A company reported $50,000 net cash provided by operating activities. It invested $1,000 in equipment and paid $1,000 in dividends. Its free cash flow was a) $44,000. b) $52,000. c) $48,000. d) $12,000.

Answer:

d. empirical discrete distribution

Step-by-step explanation:

Empirical refers to what you observe, in this case the relative frequency

Discrete probability distributions is what you are trying to develop.

a, b and c are different forms an empirical discrete distribution can take. You could say that a,b and c are "types" of the "empirical discrete distribution"

The use of the relative frequency method leads to an empirical discrete distribution, which reflects observed frequencies in a sample and is distinct from theoretical models like the binomial distribution.

The use of the relative frequency method to develop discrete probability distributions leads to what is known as an empirical discrete distribution. This method involves determining probabilities based on the frequency of observed outcomes in a sample. In contrast, other discrete distributions such as the binomial distribution, hypergeometric distribution, and Poisson distribution are based on mathematical models with specific properties and assumptions beyond empirical observation.

An empirical discrete distribution captures the observed frequencies of outcomes in a sample and uses these frequencies as probabilities. It does not assume a specific theoretical distribution model, unlike the uniform distribution which assumes each outcome is equally likely, or the binomial distribution which is based on a fixed number of independent trials with a constant probability of success.

Answer:

A- for every animal, if the animal is a rabbit, the animal hops.

B- every animal is a rabbit and it hops.

C-there are animals that, if they are rabbits, they hop.

D-there are animals that are rabbits and they hop

Answer:

a) For every animal, if the animal is a rabbit, then the animal hops

b) For every animal, the animal is a rabbit and the animal hops

c) there are animals such that if they are rabbits then they hop

d) there are animals such that they are rabbits and they hop

Step-by-step explanation:

∀ For every

a⇒b  a then b

a∧b   a and b

∃ there are

Answer:

The answer is (d) "None of the these alternatives are correct"

Step-by-step explanation:

If two events A and B are independent, the probability of the intersection [tex]P(A\cap B)[/tex] is defined as:

[tex]P(A\cap B)=P(A)\cdot P(B)[/tex]

Therefore, in the exercise:

[tex]P(A\cap B)=P(A)\cdot P(B)=0.5\cdot 0.5\\P(A\cap B)=0.25[/tex]

which give (d) "None of the these alternatives are correct"

For independent events A and B with P(A) = 0.5 and P(B) = 0.5, the probability of both events occurring, P(A ∩ B), is the product of their probabilities, which is 0.5 × 0.5 = 0.25. The correct answer is 'd. None of these alternatives are correct.'

The question revolves around the concept of independent events in probability. Since events A and B are independent, the probability of both events occurring together, P(A ∩ B), is the product of their individual probabilities. Thus, using the given probabilities P(A) = 0.5 and P(B) = 0.5, the probability of both A and B occurring is found by multiplying these probabilities together.

P(A ∩ B) = P(A) × P(B) = 0.5 × 0.5 = 0.25.

Therefore, the correct answer is not listed among the provided alternatives, so the correct choice would be 'd. None of these alternatives are correct.'

Answer:

Perimeter at the big rectangle is 156 cm.

Step-by-step explanation:

Let's see how to calculate it.

1. First of all you know that perimeter in the blue one is 20cm, so imagine this:

L (long side); S (short side)

2L + 2S =20

and we consider that L = 4S

So, solving the equation:

2.4S + 2S =20

10S=20

S=20/10

S=2

L=8

2. Side at the gold square is 8, the same at the long side in the blue rectangle. So, if you see on the right side in the big one, we got 2 + 8 + 8 + (?). Take a look to the green. Green square is the gold + a short piece and you can understand the short piece as 2 short sides from the blue. If we give numbers we have 8 + 2 + 2, 12.

Now, 2+8+8+12 = 30cm

3. Let's go to the long side in the big one.

We have long side from blue (8) and as you see, side at the orange square must be side at the yellow + short at the blue, so 8+2 =10. We have four oranges square so 10+10+10+10=40, and +8 =48

4. Now that we have the two sides in the big one, let's find the perimeter with the rectangle formula:

2L + 2S =P

2.48 + 2.30 = 156 cm.

In order to get the answer to this question you will have to multiply both sides by 8.75 and you will get your answer.

