A cord of mass 0.75 kg is stretched between two supports 7.2 m apart. part a if the tension in the cord is 150 n , how long will it take a pulse to travel from one support to the other?

Answer: Option (B) is the correct answer.

Explanation:

Non-metals are the substance which are electron deficient in nature.

Some properties of non-metals are as follows.

Thus, we can conclude that unlike metals, nonmetals exhibit high brittleness and fractures easily when subjected to stress.

4.8 is the correct answer

Answer:

4.8%

Explanation:

percentage error can be calculated as the difference between the theoretical and experimental value divided by the experimental value expressed in percentage.

The percentage error can be  computed mathematically as

(accepted value - experimental value)/accepted value × 100

accepted value = 63 m/s

experimental value = 66 m/s

difference = 63 - 66 = -3 m/s

use the absolute value = 3 m/s

percentage error = (accepted value - experimental value)/accepted value × 100

percentage error = 3/63 × 100

percentage error = 300/63

percentage error = 4.76%

percentage error = 4.8%

The horizontal distance traveled by the spittle is 2.62 m.

The given parameters;

The time of motion is calculated as;

[tex]h = v_0_yt + \frac{1}{2} gt^2\\\\1.8 = (5.5\times sin(13))t + (0.5\times 9.8)t^2\\\\1.8 = 1.24t + 4.9t^2\\\\4.9t^2 + 1.24t - 1.8= 0\\\\solve \ the \ quadratic \ equation\ using \ formula \ method;\\\\a = 4.9, \ b = 1.24, \ c = -1.8\\\\t = \frac{-b \ \ +/- \ \ \sqrt{b^2 - 4ac} }{2a} \\\\t = \frac{-1.24 \ \ +/- \ \ \sqrt{(1.24)^2 - 4(4.9\times -1.8)} }{2(4.9)} \\\\t = 0.49 \ s[/tex]

The horizontal distance traveled by the spittle is calculated as;

[tex]X = v_0_x \times t\\\\X = 5.5\times cos (13) \times 0.49\\\\X = 2.62 \ m[/tex]

Thus, the horizontal distance traveled by the spittle is 2.62 m.

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The time it would take for a 20.0 μF capacitor initially charged to 30.0 μC to discharge through a 1.80 kΩ resistor and reduce the capacitor's charge to 15.0 μC can be calculated using the formula for exponential decay and the time constant of the RC circuit.

The time it takes for a capacitor to discharge to half of its original charge can be found using the formula for exponential decay, based on the time constant (t) of the RC circuit, which is given by t = RC, where R is the resistance and C is the capacitance. The time constant represents the time it takes for the charge to decrease to about 36.8% of its initial value. Since we are looking for the time it takes to reduce to half of the initial charge, we must solve the equation 0.5 = e^(-t/RC), where e is the base of natural logarithms.

To solve for t, we can rearrange the equation to get -ln(0.5) = t/RC. Given that R = 1.80KΩ = 1.80x10^3 Ω and C = 20.0 µF = 20.0x10^-6 F, we can substitute these into the equation to find t. Therefore, the time it takes for a 20.0 μF capacitor initially charged to 30.0 µC to discharge through a 1.80 kΩ resistor to reduce the capacitor's charge to 15.0 μC can be calculated using these formulas.

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Answer:

heat transfer by convection

Explanation:

yeah the heat just goes to your hand like "hello" now your hand is warm just don't TOUCH the fire because then it will go "HELLO" and it will be painful

Have a fantastic life and just I don't know... live life and go outside it's beautiful.

A typical cell membrane in an animal maintains a potential difference across the membrane of ΔV = 70 mV and the membrane has a thickness of about 8 nm. The capacitance of the membrane is about 1 microFarad per square cm. 

(B) If we model the membrane by a simple "two thin sheets of charge" model separated by 8 nm with nothing between them, what would be the electric field be between the sheets and what would the charge density on the sheets of the membrane? Explain your reasoning.

Now, notice that:

[tex]Q=C\Delta V\\ \Delta V=E.L[/tex]

Where L is the thickness of the membrane.

