A horizontal 100-mm-diameter pipe passing hot oil is to be used in the design of an industrial water heater. Based on a typical water draw rate, the velocity of the water over the pipe is 0.5 m/s. the hot oil maintains the outer surface of the pipe at 85 °C and the water temperature is 37 °C. Investigate the effect of water flow direction on the heat rate (W/m) for (a) horizontal, (b) downward, and (c) upward flow.

Answer:

The result seem reasonable.

Explanation:

Relative density shows us how heavy a substance is in comparison to water.It aids us in determine the density of an unknown substance by knowing the density of a known substance. Relative density is defined as the ratio of the density (mass of a unit volume) of a substance to the density of a given reference material. It is very important in the accurate determination of density.

Relative density= emax - e/emax - emin× 100

Relative density ranges between 35 and 65 because the soil is in medium state.

For well graveled sand, maximum friction angle is uo^r

and for minimum friction angle, minimum friction angle is 33°.

Therefore, for given friction angle of 31° (shear strength criteria). This result seem reasonable.

Therefore, it is worthy to note that if friction angle is more, the shear strength is more which implies that it is a densified soil, that is to say, void ratio decreases.

Answer:

d/dt[mCp(Ts-Ti)] =  FCp(Ts-Ti) -  FoCp(Ts-Ti) + uA(Ts-Ti)

Explanation:

Differential balance equation on the tank is given as;

Accumulation = d/dt[mcp(Ts-Ti)]

Energy of inlet steam = FCp(Ts-Ti)

Energy of outlet steam =  FoCp(Ts-Ti)

Heat transfer from the steam = uA(Ts-Ti)

Substituting into the formula, we have;

The differential energy balance is [tex]\(\frac{dT}{dt} = \frac{11.5 T_s + 690 - 39.1 T}{1748}\).[/tex]

To write a differential energy balance on the tank contents, we need to consider the energy entering and leaving the system. The system in question is the well-stirred heating tank. Here are the steps to formulate the energy balance:

1. Define the system and parameters:

  - The solvent enters the tank at a flow rate of 12.0 kg/min and at a temperature of 25°C.

  - The solvent has a heat capacity  [tex]\( C_p = 2.30 \text{ kJ/kg°C} \).[/tex]

  - The tank is initially filled with 760 kg of solvent at 25°C.

  - Heat transfer rate from the steam coil to the solvent is given by

[tex]\( UA(T_s - T) \)[/tex]  where  [tex]\( UA = 11.5 \text{ kJ/min·°C} \), \( T_s \)[/tex]   is the steam temperature, and ( T ) is the solvent temperature.

  - The tank is well-stirred, ensuring uniform temperature throughout, and the outlet temperature equals the tank temperature.

2. Energy balance:

  The energy balance for a well-stirred tank in differential form is given by:

[tex]\[ \frac{d(U)}{dt} = \dot{Q}_{\text{in}} + \dot{m} C_p T_{\text{in}} - \dot{m} C_p T_{\text{out}} \][/tex]

  Where:

  - ( U ) is the internal energy of the tank contents.

[tex]- \( \dot{Q}_{\text{in}} \)[/tex]  is the heat transfer rate from the steam coil.

[tex]- \( \dot{m} \)[/tex]  is the mass flow rate of the solvent.

[tex]- \( T_{\text{in}} \)[/tex] is the inlet temperature of the solvent.

[tex]- \( T_{\text{out}} \)[/tex] of the solvent (equal to tank temperature ( T ).

  Since  [tex]\( \dot{m}_{\text{in}} = \dot{m}_{\text{out}} = \dot{m} \) and \( T_{\text{out}} = T \):[/tex]

 [tex]\[ \frac{d(U)}{dt} = UA(T_s - T) + \dot{m} C_p (T_{\text{in}} - T) \][/tex]

3. Internal energy change:

  The internal energy change of the tank contents can be expressed as:

  [tex]\[ \frac{d(U)}{dt} = m C_p \frac{dT}{dt} \][/tex]

  Where ( m ) is the mass of the solvent in the tank (760 kg) and ( T ) is the solvent temperature in the tank.

