Answer:
The speed of the car is 32.4m/s
Explanation:
1mi = 1600m
152mi = 243 200m
2hr 5min = 7200s + 300s
= 7500s
speed = distance/time
= 243200/7500
= 32.4m/s (3s.f)
Which can cause blockage of the ear canal, leading to hearing loss? aging disease earwax noise
Explanation:
Earwax helps to protect your ears from infection so if you like chewing gum, this helps in removing the wax. But this might not happen at your young age. So if you grow and still likes chewing gum it will remove the wax completely thereby leading to loss on hearing
A ball rolls 50 meters in
10 seconds *
A. 2 meters per second
B. 5 meters per second
C. 10 meters per second
D. 25 meters per second
The speed of the ball is B. 5 meters per second
Explanation:
For an object in uniform motion (= at constant velocity), the speed can be calculated using the equation
[tex]v=\frac{d}{t}[/tex]
where
v is the speed
d is the distance covered
t is the time taken
For the ball in this problem:
d = 50 m is the distance covered
t = 10 s is the time taken
Substituting, we find the speed:
[tex]v=\frac{50}{10}=5 m/s[/tex]
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If all of the forces acting on an object are balanced, then:
Check all that apply.
I
A. the direction the object is moving in will not change.
B. the acceleration of the object will be 0 m/s2
I
c. the object will not be in motion.
D. the velocity of the object will be 0 m/s.
A. the direction the object is moving in will not change.
B. the acceleration of the object will be 0 m/s2
Explanation:
We can answer this problem by using Newton's second law of motion:
[tex]\sum F = ma[/tex]
where
[tex]\sum F[/tex] is the net force acting on an object
m is the mass of the object
a is its acceleration
In this problem, all the forces acting on the object are balanced, therefore the net force is zero:
[tex]\sum F=0[/tex]
which means that also the acceleration is zero:
[tex]a=0[/tex]
Acceleration is equal to the rate of change of velocity: therefore, zero acceleration means that the velocity of the object does not change. We can now analyze the given statements:
A. the direction the object is moving in will not change. --> TRUE, because the velocity is not changing.
B. the acceleration of the object will be 0 m/s2 --> TRUE, as we stated above
c. the object will not be in motion. --> FALSE: we just know that its velocity is constant, but it can be different from zero
D. the velocity of the object will be 0 m/s. --> FALSE, for the same reason stated in C
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Final answer:
When all of the forces on an object are balanced, the object will not change its direction of motion, its acceleration will be 0 m/s^2, and its velocity will be 0 m/s.
Explanation:
When all of the forces acting on an object are balanced, several things occur:
The direction the object is moving in will not change. This is because there is no net force acting on the object to change its motion.The acceleration of the object will be 0 m/s². This is because acceleration is directly proportional to the net force acting on an object, and if the forces are balanced, there is no net force and therefore no acceleration.The velocity of the object will be 0 m/s. Velocity is the rate at which an object changes its position, and if the forces are balanced, there is no change in position and therefore the velocity is 0 m/s.explain why a description of position depends on a refrence point.
Answer:
starting point you choose to describe the location, or position, of an object. A description of position depends on a reference point because if the reference point changes than the distance and direction can change. Before the weight was moving two forces were acting on it.ation:
A 2.3 kg block slides along a frictionless
horizontal with a speed of 5.3 m/s. After
sliding a distance of 8 m, the block makes
a smooth transition to a frictionless ramp
inclined at an angle of 43° to the horizontal.
The acceleration of gravity is 9.81 m/s.
5.3 m/s
2.3 kg
How far up the ramp does the block slide
before coming momentarily to rest?
Answer in units of m.
Answer:
The block slides 2.1 m up the ramp before coming momentarily to rest
Explanation:
Let the maximum height reached by the block be 'h' m.
Given:
Mass of the block is 2.3 kg.
Initial velocity of the block is, [tex]u=5.3\ m/s[/tex]
Since, the block comes momentarily to rest, the final velocity is zero.
