Answer:
Reference Point
Explanation:
a piece of metal with a mass of 15.3 grams has a temperature of 50.0°C. When the metal is placed in 80.2 grams of water at 21.0°C, the temperature rises by 4.3°C. What is the specific heat capacity of the metal?
Final answer:
The specific heat capacity of the metal can be calculated using the equation q = m*c*ΔT. By substituting the given values into the equation and rearranging, we can find that the specific heat capacity of the metal is approximately 0.33 J/g°C.
Explanation:
The specific heat capacity of a substance is the amount of energy required to raise the temperature of 1 gram of the substance by 1°C. In this question, we can use the equation:
q = m*c*ΔT
Where q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.
Given that the metal has a mass of 15.3 grams and the temperature rises by 4.3°C, and the water has a mass of 80.2 grams and the temperature rises by 4.3°C, we can substitute these values into the equation to find the specific heat capacity of the metal:
qmetal = mmetal * cmetal * ΔTmetal
qwater = mwater * cwater * ΔTwater
The specific heat capacity, cmetal, can then be calculated by rearranging the equation:
cmetal = (qmetal - mwater * cwater * ΔTwater) / (mmetal * ΔTmetal)
Plugging in the given values, we find that the specific heat capacity of the metal is approximately 0.33 J/g°C.
Mg represents the element
Answer:
Mg is the symbol for Magnesium. Atomic #- 12
Explanation:
A net force of 50 N is applied to a 10 kg cart that is already moving at 3 m/s. The final velocity of the cart was 8 m/s. For How long was the force applied
Answer:
1 second
Explanation:
Assuming that the force is in the same direction as speed we can do the graphic.
Draw the forces present on the problem (weight and the net force).Newton's second law. The summation of the forces is equal to the product between mass and aceleration.[tex]F = m * a[/tex]Plan the equation on x direction (because the mass is moving on that way). The result would be: [tex]50 = 10 * a[/tex]From that equation we know that the aceleration is 5m/s2.Also, we know (because it is a uniform line movement) that the aceleration is related with the speed. [tex]s_{f} = s_{0} + a * t[/tex] Clearing the equation: [tex]\frac{s_{f} - s_{0} }{t} = a[/tex]And replacing: [tex]\frac{8-3}{t} = 5[/tex]So, the force is applied for 1 second.A 150kg motorcycle starts from rest and accelerates at a constant rate along a distance of 350m. The applied force is 250N and the coefficient of kinetic friction is 0.03.
A - Find the net force applied to the motorcycle.
B - Find the acceleration of the motorcycle.
C - What is its speed at the end of 350m?
D - Find the elapsed time of this acceleration.
[Explain and Show Work]
A) The net force on the motorbike is 205.9 N
B) The acceleration of the motorbike is [tex]1.37 m/s^2[/tex]
C) The final speed is 5.2 m/s
D) The elapsed time is 3.80 s
Explanation:
A)
There are two forces acting on the motorbike:
- The applied force, F = 250 N, forward
- The frictional force, [tex]F_f[/tex], backward
The frictional force can be written as
[tex]F_f = \mu mg[/tex]
where
[tex]\mu=0.03[/tex] is the coefficient of kinetic friction
[tex]m=150 kg[/tex] is the mass of the motorbike
[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity
Therefore the net force is given by
[tex]\sum F = F - F_f = F - \mu mg[/tex]
And substituting, we find
[tex]\sum F=250 - (0.03)(150)(9.8)=205.9 N[/tex]
2)
The acceleration of the motorbike can be found by using Newton's second law, which states that the net force is equal to the product between mass and acceleration:
[tex]\sum F = ma[/tex]
where
m is the mass
a is the acceleration
In this problem, we have
[tex]\sum F = 205.9 N[/tex] is the net force
m = 150 kg is the mass
Solving for a, we find the acceleration:
