A photoconductor film is manufactured at a nominal thickness of 25 mils. The product engineer wishes to increase the mean speed of the film, and believes that this can be achieved by reducing the thickness of the film to 20 mils. Eight samples of each film thickness are manufactured in a pilot production process, and the film speed (in microjoules per square inch) is measured. For the 25-mil film the sample data result is x1 = 1.17 and s1 = 0.11 , while for the 20-mil film, the data yield x2 = 1.04 and s2 = 0.09 . Note that an increase in film speed would lower the value of the observation in microjoules per square inch.

Do the data support the claim that reducing the film thickness increases the mean speed of the film? Use alpha=0.05

Answers

Answer 1

Answer:

[tex]t=\frac{1.17-1.04}{\sqrt{\frac{0.11^2}{8}+\frac{0.09^2}{8}}}}=2.587[/tex]  

[tex]df=n_{1}+n_{2}-2=8+8-2=14[/tex]

Since is a one sided test the p value would be:

[tex]p_v =P(t_{(14)}>2.587)=0.0108[/tex]

If we compare the p value and the significance level given [tex]\alpha=0.05[/tex] we see that [tex]p_v<\alpha[/tex] so we can conclude that we have enough evidence to reject the null hypothesis, we have enough evidence to reject the null hypothesis on this case and the 25 mil film have a mean greater than the 20 mil film so then the claim is not appropiate

Step-by-step explanation:

Data given and notation

[tex]\bar X_{1}=1.17[/tex] represent the mean for the sample 1 (25 mil film)

[tex]\bar X_{2}=1.04[/tex] represent the mean for the sample 2 (20 mil film)

[tex]s_{1}=0.11[/tex] represent the sample standard deviation for the sample 1

[tex]s_{2}=0.09[/tex] represent the sample standard deviation for the sample 2

[tex]n_{1}=8[/tex] sample size selected for 1

[tex]n_{2}=8[/tex] sample size selected for 2

[tex]\alpha=0.05[/tex] represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

[tex]p_v[/tex] represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if reducing the film thickness increases the mean speed of the film, the system of hypothesis would be:

Null hypothesis:[tex]\mu_{1} \leq \mu_{2}[/tex]

Alternative hypothesis:[tex]\mu_{1} > \mu_{2}[/tex]

If we analyze the size for the samples both are less than 30 so for this case is better apply a t test to compare means, and the statistic is given by:

[tex]t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}[/tex] (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

[tex]t=\frac{1.17-1.04}{\sqrt{\frac{0.11^2}{8}+\frac{0.09^2}{8}}}}=2.587[/tex]  

P-value

The first step is calculate the degrees of freedom, on this case:

[tex]df=n_{1}+n_{2}-2=8+8-2=14[/tex]

Since is a one sided test the p value would be:

[tex]p_v =P(t_{(14)}>2.587)=0.0108[/tex]

If we compare the p value and the significance level given [tex]\alpha=0.05[/tex] we see that [tex]p_v<\alpha[/tex] so we can conclude that we have enough evidence to reject the null hypothesis, we have enough evidence to reject the null hypothesis on this case and the 25 mil film have a mean greater than the 20 mil film so then the claim is not appropiate


Related Questions

An experiment consists of 8 independent trials where the probability of success on each trial is 3 8 . Find the probability of obtaining the following. Round answers to the nearest ten-thousandth. 13. Exactly 3 successes. 14. Exactly 6 successes. 15. Exactly 1 success. 16. Exactly 5 successes. 17. At least 1 success. 18. At least 2 successes. 19. At least 6 successes. 20. At least 7 successes. 21. At most 7 successes. 22. At most 6 successes

Answers

Answer:

Step-by-step explanation:

This is a binomial distribution because the probabilities are either that of success or failure.

If probability of success, p = 3/8 = 0.375, then probability of failure, q = 1 - p = 1 - 0.375 = 0.625

The formula is expressed as

P(x = r) = nCr × p^r × q^(n - r)

Where

x represent the number of successes.

p represents the probability of success.

q = represents the probability of failure.

n represents the number of trials or sample.

n = 8

13) P(x = 3) = 8C3 × 0.375^3 × 0.625^(8 - 3) = 0.28

14) P(x = 6) = 8C6 × 0.375^6 × 0.625^(8 - 6) = 0.03

15) P(x = 1) = 8C1 × 0.375^1 × 0.625^(8 - 1) = 0.11

16) P(x = 5) = 8C5 × 0.375^5 × 0.625^(8 - 5) = 0.1

17) P(x ≥ 1) = 1 - P(x < 1)

P(x < 1) = P(x = 0)