4. Combine the equations:

  Substituting  [tex]\( \frac{d(U)}{dt} = m C_p \frac{dT}{dt} \)[/tex] into the energy balance:

[tex]\[ m C_p \frac{dT}{dt} = UA(T_s - T) + \dot{m} C_p (T_{\text{in}} - T) \][/tex]

5. Simplify the equation:

  Substitute the given values:

[tex]- \( m = 760 \text{ kg} \)\\ - \( C_p = 2.30 \text{ kJ/kg°C} \)\\ - \( \dot{m} = 12.0 \text{ kg/min} \) - \( UA = 11.5 \text{ kJ/min·°C} \)\\ - \( T_{\text{in}} = 25 \text{ °C} \)[/tex]

[tex]\[ 760 \cdot 2.30 \frac{dT}{dt} = 11.5 (T_s - T) + 12.0 \cdot 2.30 (25 - T) \][/tex]

  Simplify to:

  [tex]\frac{dT}{dt} = 11.5 (T_s - T) + 27.6 (25 - T) \]\[ 1748[/tex]

  Further simplify:

[tex]\[ 1748 \frac{dT}{dt} = 11.5 T_s - 11.5 T + 690 - 27.6 T \][/tex]

  Combine like terms:

 [tex]\[ 1748 \frac{dT}{dt} = 11.5 T_s + 690 - 39.1 T \][/tex]

  Finally:

[tex]\[ \frac{dT}{dt} = \frac{11.5 T_s + 690 - 39.1 T}{1748} \][/tex]

This is the differential energy balance equation for the tank contents.

Answer:

Q = 2450 KJ/day

Explanation:

We are given;

The amount of moisture produced by a person while taking shower; m = 0.25 kg/person

Total number of persons in the family; N = 4

Latent heat of vaporization of water:

h_fg = 2450 KJ/kg

Since amount of moisture per person is 0.25kg per day,thus for 4 people, total mass; m_total = 4 x 0.25 = 1 kg per day

The formula for the amount of latent heat added to the space due to shower per day, is given as;

Q = m_total x h_fg

Plugging in the relevant values;

Q = 1 x 2450 = 2450 KJ/day

Answer:

a) [tex]Re = \frac{4\cdot \rho \cdot Q}{\pi\cdot \mu\cdot D}[/tex], b) [tex]Re = \frac{4\cdot \dot m}{\pi\cdot \mu\cdot D}[/tex], c) 1600

Explanation:

a) The Reynolds Number is modelled after the following formula:

[tex]Re = \frac{\rho \cdot v \cdot D}{\mu}[/tex]

Where:

[tex]\rho[/tex] - Fluid density.

[tex]\mu[/tex] - Dynamics viscosity.

[tex]D[/tex] - Diameter of the tube.

[tex]v[/tex] - Fluid speed.

The formula can be expanded as follows:

[tex]Re = \frac{\rho \cdot \frac{4Q}{\pi\cdot D^{2}}\cdot D }{\mu}[/tex]

[tex]Re = \frac{4\cdot \rho \cdot Q}{\pi\cdot \mu\cdot D}[/tex]

b) The Reynolds Number has this alternative form:

[tex]Re = \frac{4\cdot \dot m}{\pi\cdot \mu\cdot D}[/tex]

c) Since the diameter is the same than original tube, the Reynolds number is 1600.

Answer:

(a) Precipitation hardening

(1) The strengthening mechanism involves the hindering of dislocation motion by precipitates/particles.

(2) The hardening/strengthening effect is not retained at elevated temperatures for this process.

(4) The strength is developed by a heat treatment.  

(b) Dispersion strengthening

(1) The strengthening mechanism involves the hindering of dislocation motion by precipitates/particles.  

(3) The hardening/strengthening effect is retained at elevated temperatures for this process.

(5) The strength is developed without a heat treatment.  

Answer:

Explanation:

r=72.3 is my thought

I hope it is helpful

Answer:

Maximum number of vehicle = 308

Explanation:

See the attached file for the calculation.

Answer:

inform the readers about Diane and her unusual job.