We then can get the electric field by just using:

[tex]E=\frac{\Delta V}{L}=\frac{70\times10^{-3}}{8\times10^{-9}}=8.75\times10^{6}N.C^{-1}[/tex]

Now using the charge expression and plugging the the expression for [tex]\Delta V[/tex] into it and then solving for [tex]E[/tex] we get:

[tex]E=\frac{Q}{CL}[/tex]

Now let's multiply both denominator and numerator by [tex]\frac{1}{A}[/tex] this yields:

[tex]E=\frac{\sigma}{C_{\sigma}L}[/tex]

Where 

[tex]\sigma=\frac{Q}{A}\\ C_{\sigma}=\frac{C}{A}[/tex]

Notice that the value in the wording of the problem is no actually the capacitance, but the capacitance per area [tex]C_{\sigma}[/tex], also [tex]\sigma[/tex] is the charge density.

Let's transform [tex]C_{\sigma}[/tex] to [tex]\frac{farad}{m^2}[/tex]:

[tex]\frac{1\mu F}{cm^2}=\frac{1\times10^{-2}F}{m^2}[/tex]

Solving for  [tex]\sigma[/tex] we get:

[tex]sigma=E.C_{\sigma}.L=7\times10^{-4}\frac{Coulomb}{m^2}=7\times10^{-8}\frac{Coulomb}{cm^2}[/tex]

Using the law of conservation of momentum, it is determined that after her collision with Jack, Jill will move in a direction that is south of east.

This problem involves the principle of conservation of momentum. In this case, we have a two-body collision, where Mass1 (Jack, with mass 52kg and initial velocity 8m/s due east) collides with Mass2 (Jill, with mass 49.0kg and initially at rest). After the collision, Jack is traveling at a direction 34.0° north of east (let's call this direction east') with a speed of 5m/s. The initial momentum (Mass1 + Mass2) should be equal to the final momentum if we ignore the friction.

Before the collision, the total momentum was Momentum1 initial = Mass1 x Velocity1 initial = 52kg x 8m/s = 416 kg m/s, all in an eastward direction. Momentum2 initial = 0, as Jill was at rest.

After the collision, the final momentum of Jack becomes Momentum1 final = Mass1 x Velocity1 final = 52kg x 5m/s = 260 kg m/s, directed 34° north of east.

According to the law of conservation of momentum, the total initial momentum must equal the total final momentum. Hence, the final momentum of Jill will be Momentum2 final = Momentum1 initial - Momentum1 final = 156 kg m/s. This quantity only gives us the magnitude of the momentum, but we can calculate the direction based on Jack’s final direction. Given that momentum is a vector quantity, the principle of vector composition lets us infer that Jill’s final direction must be south of east to balance the north-of-east component of Jack's final momentum.

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Answer:C) gasoline

Explanation:

Specific heat is the measure of the heat energy required to increase or decrease the temperature of a substance by a certain temperature interval. Gasoline has the lowest specific heat; that means it takes less energy to lower or raise the temperature of gasoline compared to the other three liquids.

a. the maximum height reached by the ball is approximately 3.46 meters.

b.   the speed of the ball when it is at the highest point is approximately 21.19 meters per second.

c.   the ball lands  14.83 meters away from the launch point in the same direction as its horizontal component of velocity.

a)

Vertical component = Initial speed * sin(launch angle)

Vertical component = 23 m/s * sin(21°) = 8.23 m/s

The maximum height reached by the ball can be calculated using the equation:

Maximum height = (Vertical component²) / (2 * gravity)

Gravity = 9.81 m/s².

Maximum height = (8.23 m/s)² / (2 * 9.81 m/s²)

=  3.46 m

b)

At the highest point, the vertical component of velocity becomes zero  because the ball stops momentarily before falling back down.

Horizontal component = Initial speed * cos(launch angle)

Horizontal component = 23 m/s * cos(21°) =  21.19 m/s

c)

Time to fall = (2 * Maximum height) / gravity

Time to fall = (2 * 3.46 m) / 9.81 m/s² =  0.70 s

Horizontal distance = Horizontal component * Time to fall

Horizontal distance = 21.19 m/s * 0.70 s =  14.83 m

Veins contain a network of valves to insure a one-way flow of blood but arteries do not. This is because veins must counteract the force of gravity on blood flow.

