Final answer:
To find the fox population after 28 years, we use the function y = 55 × 2^x, with x = 2 because 28 years is two 14-year periods. After calculating 2^2 and multiplying by 55, we find that there will be 220 foxes.
Explanation:
To calculate the number of foxes in a wildlife preserve after 28 years, given that the population doubles every 14 years, we start with the function y = 55 × 2^x, where x represents the number of 14-year periods.
Since 28 years is equivalent to 2 periods of 14 years, we will substitute x with 2:
Write down the equation substituting x with 2: y = 55 × 2^2.Calculate the exponent: 2^2 = 4.Multiply the base population by 4: 55 × 4 = 220.Therefore, after 28 years, there will be 220 foxes in the wildlife preserve.
Use the Remainder Theorem to find the remainder: (–6x3 + 3x2 – 4) ÷ (2x – 3).
23
-17.5
-4.4444444...
-0.8888888...
The remainder obtained when we carry out the operation (-6x³ + 3x² - 4) ÷ (2x - 3) is -17.5 (2nd option)
How do i determine the remainder?The following data were obtained from the question:
Expression = (-6x³ + 3x² - 4) ÷ (2x - 3)Remainder =?Using the remainder theorem, we can obtain the remainder as illustrated below:
Let
f(x) = -6x³ + 3x² - 4
2x - 3 = 0
From 2x - 3 = 0, make x the subject as shown below:
2x - 3 = 0
x = 3/2
Substitute the value of x into f(x). We have:
f(x) = -6x³ + 3x² - 4
f(3/2) = -6(3/2)³ + 3(3/2)² - 4
= -6(27/8) + 3(9/4) - 4
= -20.25 + 6.75 - 4
= -17.5
Thus, we can conclude that the remainder obtained when (-6x³ + 3x² - 4) is divided by (2x - 3) is -17.5 (2nd option)
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if the remainder on division of x^3+2x^2+kx+3 by x-3 is 21,find the quotient and the value of k. Hence,find the zeroes of the cubic polynomial x^3+2x^2+kx-18.
Bill and Greg are walking in opposite directions with speeds of 45 and 75 feet per minute. When they started, the distance between them was 20 feet. What will be the distance between them in 2.5 min?
Answer:
320 ft
Step-by-step explanation:
I'm not sure how the other person was awarded brainliest answer because that answer is pretty far off. But the work was good just they messed up. Also kinda sad he is a brainly teacher and still has incorrect answers.
solve for t. use the quadratic formula.
d=−16t^2+12t
Answer:
[tex]t\,=\,\frac{-3+\sqrt{9+4d}}{-8}\:\:and\:\:\frac{3+\sqrt{9+4d}}{8}[/tex]
Step-by-step explanation:
Given: d = -16t² + 12t
To find: t using quadratic formula
If we have quadratic equation in form ax² + bx + c = 0
then, by quadratic formula we have
[tex]x\,=\,\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
Rewrite the given equation,
-16t² + 12t - d = 0
from this equation we have,
a = -16 , b = 12 , c = d
now using quadratic formula we get,
[tex]t\,=\,\frac{-12\pm\sqrt{12^2-4\times(-16)\times d}}{2\times(-16)}[/tex]
[tex]t\,=\,\frac{-12\pm\sqrt{144+64d}}{-32}[/tex]
[tex]t\,=\,\frac{-12\pm\sqrt{16(9+4d)}}{-32}[/tex]
[tex]t\,=\,\frac{-12\pm4\sqrt{9+4d}}{-32}[/tex]
[tex]t\,=\,\frac{4(-3\pm\sqrt{9+4d})}{-32}[/tex]
[tex]t\,=\,\frac{-3\pm\sqrt{9+4d}}{-8}[/tex]
[tex]t\,=\,\frac{-3+\sqrt{9+4d}}{-8}\:\:,\:\:\frac{-3-\sqrt{9+4d}}{-8}[/tex]
[tex]t\,=\,\frac{-3+\sqrt{9+4d}}{-8}\:\:and\:\:\frac{-(3+\sqrt{9+4d})}{-8}[/tex]
[tex]t\,=\,\frac{-3+\sqrt{9+4d}}{-8}\:\:and\:\:\frac{3+\sqrt{9+4d}}{8}[/tex]
Therefore, [tex]t\,=\,\frac{-3+\sqrt{9+4d}}{-8}\:\:and\:\:\frac{3+\sqrt{9+4d}}{8}[/tex]
Answer:
[tex]\frac{3-\sqrt{9-d}} {8}\text{ or }t=\frac{3+\sqrt{9-d}} {8}[/tex]
Step-by-step explanation:
Here, the given expression,
[tex]d= -16t^2+12t[/tex]
[tex]\implies -16x^2+12t-d=0[/tex] ------(1)
Since, if a quadratic equation is,
[tex]ax^2+bx+c=0[/tex] ------(2)
By using quadratic formula,
We can write,
[tex]x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]
By comparing equation (1) and (2),
We get, a = -16, b = 12, c = -d,
[tex]t=\frac{-12\pm \sqrt{12^2-4\times -16\times -d}}{2\times -16}[/tex]
[tex]t = \frac{-12\pm \sqrt{16\times 9-16\times d}}{-32}[/tex]
[tex]t = \frac{-12\pm \sqrt{16}\times \sqrt{9-d}} {-32}[/tex]
[tex]t = \frac{-12\pm 4\sqrt{9-d}} {-32}[/tex]
[tex]t = \frac{4(-3\pm \sqrt{9-d})} {4(-8)}[/tex]
[tex]t = \frac{-3\pm \sqrt{9-d}} {-8}[/tex]
[tex]t = \frac{-3+\sqrt{9-d}} {-8}\text{ or }t=\frac{-3-\sqrt{9-d}} {-8}[/tex]
[tex]\implies t = \frac{3-\sqrt{9-d}} {8}\text{ or }t=\frac{3+\sqrt{9-d}} {8}[/tex]
Which is the required solution.
