Two cars of the same mass have different velocities. Which car has more momentum
A block of mass 2.5 kg is attached to a spring with spring constant 150 n/m and slides on a rough, horizontal surface (coefficient of kinetic friction 0.25). the spring is initially extended by a distance of 45 cm from its equilibrium position and released from rest. (a) what is the speed of the block when it is at the equilibrium position of the spring? (b) where does the block stop?
A 2.90 kg mass is pushed against a horizontal spring of force constant 23.0 n/cm on a frictionless air table. the spring is attached to the tabletop, and the mass is not attached to the spring in any way. when the spring has been compressed enough to store 15.0 j of potential energy in it, the mass is suddenly released from rest. part a find the greatest speed the mass reaches. vmax = 3.22 m/s submitmy answersgive up correct part b when does this occur? if not friction acts on it forever. if there is right at the beginning when it is just released. submitmy answersgive up
When traveling from oxygen to sulfur to selenium, through this group in the periodic table, what is changing?
A) The density of the elements decreases.
B) The number of energy levels increases.
C) The number of valence electrons of the elements decreases.
D) The state of the element changes from gas to liquid to solid.
Answer: Option (B) is the correct answer.
Explanation:
It is known that oxygen, sulfur and selenium are all group 16 elements.
The electronic configuration of oxygen is as follows.
[tex]1s^{2}2s^{2}2p^{4}[/tex]
The electronic configuration of sulfur is as follows.
[tex]1s^{2}2s^{2}2p^{6}3s^{2}3p^{4}[/tex]
The electronic configuration of selenium is as follows.
[tex]1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{10}4p^{4}[/tex]
Hence, we can see that on moving down the group there is increase in energy levels of the atoms from 2p to 4p.
Therefore, we can conclude that when traveling from oxygen to sulfur to selenium, through this group in the periodic table, change is that the number of energy levels increases.
The part of the flower responsible for producing pollen (sperm) is the _______. A. stigma B. anther C. style D. filament
__________ helps us adapt to our environment. It also generally __________ with age. A. Plasticity . . . decreases B. Development . . . increases C. Plasticity . . . increases D. Development . . . decreases
Answer: A, Plasticity ... decreases
Explanation:
Which has a higher acceleration: a 10 kg object acted upon with a net force of 20 N or an 18 kg object acted on by a net force of 30 N
Answer:
the 10-kg object has higher acceleration
Explanation:
A 7 L sample of gas has a pressure of 1.1 atm at a temperature of 285 K. If the pressure decreases to 0.6 atm, causing the volume to increase to 10 L, what is the new temperature? Round your answer to the nearest tenth.
A 7 L sample of gas has a pressure of 1.1 atm at a temperature of 285 K. If the pressure decreases to 0.6 atm, causing the volume to increase to 10 L, what is the new temperature? Round your answer to the nearest tenth.
Answer: 222.1K
Which statements accurately describe elements? Check all that apply.
Elements are made up of two or more types of atoms.
Elements are made up of only one type of atom.
Each element has a unique chemical symbol.
Elements can be identified by their atomic number.
One element cannot be combined with another element.
Answer: The correct statements are:
- Elements are made up of only one type of atom.
- Each element has a unique chemical symbol.
- Elements can be identified by their atomic number.
Explanation: and just for a little bit more information about elements.
An element is a pure substance that is made from a single type of atom. Elements are the building blocks for all the rest of the matter in the world. Examples of elements include iron, oxygen, hydrogen, gold, and helium. An important number in an element is the atomic number.
An inclined plane of angle θ has a spring of force constant k fastened securely at the bottom so that the spring is parallel to the surface. A block of mass m is placed on the plane at a distance d from the spring. From this position, the block is projected downward toward the spring with speed v as shown in the figure below. By what distance is the spring compressed when the block momentarily comes to rest? (Use any variable or symbol stated above along with the following as necessary: g, the acceleration due to gravity.)
