A plane intersects one cone of a double-napped cone such that the plane is neither parallel to the generating line nor perpendicular to the axis. What conic section is formed?
circle
hyperbola
ellipse
parabola

Answers

Answer 1
The conic section formed is an ...
  ellipse
A Plane Intersects One Cone Of A Double-napped Cone Such That The Plane Is Neither Parallel To The Generating
Answer 2
C is most likely the answer.

Hope this Helped!

;D

Related Questions

Divide £770 in the ratio of 4:3 plsss

Answers

we'll simply divide the amount by 4+3, namely 770 ÷ (4+3) and split the amounts accordingly,

[tex]\bf 4:3\qquad \cfrac{4}{3}\qquad \cfrac{4\cdot \frac{770}{4+3}}{3\cdot \frac{770}{4+3}}\implies \cfrac{4\cdot 110}{3\cdot 110}\implies \cfrac{440}{330}[/tex]

What is the value of c when the expression 21.2x + c is equivalent to 5.3(4x − 2.6)?

Answers

Hi there! The answer is c = - 13.78

To find our answer we need to work out the parenthesis. This is for instance possible using rainbow technique.

[tex]5.3(4x - 2.6) = \\ 5.3 \times 4x - 5.3 \times 2.6 = \\ 21.2x - 13.78[/tex]

Therefore the value of c = - 13.78.
~ Hope this helps you!
5.3(4x - 2.6) = 21.2x - 13.78
Comparing with 21.2x + c:-
the value of c = -13.78 Answer

Item 18 A spherical ball with a volume of 972π in.3 is packaged in a box that is in the shape of a cube. The edge length of the box is equal to the diameter of the ball. What is the volume of the box?

Answers

Volume of the given box is 5832 in³

Volume of the cube:

Given a spherical ball with a volume of 972π in.³,

Since the volume of a sphere is (4/3)πr³, we can find that the radius of the sphere is 9 inches.

The edge length of the cube (box) is twice the radius (diameter of the sphere), so the edge length of the cube is equal to 18 inches.

The volume of the cube is then (18³) in³

Volume of the cube = 5832 in³

The depth of a lake, dd, varies directly with rr, the amount of rainfall last month. if kk is the constant of variation, which equation represents the situation?

Answers

Given that the depth varies directly with amount of rainfall, then we shall have:
let d be the depth and r be the rainfall amount
dαr
thus
d=kr
where, k is the constant of proportionality, thus the formula will be:
d=kr

Chiara pays $21 for 3 DVDs that she finds in a one-price bin. Gunther wants to know how much he would spend for 1 DVD in this bin. Chiara wants to know how many dollars she will need to purchase 9 DVDs the next time she goes.

Answers

Gunther would spend $7 for 1 DVD. Chiara would need $63 for 9 DVD's
To figure out what one DVD would cost, we take our information "$21 for 3 DVD's." All you have to do here is do $21 divided by 3 DVD's to find that one DVD is $7.

If Chiara wants to purchase 9 DVD's next time and needs to know the money, we take our previous information (1 DVD = $7) and input it into this equation.

x (unknown dollars) = 9 (DVD) * 7 ($).

Meaning that 9 * 7 = 63.

It will cost $63 for 9 DVD's, when 1 DVD is $7.

Find the base area of a rectangular pyramid whose pyramid height is 5 cm and slant height of one side of the base is 13 cm and another side of the base is 7 cm.

a. 92√6 cm^2 
b. 96√6 cm^2 
c. 180√6 cm^2
d. 100√6 cm^2
e. 198√6 cm^2

Answers

Let
x------> the larger side of the rectangular base
y-------> the smaller side of the rectangular base

we know that
Applying the Pythagoras theorem

for the larger side of the base
slant height =13 cm
h=5 cm
13²=5²+(x/2)²-----> (x/2)²=13²-5²-----> 144
(x/2)²=144------> x/2=12------> x=24 cm

for the smaller side of the base
slant height =7 cm
h=5 cm
7²=5²+(y/2)²-----> (y/2)²=7²-5²-----> 24
(y/2)²=24------> y/2=√24------> y=4√6 cm

the area of the base is
24*4√6------> 96√6 cm²

the answer is the option
b. 96√6 cm^2 


There are 100 students in a drawing contest, and 58 of them are girls. What percent of the students in the contest are girls?

