Answer:
460 ohms
Explanation:
Resistance=Voltage/Current
=115/0.25=460
The resistance of the lamp can be calculated using Ohm's law, which states that resistance is equal to voltage divided by current. In this case, the resistance of the lamp is 460 ohms.
Explanation:To find the resistance of a lamp, we can use Ohm's law, which states that resistance is equal to voltage divided by current.
R = V/I
From the given information, the voltage is 115 volts and the current is 0.25 amperes. Plugging these values into the equation, we get:
R = 115 V / 0.25 A = 460 ohms
Therefore, the lamp's resistance is 460 ohms.
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Use the drop-down menus to complete the sentences. A is a seasonal wind___that blows in the opposite direction of normal winds. A wind___ is a wind that blows mainly from a single general direction. Seasonal winds that blow in the opposite direction of normal winds often cause____ in the winter.
The following sentences are completed and explained below
Explanation:
A is a seasonal wind known as monsoon wind that blows in the opposite direction of normal winds.
Prevailing winds are the wind that blows mainly from a single general direction.
Seasonal winds that blow in the opposite direction of normal winds often cause drought in the winter.
The monsoon winds are seasonal winds that refers to wind systems that have a pronounced seasonal reversal of direction.
The winds that blow from single direction over a specific area of the earth is known as prevailing winds.
1. Monsoon wind: a seasonal wind that blows in the opposite direction of normal winds.
2. Prevailing wind: it is a wind that blows mainly from a single (one) general direction.
3. Seasonal winds that blow in the opposite direction of normal winds often cause drought in the winter.
A wind can be defined as the natural movement of air and its constituent gases blowing in a particular with respect to a planet's surface.
Based on the location of occurrence and periodicity, winds are classified into three (3) main categories and these are:
1. Local winds: these include bora, foehn, loo, mistral, etc.
2. Secondary winds: these include mountain and valley breeze, monsoon wind, etc.
3. Primary winds: polar easterlies, trade winds, westerlies, etc.
In this exercise, you're required to complete the given sentences as follows:
Monsoon wind: a seasonal wind that blows in the opposite direction of normal winds.Prevailing wind: it is a wind that blows mainly from a single (one) general direction.During winter, droughts are typically caused by the seasonal winds that blow in the opposite direction of normal winds.Read more: https://brainly.com/question/15520014
Choose all correct sentences a. The power (equation 8) is maximum when the value of the impedance is greater than the value of the resistance. b. Resonance occurs when ω2 = 1/ LC c. At resonance, the power is maximum and the impedance is minimum. d. At resonance, R2- LC e. The quality factor L/ C f. The quality factor Q = g. The impedance Z is always larger than the resistance R.
Answer:
Note: Check the attached image for a clearer question
From the attached image, the answers are 2,3,6,7
Explanation:
Maximum power occurs at resonance, i.e. [tex]X_{L} = X_{C}[/tex], not when impedance is greater than resistance
Resonance occurs when the Inductive reactance equals the capacitive reactance, i.e. [tex]X_{L} = X_{C}[/tex], not [tex]R^{2} = (X_{L} - X_{C} ) ^{2}[/tex]
and when, [tex]w = \frac{1}{\sqrt{LC} }[/tex]
Therefore, option B is correct
Since the formula for impedance is [tex]Z = \sqrt{R^{2} + (X_{L}-X_{C}) ^{2} }[/tex], at resonance, Z = R i.e. the impedance is minimum
At resonance, there is maximum power and minimum impedance
Thew Quality Factor, [tex]Q = \frac{w_{0}L }{R} = \frac{1}{R} \sqrt{\frac{L}{C} }[/tex]
The impedance Z is always larger than the resistance R, note that it is not stated that this condition is at Resonance, that makes it correct.