Using the principles of energy conservation and kinetic energy, the distance the spring compresses when the block comes to rest is found through the equation x = sqrt((m*v*v)/k), where m is the mass, v is the velocity, k is the spring constant, and x is the distance of compression.
Explanation:To compute the distance the spring is compressed when the block comes to rest, we need to consider both kinetic energy conservation and energy conservation through potential energy of the spring. Our initial kinetic energy supplied by the block sliding down the plane (K1) will turn into a potential energy in the spring when it's compressed (U2). Hence, we have K1 = U2.
Assuming initial kinetic energy (K1) given by 0.5*m*v*v, and potential energy in the spring (U2) equals to 0.5*k*x*x where x is the distance in which spring is compressed.
From the conservation of energy principle, 0.5*m*v*v = 0.5*k*x*x. By simplifying the equation, we get x = sqrt((m*v*v)/k). This equation provides us the distance the spring is compressed when the block comes to rest.
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If the initial velocity of the system were not zero, how would this affect your results?
What type of motor operates at a constant steady-state speed regardless of the load?
Recall that the blocks can only move along the x axis. the x components of their velocities at a certain moment are v1x and v2x. find the x component of the velocity of the center of mass (vcm)x at that moment. keep in mind that, in general: vx=dx/dt. express your answer in terms of m1, m2, v1x, and v2x.
The x component of the center of mass velocity is calculated as the momentum-weighted average of the individual blocks' velocities, using the formula (m1*v1x + m2*v2x) / (m1 + m2).
Explanation:To find the x component of the velocity of the center of mass (vcm)x, we use the formula for the center of mass velocity in one dimension, which is given by:
(vcm)x = (m1*v1x + m2*v2x) / (m1 + m2)
This equation reveals that the center of mass velocity is the momentum-weighted average of the velocities of the individual blocks. Since momentum is mass times velocity, the product m1*v1x is the momentum of block 1 in the x direction, and m2*v2x is the momentum of block 2 in the x direction. The sum of these momenta gives the total momentum in the x direction. By dividing this sum by the total mass (m1 + m2), we obtain the velocity of the center of mass in the x direction.
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) a charge of 6.15 mc is placed at each corner of a square 0.100 m on a side. determine the magnitude and direction of the force on each charg
The magnitude and direction of the force between each pair of charges can be determined using Coulomb's Law.
Explanation:The magnitude of the force between two charges can be determined using Coulomb's Law. In this case, we have four charges placed at the corners of a square. Since the charges are the same (6.15 mc), the force between each pair of charges will have the same magnitude. Let's label the charges as q1, q2, q3, and q4. The force between q1 and q2 is given by:
F12 = (k * q1 * q2) / r^2
where k is the Coulomb's constant (8.988 × 10^9 N m^2/C^2) and r is the distance between the charges (0.100 m). The direction of the force will be repulsive, since the charges have the same sign.
Using this formula, we can calculate the magnitude and direction of the force for all pairs of charges.
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At an instant when a soccer ball is in contact with the foot of the player kicking it, the horizontal or x component of the ball's acceleration is 930 m/s2 and the vertical or y component of its acceleration is 900 m/s2. the ball's mass is 0.39 kg. what is the magnitude of the net force acting on the soccer ball at this instant?
For a temperature increase of δt1, a certain amount of an ideal gas requires 30 j when heated at constant volume and 50 j when heated at constant pressure. how much work is done by the gas in the second situation?
Work done by the ideal gas in the second situation is 20 Joule.
We know that amount of energy given to a ideal gas is distributed in it to increase its internal energy and to work done by increasing it volume.
Mathematically:
energy given to a ideal gas (dQ) = Increase in internal energy (dU) + work done (dW).
Now in this question: a certain amount of an ideal gas requires 30 j when heated at constant volume. So, this energy is used to increase internal energy (as no volume change occurs).
So, dQ₁ = dU = 30 Joule.