[tex]\frac{w}{8.75} =7[/tex]

[tex]\times8.75\times8.75[/tex]

[tex]7\times8.75=61.25[/tex]

[tex]w=61.25[/tex]

Therefore your answer is "w = 61.25."

Hope this helps.

Answer:

Option D. No solutions

Step-by-step explanation:

we have

[tex]3x+2y=1[/tex] -----> equation A

[tex]-9x-6y=3[/tex] ----> equation B

Multiply by -3 both sides equation A

[tex]-3(3x+2y)=-3(1)[/tex]

[tex]-9x-6y=-3[/tex] -----> equation C

Compare equation B and equation C

Equation B and equation C are parallel lines with different y-intercept

Verify

For x=0

Equation C

[tex]-9(0)-6y=-3[/tex] ----->[tex]y=0.5[/tex]

The y-intercept is the point (0,0.5)

Equation B

[tex]-9(0)-6y=3[/tex] ----->[tex]y=-0.5[/tex]

The y-intercept is the point (0,-0.5)

therefore

Lines do not intersect

The system has no solution

see the attached figure to better understand the problem

Final answer:

The system of equations has infinitely many solutions because the second equation is an exact multiple of the first, indicating that both equations are equivalent and represent the same line.

Explanation:

To determine how many solutions the system of equations has, we can look at the coefficients of the variables x and y in both equations.

The first equation is 3x + 2y = 1.

The second equation is -9x - 6y = 3. If we multiply the first equation by -3, we obtain -9x - 6y = -3.

We notice that the second equation is an exact multiple of the first equation after our manipulation. This means that the two equations are equivalent, and every solution to one equation is also a solution to the other. Thus, the system does not have a unique solution, but rather infinitely many solutions, as both lines represented by these equations would perfectly overlap on a graph.

The correct answer to the question is A. Infinitely many solutions.

Answer:

The given statement is false.

Step-by-step explanation:

Accounting deals with the strategic financial issues associated with increasing the value of the business while observing applicable laws and social responsibilities.

This is false.

In accounting, we can make reports like journal entries, trial balance, profit and loss balance sheet etc. for the year but an accountant cannot make strategies over financial issues.

In order to get the answer to this question you will have to rearrange and solve the question step by step.

[tex]10=7-m[/tex]

Rearrange:

[tex]10-(7-m)=0[/tex]

[tex]10-7=3[/tex]

Rearrange once more:

[tex]m+3=0[/tex]

[tex]-3 -3[/tex]

[tex]m=-3[/tex]

Therefore the answer is "m=-3."

Hope this helps.

Answer:

8,695

Step-by-step explanation:

The formula for compound interest is :

Money = C * (1+r)^n

Where

C is the money invested

r is the interest

n is the periods you are investing

Money is the money you will have at the end of the period

In this problem C is what you need to find, the interest is 3.5% (anually) and since it is compounded monthly you have to divide it by 12 months to know exactly the interest of each month:

3.5/12 = 0.2917

The number of periods invested is 4 years, and because the interest is monthly the exact number of periods is 48 ( 4* 12 )

Replacing and solving:

10000 = C * (1+0.002917)^48

C = 8,695

Answer:

8,695

Step-by-step explanation:

Answer:

See the picture

Step-by-step explanation:

Interval   (-∞, 1] U (8, ∞)

On a number line the inequality x ≤ 1 shows all the numbers less than 1 and x>8 shows all the numbers greater than 8.

Inequality is the relationship between two expressions that are not equal, employing a sign such as ≠ “not equal to,” > “greater than,” or < “less than.”.

A number line in elementary mathematics is a representation of a graduated straight line that serves as an abstraction for real numbers, represented by the symbol R." It is assumed that every point on a number line corresponds to a real number and that every real number corresponds to a point.

The graph of the two inequality is attached with the answer below where the inequality x ≤ 1 shows all the numbers less than 1 and x>8 shows all the numbers greater than 8.