An ellipse has vertices along the major axis at (0, 1) and (0, −9). The foci of the ellipse are located at (0, −1) and (0, −7). The equation of the ellipse is in the form below.
The equation of the ellipse is required.
The required equation is [tex]\dfrac{x^2}{16}+\dfrac{(y+4)^2}{25}=1[/tex]
It can be see that the major axis is parallel to the y axis.
The major axis points are
[tex](h,k+a)=(0,1)[/tex]
[tex](h,k-a)=(0,-9)[/tex]
[tex]k+a=1[/tex]
[tex]k-a=-9[/tex]
Subtracting the equations
[tex]2a=10\\\Rightarrow a=5[/tex]
The foci are
[tex](h,k+c)=(0,-1)[/tex]
[tex](h,k-c)=(0,-7)[/tex]
[tex]k+c=-1[/tex]
[tex]k-c=-7[/tex]
Subtracting the equations
[tex]2c=6\\\Rightarrow c=3[/tex]
[tex]k+c=-1\\\Rightarrow k=-1-c\\\Rightarrow k=-1-3\\\Rightarrow k=-4[/tex]
Foci is given by
[tex]c^2=a^2-b^2\\\Rightarrow b=\sqrt{a^2-c^2}\\\Rightarrow b=\sqrt{5^2-3^2}=4[/tex]
The equation is
[tex]\dfrac{(x-h)^2}{b^2}+\dfrac{(x-k)^2}{a^2}=1\\\Rightarrow \dfrac{(x-0)^2}{4^2}+\dfrac{(y+4)^2}{5^2}=1\\\Rightarrow \dfrac{x^2}{16}+\dfrac{(y+4)^2}{25}=1[/tex]
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Which is the ratio for sin a written as a fraction in simplest form
your Answer issss:
√3/2
if you received an annual salary of 33500 paid monthly what would your gross pay be each pay period
need help so much ...
If the expected adult of a 2 week old puppy is 20 pounds how many grams per day should they gain?
Is .8/100 equal to .8%
If a < 0 and b > 0, then the point (a, b) is in Quadrant A) I. B) II. C) III. D) IV.
Answer:
The actual answer is D
The point (a, b) lies in the second quadrant. Then the correct option is B.
What is coordinate geometry?Coordinate geometry is the study of geometry using the points in space. Using this, it is possible to find the distance between the points, the dividing line is m:n ratio, finding the mid-point of the line, etc.
If a < 0 and b > 0.
Then the point (a, b) is in Quadrant will be given as,
If a > 0 and b > 0, then the points is in first quadrant.If a < 0 and b > 0, then the points is in second quadrant.If a < 0 and b < 0, then the points is in third quadrant.If a > 0 and b < 0, then the points is in fourth quadrant.Thus, the point (a, b) lies in the second quadrant.
Then the correct option is B.
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What is the area of the composite figure whose vertices have the following coordinates? (−1, 5) , (3, 5) , (7, 3) , (3, 0) , (−1, 1)
Answer:
28
Step-by-step explanation:
Square: 4 * 4 = 16
Small Triangle: 1 * 4 = 4 / 2 = 2
Large Triangle: 5 * 4 = 20 / 2 = 10
16 + 2 + 10 = 28
Look at the data in the table below
X Y
4. 9
12. 28
7. 14
9. 20
5. 9
12. 30
10. 22
Which graph shows the best fit for this data
Write the first five terms of a sequence. Don’t make your sequence too simple. Write both an explicit formula and a recursive formula for a general term in the sequence. Explain in detail how you found both formulas.
