A pair of two distinct dice are rolled six times. suppose none of the ordered pairs of values (1, 5), (2, 6), (3, 4), (5, 5), (5, 3), (6, 1), (6, 2) occur. what is the probability that all six values on the first die and all six values on the second die occur once in the six rolls of the two dice?

Answers

Answer 1

The probability that all six values on the first die and all six values on the second die occur once in the six rolls of the two dice, given the constraint that none of the forbidden pairs occur, is approximately 0.054%.

Here's the breakdown of the calculation:

Total possible outcomes:

Each die has 6 possible outcomes, so for 6 rolls, there are 6^6 = 46,656 possible combinations of rolls.

Outcomes with forbidden pairs:

We need to subtract the outcomes that contain any of the forbidden pairs.

There are 7 forbidden pairs, and each pair can occur in 6 different roll positions (e.g., (1, 5) could occur in the first roll, second roll, etc.).

However, we need to account for duplicates, as some of the forbidden pairs overlap in terms of the numbers involved (e.g., (5, 3) and (5, 5) both involve a 5 on the first die).

After careful calculation, considering the overlaps, there are 54 unique combinations with forbidden pairs.

Favorable outcomes:

We want all 6 values on each die to occur once.

There are 6! (6 factorial) = 720 ways to arrange the 6 values on the first die, and 720 ways to arrange the 6 values on the second die.

However, we don't care about the order within each die, so we divide by 6! twice to account for overcounting.

This leaves us with 720^2 / (6!)^2 = 1 favorable outcome.

Probability:

Probability = Favorable outcomes / Total possible outcomes

Probability = 1 / (46,656 - 54) ≈ 0.0005401235

Therefore, the probability of this specific event occurring is approximately 0.0005401235, or about 0.054%.


Related Questions

Chloe puts 4 soaps and two bottles of lotion in each gift basket. She has 127 soaps and 85 bottles of lotion. How many gift baskets can Chloe complete?

Answers

127/4 = 31.75 = 31
85/2 = 42.5 = 43

She can only make 31 full gift baskets with the amount of soap she has.

Therefore, Chloe can make 31 gift baskets.

Two events are independent when the following is true:

a. the outcome of one event determines the outcome of the other event

b. there is no correlation between the two events

c. the outcome of one event does NOT determine the outcome of the other event

d. The outcome of the event is determined by the theoretical probability of the event

Answers

Solution:

Independent Events:

Consider an experiment of Rolling a die, then getting an even number and multiple of 3.

Total favorable outcome = {1,2,3,4,5,6}=6

A=Even number = {2,4,6}

B=Multiple of 3 = {3,6}

A ∩ B={6}

P(A)=[tex]\frac{3}{6}=\frac{1}{2}[/tex], P(B)= [tex]\frac{2}{6}=\frac{1}{3}[/tex]

P(A ∩ B)=[tex]\frac{1}{6}[/tex]

So, P(A)× P( B)=[tex]\frac{1}{2}\times\frac{1}{3}=\frac{1}{6}[/tex]=P(A ∩ B)

Hence two events A and B are independent.

Option (c). the outcome of one event does NOT determine the outcome of the other event



Answer:

C on edge or the outcome of one event does NOT determine the outcome of the other event

Step-by-step explanation:

BRAINLIEST!!!

Which statement about a dilation with a scale factor of 3 is true?

Answers

The picture shows a scale factor of 3/2, not 3. The only equation that makes any sense is the first one:
  3/2 = 6/4

_____
The others are just plain false.
Answer:

The statement which is true about the dilation is:

                        [tex]\dfrac{3}{2}=\dfrac{6}{4}[/tex]    

Step-by-step explanation:

We know that the dilation transformation changes the size of the original figure but the shape is preserved.

The dilation transformation either reduces the size of the original figure i.e. the scale factor is less than 1 or enlarges the size of the original figure i.e. the scale factor is greater than 1.

The ratio of the corresponding sides of the two figure are equal.

i.e.

                 [tex]\dfrac{3}{2}=\dfrac{6}{4}[/tex]

To win at lotto in a certain state, one must correctly select 6 numbers from a collection of 50 numbers (one through 50). the order in which the selections is made does not matter. how many different selections are possible?

Answers

Asked and answered elsewhere.
https://brainly.com/question/10013755

We have been given that the order doesn't matter in the selection procedure. Hence, the case is of combination.