[tex]a=\frac{\sum F}{m}=\frac{205.9}{150}=1.37 m/s^2[/tex]
C)
Since the motion of the motorbike is a uniformly accelerated motion, we can use the following suvat equation:
[tex]v^2-u^2=2as[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance covered
For this motorbike, we have:
u = 0 (it starts from rest)
[tex]a=1.37 m/s^2[/tex]
s = 350 m
Solving for v,
[tex]v=\sqrt{u^2+2as}=\sqrt{0+2(1.37)(9.8)}=5.2 m/s[/tex]
4)
For this part of the problem, we can use the following suvat equation:
[tex]v=u+at[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the elapsed time
Here we have:
v = 5.2 m/s
u = 0
[tex]a=1.37 m/s^2[/tex]
Solving for t, we find
[tex]t=\frac{v-u}{a}=\frac{5.2-0}{1.37}=3.80 s[/tex]
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Answer:
This is a great question
*copy and paste for my physics homework* lol
What are the reactants in the following chemical equation NaCl+AgF=>NaF+AgCl
Answer:
NaCl,AgF
Explanation:
Chemical equations show the reactants and products, as well as other factors such as energy changes, catalysts, and so on. With these equations, an arrow is used to indicate that a chemical reaction has taken place. In general terms, a chemical reaction follows this format:
Reactants→Products
So the reactants of the given reaction are NaCl,AgF
The reactants in the chemical equation NaCl+AgF → NaF+AgCl are sodium chloride (NaCl) and silver fluoride (AgF).
Explanation:The reactants in the chemical equation NaCl+AgF → NaF+AgCl are sodium chloride (NaCl) and silver fluoride (AgF). In this reaction, a double displacement reaction, also known as a metathesis reaction, occurs where the elements in the reactants switch places, resulting in the formation of new compounds. The sodium ion (Na+) and the fluoride ion (F-) form sodium fluoride (NaF), while the silver ion (Ag+) and the chloride ion (Cl-) form silver chloride (AgCl), which is a precipitate, as illustrated in various silver reaction equations provided.
Select the correct answer.
Thirst is a sign of dehydration.
A.
True
B.
False
Reset
Next
Answer:
this is a trap ur done
A mass of 2kg is at attached to a spring with constant 8N/m. It is then displaced to the point x=2. What time does it take for the block to travel to the point x=1?
Answer:
0.523598776 seconds
Explanation:
m =2 kg , k =8 N/m
[tex]w = \sqrt {\frac {k}{m}}[/tex]
[tex]w=\sqrt {\frac {8}{2}}= 2 rad/s[/tex]
x = xm cos(wt)
1 =2 cos(2t)
cos 2t=0.5
[tex]2t=cos^{-1} 0.5=1.047197551[/tex]
t=0.523598776 seconds
Final answer:
The time it takes for a 2kg mass attached to a spring with a spring constant of 8N/m to move from x=2 to x=1 is π/4 seconds, which is one-quarter of the period of oscillation in simple harmonic motion.
Explanation:
To calculate the time it takes for a 2kg mass attached to a spring with a spring constant of 8N/m to travel from the point displaced at x=2 to the point x=1, we must understand simple harmonic motion (SHM). In SHM, the angular frequency ω can be determined by the formula ω = √(k/m), where k is the spring constant, and m is the mass of the object attached to the spring. The period of oscillation is given as T = 2π/ω. It's important to note that the time taken to travel from x=2 to x=1 is one-quarter of the period, because the motion from the maximum displacement to the equilibrium position constitutes one-quarter of the cycle of oscillation.
Applying the given values:
Spring constant, k = 8 N/m
Mass, m = 2 kg
We calculate the angular frequency:
ω = √(k/m) = √(8/2) = 2 rad/s
The period of oscillation, T, is:
T = 2π/ω = 2π/2 = π seconds
The time taken to travel from x=2 to x=1 is one-quarter of this period:
Time = T/4 = π/4 seconds.
mass×acceleration of a triangle =force
Answer:
The force acting on a body is always equal to the product of the mass of the body and its acceleration.