P(x = 0) = 8C0 × 0.375^0 × 0.625^(8 - 0) = 0.023

P(x ≥ 1) = 1 - 0.023 = 0.977

18) P(x ≥2) = 1 - P(x < 2)

P(x < 2) = P(x = 0) + P(x = 1)

P(x = 0) = 8C0 × 0.375^0 × 0.625^(8 - 0) = 0.023

P(x = 1) = 8C1 × 0.375^1 × 0.625^(8 - 1) = 0.11

P(x ≥ 2) = 1 - (0.023 + 0.11) = 0.867

19) P(x ≥ 6) = P(x = 6) + P(x = 7) + P(x = 8)

P(x = 6) = 8C6 × 0.375^6 × 0.625^(8 - 6) = 0.03

P(x = 7) = 8C7 × 0.375^7 × 0.625^(8 - 7) = 0.005

P(x = 8) = 8C8 × 0.375^8 × 0.625^(8 - 8) = 0.0004

P(x ≥ 6) = 0.03 + 0.005 + 0.0004 = 0.0354

20) P(x ≥ 7) = P(x = 7) + P(x = 8)

P(x ≥ 7) = 0.005 + 0.0004 = 0.0054

21) P(x ≤ 6) = 1 - P(x = 8)

P(x ≤ 6) = 1 - 0.0004 = 0.9996

22) P(x ≤ 6) = 1 - [P(x = 7) + P(x = 8)]

P(x ≤ 6) = 1 - (0.005 + 0.0004) = 0.9946

The probabilities are listed below:

The probability of success of exactly 3 successes is 5.27 %.The probability of success of exactly 6 successes is 0.28 %.The probablity of success of exactly 1 success is 37.5 %.The probablity of success of exactly 5 successes is 0.74 %.The probability of success of at least 1 success is at most 37.5 %.The probability of success of at least 2 successes is at most 14.1 %.The probablity of success of at least 6 successes is at most 0.28 %.The probability of success of at least 7 successes is at most 0.10 %. The probability of success of at most 7 successes is at least 0.10 %.The probability of success of at most 6 successes is at least 0.28 %.

If each trial represents an independent event, then the probability of success of a given number of consecutive trials ([tex]p_{T}[/tex]) in defined by the following formula:

[tex]p_{T} = p^{n}[/tex] (1)

Where:

[tex]p[/tex] - Success probability for a sole event.[tex]n[/tex] - Number of consecutive events.

If we know that [tex]p = \frac{3}{8}[/tex], then the probabilities associated to a given number of trials:

1) 3 successes

[tex]p_{3} = \left(\frac{3}{8} \right)^{3}[/tex]

[tex]p_{3} = \frac{27}{512}[/tex]

The probability of success of exactly 3 successes is 5.27 %.

2) 6 successes

[tex]p_{6} = \left(\frac{3}{8} \right)^{6}[/tex]

[tex]p_{6} = \frac{729}{262144}[/tex]

The probability of success of exactly 6 successes is 0.28 %.

3) 1 success

[tex]p_{1} = \frac{3}{8}[/tex]

The probablity of success of exactly 1 success is 37.5 %.

4) 5 successes

[tex]p_{5} = \left(\frac{3}{8} \right)^{5}[/tex]

[tex]p_{5} = \frac{243}{32768}[/tex]

The probablity of success of exactly 5 successes is 0.74 %.

5) At least 1 success

The probability of success of at least 1 success is at most 37.5 %.

6) At least 2 successes

The probability of success of at least 2 successes is at most 14.1 %.

7) At least 6 successes

The probablity of success of at least 6 successes is at most 0.28 %.

8) At least 7 successes

The probability of success of at least 7 successes is at most 0.10 %.

9) At most 7 successes

The probability of success of at most 7 successes is at least 0.10 %.

10) At most 6 successes

The probability of success of at most 6 successes is at least 0.28 %.

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A survey is being conducted in a county where 62% of the voters are Democrats and 38% are Republican. (a) What is the probability that two independently surveyed voters would both be Democrats?

Answers

Answer:

0.3844 = 38.44% probability that two independently surveyed voters would both be Democrats

Step-by-step explanation:

For each voter, there are only two possible outcomes. Either the voter is a Democrat, or he is not. The probability of the voter being a Democrat is independent of other voters. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

62% of the voters are Democrats

This means that [tex]p = 0.62[/tex]

(a) What is the probability that two independently surveyed voters would both be Democrats?

This is P(X = 2) when n = 2. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 2) = C_{2,2}.(0.62)^{2}.(0.38)^{0} = 0.3844[/tex]

0.3844 = 38.44% probability that two independently surveyed voters would both be Democrats

whats the ratio of 14,10 and 4

Answers

Step-by-step explanation:

14 : 10 : 4

Divide it by 2

7 : 5 : 2

This is the simplest form because it cannot be divided further

Write a quadratic function f whose zeros are 3 and -6.