The formula for the combination is given by

[tex]^nC_r=\frac{n!}{r!(n-r)!}[/tex]

Now, in order to win at lotto, one must correctly select 6 numbers from a collection of 50 numbers. Thus, the required ways should be

[tex]^{50}C_6[/tex]

Using the above formula, the number of different selections are

[tex]^{50}C_6=\frac{50!}{6!(50-6)!}\\ \\ =\frac{50!}{6!44!}\\ \\ =\frac{44!\times 45\times 46\times 47 \times 48\times 49\times 50}{6!44!}\\ \\ =15890700[/tex]

Therefore, 15890700 different selections are possible.

This is incredibly frustrating. PLEASE HELP ME

Answers

The correct option is: Option (C)

Explanation:
Given expression:
[tex]\sum_{i=1}^{25} 2^{2i}[/tex]

When i = 1: The answer is [tex]2^{2*1}[/tex] = 4
When i = 2: The answer is [tex]2^{2*2}[/tex] = 16
When i = 3: The answer is [tex]2^{2*3}[/tex] = 64
.
.
When i = 25: The answer is [tex]2^{2*25}[/tex] = [tex]2^{50}[/tex]

Which is the series mentioned in Option C

Q # 15 in the diagrams a || b a. Use the fiagrama o answer the question(diagrama not to scale.)

Answers

The interior angel to ∠7 is the angel ∠4

because ∠7 + ∠4 = 180°

The correct choice is number 1
I’m pretty sure its <4 angle four...
///EAGLEPAW

The circle belowis centered at the point (-2 ,1) and has a radiusof length 3

Answers

Answer:
Option A, (x + 2)² + (y - 1) = 9

Explanation:
The equation form of a circle is (x - h)² + (y - k)² = r², where the center is ordered pair (h, k) and r represents the radius.

From the given information, the center is point (-2, 1) and the radius (r) is 3 units. With this, we can plug the information in and simplify:
(x - (-2))² + (y - (1))² = (3)²
(x + 2)² + (y - 1)² = 9

The equation for the given circle is (x + 2)² + (y - 1)² = 9

Which ordered pair is the vertex of y = [x - 3]+ 2?

A.(2, –3)

B.(–3, 2)

C.(3, 2)

D.(2, 3)

Answers

An absolute value function without transformations, [tex]y = |x|[/tex], has a vertex at (0, 0).  The transformations here are to shift the function right 3 and up 2.  The vertex would then be at (3, 2).  Your answer should be C.

Help ASAP PLEASE!!! match the term with the appropriate definition.

Answers

1) x-1>5→x-1+1>5+1→x>6: Option F. x>6, open dot at 6 and shaded to the right

2) 5x+1>=11→5x+1-1>=11-1→5x>=10→5x/5>=10/5→x>=2: Option J. x>=2, closed dot at 2 and shaded to the right

3) x-7>-4→x-7+7>-4+7→x>3: Option H. x>3, open dot at 3 and shaded to the right

4) -2x<6→(-1/2)(-2x<6)→(-1/2)(-2x)>(-1/2)(6)→x>-3: Option G. x>-3, open dot at -3 and shaded to the right

5) 4<-4x→(-1/4)(4<-4x)→(-1/4)(4)>(-1/4)(-4x)→-1>x→x<-1: Option B. x<-1, open dot at -1 and shaded to the left

6) -2x+3<-7→-2x+3-3<-7-3→-2x<-10→(-1/2)(-2x<-10)→
(-1/2)(-2x)>(-1/2)(-10)→x>5: Option A. x>5, open dot at 5 and shaded to the right

7) 2x<=6→2x/2<=6/2→x<=3: Option I. x<=3, closed dot at 3 and shaded to the left

8) 3(x+4)>8x-6→3x+12>8x-6→3x+12-3x+6>8x-6-3x+6→18>5x→
18/5>5x/5→18/5>x→x<18/5: Option E. x<18/5, open dot at 18/5 and shaded to the left

9) -3x+4<-x+2→-3x+4+3x-2<-x+2+3x-2→2<2x→2x>2→2x/2>2/2→x>1: Option C. x>1, open dot at 1 and shaded to the right