Explanation:
The force of a body is defined as the product of mass and acceleration of the body.
According to Newton's second law, wherever there is a change in momentum of the body for an interval of time, there is a force acting on it.
F = (mv - mu) / t
= m (v -u) /t
= m a
Where,
(v - u)/t - is the change in velocity of the body in the interval of time. It is equal to the acceleration of the body.
Hence, the equation for the force for any body becomes, F = m x a
An object can be broken up by a planet's gravity once it passes the _______. The Jovian planets are composed primarily of _______ and helium. Hydrogen and helium don't exist in Earth's _______ because the terrestrial planets of Mercury, Venus, Earth, and Mars couldn't exert a strong gravitational pull on hydrogen and helium gas within the nebula. _______ is the planet closest to the sun, has almost no atmosphere, and what little atmosphere exists is constantly getting blown away by solar wind. The atmosphere of _______ is very hot and dense, comprised of approximately 95 percent carbon dioxide, and the surface is composed of molten bedrock.
Answer:1. Roche limit
2.hydrogen
3.atmosphere
4.mercury
5.venus
6.when an object passes the Roche limit, the strength of gravity on the object increases. If the density of the planet is higher, then the object can break up farther away from the planet. If the density is lower, then the Roche limit is located closer to the planet
7.Farther our in the solar system, beyond the frost line, hydrogen was at a low enough temperature that it could condense. This allowed hydrogen to accumulate under gravity, eventually forming the Jovian planets
Explanation:
An object breaks apart at a planet's Roche limit; Jovian planets mainly consist of hydrogen and helium. Earth's atmosphere lacks these gases due to weaker gravity. Mercury, close to the sun, has little atmosphere, and Venus has a hot, dense atmosphere.
Explanation:An object can be broken up by a planet's gravity once it passes the Roche limit. The Jovian planets are composed primarily of hydrogen and helium. Hydrogen and helium don't exist in Earth's atmosphere because the terrestrial planets of Mercury, Venus, Earth, and Mars couldn't exert a strong gravitational pull on hydrogen and helium gas within the nebula. Mercury is the planet closest to the sun, has almost no atmosphere, and what little atmosphere exists is constantly getting blown away by solar wind. The atmosphere of Venus is very hot and dense, comprised of approximately 95 percent carbon dioxide, and the surface is composed of molten bedrock.
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A spy satellite is orbiting earth and experiences a gravitation Force F if a similar satellite with one half the mass is placed in an orbit that is twice as far from the earths center the gravitational force between the earth and the second satellite will be what multiple of F?
The gravitational force on the second satellite is 1/8 of the force exerted on the 1st satellite.
Explanation:
The magnitude of the gravitational force exerted by the Earth on the satellite is given by:
[tex]F=G\frac{Mm}{r^2}[/tex]
where
G is the gravitational constant
M is the Earth's mass
m is the mass of the satellite
r is the radius of the orbit of the satellite
Let's call F the gravitational force on the first satellite, of mass m, with an orbit of radius r.
The second satellite has mass
[tex]m'=\frac{m}{2}[/tex]
and the radius of its orbit is
[tex]r'=2r[/tex]
So, the gravitational force exerted on the second satellite is
[tex]F'=G\frac{M(\frac{m}{2})}{(2r)^2}=\frac{1}{8}(\frac{GMm}{r^2})=\frac{1}{8}F[/tex]
Therefore, the force on the second satellite is 1/8 of the force exerted on the 1st satellite.
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A 1.0-kg block of aluminum is at a temperature of 50 Celsius. How much thermal energy will it lose when it’s temperature is reduced by half?
