A mixture of gaseous reactants is put into a cylinder, where a chemical reaction turns them into gaseous products. The cylinder has a piston that moves in or out, as necessary, to keep a constant pressure on the mixture of . The cylinder is also submerged in a large insulated water bath. (See sketch at right.) From previous experiments, this chemical reaction is known to absorb of energy. The temperature of the water bath is monitored, and it is determined from this data that of heat flows out of the system during the reaction. Is the reaction exothermic or endothermic

Answer:

Explanation:

1. Number of moles of gasoline

a)  Convert 60.0 liters to grams

b) Convert 46,200 grams to moles

2. Number of moles of carbon dioxide, CO₂ produced

a) Balanced chemical equation (given):

b) mole ratio:

Solve for x:

3. Convert the number of moles of carbon dioxide to volume

Use the ideal gas equation:

Substitute and compute:

Round to two significant figures (because the density has two significant figures): 79,000 liters ← answer

The liters L of carbon dioxide at 1.00 atm and 298.15 K released from the car's engine upon consumption of a 60.0 L LIQUID tank gasoline is 79230.76 L

From the given information;

The equation for the reaction can be expressed as:

[tex]\mathbf{C_8H_8 _{(l)} + \frac{25}{2}O_2_{(g)} \to 8 CO_2_{(g)} + 9H_2O_{(g)}}[/tex]

Given that:

The first thing to do is to determine the mass amount of gasoline used by using the relation:

[tex]\mathbf{Density = \dfrac{mass}{volume}}[/tex]

[tex]\mathbf{0.77 \ kg/L = \dfrac{mass}{60 \ L}}}[/tex]

mass amount of gasoline used = 0.77 kg/L × 60 L

mass amount of gasoline used = 46.2 kg

mass amount of gasoline used = 46.2 × 1000g

mass amount of gasoline used = 46200 g

Now, since we know the mass amount of the gasoline used, we can determine the number of moles of the gasoline by using the formula:

[tex]\mathbf{number of moles = \dfrac{mass}{molar \ mass}}[/tex]

[tex]\mathbf{number of moles = \dfrac{46200 \ g}{114.2 \ g/mol}}[/tex]

[tex]\mathbf{number \ of \ moles = 404.6 \ moles }[/tex]

From the given reaction, 1 mole of gasoline react to produce 8 moles of CO₂

As such, 404.6 moles of gasoline will produce = (404.6 moles × 8)/ 1

= 3236.8 moles of CO₂ is produced.

Now, using the ideal gas equation to determine the volume of CO₂ that  are released;

PV = nRT

[tex]\mathbf{1.00 atm \times V = 3236.8 moles \times 0.0821 atm L /K/mol \times 298.15 \ K}[/tex]

[tex]\mathbf{V = \dfrac{3236.8 moles \times 0.0821 atm L /K/mol \times 298.15 \ K}{1.00 atm}}[/tex]

V = 79230.76 L

Therefore, we can conclude that the liters L of carbon dioxide at 1.00 atm and 298.15 K released from the car's engine upon consumption of a 60.0 L LIQUID tank gasoline is 79230.76 L

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Answer:

The volume of HCl required is [tex]V = 420 mL[/tex]

Explanation:

From the question we are told that

    The chemical equation for this reaction is

             [tex]2 Al _{(s)} + 6 HCl _{(aq)} -----> 2 Al Cl_{3} _{(aq)} + 3 H_2 _{(g)}[/tex]

    The mass of Al  is [tex]m__{Al}} = 2.00g[/tex]

    The concentration of HCl is [tex]C__{HCl}} = 0.500M[/tex]

The number of moles of [tex]Al[/tex] given is [tex]n__{Al}} = \frac{mass \ of Al}{Molar \ mass \ of \ Al}[/tex]

   The molar mass of Al is  [tex]M = 27 g/mol[/tex]

       So

               [tex]n__{Al} = \frac{2}{27}[/tex]