Answers

You take 58/100 and you’ll get your answer and you should get 58%

There are 100 students in a drawing contest and 58 of students are girls. What percent of students in the drawing contest are girls?

The fraction [tex]\frac{58}{100}[/tex] represents the number of girls in the drawing contest out of all the students.

To find out what percent of the students are in the drawing contest, we can change [tex]\frac{58}{100}[/tex] into a percent.

We can first reduce the fraction by dividing both the numerator and denominator by the Greatest Common Factor of 58 and 100 using 2.

58 ÷ 2 = 29

100 ÷ 2 = 50

Our reduced fraction is [tex]\frac{29}{50}[/tex].

29 ÷ 50 = 0.58

0.58 × 100 = 58%

Therefore, 58% of the students in the drawing contest are girls.

20 POINTS!

Verify the identity.

Answers

[tex]\dfrac{\cot x}{1+\csc x}=\dfrac{\csc x-1}{\cot x}\\\\L_s=\dfrac{\cos x}{\sin x}:\left(1+\dfrac{1}{\sin x}\right)=\dfrac{\cos x}{\sin x}:\left(\dfrac{\sin x}{\sin x}+\dfrac{1}{\sin x}\right)\\\\=\dfrac{\cos x}{\sin x}:\dfrac{\sin x+1}{\sin x}=\dfrac{\cos x}{\sin x}\cdot\dfrac{\sin x}{\sin x+1}=\dfrac{\cos x}{\sin x+1}[/tex]

[tex]R_s=\left(\dfrac{1}{\sin x}-1\right):\dfrac{\cos x}{\sin x}=\left(\dfrac{1}{\sin x}-\dfrac{\sin x}{\sin x}\right)\cdot\dfrac{\sin x}{\cos x}\\\\=\dfrac{1-\sin x}{\sin x}\cdot\dfrac{\sin x}{\cos x}=\dfrac{1-\sin x}{\cos x}\cdot\dfrac{1+\sin x}{1+\sin x}=\dfrac{1-\sin^2x}{\cos x(1+\sin x)}\\\\=\dfrac{\cos^2x}{\cos x(1+\sin x)}=\dfrac{\cos x}{1+\sin x} \\\\L_s=R_s[/tex]

[tex]Used:\\\csc x=\dfrac{1}{\sin x}\\\\\cot x=\dfrac{\cos x}{\sin x}\\\\\sin^2x+\cos^2x=1\to\cos^2x=1-\sin^2x\\\\(a-b)(a+b)=a^2-b^2[/tex]

Please help me out here.

Answers

An exponent rule that applies to this scenario:

When you multiply two exponents with the same base together, you can add the indexes together. For example, if you had y * y², you could make it y³, by adding the indexes of 2 and 1.

In this scenario, you can look at the last choice, where it has [tex] x^{9} [/tex] * x. You add the indexes of 9 and 1, to get [tex] \sqrt[3]{ x^{10} } [/tex]

That's equivalent to the equation given, so your answer would be the last choice.

Which compound inequality can be used to solve the inequality |3x+2|>7

Answers

Answer:

x>[tex]\frac{5}{3}[/tex].

Step-by-step explanation:

We have given an  inequality |3x+2|>7.

We need to solve this inequality |3x+2|>7, and find the compound which can solve this.

We know that,  inequality :

|3x+2|>7

Subtrating 2 from both sides,

|3x+2-2|>7-2

3x>5

Dividing by 3 both sides,

[tex]\frac{3x}{3} > \frac{5}{3}[/tex]

x>[tex]\frac{5}{3}[/tex]

Therefore, we can see that on the inequality |3x+2|>7, we find x>[tex]\frac{5}{3}[/tex] compound.