When heated at constant pressure, the certain amount of an ideal gas requires 50 J. So, this energy is used to increase internal energy and work done.
So, dQ₂ = dU + dW
⇒ dW = dQ₂ - dU = 50 Joule - 30 joule = 20 Joule.
Hence, work is done by an amount 20 joule by the ideal gas in the second situation.
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An automobile engine slows down from 4500 rpm to 1600 rpm in 6.0 s. (a) calculate its angular acceleration, assumed constant. 3036.87 incorrect: your answer is incorrect. rad/s2 (b) calculate the total number of revolutions the engine makes in this time. 8700 incorrect: your answer is incorrect. rev
The angular acceleration of the automobile is 50.62 rad/s².
The total number of revolutions within the given time is 290 revolutions.
Angular acceleration of automobile
The angular acceleration of the automobile is calculated as follows;
[tex]\alpha = \frac{\omega _f - \omega _i}{t} \\\\[/tex]
ωf = 1600 rpm = 167.57 rad/s
ωi = 4500 rpm = 471.3 rad/s
[tex]\alpha = \frac{167.57 - 471.3}{6} \\\\\alpha = -50.62 \ rad/s^2[/tex]
Total number of revolutions in 6 sN = (4500 rpm - 1600 rpm)
N = 2,900 rpm
N = 2,900 x (6/60)
N = 290 rev
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what part of the hammer acts as the fulcrum when the hammer is used to remove a nail
The fulcrum in a hammer when removing a nail is at the part where the hammer pivots.
By applying effort to the handle of a claw hammer, the output force at the nail puller end is increased due to the lever principle. Understanding these concepts aids in efficiently removing nails from wood.
A block sliding across a level surface has a mass of 2.5 kg and a mechanical energy of 20 joules. What is its velocity?
A 120-meter-long ski ift carries skiers from a station at the foot of a slope to a second station 40 m above. what is the IMA (ideal machincal advantage) of the lift?
A 3.7-kg block on a horizontal frictionless surface is attached to an ideal spring whose force constant (spring constant) is 450 n/m. the block is pulled from its equilibrium position at x = 0.000 m to a position x = +0.080 m and is released from rest. the block then executes simple harmonic motion along the horizontal x-axis. the maximum elastic potential energy of the system is closest to
In the simple harmonic motion of a block attached to a spring, the maximum elasticity potential energy (U) occurs when displacement from equilibrium is the greatest. Given the provided spring constant (k) and displacement (x), the energy can be calculated using the formula U = (1/2)kx². The maximum elastic potential energy in this scenario is close to 1.44 joules.
Explanation:In physics, the problem you're dealing with relates to simple harmonic motion associated with a block attached to a spring on a frictionless surface. When the object is displaced from equilibrium and let go, it performs simple harmonic motion. During this motion, there is a constant interconversion between the kinetic and potential energy within the system.
The 'spring constant' (k) of an ideal spring is given as 450 n/m and the displacement from the equilibrium position (x) is 0.080 m. The maximum elastic potential energy is at extremes of the motion, when the displacement is the greatest (+/- x). It is given by the formula: U = (1/2)kx², where U is the elastic potential energy.
Substituting the given spring constant and displacement values into the formula: U = (1/2) * 450 * (0.080)² = 1.44 joules. Hence, the maximum elastic potential energy of the system is closest to 1.44 joules.
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A particle moves at a speed such that its kinetic energy just equals its mass energy. what is the speed of the particle?
a. 3 x 108 m/s;
b. 2.6 x 108 m/s;
c. 2.82 x 108 m/s;
d. 2.3 x 108 m/s
Which scientists contributed to discovering the universal law of gravitation? Check all that apply. Tycho Brahe Albert Einstein Johannes Kepler Nicolaus Copernicus Sir Isaac Newton Robert Hooke
Sir Isaac Newton is the primary contributor to the universal law of gravitation, with his precise mathematical formula that unified terrestrial and celestial phenomena. Johannes Kepler's laws of planetary motion were foundational for Newton's work, and Albert Einstein expanded on these ideas with his theory of general relativity.