Answers

Answer:

(x+3) (x-6) = 0

Step-by-step explanation:

A quadratic equation is in the form of ax²+bx+c. The quadratic function whose zeros are 3 and -6 is (x² + 3x - 18).

What is a quadratic equation?

A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers. It is written in the form of ax²+bx+c.

Given that the quadratic function whose zeros are 3 and -6. Therefore, the  quadratic function can be written as,

(x-3)(x+6)

= x² + 6x - 3x -18

= x² + 3x - 18

Hence, the quadratic function whose zeros are 3 and -6 is (x² + 3x - 18).

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The difference between 12 and 1/3 of a number is 18.

Answers

Answer:

90

Step-by-step explanation:

work backwards, (18+12)3= 90

Plz brainliest :)

Answer:

90

Step-by-step explanation:

work backwards (18+12)3=90

hope it helps to you

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A company estimates that it will sell ????(x) units of a product after spending x thousand dollars on advertising, as given by ????(x)=−5x3+235x2−3400x+20000,10≤x≤40. (A) Use interval notation to indicate when the rate of change of sales ????′(x) is increasing. Note: When using interval notation in WeBWorK, remember that: You use 'I' for [infinity] and '-I' for −[infinity], and 'U' for the union symbol. If you have extra boxes, fill each in with an 'x'. ????′(x) increasing:

Answers

Answer:

[tex](11\frac{1}{3},20)[/tex]

Step-by-step explanation:

If the Number of Sales of x units, N(x) is defined by the function:

[tex]N(x)=-5x^3+235x^2-3400x+20000,10\leq x\leq 40[/tex]

[tex]N'(x)=-15x^2+470x-3400\\When -15x^2+470x-3400=0\\x=20, x=11\frac{1}{3}[/tex]

Next, we text the critical points and the end points of the interval to see where the derivative is increasing.

[tex]N'(10)=-200\\N'(11\frac{1}{3})=0\\N'(19)=115\\N'(20)=0\\N'(40)=-8600[/tex]

Thus, the rate of change of sales [tex]N'(x)[/tex] is increasing in the interval [tex](11\frac{1}{3},20)[/tex] on 10≤x≤40.

The rate of change is how much the company sales changes after spending

The rate of change increases at: (10, 20)

The function is given as:

[tex]\mathbf{f(x) = -5x^3 +235x^2 - 3400x + 20000}[/tex]

Differentiate, to calculate the rate of change

[tex]\mathbf{f'(x) = -15x^2 +470x- 3400}[/tex]

Set to 0

[tex]\mathbf{ -15x^2 +470x- 3400 = 0}[/tex]

Divide through by 5

[tex]\mathbf{ -3x^2 +94x- 680 = 0}[/tex]

Using a calculator, we have:

[tex]\mathbf{x = \{20,11.3\}}[/tex]

The domain is given as: [tex]\mathbf{10 \le x \le 40}[/tex]

When x = 10, we have:

[tex]\mathbf{f'(10) = -15(10)^2 +470(10)- 3400 = -200}[/tex]

When x = 11.3, we have:

[tex]\mathbf{f'(11.3) = -15(11.3)^2 +470(11.3)- 3400 = -4.35}[/tex]

When x = 20, we have:

[tex]\mathbf{f'(20) = -15(20)^2 +470(20)- 3400 = 0}[/tex]

When x = 40, we have:

[tex]\mathbf{f'(40) = -15(40)^2 +470(40)- 3400 = -8600}[/tex]

The value of f'(x) increases at x = 10 to 20.

Hence, the rate of change increases at: (10, 20)

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9 of the 13 participants in a triathlon are men and the rest are women. What is the ratio of the number of women participating to the total number of participants?

Answers

Final answer:

The ratio of the number of women to the total number of participants in the triathlon is 4:13.

Explanation:

The question is asking for the ratio of the number of women to the total number of participants in a triathlon. We know that there are 13 total participants and 9 of them are men. We can determine that there are 4 ladies by taking 9 out of 13. Therefore, the ratio of the number of women to the total number of participants is 4:13. This indicates that 4 women make up each of the 13 participants, according to our calculations.

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Which of the following statements is true?

A. A tangent is never a secant.
B. A secant is always a chord.
C. A chord is always a radius.
D. A diameter is never a chord.
Please select the best answer from the choices provided

Answers

Answer:

a tangent is never a secant

Step-by-step explanation:

the secant is in the circle

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Final answer:

The correct statement is A: 'A tangent is never a secant.' because it accurately describes that a tangent only touches the circle at one point and does not cross the circle's interior unlike a secant.