Answer:

D. 3x + 2 < –7 or 3x + 2 > 7

Step-by-step explanation:

Aaron solved an inequality and then graphed the solution as shown below. Anwser: A

A student found the solution below for the given inequality lx-9l less than 4

Anwser: D

Amber is solving the inequality lx+6l - 12 less than 13 by graphing. Which equations should Amber graph?

Anwser: A

What is the solution, if any, to the inequality l3xl greater than or equal to 0?

Anwser: A

Which compound inequality is equivalent to lax-bl greater than c  for all real numbers a, b, and c, where c is greater than or equal to 0?

Anwser: D

Which compound inequality is equivalent to the absolute value inequality lbl greater than 6?

Anwser: D

What is another way to write the absolute value inequality lpl less than or equal to 12?

Anwser: A

What is the solution to the inequality lx-4l less than 3?

Anwser: B

Which inequality is equivalent to lx-4l less than 9?

Anwser: B

Hope This Helps!

Two cities are 45 miles apart. Two trains, with speeds of 70 mph and 60 mph, leave the two cities at the same time so that one is catching up to the other. How long after the trains leave will they be 10 miles apart for the first time? How long after the trains leave will they be 10 miles apart for the second time?

Answers

Final answer:

The first time the two trains are 10 miles apart is approximately 16.15 minutes after they start. The second time they are 10 miles apart is about 25.38 minutes after they start.

Explanation:

This problem is a relative speed problem in mathematics, specifically in the subsection of algebra known as rate, time, and distance problems. To solve, you should consider that when the two trains move towards each other, their speeds add up. Hence, the relative speed of the two trains is 70 mph + 60 mph = 130 mph.

First, we need to figure out the time it would take for the trains to be 10 miles apart for the first time. This would be when they have collectively traveled 35 miles (45 miles initial separation - 10 miles final separation). To find the time it takes, we use the formula d=rt, where d is distance, r is rate or speed, and t is time. Here, time t = d/r = 35 miles / 130 mph = approximately 0.27 hours, which converts to about 16.15 minutes.

Next, to find the time when they are 10 miles apart for the second time, we need to consider when they have covered the total distance of 45 miles and then kept going until they've covered an additional 10 miles. This is a total of 55 miles. Again, using the time formula t = d/r, we get t = 55 miles / 130 mph = approximately 0.42 hours or about 25.38 minutes.

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use formulas to find the lateral and surface are of the given prism the numbers are 5.39m 26m 5m 2m 

Answers

3(24) + 2(24) + 5.39(24) = 72 + 48 + 129.36 = 249.36 ~ 249m^2 

Total Surface Area: 
(add to the above) 
2(1/2)(3)(2) = 6m^2 (area of the two triangles) 
6 + 149 = 155m^2 
The correct answer is 6 + 149 = 155m^2! Hope This Helps!

Using a straightedge, or using technology, sketch an obtuse, scalene triangle. Make sure to include your sketch in your answer.

Answers

Obtuse angles measure more than 90 degrees, scalene angles have three different side lengths. Would you like for me to include angle measure in the sketch?

The problem is in the first picture and the questions are in the second one. I have no idea how to do any of this.

Answers

Problem A
You are given that CB = 271 feet. You are also given that <CAB = 30 degrees.

So you can use Sin(<CAB) = opposite / hypotenuse or
hypotenuse = opposite / sin(<CAB)
hypotenuse = 271 / 0.5
hypotenuse (AB) = 542 feet.

Problem B
CD = 772 feet           Given in table
<ACD = 74o              Given on drawing.

We need to find AC which is not given
Cos 30 = adjacent / hypotenuse.
adjacent = hypotenuse * Cos(30)
adjacent = AB * Cos(30)
Adjacent = 542 * cos(30)
Adjacent = AC = 469.4 feet

Now we need to start again
AC = 469.4
<ACD = 74
CD = 772
AD = ???