Explanation:

The purpose of Lorraine Jean Hopping's viewpoint in "Bone Detective" is just to inform the readers about Diane as a person and how what she does has really helped people even though her job was really unusual. It was mainly for the purpose of passing information across to the readers and nothing else.

Answer:

Explanation:she is trying to inform you hope it helps

Answer:

c.if the flow is laminar it could become turbulent.

Explanation:

The Reynolds number (Re) is a dimensionless quantity used to help predict flow patterns in different fluid flow situations. At low Reynolds numbers of below 2300 flows tend to be dominated by laminar, while at high Reynolds numbers above 4000, turbulence results from differences in the fluid's speed and direction. In between these values is the transition region of flow.

In practice, fluid flow is generally chaotic, and very small changes to shape and surface roughness of bounding surfaces can result in very different flows.

Thermodynamic calculations for mass flow rate, compressor power, and coefficient of performance of a heat pump require refrigerant property data, which is not provided in the question. An energy balance and compressor efficiency adjustment are also essential for accurate calculations.

To calculate the properties of the heat pump using refrigerant 134a and determine the refrigerant mass flow rate, compressor power, and coefficient of performance, we need to make use of thermodynamic equations and refrigerant property data under the given conditions (such as pressures and phase states).Normally, these calculations would involve using a thermodynamic properties table or software to find enthalpies for the refrigerant at the specified conditions. An energy balance would be applied around the compressor and condenser. The work done by the compressor can be calculated using the enthalpy values before and after the compressor and assuming an isentropic process initially, and then adjusting for the non-ideal compressor efficiency of 75% in the revised calculation.For the coefficient of performance (COP) of the heat pump, it is calculated as the ratio of heat output to work input for the heating mode. The provided heat output is given here as 35 kW. For ideal conditions, the COP can be calculated without the compressor efficiency factor; for the revised COP with a 75% efficient compressor, this factor is taken into account.Unfortunately, without the enthalpy values or additional data, it is not possible to provide the numerical answers to the student's question.

Answer:

a) The temperature of evaporation is -10.09°C

The temperature of condensation is 35.53°C

b) The mass flow of the refrigerant is 0.149 kg/s

c) The COP is 3.65

d) The new COP is 4.05

Explanation:

please look at the solution in the attached Word file

Answer:

Explanation:

Arbitrary means That no restrictions where placed on the number rather still each number is finite and has finite length. For the answer to the question--

Find(A,n,i)

for j =0 to 10000 do

frequency[j]=0

for j=1 to n do

frequency[A[j]]= frequency[A[j]]+1

for j =1 to n do

if i>=A[j] then

if (i-A[j])!=A[j] and frequency[i-A[j]]>0 then

return true

else if (i-A[j])==A[j] and frequency[j-A[j]]>1 then

return true

else

if (A[j]-i)!=A[j] and frequency[A[j]-i]>0 then

return true

else if (A[j]-i)==A[j] and frequency[A[j]-i]>1 then

return true

return false

The couplings are not all on the same axis or plane, but if the A and B connector were to be described, it would travel with a magnitude of roughly 15 by the yz axis diagonal to the x axis. The axis would be oriented so that it was pointing upward into the second quadrant.

In terms of physics, magnitude is just "distance or quantity." It displays an object's size, direction, or motion in absolute or relative terms. It is employed to indicate the size or scope of something.

In physics, the term "magnitude" often refers to a size or amount. Magnitude is defined as "how much of a quantity." The magnitude can be used, for instance, to compare the speeds of a car and a bicycle.

It can also be used to indicate how far something has come or how much something weighs relative to its size.

Thus, The couplings are not all on the same axis or plane.

For more details about magnitude, click here:

https://brainly.com/question/14452091

#SPJ2

Answer:

15.53 m2

Explanation:

Energy needed = 23.8 kW-hr

Solar intensity of required panel = 336 W/m2

Efficiency of panels = 19%

Power needed = 23.8kW-hr = 23800 W-h,

In one day there are 24 hr, therefore power required = 23800/24 = 991.67 W

991.67 = 19% of incident power

991.67 = 0.19x

x = incident power = 991.67/0.19 = 5219.32 W

Surface area required = 5219.32/336

= 15.53 m2

To determine the relative humidity of the mixed air stream based on the information provided, one would typically use a psychrometric chart or other moist air property calculations. Without access to the required psychrometric data or tables to reference, an accurate calculation cannot be provided here, but principles of moist air mixing and conservation of mass for the water vapor can guide the process.

