A cheetah can run at a maximum speed 97.8 km/h and a gazelle can run at a maximum speed of 78.2 km/h. If both animals are running at full speed, with the gazelle 96.8 m ahead, how long before the cheetah catches its prey? Answer in units of s.


The cheetah can maintain its maximum speed for only 7.5 s. What is the minimum distance the gazelle must be ahead of the cheetah to have a chance of escape? (After 7.5 s the speed of cheetah is less than that of the gazelle.) Answer in units of m.

Explanation :

(a) The distance between two consecutive crests or troughs is called wavelength of a wave. It is denoted by [tex]\lambda[/tex]

The number of vibrations produced per second is called its frequency. It is denoted by [tex]\nu[/tex].

We know that the distance covered per unit time is called the speed of the wave i.e.

[tex]s=\dfrac{d}{t}[/tex]

The distance covered by the wave is [tex]\lambda[/tex]. So,

[tex]s=\dfrac{\lambda}{T}[/tex]

We know that T is the time period of the wave and the relation between the frequency and the time period is [tex]\nu=\dfrac{1}{T}[/tex]

So, [tex]speed=wavelength\times frequency[/tex]

So, the correct option is (b).

(b) Human ear consists of the outer ear, middle ear, and inner ear.

Middle ear amplifies the vibrations from the sound waves. It consists of three bones namely hammer, anvil and stirrup. The amplification of sound waves takes place many times by these bones.

So, the correct option is (c).

Answer: Earth

Explanation:

odour = gas suggesting molecular rearrangement ... chem change

A change in odor can indicate a chemical change has occurred. Examples include the oxidation of iron in myoglobin when cooking red meat and a banana turning brown.

A change in odor can indicate a chemical change has occurred. Examples of reactions that result in a change in odor include the oxidation of iron in myoglobin when cooking red meat, which causes a red-to-brown color change and change in smell. Another example is a banana turning brown, where new, darker substances form and the odor changes. These changes in odor are indicators that chemical reactions have taken place.

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i believe it would be the same because time doesn't matter when calculating total work done.

Work=FxD

F=force

D=distance

Final answer:

The scenario that requires more work is when the force applied is greater.

Explanation:

Work is defined as the product of force and displacement.

The work done on an object is given by the formula: work = force × distance × cosine(θ), where θ is the angle between the force and displacement vectors.

In this case, both objects are lifted through the same distance. Therefore, the work done on each object is equal to the force applied to lift the object multiplied by the distance lifted.

The time taken to lift the object does not affect the work done.

So, the scenario that requires more work is when the force applied is greater.

If force is applied at 30 degree with the horizontal

then first we will find the components of force in two directions

[tex]F_x = 20 cos20[/tex]

[tex]F_y = 20 sin30[/tex]

now we can find normal force by balancing the forces in Y direction

[tex]F_n + Fy = mg[/tex]

[tex]F_n + 20 sin30 = 3*10[/tex]

[tex]F_n + 10 = 30[/tex]

[tex]F_n = 20 N[/tex]

now since block is moving with constant speed

so here forces along horizontal plane will be balanced also

[tex]F_x = F_f[/tex]

[tex]F_f = 20 cos30[/tex]

[tex]F_f = 17.3 N[/tex]

Now the weight of the box is defined as

[tex]W = mg[/tex]

now plug in all values

[tex]W = 3*10 = 30 N[/tex]

It has to be D because the arrow will drop as it moves, if it were a gun, you'd lead the target so fire below it, but due to it being an arrow, you aim high not low. Also, they didnt specify how fast anything is, so you'd probably miss if you actually did it.

Answer:

C. directly at the initial position of the object

Explanation:

As we know that archer wants to hit the target at a given position but at the same time when archer shot the arrow the the target is also dropped under gravity

So here the arrow will move simultaneously in two directions

a) horizontal motion with uniform speed

b) motion under gravity

so here the arrow will move under gravity and drops the same distance in same time as that the target will drop due to gravity

so here the motion of arrow will hit the target if the archer initial shot at the initial position of the target

Answer: Atmosphere and geosphere.

Geo-sphere is the solid part of the earth. Hydrosphere is the water part. The living things on the earth make up the biosphere. The gases, water vapors etc make up the atmosphere. When a volcanic eruption adds carbon dioxide to the air, the carbon-dioxide is being added from geosphere to the atmosphere. Hence, there is interaction between atmosphere and geosphere.

Your answer is B. 1.53 m/s towards the beach.

