A person jogged 10 times along the perimeter of a rectangular field at the rate of 12 kilometers per hour for 30 minutes. if field has a length that is twice its width, find the area of the field in square meters. ________________________________________

To find the minimum cost of blending the plant food mixes, set up a system of equations to calculate the quantities of each mix needed. Solve the equations to find the values of x and y, then calculate the cost using the mix prices.

To find the minimum cost of blending the plant food mixes, we need to set up a system of equations and solve for the quantities of each mix needed. Let's let x be the number of cubic yards of mix a and y be the number of cubic yards of mix b that the farmer needs.

The total pounds of phosphoric acid required from mix a and mix b should equal the minimum monthly requirement of 440 pounds. This gives us the equation: 20x + 10y = 440.

The total pounds of nitrogen required from mix a and mix b should equal the minimum monthly requirement of 990 pounds. This gives us the equation: 30x + 30y = 990.

The total pounds of potash required from mix a and mix b should equal the minimum monthly requirement of 200 pounds. This gives us the equation: 5x + 10y = 200.

Solving this system of equations will give us the values of x and y. Once we have these values, we can calculate the cost by multiplying the quantity of each mix by their respective prices and adding them together.

Final answer:

The value of x that is part of a solution to this system of equations is 22.

Explanation:

To find the value of x in the system of equations:

We can use the method of elimination or substitution. Let's use substitution for this example:

Thus, the value of x that is part of a solution to this system of equations is 22.

The solution is Option A.

The value of the equation is 2( y - 4 ) - 5y = 3

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the value of x = y - 4   be equation (1)

Let the value of the equation 2x - 5y = 3   be equation (2)

Now ,

We know the value of the equation x = y -4

Substituting the value of equation (1) in equation (2) , we get

2 ( y - 4 ) - 5y = 3

So , the equation has now become ,

2 ( y - 4 ) - 5y = 3

Hence , the value of the equation is 2 ( y - 4 ) - 5y = 3

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Final Answer:

Quadratic equation: [tex]\( x^2 + 24x - 3456 = 0 \)[/tex]

Dimensions: Length = 48 inches, Width = 72 inches

Explanation:

To find the quadratic equation representing the area of the screen, we first need to express the area as a product of its length (L) and width (W). Given that the width is 24 inches longer than the length, we can represent the width as [tex]\( L + 24 \)[/tex]. Thus, the equation becomes [tex]\( L \times (L + 24) = 3456 \)[/tex], which simplifies to the quadratic equation [tex]\( x^2 + 24x - 3456 = 0 \)[/tex], where x represents the length of the screen. Solving this equation yields the length x as 48 inches. Substituting this value back into [tex]\( L + 24 \)[/tex] gives the width as 72 inches. Therefore, the dimensions of the screen are 48 inches by 72 inches.

Answer:

4,000

Step-by-step explanation:

Answer:

Probability that a marble drawn at random is not red = [tex]\frac{2}{3}[/tex].

Step-by-step explanation:

Given : A jar contains 3 red, 4 blue, and 2 white marbles.

To find  : What is the probability that a marble drawn at random is not red.

Solution : We have given that

Red marbles = 3.

White marbles = 2.

Blue marbles = 4

Total marbles = 9

Marbles that are not red = white + blue =2+4 = 6.

Probability that a marble drawn at random is not red = [tex]\frac{Number\ of\ marbles\ not\ red}{Total\ that\  number\ of\ marbles}[/tex].

Probability that a marble drawn at random is not red = [tex]\frac{6}{9}[/tex].

Probability that a marble drawn at random is not red = [tex]\frac{2}{3}[/tex].

Therefore, Probability that a marble drawn at random is not red = [tex]\frac{2}{3}[/tex].

Answer:

The answer above me is correct

Step-by-step explanation:

Cause he big brain

Final answer:

In this high school math question, you will solve for the dimensions of a gift bag shaped like a rectangular prism using the given volume and expressions for width, length, and height.

Explanation:

The volume of a rectangular prism is given by the formula V = lwh, where l is the length, w is the width, and h is the height. In this case, the volume of the gift bag is 1152 cubic inches, so we have 1152 = w(2w+4)(18-w).

Solving this equation leads to w = 8, which means the width is 8 inches, length is 20 inches, and height is 10 inches.

Therefore, the dimensions of the gift bag are 8 inches width, 20 inches length, and 10 inches height.

30 degrees / 360 degrees = 0.0833

0.0833 * 96 = 8

 answer is 8π m²

The area of a [tex]30^{\circ}[/tex] sector of this circle is [tex]8\pi \ m^2[/tex]. The correct option is B. [tex]8\pi \ m^2[/tex].

The area of circle is [tex]96 \pi \ m^2[/tex].

We have to calculate the area of [tex]30^{\circ}[/tex] sector of this circle.

We know that, Area of circle is,

[tex]A=\pi r^{2}[/tex]

Here, [tex]96\pi =\pi r^{2}[/tex]

Or,

[tex]r^{2} =96[/tex]

[tex]r=\sqrt{96}[/tex]

[tex]r=4\sqrt{6}[/tex]

So, radius of the circle,  

[tex]r=4\sqrt{6}[/tex] [tex]m[/tex].

Now we know that Area of a Sector of Circle

Say [tex]A_{1}[/tex],

[tex]A_{1} = \frac{\Theta}{360} \pi r^{2}[/tex]  

where [tex]\Theta[/tex]  is the angle subtended at the center, given in degrees, and '[tex]r[/tex]' is the radius of the circle.

So,

[tex]A_{1} =\frac{30}{360} \pi (4\sqrt{6} )^{2}[/tex]

[tex]A_{1} =\frac{1}{12} \pi \times96[/tex]

[tex]A_{1} =8\pi \ m^2[/tex].

Hence the area of a [tex]30^{\circ}[/tex] sector of this circle is [tex]8\pi \ m^2[/tex]. the correct option is B [tex]8\pi \ m^2[/tex].

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Answer: B

Step-by-step explanation:

just did on edge

Answer:

the answer is 1/4

Step-by-step explanation:

Alright to solve it

Part A)

C = 1.5  

F =1

You will need to solve it for volume= length times width and times height

3.14 x 1^2 x 1.5

The answer you will get is 5 in^3

Part B)  Just do the same proccess as i did on the first one

CV= 192 in^3

Part C)

C=36x5in^3

So this is going to be 180 in^3 because is the less volume.

Hope this helps

Tobey

Answer:

B) 72 sq in

Step-by-step explanation:

The maximum size of the picture that can fit into the frame must be equivalent to the area of the shape. Given that the frame is 9 in x 8 in, it may be safe to conclude that the frame is a 4 sides plane shape, a rectangle.

The area of a rectangle is given as the product of it's length and breadth, which are 9 in and 8 in respectively. Hence, maximum area the picture can have to fit in the frame

= 9 in * 8 in

= 72 sq in