Explanation:

The question you've asked pertains to the geometric definitions of a tangent, secant, chord, and diameter in relation to a circle. Reviewing the options provided:

A tangent is a line that touches a circle at exactly one point and never enters the circle's interior, so it's distinct from a secant, which does enter the interior. Therefore, option A ('A tangent is never a secant.') is true.A secant is a line that intersects a circle at two points and always includes a chord, the segment between these two points, which makes option B ('A secant is always a chord.') incorrect as a secant is not a chord, it includes a chord.A chord is a segment whose endpoints lie on a circle, and it could be any length up to the length of the diameter; hence, option C ('A chord is always a radius.') is incorrect.A diameter is a special type of chord that passes through the center of the circle and its longest possible chord. So, option D ('A diameter is never a chord.') is incorrect.

Given these explanations, the best answer from the choices provided is in fact option A.

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What is the volume of a sphere with a radius of 6 mm?

Answers

Maybe 6 but I’m not sure.

give an equation of the form f(x)=a^x to define the exponential function whose graph contains the point (3,8)

Answers

Answer:

f(x) = 2^x

Step-by-step explanation:

Solve for a.  At point (3,8), x = 3, f(x) = 8

Plugging into the equation it becomes 8 = a^3

a = [tex]\sqrt[3]{8}[/tex]

a = 2

The exponential function is [tex]\boldsymbol{f(x)=2^x}[/tex].

Exponential Function

A mathematical function of the form [tex]\boldsymbol{f(x)=a^x}[/tex] is an exponential function. where [tex]x[/tex] is a variable and [tex]a[/tex] is a constant known as the function's base.

Put [tex](x,f(x))=(3,8)[/tex] in the given exponential function.

[tex]8=a^3\\2^3=a^3\\a=2[/tex]

So, the exponential function is [tex]\boldsymbol{f(x)=2^x}[/tex]

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Which simplified fraction is equal to 0.53?

Answers

Answer:

53/100?

Step-by-step explanation:

I mean you can't really simplify it any more. There's no LCD, GCD. Can't divide it evenly.

To solve it I just looked at the number of places, (3 which mean 100.)

Then I looked at the numbers, (53.)

So you just turn that into a fraction...

Answer:

well there are many ways to but id say 8/15

Step-by-step explanation:

Problem 2.2 (20 points)Black and yellow pigment cells (melanophores and xanthophores) are responsible for patterns onthe skin of Zebra Fish. We denote the number of melanophores at timetbyM(t) and the numberof xanthophores at timetbyX(t). Suppose that 10% of melanophores become (differentiate into)xanthophores per unit time. Conversely, 40% of xanthophores become melanophores per unit time,and 10% of xanthophores die per unit time. Finally, 10 melanophores and 20 xanthophores areborn per unit time.1. DefineP(t)

Answers

Your question is not complete as you have not provided some details.

Please let me assume this to complete your question;

P(t) = M(t) ÷ X(t)

ANSWER:

P(t) is the ratio of the number of melanophores to the number of xanthophores per unit time.

Therefore P(t) = 1.55

Step-by-step explanation:

KEY NOTE:

I) 10% of melanophore converts to Xanthophore per unit time.

II) 40% of Xanthophore converts to melanophore per unit time.

III) 10 melanophore and 20 Xanthophore are born per unit time

IV) 10% of Xanthophore die per unit time.

STEP 1: Conversion rate to number of birth per unit time.

For M(t) 10% of 10 = 1

For X(t) 40% of 20 = 8

Therefore;

M(t) = 10 + 8 - 1 = 17

X(t) = 20 + 1 - 8 = 13

STEP 2:

10% of Xanthophore die per unit time.

10% of 20 = 2

Therefore X(t) is;

13 - 2 = 11

The total X(t) = 11

The total M(t) = 17

P(t) = M(t)/X(t) = 17÷ 11 = 1.55

A triangular pyramid. The triangular base has a height of 8 units and base of 12 units. 2 sides have a base of 10 and height of 14. 1 side has a base of 12 and height of 13.6. Find the surface area of the pyramid. The triangular base has a height of 8 units and a base of 12 units. What is the base area? What is the lateral area? What is the surface area?

Answers

Base area of the triangular pyramid is 96 square units.

Lateral surface area of the triangular pyramid is 221.6 square units.

Surface area of the triangular pyramid is 317.6 square units.

Step-by-step explanation:

Base area = 8 x 12

= 96 square units

Base area of the triangular pyramid is 96 square units.