[tex]Z = \sqrt{R^{2} + X^{2} }[/tex]
Technician A says that in any type of fluid coupling not equipped with a mechanical lock-up some slippage exists resulting in a difference between input and output speeds. Technician B says that in torque converter coupling phase impeller and turbine rpms match. Who is correct
Final answer:
Technician A is correct, as there is slippage between input and output speeds in fluid couplings without a mechanical lock-up. Technician B is incorrect, as the impeller and turbine rpms do not match in a torque converter coupling.
Explanation:
Technician A is correct. In any type of fluid coupling without a mechanical lock-up, there is always some slippage between the input and output speeds. This means that the output speed will be less than the input speed, resulting in a difference between them.
Technician B is incorrect. In a torque converter coupling, the impeller and turbine do not have matching rpm (revolutions per minute). The impeller rpm is higher than the turbine rpm, which allows the torque converter to efficiently transfer power from the engine to the transmission.
Two quakes of equal measurements on all scales occur in two different areas. In earth quake 1, the damage is severe but in earthquake 2, the damage is minimal. Explain some reasons why this is possible.
Answer:
See explanation
Explanation:
Depth: Earthquakes can happen anywhere from at the surface to 700 kilometers below. In general, deeper earthquakes are less damaging because their energy dissipates before it reaches the surface. So it is highly likely that the earthquake 1 was shallower than earthquake 2.
Distance from the epicenter: The epicenter is the point at the surface right above where the earthquake originates and is usually the place where the earthquake's intensity is the greatest. Plausible that earthquake 1 might have been closer to its epicenter as compared to earthquake 2.
Local geologic conditions: The nature of the ground at the surface of an earthquake can have a profound influence on the level of damage. Loose, sandy, soggy soil, like in Mexico City, can liquefy if the shaking is strong and long enough, for example. That doesn't bode well for any structures on the surface. Plausible that the area around the earthquake 1 might have poorer geologic conditions as compared to area of earthquake 2.
Let the magnitudes of two displacement vectors be 4 m and 8 m, respectively. If the two vectors are added, the magnitude of the resultant vector. A. is exactly equal to 4 m. B. is exactly equal to 12 m. C. is greater than 12 m. D. could be as small as 4 m, and as large as 12 m
Answer:
D. Could be as small as 4 m, and as large as 12 m.
Explanation:
Since the magnitudes are vectors instead of scalars, their sum is not just the sum of their magnitudes; their directions must be taken in account. The maximum possible magnitude of the resultant occurs when both vectors have the same direction; in that case the resultant magnitude is the sum of the individual magnitudes (in this case, 12 meters). In the other hand, the minimum possible magnitude is when the vectors have opposite directions; in that case the magnitude of the resultant is the substraction of one magnitude to another (in this case, 4 meters). Finally, the right answer is D, because the possible values range from 4m to 12m.
Final answer:
The magnitude of the resultant vector when adding two displacement vectors of 4 m and 8 m can be as small as 4 m if they are in opposite directions or as large as 12 m if they are collinear and in the same direction.(Option D)
Explanation:
The question asks about the magnitude of the resultant vector when two displacement vectors are added. A displacement vector has both magnitude and direction, and when two vectors are combined, their resultant depends on both their magnitudes as well as the angle between them. When two vectors are added, the magnitude of the resulting vector can vary depending on this angle. If the vectors are collinear and in the same direction, the magnitude of the resultant will be the sum of the magnitudes of the individual vectors, which is the maximum possible magnitude.
However, vectors can also be in opposite directions, in which case the resultant magnitude will be the difference between the two, representing the minimum magnitude. Therefore, given two displacement vectors with magnitudes of 4 m and 8 m, the magnitude of the resultant vector upon addition can range from 4 m to 12 m. This occurs because if the vectors are in the same direction, their magnitudes add up (to 12 m); if they are opposite, the resultant is the difference (to 4 m). In any other scenario of different angles between the vectors, the resultant will fall somewhere between 4 m and 12 m.
Which features do sound waves have the ocean and light waves do not
Sound waves spread out and bend around corners, while light waves behave like rays and do not bend around corners.