Explanation:Contributors to the Universal Law of GravitationSeveral prominent individuals contributed to the discovery and understanding of the universal law of gravitation. Sir Isaac Newton is the most well-known figure associated with the law, as he defined the gravitational force, proposing that it was a universal force that explained both why objects fall to Earth and the motions of celestial bodies. He was the first to provide a precise mathematical formula for the law of gravitation.
Before Newton, Johannes Kepler discovered three laws of planetary motion, which Newton found crucial for his own work, as they showed gravitation's effects on planetary orbits. Moreover, Albert Einstein expanded upon the concept of gravitation with his theory of general relativity which showed that there is more to the gravity story than Newton's law suggested. Although their contributions were indirect, scientists such as Galileo Galilei and Robert Hooke, also helped set the stage for Newton's discoveries through their work on planetary motions and gravitational investigations respectively.
How much energy is required to move a 1350 kg object from the earth's surface to an altitude twice the earth's radius?
Final answer:
The calculation of energy required to move an object to an altitude twice the Earth's radius involves understanding and applying principles of gravitational potential energy and the universal law of gravitation.
Explanation:
The question involves calculating the energy required to move a 1350 kg object from the Earth's surface to an altitude twice the Earth's radius. To solve this, we use the formula for gravitational potential energy (GPE), which is GPE = mgh at close distances to Earth's surface, and the universal law of gravitation for larger distances.
However, at distances far from the surface, the formula shifts to GPE = -G * (m1*m2)/r, where G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between their centers. Since the altitude is twice the Earth's radius, the effective distance r would be 3 times the Earth's radius. This question requires integration of both concepts and understanding of physics to solve comprehensively.
To recharge a 12 v battery, a battery charger must move 3.3 × 105 c of charge from the negative terminal to the positive terminal. how much work is done by the battery charger? answer in units of j
Work done is calculated by change * potential
difference
in equation it means: W = Q * V
since the 2 terminals have now dq charge and (V) potential difference
small work done (dW) = V dq
total work done W = V Q = 12 * 3.3*10^5 = 3.96 *10^6 Joules which is
approximately 4 mega joules
To calculate the work done by the battery charger, multiply the charge moved (3.3 × [tex]10^5[/tex] C) by the voltage (12 V). The result is 3.96 × [tex]10^6[/tex] J.
To find out how much work is done by the battery charger, we use the relationship between electrical potential difference (voltage), charge, and work. The work done, W, when moving a charge, Q, through a potential difference, V, is given by the equation:
W = Q × VHere, the battery charger must move 3.3 × [tex]10^5[/tex] C of charge (Q) through a potential difference of 12 V (V). Substituting these values into the equation gives:
W = 3.3 × [tex]10^5[/tex] C × 12 VW = 3.96 × [tex]10^6[/tex] JTherefore, the work done by the battery charger is 3.96 × [tex]10^6[/tex] J.
Based on their locations on the periodic table, which best compares the properties of the metalloids arsenic (As) and antimony (Sb)?
Which of the following statement is true about image formation using a plane mirror? The distance from the image to the mirror is determined by-
A.the distance from the mirror to the object.
B.the size of the object compared to the mirror.
C.the brightness of the light on the object.
D.the orientation of the object relative to the mirror.
Which equations can be used to calculate the electric potential energy stored in a capacitor? Check all that apply. U = QV U = CV U = U = CV2 U = U = QV2
U=1/2QV
U=1/2CV^2
U=Q^2/2C
A 1200-kg ore cart is rolling at 10.8 m/s across a flat friction-free surface. a crane suddenly drops of ore vertically into the cart. how fast does the cart move just after being loaded with the ore?
Which graphic design tools help you draw circles and rectangles?
Answer: geometric shape tools
Explanation: plato/edmentum answer.
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