To determine the relative humidity and temperature of the exiting stream in the mixing chamber problem, we need to use the principles of thermodynamics specifically relating to moist air properties. This requires using a psychrometric chart or similar calculation methods to find the properties of the mixed air stream. The information provided in the initial question about the temperatures, pressures, and humidities of the incoming air streams is used along with conservation of mass and energy principles.

However, as a tutor on Brainly, I do not have access to the necessary tables or psychrometric data through this platform, which are required to calculate the final relative humidity of the exiting stream. Such data typically includes saturation pressure, saturation temperature, and specific enthalpy of the air-water mixture at various conditions.

To solve the problem accurately, you would need to reference the appropriate psychrometric chart or software at the specific temperatures given in the question. Assuming the total pressure remains constant and using the principle of the conservation of mass for the water vapor, the mixing ratio of the incoming streams can be used to determine the mixing ratio of the outgoing stream. Then, with the final temperature known, you could identify the corresponding saturation mixing ratio and use it to calculate the relative humidity.

If we assume that the mass flow rates of both streams are equal, we can consider that the exiting air stream will be a mixture of the two streams. Given the final exit temperature of 17°C, we could interpolate between the saturation mixing ratios at the temperatures given for the two streams to estimate the relative humidity, but a more precise result would come from detailed calculations or a psychrometric chart.

Answer:

a) k = 6.4 s/cm²

b) Te = 160 s

Explanation:

a) Given

Solidification time in s: Te = 160 s

L = 50 mm = 5 cm

We use the formula

Te = k*(V/A)ⁿ  

k = Te*(A/V)ⁿ

where

k is the Chvorinov's mold constant

V is casting volume in cm³ = V = L³ = (5 cm)³ = 125 cm³

A is the surface area of the casting in cm² = A = L² = (5 cm)² = 25 cm²

n = 2 (assumed)

⇒  k = 160 s*(25 cm²/125 cm³)²

⇒  k = 6.4 s/cm²

b) Given

D = 25 mm = 2.5 cm  ⇒  R = D/2 = 2.5 cm/2 = 1.25 cm

h = 50 mm = 5 cm

k = 6.4 s/cm²

n = 2

We find the volume as follows

V = π*R²*h ⇒   V = π*(1.25 cm)²*(5 cm) = 24.5436 cm³

and the surface area

A = π*R² = π*(1.25 cm)² = 4.9087 cm²

We apply the equation

Te = k*(V/A)ⁿ  

⇒  Te = (6.4 s/cm²)*(24.5436 cm³/4.9087 cm²)²

⇒  Te = 160 s

Answer:

1.443hrs

Explanation:

Please kindly check attachment for the detailed and step by step solution to the problem.

Answer:

(a) [tex]G(s) = \frac{i_{out(s)}}{v_{in}(s)} = \frac{2S}{S^2+4S+4}[/tex]

(b) see plot in the attached explanation.

(c) [tex]i_{out}(t) = 0.2 Cos(10t-63)[/tex]

Explanation:

See attached solution a to c

Answer:

18.6h

Explanation:

To solve this Duck's second law in form of Diffusion will be used.

Also note that since the temperature is constant D (change) will also be constant.

Please go through the attached files for further explanation and how the answer Is gotten.

Answer:

radius = 9.1 × [tex]10^{-3}[/tex] m

Explanation:

given data

applied load = 5560 N

flexural strength = 105 MPa

separation between the support =  45 mm

solution

we apply here minimum radius formula that is

radius = [tex]\sqrt[3]{\frac{FL}{\sigma \pi}}[/tex]      .................1

here F is applied load and  is length

put here value and we get

radius =  [tex]\sqrt[3]{\frac{5560\times 45\times 10^{-3}}{105 \times 10^6 \pi}}[/tex]  

solve it we get

radius = 9.1 × [tex]10^{-3}[/tex] m

Answer:

1. Maximum flow = 0.7768 L/s

2. The flow would reduced if other faucets were open. This is due to increase pipe flow and frictional resistance between the water main and the faucets.