Explanation:The difference between sound waves and light waves when passing through an opening is that light waves behave like rays and do not bend around corners, while sound waves spread out and bend around corners due to their longer wavelengths.
Light waves have very short wavelengths, which allows them to act like rays and create sharp shadows when passing through openings. On the other hand, sound waves have longer wavelengths, on the order of the size of the opening, and can bend around corners.
For example, when light shines through an open door into a dark room, we expect to see a sharp shadow of the doorway on the floor and no light bending around corners. However, when sound passes through a door, we expect to hear it everywhere in the room, indicating that sound waves spread out and bend around corners.
A billiard ball is moving in the x-direction at 30.0 cm/s and strikes another billiard ball moving in the y-direction at 40.0 cm/s. As a result of the collision, the first ball moves at 50.0 cm/s, and the second ball stops. What is the change in kinetic energy of the system as a result of the collision
Explanation:
Given that,
Initial speed of the billiard ball 1, u = 30i cm/s
Initial speed of another billiard ball 2, u' = 40j cm/s
After the collision,
Final speed of first ball, v = 50 cm/s
Final speed of second ball, v' = 0 (as it stops)
Let us consider that both balls have same mass i.e. m
Initial kinetic energy of the system is :
[tex]K_i=\dfrac{1}{2}mu^2+\dfrac{1}{2}mu'^2\\\\K_i=\dfrac{1}{2}m(u^2+u'^2)\\\\K_i=\dfrac{1}{2}m((30)^2+(40)^2)\\\\K_i=1250m\ J[/tex]
Final kinetic energy of the system is :
[tex]K_f=\dfrac{1}{2}mv^2+\dfrac{1}{2}mv'^2\\\\K_f=\dfrac{1}{2}m(v^2+v'^2)\\\\K_f=\dfrac{1}{2}m((50)^2+(0)^2)\\\\K_f=1250m\ J[/tex]
The change in kinetic energy of the system is equal to the difference of final and initial kinetic energy as :
[tex]\Delta K=K_f-K_i\\\\\Delta K=1250m-1250m\\\\\Delta K=0[/tex]
So, the change in kinetic energy of the system as a result of the collision is equal to 0.
What type of bond results from the side‑on overlap of orbitals?
Answer:
A pi bond
Explanation:
A pi bond is a type of covalent bond that results from the formation of a molecular orbital by the side-to-side overlap of atomic orbitals along a plane perpendicular to a line connecting the nuclei of the atoms.
what voltage would be required to run a 600-watt motor with a current of 400 amperes
Answer:
Voltage can be calculated in various ways but I am a easier solution to it:
Explanation:
V=I×R instead of this formula I use:
P=I×V
600=400×V
600=400V
Divide both sides by 400
V=3÷2
V=1.5 J/C
1volt=1coulomb or joule
Answer:1.5V
Explanation: power =IV
Where I= current
V= voltage
Therefore Voltage=power/current
V= 600/400= 1.5
A particle with mass 1.81×10−3 kgkg and a charge of 1.22×10−8 CC has, at a given instant, a velocity v⃗ =(3.00×104m/s)j^v→=(3.00×104m/s)j^. What are the magnitude and direction of the particle’s acceleration produced by a uniform magnetic field B⃗ =(1.63T)i^+(0.980T)j^B→=(1.63T)i^+(0.980T)j^?