110/72 = 1.52777 and then you round it to 1.53  :)

A great, helpful, useful definition of acceleration is

A = (change in speed) / (time for the change) .   <== you should memorize this

This simple tool will directly solve all 3 problems.

The REASON for assigning these problems for homework is NOT to find the answers.  It's to help YOU find out whether you know this definition, to let you go back and review it if you don't, and to give you a chance to practice using it if you do.  Noticed that if you get the answers from somebody else, you lose all of these benefits.

The only wrinkle anywhere here is in #3, because when you use this definition,      the unit of time has to be the same in both the numerator and the denominator.  

So for #3, you have to EITHER  change the km/hr to km/sec, OR change the 4sec to a fraction of an hour, before you plug anything into the definition.

D. Uranium

Hope this helps :)

Answer:

It is Uranium.

Option (D)

Explanation:

Uranium is a radioactive substance.

When uranium is bombarded with neutrons it emits very large amount of energy along with some stable substances. The energy emitted s called nuclear energy.

The reaction is given by

Find the velocity of the object after one second.  

v = vo + at  

v = (0 m/s) + (9.8 m/s^2)(1 s)  

v = 9.8 m/s  

Now, using that, you can find the displacement in that one second between 1 and 2.  

d = vot + (1/2)at^2  

d = (9.8 m/s)(1 s) + (1/2)(9.8 m/s^2)(1 s)^2  

d = 14.7 m  

Answer: In 1.0 s , Displacement = 4.9 m

               In 2.0 s, Displacement = 19.6 m

Explanation: Using formula for equation of motion

[tex]h=u\times t + \frac{1}{2}\times g\times t^{^{2}}[/tex]

Initially , u= 0 m/s , t= 1.0 s and g=9.8 [tex]\frac{m}{s^{2}}[/tex]

Therefore [tex]h_1= 0 + \frac{1}{2}\times 9.8\times 1^{2} m = 4.9 m[/tex]

In Case t=2.0 s

[tex]h_2= 0 + \frac{1}{2}\times 9.8\times 2^{2} m = 19.6 m[/tex]

The answer choice that is a part of the interphase is A. S phase.

Interphase is the stage of the cell cycle that prepares the cell for division and is divided into three phases: G1, S, and G2.

During the S phase (synthesis phase), DNA replication occurs, meaning the cell's genetic material is duplicated in preparation for cell division.

Hence, it can be noted that the other answer choices are not a part of interphase as the S phase is the synthesis phase that helps prepare the cell for division

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Final answer:

The part of interphase related to chromosome duplication is the S phase. Interphase, which includes the S phase, is separate from mitotic stages like anaphase and telophase and the cell division process of cytokinesis.

Explanation:

The part of interphase that involves the replication of DNA is known as the S phase. Therefore, the answer is A. S phase. Interphase consists of three main stages in the cell cycle: the G1 phase, S phase (synthesis phase), and G2 phase. During the S phase, the chromosomes are duplicated, ensuring that each new cell will have a complete set of chromosomes after cell division.

Interphase is distinct from the stages of mitosis, which include prophase, metaphase, anaphase, and telophase. Finally, cytokinesis is the process where the cytoplasm divides, forming two separate cells.

In contrast to interphase, anaphase is a stage of mitosis where sister chromatids are separated and pulled to opposite poles of the cell. Telophase is the stage when the chromosomes begin to decondense, and new nuclear envelopes start to form around the daughter nuclei. Cytokinesis, while often occurring concurrently with telophase, is considered a separate process from mitosis and is not part of interphase.

The answer is velocity

Answer: Speed.

Explanation :

It is given that if an object is said to be moving at 10 m/s due north. In this case, the velocity of an object is given. It has both magnitude and direction as well.

Velocity is a vector quantity. 10 m/s is the magnitude of velocity and it is moving towards the north direction.

We know that the sped of an object is the total distance covered divided by the total time is taken. It is a scalar quantity.

So, 10 m/s shows the speed of an object.

An area where the particles in a medium are spaced close together is called compression.

Answer : Compression

Explanation :

An area where the particles in a medium are spaced close together is called a compression. In this region the particles are very close to each other.

In the attached figure, the rarefaction and compression is shown very clearly. In rarefaction, the particles of medium are very far apart form each other.

The distance between two consecutive compression and rarefaction is called the wavelength of wave.

So, the compression is the area where the particles are close to each other.

The person is exerting an equal force of 150 N against the crate, as per Newton's Third Law of Motion, meaning the force exerted by the person is equal to the normal force of 150 N.