Final velocity at the maximum height of the ramp is, [tex]v=0[/tex]
Acceleration due to gravity is, [tex]g=9.8\ m/s^2[/tex]
Angle of inclination is, [tex]\theta=43\°[/tex]
Now, since all the surfaces are frictionless, we can apply law of conservation of energy.
Therefore, as per conservation of energy,
Decrease in kinetic energy = Increase in potential energy
[tex]\frac{1}{2}m(u^2-v^2)=mgh\\\frac{1}{2}(5.3^2-0)=(9.8)h\\9.8h=\frac{28.09}{2}\\h=\frac{28.09}{2\times 9.8}=1.43\ m[/tex]
The maximum height reached by the block is 1.43 m. Now, the distance traveled along the ramp is the hypotenuse.
The hypotenuse length of the block along the ramp is given as:
[tex]L=\frac{h}{\sin \theta}\\\\L=\frac{1.43}{\sin 43\°}\\L=2.1\ m[/tex]
Therefore, the block slides 2.1 m up the ramp before coming momentarily to rest.
Water flow will be reduced in a pipe if the pipe is constricted. True False
The CORRECT answer is TRUE.
10) If the mass 2m, the left mass
is m/2 and the distance is
r What is the gravitation
force ?
Answer:
F = [tex]\frac{-Gm_{1}m_{2} }{r^{2} }[/tex].
Explanation:
Gravitational force between two objects of masses [tex]m_{1}, m_{2}[/tex] kept at a distance r is given by the formula
F = [tex]\frac{-Gm_{1}m_{2} }{r^{2} }[/tex]
Here ,[tex]m_{1}[/tex] = 2m
[tex]m_{2}[/tex] = [tex]\frac{m}{2}[/tex]
Thus , F = [tex]\frac{-G.2m.\frac{m}{2} }{r^{2} }[/tex]
F = [tex]\frac{-Gm_{1}m_{2} }{r^{2} }[/tex].
Type O negative blood is considered the universal red blood cell donor because it _____.
A.
Has all 3 types of antigens.
B.
Has all 3 types of antibodies.
C.
Lacks all 3 types of antigens.
D.
Lacks all 3 types of antibodies.
Answer:
Honestly i think the answer is B
Explanation:
the periodic table arranges elements by increasing_____.
The periodic table arranges element by increasing atomic number
what happens when light travels from one medium to another with a different index of refraction at a zero degree angle of incidence?
Answer:
No Refraction takes places
Explanation:
When light travels from one medium to another at an angle of incidence 0 degree then no refraction takes place .
It is because according to Refraction law
[tex]n_{i}[/tex]sini = [tex]n_{r}[/tex]sinr
where [tex]n_{i} ,n_{r}[/tex] are the refractive index of medium of incidence and medium of refraction .
When i = 0 , left side of the equation becomes 0 and thus r (angle of refraction) must be zero. So No refraction takes place
Answer:
If the index of refraction of the medium is greater, the light slows down.
A certain steam turbine is designed to be used as both a power generator and a pump. When used as a generator, the turbine provides enough power to do 3* 10^10 J of work in 1 min. What is the power output of the turbine?
Answer:
5 x 10^8 W
Explanation:
Power = Energy ÷ time
given
Energy = 3 x 10^10J
time = 1 min = 60 s
Power = Energy ÷ time
= 3 x 10^10 ÷ 60
= 5 x 10^8 W
Final answer:
The power output of the steam turbine that does 3 × 10^10 joules of work in 1 minute is 500 megawatts.
Explanation:
The student asked about the power output of a steam turbine that does 3 × 10^10 joules of work in 1 minute. To determine the power output, we use the formula Power = Work / Time. The work done is 3 × 10^10 joules, and the time is 1 minute, which is 60 seconds. Therefore, the power output is:
Power = 3 × 10^10 J / 60 s = 5 × 10^8 watts or 500 megawatts.
This indicates that when functioning as a generator, this turbine can generate 500 megawatts of power.
Arthur reads an article describing an experiment to test the effects of caffeine on the reaction time of humans—how long it took them to respond to a particular signal. In the experiment, the subjects' reaction times were measured, then they were divided into three groups. One group was given a high dose of caffeine. The second group was given a medium dose of caffeine. The third group was given a sugar pill that had no caffeine. After waiting 45 min for the caffeine to take effect, the reaction times were measured again.