Answer:
-(0.330m/s² ) kˆ
Explanation:
given data:
Mass of particle 'm'= 1.81 x [tex]10^{-3}[/tex] kg
Velocity 'v'= (3.00 x[tex]10^{4}[/tex] m/s)j
Charge of particle 'q'= 1.22 x [tex]10^{-8}[/tex] C
Uniform magnetic field 'B' = (1.63iˆ + 0.980jˆ )T
In order to calculate particle's acceleration, we'll use Newton's second law of motion i.e F=ma
Also,the force a magnetic field exerts on a charge q moving with velocity v is called the magnetic Lorentz force. It is given by:
F = qv × B
F= ma = qV x B
a= [tex]\frac{q(v*B)}{m}[/tex] --->eq(1)
Lets determine the value of (v x B) first
v x B= (3.00 x[tex]10^{4}[/tex] m/s)j x (1.63iˆ + 0.980jˆ )
v x B= 4.89 x [tex]10^{4}[/tex]
Plugging all the required values in eq(1)
a= [1.22 x [tex]10^{-8}[/tex] x (4.89 x [tex]10^{4}[/tex]kˆ)] / 1.81 x [tex]10^{-3}[/tex]
a= -(0.330m/s² ) kˆ
-ve sign is representing the opposite direction
Jordana pulled a muscle while running at a track meet. Her coach gave her a self-heating pack to treat the injury. The instructions on the box said to twist the pack until the liquids mix. Which type of energy contained in the pack is responsible for producing the heat?
Answer:
Chemical
Explanation:
Jordana pulled a muscle while running at a track meet. Her coach gave her a self-heating pack to treat the injury. The instructions on the box said to twist the pack until the liquids mix. Chemical energy contained in the pack is responsible for producing the heat.
What is chemical energy ?Chemical energy is the energy that is released when chemical substances engage in a chemical reaction and change into other substances. Batteries, food, and gas are a few examples of chemical energy storage mediums.
Chemical energy is the energy held in atom and molecule bonding. Chemical energy can be found in things like batteries, biomass, oil, natural gas, and coal. When humans burn fuel in a car's engine or wood in a fireplace, chemical energy is transformed into thermal energy.
Around the world, we generate heat and power using chemical energy. Methane, natural gas, oil, and petroleum are examples of fossil fuels that we burn to create steam that turns turbines to generate power.
Thus, Chemical energy contained in the pack is responsible for producing the heat.
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A child bounces a 57 g superball on the sidewalk. The velocity change of the superball is from 24 m/s downward to 11 m/s upward. If the contact time with the sidewalk is 1 800 s, what is the magnitude of the average force exerted on the superball by the sidewalk? Answer in units of N.
Correct question:
A child bounces a 57 g superball on the sidewalk. The velocity change of the superball is from 24 m/s downward to 11 m/s upward. If the contact time with the sidewalk is 1/800 s, what is the magnitude of the average force exerted on the superball by the sidewalk? Answer in units of N.
Answer:
The magnitude of the average force exerted on the superball by the sidewalk is 592.8 N
Explanation:
Given;
mass of the superball, m = 57 g = 0.057 kg
initial velocity of the superball, u = 24 m/s
final velocity of the superball, v = 11 m/s
contact time with the sidewalk, t = 1 / 800 s
To determine the magnitude of the average force exerted on the superball by the sidewalk, we apply Newton's second law of motion;
F = ma
[tex]But, a = \frac{v-u}{t} \\\\Thus, F = m(\frac{v-u}{t} )\\\\F = 0.057(\frac{11-24}{1/800} )\\\\F = 0.057(\frac{-13}{1/800})\\\\F = -0.057(\frac{800*13}{1})\\\\ F = -592.8 \ N\\\\Magnitude \ of \ the \ force \ is \ 592.8 \ N[/tex]
Therefore, the magnitude of the average force exerted on the superball by the sidewalk is 592.8 N
A light bulb produces light with frequency = 4.65 x 1014 Hz. What is the wavelength of light the bulb produces?
6.45 x 10-7 meters
1.55 x 106 meters
6.45 x 1021 meters
1.395 x 1023 meters
Answer:
6.45 x 10-7 meters
Explanation:
Taking speed of light as 300000000 m/s
We know that speed of light is product of wavelength and frequency and expressed as
s=fw
Where s represent speed, f is frequency and w is wavelength
Substituting 4.65*10^14 Hz for frequency then the wavelngth will be given by
300000000=4.65*10^14 *w
w=300000000÷4.65*10^14
w=6.451612903225*10^-7 m
Rounded off, the wavelength is 6.45 x 10-7 meters
In a double-slit arrangement the slits are separated by a distance equal to 100 times the wavelength of the light passing through the slits. What is the angular separation in radians between the central maximum and an adjacent maximum?