Explanation:

See the attached file for the calculation.

Answer:

q₀ = 350,740.2885 N/m

Explanation:

Given

[tex]q(x)=\frac{x}{L} q_{0}[/tex]

σ = 120 MPa = 120*10⁶ Pa

[tex]L=4 m\\w=200 mm=0.2m\\h=300 mm=0.3m\\q_{0}=? \\[/tex]

We can see the pic shown in order to understand the question.

We apply

∑MB = 0  (Counterclockwise is the positive rotation direction)

⇒ - Av*L + (q₀*L/2)*(L/3) = 0

⇒ Av = q₀*L/6   (↑)

Then, we apply

[tex]v(x)=\int\limits^L_0 {q(x)} \, dx\\v(x)=-\frac{q_{0}}{2L} x^{2}+\frac{q_{0} L}{6} \\M(x)=\int\limits^L_0 {v(x)} \, dx=-\frac{q_{0}}{6L} x^{3}+\frac{q_{0} L}{6}x[/tex]

Then, we can get the maximum bending moment as follows

[tex]M'(x)=0\\ (-\frac{q_{0}}{6L} x^{3}+\frac{q_{0} L}{6}x)'=0\\ -\frac{q_{0}}{2L} x^{2}+\frac{q_{0} L}{6}=0\\x^{2} =\frac{L^{2}}{3}\\ x=\sqrt{\frac{L^{2}}{3}} =\frac{L}{\sqrt{3} }=\frac{4}{\sqrt{3} }m[/tex]

then we get  

[tex]M(\frac{4}{\sqrt{3} })=-\frac{q_{0}}{6*4} (\frac{4}{\sqrt{3} })^{3}+\frac{q_{0} *4}{6}(\frac{4}{\sqrt{3} })\\ M(\frac{4}{\sqrt{3} })=-\frac{8}{9\sqrt{3} } q_{0} +\frac{8}{3\sqrt{3} } q_{0}=\frac{16}{9\sqrt{3} } q_{0}m^{2}[/tex]

We get the inertia as follows

[tex]I=\frac{w*h^{3} }{12} \\ I=\frac{0.2m*(0.3m)^{3} }{12}=4.5*10^{-4}m^{4}[/tex]

We use the formula

σ = M*y/I

⇒ M = σ*I/y

where

[tex]y=\frac{h}{2} =\frac{0.3m}{2}=0.15m[/tex]

If M = Mmax, we have

[tex](\frac{16}{9\sqrt{3} }m^{2} ) q_{0}\leq \frac{120*10^{6}Pa*4.5*10^{-4}m^{4} }{0.15m}\\ q_{0}\leq 350,740.2885\frac{N}{m}[/tex]

Answer:

175.5 mm

Explanation:

a hollow shaft of diameter ratio 3/8 is required to transmit 600kw at 110 rpm, the maximum torque being 20% greater than the mean. the shear stress is not to exceed 63 mpa and twist in a length of 3 meters not t exeed 1.4 degrees Calculate the minimum external diameter satisfying these conditions. G = 80 GPa

Let

D = external diameter of shaft

Given that:

d = internal diameter of the shaft = 3/8 × D = 0.375D,

Power (P) = 600 Kw, Speed (N) = 110 rpm, Shear stress (τ) = 63 MPa = 63 × 10⁶ Pa, Angle of twist (θ) = 1.4⁰, length (l) = 3 m, G = 80 GPa = 80 × 10⁹ Pa

The torque (T) is given by the equation:

[tex]T=\frac{60 *P}{2\pi N}\\ Substituting:\\T=\frac{60*600*10^3}{2\pi*110} =52087Nm[/tex]

The maximum torque ([tex]T_{max[/tex]) = 1.2T = 1.2 × 52087 =62504 Nm

Using Torsion equation:

[tex]\frac{T}{J} =\frac{\tau}{R}\\ J=\frac{T.R}{\tau} \\\frac{\pi}{32}[D^4-(0.375D)^4]=\frac{62504*D}{2(63*10^6)} \\D^3(0.9473)=0.00505\\D=0.1727m=172.7mm[/tex]

