A circle has a radius of 26.85 inches what is the circumference of this circle

Cedric has 9/20 of a dollar.

To find the fraction of a dollar that Cedric has, we need to convert $0.45 into a fraction with a denominator of 100, which represents cents. Since 1 dollar is equal to 100 cents, we can write $0.45 as 45 cents. So, Cedric has 45/100 of a dollar, which can be simplified to 9/20.

Answer:

Scenario II i.e. when the price of ticket is $[tex]$245[/tex]  will generate the greatest profit for the airline

Step-by-step explanation:

Scenario I

[tex]5000[/tex] tickets are sold at $ [tex]250[/tex] per ticket

The total money earned by the flight agency is

Number of tickets x price of each tickets

[tex]= 5000 * 250\\[/tex]

[tex]= 1250000[/tex] dollars

Scenario II

The price of each ticket is reduced by $[tex]5[/tex]

The price of new ticket is

[tex]250 -5[/tex]

[tex]= 245[/tex] dollars

The new number of tickets sold after reducing the price is

[tex]5000+ 500\\[/tex]

[tex]5500[/tex]

The total money earned by the flight agency is

Number of tickets x price of each tickets

[tex]5500 * 245\\[/tex]

[tex]1347500[/tex] dollars

Scenario II i.e. when the price of ticket is $[tex]$245[/tex]  will generate the greatest profit for the airline

Answer:

the answer is 12

hope i helped

Step-by-step explanation:

Yes, in a balanced chemical equation, the number of total molecules (or atoms) on the left side of the equation is always equal to the number of total molecules (or atoms) on the right side of the equation. This principle is known as the Law of Conservation of Mass.

The Law of Conservation of Mass states that in a chemical reaction, matter is neither created nor destroyed. This means that the total mass of the reactants must be equal to the total mass of the products. Since molecules are composed of atoms, the number of atoms of each element on the left side of the equation must equal the number of atoms of the same element on the right side of the equation.

To balance a chemical equation, coefficients are placed in front of the chemical formulas to ensure that the number of atoms of each element is the same on both sides of the equation. Balancing the equation ensures that the total number of molecules (or atoms) is conserved, maintaining the principle of the Law of Conservation of Mass. Therefore, in a balanced chemical equation, the number of total molecules on the left side is always equal to the number of total molecules on the right side.

COMPLETE QUESTION:

Balancing chemical equations lab answers is the number of total molecules on the left side of a balanced equation always equal to the number of total molecules on the right side of the equation?

This is an incomplete question, here is the complete question.

The three-dimensional figure shown consists of a cylinder and a right circular cone. The radius of the base is 10 centimeters. The height of the cylinder is 16 centimeters, and the total height of the figure is 28 centimeters. The slant height of the cone is 13 centimeters. Which choice is the best approximation of the surface area of the figure? Use 3.14 to approximate pi.

(1) 1727 cm²

(2) 2355 cm²

(3) 2041 cm²

(4) 6699 cm²

Answer : The surface area of the figure is, 1727 cm²

Step-by-step explanation :

The formula for curved surface area of triangle is:

[tex]A=\pi \times r\times l[/tex]

where,

r and l are radius and slant height of triangle.

The formula for curved surface area of cylinder is:

[tex]A=2\pi \times r\times h[/tex]

where,

r and h are radius and height of cylinder.

The formula for area of circle is:

[tex]A=\pi r^2[/tex]

where,

r is radius circle.

Now we have to calculate the surface area of total figure.

Surface area of total figure = Surface area of triangle + Surface area of cylinder + Area of circle

Surface area of total figure = [tex]\pi \times r\times l+2\pi \times r\times h+\pi r^2[/tex]

Surface area of total figure = [tex]\pi \times r(l+2h+r)[/tex]

Given:

r = 10 cm

h = 16 cm

l = 13 cm

Now put all the given values in this formula, we get:

Surface area of total figure = [tex]3.14\times 10\times (13+2\times 16+10)[/tex]

Surface area of total figure = 1727 cm²

Thus, the surface area of the figure is, 1727 cm²

The formula for amount is given by:

[tex] A=P(1+\frac{r}{n})^{nt} [/tex]

Now we are given ,

Principal (P) =$8500

rate (r) =3.9% = 0.039

period of interest (n) =1 for compounded annually

time (t) = 12 years

Plugging these values in the formula,

[tex] A=8500(1+\frac{0.039}{1})^{1*12} [/tex]

Amount =$13452.5773053

Answer : There will be $13452.5773053 in the account after 12 years.