To know more about inequality follow

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Answer:

May

Step-by-step explanation:

Let x be the sales in January,

∵ Sales were 10% greater in February than in January,

So, the sales in February = (100 +10)% of x

= 110% of x

= [tex]\frac{110x}{100}[/tex]

= 1.1x

∵  it is 15% less in March than in Feb,

Sales in march = (100-15)% sales in February

= 85% of 1.1x

= 0.935x

∵ It is 20% greater in April than in March,

Sales in April = (100+20)% of sales in march

= 120% of 0.935x

= 1.122x,

∵ It is 10% less in May than in April

Sales in May = (100-10)% of sales in march

= 90% of 1.122x,

= 1.0098x,

∵ It is 5% greater in June than in May

Sales in June = (100+5)% of sales in march

= 105% of 1.0098x,

= 1.5147x

∵ 1.0098x is much closure to x than 1.1x, 0.935x, 1.122x and 1.5147x

Hence, the sales in May is closest to sales in January.

Answer:

E)II and III only

Step-by-step explanation:

This can be seen with examples. Say a[0]=1 and and a[1]=2.

for I , the first line of code would be:

a[0]=a[1];

thus, we would get a new value for a[0]=2.

The second line of code

a[1]=a[0]; uses the new value of a[0], so we would get a[1]=2.

The end result is a[0]=2, and a[1]=2 which doesn't exchange the values of the first two elements.

For II the first line of code

int t= a[0]; saves the original value of a[0] to t, so we get t=1.

the second line of code

a[0]=a[1]; changes the value of a[0]  to that of a[1]. Thus, in our example a[0]=2.

the final line

a[1]=t; changes the value of a[1] to the original value of a[0], giving us a[1]=1 and a[0]=2, what we were looking for.

For III

the first line of code

a[0]=a[0]-a[1];

gives us

a[0]=1-2

the secon line

a[1]=a[1]+a[0];

takes the new value of a[0] and replaces it in the expression

a[1]= 2+(1-2)=1

the last line

a[0]=a[1]-a[0];

takes the new value of a[0] and a[1] and replaces the in the expression

a[0]=1-(1-2)=1-1+2=2

which exchanges the values needed.

So we can see that only II and III do what we require, giving us E as the answer.

To find the probability that a middle-aged man with diabetes is very active, we need to use conditional probability. We calculate the probability of a middle-aged man being very active and the probability that a middle-aged man has diabetes. Then we use these probabilities to find the conditional probability of being very active given diabetes.

To find the probability that a middle-aged man with diabetes is very active, we need to use conditional probability. Let's first calculate the probability of a middle-aged man being very active:

P(very active) = 1/10

The remaining probability would be for men who are sedentary:

P(sedentary) = 1 - P(very active) = 9/10

Now we can calculate the probability that a middle-aged man with diabetes is very active using conditional probability:

P(very active | diabetes) = (P(very active) * P(diabetes | very active)) / P(diabetes)

Since the question states that men who are very active are a third as likely to develop diabetes compared to men who are sedentary, we can calculate:

P(diabetes | very active) = 202/5990

P(diabetes) = (202/5990 * 1/10) + (P(diabetes | sedentary) * 9/10)

Substituting the values, we can calculate the probability that a middle-aged man with diabetes is very active:

P(very active | diabetes) = (1/10 * 202/5990) / ((202/5990 * 1/10) + (P(diabetes | sedentary) * 9/10))

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The probability that a middle-aged man with diabetes is very active is:

[tex]\[ {0.0356} \][/tex].

Given data:

- [tex]\( P(A) = \frac{1}{10} = 0.1 \)[/tex](probability of being very active)

- [tex]\( P(S) = \frac{9}{10} = 0.9 \)[/tex] (probability of being sedentary)

- [tex]\( P(D | S) \)[/tex] (probability of developing diabetes given sedentary) is not directly given, but we can deduce it using the provided data and the fact that the risk of diabetes for active men is a third of that for sedentary men.