In the experiment Arthur read about, what was the dependent variable?
A.
the amount of caffeine given to each person
B.
the type of signal each person responded to
C.
the amount of time the caffeine was given to take effect
D.
the change in reaction times for each person
Answer:
the change in reaction times for each person
Explanation:
The dependent variable in Arthur's article on the effects of caffeine on human reaction time is the change in reaction times for each person after consuming caffeine or a placebo.
Explanation:In the described experiment, the dependent variable is the change in the subjects' reaction times after they have been administered varying amounts of caffeine or a placebo. This is because the dependent variable is the factor that the researchers are measuring to see if it changes in response to the manipulation of the independent variable (in this case, the amount of caffeine given to each person). The different doses of caffeine or the placebo (sugar pill) represents the independent variables, because they are what the researchers are manipulating to see if there is an effect on the dependent variable.
Therefore, the correct answer to the question 'In the experiment Arthur read about, what was the dependent variable?' is D. the change in reaction times for each person.
A feather is dropped onto the surface of the moon. How far will the feather have fallen if it reaches the surface in 9.00 seconds?
Given: g on moon = –1.63 meters/second2
Answer: 66m
Explanation:
Using equation of motion;
S = ut + 1/2gt²
u = 0 ( initial velocity wasn't given)
t = 9s
g = 1.63m/s²
S = 0 + 0.5*(1.63)*(9²)
S= 66.015m
A feather is dropped onto the surface of the moon. How far will the feather have fallen if it reaches the surface in 9.00 seconds?
The distance covered by the feather is 65.5 m
Explanation:
The motion of the feather is a free-fall motion (affected only by the force of gravity), therefore it is a motion at constant acceleration, and so we can use the following suvat equation:
[tex]s=ut+\frac{1}{2}at^2[/tex]
where
s is the displacement
u is the initial velocity
t is the time
a is the acceleration
In this problem, we have
u = 0 is the initial velocity of the feather
t = 9.00 s is the time interval
[tex]a=g=1.62 m/s^2[/tex] is the acceleration of gravity on the Moon
And solving for s, we find the distance covered by the feather in its fall:
[tex]s=0+\frac{1}{2}(1.62)(9.00)^2=65.6 m[/tex]
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Determine the acceleration of a raptor that reaches 25 m/s from rest in 6.5 s.
Answer:
3.8 m/s²
Explanation:
Average acceleration is the change in velocity over change in time.
a = Δv / Δt
a = (25 m/s − 0 m/s) / 6.5 s
a ≈ 3.8 m/s²
Final answer:
The raptor's acceleration is found using the formula a = Δv / t. By substituting the final velocity (25 m/s), initial velocity (0 m/s), and time (6.5 s), we determine the acceleration to be approximately 3.85 m/s².
Explanation:
The question asks us to determine the acceleration of a raptor that changes its velocity from rest to 25 m/s in 6.5 seconds.
To find the acceleration, we can use the formula:
a = Δv / t
Where:
a is the acceleration,Δv is the change in velocity, andt is the time.Since the raptor starts from rest, its initial velocity is 0 m/s, and its final velocity is given as 25 m/s. The time taken is 6.5 seconds. Substituting the values into the formula gives:
a = (25 m/s - 0 m/s) / 6.5 s = 25 m/s / 6.5 s = approximately 3.85 m/s²
Therefore, the raptor's acceleration is approximately 3.85 m/s².
1. What is the average velocity of a car that moved 40 km East and 80 km West in 2 hours?
The average velocity is 20 km/h west
Explanation:
The velocity of an object is given by:
[tex]velocity = \frac{d}{t}[/tex]
where
d is the displacement
t is the time elapsed
The displacement of an object is a vector connecting the initial position and the final position of motion.
In this problem, the car moved
40 km East
80 km West
Therefore, the displacement is given by (taking West as positive direction)
[tex]d=80 km - 40 km = 40 km[/tex] West
The time elapsed is
t = 2 h
Therefore, the average velocity is
[tex]v=\frac{40 km}{2h}=20 km/h[/tex] in the West direction.