               [tex]n__{Al} = \ 0.07 \ moles[/tex]

From the balanced equation

           2 moles of  Al  reacts  with  6 moles of  HCl

So        0.07 moles of Al will react with x

  Therefore

                [tex]x = \frac{0.07 *6}{2}[/tex]

                [tex]x = 0.21 \ moles[/tex]

Now the volume of HCl can be obtained as

           [tex]Volume(V) = \frac{moles}{concentration }[/tex]

 So       [tex]V = \frac{0.21}{0.500}[/tex]

             [tex]V = 420 mL[/tex]

Answer:

A rapid reaction is distinguished by having a relatively small value of activation energy.

Explanation:

Chemical kinetics is involved in determining the rate of a reaction, how fast or slow a reaction will occur in a particular condition. The factors affecting the rate of reaction determining whether it will be a rapid reaction includes nature of the reactants, temperature, pressure, surface area of solid state, catalysts, concentration and so on. Based on temperature, temperature affects the collision frequency of a reaction and this contributes to a portion of the increased rate of reaction. At a given temperature, the rate of  a reaction depends on the magnitude of the activation energy, pre-exponential factor A, molar gas constant, R, and temperature. This is true based on the Arrhenius equation K = Ae^-Ea/(RT). So therefore, from the equation, it is revealed that at small activation energies, reaction rate is rapid and slow at high activation energies.

Final answer:

A rapid reaction is characterized by a low activation energy, which allows for a faster reaction rate. Catalysts can lower this energy barrier, further speeding up the reaction without altering the overall energy change of the reaction.

Explanation:

A rapid reaction is distinguished by having a small value of activation energy. Activation energy (Ea) is the barrier that must be overcome for reactants to transform into products. A low activation energy indicates that the reactants can more easily reach the transition state and react to form products, leading to a faster reaction rate.

Catalysts are substances that lower the activation energy and provide a new pathway for the reaction to occur, thus speeding up the reaction without being consumed in the process. They do not affect the overall energy change of the reaction (∆H), but they make it easier for the reaction to occur.

This is especially valuable in biological systems where catalysis allows for important cellular reactions to occur at appreciable rates without the need for high temperatures that could harm the cell.

It is the heat of the reaction (∆H) that determines whether a reaction is exothermic or endothermic, not the activation energy.

Therefore, whether a reaction has a large heat of reaction or a small heat of reaction does not directly relate to its speed.

Answer:

The correct name for the following compound is

2 - methylbicyclo[4.3.0]nonane

Explanation:

Rule 1

Numbering of bicyclic compound is done from bridgehead carbon

Rule 2

The system is numbered with one of the bridgeheads, numbering proceeding by the longest possible path to the second bridgehead.

Name of the given bicyclic compound is 2 - methylbicyclo[4.3.0]nonane

Answer:

The answer to the question above is explained below

Explanation:

There are so many differences between the two ecosystem (terrestrial ecosystems and aquatic ecosystems). The most important ones will be highlighted:

1. Aquatic environments are so rich in nutrients they support more live than equivalent terrestrial ecosystems as aquatic ecosystems have availability of water more than the terrestrial ecosystems. Presenting the consequent importance of water as a limiting factor in the terrestrial ecosystems.

2. Aquatic ecosystems are much more stable than terrestrial ecosystems, with smaller fluctuations in temperature and other variables.

3. In terrestrial ecosystems, there is hardly ever a shortage of light, while it can be a limiting factor in some aquatic ecosystems.

4. Gravity has so much influence on terrestrial animals. That is not the case for their aquatic counterparts where water supports aquatic organisms.

An ecosystem is a large community of living organisms (plants, animals and microbes) in a particular area in conjunction with the non-living components of their environment, interacting as a system.

Terrestrial Ecosystem includes: Grasslands, Forests, Desert.