AD^2 = AC^2 + CD^2 - 2 * AC * CD * Cos(74)
AD^2 = 595984 + 220336.4 - 399538 
AD^2 = 416782.1
AD = sqrt(416782.1)
AD = 645.59

Problem 3
I'll set it up for you. And give you the answer I get, but I'm going to leave it to you mostly. It just follows what I've done above.

DC = 645.59
CE = 561
DE = 543

DC^2 = CE^2 + DE^2 - 2* CE * DE * Cos(E)
645.59^2 = 561^2 + 543^2 - 2*561*543 * Cos(E)
Cos(E) = -0.3164
E = cos-1(0.3164)
E = 108.45 degrees.


 


______________ is process that you can do over and over, where each result does not affect the next.
Ex. Flipping a coin, rolling dice, choosing a card, etc.

Answers

In probability, an experiment is any procedure that can be infinitely repeated and has a well-defined set of possible outcomes. Thus, an experiment is a process that you can do over and over, where each result does not affect the next. For example: Flipping a coin, rolling dice, choosing a card, etc. are all experiments.

A basketball player has a 50 chance of making each free throw. what is the probability that the player makes at least eleven out of twele free throws

Answers

it would be about 1.89 or 1 5/6

Select the property that allows the statement 10 = y to be written y = 10.


Commutative - addition

Distributive

Associative - multiplication

Symmetric

Commutative - multiplication

Associative - addition

Identity - addition

Answers

Hello!

This is the symmetric property

Hope this helps!
Answer:

The property that allows the statement 10 = y to be written y = 10 is:

                       Symmetric

Step-by-step explanation:

We know that for any set A. if a and b are two elements of the set A.

Then if a is related to b by some relation then by the symmetric property b must be related to a by the same property.

Here 10 is related to y by the equality relation.

i.e. 10=y

Hence, by the symmetric property we have that y must be related to 10 by the same equality relation.

i.e.   y=10

ivan began to prove the law of sines using the diagram and equations below. sin(A) = h/b, so b sin(A) = h. sin(B) = h/a, so a sin(B) = h. Therefore, b sin(A) = a sin(B). Which equation is equivalent to the equation b sin(A) = a sin(B)? 

edit: the answer is b!

Answers

the answer is b. its correct

(B.) sin(A)/a = sin(B)/b

Solve 6,394 divided by 42 =

Answers

The required quotient is [tex]152[/tex] and remainder is [tex]10[/tex].

Given that [tex]6394[/tex] ÷ [tex]42[/tex].

Long division states that [tex]divident= divisor*quotient+remainder[/tex].

Let [tex]a[/tex] and [tex]b[/tex] be any real number. Consider [tex]a[/tex] ÷ [tex]b[/tex] gives

[tex]a=bq+r[/tex], [tex]q[/tex] is quotient [tex]r[/tex] is remainder and its value is [tex]0\leq r < b[/tex].

[tex]\begin{array}{ccccc}42)&006394(152&\\-&42____________&\\&219& \\&\\-&210&\\&0094\\-&0084\\&0010\end{array}\right][/tex]

Hence, the required quotient is [tex]152[/tex] and remainder is [tex]10[/tex].

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How do you know the sum of a positive and negative integer will be negative?

Answers

Um, you don't. The sum of a positive and a negative integer can be positive:

[tex]8+(-3)=+5[/tex]

If what you're asking is, under what condition will the sum of a positive and negative be negative, then it's when the absolute value of the negative number is greater than the positive number. For example:

positive number: 8
negative number: -10

[tex]8+(-10)=-2[/tex]

This sum is negative. Note that [tex]\mid{-10}\mid\ \textgreater \ 8[/tex].

How to solve this problem

Answers

Step One
Solve for y
Cos(A) = adjacent / hypotenuse
Cos(A) = y / 8
y = 8 * cos(A)
y = 8 * cos(73)
y = 8 * 0.2924
y = 2.339

Step Two
Solve for x
Sin(A) = opposite / hypotenuse
Sin(73) = x / 8
x = 8 * sin(73)
x = 8 * 0.9563
x = 7.550

Check
x^2 + y^2 =? 8^2
2.339^2 + 7.55^2 =? 8^2
5.471 + 58.53 =? 64
64.000921  =  64 which is close enough.