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Final answer:
The average velocity of the car is -20 km/h toward the West, calculated by dividing the net displacement (-40 km) by the total time (2 hours).
Explanation:
To find the average velocity of the car, we need to consider the total displacement and the total time. Displacement is the change in position of the car, and since velocity is a vector quantity, it also includes direction. The car first moves 40 km East and then 80 km West, resulting in a total displacement of 40 km East - 80 km West = -40 km (where negative indicates the direction West).
The total time taken is 2 hours. Therefore, the average velocity v is calculated as:
v = Total Displacement / Total Time = -40 km / 2 hours = -20 km/h
The negative sign indicates that the average velocity is directed toward the West.
a 5.000 kg crate is accelerated from 5.000 m/s to 10.00m/s what is the amount of work needed to accelerate the crate to the nearest tenth of a joule
To find the work needed to accelerate the crate from 5.000 m/s to 10.00 m/s, we calculate the change in kinetic energy, which comes out to be 187.5 J when rounded to the nearest tenth.
Explanation:To determine the work done on the crate, we can use the work-energy principle which states that the work done on an object is equal to the change in its kinetic energy. The kinetic energy (KE) of an object is given by the equation KE = ½mv², where m is the mass and v is the velocity.
First, we calculate the initial kinetic energy (KEi) using the initial speed of 5.000 m/s:
KEi = ½ × 5.000 kg × (5.000 m/s)² = ½ × 5.000 × 25.00 = 62.50 J
Next, we calculate the final kinetic energy (KEf) using the final speed of 10.00 m/s:
KEf = ½ × 5.000 kg × (10.00 m/s)² = ½ × 5.000 × 100.0 = 250.0 J
The work done (W) on the crate is the change in kinetic energy, so:
W = KEf - KEi = 250.0 J - 62.50 J = 187.5 J
Therefore, the amount of work needed to accelerate the crate is 187.5 J, which can be rounded to the nearest tenth of a joule as 187.5 J.
Final answer:
The amount of work needed to accelerate the crate is 187.5 Joules (to the nearest tenth of a joule).
Explanation:
The amount of work needed to accelerate the crate can be calculated using the formula:
Work = Change in kinetic energy
First, calculate the initial kinetic energy:
Kinetic energy = (1/2) * m * v^2
= (1/2) * 5.000 kg * (5.000 m/s)^2
= 62.5 Joules
Next, calculate the final kinetic energy:
Kinetic energy = (1/2) * m * v^2
= (1/2) * 5.000 kg * (10.00 m/s)^2
= 250 Joules
Finally, calculate the change in kinetic energy:
Change in kinetic energy = Final kinetic energy - Initial kinetic energy
= 250 Joules - 62.5 Joules
= 187.5 Joules
Therefore, the amount of work needed to accelerate the crate is 187.5 Joules (to the nearest tenth of a joule).
determine the quantity of work done when a crane lifts a 100-N block from 2 m above the ground to 6 m above the ground.
A. 600 J
B. 400 J
C. 100 J
D. 200 J
I will mark the first RIGHT answer brainliest!
The work done on the block is B) 400 J
Explanation:
The work done when lifting an object is equal to the change in gravitational potential energy of the object:
[tex]W=mg \Delta h[/tex]
where
m is the mass of the object
g is the acceleration of gravity
[tex]\Delta h[/tex] is the change in height of the object
In this problem we have:
(mg) = 100 N is the weight of the block (product of mass and acceleration of gravity)
[tex]\Delta h = 6 m - 2 m = 4 m[/tex] is the change in heigth of the object
Substituting, we find the work done:
[tex]W=(100)(4)=400 J[/tex]
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Answer:
400j
Explanation:
took test and 100 times 4 equals 400
Which statement is an example of determining the relative age?
determining which individual is older based on the style of clothing they wore in a picture
knowing the age of a grandmother because she was a kid during the Great Depression
doing a genealogy search to find out a great, great, grandfather was born June 2, 1890
use birth certificate records to confirm the first birth occurred in the hospital on January 11, 1750
knowing the age of a grandmother because she was a kid during the Great Depression
Explanation:
The best example for relative age is simply knowing the age of a grandmother because she was a kid during the Great Depression. Relative age is usually based on the occurrence of a popular and world wide event. It is not an absolute age that gives numerical and quantitative values to age.
