) a charge of 6.15 mc is placed at each corner of a square 0.100 m on a side. determine the magnitude and direction of the force on each charg

Answers

Answer 1
Because charges are positioned on a square the force acting on one charge is the same as the force acting on all others. 
We will use superposition principle. This means that force acting on the charge is the sum of individual forces. I have attached the sketch that you should take a look at.
We will break down forces on their x and y components:
[tex]F_x=F_3+F_2cos(45^{\circ})[/tex]
[tex]F_y=F_1+F_2sin(45^{\circ})[/tex]
Let's figure out each component:
[tex]F_1=\frac{1}{4\pi \epsilon}\frac{q^2}{a^2}\\ F_3=\frac{1}{4\pi \epsilon}\frac{q^2}{a^2}\\[/tex]
[tex]F_2=\frac{1}{4\pi \epsilon}\frac{q^2}{(\sqrt{2}a)^2}[/tex]
Total force acting on the charge would be:
[tex]F=\sqrt{F_x^2+F_y^2}[/tex]
We need to calculate forces along x and y axis first( I will assume you meant micro coulombs, because otherwise we get forces that are huge).
[tex]F_x=F_3+F_2cos(45^{\circ})=\frac{1}{4\pi \epsilon}\frac{q^2}{a^2}+\frac{1}
{4\pi \epsilon}\frac{q^2}{(\sqrt{2}a)^2}\cdot\cos(45)=46N[/tex]
[tex]F_y=\frac{1}{4\pi \epsilon}\frac{q^2}{(\sqrt{2}a)^2}\cdot sin(45)+\frac{1}{4\pi \epsilon}\frac{q^2}{a^2}=46N[/tex]
Now we can find the total force acting on a single charge:
[tex]F=\sqrt{F_x^2+F_y^2}=\sqrt{46^2+46^2}=65N[/tex]
As said before, intensity of the force acting on charges is the same for all of them.
) A Charge Of 6.15 Mc Is Placed At Each Corner Of A Square 0.100 M On A Side. Determine The Magnitude
Answer 2
Final answer:

The magnitude and direction of the force between each pair of charges can be determined using Coulomb's Law.

Explanation:

The magnitude of the force between two charges can be determined using Coulomb's Law. In this case, we have four charges placed at the corners of a square. Since the charges are the same (6.15 mc), the force between each pair of charges will have the same magnitude. Let's label the charges as q1, q2, q3, and q4. The force between q1 and q2 is given by:

F12 = (k * q1 * q2) / r^2

where k is the Coulomb's constant (8.988 × 10^9 N m^2/C^2) and r is the distance between the charges (0.100 m). The direction of the force will be repulsive, since the charges have the same sign.

Using this formula, we can calculate the magnitude and direction of the force for all pairs of charges.

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Related Questions

A 1200-kg ore cart is rolling at 10.8 m/s across a flat friction-free surface. a crane suddenly drops of ore vertically into the cart. how fast does the cart move just after being loaded with the ore?

Answers

The value of the final speed depends on the mass of the ore.

Let's call m the mass of the ore. We can solve the exercise by requiring the conservation of momentum, which must be the same before and after the ore is loaded.

Initially, there is only the cart, so the momentum is
[tex]p=Mv=(1200 kg)(10.8 m/s)=12960 kg m/s[/tex]
After the ore is loaded, the new mass will be (1200 kg+m), and the new speed is [tex]v_f[/tex]. The momentum p is conserved, so it is still 12960 kg m/s. Therefore, we have
[tex]p=12960 kg m/s =(1200 kg+m)v_f[/tex]
and so the final speed is
[tex]v_f = \frac{12960 kg m/s}{1200 kg +m} [/tex]

what causes the end of a star?