A campground owner plans to enclose a rectangular field adjacent to a river. the owner wants the field to contain 180,000 square meters. no fencing is required along the river. what dimensions will use the least amount of fencing?

Answers

Calling x and y the two sizes of the rectangular field, the problem consists in finding the minimum values of x and y that give an area of [tex]A=180000 m^2[/tex]. 
The area is the product between the two sizes:
[tex]A=xy[/tex] (1)
While the perimeter is twice the sum of the two sizes:
[tex]p=2(x+y)[/tex] (2)

From (1) we can write
[tex]y= \frac{A}{x} [/tex]
and we can substitute it into (2):
[tex]p=2(x+ \frac{A}{x})=2x+2 \frac{A}{x} [/tex]

To find the minimum value of the perimeter, we have to calculate its derivative and put it equal to zero:
[tex]p'(x)=0[/tex]
The derivative of the perimeter is
[tex]p'(x) = 2 -2 \frac{A}{x^2}= \frac{2x^2-2A}{x^2} [/tex]
If we require p'(x)=0, we find
[tex]x^2=A[/tex]
[tex]x= \sqrt{A} = \sqrt{180000 m^2}=424.26 m [/tex]
And the other side is
[tex]y= \frac{A}{x}= \frac{180000 m^2}{424.26 m} =424.26 m[/tex]

This means that the dimensions that require the minimum amoutn of fencing are (424.26 m, 424.26 m), so it corresponds to a square field.


Kelly wants to know if the number of words on a page in her geometry book is generally more than the number of words on a page in her science book. She takes a random sample of 25 pages in each book, then calculates the mean, median, and mean absolute deviation for the 25 samples of each book.



Kelly claims that because the mean number of words on each page in the science book is greater than the mean number of words on each page in the geometry book, the science book has more words per page. Based on the data, is this a valid inference?

Answers

B because there is a mean of 42.9 in the geometry book there fore it is theoretically going to have less pages

Answer:

No, because there is a lot of variability in the science book data

Step-by-step explanation:

A sphere has a diameter of 12 ft. What is the volume of the sphere? Give the exact value in terms of pi

Answers

Diameter = 12 ft
Radius = 12 ÷ 2 = 6 ft

[tex]\text {Volume = } \dfrac{4}{3} \pi r^3[/tex]

[tex]\text {Volume = } \dfrac{4}{3} \pi (6)^3 = 288 \pi \text{ ft}^3[/tex]
hey user!

your answer is here..

given the diameter of the sphere is 12 ft.

therefore radius of the sphere = 12/2 = 6 ft

[tex]volume \: of \: the \: sphere = \frac{4}{3} \pi {r}^{3} \\ = \frac{4}{3} \pi( {6}^{3} ) \\ \\ = \frac{4}{3} \pi(216) \\ \\ = 288\pi {ft}^{3} \\ \\ cheers...[/tex]

a glass jar contains 1 red, 3 green, 2 blue, and 4 yellow marbles. if a single marble is chosen at random from the jar, what is the probability that it is red

Answers


[tex] \frac{1}{10} [/tex]
The probability of a red marble being chose is 10%

Find the equation of the line.

A) y= -3/2 x + 1

B) y= -2/3 x - 1

C) y= 2/3 x + 1

D) y= 3/2 x - 1

Answers

It’s y=2/3x+1 that’s the equation of the line.

Hope this helps

Answer:

It’s y=2/3x+1 that’s the equation of the line.