Answer:
The lose of thermal energy is, Q = 22500 J
Explanation:
Given data,
The mass of aluminium block, m = 1.0 kg
The initial temperature of block, T = 50° C
The final temperature of the block, T' = 25° C
The change in temperature, ΔT = 50° C - 25° C
= 25° C
The specific heat capacity of aluminium, c = 900 J/kg°C
The formula for thermal energy,
Q = mcΔT
= 1.0 x 900 x 25
= 22500 J
Hence, the lose of thermal energy is, Q = 22500 J
The thermal energy loose by the aluminum block will be Q = 22500 J
What will be the amount of energy aluminum block will lose?It is given that Given data,
The mass of the aluminum block, m = 1.0 kg
The initial temperature of the block, T = 50° C
Since the temperature of the block is halved then,
The final temperature of the block, T' = 25° C
The change in temperature, ΔT = 50° C - 25° C = 25° C
The specific heat capacity of aluminum,
c = 900 J/kg°C
The formula to find out the thermal energy will be
[tex]Q=m\times c\times\Delta T[/tex]
[tex]Q=1.0\times 900\times 25[/tex]
[tex]Q= 22500J[/tex]
Thus the thermal energy loose by the aluminum block will be Q = 22500 J
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While taking off from an aircraft carrier, a jet starting from rest accelerates uniformly to a final speed of 40. meters per second on a runway that is 70. meters long. What is the magnitude of the acceleration of the jet? Group of answer choices
The acceleration of the jet is [tex]11.4 m/s^2[/tex]
Explanation:
Since the jet motion is a uniformly accelerated motion (=constant acceleration), we can use the following suvat equation:
[tex]v^2-u^2=2as[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the displacement
For the jet in this problem, we have
u = 0 (it starts from rest)
v = 40 m/s (final velocity)
s = 70 m (length of the runway)
Solving for a, we find the acceleration:
[tex]a=\frac{v-u}{t}=\frac{40^2-0}{2(70)}=11.4 m/s^2[/tex]
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The magnitude of the acceleration of the jet is approximately 11.43 m/s².While taking off from an aircraft carrier, a jet starting from rest accelerates uniformly to a final speed of 40.
To determine the magnitude of the acceleration of the jet, we can use the following kinematic equation:
v² = u² + 2as
where:
v is the final velocity (40 m/s),
u is the initial velocity (0 m/s, starting from rest),
a is the acceleration
and s is the displacement (70 m).
a = (v² - u²) / (2s)
a = (40² - 0²) / (2 × 70)
a = 1600 / 140
a ≈ 11.43 m/s²
Therefore, the magnitude of the acceleration of the jet is approximately 11.43 m/s².
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A tumbleweed rolls from x = 25.6 m
to x = -14.4 m in 7.90 s. What was
its average velocity?
(Unit = m/s)
Answer:
-5.06 m/s
Explanation:
The formula to calculate average speed is
V = x2 - x1 / t2 - t1
The start point of the tumbleweed is 25.6m and the final point is -14.4 m
The start time is 0s and the final time is 7.9s
Replacing the values the result is -5.06m/s.
The result of the speed is negative because the direction of the speed is opposite to the direction of the tumbleweed.
a bucket of mass 2kg is whirled in a vertical circle of radius 1.20M. at the lowest point of its motion the tension in the rope supporting the bucket is 25N. find the speed of the bucket
The speed of the bucket is 1.8 m/s
Explanation:
The bucket is in circular motion, therefore the net force acting on it is equal to the centripetal force:
[tex]F=m\frac{v^2}{r}[/tex]
where
m = 2 kg is the mass of the bucket
v is its speed
r = 1.20 m is the radius of the circle
At the lowest point of motion, there are two forces acting on the bucket:
The tension in the rope, T = 25 N, upward (same direction as the centripetal force, acting towards the centre of the circle)The force of gravity, [tex]mg[/tex], where [tex]g=9.8 m/s^2[/tex] is the acceleration of gravityTherefore the equation of motion for the bucket is:
[tex]T-mg=m\frac{v^2}{r}[/tex]
And solving for v, we find the speed of the bucket:
[tex]v=\sqrt{r(\frac{T}{m}-g)}=\sqrt{(1.20)(\frac{25}{2}-9.8)}=1.8 m/s[/tex]
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a rabbit hops 50 m to the south in 5 seconds
Answer:
nice, thats a fast rabbit
Explanation:
1. When a particle moves in a circle with constant speed, its acceleration is
A) constantly increasing.
constant in direction.
