A box weighing 180 newtons is hanging by rope as shown in the figure. Find the tension T2.
A. 81 newtons
B.
171 newtons
C. 130 newtons
OD. 85 newtons

Explanation:

The gravitational potential energy is the energy that a body or object possesses, due to its position in a gravitational field.

That is why this energy depends on the relative height of an object with respect to some point of reference and associated with the gravitational force.

In the case of the Earth, in which  the gravitational field is considered constant, the value of the gravitational potential energy [tex]U_{p}[/tex] will be:

[tex]U_{p}=mgh[/tex]  

Where [tex]m[/tex] is the mass of the object, [tex]g[/tex] the acceleration due gravity and [tex]h[/tex] the height of the object.

As we can see, the value of [tex]U_{p}[/tex] is directly proportional to the height.

Earth is considered an inner planet because it lies between the Sun and the main asteroid belt, along with the other terrestrial planets Mercury, Venus, and Mars.

Earth is considered to be an inner planet because it is located between the sun and the main asteroid belt. This asteroid belt is the region of the solar system between the orbits of Mars and Jupiter, where most asteroids are found. Earth, along with Mercury, Venus, and Mars, falls into the category of terrestrial or inner planets, which are closer to the Sun and primarily composed of rock and metal with solid surfaces that have geological features.

Correct answer to the student's question: B- It is located between the sun and the main asteroid belt.

Answer:

Pulse modulation

Explanation:

Remote control toys use the radiations that lie in the range of infrared for their working. The frequency of these infrared radiations is  36-46 kilo Hertz.

The signals we give to the toys through remote control are actually given in the form of bits of data which are then modulated with the any desired carrier frequency. Therefore, the data we are sending is in the form of pulses and the pulses' duration determines that whether the signal will be read as OFF (0) or ON (1). This modulation is pulse modulation which is an effective method to lower the power value delivered by a signal by cutting the signal into smaller parts.

Similarly there are some other kinds of modulations used in some other purposes like frequency and amplitude modulation for signals transmission video and music.

Hope it helps!

Answer:

pulse

Explanation:

Answer:

5,000 cal

Explanation:

q = m C ΔT

where q is heat, m is mass, C is specific heat, and ΔT is change in temperature.

q = (500 g) (1.0 cal/g/°C) (10.0°C)

q = 5,000 cal

Answer: false

Explanation: the longer the period, the less thef= frequency

Answer:

True

Explanation:

As frequency increases, period decreases, and vice versa.

For more information please comment below and I'll respond as soon as possible.

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Answer:

The plan would result in domination of the country by special interests. - C.

Answer:

100 Watts

Explanation:

Power is work per time.

P = W / t

P = 200 J / 2 s

P = 100 W

Answer: 100 Watts

Explanation:

Answer:

AMURT

Explanation:

BUT THERE ARE MANY OTHERS LIKE THE AMERICAN RED CROSS ETC

Answer: Mercy corps

answered this on another dudes comment thread but still, give me brainliest please!

1. Acceleration: [tex]0.375 m/s^2[/tex]

Newton's second law states that the net force on an object is equal to the product between the object's mass and its acceleration:

F = ma

where

F is the net force

m is the mass

a is the acceleration

For the crate in this problem we have

F = 60 N

m = 160 kg

Re-arranging the equation, we can find the acceleration of the crate:

[tex]a=\frac{F}{m}=\frac{60 N}{160 kg}=0.375 m/s^2[/tex]

2. Distance: 3 m

For this problem we can use the following SUVAT equation:

[tex]S=ut+\frac{1}{2}at^2[/tex]

where

S is the distance travelled by the crate

u = 0 is the initial velocity, since it starts from rest

t = 4 s is the time elapsed

[tex]a=0.375 m/s^2[/tex] is the acceleration

Substituting all numbers into the equation,

[tex]S=0+\frac{1}{2}(0.375)(4)^2=3 m[/tex]

3. Work done: 180 J

The work done by a force, assuming that the force is parallel to the displacement of the object, is given by

W = F d

where

W is the work done

F is the magnitude of the force

d is the displacement

Here we have

F = 60 N

d = 3 m

So the work done is

[tex]W=(60 N)(3 m)=180 J[/tex]

4. Final velocity: 1.5 m/s

The final velocity of the crate can be found by using the following SUVAT equation:

[tex]v^2 = u^2 +2ad[/tex]

where here

u = 0 is the initial velocity

[tex]a=0.375 m/s^2[/tex] is the acceleration

d = 3 m is the distance covered

Substituting all the numbers that we have, we found:

[tex]v=\sqrt{u^2 +2ad}=\sqrt{0^2+2(0.375)(3)}=1.5 m/s[/tex]

5. Kinetic energy: 180 J

The kinetic energy of an object is given by

[tex]K=\frac{1}{2}mv^2[/tex]

where

m is the mass of the object

v is the velocity

Here we have

m = 160 kg is the mass of the crate

v = 1.5 m/s is its final velocity

So the kinetic energy of the crate is

[tex]K=\frac{1}{2}(160)(1.5)^2=180 J[/tex]

Answer:

2 m

Explanation:

Work = force × distance

500 J = 250 N × d

d = 2 m

She moved the couch 2 meters.

Answer:

When the neutral point of a magnet is broken into two each part gains polarity opposite to each other. This is because the broken parts of this magnet become a complete magnet as the Original magnet with complete poles N and S.  

When the neutral region of a bar magnet is broken into two, the broken two parts of the magnet becomes a whole magnet in itself, that is from one magnet, two new magnets are formed.

Explanation:

The neutral region exists in the mid of the magnet as the magnet is only polarized at the end on whole. Thereby the broken pieces on its ends acquires the polarity on the two end sides.

This occurs in both the broken parts. With the acquirement of the polarity, one side becomes the North Pole and the other side becomes the South pole. Therefore, the broken bar magnets becomes a magnet in itself.  

The following formula relates applied force to pressure:

P = F/A

P is the pressure, F is the applied force, and A is the area over which the force is applied.

Unfortunately we cannot calculate the pressure if we don't know the area of contact between the ball and the tube.

Answer:

The following diagram shows resistors in a series circuit.

Answer:

104 N

Explanation:

Calculate the spring stiffness:

F = kx

32.5 N = k (0.500 cm)

k = 65 N/cm

Find the force for the new length:

F = kx

F = (65 N/cm) (1.60 cm)

F = 104 N

The safety contract will include basic lab safety guidelines such as:

Further Explanation:

In his safety contract, Chris will find statements that has him agreeing that he will behave appropriately inside the lab especially since they will be working with an open fire (Bunsen burner) or a heating equipment (hot plate) to change the temperature of the water. Proper behavior and basic expectation inside a lab are in the items listed above.

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Keywords: lab safety, lab contract

Answer:

th

Explanation:

Answer:

10 kW

Explanation:

First convert km/hr to m/s.

72 km/hr × (1000 m / km) × (1 hr / 3600 s) = 20 m/s

The power is:

P = Fv

P = (500 N) (20 m/s)

P = 10000 W

P = 10 kW

The power applied by the bike is 10 kW.

The power applied by the bike climbing the inclined road at a constant speed with a force of 500 N is calculated as 10000 watts or 10 kW using the formula Power = Force x Velocity.

The problem at hand involves calculating the power applied by a bike when it ascends an inclined road at a uniform speed while applying a force. To find the power, we need to use the formula for power in the context of mechanical systems, which is Power (P) = Force (F) × Velocity (v). Here, force is given as 500 N and the velocity can be converted from 72 km/hr to meters per second (m/s) by multiplying it with (1000 m/km) / (3600 s/hr), which gives us 20 m/s.

Therefore, the power applied by the bike is P = 500 N × 20 m/s = 10000 watts or 10 kW.

This is the instantaneous power delivered by the force that the bike exerts on the road to overcome resistant forces like friction and air resistance while moving uphill. It's important to note that the power can change if any of the variables, such as speed or the force, change.

Answer:

870 metres

Explanation:

Speed = Distance/Time

Distance = Speed x Time

Distance = 29 x 30

= 870 metres

Answer:

5.61 seconds

Explanation:

Given:

y₀ = 0 m

y = 14.0 m

v₀ = 30.0 m/s

a = -9.8 m/s²

Find: t

y = y₀ + v₀ t + ½ at²

14 = 0 + 30t − 4.9t²

4.9t² − 30t + 14 = 0

Solve with quadratic formula:

t = [ -b ± √(b² − 4ac) ] / 2a

t = [ 30 ± √(900 − 274.4) ] / 9.8

t = 0.509, 5.61

t = 0.509 is the time when the ball first reaches the height of 14.0 meters on the way up.  t = 5.61 is the time when the ball reaches the height of 14.0 meters on the way down.