Lateral surface area = 2[(1/2) 10x 14] + (1/2) (12 x 13.6)

= 2(70) +81.6

= 140 + 81.6

= 221.6 square units

Lateral surface area = 221.6 square units

Lateral surface area of the triangular pyramid is 221.6 square units.

Surface area= 221.6 + 96

= 317.6 square units

Surface area of the triangular pyramid is 317.6 square units.

Answer:

the right answer is 48,221.6,269.6

Step-by-step explanation:

Find the domain for f(x)=x^2+3x+2

Answers

Answer:

  all real numbers: -∞ < x < ∞

Step-by-step explanation:

Any polynomial function is defined for all real numbers. This one is, too.

The domain is ...

  -∞ < x < ∞

_____

Additional comment

Polynomial functions are often used to model things in the real world. One common application is the use of a quadratic function to model ballistic motion (height versus time). Such functions are defined for all values of the independent variable (time), but only have practical application over a smaller domain (time and height ≥ 0). Any question of domain might need to consider the practical domain, where the function is useful.

As part of a fundraiser, a local charity has sold 6 raffle tickets,

with a goal of selling 140 tickets. What percentage of the goal has been sold? (Round to the nearest tenth of a percent, if necessary).

Answers

Answer:

4.3%

Step-by-step explanation:

[tex]selling \: percent \\ = \frac{6}{140} \times 100 \\ \\ = \frac{60}{14} \\ \\ = 4.28 \\ = 4.3\% \\ [/tex]

As per linear equation, 4.3% of tickets are sold of the goal.

What is a linear equation?

"A linear equation is an equation in which the highest power of the variable is always 1."

Given, a local charity has sold 6 raffle tickets.

The goal of selling tickets is 140.

Therefore, the percentage of sold tickets is

[tex]= \frac{6}{140}[/tex] ×100%

[tex]= 4.3[/tex]%

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Six pounds of grapefruit costs 3 dollars 5 pound of apples cost 2.65. What is the cost per pound for each fruit ?

Answers

Answer:

We need to find the unit rates for the fruit. To do this, divide the cost by the number of pounds

Grapefruit:

cost/pounds

$3/6 pounds

3/6=0.5

0.5 per pound

Apples:

cost/pounds

$2.65/5 pounds

2.65/5=0.53

0.53 per pound

Find the period, range, and amplitude of the cosine function y= 3/2cos t/2

Answers

Answer:

[tex]Amplitude = /\frac{3}{2}/[/tex]

[tex]Range = [\frac{-3}{2} , \frac{3}{2}][/tex]

[tex]Period = \pi[/tex]

Step-by-step explanation:

Given: [tex]y = \frac{3}{2}cos\frac{t}{2}[/tex]

Comparing the equation with the standard form of cosine function :

[tex]y = A cos(Bx- C)[/tex]

where:

[tex]A = Amplitude[/tex]

Formula for calculating Amplitude is given as:

[tex]Amplitude = /A/[/tex]

The formula for calculating Period is given as :

[tex]Period =\frac{2\pi }{B}[/tex]

[tex]B = \frac{1}{2}[/tex]

Therefore , with the comparison

[tex]A = /\frac{3}{2}/[/tex]

which means that:

[tex]Range = \frac{-3}{2} , \frac{3}{2}[/tex]

[tex]Period = \frac{2\pi }{2}[/tex]

[tex]Period = \pi[/tex]

A quality-control inspector rejects any shipment of printed circuit boards whenever 3 or more defectives are found in a sample of 50 boards tested. Find the (1) expected number defective and (2) the probability of rejecting the shipment when the proportion of defectives in the entire shipment is


(a) Proportion of Defectives=0.01


Expected Number Defective=



Probability of Rejecting the Shipment=


(b) Proportion of Defectives=0.05


Expected Number Defective=

Probability of Rejecting the Shipment=


(c) Proportion of Defectives=0.1


Expected Number Defective=

Probability of Rejecting the Shipment=

Expert

Answers

Answer:

(a) Proportion of Defectives = 0.01

Expected Number Defective = 0.5

Probability of Rejecting the Shipment = 0.0138

(b) Proportion of Defectives = 0.05

Expected Number Defective = 2.5

Probability of Rejecting the Shipment = 0.459

(c) Proportion of Defectives = 0.1

Expected Number Defective = 5

Probability of Rejecting the Shipment = 0.888

Step-by-step explanation:

This is a binomial distribution problem due to the unchanging probability of getting a defective board, no matter the number of trials ran.