Answer: The answer is 5, 10, 20, 40 and 80.
Step-by-step explanation: We are to write the first five terms of a sequence, along with the explicit and recursive formula for the general term of the sequence.
Let the first five terms of a sequence be 5, 10, 20, 40 and 80. These terms are taken from a geometric sequence with first term [tex]a_1 5[/tex] and common ratio [tex]r=2.[/tex]
Therefore, we have
[tex]a_2=a_1\times r,\\\\a_3=a_2\times r,\ldots[/tex]
Therefore, the recursive formula is
[tex]a_{n+1}=2a_n,~~a_1=5.[/tex]
And explicit formula is
[tex]a_n=a_1r^{n-1}.[/tex]
Answer:
Let the first five terms of a sequence be, 4,8,12,20,24
Ok, let me explain the meaning of term explicit and Recursive formula.
Explicit formula ,is the general formula to find any term of the sequence.
And, Recursive formula, is the method by which, we can find the nth term of the sequence if (n-1)th term of the sequence is known.
So,the explicit formula for the sequence is,
y = 4 n, where , n is any natural number.
And the recursive formula is .
y = 4 (n-1), with the help of (n-1)th term we can find nth term.
First term =4=4 × 1
Second term =8 =4 × 2
Third term =12=4×3
Fourth term =16 =4 × 4
.....................
...........................
.................................
(n-1) th term =4 × (n-1)
nth term =4 × n
Applying the simple procedure by looking at the first , second and the way the next term goes , the general and recursive formula is obtained.
As, you said you don't want simpler sequence
Consider the first five terms of the sequence, 0, 3,8,15, 24.
Explicit formula =n² + 2 n
Recursive formula=(n-1)²+2(n-1)
If,you will look at the sequence, it is neither Arithmetic nor geometric .
First term =0=0²+0×0
Second term =3=1+2=1²+2 × 1
Third term =8=4+4=2²+2×2
Fourth term =15=9+6=3²+2×3
Fifth term =24=16 +8=4²+2×4
So, Explicit formula= n²+ 2 n, where n is a whole number.
Dominik paid three-quarters of a dollar for a newspaper. Which amount is equivalent to the cost of the newspaper?
Which expression represents the number of sides in the polygon for the nth member of the pattern? A) n + 3 B) n3 C) n + 2 D) 3n
PLEASE HELP ME ASAP 40 POINTS AND BRAINLIEST SHOW WORK
Find the variables and the lengths of the sides of this kite
An inscribed angle has a measure of 48°. Determine the measure of the intercepted arc.
24° 48° 72° 96°
What is the circumference of a circle with a radius of 6.1 centimeters? Enter your answer as a decimal in the box. Use 3.14 for pi. Round your answer to the nearest tenth. cm
Joan has 45 marbles . MARY HAS m marbles if Joan has 15 times as many marbles , write an equation that shows how many marbles mary has
Mary has 3 marbles.
Explanation:To find out how many marbles Mary has, we can use the information that Joan has 45 marbles and Joan has 15 times as many marbles as Mary. So, we can set up an equation:
45 = 15m
To solve for m, we divide both sides of the equation by 15:
m = 45/15
Simplifying the expression, we get:
m = 3
Therefore, Mary has 3 marbles.
A car travels 3 times around a traffic circle whose radius is 80 feet. What is the distance the car will travel? Use 3.14 for π . Enter your answer in the box. ft
Answer : Distance will be 1507.2 feet .
Explanation :
Since we have given that
Radius of circle = 80 feet
So,
Circumference of circle is given by
[tex]2\pi r=2\times 3.14\times 80=502.4 \text{ feet}[/tex]
Since , a car travels 3 times around a traffic circle.
So,
[tex]\text{ Distance covered by the car will travel}= 3\times 502.4= 1507.2 \text{ feet }[/tex]
So, Distance will be 1507.2 feet .
Which linear inequality is represented by the graph? y > 2/3x – 1/5 y ≥ 3/2x + 1/5 y ≤ 2/3x + 1/5 y < 3/2x – 1/5
Answer: The correct option is third, i.e., [tex]y\geq \frac{3}{2} x+\frac{1}{5}[/tex].
Explanation:
From the figure it is noticed that the line passing through the points (0,0.2) and (3,2.2).
The equation of line passing through two points is,
[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)[/tex]
[tex]y-0.2=\frac{2.2-0.2}{3-0}(x-0)[/tex]
[tex]y-\frac{1}{5} =\frac{2}{3} x[/tex]
[tex]y =\frac{2}{3} x+\frac{1}{5}[/tex]
The equation of the line is [tex]y =\frac{2}{3} x+\frac{1}{5}[/tex].