Answer:
0.01 rad
Explanation:
For a double-slit experiment, we have that dsinθ = nλ. The separation between the central maximum and an adjacent maximum is when n = 1
dsinθ = λ
The angular separation θ = sin⁻¹(λ/d)
now d = 100λ
θ = sin⁻¹(λ/100λ) = sin⁻¹(0.01) = 0.573°
θ = 0.573° × π/180 = 0.01 rad
500 kg cannon and is at rest on a horizontal, frictionless surface on a clear and sunny day. When a crazy cool 100 kg clown decided to show how the cannon works they decided to get fired horizontally from the barrel of the cannon and the cannon recoils with a speed of 5 m/s. A very inquisitive Physics student figured out how fast the clown was traveling when leaving the cannon. What value did they come up with?
Answer:
Explanation:
Given that,
Mass of cannon
M1= 500kg and initially at rest
U1 = 0m/s
Mass of clown
M2 = 100kg
so it was initial at rest before this time, therefore, U2 = 0
Recoils speed of cannon V1 =5m/s, the recoils speed is after the cannon has left the barrel.
Using construction of linear momentum
Momentum before collision is equal to momentum after collision
The initial momentum is zero since the two bodies are until at rest
And the final momentum is
M1•V1 + M2•V2
Then,
P(initial) = P(final)
0 = M1•V1 + M2•V2
0 = 500 × 5 + 100 × V2
0 = 2500 +100•V2
100•V2 = -2500
V2 = -2500/100
V2 = —25m/s
So, the final velocity of the clown is -25m/s, opposite direction of the cannon
Two blocks of masses 6 kg and 10 kg are placed on a horizontal, frictionless surface. A light spring is attached to one of them, and the blocks are pushed together with the spring between them. A cord holding them together is burned, after which the block of mass 10 kg moves to the right with a speed of 3.4 m/s. What is the velocity of the other mass in
Answer:
5.67 m/s ( towards left)
Explanation:
We are given that
[tex]m_1=6 kg[/tex]
[tex]m_2=10 kg[/tex]
Speed of mass 10 kg=3.4 m/s
We have to find the velocity of other mass.
When there is no external force applied the the linear momentum will be conserved
[tex]-m_2v_2=m_1v_2[/tex]
Substitute the values
[tex]10\times 3.4=6v_1[/tex]
[tex]v_1=-\frac{10\times 3.4}{6}[/tex]
[tex]v_1=-5.67 m/s[/tex]
The mass 6 kg moves to the left with speed 5.67 m/s.
When you swim, your hands apply a force backward on the water. The reaction to this force is________
Explanation:
THERE FORE THE REACTION IS FRICTION FORCE.
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It should be pushing because when you swim you are pushing yourself
What are characteristics that enable plants to protect themselves from herbivores include
Answer:
All of the above!
Explanation:
All of the answers are true! I hope I helped!
what is electrical circuit
you push a 560 mm radius bicycle wheel, which is approximately hoop shaped, along a flat region until it reaches a speed of 5.01 m/s. It then goes up a smooth hill of irregular shape and height 0.6 m before falling off the vertical face on the opposite side.
What is its speed at the top of the hill?
Answer:
The speed at the top of the hill is 4.38 m/s
Explanation:
Here we have total Kinetic = KE (translational) +KE (rotational)
=0.5 m v² + 0.5m·r²v²/r² = m·v²
Therefore at height 0.6 m we have
0.6 mg = mv²
When v = 5.01 m/s maximum height is
m·g·h=m·5.01²
or h = 2.56 m
Therefore at 0.6 m we have 2.56 - 0.6 more height energy to climb
which gives
1.96·m·g = m v₂²
or v₂² = 19.22
v₂ = 4.38 m/s.