Answers

The start likely burned all of its hydrogen fuel and expands in size

A 2.90 kg mass is pushed against a horizontal spring of force constant 23.0 n/cm on a frictionless air table. the spring is attached to the tabletop, and the mass is not attached to the spring in any way. when the spring has been compressed enough to store 15.0 j of potential energy in it, the mass is suddenly released from rest. part a find the greatest speed the mass reaches. vmax = 3.22 m/s submitmy answersgive up correct part b when does this occur? if not friction acts on it forever. if there is right at the beginning when it is just released. submitmy answersgive up

Answers

A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs. 
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if a vector a - b = 2c, a + b = 4c and c = 3i + 4j,find a and b

Answers

Ans:
a = 9i + 12j
b = 3i + 4j

Explanation:
We have two equations:

a - b = 2c --- (A)
a + b = 4c --- (B)

and two unknowns:
a = ?
b = ?

Whereas,
c = 3i + 4j

Add equations (A) and (B):
=> a - b = 2c
     a + b = 4c
----------------------
    2a = 6c

=> a = 3c --- (C)
Put the value of vector c in equation (C):

(C) => a = 3(3i + 4j)
=> a = 9i + 12j

Now that we have vector a, put that vector and vector c in equation (A):
(A)=> (9i + 12j) - b = 2(3i + 4j)

=> b = (9i + 12) - (6i + 8j)
=> b = 3i + 4j

Ans:
a = 9i + 12j
b = 3i + 4j

A 1 ev electron has a 10-4 "probability of tunneling through a" 2.0 ev "potential barrier. what is the probability of a" 1 ev "proton tunneling through the same barrier

Answers

if the object, ends up with a positive charge, then it is missing electrons. if it is missing electrons, then it must have been removed form the object during the rubbing process.

Which of these was a characteristic of the Thomson model of the atom, but not the Dalton model?

negatively charged electrons
positive charge concentrated at the center of the atom
unequal positive and negative charges
indivisible atoms

Answers

The correct option is the first one, which is: Negatively charged electrons.

 J.J Thomson was British physicist who discovered the electron in 1897, by his experiment with "cathode ray tubes". For this work and contribution to science, he was awarded the Nobel Prize for physics in 1906.

Answer:

negatively charged electrons  

Explanation:

According to Dalton's Model, matter is made up of tiny particles known as atoms. Electrons were not known at that time. Thomson gave the plum pudding model which describe atom to be over all neutral with equal distribution of negatively charged electrons in the region of positive charges.

Thus, negatively charged electrons were a characteristic of the Thomson's model of the atom but not the Dalton's model.

Monochromatic light of a given wavelength is incident on a metal surface. however, no photoelectrons are emitted. if electrons are to be ejected from the surface, how should the incident light be adjusted? monochromatic light of a given wavelength is incident on a metal surface. however, no photoelectrons are emitted. if electrons are to be ejected from the surface, how should the incident light be adjusted? light of a longer wavelength should be used. light of a shorter wavelength should be used. the intensity of the light should be decreased. the intensity of the light should be increased.

Answers

if the object, ends up with a positive charge, then it is missing electrons. if it is missing electrons, then it must have been removed form the object during the rubbing process.

To eject electrons from a metal surface, monochromatic light of a shorter wavelength should be used, as this will increase the energy of photons to overcome the metal's work function.

When monochromatic light is incident on a metal surface and no photoelectrons are emitted, it indicates that the energy of the photons is not sufficient to overcome the work function of the metal. To eject electrons from the surface, one should use monochromatic light of a shorter wavelength. According to the photoelectric effect, there is a minimum frequency (threshold frequency) required for electrons to be emitted, and since frequency and wavelength are inversely related (the shorter the wavelength, the higher the frequency), a shorter wavelength would increase the energy of the photons. It is important to note that increasing the intensity of light only increases the number of electrons ejected but does not affect their kinetic energy or the threshold frequency.

An element which has strong intermolecular forces is most likely to have
a. a boiling point below room temperature
b. a melting point below room temperature
c. a boiling point very close to its melting point
d. a very high melting point

Answers

an element like that would have have a molecular structure that has a high tolerance to heat, so the correct answer is D

According to the forces of attraction, an element which has strong inter molecular  forces is most likely to have a very high melting point.

What are forces of attraction?

Forces of attraction  is a force by which atoms in a molecule  combine. it is basically an attractive force in nature.  It can act between an ion  and an atom as well.It varies for different  states  of matter that is solids, liquids and gases.