The reference here is the Great Depression The Grandmother was kid during this period in time. We can use this knowledge to infer her age. Since she was a kid at that point, her current age would how far back the depression was and an estimate of her age at that time.Learn more;
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The density of a material is calculated by:
Answer:
The density of the material is defined as the mass of the material to its volume.
ρ = M / V
Explanation:
The density of the material is a scalar quantity.
If the mass and the volume of the material is known the density of the material can be calculated using the formula,
ρ = M / V
The mass of the material can be found using a physical balance.
The volume of a geometrically symmetrical material can be found using the geometrical measurement. For a brick,
V = l x b x h
For non-geometrically shaped material the volume can be found from the displacement method using water.
1 - It is okay to use slang on a record as long as the auditor can interpret it.
True
False
2 - Never access social media accounts at work.
True
False
3 - Refrain from using profanity in the workplace.
True
False
4 - Chemical components contained in a product can be found in a(an) _______. A) chemical manual
B) procedures manual
C) Safety Data Sheet (SDS)
D) Material Data Sheet (MDS)
5 - To ensure a positive outcome it is essential for a group to be able to effectively communicate with one another within the workplace. What is this process known as?
A) Teamwork
B) Verbal communication
C) Groupthink
D) Planning
6 - _______ is a skill and behavior from a person trained to do their job well.
A) Teamwork
B) Professionalism
C) Planning
D) Communication
7 - These records are used to assist in providing a basis for quality improvement within the CS department.
A) Personnel monitors
B) CE educational records
C) Competencies
D) Training plans
8 - Employees in-services are an example of which of the following?
A) Personnel monitors
B) Continuing education records
C) Competencies
D) Training plans
9 - Which of the following organizations monitors exposure to hazardous materials?
A) EPA
B) OSHA
C) FDA
D) AAMI
10 - If a fire occurs, who should the staff rescue first?
A) Doctor
B) Tech
C) Patient
D) Nurse
If a ball is rolling at a velocity of 1.5 meters per second and has a momentum of 10.0 kg meters per second what is the mas6of the ball
The mass of the ball is 6.7 kg
Explanation:
The momentum of an object is defined as
[tex]p=mv[/tex]
where
p is the momentum
m is the mass of the object
v is its velocity
For the ball in this problem we have the following data:
v = 1.5 m/s (velocity)
p = 10.0 kg m/s (momentum)
Solving the equation for m, we find the mass of the ball:
[tex]m=\frac{p}{v}=\frac{10}{1.5}=6.7 kg[/tex]
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On Earth, you swing a simple pendulum in simple harmonic motion with a period of 1.6 seconds. What is the period of this same pendulum on the Moon? Assume the Moon’s acceleration due to gravity is 1/6 of the acceleration due to gravity on Earth.
The period of the pendulum in the Moon is 3.9 s
Explanation:
The period of a simple pendulum is given by the equation
[tex]T=2\pi \sqrt{\frac{L}{g}}[/tex] (1)
where
L is the length of the pendulum
g is the acceleration due to gravity
Here we have a pendulum whose period on Earth is
[tex]T_e = 1.6 s[/tex]
where on Earth, the acceleration due to gravity is
[tex]g_e = 9.8 m/s^2[/tex]
So eq.(1) can be written as
[tex]T_e = 2\pi \sqrt{\frac{L}{g_e}}[/tex] (2)
When the same pendulum is moved to the Moon, its length does not change, so its period on the Moon is given by
[tex]T_m = 2\pi \sqrt{\frac{L}{g_m}}[/tex] (3)
where
[tex]g_m = \frac{1}{6}g_e[/tex] is the acceleration due to gravity on the Moon (1/6 of that on the Earth)
Dividing eq.(3) by eq.(2), we get
[tex]\frac{T_m}{T_e}=\sqrt{\frac{g_e}{g_m}}=\sqrt{\frac{g_e}{\frac{1}{6}g_e}}=\sqrt{6}[/tex]
Therefore, the period of the pendulum on the moon is
[tex]T_m = \sqrt{6}T_e = \sqrt{6}(1.6)=3.9 s[/tex]
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Scientists draw conclusions based on evidence that has been gathered
through observation, experience, and experimentation. Which of the following
terms best describes this kind of evidence?