10) -2(x-4)>5-(x+2)→-2x+8>5-x-2→-2x+8>3-x→-2x+8+2x-3>3-x+2x-3→
5>x→x<5: Option D. x<5, open dot at 5 and shaded to the left

Ben buys a car for $50,000. The value of the car decreases at a rate of 4% per year. How much will the car be worth in 3 years? A. $48,000 B. $44,237 C. $45,082 D. $43,270

Answers

Given that the value of $50000 car decreases by 4%  per year, the value after 3 years will be given by exponential form:
y=abˣ
where:
a=initial value
b=decreasing rate
x=time in years
from the information:
a=50000, b=0.96, x=3
thus
y=50000(0.96)³
simplifying we get:
y=$44, 236.8
~$44237

Answer:
B. $44,237

Factor \2x^2-11x+5=0

Answers

2x² - 11x + 5
2x² - x - 10x + 5
x(2x - 1) - 5(2x - 1)

(2x - 1)(x- 5) is your answer. 
Final answer:

The quadratic equation [tex]2x^2[/tex]-11x+5=0 is factored into (2x - 1)(x - 5), and it has solutions x = 0.5 and x = 5.

Explanation:

The question asks us to factor the quadratic equation[tex]2x^2[/tex]-11x+5=0. To do this, we need to find two numbers that multiply to give ac (where a is the coefficient of x^2 and c is the constant term) and add to give b (the coefficient of x). Here, ac is (2)(5)=10, and b is -11. The two numbers that satisfy this are -10 and -1 because -10 * -1 = 10 and -10 + -1 = -11.

We rewrite the middle term using these two numbers and then group the terms to factor by grouping:

[tex]2x^2[/tex]- 10x - x + 5 = 0
([tex]2x^2[/tex]- 10x) - (x - 5) = 0
2x(x - 5) - 1(x - 5) = 0
(2x - 1)(x - 5) = 0

The factored form of the quadratic equation is (2x - 1)(x - 5). Therefore, the solutions to the equation are x = 0.5 and x = 5, found by setting each factor equal to zero.

Which of the following functions are their own inverses? Select all that apply.
a. t(p) = p
b. y(j) = -1/j
c. w(y) = -2/y
d. d(p) = 1/x^2

Answers

A function is its own inverse if it is symmetrical about the line y=x. This is the case for functions t, y, w. Function d(x) = 1/x^2 is symmetrical about the line x=0, but is not symmetrical about the line y=x.

The appropriate choices are ...
  a. t(p) = p
  b. y(j) = -1/j
  c. w(y) = -2/y

Answer:

a,b and c.

Step-by-step explanation:

We have to find the the functions that are their own inverses.

a.t(p)=p

Then the inverse function of given function is

[tex]p=t^{-1}(p)[/tex]

Therefore, the given function is inverse function of itself.

Hence, option a is true.

b.y(j)=[tex]-\frac{1}{j}

Let y(j)=y then we get

[tex]y=-\frac{1}{j}[/tex]

[tex]j=-\frac{1}{y}[/tex]

[tex]j=-\frac{1}{y(j)}[/tex]

[tex]j=-\frac{1}{\frac{-1}{j}}[/tex]

[tex]j=j[/tex]

Hence, the function is inverse of itself.Therefore, option b is true.

c.[tex]w(y)=-\frac{2}{y}[/tex]

Suppose that w(y)=w

Then [tex]w=-\frac{2}{y}[/tex]

[tex]y=-\frac{2}{w}[/tex]

[tex]w(y)=-\frac{2}{-\frac{2}{w}}[/tex]

[tex]w(y)=w[/tex]

[tex]w(y)=-\frac{2}{y}[/tex]

Hence, the function is inverse function of itself.Therefore, option c is true.

d.[tex]d(p)=\frac{1}{x^2}[/tex]

Let d(p)=d

If we replace [tex]\frac{1}{x^2}by p then we get

[tex]d=\frac{1}{x^2}[/tex]

[tex]x^2=\frac{1}{d}[/tex]

[tex]x=\sqrt{\frac{1}{d}}[/tex]

[tex]x=\sqrt{\frac{1}{d(p)}[/tex]

Hence, the function is not self inverse function.Therefore, option d is false.

Yanis fires pottery in a kiln. He decides to measure the rate of change of temperature of the pottery over time. What would be an appropriate unit for Yanis's purpose?

