A plane is flying at an altitude of 32,000 feet. The distance between the plane and a radio tower on the ground is 50,000 feet. What is the angle of depression between the plane and radio tower (round to 1 decimal place)?

The probability is 0.125

Answer:

The correct option is 2.

Step-by-step explanation:

From the given graph it is noticed that the data points are located at (0,0), (1,0.25), (2,1), (3,2), (4,3), (5,4), (5.5,5), (6,6), (6.4,7), (6.7,7.8) and (7,9).

The rate of change from first two data points is

[tex]m_1=\frac{y_2-y_1}{x_2-x_1}=\frac{0.25-0}{1-0}=0.25[/tex]

The rate of change from next two data points is

[tex]m_2=\frac{2-1}{3-2}=1[/tex]

[tex]m_1\neq m_2[/tex]

The rate of change it not constant, therefore the given data points are non linear.

The value of y increases as the value of x-increases. It means there is a positive relation between x and y.

Therefore the graph represent a Nonlinear positive association between x and y. Option 2 is correct.

Answer:

The correct answer is 2.

25/4 is the anwser. i just took this test

Answer:

Step-by-step explanation:

The given graph belongs to a linear function, because it's a line.

To find its equation, we first need to find the slope of the line using two points and the formula

[tex]m=\frac{y_{2}-y_{1} }{x_{2} -x_{1} }[/tex]

We are gonna use points (0,-1) and (3,1), because the lines crosses through them. Replacing these points in the formula, we have

[tex]m=\frac{1-(-1)}{3 -0 }=\frac{1+1}{3}\\m=\frac{2}{3}[/tex]

Now, we use one points and the point-slope formula

[tex]y -y_{1} =m(x-x_{1} )\\y-(-1)=\frac{2}{3}(x-0)\\ y+1=\frac{2}{3}x\\y=\frac{2}{3}x-1[/tex]

Therefore, the right answer is A.

[tex]y=\frac{2}{3}x-1[/tex]

Answer:

Step-by-step explanation:

the right answer is B. 91 2/3 Cubic units i got it right on my geometry test :)

Given the condition that the sum of the dice rolled is less than 8, the probability of the dice having a sum of 6 is found by considering all outcomes where the sum is less than 8 and outcomes that result in a sum of 6. The probability turns out to be 20%.

This question involves the concept of conditional probability in mathematics. For a pair of six-sided dice, there are 36 equally likely outcomes (Because 6 faces of one die times 6 faces of the other). We are interested in the event of getting a sum of 6, given the sum is less than 8.

We first consider all the outcomes where the sum of two dice is less than 8: (1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (2,4), (2,5), (3,1), (3,2), (3,3), (3,4), (3,5), (4,1), (4,2), (4,3), (4,4), (5,1), (5,2), (5,3), (6,1), (6,2). There are 25 equally likely outcomes where the sum is less than 8.

Then, consider all the outcomes where the sum of the two dice is equal to 6: (1,5), (2,4), (3,3), (4,2), (5,1). There are 5 equally likely outcomes. So given the condition that the sum is less than 8, the probability of getting a sum of 6 is 5/25 or 20%.

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Answer:

C

Step-by-step explanation:

f(x) = x2 - 2

We have been given that company A has a 30% chance of losing $12,000.

Let us calculate the amount that Yun can loose.

[tex]\frac{12000\times 30}{100} \\ \\ =\$3600[/tex]

Now, 45% chance of breaking even. It means neither loss nor profit.

Then, 25% chance of earning Yun $11,000.

Let us calculate the amount of profit

[tex]\frac{11000 \times 25}{100} \\ \\ =\$2750[/tex]

Since, 3,600 > 2,750. It means that Yun will be in loss on investing in the company.

Hence, she will not invest in the company A.

d is the correct option.

d. no, 3,600 > 2,750

Answer:

Increasing

Step-by-step explanation:

We know that, a function can be increasing, decreasing, constant or a mix of these three i.e. a function is:

1. Increasing: if for x < y, f(x) < f(y).

2. Decreasing: If for x < y, f(x) > f(y).

3. Constant: If for any two numbers say x and y, f(x) = f(y).

As we can see from the graph, between [2,6], the value of function at 2 is less than the value of function at 6.

i.e. As 2 < 6, f(2) < f(6).

Which satisfies the definition of an increasing function.

Hence, the graph of the function over [2,6] is increasing.

The mean and standard deviation of the sample of orange sweets can be ibtaide using the binomial approximation relation. Hence, the mean and standard deviation are 13.75 and 2.905

Mean = np

Dynamite mints :

Holiday mints:

Total orange candies = (2.5 + 11.25) = 13.75

2.)

Standard deviation, σ = √(npq)

Dynamite mints :

√[25 x 0.1 × (1 - 0.1)] = 1.5

Holiday mints :

√[25 x 0.45 (1 - 0.45)] = 2.4874

Combined standard deviation : s²(x + y) = s²(x) + s²(y)

Std = √(1.5²2 + 2.4874²) = 2.905

Therefore, the mean and sample standard deviation are 13.75 and 2.905 respectively.