Veins must counteract the force of gravity on blood flow. Unlike arteries that carry blood away from the heart under high pressure, blood in veins is under much lower pressure after passing through capillaries.

The presence of one-way valves in veins, particularly in the limbs, is crucial to ensure the unidirectional flow of blood back toward the heart. These valves, along with the help of muscle contractions, prevent backflow and assist venous return to the heart, overcoming the effects of gravity and the reduced pressure in the venous system.

By the time blood reaches the venules and veins, the pressure initially exerted by heart contractions has greatly decreased. The veins are equipped with thin walls, large lumens, and valves that work together with muscle contractions to promote the return of blood to the heart.

This system compensates for the low blood pressure and the pull of gravity that would otherwise hinder the upward movement of blood from the extremities.

Explanation:

It is given that, two teams are playing tug of war.

Force applied by Team A, [tex]F_A=450\ N[/tex]

Force applied by Team B, [tex]F_B=415\ N[/tex]

We need to find the net force acting on the rope. It is equal to :

[tex]F_{net}=F_A-F_B[/tex]

[tex]F_{net}=450-415[/tex]

[tex]F_{net}=35\ N[/tex]

So, the net force acting on the rope is 35 N and it is acting toward right. Hence, this is the required solution.

Answer:

20 N to the left

Explanation:

The calculation involves combining the masses after collision, calculating the final velocity using the law of conservation of momentum and then finding the frictional work done. Using the work-energy theorem, we can solve for the coefficient of kinetic friction.

The question is asking to find the coefficient of kinetic friction on the rough surface where two blocks m1 and m2 have collided and eventually come to a stop after traveling a certain distance. We first need to combine the mass of both blocks as they stick together and this results in a total mass (m1 + m2 = 3.5 kg + 1.7 kg = 5.2 kg). After collision, we can use the law of conservation of momentum to calculate the final velocity when both blocks stick together (m1*v1 + m2*v2 = (m1 + m2) * v_final).

Substituting known values (3.5 kg * 6.3 m/s + 1.7 kg * 0 m/s = 5.2 kg * v_final), we get v_final = 4.425 m/s.

Now, to find the coefficient of kinetic friction, we will use the equation of work-energy theorem where Workdone by friction = Change in kinetic energy. The work done by frictional force is equal to the force of friction multiplied by the distance, and force of friction equals the coefficient of kinetic friction times the normal force (which is mass times gravity in this case).

Thus, the equation would be: μk * m1 * g * d = ½ * m1 * v1^2 (since the final velocity is zero). Substituting the known values into this equation, we can solve to find the coefficient μk.

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Brass can be classified as  [tex]\boxed{{\text{a}}{\text{. homogenous mixture and a solid solution}}}[/tex].

Further explanation:

Alloy:

An alloy is defined as combination of metals or a combination of one or more metals with non-metals. Alloys have a large range of applications, ranging from surgical tools, aerospace industry to automobile construction. Steel, solder, brass, pewter, bronze, and amalgams are some examples of alloys. Alloys can be either solid solution or a mixture of metallic phases.

Mixture:

The material that is made up of two or more substances is called a mixture. It has no fixed formula, and its composition is also varied. All the individual constituents retain their properties after the formation of the mixture.

Types of mixtures:

1. Homogeneous mixtures

Homogeneous is a Latin word that means the same. These mixtures have a uniform composition throughout. Air, orange juice, and blood are the examples of a homogenous mixture.

2. Heterogeneous mixtures

Heterogeneous is a Latin word that means different. These mixtures that have non-uniform composition throughout. Concrete, soda, and chocolate chip cookies are the examples of a heterogeneous mixture.

Characteristics of mixtures:

1. It has a variable composition and has no formula.

2. Mixtures are not formed by any chemical reactions.

3. Mixtures can be either homogeneous or heterogeneous.

4. The constituents of the mixtures can be separated by physical methods such as filtration, heating, drying, distillation, crystallization.

5. The properties of the individual particles of the mixture are retained even after the formation of mixtures.

Copper and zinc are the two metals that are first melted, mixed and then solidified to form brass. Their composition is the same throughout the whole part of brass. So brass is an example of homogeneous mixture. It is also known as solid solution where zinc acts as solute and copper is a solvent.