Aquatic Ecosystem includes: Freshwater ecosystem, Marine Ecosystem.

Answer:

1.45 *10^23 atoms C

Explanation:

3.50 g butane * 1 mol butane/58.1 g butane =0.06024 mol butane

in 1 mol C4H10           -------- 4 mol C

in 0.06024 mol C4H10 -------- 4*0.6024 = 0.241 mol C

0.241 mol C * 6.02*10^23 atoms C/1 mol C = 1.45 *10^23 atoms C

Answer:

Nitrification is a biological process by which ammonia is oxidized to nitrites ([tex]NO_{2} ^{-}[/tex]) and then to nitrates ([tex]NO_{3} ^{-}[/tex]) by action of specialized bacteria in nature (such as nitrosomonas and nitrobacter).

Explanation:

This two-step process utilizes molecular atmospheric oxygen and ammonia and ammonium components of soil and nature.

(a.) Ammonia and ammonium compounds to nitrite

[tex]NH_{4} ^{+} + O_{2}[/tex] → [tex]NO_{2} ^{-} + 4H^{+}[/tex]

[tex]2NH_{3} ^{+} + 3O_{2}[/tex] → [tex]2NO_{2} ^{-} + 2H^{+} + 2H_{2} O[/tex]

(b.) Nitrite to nitrate

[tex]2NO_{2} ^{-} + O_{2}[/tex] → [tex]2NO_{3} ^{-} + energy[/tex]

(c.) The reverse process involves reduction of nitrates to molecular nitrogen, called denitrification (with succinic acid in the equation below).

[tex]4NO_{3} ^{-} + 10H^{+} + (CH_{2})_{2}(COOH)_{2}[/tex] → [tex]2N_{2} +4CO_{2} + 8 H_{2} O[/tex]

([tex]NO[/tex] and [tex]N_{2}O[/tex] is an intermediate product in this process.)

Answer:

4.95×10^22 atoms of hydrogen.

Explanation:

Now, we must remember that the number of elementary entities in one mole of a substance (atoms, molecules, ions,etc) is given by the Avogadro's number. Avogadro's number is numerically equal to 6.02×10^23.

We must first find the number of moles of hydrazine corresponding to 2.65 g

We find that from;

Number of moles= mass of hydrazine given/ molar mass of hydrazine

Molar mass of hydrazine= 32.0452 g/mol

Number of moles of hydrazine= 2.65/32.0452 g/mol= 0.0823 moles

If 1 mole of hydrazine contains 6.02×10^23 hydrogen atoms

0.0823 moles of hydrazine will contain 0.0823 moles × 6.02×10^23 = 4.95×10^22 atoms of hydrogen.

Answer:

The Phosphorylated  glucose(glucose +inorganic phosphate), with the energy supplied from ATP hydrolysis formed glucose 6- phosphate, which is later converted to 2 molecules of fructose 6-phosphate- this is phosphorylation.And  represented the fate of  glucose -6-phosphate.

The fructose 6-phosphate are converted to triose phosphate- which is a 2-molecules of 3C compound. The latter is oxidized by NAD→ NADH+ to form intermediates in the glycolytic pathways .

These intermediates are converted to ribose 5-phosphates in the presence of transketolase  and transaldolase enzymes.And they are finally   converted to pyruvate in the glycolytic pathway with the production of 2ATPs per molecule of glucose.

Basically the phosphate pathway reaction is very slow due to enzyme catalysis.

Answer:

see below

Explanation:

The rate constant is missing in question, but use C(final) = C(initial)e^-kt = 0.200M(e^-k·10). Fill in k and compute => remaining concentration of reactant

Answer:

C(initial)e^-kt = 0.200M(e^-k·10).

Explanation:

The rate constant is missing in question, but use C(final) = C(initial)e^-kt = 0.200M(e^-k·10).

Fill in k and compute => remaining concentration of reactant

Answer: A

Explanation:

Hydrolysis reactions break down not only feldspars but many other silicate minerals as well, amphiboles, pyroxenes, micas, and olivines.