[tex]\theta=1.4^0=\frac{1.4*\pi}{180}rad[/tex]

From the torsion equation:

[tex]\frac{T}{J} =\frac{G\theta }{l}\\ J=\frac{T.l}{G\theta} \\\frac{\pi}{32}[D^4-(0.375D)^4]=\frac{62504*3}{84*10^9*\frac{1.4*\pi}{180} } \\D=0.1755m=175.5mm[/tex]

The conditions would be satisfied if the external diameter is 175.5 mm

Answer:

// This program is written in C++ programming language

// Comments are used for explanatory purpose

/* The aim of this program is to to remove all the white space,digits, punctuation, and other special characters, leaving only the letters. */

// Program starts here

#include <stdio.h>

#include<iostream>

using namespace std;

int main()

{

// Declare Variable of 100 characters

char word[100];

// Prompt user for input

cout<<"Your input goes here (max, 100 characters)";

cin>>word;

// Iterate through string to check for non alphabetic characters

for (int i = 0; word[i] != '\0'; ++i) {

// Check for uppercase and lowercase letters

while (!((word[i] >= 'a' && word[i] <= 'z') || (word[i] >= 'A' && word[i] <= 'Z') || word[i] == '\0')) {

for (int j = i; word[j] != '\0'; ++j) {

word[j] = word[j + 1];

}

word[j] = '\0';

}

}

cout<<"The resulting compressed string: "<<word;

return 0;

}

Answer:

w = str(input("input your values: "))

values = ' '.join(filter(str.isalpha, w))

while len(w) < 100:

       print(values)

       break

Explanation:

The code is written in python

w = str(input("input your values: "))

This code ask the user to input any string values with characters, numbers, line spaces , letters etc.

values = ' '.join(filter(str.isalpha, w))

This code filters the inputted value to bring only letters. All the letter are then joined together

while len(w) < 100:

The code check if the inputted value is less than 100 characters. While it is less than 100 characters. If it is less than 100 character the next code will function.

print(values)

This code prints the joined letters after checking with  a while loop to confirm the length of character is less than 100

break

The break function breaks the code whether it print the values or not.

Generally, the letters will only be printed if the character inputted is less than 100 and later break the while loop or will not print any letter if the character is greater than 100 and later break.

Answer:

c. can destablize the slopes by increasing pore fluid pressure.

Explanation: A reservoir is a term used in Agriculture or geography to describe a location where water is either collected artificially or naturally for later use in farming or to act as dam for the supply of water in large communities. Most countries of the world make use of reservoirs to store water for future use.

To find the maximum velocity at section (1) in a two-dimensional reducing bend with a linear velocity profile, apply the principle of conservation of mass and the equation Q = Av. The maximum velocity, V1,max, occurs at section (1) where the cross-sectional area is the smallest.

To find the maximum velocity, V1,max, at section (1) in a two-dimensional reducing bend with a linear velocity profile at section (1), we can apply the principle of conservation of mass. As the cross-sectional area decreases, the velocity increases to maintain constant flow rate. At section (1), the velocity is maximum due to the smallest area.

Using the equation Q = Av, where Q is the flow rate, A is the cross-sectional area, and v is the velocity, we can determine the maximum velocity at section (1). The maximum velocity, V1,max, occurs at section (1) where the cross-sectional area is the smallest, resulting in the highest velocity to maintain flow rate continuity.

The following code or the program will be used:

Explanation:

import java.util.Scanner;

public class Authenticate

{

public static void main(String[] args)

{

// Actual password is 99508

int[] actual_password = {9, 9, 5, 0, 8};

// Array to hold randomly generated digits

int[] random_nums = new int[10];

// Array to hold the digits entered by the user to authenticate

int[] entered_digits = new int[actual_password.length];

// Randomly generate numbers from 1-3 for

// for each digit

for (int i=0; i < 10; i++)

{

random_nums[i] = (int) (Math.random() * 3) + 1;

}

// Output the challenge

System.out.println("Welcome! To log in, enter the random digits from 1-3 that");