- Total probability of developing diabetes, [tex]\( P(D) = \frac{202}{5990} \approx 0.0337 \)[/tex]

First, we need to calculate [tex]\( P(D | A) \) and \( P(D | S) \)[/tex]:

Since active men are a third as likely to develop diabetes compared to sedentary men:

[tex]\[ P(D | A) = \frac{1}{3} P(D | S) \][/tex]

Using the law of total probability for  P(D) :

[tex]\[ P(D) = P(D | A)P(A) + P(D | S)P(S) \][/tex]

Substitute the given values and the relationship between  P(D | A) and  P(D | S):

[tex]\[ 0.0337 = \left( \frac{1}{3} P(D | S) \right)(0.1) + P(D | S)(0.9) \][/tex]

Solve for P(D | S) :

[tex]\[ 0.0337 = \frac{1}{30} P(D | S) + 0.9 P(D | S) \]\[ 0.0337 = 0.0333 P(D | S) + 0.9 P(D | S) \]\[ 0.0337 = (0.0333 + 0.9) P(D | S) \]\[ 0.0337 = 0.9333 P(D | S) \]\[ P(D | S) = \frac{0.0337}{0.9333} \approx 0.0361 \][/tex]

Now calculate  P(D | A) :

[tex]\[ P(D | A) = \frac{1}{3} P(D | S) = \frac{1}{3} \times 0.0361 \approx 0.0120 \][/tex]

Next, apply Bayes' theorem to find  P(A | D) :

[tex]\[ P(A | D) = \frac{P(D | A) P(A)}{P(D)} \]\[ P(A | D) = \frac{0.0120 \times 0.1}{0.0337} \]\[ P(A | D) = \frac{0.0012}{0.0337} \approx 0.0356 \][/tex]

Answer:

The answer to your question is: t = 11-3 h

Step-by-step explanation:

Data

r = 33.2 m/h

d = 375.16 m

Formula

d = rt

Clear t from the equation

 t = d/r

Substitution

t = 375.16 m / 33.2 m/h  

Simplifying

t = 11.3 h        result

Answer:

  C = 18g +350

Step-by-step explanation:

The 2-point form of the equation of a line is useful for this. For points (x1, y1) and (x2, y2), the equation is ...

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

For points (25, 800) and (60, 1430), the line is ...

  y = (1430 -800)/(60 -25)(x -25) +800

  y = 630/35(x -25) +800

  y = 18x +350

Using the variables required by the problem statement, this is ...

  C = 18g +350

Answer:

The statistical tests that researchers use to determine if there was a statisticallysignificant difference in levels of self-esteem between the boys and the girls were the T-test and Cohen's d.

Step-by-step explanation:

A statistical test is utilized to evaluate differences between groups (in this case, between boy and girls). The dependent variable was the self-esteem while the independent variable was the sex. A T-test is utilized to establish differences in the mean of two groups. The null hypothesis for a T-test is that means of the groups are the same; the statistical value is t. A Cohen's d test indicates standardized differences between the mean of both groups. It usually accompanies a T-test result; the statistical value is d.

Answer:

The answer is d) 297000

Step-by-step explanation:

The stockholders' equity of a company represents the amount of money that will be returned to the accionists if all the assests will be liquidated and the compan'y debt will be paid.  So to calculate the Swifty Corporation stockholders' equity at the end of the year you need to add all what enters to the company (assets and revenues) and substract all what goes out (liabilities, expenses and dividends).

- What enters?

Total incomes = $300.000 + $633.000 = $933.000

- What goes out?

Total expenses = $240.000 + $335.000 + $61.000 = $636.000

Stockholders' equity = Total income - Total expenses

Stockholders' equity = $933.000 - $636.000 = $297.000

Answer:

The equation of the line is [tex]y=45.25t+545[/tex]

Step-by-step explanation:

The general for of a line is:

[tex]y=mt+n[/tex]       (1)

where:

[tex]m[/tex] is the slope of the line and [tex]m[/tex] is the intercept with the axis of the dependent variable, [tex]y[/tex] in this case.

In order to obtain the value of the slope ([tex]m[/tex]) we can use the corresponding slope formula:

[tex]m=\frac{y_{2}-y_1 }{t_2-t_1}[/tex]         (2)

where [tex]t_1, t_2, y_1[/tex] and [tex]y_2[/tex] are the corresponding coordinates of the given points. In this case:

[tex]t_1=0\\t_2=4\\y_1=545\\y_2=726\\[/tex]

Substituting these values in equation (2) we obtain:

[tex]m=\frac{726-545}{4-0}=\frac{181}{4}=45.25\\m=45.25[/tex]

Hence, the line equation is now:

[tex]y=45.25t+n[/tex]     (3)

Now to obtain the value of [tex]n[/tex] you can follow two options:

Note that for this question, it is easier to select point A because of having the independent variable equals to zero [tex]t=0[/tex]. Hence, substituting point A in equation (3):

[tex]45.25*0+n=545\\n=545[/tex]

Therefore, the line equation is: [tex]y=45.25t+545[/tex]

The second option to find [tex]n[/tex] is to think of the meaning of the intercept. The intercept of a line is defined as the point in which the line crosses the axis of the dependent variable, which also means that the value of the independent variable for this point is zero. From this, we could have automatically said that [tex]n[/tex] is equal to [tex]545[/tex].