The expected number for binomial distribution is given as E(X) = np

The probability mass funaction for binomial distribution is given as

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

n = total number of sample spaces = 50

x = Number of successes required = ≥3

p = probability of success = changing from question to question

q = probability of failure = 1 - p

Total number of boards tested = 50

Note that probability of rejecting the shipment for each of the sub-question is the probability that 3 or more boards are defective. That is, P(X ≥ 3)

P(X ≥ 3) = 1 - P(X < 3) = 1 - [P(X=0) + P(X=1) + P(X=2)]

a) Proportion of Defectives=0.01

Expected Number Defective = np = 0.01 × 50 = 0.5

Probability of Rejecting the Shipment = P(X ≥ 3)

n = total number of sample spaces = 50

p = probability of success = probability of a detective board = 0.01

q = probability of failure = 1 - 0.01 = 0.99

P(X ≥ 3) = 1 - P(X < 3) = 1 - [P(X=0) + P(X=1) + P(X=2)] = 0.01381727083 = 0.0138

b) Proportion of Defectives = 0.05

Expected Number Defective = np = 0.05 × 50 = 2.5

Probability of Rejecting the Shipment = P(X ≥ 3)

n = total number of sample spaces = 50

p = probability of success = probability of a detective board = 0.05

q = probability of failure = 1 - 0.05 = 0.95

P(X ≥ 3) = 1 - P(X < 3) = 1 - [P(X=0) + P(X=1) + P(X=2)] = 0.45946687728 = 0.459

c) Proportion of Defectives = 0.1

Expected Number Defective = np = 0.1 × 50 = 5

Probability of Rejecting the Shipment = P(X ≥ 3)

n = total number of sample spaces = 50

p = probability of success = probability of a detective board = 0.1

q = probability of failure = 1 - 0.1 = 0.90

P(X ≥ 3) = 1 - P(X < 3) = 1 - [P(X=0) + P(X=1) + P(X=2)] = 0.88827124366 = 0.888

Hope this Helps!!!

Conceptual Set 1. The same researcher wants to then compare the final (time 2) levels of anger in this experimental group to a control group that just had the water balloons thrown at them. He compares the group from the previous questions to a group who did not do pushups. Which t-test should he use?

QUESTION 55-Conceptual Set 1. Why should the researcher from question 54 use that test?


A.Because single sample t-tests compare a sample mean to a population mean, which is what the researcher is attempting to do
B. Because single sample t-tests compare scores before and after an event, which is what the researcher isattempting to do
C. Because single sample t-tests compare two completely different groups in a sample, which is what the researcher is attempting to do
D. Because paired samples t-tests compare a sample mean to a population mean, which is what the researcher is attempting to do
E. Because paired samples t-tests compare scores before and after an event, which is what the researcher is attempting to do
F. Because paired samples t-tests compare two completely different groups in a sample, which is what the researcher is attempting to do
G. Because independent sample t-tests compare a sample mean to a population mean, which is what the researcher is attempting to do
H. Because independent sample t-tests compare scores before and after an event, which is what the researcher is attempting to do
I. Because independent sample t-tests compare two completely different groups in a sample, which is what the researcher is attempting to doA

Answers

Answer:

I

Step-by-step explanation:

Because independent sample t-tests compare two completely different groups in a sample, which is what the researcher is attempting to do.

I REALLY NEED HELP WITH THIS!! I'VE BEEN TRYING TO SOLVE IT FOR SO LONG!!

THANK YOU AND STAY SAFE!!

Answers

Answer:

44

Step-by-step explanation:

The discriminant is b^2-4ac
In this example, a is 5
B is 2
C is -2


2^2-4*5*-2
So the discriminant is 44

If Serena painted all the faces of the piece of the model, including the base, what area did she paint?

Answers

Answer:

is there any measurements included?

Step-by-step explanation:

Final answer:

The question mainly discusses the artistic attributes and historical aspects of a sculpture, including descriptions of paint used, rather than providing information needed to calculate the area painted.

Explanation:

The question provided does not directly relate to computing the area painted as it mostly describes the artistic characteristics and historical context of a sculpture. It talks about the sculpture's features, color schemes used for painting such as black hair, red and blue dress with a yellow belt, and the use of paint on the sculpture's body and face.

To calculate the area painted, one would ideally need the dimensions of each face of the model or sculpture to sum up their areas if it were a geometric problem in Mathematics. However, the question mainly focuses on the art critique, interpretation, and visual description of the sculpture, highlighting its historical significance and the artistic techniques employed.

A certain bowler can bowl a strike 85 % of the time. What is the probability that she ​a) goes three consecutive frames without a​ strike? ​b) makes her first strike in the third ​frame? ​c) has at least one strike in the first three ​frames? ​d) bowls a perfect game​ (12 consecutive​ strikes)?