Since we know the ball reaches its maximum height and begins falling again, we want the second time.  t = 5.61 seconds.

Answer:

three times

Explanation:

F=Eq

3F=3Eq

Answer:

three times

Explanation:

The relation between the force and the electrostatic field is given by

F = q E

where, F be the force , q be the charge and E be the strength of electrostatic field.

Here the charge is q

F = q E .... (1)

Now the charge remains same but the force three times, let E' be the electrostatic field strength.

3F = q E'    .... (2)

Divide equation (2) by equation (1)

E' / E = 3F / F

E' = 3 E

Answer:

4 m/s

Explanation:

Momentum is conserved.

m₁ v₁ + m₂ v₂ = (m₁ + m₂) v

(50)(5) + (20)(1.5) = (50 + 20) v

v = 4

The final velocity is 4 m/s.

We want to find how much momentum the dumbbell has at the moment it strikes the floor. Let's use this kinematics equation:

Vf² = Vi² + 2ad

Vf is the final velocity of the dumbbell, Vi is its initial velocity, a is its acceleration, and d is the height of its fall.

Given values:

Vi = 0m/s (dumbbell starts falling from rest)

a = 10m/s² (we'll treat downward motion as positive, this doesn't affect the result as long as we keep this in mind)

d = 80×10⁻²m

Plug in the values and solve for Vf:

Vf² = 2(10)(80×10⁻²)

Vf = ±4m/s

Reject the negative root.

Vf = 4m/s

The momentum of the dumbbell is given by:

p = mv

p is its momentum, m is its mass, and v is its velocity.

Given values:

m = 10kg

v = 4m/s (from previous calculation)

Plug in the values and solve for p:

p = 10(4)

p = 40kg×m/s

By using the equations of motion and momentum, it can be determined that a 10 kg d.umbbell falling from a height of 80 cm will transfer 40 kg m/s of momentum to the floor.

The subject of this question is Physics, particularly dealing with the concept of momentum. To find out how much momentum a d.umbbell will transfer to the floor, we first need to calculate its velocity right before it hits the ground. This can be calculated using the equation of motion: v² = u² + 2gh, where u (initial velocity) is 0 (because it starts from rest), g (gravity) is 10 m/s², and h (height) is 0.8m (80cm).

Using the given values in the equation, the velocity v comes out to be √(2*10*0.8) = √16 = 4 m/s. The momentum is then calculated using the formula p=mv, where p represents momentum, m is mass, and v is velocity. Substituting the mass (10 kg) and the velocity (4 m/s), we find out that the momentum transferred to the floor is 40 kg m/s. Therefore, a d.umbbell of mass 10 kg falling from a height of 80 cm transfers 40 kg m/s momentum to the floor.

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The displacement covered by the worker in the whole trip is 30km.

The easiest way to solve this problem is using the displacement equation:

Δx = x₂ - x₁

A worker covers a distance of 40 km from his house to his place of

work, and 10 km towards his house back. So:

Δx = x₂ - x₁ = 40km - 10km = 30km

Since displacement is a vector quantity, the displacement of the worker from the data is 30Km.

Displacement refers to distance covered in a specific direction. Hence, unlike distance, we include direction in our discussion of  displacement.

As such, displacement is a vector quantity therefore, the displacement of the worker is obtained from 40 Km - 10 Km = 30Km.

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Answer:

4020 N

Explanation:

First convert km/h to m/s.

54.0 km/h × (1000 m / km) × (1 h / 3600 s) = 15.0 m/s

Sum of the forces in the radial direction:

∑F = ma

F = m v² / r

F = (1250 kg) (15.0 m/s)² / 70.0 m

F ≈ 4020 N

Answer:

v² = u² + 2x²

Explanation:

v² = u² + 2as​ is only valid for constant acceleration.  Here, the acceleration is a function of position.  We can find the function of velocity by integrating.  Acceleration is the derivative of velocity with respect to time:

a = 2x

dv/dt = 2x

Apply chain rule:

dv/dt = dx/dt × dv/dx

dv/dt = v × dv/dx

Therefore:

v dv/dx = 2x

Separate the variables and integrate:

v dv = 2x dx

½ v² |ᵤᵛ = x² |₀ˣ

½ (v² − u²) = x²

v² − u² = 2x²

v² = u² + 2x²

Answer:

I believe the answer is C

Explanation:

For this case we must make a conversion, we have as data that:

1 gallon is equivalent to 3.79 liters

By making a rule of three we have:

1 gallon ------------> 3.79 L

13 gallons --------> x

Where "x" represents the equivalent in liters:

[tex]x = \frac {13 * 3.79} {1}\\x = 49.27[/tex]

So, we have 49.27 liters of gasoline.