The forces of attraction are maximum in solids as  the molecules present in solid are tightly held while it is minimum in gases  as the molecules are far apart . The forces of attraction in liquids is intermediate of solids and gases.

The physical properties such as melting point, boiling point, density  are all dependent on forces of attraction which exists in the substances.

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Burning magnesium gives us magnesium oxide. This is a example of

Answers

radioactive movement

combustion and oxygen 

A culture is a group of people that share the same __________.
A. development goals
B. professions and work
C. beliefs and behaviors
D. philosophies and religion

Answers

The correct answer is:  [C]:  "beliefs and behaviors" .
_________________________________________________
   This would include "philosophies and religion" [which is "Choice: [D]" ) ;  however, "Choice : [C]:  "beliefs and behaviors" is the correct answer; since "Choice:  [C]"  is completer and more comprehensive.
__________________________________________________

Which statements accurately describe elements? Check all that apply.
Elements are made up of two or more types of atoms.
Elements are made up of only one type of atom.
Each element has a unique chemical symbol.
Elements can be identified by their atomic number.
One element cannot be combined with another element.

Answers

The correct statements are:
- Elements are made up of only one type of atom.
- Each element has a unique chemical symbol.
- Elements can be identified by their atomic number.

In fact, elements are made up of only one tipe of atom, and each of them is identified by a different symbol. Moreover, each element has a different atomic number (number of protons), therefore elements can be identified by their atomic number.

Answer: The correct statements are:

- Elements are made up of only one type of atom.

- Each element has a unique chemical symbol.

- Elements can be identified by their atomic number.

Explanation: and just for a little bit more information about elements.

An element is a pure substance that is made from a single type of atom. Elements are the building blocks for all the rest of the matter in the world. Examples of elements include iron, oxygen, hydrogen, gold, and helium. An important number in an element is the atomic number.

What is the current when a typical static charge of 0.234~\mu\text{c}0.234 μc moves from your finger to a metal doorknob in 0.595~\mu\text{s}0.595 μs?

Answers

The current is defined as the quantity of charge Q that passes through a certain location in a time [tex]\Delta t[/tex]:
[tex]I= \frac{Q}{\Delta t} [/tex]
Using the data of the problem, we find:
[tex]I= \frac{Q}{\Delta t} = \frac{0.234 \mu C}{0.595 \mu s}=\frac{0.234\cdot 10^{-6} C}{0.595 \cdot 10^{-6} s}=0.39 A [/tex]

__________ helps us adapt to our environment. It also generally __________ with age. A. Plasticity . . . decreases B. Development . . . increases C. Plasticity . . . increases D. Development . . . decreases

Answers

Not sure this is a physics question (probably biology).
Anyway, the correct answer is A):
"Plasticity helps us to adapt to our environment. It also generally decreases with age".
Plasticity is the ability to adapt to the environment. Since this ability is linked with brain functions, and brain functions worsen with age, then plasticity decreases with age.

Answer: A, Plasticity ... decreases

Explanation:

A mass m = 12 kg is pulled along a horizontal floor, with a coefficient of kinetic friction μk = 0.06, for a distance d = 7.8 m. then the mass is continued to be pulled up a frictionless incline that makes an angle θ = 25° with the horizontal. the entire time they massless rope used to pull the block is pulled parallel to the incline at an angle of θ = 25° (thus on the incline it is parallel to the surface) and has a tension t = 20 n. 1) what is the work done by tension before the block gets to the incline

Answers

The rope is doing work against friction. The equation for work done by a force is:

W = F×d

W is the work done.

F is the force.

d is the distance covered by the object subjected to the force.


The force of friction is calculated using the following equation:

F = μN

F is the frictional force.

μ is the coefficient of friction between the object and the contact surface.

N is the normal force exerted on the object by the contact surface.


In this situation the normal force is equal to the force of gravity on the object. The normal force is then:

N = mg

m is the mass of the object and g is the acceleration due to gravity of the Earth (9.81m/s²).


Combine all of these equations to get the total work done:

W = μ×m×g×d

Given values:

μ = 0.06

m = 12kg

g = 9.81m/s²

d = 7.8m

Substitute the terms in the equation with the given values and solve for W:

W = 0.06×12×9.81×7.8

W = 55.1J

Final answer:

The work done by tension on a 12 kg block being pulled along a horizontal floor with a coefficient of kinetic friction of 0.06 for a distance of 7.8 m is 156 joules.