Answers

Final answer:

The probability calculations for the bowler indicate that she has a 0.33% chance of not getting a strike for three consecutive frames, a 1.9% chance of getting her first strike in the third frame, a 99.66% chance of getting at least one strike in the first three frames, and a 3.4% chance of bowling a perfect game.

Explanation:

The subject here is probability, with the scenario provided being that a bowler can strike 85% of the time. We assume that all strikes are independent events, meaning one strike does not affect the probability of the next strike.

a) Probability of no strike in three consecutive frames:

The probability of her not getting a strike in one turn is 1 - 0.85 = 0.15 (the complement of her strike rate). For three consecutive frames without a strike, we multiply these probabilities because of their independence: 0.15 * 0.15 * 0.15 = 0.003375 or 0.33%.

b) Probability of first strike in the third frame:

This means not striking in the first two frames and getting a strike in the third. Calculate this by multiplying the probabilities: 0.15 * 0.15 * 0.85 = 0.01912 or 1.9%.

c) Probability of at least one strike in three frames:

This is best calculated by subtracting the probability of no strikes in 3 frames (found in part a) from 1, as it is the complement: 1 - 0.003375 = 0.996625 or 99.66%.

d) Probability of a perfect game:

A perfect game requires 12 consecutive strikes. Multiply the probability of a strike (0.85) by itself 12 times : 0.85^12 = 0.034 (3.4% chance of a perfect game).

Learn more about probability here:

https://brainly.com/question/32117953

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The step-by-step probabilities for varying scenarios in a bowling game are: a) 0.003375 for no strikes in three frames, b) 0.019125 for the first strike in the third frame, c) 0.996625 for at least one strike in three frames, and d) 0.1489 for a perfect game.

Probability Calculations for a Bowler

A certain bowler has an 85% chance of bowling a strike. Let's break down each part of the question:

a) Probability of three consecutive frames without a strike

The probability of not getting a strike in one frame is 1 - 0.85 = 0.15. Therefore, the probability of not getting a strike in three consecutive frames is:

(0.15) × (0.15) × (0.15) = 0.003375

b) Probability of making the first strike in the third frame

The probability of not getting a strike in the first two frames but getting a strike in the third frame is:

(0.15) × (0.15) × (0.85) = 0.019125

c) Probability of at least one strike in the first three frames

First, find the probability of no strikes in three frames, which we've already calculated as 0.003375. Therefore, the probability of at least one strike is:

1 - 0.003375 = 0.996625

d) Probability of a perfect game (12 consecutive strikes)

The probability of getting a strike in each of the 12 frames is:

(0.85)¹² = 0.1489

Insert the greater than, less than, or equal sign (>, <, or =) to make each statement true.
a. 45⁄45 ____1
b. 1____ 6⁄3
c. 2⁄7 ____1
d. 64⁄23 ____1

Answers

=.6/3=2 so 2 is greater than1 .1 is greater.1 is greater.

hope it helps to you

what is a numerators characteristics

Answers

The number above the line is the numerator
The line above isstraight and has numbers

A random sample of 81 automobiles traveling on a section of an interstate showed an average speed of 60 mph. The distribution of speeds of all cars on this section of highway is normally distributed, with a standard deviation of 13.5 mph.

The value to use for the standard error of the mean is:

1.13.5
2.9
3.2.26
4.1.5

Answers

Answer:

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

[tex]X \sim N(60,13.5)[/tex]  

Where [tex]\mu=60[/tex] and [tex]\sigma=13.5[/tex]

And for this case we select a sample size of n= 81. Since the distribution for X is normal then we know that the distribution for the sample mean [tex]\bar X[/tex] is given by:

[tex]\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})[/tex]

And the standard error of the mean would be:

[tex]\sigma_{\bar X} =\frac{13.5}{\sqrt{81}}= 1.5[/tex]

4.1.5

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

[tex]X \sim N(60,13.5)[/tex]  

Where [tex]\mu=60[/tex] and [tex]\sigma=13.5[/tex]

And for this case we select a sample size of n= 81. Since the distribution for X is normal then we know that the distribution for the sample mean [tex]\bar X[/tex] is given by:

[tex]\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})[/tex]

And the standard error of the mean would be:

[tex]\sigma_{\bar X} =\frac{13.5}{\sqrt{81}}= 1.5[/tex]

4.1.5

The standard error of the mean for the sample of automobiles is 1.5 mph ,i.e, option 4, which is found by dividing the standard deviation, 13.5 mph, by the square root of the sample size, 9, because the sample size is 81 vehicles.