C) zero.
D) constant in magnitude.
E) constant in magnitude and direction.
Answer:
Its A.
Explanation:
sound energy cannot travel through
A vacuum,a wooden table,polluted air,pond water
Sound energy cannot travel through a vacuum.
Explanation:
Waves are periodic disturbance of the space, which travel carrying energy but not matter.
There are two types of waves:
Mechanical waves: mechanical waves propagate through the vibrations of the particles in a medium. Examples of mechanical waves are sound waves.Electromagnetic waves: these waves consist of periodic oscillations of electric and magnetic fields, perpendicular to each other. These waves do not need a medium to propagate, so they can also travel in a vacuum.In this problem, we are analyzing sound energy, which is the energy carried by sound waves. Sound waves are mechanical waves, so they need a medium to propagate: therefore, they cannot travel through a vacuum, since there is no medium.
So, sound energy cannot travel through a vacuum.
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A bullet fired from a pistol with a barrel of 0.30 m travels at 800.0 m/s determine the time it takes the bullet to travel down barrel
The time taken is [tex]3.75\cdot 10^{-4}s[/tex]
Explanation:
The motion of the bullet is a uniform motion (=constant velocity), therefore we can use the following equation:
[tex]v=\frac{d}{t}[/tex]
where
v is the speed of the bullet
d is the distance covered
t is the time taken
For the bullet in this problem,
d = 0.30 m is the distance travelled
v = 800.0 m/s is the speed
Solving for t, we find the time taken:
[tex]t=\frac{d}{v}=\frac{0.3}{800}=3.75\cdot 10^{-4}s[/tex]
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Explain the role of gravity and inertia in keeping the moon in orbit? 15points pleaseee
Answer:
The gravity pulls the sun and the planets together, while keeping them apart. The inertia provides the tendency to maintain speed and keep moving. The planets want to keep moving in a straight line because of the physics of inertia. However, the gravitational pull wants to change the motion to pull the planets into the core of the sun. Together, this creates a rounded orbit as a form of compromise between the two forces.
Final answer:
Gravity acts as a centripetal force pulling the Moon towards Earth, while inertia gives the Moon its straight-line momentum. Together, they balance each other out, keeping the Moon in a stable elliptical orbit around Earth. The gravity gradient also affects the Moon's rotation and contributes to the equilibrium between Earth and the Moon.
Explanation:
Gravity and Inertia in Maintaining the Moon's Orbit
The Moon remains in orbit around the Earth due to the combined effects of gravity and inertia. Gravity, a fundamental force discovered by Isaac Newton, acts as a centripetal force that pulls the Moon towards the center of the Earth. Without this force, the Moon would move in a straight line into space. On the other hand, inertia is the tendency of an object to maintain its state of motion unless acted upon by an external force. The Moon has a momentum perpendicular to the gravitational pull of the Earth which would allow it to move in a straight line. These two forces together create a delicate balance that results in the Moon's smooth, elliptical orbit around the Earth.
The gravity gradient also plays a role in the Moon's rotation and orbital characteristics. This gradient explains why the Moon is slightly elongated towards the Earth and contributes to maintaining its stable orbit. Furthermore, the Earth and Moon stay in equilibrium since the gravitational force of attraction between them is perfectly balanced by the centrifugal force, stemming from their relative motion.
In summary, gravity acts to pull the Moon towards the Earth, while inertia contributes to the Moon's tendency to move forward. Together, these forces create the conditions for a stable, synchronous orbit, manifesting in phenomena such as synchronous rotation and the consistent face of the Moon that is always directed towards Earth.
4. When referring to the element phosphorus on the periodic table
osphorus on the periodic table, the number 15 represents
A. energy level.
B. atomic weight.
C. atomic number.
D number of atoms.