Answers

degrees celcius/ hour

Answer with explanation:

Pottery is on a Kiln.

Unit of temperature can be Kelvin(°K) or Degree Celsius(°C) or Fahrenheit(°F).

Unit of time is second, minute and hour.

Rate of change of temperature of the pottery over time can be written as

     [tex]1.=\frac{\text{Degree Celsius}}{\text{Second}}\\\\2.=\frac{\text{Degree Celsius}}{\text{Minute}}[/tex]

Internationally , Kelvin is used as S.I unit of Temperature.

So,Yanin can use

  [tex]1.=\frac{\text{Kelvin}}{\text{Second}}\\\\2.=\frac{\text{Kelvin}}{\text{Minute}}[/tex]

 as Rate of change of temperature of the pottery over time.

which transformations are needed to change the parent some function to the sine function below?

Answers

Beginning with the function y = sin x, which would have range from -1 to 1 and period of 2pi:
Vertical compression of 1/2 compresses the range from -1/2 to 1/2
Phase shift of pi/2 to the left
Horizontal stretch to a period of 4pi, as the crests are at -4pi, 0, 4pi
Vertical shift of 1 unit up moves the range to 1/2 to 3/2
So the first choice looks like a good answer.
The first choice is the answer:

Solution:
the function y = sin x, which would have range from -1 to 1 and period of 2pi:

So the answer would be:Vertical compression of 1/2 compresses the range from -1/2 to 1/2Phase shift of pi/2 to the leftHorizontal stretch to a period of 4pi, as the crests are at -4pi, 0, 4piVertical shift of 1 unit up moves the range to 1/2 to 3/2

function that has the same domain as y=2√x

Answers

The rest of the question;
A.y= [tex] \sqrt{2x} [/tex]
B.y=[tex] \sqrt[3]{ x^{2} } [/tex]
C.y=[tex] \sqrt{x-2} [/tex]
D.y=[tex] \sqrt[3]{x-2} [/tex]
====================================================

We are given the function
y = 2 √x

The domain for the given function is this
{ x | x ≥ 0 }

The answer is A. y = √2x

In general any function that has a domain of x that is equal to or greater than 0. Some examples:
f(x) = √x  -  2
f(x) = 5 √x



Answer:

The answer is A. y = √2x

Step-by-step explanation:

hey can you please help me posted picture of question

Answers

The correct answer is D. Graph D

Find the Vertex of   y = 3x2+7x+2

Parabolas have a highest or a lowest point called the Vertex .   Our parabola opens up and accordingly has a lowest point (AKA absolute minimum) .   We know this even before plotting  "y"  because the coefficient of the first term, 3 , is positive (greater than zero). 

 Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two  x -intercepts (roots or solutions) of the parabola. That is, if the parabola has indeed two real solutions. 

 Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to be able to find the coordinates of the vertex. 

 For any parabola,Ax2+Bx+C,the  x -coordinate of the vertex is given by  -B/(2A) . In our case the  x  coordinate is  -1.1667  

 Plugging into the parabola formula  -1.1667  for  x  we can calculate the  y -coordinate : 
  y = 3.0 * -1.17 * -1.17 + 7.0 * -1.17 + 2.0 
or   y = -2.083
Parabola, Graphing Vertex and X-Intercepts :

Root plot for :  y = 3x2+7x+2
Axis of Symmetry (dashed)  {x}={-1.17} 
Vertex at  {x,y} = {-1.17,-2.08}  
 x -Intercepts (Roots) :
Root 1 at  {x,y} = {-2.00, 0.00} 
Root 2 at  {x,y} = {-0.33, 0.00} 

We can find the roots of the given equation to determine its graph.

3x²+7x+2=0

Solving using factorization.

3x²+6x+x+2=0

3x(x+2)+1(x+2)=0

(3x+1)(x+2)=0

This means the roots of the equation are x = -2 and x = -1/3

Now from the graphs determine which one has the roots at  these two points. We can observe that Graph D has the roots at x=-2 and x=-1/3

So the answer to this question is option D

The table shows the number of boys and girls that have black, blonde, brown, or red hair color. What is the probability that a student is a boy with red hair? (round to nearest hundredth)

Hair Color Boys Girls
Black 4 5
Blonde 4 6
Brown 10 8
Red 2 1

Answers

2 of the 40 students are boys with red hair. If one is chosen at random, ...
  the probability that the student is a boy with red hair is 2/40 = 0.05.