Explanation:

To calculate the work done by tension before the block reaches the incline, we must consider the effects of kinetic friction. Since the rope is parallel to the incline and the force is constant, we can use the formula Work (W) = Force (F) * distance (d) * cos(\theta), where \(\theta\) is the angle between the force and displacement. In this case, the force is the tension in the rope and is parallel to the displacement, so \(\theta = 0 degrees\) and \(\cos(0) = 1\). The work done by tension can be calculated as:

\[W = T \times d \times \cos(0 degrees)\]

\[W = 20 N \times 7.8 m \times 1\]

\[W = 156 J\]

Therefore, the work done by tension on the block before it gets to the incline is 156 joules.

An ebonite (very hard, black rubber) rod is rubbed with the four different substances below. Choose the one that is MOST likely to produce the largest static charge by friction.

Answers

electrons form the atoms f one material may move to the atoms of the other material. The movement of electrons from one atom to another changes the charge of the atoms. When an atom loses electrons, it is left with more protons than electrons, so it then has a positive charge. when an atom gains electrons, it has more electrons than protons so its charge is negative.

A 3.00 kg mud ball has a perfectly inelastic collision with a second mud ball that is initially at rest. the composite system moves with a speed equal to one- third the original speed of the 3.00 kg mud ball. what is the mass of the second mud ball?

Answers

Perfectly inelastic collision is type of collision during which two objects collide, stay connected and momentum is conserved. Formula used for conservation of momentum is:

[tex] m_{1} * v_{1} + m_{2} * v_{2} = m_{1} * v'_{1} + m_{2} * v'_{2}[/tex]

In case of perfectly inelastic collision v'1 and v'2 are same.

We have following information:
m₁=3 kg
m₂=? kg
v₁=x m/s
v₂=0 m/s
v'1 = v'2 = 1/3 * v₁

Now we insert given information and solve for m₂:
3*v₁ + 0*? = 3*1/3*v₁ + m₂*1/3*v₁
3v₁ = v₁ + m₂*1/3*v₁
2v₁ = m₂*1/3*v₁
2 = m₂*1/3
m₂= 6kg

Mass of second mud ball is 6kg.

A soccer ball is kicked with an initial horizontal velocity of 17 m/s and an initial vertical velocity of 20 m/s. 1) what is the initial speed of the ball?

Answers

Final answer:

The initial speed of the soccer ball can be calculated using the Pythagorean theorem and is found to be approximately 26.24 meters per second.

Explanation:

The initial speed of a soccer ball that is kicked with an initial horizontal velocity of 17 m/s and an initial vertical velocity of 20 m/s can be calculated using the Pythagorean theorem. The theorem states that the square of the hypotenuse (the initial speed, in this case) is equal to the sum of the squares of the other two sides (the horizontal and vertical velocities).

To find the initial speed, we use the following equation: [tex]initial speed = \sqrt{(horizontal velocity)^2 } +\sqrt{(vertical velocity)^2[/tex]. Substituting the values, we get initial speed = [tex]\sqrt{(17 m/s)^2} + \sqrt{(20 m/s)^2}[/tex]

≈[tex]\sqrt{289 + 400} m^2/s^2[/tex] ≈ 26.24 m/s. Therefore, the initial speed of the ball is approximately 26.24 meters per second.

The air inside the building is easily pressed out the windows because the air is composed of widely spaced molecules in the _____ phase.

solid
liquid
gas
plasma

Answers

Hello!

The air inside the building is easily pressed out the windows because the air is composed of widely spaced molecules in the gas phase. 

The word "gas" was created by the Netherlandish scientist Jean Baptista van Helmont from the Latin word "chaos". The gas phase consists of molecules with high kinetic energy, that adopt the shape of the container and tend to expand.  The molecules are essentially free, and the gravitational pull on them is negligible. 

Have a nice day!

The rock in the picture is pushed over the edge and it begins to falls. Which type of energy conversion is taking place?