The standard error of the mean (SEM) is the standard deviation ()divided by the square root of the sample size (n). For the given data, with a sample size of 81 automobiles and a standard deviation of 13.5 mph, the standard error of the mean can be calculated as follows:

SEM = 13.5 /  81 = 13.5 / 9 = 1.5 mph

Therefore, the value for the standard error of the mean is 1.5.

what is the slope of the line that is parallel ^

Answers

Given:

Given that the equation of the line is [tex]y=2x-4[/tex]

We need to determine the slope of the line.

Slope:

The general form of the equation of the line is [tex]y=mx+c[/tex] where m is the slope of the line.

Comparing the equation [tex]y=2x-4[/tex] with the general form of the equation of the line, we get;

Slope = m = 2.

Hence, the slope is 2.

Since, we need to determine the slope of the parallel lines and we know that the slope of the parallel lines are equal.

Thus, the slope of the parallel line is 2.

Hence, Option B is the correct answer.

A student planning her curriculum for the upcoming year must select one of six business courses, one of three mathematics courses, two of eight elective courses, and either one of three history courses or one of two social science courses. How many different curricula are available for her consideration?

Answers

Answer: Four Curricula

Step-by-step explanation:

Business

Mathematics

History

Social Science

Answer:

Four Curricula

Natalie is cutting construction paper into rectangles for a project. She needs to cut one rectangle that is 6 inches x 13 1/2 inches. She needs to cut another rectangle that is 10 1/3 inches by 10 1/2 inches. How many total square inches of construction paper does Natalie need for her project?

Answers

Final answer:

To find the total area of the construction paper needed for Natalie's project, multiply the length by the width of each rectangle and add them together.

Explanation:

To find the total area of the construction paper needed for Natalie's project, we need to find the area of each rectangle and then add them together.

Rectangle 1:

Length = 6 inches and width = 13 1/2 inches.

To find the area, multiply the length by the width: 6 inches x 13 1/2 inches = 81 square inches.

Rectangle 2:

Length = 10 1/3 inches and width = 10 1/2 inches.

To find the area, multiply the length by the width: 10 1/3 inches x 10 1/2 inches = 108 1/3 square inches.

Total area:

Add the areas of both rectangles: 81 square inches + 108 1/3 square inches = 189 1/3 square inches.

Therefore, Natalie needs a total of 189 1/3 square inches of construction paper for her project.

Natalie needs a total of 149 square inches of construction paper for her project.

To find the total square inches of construction paper needed for Natalie's project, we calculate the area of each rectangle and then add them together.

1. Area of the first rectangle:

[tex]\( \text{Area}_1 = \text{length} \times \text{width} = 6 \times 13\frac{1}{2} \) square inches.[/tex]

2. Area of the second rectangle:

[tex]\( \text{Area}_2 = \text{length} \times \text{width} = 10\frac{1}{3} \times 10\frac{1}{2} \) square inches.[/tex]

3. Calculate the total area:

  Total area = Area of first rectangle + Area of second rectangle.

Let's compute:

1. [tex]\( \text{Area}_1 = 6 \times 13\frac{1}{2} = 6 \times \frac{27}{2} = \frac{81}{2} = 40.5 \) square inches.[/tex]

2. [tex]\( \text{Area}_2 = 10\frac{1}{3} \times 10\frac{1}{2} = \frac{31}{3} \times \frac{21}{2} = \frac{651}{6} = 108.5 \) square inches.[/tex]

3. Total area = 40.5 + 108.5 = 149 square inches.

So, Natalie needs a total of 149 square inches of construction paper for her project.

A simple random sample of 100 bags of tortilla chips produced by Company X is selected every hour for quality control. In the current sample, 18 bags had more chips (measured in weight) than the labeled quantity. The quality control inspector wishes to use this information to calculate a 90% confidence interval for the true proportion of bags of tortilla chips that contain more than the label states.
1. What is the value of the standard error of the sample proportion?
a. 0.038
b. 384
c. 0.0015
d. 0.063

Answers

Answer:

Option A) 0.038

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 100

Number of of bags of tortilla chips that contain more than the label states, x = 18

Sample proportion:

[tex]\hat{p} = \dfrac{x}{n} = \dfrac{18}{100} = 0.18[/tex]

Formula for standard of error:

[tex]\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}[/tex]

Putting the values, we get:

[tex]\sqrt{\dfrac{0.18(1-0.18)}{100}} =0.038[/tex]

Thus, the correct answer is

Option A) 0.038

The starting salary of business students in a university is known to be normally distributed. A random sample of 18 business students results in a mean salary of $46,500 with a standard deviation of $10,200. Construct the 90% confidence interval for the mean starting salary of business students in this university.

Answers

46,500 +/- 1.740(10,200/√18)
Hope this helps
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