Answer:
the answer is C
Explanation:
a 30kg child who is running at 4m/s jumps onto a stationary 10kg skateboard. what is the approximate speed of the child and skateboard
Answer:
v=3 m/s
Explanation:
the formula for this problem is
V = v 1 ( m 1 / m 1 + m 2 )
we if we substitute ans solve we get this the answer as 3 m/s
Child and stationary skateboard move with same speed, as child jumps onto skateboard. Approximate speed of child and skateboard is 3 m/s.
What is conservation of momentum?Momentum of a object is the force of speed of it in motion. Momentum of a moving body is the product of mass times velocity.
When the two objects collides, then the initial collision of the two body is equal to the final collision of two bodies by the law of conservation of momentum.
Thus by the law of conservation of momentum,
[tex](m_1u_1)+(m_2u_2)=(m_1+m_2)v[/tex]
Here, [tex]m_1,m_2[/tex] are the masses of two bodies and [tex]u_1,u_2[/tex] are the initial velocities.
Given information-
The mass of the child is 30 kg.
The speed of the child is 10 m/s.
The mass of the skateboard is 10 kg.
Let the speed of the child and skateboard is [tex]v[/tex] m/s.
As the the child and jumps down onto a stationary skateboard then, the speed of child and skateboard should be same.
Thus by the conservation of momentum,
[tex](m_cu_c)+(m_su_s)=(m_c+m_s)v[/tex]
As the initial velocity of the skateboard is 0. Put the values in the above formula as,
[tex](30\times4)+(10\times 0)=(30+10)v\\120+0=40v\\v=3\rm m/s[/tex]
Thus the approximate speed of the child and skateboard is 3 m/s.
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6. Suzie hammers on a block of wood when she is 85 meters from a large brick wall. Each time she
she hits the block, she hears an echo 0.50 s later. With this information, show that the speed of
sound is 340 m/s.
Answer:
85 ÷ 0.50÷340=z z is the answer
A body on the circular orbit makes an angular displacement given by ∅(t)=2t^2+5t+5. If time t is in seconds, calculate the angular velocity at t=2s
Answer:
Angular Velocity at 2 s= 13 rad/s
Explanation:
∅(t)=2[tex]t^{2}[/tex] + 5t + 5
where represents angular displacement at any given time t
Angular Velocity (ω)= [tex]\frac{\textrm{d ∅(t) }}{\textrm{dt}}[/tex]
ω=4t+ 5
Putting in t=2
ω=8+5=13 rad/s
2. Which of the following cell structures is the site of photosynthesis?
O A. Golgi apparatus
O B. Mitochondria
C. Chloroplasts
D. Centrioles
Answer:
Option C. The chloroplasts contain chlorophyll pigments requires for photosynthesis.
The cell structure that is considered the site of photosynthesis is known as chloroplasts. Hence, option C is the correct answer.
Photosynthesis is a significant process that takes place in plants. The process in which light energy obtained from the sun is converted into sugar molecules for the utilization by plants cells is known as Photosynthesis.
Photosynthesis occurs at chloroplasts. Some of the significant features of the chloroplasts are listed as follows:
Chloroplasts contain chlorophyll which is defined as the primary pigment required for photosynthesis to take place It is present in plants and certain algae It is oval-shaped and is composed of two different membranes namely outer and inner membraneThus, we can conclude that the chlorophyll present in chloroplasts is vital for photosynthesis and hence, chloroplasts are the cell structure that acts as the site of photosynthesis. Therefore, option C is the correct answer.
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Which statement about distance and displacement is correct?
Distance does not take direction of motion into account, but displacement does.
Displacement does take direction of motion into account but, but distance does.
Both distance and displacement must take direction of motion into account.
Answer:
The answer i believe is A..
Explanation:
.
Answer:
Distance does not take direction of motion into account, but displacement does.