Answer:

c. Z is a catalyst, and ZA2 and A are reaction intermediates.

Explanation:

Overall reaction is given as;

A2 + 2 B → 2 BA

Mechanism:

Step 1: A2 + Z → ZA2

Step 2: ZA2 + B → BA + Z + A

Step 3: A + B → BA

The options given are centered upon catalysts and reaction intermediates. So before proceeding, we have to understand the difference between the two and how to identify them.

A catalyst is basically a reaction booster to speed up the rate of the reaction and the reaction intermediate is an unstable, temporl species formed from the reactants before getting to the products.

The difference is given as;

Catalysts are present as reactants in the very beginning and products at the end of the reaction.

Intermediates, on the other hand, are not present in the initial reaction but are produced within one of the steps and then consumed within another step.

Following the above, we can deduce that;

Z is a catalyst because it is present as a reactant in the beginning.

ZA2 and A are a reaction intermediates because they are not present in the overall reaction but are produced and consumed in one of the steps.

Correct option is given as;

c. Z is a catalyst, and ZA2 and A are reaction intermediates.

Answer:

2) ΔS°rxn is positive, and the process is spontaneous at high temperatures only.

Explanation:

ΔS = ΔH / T , ΔS is change in entropy , ΔH is change in enthalpy

Since ΔH is positive , ΔS is positive .

ΔG = ΔH - TΔS

For spontaneous reaction . ΔG should be negative .

As ΔS is positive , at high temperature the value of TΔS will be more and hence the value of TΔS will be higher than Δ H . Hence ΔG will be negative.

Hence at higher temperature , the reaction will be spontaneous.

The predicted sign of ΔS°rxn and the conditions under which this reaction would be spontaneous should be option  2) ΔS°rxn is positive, and the process is spontaneous at high temperatures only.

We know that

ΔS = ΔH / T

Here ΔS means a change in entropy

And, ΔH means a change in enthalpy

Since ΔH is positive so  ΔS is positive.

Now

ΔG = ΔH - TΔS

However, For spontaneous reaction. ΔG should be negative .

Since ΔS is positive, at high temperature the value of TΔS should be more and due to this the value of TΔS will be more than Δ H . Thus,  ΔG will be negative.

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Answer:Neptunium; Protactinium; Thorium; Uranium

Explanation:

Answer:

the reported molar concentration of the sodium hydroxide solution will be too high.

Explanation:

The term "standardization" in science or in analytical Chemistry simply means the process involved in the determination of a standard or the concentration of a particular substance.

One of the advantages and the most important of the advantages of Standardization is that it Helps in making sure that we get a result with the least error.

So, let me explain the answer. The reported molar concentration of the sodium hydroxide solution will be TOO HIGH because the potassium hydrogen phthalate is NOT completely dry. The weight of the moisture will create an additional weight which will increase the weight of potassium hydrogen phthalate in the solution

If potassium hydrogen phthalate is not completely dry, it will make the reported molar concentration of the sodium hydroxide solution too low. This is due to the added water from the moisture which causes a dilution effect.

In the situation where the potassium hydrogen phthalate is not completely dry, the reported molar concentration of the sodium hydroxide solution will be too low. This is because the water from the phthalate's moisture can dilute the sodium hydroxide solution, which leads to a lower than actual molar concentration. It's essential to have a completely dry potassium hydrogen phthalate when standardizing sodium hydroxide solutions to get an accurate molar concentration.

For instance, when potassium hydroxide, a highly soluble ionic compound, is dissolved in a dilute solution, it completely dissociates, giving a certain concentration of [OH-] ions. Suppose this reaction occurs in an environment where excess water is introduced due to the moisture in potassium hydrogen phthalate. In that case, this equilibrium will be affected, leading to a lower concentration of hydroxide ions and thus, a lower reported molar concentration of the sodium hydroxide solution.

