A hang glider is soaring over a 100-acre area that consists of thick forest and open fields. In the diagram below, the forested area is shaded in green and the open field is the white space. Upon landing, the hang glider realizes she has dropped her keys.

Answer:

The type II error might have been committed because of small sample size or small significance level.

Step-by-step explanation:

A type II error is a statistical word used within the circumstance of hypothesis testing that defines the error that take place when one is unsuccessful to discard a null hypothesis that is truly false. It is symbolized by β i.e.  

β = Probability of accepting H₀ when H₀ is false.

In this case we need to test the hypothesis whether the new advertising campaign increases the sales or not.

The hypothesis can be defined as:

H₀: The new advertising campaign does not increases the sales.

Hₐ: The new advertising campaign increases the sales.

The confidence level wanted here is 99%.

The type II error will be made if we conclude that the new advertising campaign does not increases the sales when in fact the sales are increased after the advertising campaign.

The type II error could have been made because of the following reasons:

Thus, the type II error might have been committed because of small sample size or small significance level.

Answer:

not satisfactional do not vary

Step-by-step explanation:

The subtraction is one of the four basic arithmetic operations in mathematics. The operation subtraction is used here to determine the number of students enrolled in the Saturday morning class. The number of students is 26.

The operation subtraction represents the process of removing objects from a collection. The minus sign implies the subtraction. We can also describe subtraction as the decreasing or removing physical and abstract quantities.

The subtraction method consists of three parts of numbers, they are minuend, subtrahend and difference. The number in a subtraction sentence from which we subtract another number is the minuend, and after that it is subtrahend and last number is the difference.

Here the total present students = 30

Number of absents = 4

So number of presents = 30 - 4 = 26

Thus the students who are enrolled is 26.

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Your question is incomplete most probably your full question was:

In a class the number of students is actually 30, 4 of them were absent on saturday. A dance teacher asks, "How many students are enrolled in the Saturday?

Answer:

a)From the central limit theorem we know that the distribution for the sample mean [tex]\bar X[/tex] is given by:

[tex]\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})[/tex]

And the standard error for the mean would be:

[tex]\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14[/tex]

b) We want this probability:

[tex] P(\bar X >120) [/tex]

And we can use the z score formula given by:

[tex] z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

And replacing we got:

[tex] z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143[/tex]

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

[tex] P( z>2.143) = 1-P(Z<2.143) = 1-0.984 = 0.016[/tex]

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Part a

From the central limit theorem we know that the distribution for the sample mean [tex]\bar X[/tex] is given by:

[tex]\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})[/tex]

And the standard error for the mean would be:

[tex]\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14[/tex]

Part b

We want this probability:

[tex] P(\bar X >120) [/tex]

And we can use the z score formula given by:

[tex] z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

And replacing we got:

[tex] z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143[/tex]

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

[tex] P( z>2.143) = 1-P(Z<2.143) = 1-0.984 = 0.016[/tex]

Answer:

781250 Square Meters

Step-by-step explanation:

Let the dimensions of the rectangular plot be x and y

Farmer Ed wants to enclose three sides of a rectangular plot with a fencing of 2500 meters.

Therefore: Perimeter, P=x+2y=2500

We want to find the largest area that can be enclosed.

Area of the plot, A(x,y)=xy

Substitute x=2500-2y

A(y)=(2500-2y)y

[tex]A(y)=2500y-2y^2[/tex]

To maximize A, we first find its derivative

[tex]A'(y)=2500-4y\\$Setting A'=0\\2500-4y=0\\2500=4y\\y=625 meters\\Recall: x=2500-2y\\x=2500-2(625)=1250meters[/tex]

The largest area that can be enclosed(at x=1250m,y=625m) is:

1250 X 625

=781250 Square Meters

Answer:

Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] [tex]\geq[/tex] $13.04  

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] < $13.04

Step-by-step explanation:

We are given that the mean cost of a flank steak, broccoli, and rice bought at the grocery store is $13.04.

A sample of 100 neighborhood restaurants showed a mean price of $12.65 and a standard deviation of $2 for a comparable restaurant meal.

Let [tex]\mu[/tex] = mean cost of a restaurant meal

So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] [tex]\geq[/tex] $13.04  

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] < $13.04

Here, null hypothesis states that the mean cost of a restaurant meal is more than or equal to fixing a comparable meal at home.