Explanation:
Distance is said to be how much ground an object covers during motion. Distance is a scalar quantity. Distance has magnitude but no direction. It only concerns how much ground an object covers without considering the start or end points. For example a person covering a distance from point A to B can be computed without considering it starting and ending point. The distance from A to B can be computed as 100 meters.The change in position is not considered, only the distance it covered(100 meters)
While
Displacement is the change in position of an object. Displacement is a vector quantity as it incorporates both direction and magnitude. Displacement considers the starting and ending points of an object in motion. Example a person moving from point A to B, the change in position from point A to B shows their is a displacement.
Lucille is finding it difficult to play soccer after school. Her doctor thinks that her cells might not be getting enough oxygen. When Lucille talked about it with her friend, her friend said there might be a problem with Lucille‘s respiratory system or circulatory system.
What do Lucille cells need an order for her body to function properly? How might a problem with Lucille‘s respiratory system and circulatory system make it difficult for Lucille to play soccer?
Answer:
See the explanation below.
Explanation:
Circulation of blood and oxygen is possible in body when circulatory system work along with respiratory system. Through tranche air moves in and out from lungs, whereas, through pulmonary arteries and veins (both connected to heart) blood moves in and out from the lungs. As Lucille is facing problem in his respiratory and circulatory system hence, it is difficult for him to play soccer because under normal circumstances when there is increase in physical activity then muscle cell respire more as compare to when the body is on rest. So, with increase of physical activity there is also increase in the rate of breathing which result in more absorption of oxygen and more removal of carbon dioxide but if there is problem in respiratory and circulatory system, for example, infection in throat due to pollution,etc. then this normal process of breathing gets affected which sometime may prove fatal to the person.
Lucille's cells require oxygen for cellular respiration to produce energy, and issues with her respiratory or circulatory systems can impair oxygen delivery and carbon dioxide removal, causing difficulties in playing soccer.
Explanation:In order for Lucille's body to function properly, her cells need oxygen to run the oxidative stages of cellular respiration, which produces energy in the form of adenosine triphosphate (ATP). Problems with Lucille's respiratory system or circulatory system could hinder the delivery of oxygen to her cells and removal of carbon dioxide from her body, which is critical for maintaining energy levels necessary for activities like playing soccer. Both systems work in tandem to ensure oxygen is inhaled into the lungs, transferred to the red blood cells, and delivered to body tissues, while carbon dioxide, a by-product, is picked up and exhaled.
The respiratory system includes the lungs where gas exchange occurs, and any condition like asthma, emphysema, COPD, or lung cancer can impair this function. Similarly, the circulatory system, consisting of the heart, blood, and blood vessels, is responsible for transporting gases to and from the lungs and body tissues. If the circulatory system is impaired, it can result in inadequate oxygen supply to muscles and organs, making it difficult for Lucille to sustain the physical exertion needed for soccer.
A 26.0 g ball is fired horizontally with initial speed v0 toward a 110 g ball that is hanging motionless from a 1.10 m -long string. The balls undergo a head-on, perfectly elastic collision, after which the 110 g ball swings out to a maximum angle θmax = 50.0. What was v0?
I think you need to find the tangential velocity using the angle that the ball swings to, but I am not sure how to go about beginning this problem.
Answer:
[tex]7.3 ms^{-1}[/tex]
Explanation:
Consider the motion of the ball attached to string.
In triangle ABD
[tex]Cos50 = \frac{AB}{AD} \\Cos50 = \frac{AB}{L}\\AB = L Cos50[/tex]
height gained by the ball is given as
[tex]h = BC = AC - AD \\h = L - L Cos50\\h = 1.10 - 1.10 Cos50\\h = 0.393 m[/tex]
[tex]M[/tex] = mass of the ball attached to string = 110 g
[tex]V[/tex] = speed of the ball attached to string just after collision
Using conservation of energy
Potential energy gained = Kinetic energy lost
[tex]Mgh = (0.5) M V^{2} \\V = sqrt(2gh)\\V = sqrt(2(9.8)(0.393))\\V = 2.8 ms^{-1}[/tex]
Consider the collision between the two balls
[tex]m[/tex] = mass of the ball fired = 26 g
[tex]v_{o}[/tex] = initial velocity of ball fired before collision = ?