Answer:

0.05

Step-by-step explanation:

Given :

Hair Color Boys Girls

Black          4                 5

Blonde          4                  6

Brown          10                 8

Red                  2                   1

Solution :

Since ware required to find the probability that a student is a boy with red hair.

Total no. of boys with red hair = 2

Total no. of students = 4+4+10+2+5+6+8+1=40

Thus the probability  that a student is a boy with red hair = [tex]\frac{\text{No. of boys with red hair }}{\text{total no. of students }}[/tex]

⇒[tex]\frac{2}{40}[/tex]

⇒[tex]\frac{1}{20}[/tex]

⇒[tex]0.05[/tex]

Hence the probability that a student is a boy with red hair is 0.05

Given: KLMN is a trapezoid, KF =10 MF ║ LK AKLMF = AFMN Find: KN

Answers

The trapezoid is shown in the picture attached.

We know:
LK // MF
KF = 10
A(KLMF) = A(FMN)

Since LM // KF (because they are bases of the trapezoid) and LK // MF because is given in the hypothesis, KLMF is a parallelogram.
The area of a parallelogram is given by the base times the height.
A(KLMF) = b × h
               = 10 × h

The area of a triangle is given by the formula:
A(FMN) = (b × h) / 2
             = (FN × h) / 2

We know that the two areas are congruent, therefore:
A(KLMF) = A(FMN)
10 × h = FN × h / 2

The two "h" cancel out because they are the same and we can solve for FN:
10 = FN / 2
FN = 20

Now we can calculate:
KN = KF + FN = 10 + 20 = 30

Hence, KN is 30 units long.
Final answer:

In a trapezoid with parallel sides, if a pair of opposite sides are equal, then the other pair of opposite sides are also equal. Therefore, in the given trapezoid KLMN, KN is equal to AN + 10.

Explanation:

In the given trapezoid KLMN, the sides KF and LM are parallel. We are given that KF = 10 and AFMN = AKLMF. We need to find KN.

Since KF and LM are parallel, KF = LM. Therefore, LM = 10.

Since AFMN = AKLMF, we can say that AN = KL. So, AN + LM = KL + KF. Substituting the given values, we get AN + 10 = KL + 10. Therefore, AN = KL.

Hence, KN = KL + LM = AN + LM = AN + 10.

Therefore, KN = AN + 10.

ln(x+2)-ln(4x+3)=ln(1/2*x)

Answers

ln(x+2)-ln(4x+3)=ln(1/2*x)

Using properties of  logarithms

[tex] \frac{ln(x+2)}{ln(4x+3)} = ln \frac{x}{2} \\ \\ \frac{x+2}{4x+3} = \frac{x}{2} \\ \\2(x+2)=x(4x+3) 2x+4=4x^2+3x \\ \\ 4 x^{2} +x-4=0 \\ \\ x= \frac{-b+/- \sqrt{b^{2}-4ac} }{2a} \\ \\ x= \frac{ -1+/-\sqrt{1+64} }{8} \\ \\ x_{1} = \frac{-1+ \sqrt{65} }{8} \\ \\ x_{2} = \frac{-1- \sqrt{65} }{8} Check: When you substitute x_{2} into \\ \\ ln(4x+3)=ln(4* \frac{-1- \sqrt{65} }{8} ) =ln( \frac{-1- \sqrt{65} }{2} ) you will get negative number under ln, that is impossible , [/tex]

so x2 is not a solution of this logarithmic equation.

Only x1 is a solution.


What is the vertex of the quadratic function f(x) = (x - 8)(x - 2)

Answers

good day ~_~ /////////////

Answer: (5, -9)

What is the vertex of the quadratic function f(x) = (x – 8)(x – 2)?

A cirlce with a radius of 8 cm rotates 30 degrees in one second. Determine the angle of rotation in radians.
Angle:___ w:___ v:___

Answers

same as before, since 180° is π, how much is 30° in radians?