On the other hand, alternate hypothesis states that the mean cost of a restaurant meal is less than fixing a comparable meal at home.

The test statistics that we can use for conducting this hypothesis would be t test statistics as we don't know about population standard deviation;

                            T.S. = [tex]\frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }[/tex]  ~ [tex]t_n_-_1[/tex]

where, [tex]\bar X[/tex] = sample mean price of a restaurant meal $12.65

             s = sample standard deviation = $2

             n = sample of neighborhood restaurants = 100

The null hypothesis (H0) is that the cost of a restaurant meal is equal to or more than dining in. The alternative hypothesis (Ha) is that the restaurant meal is cheaper. If the test statistic lies in the critical region, we would then reject the null hypothesis in favor of the alternative.

To determine whether the mean cost of a restaurant meal is cheaper than fixing a similar meal at home, we have to consider hypothesis testing. In this case, the null hypothesis (H0) would be that the restaurant meal is equally or more expensive than dining in, and the alternative hypothesis (Ha) would be that the meal at the restaurant is cheaper.

H0: μ ≥ $13.04

Ha: μ < $13.04

Where μ stands for the mean cost of a restaurant meal. This hypotheses are based on a sample of 100 neighborhood restaurants with a mean price of $12.65 and a standard deviation of $2. If we get a test statistic that lies in the critical region, we could then reject the null hypothesis in favor of the alternative, thereby concluding that it is cheaper to eat at a restaurant.

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Answer:

the answer is B

Step-by-step explanation:

The expression that is equivalent to [tex](256 x^{16})^{\frac{1}{4} }[/tex] is [tex]4x^4[/tex].

The given parameters:

The given expression can be simplified by applying laws of indicial expressions as follows;

[tex](256 x^{16})^{\frac{1}{4} } = (2^8 x^{16})^{\frac{1}{4} } \\\\[/tex]

The expression can be simplified further as follows;

[tex](2^8 x^{16})^{\frac{1}{4} } = (2^8)^{\frac{1}{4} } \times (x^{16}) ^{\frac{1}{4} } = (2^2) \times (x ^4) = 4x^4\\\\[/tex]

Thus, the expression that is equivalent to [tex](256 x^{16})^{\frac{1}{4} }[/tex] is [tex]4x^4[/tex].

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Answer:

From the question 10 to 13:Hint: check Lectures 26 and 27 in the Book, the answer to the questions are, question 10 (option B), question 11 (option b), question 12 (option c), question 13 (option b)

Step-by-step explanation:

From the given question, we simulate this scenario by answering this questions.

A random experiment was carried out a Person A tossed five coins and recorded the number of "heads"., the two dice rolled and  recorded the average the two numbers was carried out by the Person B.

Then,

When a person A tossed five coins and recorded the number of heads, person B rolled two dice and recorded the smaller out of the two dice.

Question 10 : The person A is likely to get the number 5, this is so because he has a better chance to get it. the answer here is option (b) from the lectures 26 and 27 in the book.

Question 11: The person B will have higher variations in their outcomes that is higher standard deviation, because the person B is having the smaller number out of the two dice. the correct answer here is option (b) from the the lectures 26 and 27 in the book.

Question 12: The probability that a person B get the numbers 5 or 6 is 0.03. the correct answer to the question is option (C) from the the lectures 26 and 27 in the book.

Question 13: The person's that will have a higher probability number 3 or larger is Person B. correct answer to the question is option (b) from the the lectures 26 and 27 in the book.

Step-by-step explanation:

To find out the points which are 4 units apart, plot the points on the XY plot.

Another condition is that either the X or Y co-ordinates should be the same point and the other co-ordinate should vary by 4 units to satisfy the given condition in the question.

Comparing all the given points, B(3,-6) and D(3,-2) are 4 units apart.

Such that their X co=ordinate is same and Y differs by 4 units.

Therefore, Option D, (B and  D) is correct

Answer:

D

Step-by-step explanation:

Answer:

The game developer tested by 24 participants and these 24 participants were divided evenly between the treatments and the required total number of possible replications combinations is 4.

Step-by-step explanation:

The Concepts and reason

The ANOVA can be used to analyze the data obtained from experimental or observational studies. A factor is a variable that the experimenter has taken for investigation.

A treatment is a level of a factor, and its experimental units are the objects of interest in the experiment. The variation between treatments groups captures the effect of the treatment and the variation within treatment groups represents random error not explained by the experimental treatments.