[tex]v_{f}[/tex] = final velocity of ball fired after collision = ?
using conservation of momentum
[tex]m v_{o} = MV + m v_{f}\\26 v_{o} = (110)(2.8) + 26 v_{f}\\v_{f} = v_{o} - 11.85[/tex]
Using conservation of kinetic energy
[tex]m v_{o}^{2} = MV^{2} + m v_{f}^{2} \\26 v_{o}^{2} = 110 (2.8)^{2} + 26 (v_{o} - 11.85)^{2} \\v_{o} = 7.3 ms^{-1}[/tex]
At a maximum angle of 50°, the initial velocity ([tex]V_0[/tex]) of the ball is equal to 7.3 m/s.
Given the following data:
Mass of ball 1 = 26.0 g.
Mass of ball 2 = 110.0 g.
Length = 1.10 m.
Maximum angle = 50°
How to calculate the initial velocity.First of all, we would determine the height of the ball in motion through this derivation:
[tex]h = L-Lcos\theta\\\\h = 1.10-1.10cos50\\\\h = 1.10-0.7071[/tex]
Height, h = 0.3929 meter.
Next, we would determine the velocity of the ball by applying the law of conservation of energy:
[tex]P E=KE\\\\mgh=\frac{1}{2} mv^2\\\\V=\sqrt{2gh} \\\\V=\sqrt{2 \times 9.8 \times 0.3929 }[/tex]
V = 2.7750 m/s.
Also, we would determine the final velocity by applying the law of conservation of momentum:
[tex]m_1v_o=m_1vf+m_2V\\\\26v_0=26v_f+110(2.7750)\\\\26v_f=26v_0-305.25\\\\v_f=(v_0-11.7404)\;m/s[/tex]
Now, we can determine the initial velocity:
[tex]m_1v_o^2=m_1v_f^2+m_2V^2\\\\26v_0^2=26(v_0-11.7404)^2+110(2.7750)^2\\\\26v_0^2=26(v_0-11.7404)^2-847.0688\\\\V_0=7.3\;m/s[/tex]
Read more on kinetic energy here: brainly.com/question/1242059
QUICK: Using this energy transformation diagram of a battery drill, what is the drill’s thermal energy output?
Answer:
35
Explanation:
Which sphere of Earth includes the continental ice sheets and glaciers? Biosphere Cryosphere Geosphere Hydrosphere
Answer:
C. Cryosphere
Explanation:
The definition for Cryo is:
Involving extreme Coldness and etc.
There are studies done on Cyro Freezing the body to preserve the body until there is a cure for a deadly disease. They do this as well to try to live in the future. Our technology hasn't been able to get the people alive yet, but when we do.
If you ever need to think of "Cryo" just think of Cryo Freezing.
Answer:
C.
Explanation:
What two models are used to describe how light behaves
The two models used to describe light are the ray model, which is useful in geometric optics for large surfaces, and the wave model, which explains diffraction and color. At the atomic level, the particle model describing light as photons is also used.
Explanation:The two models used to describe how light behaves are the ray model and the wave model. The ray model of light simplifies its behavior to straight-line paths, which is particularly useful in geometric optics, where light's interaction with large surfaces—such as reflections from mirrors and refractions through lenses—is considered. The wave model, on the other hand, is essential for explaining phenomena like diffraction and the observation of colors, representing light as electromagnetic waves with different frequencies.
Furthermore, at the scale where light interacts on the level of individual atoms, the particle model of light, which describes light as photons, becomes more apparent. This model is crucial for understanding concepts like the photoelectric effect. Therefore, depending on the scale of the interaction and the nature of the observation, either model—or sometimes both—may be more appropriate for describing the behavior of light.