System.out.println("correspond to your PIN number.");

System.out.println();

System.out.println("PIN digit: 0 1 2 3 4 5 6 7 8 9");

System.out.print("Random #: ");

for (int i=0; i<10; i++)

{

System.out.print(random_nums[i] + " ");

}

System.out.println();

System.out.println();

// Input the user's entry

Scanner keyboard = new Scanner(System.in);

System.out.println("Enter code.");

String s = keyboard.next();

String s = keyboard.next();

// Extract the digits from the code and store in the entered_digits array

for (int i=0; i<s.length(); i++)

{

entered_digits[i] = s.charAt(i) - '0'; // Convert char to corresponding digit

}

// At this point, if the user typed 12443 then

// entered_digits[0] = 1, entered_digits[1] = 2, entered_digits[2] = 4,

// entered_digits[3] = 4, and entered_digits[4] = 3

/****

TO DO: fill in the parenthesis for the if statement

so the isValid method is invoked, sending in the arrays

actual_password, entered_digits, and random_nums as

parameters

***/

if (isValid (actual_password, entered_digits, random_nums)) // FILL IN HERE

{

System.out.println("Correct! You may now proceed.");

}

else

{

System.out.println("Error, invalid password entered.");

}

/***

TO DO: Fill in the body of this method so it returns true

if a valid password response is entered, and false otherwise.

For example, if:

actual = {9,9,5,0,8}

randnums = {1,2,3,1,2,3,1,2,3,1}

then this should return true if:

entered[0] == 1 (actual[0] = 9 -> randnums[9] -> 1)

entered[1] == 1 (actual[1] = 9 -> randnums[9] -> 1)

entered[2] == 3 (actual[2] = 5 -> randnums[5] -> 3)

entered[3] == 1 (actual[3] = 0 -> randnums[0] -> 1)

entered[4] == 3 (actual[4] = 8 -> randnums[8] -> 3)

or in other words, the method should return false if any of

the above are not equal.

****/

public static boolean isValid(int[] actual, int[] entered, int[] randnums)

{

int Index = 0;

boolean Valid = true;

while (Valid && (Index < actual.length))

{

int Code = actual[Index];

if (entered [Index] != randnums [Code])

{

Valid = false;

}

Index++;

}

return Valid;

}

Answer:

See Explaination

Explanation:

#include <stdio.h>

int main(void)

{

const double G = 6.673e-11;

const double M = 5.98e24;

double accelGravity = 0.0;

double distCenter = 0.0;

distCenter = 6.38e6;

//<StudentCode>

accelGravity = (G * M) / (distCenter * distCenter);

printf("accelGravity: %lf\n", accelGravity);

return 0;

}

Answer:

See explaination

Explanation:

In recent times and in the past, so many companies have been dealt with or bankrupted by disaster.

This disasters are in the form of floods, earthquake and tsunami. This has led to many companies across world to have faced problem. As Japan is particularly vulnerable to natural disaster because of its climate and topography let me take example of japan .The tsunami that struck Japan in March this year which has lead to a debt of worth nearly $8 billion due to failed businesses. A total of 341 firms in japan with a combined 6,376 employees has got affected by this disaster.

One of company that hit hard by these disaster is Toyota. Toyota is a Japanese multinational automotive manufacturer headquartered in Toyota, Aichi, Japan. Actually due to flood in thailand toyota has faced a big loss. As flood hit thailand the parts of vehicle which is produced in thailand has stopped . It leads to interruption in the supply chain of some Thailand made components.

This lead to suspension of production as thai made component was unavailable.It has been reported until the situation of thailand will be good toyota plants in Indiana, Kentucky and Ontario, Canada, will be shut down . And production rate at plant in North America will get slow down .This flood leads to a loss of 37500 vehicles .Due to this reason toyota was forced to open its plants in Southeast asian country just to enhance the production rate.Sales of vehicle has also got reduced in thailand . Hence toyota faced a total loss of 1.6 billion dollar.

In Nigeria, due to the insurgency of the Boko Haram, many companies have entirely stopped operations in some regions, this harsh realities leads to massive loss of revenue for such companies.