What is your prediction on the effects of drinking 20oz of sports drink vs. 20oz of water? What would happen to urine volume
Answer:
Drinking 20oz of sports drinks decrease the urine volume compared to 20oz of water
Explanation:
Sport drinks typically used by athletes contain water,carbs and electrolytes which helps to replenish the lost minerals from the body during exercises.
Electrolytes an important ingredients of sports drinks is typically sodium and potassium they help the body to retain water,hence less volume of urine is released from the body.
What would happen if a person who is wearing a heavy winter jacket were to place a thermometer inside the jacket next to his or her skin? What would happen if we took the same jacket, after it had been hanging in a closet, and placed a thermometer inside?
Answer:
Explained.
Explanation:
Let me explain the two cases in by one.
(1) When Person wearing a jacket, heat from his or her body is going to get trapped inside his or her jacket to keep this person warm when a thermometer is placed inside, it would indicate a higher temperature on the scale.
(2) When Jacket is Hanging in a closet, its temperature would be roughly close to room temperature and when we would place a thermometer it would not indicate any change on its scale.
A single star in the process of forming starts by spinning slowly (while it is quite large and relatively cool.) As the star collapses under the pull of its own gravity, its size decreases. As a result, its rate of spinning:_____
a. will either increase or decrease depending on the star's temperature
b. will decrease
c. will stay the same
d. will increase
Answer:
d. will increase
Explanation:
The process is spinning is known as stellar rotation, it is the rotation of a star about it axis in an angular direction. Now, A single star in the process of forming starts by spinning slowly which is as a result of its size but as the star collapses under the pull of its own gravity, the radius of the size shrinks and reduces, then the spinning rate escalate and increases.
Two identical 9.60-g metal spheres (small enough to be treated as particles) are hung from separate 500-mm strings attached to the same nail in a ceiling. Surplus electrons are added to each sphere, and then the spheres are brought in contact with each other and released. Their equilibrium position is such that each string makes a 17.0 ∘ angle with the vertical.How many surplus electrons are on each sphere?
Answer:
1.349 × 10¹² electrons
Explanation:
At equilibrium, the tension T in the string is resolved into horizontal and vertical components. Tcos17 being the vertical component and Tsin17 the horizontal component. The electrostatic force of repulsion at equilibrium, F = kq²/r² where q = excess charge on sphere and r = distance apart at equilibrium,F acts horizontally to the left and its weight, mg acts vertically downwards.
For equilibrium, sum of horizontal components = 0 and sum of horizontal components = 0. So, Tsin17 - F = 0
Tsin17 = F ⇒ Tsin17 = kq²/r² (1)
Also Tcos17 - mg = 0 ⇒ Tcos17 = mg (2)
Dividing (1) by (2), we have
Tsin17/Tcos17 = kq²/r² ÷ mg
tan17 = kq²/mgr²
q = r√(mgtan17/k)
We find r using cosine rule r = √(500² + 500² -2 × 500²cos 2 × 17) since the string and the masses form an isosceles triangle at equilibrium.
r = √(2 × 500² -2 × 500²cos34) = 500√2(1 - cos 34) = 500√2 × 0.1710 =120.89 mm = 0.1209 m
substituting m = 9.60 g = 9.6 × 10⁻³ g, k = 9 × 10⁹ Nm²/C² and r into q, we have,
q = r√(mgtan17/k)
= 0.1209 m√(9.6 × 10⁻³ g × 9.8 m/s² × tan17/9 × 10⁹ Nm²/C²)
= 0.1209 m√(28.76 × 10⁻³ N/9 × 10⁹ Nm²/C²)
= 0.1209 m√(3.195 × 10⁻¹² C²/m²)
= 0.1209 m × 1.7877 × 10⁻⁶ C/m
= 0.2161 × 10⁻⁶ C
= 2.161 × 10⁻⁷ C
To find the number of surplus electrons, n on each sphere, we divide q by e the electron charge.