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Answer:

The value of Ka [tex]= 1.1*10^{-2}[/tex]

It is a weak  acid

Explanation:

   From the question we are told that

             The concentration of [tex][HClO_2]=0.24M[/tex]

             The concentration of  [tex][H^+]=0.051M[/tex]

             The concentration of  [tex][ClO_2^-]=0.051M[/tex]

Generally the equation for the ionic dissociation of [tex]HClO_2[/tex] is

                [tex]HClO_2_(aq) -------> H^{+}_{(aq)} + ClO_2^{-}_{(aq)}[/tex]

The equilibrium constant is mathematically represented as

                         [tex]Ka = \frac{concentration \ of \ product }{concentration \ of \ reactant }[/tex]

                               [tex]= \frac{[H^+][ClO_2^-]}{[HClO_2]}[/tex]

Substituting values since all value of concentration are at equilibrium

                    [tex]Ka = \frac{0.051 * 0.051}{0.24}[/tex]

                          [tex]= 1.1*10^{-2}[/tex]

Since the value of  is less than 1 it show that in water it dose not completely

disassociated  so it an acid that is weak

Answer:

The pH shifts less with small additions of titrant near the equivalence point.

Explanation:

Explanation:

In an acid-base titration, the titration curve reflects the strengths of the corresponding acid and base.

If one reagent is a weak acid or base and the other is a strong acid or base, the titration curve is irregular, and the pH shifts less with small additions of titrant near the equivalence point.

Acid-base titrations depend on the neutralization between an acid and a base when mixed in solution.

The endpoint and the equivalence point are not exactly the same: the equivalence point is determined by the stoichiometry of the reaction, while the endpoint is just the color change from the indicator.

Answer:

Thermal decomposition

Explanation:

Calcium carbonate can be broken  down by heating. The following equation represents this chemical change.

CaCO₃(s) ⇒ CaO(s) + CO₂(g)

The scientific term for this process is thermal decomposition.

The breakdown of calcium carbonate by heating is called thermal decomposition. This process involves a single substance breaking down into simpler compounds upon heating. The process is demonstrated in the reaction - CaCO3 (s) -> CaO(s) + CO2 (g), where calcium carbonate decomposes into calcium oxide and carbon dioxide.

The process of breaking down Calcium Carbonate (CaCO3) by heating is scientifically known as Thermal Decomposition. This is a chemical process where a single substance breaks down into two or more simpler substances when heated. To demonstrate this, let's use the following reaction:

CaCO3(s) → CaO(s) + CO2(g)

In this instance, calcium carbonate (which can come from limestone or chalk) decomposes into calcium oxide and carbon dioxide when heated. It's important to note that the reaction is reversible and to ensure a 100% yield of CaO, the CO2 should be allowed to escape.

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Answer:The general properties of matter such as color, density, hardness, are examples of physical properties. Properties that describe how a substance changes into a completely different substance are called chemical properties. Flammability and corrosion/oxidation resistance are examples of chemical properties.

Explanation:

Answer:

Combustion

Explanation:

Combustion reactions are the one where the oxygen is a reactant and the products are always water and carbon dioxide.

It is also a redox type because the oxygen is reduced and the carbon from the C₄H₁₀O oxidized to CO₂

C₄H₁₀O + 6O₂ → 4CO₂ + 5H₂O

1 mol of butyl alcohol burns in prescence of 6 moles of oxygen in order to produce 4 moles of carbon dioxide and 5 moles of water.

Answer:

This is a combustion reaction

Explanation:

Step 1: Data given

A single-replacement reaction is a reaction where we will replace one element with a similar element in the compound.

A single-replacement or displacement reaction has the following form:

A+BC→AC+B

Element  A  is usually a metal and will replace element  B in the compound , this should also be a metal.

If the elemnent isn't a metal ( so a nonmetal), the replacing element will either be a metal.