Answer:
empirical evidence
Explanation:
Empirical evidence includes measurements or data collected through observation, experience, and experimentation.
Scientist, in order to validate their investigations, record and analyze data which allows them to conclude about their hypothesis. This is a central part of the scientific method, but a theoretical background is also needed.
WILL MARK BRAINLYYY Which organ is part of the respiratory system of tigers?
skin
lungs
gills
tracheae
Answer:
lungs
Explanation:
Similar to other mammal species that live on land and breath air (oxygen), the pair of lungs is the most important part of the respiratory system, which keeps living organisms alive.
Answer:
lungs are part of the respiratory system of tigers
Help me with this Weather Station Model by answering 5 questions. It is due tomorrow.
1. What is the wind speed at this location?
A. 15 knots
B. 25 knots
C. 15 miles per hour
D. 25 miles per hour
2. What is the atmospheric pressure at this location?
A. 21 millibars
B. 82 millibars
C. 1002.1 millibars
D. 1021 millibars
3. What is the approximate relative humidity at this location?
A. 95%
B. 83%
C. 50%
D. 21%
4. Over the past few hours the air pressure has been
A. Decreasing
B. Increasing
C. Remaining constant
5. Which of the following instruments was NOT used to gather this weather data?
A. A sling psychrometer
B. An anemometer
C. A Seismometer
D. A Barometer
A 110-kg tackler moving at a speed of 3.5 m/s
meets head-on (and holds on to an 85-kg halfback
moving at a speed of 5.0 m/s.
Part A
What will be their mutual speed immediately after the collision?
Express your answer to two significant figures and include the appropriate units.
Units
Which type of stress is a uniform stress that doesn't lead to earthquakes?
A. Shear stress
B. Compression
C. Lithostatic pressure
D. Tension
Answer:
C) Lithostatic pressure
Explanation:
An earthquake is what happens when two blocks of the earth suddenly slip past one another. The surface where they slip is called the fault or fault plane.
In the Earth the pressure due to the weight of overlying rocks is a uniform stress and is referred to as confiningstress. If stress is not equal from all directions then the stress is a differential stress. Three kinds of differential stress occur. Shear stress, which result in slippage and translation.
Answer:
Lithostatic pressure
Explanation: when you search up what lithostatic means you will see.
Newton third law states that what objects and what forces on each other
"When an object A exerts a force (called action) on an object B, then object B exerts an equal and opposite force (called reaction) on object A"
Explanation:
Newton's third law of motion states that:
"When an object A exerts a force (called action) on an object B, then object B exerts an equal and opposite force (called reaction) on object A"
it is important to note that the pair of forces (action and reaction) do not act on the same object, but on different objects: therefore, they never appear in the same free-body diagram of an object.
There are several examples where Newton's third law is applied in daily life. For instance:
A book at rest on the table: the book exerts a downward force on the table, and the table exerts an upward force (normal reaction) on the bookIf you push against the wall, you exert a force (action) on the wall, and the wall exerts a force (reaction) back on you, of equal magnitudeA satellite in orbit around the Earth: the gravitational force exerted by the Earth on the satellite is equal to the gravitational force exerted by the satellite on the EarthLearn more about Newton's third law:
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How did Galileo use his knowledge in music to understanding the movement of a pendulum?
Galileo was taught Aristotelian physics at the university of Pisa. Galileo's discovery was that the period of swing of a pendulum is independent of its amplitude--the arc of the swing--the isochronism of the pendulum. Now this discovery had important implications for the measurement of time intervals.