The replication means an independent repeat of each factor combination.

Fundamentals

The formula for replications is: Number of participants/number of cells

The total number of participants is: 24

The number of cells is: 6

The total number of participants in the game is 24 and the number of possible combination cells is 6

so,

Number of replications: Number of participants/number of cells

which is 24/6= 4

Therefore the number of replications is 4.

In this scenario, each treatment combination of music type and interaction method would be replicated 4 times, as there are 24 participants divided evenly among six treatment groups.

The developer's experiment introduces two variables: the type of music and the method of interaction (mouse or touchpad). First, the music has 3 levels: soft, hard rock, and none. The interaction method has 2 levels: mouse and touchpad. The participants are divided evenly among the resulting combinations of these levels (3 music types x 2 interaction types = 6 groups). Given that there are 24 participants, each group would have 24 divided by 6, or 4 participants each. Thus, there would be 4 replications for each of the treatment combinations.

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Answer:

$420/5

$85 a day is Jesse's daily wage

Step-by-step explanation:

Answer:

$84

Step-by-step explanation:

$420 a week divided by 5 days per week gives $84 per day

Answer:

X is a solution of the system.

Step-by-step explanation:

To verify that the vector X is a solution of the given system:

[tex]\frac{dx}{dt}=3x-5y \\\frac{dy}{dt}=5x-7y\\X=\left(\begin{array}{c}1&1\end{array}\right)e^{-2t}[/tex]

Writing the system in the form X'=AX for some coefficient matrix A, one obtains the following.

[tex]X'=\left(\begin{array}{cc}3&-5\\5&-7\end{array}\right)X[/tex]

[tex]For\:X=\left(\begin{array}{c}1&1\end{array}\right)e^{-2t} , X'=\left(\begin{array}{c}-2&-2\end{array}\right)e^{-2t}[/tex]

Similarly:

[tex]AX=\left(\begin{array}{cc}3&-5\\5&-7\end{array}\right)\left(\begin{array}{c}1&1\end{array}\right)e^{-2t}=\left(\begin{array}{c}-2&-2\end{array}\right)e^{-2t}[/tex]

Since the above expressions are equal, [tex]X=\left(\begin{array}{c}1&1\end{array}\right)e^{-2t}[/tex] is a solution of the given system.

Final answer:

To verify that the vector X is a solution of the given system, we can substitute X into the differential equations and check if they hold true.

Explanation:

To verify that the vector X is a solution of the given system, we can substitute X into the differential equations and check if they hold true. The given system of equations is dx/dt = 3x - 5y and dy/dt = 5x - 7y. Let's substitute X = (1, 1, e^(-2t)) into these equations:

dx/dt = 3(1) - 5(1) = -2

dy/dt = 5(1) - 7(1) = -2

Since the values match, we can conclude that X = (1, 1, e^(-2t)) is a solution of the given system.

Answer: 23/111

Step-by-step explanation:

Answer:

23/111

Step-by-step explanation:

Answer:

20 yards

Step-by-step explanation:

The radius of a circle is half of the diameter

r=d/2

We know the diameter is 40 yards, so we can substitute that in

r=40/2

r=20

So, the radius is 20 yards

Answer:

96.08% probability that the average length of a randomly selected bundle of steel rods is less than 178.3-cm.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

[tex]\mu = 177.5, \sigma = 1.2, n = 7, s = \frac{1.2}{\sqrt{7}} = 0.4536[/tex]

Find the probability that the average length of a randomly selected bundle of steel rods is less than 178.3-cm.

This is the pvalue of Z when X = 178.3. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{178.3 - 177.5}{0.4536}[/tex]

[tex]Z = 1.76[/tex]

[tex]Z = 1.76[/tex] has a pvalue of 0.9608

96.08% probability that the average length of a randomly selected bundle of steel rods is less than 178.3-cm.