In a double-replacement reaction we will exchange positive and negative ions of two ionic compounds, what will cause the formation of two new compounds.

A double-replacement reaction has the following form:

AB+CD→AD+BC

IIn this example,  A  and  C  are positively-charged ions (cations), and   B  and  D  are negatively-charged ions (anions).

In a decomposition reaction a compound will break down into two or more substances ( those are smaller, more simple).

A decomposition reaction uses the following form.

AB→A+B

In a combustion reaction a substance will react with oxygen gas (O2). Oxygen gas is needed to start the reaction.CO2 gas and water vapor (H2O) will be produced.

In a combination reaction we will combine two or more substances to form a single new substance. This is also known as a synthesis reaction, and uses the general form:

A+B→AB

Step 2: The equation

C4H10(g) + 6O2(g) → 4CO2(g) + 5H2O(g)

Step 3: What kind of reaction is this

Since the reaction requires oxygen and will produce carbon dioxie and water vapor. This means this reaction is a combustion reaction.

(Combustion of butane).

Answer:

Check the explanation

Explanation:

The Grignard Reaction refers to the organomagnesium halide (also known as the Grignard reagent) addition to a ketone or aldehyde, just to create a secondary or tertiary alcohol, respectively. When there’s a reaction with the formaldehyde, it leads to a primary alcohol. It is a multipurpose material that can be utilized in creating new carbon–carbon bonds.

Kindly check the image below to see the structure of the organic product(s) of the Grignard reaction between dimethyl oxalate and excess methylmagnesium bromide.

The product of the reaction is a diol obtained by nucleophilic addition of methylmagnesium bromide to each ester group in dimethyl oxalate, followed by aqueous acid workup.

The organic product of the Grignard reaction between dimethyl oxalate and excess methylmagnesium bromide, followed by aqueous workup, is the diol resulting from the nucleophilic addition of the Grignard reagent to the carbonyl group of the ester. Each ester group in the dimethyl oxalate is replaced by a methyl group from methylmagnesium bromide. After acidic workup, the final product is a diol with two primary alcohol groups. The mechanism involves the formation of a magnesium alkoxide intermediate, which upon acid treatment, delivers the alcohol. To start, the Grignard reagent methylmagnesium bromide acts as a strong nucleophile, attacking the electrophilic carbonyl carbon of the first ester group, then similar addition occurs to the second ester group after another equivalent of the Grignard reagent. Finally, hydrolysis during the aqueous workup completes the reaction.

Answer:

Low molecular weight carboxylic acids are volatile.

One should use caution when handling low molecular weight carboxylic acids.

Final answer:

Low molecular weight carboxylic acids are volatile and can have strong odors. They are not completely safe for handling without protection due to possible irritation from the vapors. Therefore, caution and appropriate safety measures are necessary when handling these substances.

Explanation:

Low molecular weight carboxylic acids tend to be volatile, implying they can easily vaporize at room temperature, and often have strong, sharp odors. One commonly known example is ethanoic acid (acetic acid), which is found in household vinegar. While they are usually colorless and can be found in everyday products such as foods and household items, it is not accurate to say that they are completely safe and can be handled without protection. The vapors of low molecular weight carboxylic acids can be irritating and, in some cases, harmful if inhaled in large amounts. Therefore, caution should be used when handling these substances.

Carboxylic acids are weak acids that do not completely ionize in water. This characteristic makes them less dangerous than strong acids; however, they can still cause irritation and should be treated with respect in a laboratory setting. Carboxylic acids such as propionic acid, while not highly toxic, can still pose safety risks if not handled properly, reinforcing the need for appropriate safety measures such as gloves and eye protection when handling these compounds.

Answer:

The proposed mechanism is shown on the first uploaded image

Explanation:

Final answer:

The IUPAC name for the compound is 4-sec-Butyl-2,4-dimethylheptane, which is determined by identifying the longest continuous carbon chain and naming the substituents.