Answer:

Option C

Answer:

distance between the objects

masses of the objects

Explanation:

Gravitational force is a force of attraction that pulls two objects with masses together.

To best understand the concept of gravitational force, newton's law of universal gravitation provides a good insight. The law states that "every object in the universe attracts each other with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distances between them".

From the law, we see that gravitational force is dependent on the masses of the object and their distances.  

Answer:

B. distance between the objects

C. masses of the objects

Answer:

7500 m/s

Explanation:

Centripetal acceleration = gravity

v² / r = GM / r²

v = √(GM / r)

Given:

G = 6.67×10⁻¹¹ m³/kg/s²

M = 5.98×10²⁴ kg

r = 6.8×10⁵ + 6.357×10⁶ = 7.037×10⁶ m

v = √(6.67×10⁻¹¹ (5.98×10²⁴) / (7.037×10⁶))

v = 7500

The orbital velocity is 7500 m/s.

The orbital velocity is 7500 m/s.

Orbital velocity is defined as the minimum velocity a body must maintain to stay in orbit.

Given

h = 6.8 E 5 m = 6.8 * [tex]10^{5}[/tex] m

mass of satellite = 5.6 * [tex]10^{5}[/tex] kg

Earth's mass : m(e)  = 5.98 E 24 kg

Earth's radius ; R(e) = 6.357 E 6 m

orbital velocity :v(orbiting ) = [tex]\sqrt{Gm(e) / R(e) + h}[/tex]

R(e) + h  = 6.8×10⁵ + 6.357×10⁶ = 7.037×10⁶ m

v = √(6.67×10⁻¹¹ * (5.98×10²⁴)) / (7.037×10⁶))

v = 7500 m/s

The orbital velocity is 7500 m/s.

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Explanation:

critacal temperature

Answer:

The magnitude is 63 kg m²/s, and the direction is -k.

Explanation:

Plug the values into the equation:

L = m v×r

L = (3.0 kg) (<5 i + 3j> m/s × <2i − 3j> m)

Take the cross product.  The cross product of two dimensional vectors is:

<v₁ i + v₂ j> × <r₁ i + r₂ j> = <(v₁ r₂ − v₂ r₁) k>

Therefore:

L = (3.0 kg) <((5)(-3) − (3)(2)) k m²/s>

L = (3.0 kg) <-21 k m²/s>

Multiply:

L = <-63 k kg m²/s>

The magnitude is 63 kg m²/s, and the direction is -k.

Answer:

120°

Explanation:

Draw a free body diagram.  There are three forces acting on the traffic light.  Two tension forces acting along the cables, and weight.

The tension forces have an angle θ between them.  That means each tension force forms an angle of θ/2 with respect to the vertical.  So the y component of each tension force is:

Ty = T cos (θ/2)

Sum of the forces in the y direction:

∑F = ma

Ty + Ty − W = 0

2 Ty = W

Substituting:

2 T cos (θ/2) = W

If W = T, then:

2 W cos (θ/2) = W

2 cos (θ/2) = 1

cos (θ/2) = 1/2

θ/2 = 60°

θ = 120°

The angle between the cables Ф so that the tension in each cable will be equal to the weight of the traffic signal light is 120°

Let

Now, the angle between the tension and the vertical is α = Ф/2.

The net force vertical force on the traffic light is F = Tcosα + T'cosα - W

Since the traffic light is in equilibrium, we have that F = 0

So, F = Tcosα + T'cosα - W

Tcosα + T'cosα - W = 0

Tcosα + T'cosα = W

Now, since the tension in each cable equals the weight of the traffic light, T = T' = W.

So, Tcosα + T'cosα = W

Wcosα + Wcosα = W

2Wcosα = W

cosα = W/2W

cosα = 1/2

α = cos⁻¹(1/2)

α = 60°

Since α = Ф/2

Ф = 2α

Ф = 2(60°)

Ф = 120°

So, the angle between the cables Ф so that the tension in each cable will be equal to the weight of the traffic signal light is 120°

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