Answers

gravitational potential to kinetic energy conversion.

Answer: Potential energy into kinetic energy.

Explanation: When the rock is in the edge, it is not actually moving, so it only has potential energy U = m*g*h (where m is the mass of the rock, g is the gravity's acceleration and h is the height at which the rock is, in this case, the height of the edge with respect to the ground).

Now, when the rock starts to fall, now the rock has velocity, so it has kinetic energy, which is written as K = (m/2)*v^2 where v is the velocity.

You can see that as the rock starts to fall, the height decreases, and also the potential energy. This is because the potential energy is being converted into kinetic energy, and this is why the velocity of the rock is increasing.

The gauge pressure for the air in a balloon equals 1.01 x 10^5 Pa. If atmospheric pressure is equal to 1.01 x 10^5 Pa, what is the absolute pressure of the air inside the balloon?

a.

0 Pa

b.

5.05 x 10^4 Pa


c.

1.01 x 10^5 Pa

d.

2.02 x 10^5 Pa

Answers

Absolute Pressure = Atmospheric Pressure + Gage Pressure

Absolute Pressure = 1.01 x 10^5 Pa + 1.01 x 10^5 Pa = D. 2.02 x 10^5 Pa
Answer:

D.        2.02 x [tex]10^{5}[/tex] Pa

Explanation:

The gauge pressure is the pressure measured relative to the atmospheric pressure.

Absolute pressure (or total pressure), is the sum of the gauge pressure and the atmospheric pressure. i.e

[tex]P_{ABS}[/tex] = [tex]P_{G}[/tex] + [tex]P_{ATM}[/tex]

Where;

[tex]P_{ABS}[/tex] = absolute pressure

[tex]P_{G}[/tex] = gauge pressure = 1.01 x [tex]10^{5}[/tex]Pa  (from the question)

[tex]P_{ATM}[/tex] =  atmospheric pressure = 1.01 x [tex]10^{5}[/tex]Pa

Substitute these values into the equation above;

[tex]P_{ABS}[/tex] = [tex]P_{G}[/tex] + [tex]P_{ATM}[/tex]

[tex]P_{ABS}[/tex] = 1.01 x [tex]10^{5}[/tex] + 1.01 x [tex]10^{5}[/tex]

[tex]P_{ABS}[/tex] = 2.02 x [tex]10^{5}[/tex] Pa

Therefore, the absolute pressure of the air inside the balloon is 2.02 x [tex]10^{5}[/tex] Pa

If an object is released in the shaft at the earth's surface, what speed will it have when it reaches the center of the earth?

Answers

The speed of an object when it reaches the center of the Earth depends on the conversion of gravitational potential energy into kinetic energy, and while exact calculation of this speed requires complex calculations considering Earth's non-uniform structure, it would be less than the Earth's escape velocity of approximately 11 km/s.

Speed of an Object Reaching the Center of the Earth

When an object is released in a shaft at the Earth's surface, to determine the speed it would have when it reaches the center, we must look at gravitational acceleration and potential energy. The acceleration due to gravity near the Earth's surface is 9.8 m/s². However, as the object falls towards the center, the gravitational force decreases because it is proportional to the distance from the center. By the time it reaches the center, the gravitational force is zero and the object would be in freefall.

Nevertheless, when an object initially falls from the surface it accelerates, gaining velocity until the gravitational force lessens. If the Earth were a uniform sphere, the problem could be simplified using the concept of simple harmonic motion where maximum speed would be reached at the center. For a non-uniform Earth, complex calculations involving Earth's density variation would be needed. Ignoring air resistance and Earth's rotation, an important value related to this concept is the escape velocity, which is about 11 km/s for Earth. This escape velocity gives us a frame of reference for the maximum potential speed that can be achieved by an object falling towards the center due to the conversation of potential energy into kinetic energy. In practical terms however, air resistance and the rotational speed of the Earth would affect the actual speed, making the calculation far more complex.

If we were to hypothesize, the object would convert gravitational potential energy into kinetic energy. Without precise calculations and factoring in Earth's interior structure, giving an exact velocity upon reaching the center is not straightforward. It is generally understood, however, that the speed would be significant, although less than the object's escape velocity.