To determine how much force a person is currently exerting to lift a crate with a mass of 30 kg, given the normal force supplied by the floor is 150 N, we need to consider the equal and opposite force applied by the person. According to Newton's Third Law of Motion, if the normal force acting upward from the floor is 150 N, then the person must be exerting an equal amount of force in the opposite direction, which would also be 150 N in order to maintain static equilibrium (assuming no other vertical forces are acting on the system, such as acceleration or additional weights).

Answer:

It must be moving at a constant speed

Explanation:

When an object move in a circular path, its motion is called uniform circular motion. The object moves with constant speed but the direction always changes. We know that the rate of change of velocity is called acceleration of the object.

In circular motion, the centripetal acceleration act towards the center of circle. The force acting on the object is called centripetal force. It is given by :

[tex]F_c=\dfrac{mv^2}{r}[/tex]

Hence, the statement that is true about an object to be in uniform circular motion is (C) " It must be moving at a constant speed".

The following must be true about an object for it to be in uniform circular motion C. It must be moving at a constant speed.

In uniform circular motion, an object travels in a circular path at a constant speed, but its velocity is not constant because the direction of the velocity is constantly changing.

The centripetal acceleration is directed toward the center of the circle and is responsible for keeping the object in its circular path, but the object's speed remains unchanged.

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my hypothesis is that If you drop a piece of buttered toast, it will land butter side down.

I tested it by dropping 10 pieces of buttered toast off the table and noted on which side it landed

It could be falsified cause I just made all of this up. In essence, it's like flipping a coin, 50/50 chance so I could say that 5 landed butter up and 5 landed butter down.

A scientific hypothesis, such as 'Plant growth is positively affected by the presence of light', must be testable and falsifiable. It is tested and potentially falsified through controlled experiments, where one group is exposed to the variable under question while the other is not. Science advances by testing and potentially disproving such hypotheses, never claiming absolute proof.

Example of a Scientific Hypothesis and Testing

A scientific hypothesis is a proposed explanation for a phenomenon that is testable and falsifiable. An example of a hypothesis could be: 'Plant growth is positively affected by the presence of light'. To test this hypothesis, you could conduct an experiment with two groups of plants: one group, the experimental group, would be exposed to light, while the control group would not. Plant growth can be measured over a period to determine the effect of light. The hypothesis would be falsified if the plants in darkness grew as well or better than the plants exposed to light.

Falsifiability

Falsifiability is a core principle in science, ensuring that hypotheses can be disproven. A non-falsifiable hypothesis, such as 'Red is a better color than blue', cannot be tested or disproven, and thus is not scientific. Falsifiable hypotheses contribute to the scientific method by ensuring that they can be subject to empirical testing. If ongoing tests and experiments consistently fail to disprove a hypothesis, it gains support as a valid explanation until potentially falsified by future research.

Gravitation, gravity won't work, it has to be gravitation

the answer is gravitation  :D

D. Weathering

The six steps of the rock cycle includes Weathering and Erosion, Transportation, Deposition, Compaction and Cementation. Metamorphism, Rock Melting.

Deposition is the process where rock particles sink at the rivers and become sediment.

Weathering is the process by which wind and water breaks down igneous, sedimentary, and metamorphic rocks. The process refers to large rocks broken down into smaller pieces and the broken off particles stay in the area.  

Autrotrophs obtain their energy from the sun

Biology

All living things have. Organs

Answer:

Q1: A heterotroph can obtain its energy by consuming another autotroph or a heterotroph.

Q2: Biology.

Q3: All living things are made up of one or more cells.

Q4: They are all organisms.

Q5: The population will most likely die out since most of the eggs are usually eaten and destroyed.

Q6: Appropriate environment.

Q7: They are both ways organisms maintain homeostasis.

Q8: Homeostasis.

Q9: Species

Q10: Dichotomous key.

Q11: Carolus Linnaeus

False, that would be kinetic energy.

C. Magnetism

Very few minerals are magnetic, while streak hardness and specific gravity can be used to identify lots of minerals

The mower will go approximately 1.163 meters before stopping.

To determine the distance the mower will go before stopping, we need to calculate the deceleration first. We can use Newton's second law of motion: F = ma. The net external force (F) is the force exerted by the person minus the frictional force, which is 51 N - 24 N = 27 N. The mass of the mower (m) is 22 kg. Rearranging the formula, we get: a = F/m = 27 N / 22 kg = 1.227 m/s².