So, n = q/e = 2.161 × 10⁻⁷ C ÷ 1.602 × 10⁻¹⁹ C = 0.6825 × 10¹² = 1.349 × 10¹² electrons
The number of surplus electrons on each sphere : 3.27 * 10¹²
Given data :
Mass of metal spheres = 9.60 g
length of string = 500 mm
Angle made by each string with the vertical ( ∅ ) = 17°
Determine the number of surplus electrons on each sidewe will apply the formula below
number of surplus electrons ( n ) = [tex]\frac{q}{e}[/tex] ----- ( 1 )
whereby :
Considering The forces acting on the metal spheres
Tan ∅ = [tex]\frac{q^{2} }{4\pi e_{o}mgr^{2} }[/tex] ----- ( 2 )
First step : Determine the distance between the spheres
r = 2l * sin∅
= 2 * 0.500 * sin17°
= 0.2924 m
Next step : Determine the charge on each sphere
Back to equation ( 2 )
Tan 17° = [tex]\frac{(8.99*10^{9}) * q^{2} }{(9.60 * 10^{-3})*(9.81)*(0.2924 )^{2} }[/tex]
q² = [ ( 0.3057 ) * ( 9.60 * 10⁻³ ) * ( 9.81 ) * ( 0.2924 )² ] / ( 8.99 * 10⁹ )
= 0.00246 / 8.99 * 10⁹
= 2.7364 * 10⁻¹³
Charge on each sphere ( q ) = √ ( 2.7364 * 10⁻¹³ ) = 5.23 * 10⁻⁷ C
Final step : The number of surplus electrons on each sphere
Back to equation ( 1 )
n = q / e
= ( 5.23 * 10^-7 ) / ( 1.6 * 10^-19 )
= 3.27 * 10¹²
Hence we can conclude that the number of surplus electrons on each sphere : 3.27 * 10¹².
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A typical incandescent light bulb consumes 75 W of power and has a mass of 30 g. You want to save electrical energy by dropping the bulb from a height great enough so that the kinetic energy of the bulb when it reaches the floor will be the same as the energy it took to keep the bulb on for 1.0 hour. From what height should you drop the bulb, assuming no air resistance and constant g?
Answer:
The height will be 917431.2 m.
Explanation:
Power of bulb = 75 W
Time kept on 1 hr = 60 x 60 = 3600 sec
Energy of bulb = power x time
E = 75 x 3600 = 270000 J
From conservation of energy, kinetic energy of the bulb is equal to the potential energy of the bulb due to its height of fall.
Potential energy = m x g x h
Where g = acceleration due to gravity 9.81 m/s2
m = mass = 30 g = 0.03 kg
PE = 0.03 x 9.81 x h = 0.2943h
Equating withe the energy of bulb (still obeying energy conservation)
270000 = 0.2943h
h = 270000/0.2943 = 917431.2 m
The incandescent bulb would have to be dropped from a height of approximately 918,367.35 meters to have its kinetic energy equal to the energy consumed in one hour of use.
To determine from what height you should drop a 75-watt incandescent bulb so that upon reaching the floor, its kinetic energy will equal the energy used to power it for 1.0 hour, we use the formula for gravitational potential energy (PE) and kinetic energy (KE), where PE = mgh and KE = ½ mv². The power consumption of the bulb indicates how much energy it uses per second, so we first calculate the energy consumed in one hour (E = power × time). Since the bulb is 75 watts, and there are 3600 seconds in an hour, it uses 75 W × 3600 s = 270,000 joules in one hour. This is the energy we want the bulb to have as kinetic energy when it hits the ground. To find the height, we set this equal to the potential energy at the start (mgh) and solve for h:
E = mgh
270000 J = (0.03 kg)(9.8 m/s²)(h)
h = 270000 J / (0.03 kg × 9.8 m/s²)
h = 918367.35 m
Thus, the bulb would have to be dropped from a height of approximately 918367.35 meters to have the same energy when it impacts the ground as it uses in one hour of being lit.