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Final answer:

After 140 hours, which is equivalent to 4 half-lives, the amount of bromine-82 remaining from an 80 mL sample will be 5 mL, as the amount is halved after each half-life period of 35 hours.

Explanation:

The question involves the half-life of a radioactive isotope, which is a concept in Chemistry specifically related to nuclear chemistry and radioactive decay. Since bromine-82 has a half-life of about 35 hours, after 140 hours, which is equivalent to 4 half-lives, the amount of the element remaining in the sample will be reduced by a factor of two after each half-life. To calculate this, we start with the initial 80 mL and reduce it by half 4 times.

After the first half-life (35 hours), 40 mL remains.

After the second half-life (70 hours), 20 mL remains.

After the third half-life (105 hours), 10 mL remains.

After the fourth half-life (140 hours), 5 mL remains.

Therefore, the correct answer is D. 5mL.

Final answer:

After 140 hours, which is four half-lives of Bromine-82, only 5 mL of an initial 80 mL sample will remain, making the correct answer D. 5mL.

Explanation:

The question is asking how much of a radioactive isotope will remain after a certain amount of time, given its half-life. In this example, the half-life of Bromine-82 is about 35 hours, and we want to know how much of an 80 mL sample will remain after 140 hours. To solve this, we will use the concept of half-life, which is the time it takes for half of the radioactive atoms in a sample to decay.

Since 140 hours is equal to 4 half-lives (140 hours ÷ 35 hours/half-life), we can calculate the remaining amount of Bromine-82 in the sample by halving the initial amount repeatedly, four times:

After the first half-life (35 hours), the remaining amount is ⅓ × 80 mL = 40 mL.

After the second half-life (70 hours in total), the remaining amount is ⅓ of 40 mL = 20 mL.

After the third half-life (105 hours in total), the remaining amount is ⅓ of 20 mL = 10 mL.

After the fourth half-life (140 hours in total), the remaining amount is ⅓ of 10 mL = 5 mL.

The correct answer is D. 5mL.

Final answer:

To obtain a 70% acid solution, mix 4 gallons of pure acid with the existing 6 gallons of 50% acid solution.

Explanation:

To find out how much pure acid should be mixed with 6 gallons of a 50% acid solution to obtain a 70% acid solution, we use the concept of mixtures in percentage problems. Let x be the number of gallons of pure acid to be added.

Firstly, the amount of pure acid in the initial solution is 50% of 6 gallons, which is 3 gallons. When we add x gallons of pure acid, the total volume of the mixture becomes x + 6 gallons, and the total amount of pure acid is x + 3 gallons.

To have a 70% acid solution:

The total amount of pure acid divided by the total volume should equal 70%.

Therefore, the equation is:

(x + 3) / (x + 6) = 0.70

By solving for x:

x + 3 = 0.70(x + 6)

x + 3 = 0.70x + 4.20

x - 0.70x = 4.20 - 3

0.30x = 1.20

x = 1.20 / 0.30

x = 4 gallons

You need to mix 4 gallons of pure acid with the 6 gallons of 50% acid solution to end up with a 70% acid solution.

The charge per day and charge per mile for the compact car is $36 and $0.22 respectively

let

x = charge per day

y = charge per mile

6x + 550y = 337 (1)

3x + 350y = 185 (2)

multiply (2) by 2

6x + 700y = 370 (3)

6x + 550y = 337 (1)

subtract (1) from (3)

700y - 550y = 370 - 337

150y = 33

y = 33/150

y = 0.22

substitute y = 0.22 into (2)

3x + 350y = 185

3x + 350(0.22) = 185

3x + 77 = 185

3x = 185 - 77

3x = 108

x = 108/3

x = 36

Therefore, charge per day and charge per mile for the compact car is $36 and $0.22 respectively

Learn more about equation:

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Answer:

The variable that is most likely the lurking variable that explains the correlation is:

          Distance being traveled.

Step-by-step explanation:

As we know that a lurking variable is a variable that correlates between the dependent and independent variable in a scatter plot or some other statistical model.

Hence, here as the distance traveled increases the number of stops would also increase and more passengers would come and hence the cost of ticket will increase.

          Hence, the lurking variable is:

         Distance being traveled.

The most likely lurking variable that explains the positive correlation between the price a passenger pays for a train ticket and the number of stops the train makes during their trip is distance being traveled.

The other variables are less likely to explain the correlation:

Hence, the distance being traveled is the lurking variable most likely explaining the correlation between ticket price and the number of stops.

Answer:

The 2nd graph correctly represents the situation.

Step-by-step explanation:

Let the number of Atomic Fireballs= x and the number of Gummi bears= y.

Now, Juan purchased total 7 pounds of candies.

So, [tex]x+y=7[/tex]

Also, the cost of Atomic Fireballs and Gummi bears is $4.25 and $1.25 per pound respectively.

Since, Juan spent total $14.75 before taxes.

Then, [tex]4.25x+1.25y=14.75[/tex]

That is, the system of equations is given by,

[tex]x+y=7[/tex]

[tex]4.25x+1.25y=14.75[/tex]

Plotting the equations, we get that,

The 2nd graph shown below correctly represents the situation.