Answer:

A

Step-by-step explanation:

Answer:

452.16 is the answer

Step-by-step explanation:

To determine the probability of finding at least one defective bulb in the lot of 100 bulbs, one must calculate the complementary event, picking no defective bulbs, and subtract its probability from 1.

This problem involves Probability and Combinatorics, fundamental branches in Mathematics to calculate the possible outcomes in an event. Here, to calculate the probability of finding at least one defective bulb, we can begin by calculating the complementary event, that is, finding no defective bulbs in a sample.

The total number of ways to pick 10 bulbs from 100 is the combination C(100, 10). Likewise, the total number of ways to pick 10 non-defective bulbs from the 95 non-defective bulbs in the lot is C(95, 10). The probability of picking 10 non-defective bulbs then is C(95, 10)/C(100, 10).

Since the event of finding 'at least one defective bulb' is the complementary of 'finding no defective bulbs', we can subtract this probability from 1. So, the probability of finding at least one defective bulb is 1 - (C(95, 10)/C(100, 10)).

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Final answer:

To find the limit of f(x) as x approaches 3, factor the numerator and denominator as differences of squares, cancel common terms, and substitute x = 3 into the simplified fraction to get the limit, which is 4.5.

Explanation:

The student's schoolwork question involves calculating the limit of a function as x approaches a certain value. Specifically, the function in question is f(x) = (x^3 - 27) / (x^2 - 9) and the limit to be computed is limx → 3 f(x). To solve this, first recognize that directly substituting x = 3 would result in a 0/0 indeterminate form. To find the limit, we'll use algebraic manipulation.

Since both the numerator and the denominator are differences of squares, factoring them would give (x-3)(x^2+3x+9) for the numerator and (x-3)(x+3) for the denominator. The x-3 terms cancel out, leaving us with x^2+3x+9 over x+3. Now, substituting x = 3 into the simplified fraction will provide the value of the limit.

Calculating the limit step by step:

Original function: f(x) = (x^3 - 27) / (x^2 - 9)

Factor both numerator and denominator: f(x) = [(x-3)(x^2+3x+9)] / [(x-3)(x+3)]

Cancel out (x-3) terms: f(x) = (x^2+3x+9) / (x+3)

Substitute x = 3: f(3) = (3^2+3*3+9) / (3+3) = (9+9+9) / 6 = 27 / 6 = 4.5

Answer: the andswer is randy

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

x = plus-or-minus StartRoot 5 EndRoot and x = ±10i

ED 2021

The total amount paid = $3840

"A = P(1 + rt)

Where A = Total Amount (principal + interest)

P = Principal Amount

I = Interest Amount

r = Rate of Interest in decimal

R = Rate of Interest as a percent

[tex]r=\frac{R}{100}[/tex]

t = Time Period"

For given question,

P = $3200

t = 4 years

R = 5%

[tex]\Rightarrow r=\frac{5}{100}\\\\ \Rightarrow r=0.05[/tex]

Using the formula of simple interest,

[tex]A=P(1+rt)\\\\A=3200(1+(0.05\times 4))\\\\A=3200(1+0.2)\\\\A=3200\times 1.2\\\\A=\$ 3840[/tex]

Therefore, the total amount paid = $3840

Learn more about simple interest here:

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Answer:

[tex]\frac{3x+4}{x^2} [/tex]

Step-by-step explanation:

sum of [tex]\frac{3}{x} + \frac{4}{x^2}[/tex]

To find the sum of two fractions we need to make the denominator same

LCD is x^2. we need to get x^2 in the denominator of both fractions

Multiply the first fraction with x

[tex]\frac{3 \cdot x}{ \cdot x} + \frac{4}{x^2}[/tex]

[tex]\frac{3x}{x^2} + \frac{4}{x^2}[/tex]

Denominators are same , now we add the numerators

[tex]\frac{3x+4}{x^2} [/tex]

Answer:

A. the volleyball reached it's maximum height of 3 sec

B. The maximum height of the vollybal was 23 ft

E. The vball was served from a height of 5 ft

Step-by-step explanation:

h(t) = -2 (t-3)^2 +23

Given equation is in the form of [tex]f(x)= a(x-h)^2 + k[/tex]

(h,k) is the vertex

Now we compare f(x) with h(t)

h(t) = -2 (t-3)^2 +23

h = 3  and k = 23

Vertex is (3,23)

h=3 . this means the volleyball reaches its maximum height in 3 seconds

k = 23. this means the volleyball reaches the maximum height of 23 ft

When ball reaches the ground the height becomes 0. so plug in 0 for h(t) and solve for t

0= -2 (t-3)^2 +23

Subtract 23 on both sides

-23 = -2(t-3)^2

Divide both sides by -2

[tex]\frac{-23}{-2} = (t-3)^2[/tex]

Take square root on both sides

[tex]+-\sqrt{\frac{23}{2}}= t-3[/tex]

Add 3 on both sides

[tex]+-\sqrt{\frac{23}{2}}+3= t[/tex]

We will get two value for t

t=-0.39  and t= 6.39

So option C is not correct

Given h(t) is a quadratic function not exponential

To find initial height we plug in 0 for x and find out h(0)

h(0) = -2 (0-3)^2 +23 = -2(-3)^2 + 23= -18+ 23= 5

The volleyball was served from a height of 5 ft

The probability that three runners from the same school finishing first, second, and third can be calculated as the product (5/30) * (4/29) * (3/28). This uses the principles of probability in mathematics.

The problem involves the concept of probability in Mathematics. Let's break this question down using the principles of probability.

For the first runner to be from your school, the probability would be 5/30 as there are 5 runners from your school out of 30 total runners. After one runner from your school has won, there are now 4 runners left from your school and 29 total runners left. So, the probability of the second runner being from your school is 4/29. Similarly, the probability that the third runner is also from your school is 3/28 since there are now three left from your school and 28 in total.

The final probability is the product of all three of these probabilities, so:

P(all three top spots are from your school) = (5/30) * (4/29) * (3/28), which needs to be calculated to get the final result.

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The result is 0.00246, or about 0.25% chance.

To find the probability that three runners from your school place first, second, and third in a race with 30 runners, we need to consider the number of ways to select these three positions from your school's five runners and divide it by the total number of ways to select any three runners from all 30 participants.

Calculate the number of ways to choose 3 runners out of the 5 from your school:

[tex]C(5, 3) = \( \frac{5!}{3!(5-3)!} \) = 10[/tex]

Calculate the number of ways to arrange these 3 runners in the first, second, and third positions. This is equal to the number of permutations of 3 elements:

P(3) = 3! = 6

Calculate the total number of ways to choose 3 runners out of the 30 participants:

[tex]C(30, 3) = \( \frac{30!}{3!(30-3)!} \) = 4060[/tex]

Calculate the number of ways to arrange these 3 runners in the first, second, and third positions:

P(3) = 3! = 6

Finally, calculate the probability that 3 runners from your school place first, second, and third:

[tex]Probability = \( \frac{C(5, 3) \times P(3)}{C(30, 3) \times P(3)} \) = \( \frac{10 \times 6}{4060 \times 6} \) = \( \frac{10}{4060} \) = \( \frac{1}{406} \)[/tex]

Thus, the probability is approximately 0.00246 (or 1/406).

Final answer:

Using the hypergeometric distribution, the probability that exactly 2 out of 10 TVs randomly chosen from a shipment of 20 are defective is approximately 34.81%.

Explanation:

To find the probability that exactly 2 out of 10 randomly chosen TVs are defective, we can use the hypergeometric distribution. This distribution applies because we are dealing with a scenario where we have a finite population (20 TVs) and a non-replacement condition (once a TV is chosen for inspection, it is not put back).

The probability formula for the hypergeometric distribution is:

P(X = k) = [(C(g, k) * C(N-g, n-k)) / C(N, n)]

Where:

Plugging the numbers into the formula, we have:

P(X = 2) = [(C(5, 2) * C(15, 8)) / C(20, 10)]

P(X = 2) = [(10 * 6435) / 184756]

P(X = 2) = [64350 / 184756] ≈ 0.3481

So, the probability that exactly 2 out of 10 TVs inspected will be defective is approximately 0.3481 or 34.81%.