Answer: the probability that the average length of a randomly selected bundle of steel rods is less than 178.3-cm is 0.96

Step-by-step explanation:

Since the lengths of the steel rods are normally distributed, then according to the central limit theorem,

z = (x - µ)/(σ/√n)

Where

x = sample mean lengths of the steel rods

µ = population mean length of the steel rods

σ = standard deviation

n = number of samples

From the information given,

µ = 177.5 cm

x = 178.3 cm

σ = 1.2 cm

n = 7

the probability that the average length of a randomly selected bundle of steel rods is less than 178.3-cm is expressed as

P(x < 178.3)

Therefore,

z = (178.3 - 177.5)/(1.2/√7) = 1.76

Looking at the normal distribution table, the probability corresponding to the z score is 0.96

Therefore,

P(x < 178.3) = 0.96

Answer:

108

Step-by-step explanation:

Answer:

Step-by-step explanation:

(6)2 + 5(6) -8

12 + 30 -8

42-8

Answer=34

Answer:

58

Step-by-step explanation:

x^2 + 5x – 8

Let  x = 6

6^2 +5(6) -8

36+30-8

58

Answer:

20% robability that the tourist will be able to talk with a randomly encountered resident of the region, given that the resident speaks German

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

In this problem, we have that:

Event A: Speaking German

Event B: Speaking English

3% speak both English and German

This means that [tex]P(A \cap B) = 0.03[/tex]

15% speak German

This means that [tex]P(A) = 0.15[/tex]

So

[tex]P(B|A) = \frac{0.03}{0.15} = 0.2[/tex]

20% robability that the tourist will be able to talk with a randomly encountered resident of the region, given that the resident speaks German

Final answer:

The question touches on elements of sociology, dealing with social influence, group behavior, and persuasion as evidenced through scenarios where individuals are impacted by their group affiliations. It illustrates real-life applications of sociological principles such as persuasion in deciding on a dinner venue or peer pressure in case of vandalism.

Explanation:

The subject matter here touches upon aspects of sociology, specifically related to social influence, group behaviour, and persuasion. These examples illustrate how individuals are often influenced by the groups they belong to and how persuasive tactics can be employed by individuals within a social context. The scenarios highlight how group membership and social pressures can impact decisions, such as where to eat dinner or participating in group activities like vandalism. The statement by John Donne encapsulates the concept that no person is isolated; instead, each individual is part of a broader society, emphasizing the importance of social groups in shaping behavior and attitudes.

In the given examples, we encounter various situations where group dynamics play a role - from peer pressure to persuade Jake to hang out against his parents' wishes, to a group's collective decision about whether to dine at a particular restaurant. These are everyday applications of sociological principles, demonstrating the study of group life, group behavior, and group processes, which are key concepts in understanding how individuals behave within and are influenced by their social environment.

Answer:

x₂ = 0,59 sec

x₁  = 0,8475 sec

Step-by-step explanation:

h(t) = -16*t² + 23*t + 5

h(t) is the trajectory of the ball, the curve is a parable opens downwards

if we force h(t) = 13 feet, we get;

h(t) =  13

13 =  -16*t² + 23*t + 5   ⇒  -16*t² + 23*t - 8 = 0

or    16*t² - 23*t + 8 = 0

The above expression is a second degree equation, we proceed to solve it for t

x =  [ 23  ±  √529 - 512 ] /32

x = [ 23 ± √17 ] /32

x₁ =  [ 23 + 4,12 ]/32    ⇒  x₁  = 27,12/32    ⇒   x₁  = 0,8475 sec

x₂ =   [ 23 - 4,12 ]/32   ⇒  x₂ = 18,88 /32   ⇒   x₂ = 0,59 sec

To establish control limits for Choudhury's bowling ball factory, you need to calculate the mean weight of the balls over the observed period. The control limits are then defined as two standard deviations (0.12 pounds) above and below this mean

The subject of this question is related to quality control and statistical measures, which is a part of Mathematics. Specifically, we need to create a control chart and find the control limits based on the average weights of bowling balls produced at Choudhury's factory.

First, we need to calculate the average weight of all the bowling balls produced over the 24 day period. Then, we calculate the control limits which are two standard deviations away from this mean. The standard deviation has been given as 0.12 pounds.

Upon calculation, you'll obtain an average weight, µ. Your upper control limit (UCL) would be µ + 2*(Standard Deviation) and your lower control limit (LCL) would be µ - 2*(Standard Deviation).

Therefore, assuming your calculated average weight of all balls is µ pounds, your UCL would be µ + 2*(0.12) pounds and your LCL would be µ - 2*(0.12) pounds.

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Answer:

The probability that at least 280 of these students are smokers is 0.9664.

Step-by-step explanation:

Let the random variable X be defined as the number of students at a particular college who are smokers

The random variable X follows a Binomial distribution with parameters n = 500 and p = 0.60.