Step-by-step explanation:

if 3x+2y=12 and -4x+6y=24 what is the value of -x+2y

Answers

(1) 3x+2y=12
(2) -4x+6y=24

Solving the system of equations using the method of substitution:
Isolating y in the first equation:
(1) 3x+2y=12→3x+2y-3x=12-3x→2y=12-3x→2y/2=(12-3x)/2→y=(12-3x)/2

Replacing "y" by (12-3x)/2 in the second equation:
(2) -4x+6y=24
y=(12-3x)/2→-4x+6[(12-3x)/2]=24

Solving for x:
-4x+3(12-3x)=24
-4x+36-9x=24
-13x+36=24
-13x+36-36=24-36
-13x=-12
-13x/(-13)=-12/(-13)
x=12/13

Replacing "x" by 12/13 in y=(12-3x)/2
x=12/13→y=[12-3(12/13)]/2
y=(12-36/13)/2
y={[(13)(12)-36]/13}/2
y=[(156-36)/13]/2
y=(120/13)/2
y=(120/13)(1/2)
y=60/13

x=12/13; y=60/13
-x+2y=-12/13+2(60/13)
-x+2y=-12/13+120/13
-x+2y=(-12+120)/13
-x+2y=108/13

Answer: The value of -x+2y is 108/13 

Graph the six terms of a finite series where a1 = −3 and r = 1.5.

Answers

We are given the first term and the common ratio, this means they belong to a geometric series.

For the given series:

[tex]a_{1}=-3 \\ r=1.5 [/tex]

Each term of the geometric series is obtained by multiplying the previous term by common ratio.

So the next terms will be:

-4.5, -6.75, -10.125, -15.1875, -22.78125

The general formula for the G.P would be:

[tex] a_{n}=-3(1.5)^{n-1} [/tex]

On plotting the series, the result will be like this:

Answer:

the answer is C

Step-by-step explanation:

An artist is creating a large conical sculpture for a park. The cone has a height of 16 m of and a diameter of 25 m. Find the volume the sculpture to the nearest hundredth.

A. 833.33 m3
B. 7,850 m3
C. 2,616.67 m3
D. 209.33 m3

Answers

Final answer:

The volume of the conical sculpture is calculated using the formula for the volume of a cone, 1/3πr²h. Substituting the given values, the volume is found to be approximately 2,616.67 m³.

Explanation:

The subject of this question is focused on calculating the volume of a cone. To find the volume of a cone, we apply the formula 1/3πr²h, where r is the radius and h is the height. Given in the question, the height (h) of the cone is 16 m and the diameter is 25 m. The radius is half of the diameter so it is 25/2 = 12.5 m. Substituting these values into the formula gives us:

Volume = 1/3πr²h

= 1/3 * π *(12.5 m)² * 16 m

≈ 2,616.67 m³

So, the volume of the sculpture to the nearest hundredth is approximately 2,616.67 m³. Thus, Option C is the correct answer.

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A system of equations that has an infinite number of solutions is called​ a(n) ______ system of equations.

Answers

Final answer:

A system of equations with an infinite number of solutions is known as a consistent and dependent system. These systems occur when equations are essentially the same, leading to all solutions satisfying all the equations, often represented by overlapping graphs in the case of linear equations.

Explanation:

A system of equations that has an infinite number of solutions is called​ a consistent and dependent system of equations. When a system is consistent and dependent, it means that the equations describe the same line or geometric shape, leading to an infinite number of points that satisfy all equations in the system simultaneously. This scenario often arises when the equations in the system are multiple forms of the same equation, or when they can be algebraically manipulated to become the same equation.

In practical terms, if you were to graph the equations in a consistent and dependent system, you would see that they overlap completely. For instance, if two linear equations represent the same line, any point on that line is a solution to both equations, hence the infinite solutions. A key aspect of understanding such systems is realizing that they do not lead to a single unique solution but rather a set of solutions that satisfy all conditions outlined by the equations in the system.

A system of equations with an infinite number of solutions is referred to as a consistent and dependent system, indicating the equations describe the same line.

A system of equations that has an infinite number of solutions is called​ a consistent and dependent system of equations. This type of system occurs when the equations involved describe the same geometric line, meaning every point on the line is a solution to the system, hence an infinite number of solutions. Such systems often arise in various mathematical contexts, including linear algebra and differential equations, where they indicate a fundamental underlying symmetry or redundancy in the system's constraints.This occurs when the equations are dependent, leading to multiple possible solutions that satisfy all the equations simultaneously.

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