Two balls collide with each other. Ball 1 experiences a high acceleration as a result of the collision, while Ball 2 experiences a small acceleration. What can you conclude about Ball 2?
Answer:
We conclude that ball 2 has a larger mass.
Explanation:
This is because the internal forces at collision are an action reaction pair. The force on ball 1 due to ball 2 equals the force on ball 2 due to ball 1. Since these forces are equal in magnitude, let's denote it by F. So
For each ball, F = ma and a = F/m. Since F is the same for both balls, if follows that the acceleration of each ball is inversely proportional to its mass. That is, a ∝ 1/m.
Since ball 1 has a higher acceleration, it has a lower mass. Also ball 2 has a small acceleration, so it has a higher mass.
Answer:
See explanation
Explanation:
Solution:-
- Denote the following:
mass of ball 1 = m1
initial velocity of ball 1 = vi,1
Final velocity of ball 1 = vf,1
mass of ball 2 = m2
initial velocity of ball 2 = vi,2
Final velocity of ball 2 = vf,2
- Since there are no external forces acting on the system containing the two balls then we can say that the linear momentum of the system is conserved.
- The conservation of linear momentum says that the momentum before or after the collision remains conserved:
Pi = Pf
Where, p = m*v
- The conservation of momentum for the given system:
m1*vi,1 + m2*vi,2 = m1*vi,1 + m2*vi,2
- Since no information is given about the initial conditions. We will consider the internal force (F) that acts when two balls come in contact. Then apply Newton's second law of motion on both balls individually:
F = m*a
Where, m: Mass of object
a: Acceleration of the object
- For ball 1:
F1 = m1*a1
- For ball 2:
F2 = m2*a2
Given that a1 > a2, and the the internal force that acts on both balls during collision obeys Newton's 3rd Law i.e for every action there is an equal but opposite reaction: So , F1 = F2
F = m1*a1
F = m2*a2
m1*a1 = m2*a2
- Since, a1 > a2 for above equation to hold true then m1 < m2. That is the mass of ball 1 is quite less compared to ball 2.
The diagram shows a transformer. Based on the diagram the voltage at the second winding is ____ v
Answer:
60V
Explanation:
240V/12 loops = 20 volts per loop.
20 * 3 = 60 volts
Answer:
60V
Explanation:
On classical Hall mobility: In a semiconductor sample, the Hall probe region has a dimension of 0.5 cm by 0.25 cm by 0.05 cm thick. For an applied electric field of 1.0 V/cm, 20 mA current flows (through the long side) in the circuit. When a 10 kG magnetic field is applied, a Hall voltage of 10 mV is developed. What is the Hall mobility of the sample and what is the carrier density
Answer:
hall mobility = 139.8 x 10 ∧3
carrier density = 83.1 x 10 ∧14
Explanation:
The pictures attached below shows the full explanation
Solids,liquids,and gases are three forms of matter that?
Although blood cells are contained within a special liquid called plasma, the cells themselves are___________.
Answer:
Solid
Explanation:
The plasma is the liquid part of blood, it is 90% and accounts for 55% of blood volume. It is what red blood cells, white blood cells, and platelets move around in. These cells remain solid within the plasma. I hoped this helped!
Although blood cells are contained within a special liquid called plasma, the cells themselves are suspended in plasma.
Blood is a fluid tissue that is made up of plasma, red blood cells, white blood cells, and platelets. Plasma is the liquid part of blood that makes up about 55% of blood volume.
Red blood cells make up about 45% of blood volume and are responsible for carrying oxygen to the tissues. White blood cells make up about 1% of blood volume and are responsible for fighting infection. Platelets are responsible for clotting blood.
The cells are suspended in the plasma because they are too small to sink to the bottom of the blood. The plasma also helps to transport the cells throughout the body.
Learn more about blood cells, here:
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