But the sample selected is too large and the probability of success is close to 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

1. np ≥ 10

2. n(1 - p) ≥ 10

Check the conditions as follows:

 [tex]np=500\times 0.60=300>10\\n(1-p)=500\times(1-0.60)=200>10[/tex]

Thus, a Normal approximation to binomial can be applied.

So,  

[tex]X\sim N(\mu=600, \sigma=\sqrt{120})[/tex]

Compute the probability that at least 280 of these students are smokers as follows:

Apply continuity correction:

P (X ≥ 280) = P (X > 280 + 0.50)

                   = P (X > 280.50)

                   [tex]=P(\frac{X-\mu}{\sigma}>\frac{280-300}{\sqrt{120}}\\=P(Z>-1.83)\\=P(Z<1.83)\\=0.96638\\\approx 0.9664[/tex]

*Use a z-table for the probability.

Thus, the probability that at least 280 of these students are smokers is 0.9664.

The probability of a minimum of 280 students being radio listeners would be:

0.9664

The standard deviation is a statistic that measures the dispersion of a dataset relative to its mean and is calculated as the square root of the variance in statistics.

So, the formula is,

[tex]SD=\sqrt{\sigma}[/tex]

Suppose it is known that 60% of students at a college are smokers.

A sample of 500 students from the college is selected at random.

[tex]mean=np\\=500\times 0.6\\=300[/tex]

The standard deviation is,

[tex]S=\sqrt{np(1-p)}\\ =\sqrt{500\times 0.6\times 0.4}\\ =10.95445[/tex]

So, the probability is,

[tex]P(X > 280)=\frac{P(x-mean)}{s} \\=\frac{280-300}{10.95445} \\=0.9664[/tex]

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Answer:

E(Y) = $0.5

Var(Y)  = 14.25

you should pay the same amount  $0.5

Step-by-step explanation:

E(Y) =  = Σ(YP)

P = probability of each outcomes.

Var(Y) = Σ[tex]Y^{2}[/tex]p − (μ x μ)

E(Y) = (2 x 0.25) +(6 x 0.25) + (0.5 x (-3)) = $0.5

Var(Y) = ([tex]2^{2}\\[/tex]x 0.25) + ([tex]6^{2}[/tex] x 0.25) +([tex]-3^{2}[/tex] x 0.5) - ([tex]0.5^{2}[/tex])

       = 14.5 - 0.25

Var(Y)  = 14.25

for the difference between the payoff and cost of playing to have mean 0, you should pay the same amount  $0.5

The mean of your winnings in this coin tossing game is $0.50 and the variance is $3.75. To break even on average, the cost of playing the game should be $0.50.

To calculate the mean and variance of your winnings in this coin tossing game, we first need to compute the expected value and probabilities of each outcome.

Both coins coming up heads (HH) or tails (TT) each have a probability of 0.25 (1/2 * 1/2), while the coins not matching (HT or TH) has a probability 0.5.

The expected winnings, E(Y), can be calculated using the formula E(Y) = (sum of (value x probability)).

So, E(Y) = $2(0.25) + $6(0.25) + (-$3)(0.50) = $0.50 + $1.50 - $1.50 = $0.50.

The variance can be calculated using the formula Var(Y) = E(Y^2) - [E(Y)]^2.

First, find E(Y^2) = ($2^2x0.25) + ($6^2x0.25) + ((-$3)^2x0.50) = $4. Then, calculate [E(Y)]^2 = ($0.50)^2 = $0.25. Substituting in the formula gives Var(Y) = $4 - $0.25 = $3.75.

If your net winnings are to have mean 0, the cost of playing the game should be equivalent to the expected winnings, which is $0.50.

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Answer:

30

Step-by-step explanation:

Answer:

We conclude that the Redwood trees have an average height greater than 240 feet.

Step-by-step explanation:

We are given that a random sample of 47 California Redwood trees was taken and their heights measured. The sample mean average height was 248 feet with a standard deviation of 26 feet.

We have to test the claim that Redwood trees have an average height greater than 240 feet.

Let [tex]\mu[/tex] = mean weight bag filling capacity of machine.