Learn more:

1. The major contribution of Antoine Lavoisier to chemistry: https://brainly.com/question/2500879

2. Example of physical change: https://brainly.com/question/1119909

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Mixture

Keywords: mixture, characteristics, formula, composition, properties, chemical reactions, filtration, distillation, heating, crystallization, homogeneous, heterogeneous, brass, alloy, metals, non-metals, aerospace industry, automobile construction, surgical tools, solid solution, zinc and copper.

Answer: One side of the moon always faces Earth because the time it takes the moon to spin on its axis is "the same as" the time it takes the moon to travel around Earth.

The question explores the concept of physical weathering known as frost wedging, which occurs when water freezes in rock cracks, causing the rocks to break apart. This process relates to the property of water expanding upon freezing, which explains ice's lower density and its effects on the environment and human-made structures.

The student's question pertains to the process by which water enters cracks in rocks, freezes, and expands into ice, which is known as frost wedging or frost weathering. This process is a type of physical weathering that occurs in cold climates when temperatures fluctuate above and below 0°C (32°F). As water freezes, it expands by approximately 9%, exerting significant pressure on the surrounding rock, eventually causing it to break apart. The phenomenon of water expanding upon freezing is due to the unique structure of ice.

Understanding ice density is significant for explaining why ice floats and how it affects aquatic ecosystems and human constructions. When water transitions to ice, its molecules form a crystalline structure that is less dense than liquid water, causing ice to float. This property of ice provides crucial insulating effects in natural bodies of water, allowing life to persist beneath the ice layer during winter. Furthermore, the expansion of water when it freezes is why we use antifreeze in engines and why pipes can burst if not properly insulated.

The converted energy of [tex]324\;J[/tex] is the thermal energy created by the friction during his descent.

Explanation:

Given information:

Mass of justin [tex]=50 \; \text{kg}[/tex]

Height of water slide [tex]=8\;\text{m}[/tex]

Speed at the bottom [tex]= 12 \;\text{m/s}[/tex]

Now, the total mechanical energy is:

[tex]E_i=U=mgh\\E_i=50\times 9.81\times 8\\E_i=3924\;J[/tex]

And, the kinetic energy :

[tex]E_f=K=(1/2)mv^2\\E_f=0.50\times 50\times 12\\E_f=3600\;\text{J}[/tex]

So, the energy lost by the justin:

[tex]\Delta\;E=E_i-E_f\\\Delta\;E=3924-3600\\\Delta\;E=324J\\[/tex]

Hence, this converted energy of [tex]324\;J[/tex] is the thermal energy created by the friction during his descent.

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Answer:

ΔV = 150 V

Explanation:

Final answer:

To convert the weight of a bag of groceries from newtons to kilograms, divide the weight in newtons (44 N) by the acceleration due to gravity (9.8 m/s²), which gives an approximate mass of 4.49 kg.

Explanation:

To find the approximate weight of a bag of groceries in kilograms when given a weight of 44 newtons, we need to use the relation between mass, weight, and gravitational acceleration. Weight is the force due to gravity, and it's measured in newtons (N). To convert newtons to kilograms, we divide the weight by the acceleration due to gravity, which is approximately 9.8 m/s². Therefore:

Weight in kilograms = Weight in newtons ÷ gravitational acceleration

Weight in kilograms = 44 N ÷ 9.8 m/s²

Weight in kilograms ≈ 4.49 kg

This is a physics problem involving the conversion of units between the weight (force) and mass, and it requires a basic understanding of the relationship between these concepts. The result, 4.49 kg, represents the mass of the groceries that causes a weight of 44 N.

If you charge a 1.0 f capacitor with two 1.5 volt batteries, the amount of charge on each of the plates is 3colombs

The formula for calculating the charge on a capacitor is expressed as:

[tex]Q = C \triangle v[/tex]

C is the capacitance of the capacitor in farads

Δv is the change in the potential difference

Given the following parameters

C = 1.0F

For a two 1.5V batteries, v = 2(1.5) = 3V

Substitute the given parameters into the formula as shown:

[tex]Q = 1.0 \times 2(1.5)\\Q=1 \times 3.0\\Q =3Coulumbs[/tex]

Hence the amount of charge on each of the plates is 3colombs.

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