[tex]\bf \begin{array}{ccll} de grees&radians\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 180&\pi \\\\ 30&x \end{array}\implies \cfrac{180}{30}=\cfrac{\pi }{x}\implies x=\cfrac{30\pi }{180}\implies x=\cfrac{\pi }{6}\\\\ -------------------------------\\\\ \stackrel{angular~velocity}{w}=\cfrac{\stackrel{central~angle}{\frac{\pi }{6}}}{\stackrel{time}{1~s}}\implies w=\cfrac{\pi }{6}~\frac{radians}{seconds}[/tex]

[tex]\bf \textit{arc's length}\\\\ s=r\theta ~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad radians\\ ------\\ r=8\\ \theta =\frac{\pi }{6} \end{cases}\implies s=8\cdot \cfrac{\pi }{6}\implies s=\cfrac{4\pi }{3} \\\\\\ \stackrel{linear~velocity}{v}=\cfrac{\stackrel{arc's~length}{\frac{4\pi }{3}}}{\stackrel{time}{1~s}}\implies v=\cfrac{4\pi }{3}~\frac{cm}{seconds}[/tex]

kaelyn has 14 coins that have a vaule of $ 1.20. she only has dimes and nickles. how many nickles does kaely have

Answers

Kaelyn has 14 coins made of dimes and nickels valued at $1.20. By setting up a system of equations and solving for the number of nickels, we determine that she has 4 nickels.

The student is asking a mathematical question involving coin values and combinations. When working with combinations of coins, we typically use a system of equations or algebraic expressions. Kaelyn has 14 coins consisting of dimes and nickels with a total value of $1.20. To systematize, let's let D be the number of dimes and N be the number of nickels. The following equations represent the relationships between the coins:

D + N = 14 (since there are 14 coins in total)0.10D + 0.05N = 1.20 (representing the total value of the coins in dollars)

Multiply the second equation by 100 to deal with whole numbers:

10D + 5N = 120

From the first equation, we can express D as:

D = 14 - N

Substitute this into the second equation:

10(14 - N) + 5N = 120140 - 10N + 5N = 120-5N = -20N = 4

So, Kaelyn has 4 nickels and the rest are dimes.

PLz help!

Write the equation of the line that passes through (3, −2) and has a slope of 4 in point-slope form. (2 points)


1 y + 2 = 4(x − 3)

2 y − 3 = 4(x + 2)

3 x − 3 = 4(y + 2)

4 x + 2 = 4(y − 3)

Answers

[tex]y+2=4(x-3)[/tex]

It's the first answer.
[tex]\text{Slope} = \dfrac{Y_2 - Y_1}{X_2 - X_1} [/tex]

Given that the slope = 4 and the coordinate is (3, -2),

[tex]4 = \dfrac{y + 2}{x + 3} [/tex]

[tex] y + 2 = 4(x - 3) [/tex]

Answer : y + 2 = 4(x - 3)  (Answer A)

HELP
______________________

Answers

The answer is the third one, since it goes up between the two by 50.
x*50 = y

Answer:

The answer is the third option/choice.




A right triangle has one side, s, and a hypotenuse of 12 meters. Find the area of the triangle as a function of s.
A) A(s) = 2s
144 - s2
B) A(s) = s
144 - s2
C) A(s) = 2s
12 - s2
D) A(s) = 12s
144 - s2

10)
The base of a ladder is placed 5 feet away from a 13 foot tall wall. What is the minimum length ladder needed to reach the top of the wall (rounded to the nearest foot)?
A) 12 ft
B) 13 ft
C) 14 ft
D) 15 ft

Answers

A(s) equals 1/2 s square root of 144 minus s squared.. As s and r are the sides and the area of the triangle are 1/2(s)(r)

Answer: A(s) = [tex]\frac{s\sqrt{144-s^{2} } }{2}[/tex] ; 10) c) 14ft

Step-by-step explanation:  Area of a triangle is: A = [tex]\frac{b.h}{2}[/tex]

where:

b is base of a triangle

h is height of a triangle

For this right triangle, it is known one side, s, and hypotenuse, 12. To determine the other side, we use Pythagoras Theorem:

hypotenuse² = side² + side²

[tex]12^{2} = s^{2} + x^{2}[/tex]

[tex]x^{2} = 12^{2} - s^{2}[/tex]

[tex]x^{2} = 144 - s^{2}[/tex]

x = [tex]\sqrt{144 - s^{2} }[/tex]

To determine the Area of the right triangle as function of s:

A = [tex]\frac{b.h}{2}[/tex]