SO, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] [tex]\leq[/tex] 240 feet   {means that the Redwood trees have an average height smaller than or equal to 240 feet}

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] > 240 feet   {means that the Redwood trees have an average height greater than 240 feet}

The test statistics that will be used here is One-sample t test statistics as we don't know about the population standard deviation;

                        T.S.  = [tex]\frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }[/tex]  ~ [tex]t_n_-_1[/tex]

where, [tex]\bar X[/tex] = sample mean average height = 248 feet

             s = sample standard deviation = 26 feet

             n = sample of trees = 47

So, test statistics  =  [tex]\frac{248-240}{\frac{26}{\sqrt{47} } }[/tex]  ~ [tex]t_4_6[/tex]   

                               =  2.109

Now at 5% significance level, the t table gives critical value of 1.6792 at 46 degree of freedom for right-tailed test. Since our test statistics is higher than the critical value of t as 2.109 > 1.6792, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the Redwood trees have an average height greater than 240 feet.

Answer:

a

Step-by-step explanation:

first multiply 9*6.5*.5 for the triangle

Then multiply 9*4.5

Then add up to get 69.75

Answer:

a is your answer

Step-by-step explanation:

[tex]7x^{2} +33x-10=0[/tex]

[tex]\implies 7x^{2} +35x-2x-10=0\\\implies7x(x+5)-2(x+5)=0\\\implies (7x-2)(x+5)=0[/tex]

[tex]7x - 2 = 0\\\implies \boxed{\bold{x = \frac{2}{7} }}[/tex]

[tex]x+5=0\\\implies \boxed{\bold{x=-5}}[/tex]

Answer:

P(X>4)= 0.624

Step-by-step explanation:

n = 10

p= 0.5 ,q= 1 - p = 0.5

Two fifth of 10 = 2/5 x 10 =4

It means that we have to find probability P(X>4).

P(X>4)= 1 -P(X=0)-P(X=1)-P(X=2)-P(X=3)-P(X=4)

We know that

P(X>4)= 1 -P(X=0)-P(X=1)-P(X=2)-P(X=3)-P(X=4)

P(X>4)= 1 -0.0009 - 0.0097 - 0.043 - 0.117-0.205

The probability that more than 12 of the entry forms will include an order is 0.624.

It is defined as the ratio of the number of favorable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.

We have:

The Magazine Mass Marketing Company has received 16 entries in its latest sweepstakes.

The probability that more than 12 of the entry forms will include an order can be found as:

P(X > 4) = 1 - P(X = 0) - P(X = 1) - P(X = 2) - P( X = 3) - P(X = 4)

P(X > 4) = 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3) - P(X = 4)

P(X > 4) = 1 - 0.0009 - 0.0097 - 0.043 - 0.117 - 0.205

P(X > 4) =  0.624

Thus, the probability that more than 12 of the entry forms will include order is 0.624.

Learn more about the probability here:

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Tony can get 12 combined outcomes when he throws a dice and a coin, which are combinations of six numbers (1-6) of the dice and two possible outcomes of the currency (heads or tails).

In the given scenario, Tony is throwing a dice and a coin. The dice can land on any number from 1 to 6, and the coin can land on either heads (H) or tails (T). The combined outcomes can be listed as follows:

So, there are a total of 12 possible outcomes.

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The possible outcomes of throwing a dice and flipping a coin are listed. The format is [Dice number][Coin result].

The outcomes of Tony throwing the dice once and throwing a coin to get heads or tails are:

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Answer:

The value of the coefficient of determination is 0.263 or 26.3%.

Step-by-step explanation:

R-squared is a statistical quantity that measures, just how near the values are to the fitted regression line. It is also known as the coefficient of determination.

A high R² value or an R² value approaching 1.0 would indicate a high degree of explanatory power.

The R-squared value is usually taken as “the percentage of dissimilarity in one variable explained by the other variable,” or “the percentage of dissimilarity shared between the two variables.”

The R² value is the square of the correlation coefficient.

The correlation coefficient between heights​ (in inches) and weights​ (in lb) of 40 randomly selected men is:

r = 0.513.

Compute the value of the coefficient of determination as follows:

[tex]R^{2}=(r)^{2}\\=(0.513)^{2}\\=0.263169\\\approx0.263[/tex]

Thus, the value of the coefficient of determination is 0.263 or 26.3%.

This implies that the percentage of variation in the variable height explained by the variable weight is 26.3%.

Answer:

1 Gallon is equal to 4 quarts. To convert gallons to quarts, multiply the gallon value by 4.

Step-by-step explanation:

Answer:

divide the quart value by 4 and than multiply it by o.25