Ignoring complicating factors, the speed of an object falling to the center of the Earth can be conceptualized like the parabolic velocity of 6.94 miles per second, adjusted for the varying gravitational pull as the object approaches the center. A detailed calculation would involve conservation of energy and Newton's law of gravitation.

To calculate the speed of an object as it reaches the center of the Earth after being released from the Earth's surface, we must consider the forces acting on the object. The acceleration due to gravity (9.8 m/s²) would act on the object as it falls. However, as the object moves closer to the center, the gravitational force acting on it decreases because the mass of the Earth underneath the object decreases. This means that the object will accelerate until it reaches the point where the gravitational forces from all parts of the Earth are equal.

Using the principle of conservation of energy, where potential energy is converted into kinetic energy, and assuming a uniform density of the Earth, one could calculate this speed; however, the exact calculation would require advanced knowledge of differential equations and concepts from Newton's law of gravitation.

It is crucial to note that this is a simplification, as several factors like the Earth's rotation, the changing density of Earth's layers, and air resistance are not considered here. If we ignore these factors and assume constant acceleration, an object starting from rest will be at its maximum velocity when it reaches the center. This velocity can be conceptualized similarly to the parabolic velocity of 6.94 miles per second, which represents the speed of an object affected only by Earth's gravitational pull from space without atmospheric resistance.

If vx = 7.90 units and vy = -6.50 units, determine (a)the magnitude and (b)direction of v

Answers

a) To find the magnitude of the resultant, we can apply Pythagorean theorem, because vx and vy are the two sides of a rectangle triangle, of which the resultant v is the hypothenuse:
[tex]v= \sqrt{v_x^2+v_y^2}= \sqrt{(7.90)^2+(6.50)^2}=10.2 units [/tex]

b) To find the direction (the angle with respect to the horizontal), let's keep in mind that the tangent of the angle is equal to the ratio between the opposite side and the adiacent side:
[tex]\tan \alpha = \frac{v_y}{v_x}= \frac{-6.50}{7.90}=-0.82 [/tex]
From which we find
[tex]\alpha = arctan (-0.82)=-39.4 ^{\circ}[/tex]

A block of mass 2.5 kg is attached to a spring with spring constant 150 n/m and slides on a rough, horizontal surface (coefficient of kinetic friction 0.25). the spring is initially extended by a distance of 45 cm from its equilibrium position and released from rest. (a) what is the speed of the block when it is at the equilibrium position of the spring? (b) where does the block stop?

Answers

A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs. 
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Select all 3 of the reactants (things needed) necessary for photosynthesis to occur. A. oxygen B. carbon dioxide C. sunlight D. water E. sugar (glucose)

Answers

The answers would be B. carbon dioxide, C. sunlight, and D. water!
Hope this helps!

The part of the flower responsible for producing pollen (sperm) is the _______. A. stigma B. anther C. style D. filament

Answers

the answer to ur question is B

To recharge a 12 v battery, a battery charger must move 3.3 × 105 c of charge from the negative terminal to the positive terminal. how much work is done by the battery charger? answer in units of j

Answers

Work done is calculated by change * potential difference 
in equation it means: W = Q * V 

since the 2 terminals have now dq charge and (V) potential difference 

small work done (dW) = V dq 
total work done W = V Q = 12 * 3.3*10^5 = 3.96 *10^6 Joules which is approximately 4 mega joules 

To calculate the work done by the battery charger, multiply the charge moved (3.3 × [tex]10^5[/tex] C) by the voltage (12 V). The result is 3.96 × [tex]10^6[/tex] J.

To find out how much work is done by the battery charger, we use the relationship between electrical potential difference (voltage), charge, and work. The work done, W, when moving a charge, Q, through a potential difference, V, is given by the equation:

W = Q × V

Here, the battery charger must move 3.3 × [tex]10^5[/tex] C of charge (Q) through a potential difference of 12 V (V). Substituting these values into the equation gives:

W = 3.3 × [tex]10^5[/tex] C × 12 VW = 3.96 × [tex]10^6[/tex] J

Therefore, the work done by the battery charger is 3.96 × [tex]10^6[/tex] J.