Explanation:

The IUPAC name for the compound is 4-sec-Butyl-2,4-dimethylheptane.

The name is determined by identifying the longest continuous carbon chain, which in this case is heptane. The substituents are then named using prefixes such as sec-, iso-, or tert-, which indicate the position of the substituent on the main chain. The substituents are listed alphabetically, followed by the position number and the main chain name.

In this case, the compound has a butyl group attached at the 4th position on the main chain, and two methyl groups attached at the 2nd and 4th positions. Therefore, the IUPAC name is 4-sec-Butyl-2,4-dimethylheptane.

Answer:

26 g

Explanation:

Write the balanced reaction first

CH4 + 2 O2 --> CO2 + 2 H2O

9.3g + 52.3g --> ? CO2

You must determine how much carbon dioxide can be made from each of the reactants. The maximum mass that can be made is the lower of the two.

From CH4:

9.3g CH4 (1molCH4/16.05gCH4) (1molCO2 / 1molCH4) (44.01g CH4 / 1molCO2) = 26 g

From O2:

52.3g O2 (1molO2/32gO2) (1molCO2/2molO2)(44.01g/1molCO2) = 36 g

Final answer:

In a galvanic cell, half-reactions occur at separate electrodes: reduction at the cathode and oxidation at the anode. The cathode is the positive electrode, while the anode is the negative electrode. Standard cell potential can be calculated but requires the standard reduction potentials for the specific half-reactions.

Explanation:

Galvanic Cell Half-Reactions, Electrodes, and Potentials

In a galvanic cell, a spontaneous redox reaction occurs that drives the flow of electrons from the anode to the cathode through an external circuit. The original question does not provide a complete redox reaction, but assuming it involves bromine (Br2), hydrogen (H2), and hydroxide ions (OH-), the following can be considered:

For the provided redox reaction, the half-reaction that occurs at the cathode (reduction) might be:

2H+ + 2e- → H2

And the half-reaction at the anode (oxidation) could be:

2Br- → Br2 + 2e-

The cathode is the positive electrode, as it undergoes reduction, and the anode is the negative electrode, as it undergoes oxidation. Without actual potential values given, the cell voltage under standard conditions cannot be calculated here. However, the standard cell potential can be found by using standard reduction potential tables and subtracting the anode potential from the cathode potential.

Explanation:

1. When sodium phosphate is added to copper (II) sulfate it gives solid precipitate of copper(II) phosphate and solution of sodium sulfate.

The balanced equation is given as:

[tex]2Na_3PO_4(aq)+3CuSO_4(aq)\rightarrow Cu_3(PO_4)_2(s)+3Na_2SO_4(aq)[/tex]

2. When sodium phosphate is added to iron(III) chloride it gives solid precipitate of iron (III) phosphate and solution of sodium chloride.

The balanced equation is given as:

[tex]Na_3PO_4(aq)+Fe(Cl)_3(aq)\rightarrow FePO_4(s)+3NaCl(aq)[/tex]

The properties of matter including structure, composition, and behavior can all be explained on a submicroscopic level. The atoms or molecules' arrangement, what they are composed of, and their response to different conditions, helps in understanding the properties of the matter.

The properties of matter such as structure, composition, and behavior can all be explained on a submicroscopic level. In fact, observing matter at this level allows us to understand why material behaves in the way that it does.

Structure refers to the arrangement of atoms in a material. For example, diamonds and graphite are both made of carbon atoms, but their different structures make them drastically different in hardness.

Composition refers to what a material is made of at the elemental level. For example, water is composed of two hydrogen atoms and one oxygen atom, leading to its unique properties.

Behavior can be understood as the way that material reacts under different conditions, this can be due to the interaction of its molecules. For example, water boils at 100 degrees Celsius because that's the temperature at which its molecules have enough energy to change from a liquid to a gas.

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