See the attachment for a plot of the line.

Final answer:

To derive the equation of the line through A(0, 545) and B(4, 726), calculate the slope (45.25) and use the point-slope form to get the final equation: [tex]\(y = 45.25t + 545\).[/tex]

Explanation:

To derive an equation of the line passing through points A(0, 545) and B(4, 726), first we need to find the slope of the line. The slope, usually represented as[tex]\(m\),[/tex] is given by the change in \(y\) over the change in \(x\), which is [tex]\(\Delta y / \Delta x\).[/tex]We use the formula [tex]\(m = (y_2 - y_1) / (x_2 - x_1)\).[/tex]

Substituting the given points into the formula:

[tex]\[m = \frac{726 - 545}{4 - 0} = \frac{181}{4} = 45.25\][/tex]

Now that we have the slope, we use the point-slope form of a line's equation, which is [tex]\(y - y_1 = m(x - x_1)\), where \((x_1, y_1)\)[/tex]is a point on the line. Since one point we have is A(0, 545), we can substitute the values in:

[tex]\[y - 545 = 45.25 \cdot (x - 0)\][/tex]

Therefore, the equation simplifies to:

[tex]\[y = 45.25x + 545\][/tex]

This is the equation of the line in slope-intercept form, with \(t\) being the independent variable and \(y\) being the dependent variable.

Answer:

A. [tex]150+75h>600[/tex]

B. More than 6 hours

Step-by-step explanation:

A plumber earns $50 for a repair job, so he will earn $150 for three repair jobs.

Let h be the number of hours the plumber worked on Tuesday. He earns $75 per hour worked, so he will earn $75h in h hours.

In total, the plumber earned $(150 + 75h)

A. On Tuesday, he completed 3 repair jobs and earned a total of more than $600. Thus

[tex]150+75h>600[/tex]

B. Solve this inequality. Subtract 150:

[tex]150+75h-150>600-150\\ \\75h>450[/tex]

Divide by 75:

[tex]h>\dfrac{450}{75}\\ \\h>6[/tex]

This means, the plumber worked more than 6 hours.

Answer:

x = 50

Step-by-step explanation:

The two angles are vertical angles, so they are congruent. Congruent angles have equal measures. Set the angle measures equal to each other, and solve the equation for x.

2(x + 10) = 3x - 30

Distribute on the left side.

2x + 20 = 3x - 30

Subtract 2x from both sides.

20 = x - 30

Add 30 to both sides.

50 = x

x = 50

Answer:

x=50

Step-by-step explanation:

2x+20 = 3x-30

2x+50 = 3x

50 = x

To find a possible value for n given the number of squares not along the boundary of a gameboard, set up an equation and solve it using the quadratic formula.

The number of squares that do not lie along the boundary of the gameboard can be found by subtracting the number of squares along the boundary from the total number of squares on the gameboard. The total number of squares on the gameboard is n×n, and since there are n squares along each side of the gameboard, the number of squares along the boundary is 4n. Therefore, the number of squares that do not lie along the boundary is n×n - 4n.

Given these equations, we can set up an equation for each possible value of k:

We can solve these equations to find the possible values of n. For the first equation, arranging the terms gives us the quadratic equation n×n - 4n - 10 = 0. By solving this quadratic equation using the quadratic formula, we can find the possible values of n that satisfy the equation. Similarly, we can do the same for the remaining equations to find all possible values of n.

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Answer: 896.9072165

Step-by-step explanation:

Answer:

There is one knave

Step-by-step explanation:

Let's analyze the two possible scenarios, from the unheard Fred's answer

- SCENARIO 1: Fred is a knave.