FILL IN TUE BLANK WITH ANSWER DOWN BELOW!!! When storm clouds produce lightning and thunder, 1)_________ energy changes to2)______ energy and 3)_______ energy

1) electric potential, gravitational potential, or sound?
2) Chemical, electric potential, or radiant?
3) Chemical, electric potential, or sound?

Answers

Electric potential, Chemical , sound

Answer:

1) electric potential, Radiant Energy(Lightening) , or sound Energy(Thundering)

Explanation:

During lightening we know that clouds are at high electric potential and earth surface is taken at low potential.

Due to this potential difference the charge particles in the atmosphere has tendency to move from high potential to low potential.

Also the moisture present and few dipole gases present in the atmosphere will have tendency to show breakdown and due to this breakdown and motion of charge the phenomenon of lightening occurs.

So here the electric potential energy of charge particles will change and it will convert into sound energy as it produce sound as well as in Radiant energy in form of lightening occurs in the sky.

Which image editing technique allows you to reverse an image (horizontally or vertically)?

cropping

rotating

resizing

flipping

Answers

Answer:

Flipping

Explanation:

The flip tool reverses an image on the horizontal or vertical axis.

The image editing technique that allows you to reverse an image (horizontally or vertically) is known as flipping. Thus, the correct option for this question is D.

What do you mean by image editing technique?

Image editing technique may be defined as a type of technique that modifies or improves digital or traditional photographic images using different techniques, tools or software. Images produced by scanners, digital cameras, or other image-capturing devices may be good, but not perfect.

It encompasses the processes of altering images, whether they are digital photographs, traditional photo-chemical photographs, or illustrations. Some basic image editing process is as follows:

Crop your images and clean them up.Adjust the white balance.Adjust exposure and contrast.Adjust color vibrancy and saturation.Sharpen images.Finalize and share.

Therefore, the image editing technique that allows you to reverse an image (horizontally or vertically) is known as flipping. Thus, the correct option for this question is D.

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A 2.90-kg ball, moving to the right at a velocity of 4.69 m/s on a frictionless table, collides head-on with a stationary 8.80-kg ball. find the final velocities of (a) the 2.90-kg ball and of (b) the 8.80-kg ball if the collision is elastic. (c) find the magnitude and direction of the final velocity of the two balls if the collision is completely inelastic.

Answers

Final answer:

The problem requires applying the conservation of momentum and kinetic energy to find final velocities for elastic collisions, and only momentum conservation for inelastic collisions.

Explanation:

The question involves a 2.90-kg ball colliding with an 8.80-kg stationary ball. For elastic collisions, we use conservation of momentum and conservation of kinetic energy. For inelastic collisions, we only use the conservation of momentum.

(a) For the 2.90-kg ball, we first apply the law of conservation of momentum:


 m1×v1_initial + m2×v2_initial = m1×v1_final + m2×v2_final,

where m1 = 2.90 kg, v1_initial = 4.69 m/s, m2 = 8.80 kg, and v2_initial = 0 m/s.

(b) The final velocity of 8.80-kg ball is also determined by applying conservation of momentum and energy for an elastic collision.

c) If the collision is completely inelastic, the balls stick together and move with the same final velocity. This is found using:


 (m1 + m2) × v_final = m1×v1_initial + m2×v2_initial,

We can solve these equations to find the final velocities of both balls for both scenarios.

A solid object heated to 120°C is placed inside a container of water at 33°C. What is the BEST explanation of the resulting change in temperature?
A) The temperature of both the water and solid will decrease.
B) The temperature of the solid will decrease and the water will decrease.
C) The temperature of the water will increase; the temperature of the solid will decrease.
D) The temperature of the water will remain constant; the temperature of the solid will decrease.

Answers

The correct answer is C) The temperature of the water will increase; the temperature of the solid will decrease.

In fact, the solid is at higher temperature, so when it is put inside the water it starts to release heat to the water. As a result, the temperature of the solid decreases, and since the heat is absorbed by the water, the temperature of the water increases. This process continues until the water and the solid reach thermal equilibrium (i.e. until they reach same temperature).

Answer:

its c

Explanation:

i took it

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