents heat transfer at constant pressure, T1 and T2 are the initial and final temperatures respectively.
Explanation:This question pertains to the field of thermochemistry and the role of heat transfer in chemical reactions. The process in question involves the transformation of ethylene gas and steam into ethanol, or C2H5OH. We would need the specific heat, or enthalpy change (ΔH), values for these reactions to calculate the heat transfer per mole of ethanol produced. Since these values haven't been provided, we can't provide a definite answer.
Generally, in such questions, when ΔH values and temperatures are given, one formula that can be applied is q_p = ΔH(T2-T1)/T1*T2 where T1 is initial temperature, T2 is final temperature and qp represents heat transfer at constant pressure.
This formula can be used to estimate the heat transfer associated with the process per mole of ethanol produced, once the ΔH value is known. It's also important to remember that if the reaction is exothermic (releases heat), the ΔH value would be negative, and if it's endothermic (absorbs heat), the ΔH value would be positive.
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Think about a carbon atom that is released into the atmosphere from the burning of wood in a campfire. If it were to go through the whole carbon cycle,
Step 1 A caterpillar gets the carbon by eating the tree's leaves.
Step 2 The bird decomposes and the carbon is added to the atmosphere.
Step 3 A bird gets the carbon by eating the caterpillar.
Step 4 The bird flies into a building and dies instantly. It falls to the ground
Step 5 A tree absorbs the carbon from the atmosphere into its leaves for photosynthesis.
plz help me by telling me what order this go's in?
Answer: the actual answer is
step 1: A tree absorbs the carbon from the atmosphere into its leaves for photosynthesis
step 2: A caterpillar gets the carbon by eating the tree's leaves
step 3: A bird gets the carbon by eating the caterpillar
step 4: The bird flies into a building and dies instantly. It falls to the ground
step 5: The bird decomposes and the carbon is added to the atmosphere
Explanation:
What is the molecular formula of the molecule that has an empirical formula of C2H2O and a molar mass of 252.22 g/mol?
Empirical formula is the simplest whole number ratio of elements in a compound. Molecular formula is n times the empirical formula, where n is integers 1,2,... Therefore, the molecular formula of the compound C[tex]_{10}[/tex]H[tex]_{10}[/tex]O[tex]_5[/tex].
What is empirical formula?
Empirical formula gives the proportion of the element that is present in a compound. It does not give information about the actual number or the arrangements of the atoms.
n= molecular formula÷ empirical formula
Molar masses of C[tex]_2[/tex]H[tex]_2[/tex]O
C = 12.0107
H = 2.016
O = 15.999
Molar masses of C[tex]_2[/tex]H[tex]_2[/tex]O =2(12.0107)+2(2.016)+15.999
=24.0214+4.032+15.999
= 44.0524
252.22/44.0524 = 5
C[tex]_2[/tex]H[tex]_2[/tex]O ×5=C[tex]_{10}[/tex]H[tex]_{10}[/tex]O[tex]_5[/tex]
The molecular formula is C[tex]_{10}[/tex]H[tex]_{10}[/tex]O[tex]_5[/tex]
Therefore, the molecular formula of the compound C[tex]_{10}[/tex]H[tex]_{10}[/tex]O[tex]_5[/tex].
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