If Fred is a Knave, he must have told to the other natives that he wasn't, remember that Knaves will never tell the truth. In that sense, George said that Fred denied being a knave, he would be telling the truth (Fred is a knight) and Quincy said that Fred is a knave, which would also be true (Quincy is a knight too).

-SCENARIO 2: Fred is a knight

If Fred is a knight, he must have told to the other natives that he wasn't a knave, he would be telling the truth. In this case, George would also be telling the truth by ensuring that Fred denied being a knave (Fred is a knight). However, Quincy would be lying to ensure that Fred is a knave. In this scenario Quincy is the knave

In conclusion, in both scenarios, there is only one knave.

Answer:

D.8 inches

Step-by-step explanation:

Answer:

P = 8x + 2

P = 98 when x = 12

Step-by-step explanation:

the perimeter is 2 times width + length

P = 2(w + l)

w = 2x - 5

l = 2x + 6

replacing both terms in the perimeter:

P = 2(2x - 5 + 2x + 6)

P = 2(4x + 1)

P = 8x + 2

Evaluating P for x = 12

P = 8(12) + 2

P = 98

Step-by-step explanation:

A line and circle intersect at exactly one point if the line is tangent to the circle.

A line and circle intersect at exactly two points if the line is a secant line to the circle.

A line and circle cannot intersect at three points.

See attached diagram.

Explanation:

A line that intersects a circle at exactly two points is considered a secant line.

A line that intersects a circle at exactly one point is considered a tangent line.

* I apologize for not having the illustrations, but at least you know what they look like from what that user sent.

You can never intersect a circle at three points.

I am joyous to assist you anytime.

Answer:

58.3%

Step-by-step explanation:

125/300 people decided to buy their product but 175 didn't to get the answer for the problem you just divide 175 by 300 which gets you 0.58333... in which you move the decimal place two to the right which gives you 58.3 then that is your percent 55.3%

Answer: There is 58.3% of students that are not convinced.

Step-by-step explanation:

Since we have given that

Number of schools = 300

Number of schools that are convinced to sell their products = 125

Number of schools that are not convinced to sell their products = 300 - 125 = 175

Percentage of schools that are not convinced is given by

(175 ÷ 300) × 100

= 175 ÷ 3

= 58.3 %

Hence, there is 58.3% of students that are not convinced.

Answer:

36.888

Step-by-step explanation:

you would just add them all up. 11.238 + 9.45 + 16.2 then you'll get your answer which is 36.888

Answer:

for year 1

common stock =  $1.75 per share

preferred stock  = Zero

for year 2

common stock =  $4.25 per share

preferred stock  = $0.3 per share

for year 3

common stock =   $3 per share

preferred stock  =  $2 per share

Step-by-step explanation:

step 1

preferred stock value =  (40000 shares * $150) = $6000000

common stock value  = (100000 shares * $5) = $500000

 step 2

For year 1:

Dividend on preferred stock;

[tex]\frac{6000000 * 2}{100}[/tex] = $120000

But total dividend in the question was $70000 therefore total amount of  dividend on cumulative preferred stock is $70000.

hence, dividend per share

[tex]= \frac{70000}{40000 shares}[/tex] = $1.75 per share

Dividend on common stock;

70,000 - 70,000 = Zero

as total dividend distributed in year 1 is insufficient for cumulative preferred stock therefore no dividend will be paid on common stock.

For year 2:

Dividend on cumulative preferred stock;

[tex]\frac{6000000 * 2}{100}[/tex]= $120000

extra dividend of year 1 ($120000 - $70000) = $50000

Thus total dividend on cumulative preferred stock

($120000 + $50000) = $170000

So dividend per share

[tex]\frac{170000}{40000\ shares}[/tex]= $4.25 per share

Dividend on common stock;

($200000 – $170000) = $30000

dividend per share

[tex]\frac{30000}{100000\ shares}[/tex] = $0.3 per share

For year 3:

Dividend on cumulative preferred stock;

[tex]\frac{6000000 * 2}{100}[/tex] = $120000

total dividend on cumulative preferred stock $120000

dividend per share

[tex] \frac{120000}{40000 shares}[/tex] = $3 per share

No dividend was extra in the year 2 therefore only available dividend of this year will be paid.

Dividend on common stock;

($320000 – $120000) = $200000

dividend per share

[tex]\frac{200000}{100000\ shares}[/tex]= $2 per share