Then, using the equation v² = u² + 2as, where v is the final velocity (0 m/s when the mower stops), u is the initial velocity (1.5 m/s), a is the deceleration (-1.227 m/s²), and s is the distance we're trying to find. Rearranging the equation, we get: s = (v² - u²) / (2a) = (0 - (1.5)²) / (2 * (-1.227)) = 1.163 m.

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The lawn mower will travel approximately 0.955 meters before stopping.

To find out how far the lawn mower will travel before stopping, we need to use the principles of physics, specifically the concepts of friction and linear motion. Here’s the step-by-step method:

Therefore, the lawn mower will travel approximately 0.955 meters before coming to a stop.

Answer:

[tex]25L[/tex]

Explanation:

The problem can be solved using Boyle's law for the volume and pressure of a gas at constant temperature:

[tex]P_{1}V_{1}=P_{2}V_{2}[/tex]

Where the quantities with sub-index 1 are the initial conditions for the gas and the quantities with sub-index 2 are for the final conditions of the gas.

We want to know the initial volume, this is:

[tex]V_{1}=\frac{P_{2}V_{2}}{P_{1}}[/tex]

we also know from the problem that

[tex]P_{1}=4atm\\P_{2}=0.2atm\\V_{2}=500L[/tex]

Thus, the initial volume V1 is:

[tex]V_{1}=\frac{0.2atm*500L}{4atm}[/tex]

[tex]V_{1}=25L[/tex]

A continued schedule of reinforcement (CRF) happens when reinforcement  is delivered after each and ever single targeted behavior

While a intermittented schedule of reinforcement (INT) is when reinforcement is delivered after only a few behaviors or responses not after each and every single one

Continuous reinforcement and intermittent reinforcement differ as follows:

In continuous reinforcement, each and every emission of the target behavior always receives reinforcement.

That is, each time the desired or studied behavior is carried out, it will result in the arrival of the reinforcer.

In the case of intermittent or partial reinforcement, only some of the times that the behavior is carried out is a reinforcer received, so that not every time we do the behavior we will get a reward.

Therefore, we can conclude that in intermittent reinforcement the behavior of the person is only reinforced on certain occasions and in continuous reinforcement the person is constantly rewarded for an action or behavior.

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The box slows steadily until it stops.

Let us understand why this should be the case.

We know that the Tension Force in the rope is greater than Friction and hence is responsible for accelerating the box.

As soon as the rope breaks, the Tension Force becomes 0 and the box is left with only the Friction acting on it.

Since the friction takes over immediately, the box begins to slow down at a steady pace until it stops completely.

Following the breaking of the rope, the box continues with the speed it had at that moment. The box then slows down due to the unopposed force of friction and eventually halts.

In the given scenario, a box is pulled to the right over a rough surface with a force t that is greater than the friction force f.k. This indicates that the box is accelerating to the right. When the rope breaks, the force t acting on the box suddenly becomes zero. However, the force of friction f.k still acts on it. This force f.k, previously balanced by t, now unopposed, slows the box down by acting opposite to its direction of motion. Therefore, the box continues with the velocity it had when the rope broke, slows down steadily due to friction until it eventually stops.

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Scientific hypotheses cannot be proven to be true but can be strongly supported by evidence.

Hypotheses in science cannot be proven to be true with absolute certainty because scientific knowledge is always subject to revision and refinement based on new evidence. However, we can provide strong evidence supporting a hypothesis through experimentation and observation. Scientific theories are formed when a hypothesis has been extensively tested and supported by a large body of evidence. Such theories serve as the most accurate explanations for natural phenomena and are considered to be highly reliable.

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Since the Van de Graaff generator is given to behave like a point charge, we can use the equation for Electric Field, given as

[tex]E = \frac{kQ}{r^{2} }[/tex]

where, [tex]k = \frac{1}{4\pi ε₀}[/tex] = [tex]8.99 X 10^{9} \frac{Nm^{2} }{C^{2} }[/tex]

r is the distance between the generator and the test charge = 0.75 m

E is the magnitude of the Electric Field Strength = [tex]4.5 X 10^{5} N/C[/tex]

Rearranging the equation, making Q the subject of the formula, we have

[tex]Q = \frac{E.r^{2} }{k}[/tex]

Plugging in the numerical values and simplifying them gets us

[tex]Q = 0.2815 X 10^{-4} \\[/tex]

Thus, the charge on the Van de Graaff generator is 28.16 μC.

Answer:

Answer is 2.8 × 10-7 coulombs.