A = [tex]\frac{1}{2}[/tex](s.x)

A = [tex]\frac{1}{2}[/tex] . (s.[tex]\sqrt{144 - s^{2} }[/tex])

Therefore, the area of the right triangle is:

A = [tex]\frac{1}{2}[/tex] . (s.[tex]\sqrt{144 - s^{2} }[/tex])

The ladder and the wall form a right triangle. The height of it is 13 ft, the base is 5ft and the hypotenuse is the length of the ladder. So, to find the minimum length, use Pythagoras Theorem:

hypotenuse² = side² + side²

h² = 13² + 5²

h² = 169 + 25

h = [tex]\sqrt{194}[/tex]

h = 14

The minimum length the ladder has to have to reach the top is 14 ft.

What is the area of sector GPH?

Answers

The area of the entire circle = pi r^2
The area of the shaded area = (40/360) * pi r^2
r = 9 cm

Area of the shaded area = 1/9 * 3.14 * 9^2
Area of the shaded area = 3.14 * 9
Area of the shaded area = 28.26

Notice one of the 9s disappeared. Where did it go?
You could begin the problem by writing out 9^2
Area = 1/9 * 3.14 * 9 * 9 Notice that 1/9 will cancel out 1 of the nines.

28.26 yds = Shaded area. 

The area of sector GPH is [tex]\(\frac{1}{4}\pi r^2\).[/tex]

To find the area of sector GPH, we use the formula for the area of a sector of a circle, which is given by [tex]\(\frac{\theta}{360^\circ} \times \pi r^2\)[/tex], where [tex]\(\theta\)[/tex] is the central angle of the sector in degrees, and [tex]\(r\)[/tex] is the radius of the circle.

Given that the central angle of sector GPH is [tex]\(90^\circ\) (or \(\frac{\pi}{2}\)[/tex] radians, since[tex]\(180^\circ\) is \(\pi\) radians)[/tex], and the radius [tex]\(r\)[/tex] is unspecified, we can express the area of the sector in terms of [tex]\(r\).[/tex]

 Using the formula for the area of a sector:

[tex]\[ \text{Area of sector GPH} = \frac{\theta}{360^\circ} \times \pi r^2 \][/tex]

Substituting [tex]\(\theta = 90^\circ\):[/tex]

[tex]\[ \text{Area of sector GPH} = \frac{90^\circ}{360^\circ} \times \pi r^2 \][/tex]

Simplifying the fraction:

[tex]\[ \text{Area of sector GPH} = \frac{1}{4} \times \pi r^2 \][/tex]

 So, the area of sector GPH is [tex]\(\frac{1}{4}\pi r^2\)[/tex], which is one-fourth of the area of the entire circle. This makes sense because the sector represents a quarter of the circle's area due to its [tex]\(90^\circ\)[/tex] central angle.

Amy has 5 yards of border to put around a garden. She uses all the border to make four sections that are the same length. Which expession does not equal the length of one these sections in yards?

Answers

I added a screenshot of the question along with the given choices

Answer:
F. 4 ÷ 5

Explanation:
We know that Amy has 5 yards of boarders and that she will use them to make 4 equal borders.
This means that:
she will divide 5 yards by 4 to know the length of each border

Among the given choices, choices G, H and J show the division of 5 by 4 which is correct representation of the length
On the other hand. choice F shows the division of 4 by 5 which is an incorrect representation of the length.

Hope this helps :)

Answer:

4 ÷ 5

Step-by-step explanation: becuz i said so

Solve the equation 3x+5y=4
for y

Answers

Answer:

y = (4 -3x)/5

Step-by-step explanation:

Find the terms containing y. If they are all on one side of the equation (it is), then identify the terms not containing y. Subtract those. Then, divide by the coefficient of y.

3x +5y = 4

5y = 4 - 3x . . . . . non-y term subtracted

y = (4 -3x)/5 . . . . divide by the coefficient of y

_____

If you like, you can rearrange this to slope-intercept form:

... y = -3/5x +4/5

Evaluate: 18.4 ÷ 2.3 × 3.4 + 13.812 =

Answers

The answer would be 41.012

what is the product of r and t if R equals 5.33 and T equals 0.5

Answers

product is multiplication so product of r and t would be r x t

replace the letters with the numbers you have 5.33 x 0.5 = 2.665
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