From the figure it is noticed that as the value of x increases the value of y is less.
he point (1,0) lies on the shaded reason it means this point must satisfy the equation.
[tex](0)=\frac{2}{3} (1)+\frac{1}{5}[/tex]
[tex](0)=\frac{2}{3} +\frac{1}{5}[/tex]
[tex](0)=\frac{10+3}{15}[/tex]
[tex](0)=\frac{13}{15}[/tex]
It is true of the sign is less than or equal to instead of equal.
[tex]y \leq \frac{2}{3} x+\frac{1}{5}[/tex]
Therefore, option third is correct.
Check my answers? GIving medal:
7. What is the slope of the line that passes throught the pair of points (1, 7) and (10, 1)?
a. 3/2
b. -2/3
c. -3/2
d. 2/3 <--
8. What is the slope of the line that passes through the points (-5.5, 6.1) and (-2.5, 3.1)?
a. -1
b. 1
c. -3 <--
d. d
9. what is the slope of the line that passes through the pair of points (-7/3, -3) and (-5, 5/2)?
a. 6/22 <--
b. -6/22
c. 22/6
d. -22/6,
Number seven Is B. -2/3
The formula used to find the length of a line segment in space.
if youre doing the vocab thing -- Distance
A small plane leaves an airport at a speed of 252 miles per hour. A jet leaves the airport 2 hours later traveling at 672 miles per hour. How long will the small plane be flying before the jet catches up to it? What unit will you use for your answer?
No, thanks to you, I got the question wrong it was hours.
Ben and Marge are purchasing a house with a 20-year, 5/1 ARM for $265,000 at 5.25% with a 3/12 cap structure. What will the difference in payments be from year 5 to year 6?
A. $925.81
B. $880.29
C. $369.32
D. $234.39
The difference in payments from year 5 to year 6 is approximately $369.32 for the 5/1 ARM mortgage.
To calculate the payment difference from year 5 to year 6 for a 5/1 ARM (Adjustable Rate Mortgage) with a 3/12 cap structure, we need to understand how the ARM works and how the caps affect the adjustment.
1. Initial Mortgage Parameters :
- Loan Amount: $265,000
- Interest Rate: 5.25%
- Term: 20 years
2. Adjustment Frequency : The 5/1 ARM adjusts after the initial 5-year fixed period, then annually.
3. Cap Structure :
- Initial Adjustment Cap: 3%
- Subsequent Adjustment Cap: Each year after the initial adjustment, the rate can adjust up to 3% from the previous rate.
4. Calculation Steps :
a. Calculate the initial monthly payment using the loan amount, interest rate, and term.
b. Determine the new interest rate for year 6 based on the cap structure.
c. Calculate the monthly payment for year 6 with the new interest rate.
d. Find the difference between the payments from year 5 to year 6.
Let's start the calculations:
a. Calculate the initial monthly payment using the loan amount, interest rate, and term. We'll use the formula for a fixed-rate mortgage:
[tex]\[ P = \frac{P_r \cdot A}{1 - (1 + r)^{-n}} \][/tex]
Where:
- [tex]\( P \)[/tex] = Monthly Payment
- [tex]\( P_r \)[/tex] = Periodic Interest Rate (annual rate divided by 12)
- [tex]\( A \)[/tex] = Loan Amount
- [tex]\( r \)[/tex] = Periodic Interest Rate
- [tex]\( n \)[/tex] = Total number of payments (loan term in years multiplied by 12)
For the initial fixed period of 5 years:
[tex]\[ P_r = \frac{5.25\%}{12} = 0.004375 \][/tex]
[tex]\[ n = 20 \times 12 = 240 \][/tex]
Plugging these values into the formula:
[tex]\[ P = \frac{0.004375 \cdot 265000}{1 - (1 + 0.004375)^{-240}} \][/tex]
[tex]\[ P \approx 1645.80 \][/tex]
So, the initial monthly payment is approximately $1,645.80.
b. Determine the new interest rate for year 6 :
- The initial rate can adjust up to 3% in year 6.
- So, the new interest rate could be up to \( 5.25\% + 3\% = 8.25\% \).
c. Calculate the monthly payment for year 6 :
- Use the formula for the monthly payment again with the new interest rate:
[tex]\[ P_r = \frac{8.25\%}{12} = 0.006875 \][/tex]
Plugging into the formula:
[tex]\[ P = \frac{0.006875 \cdot 265000}{1 - (1 + 0.006875)^{-240}} \][/tex]
[tex]\[ P \approx 1985.09 \][/tex]
So, the monthly payment for year 6 is approximately $1,985.09.
d. Find the difference in payments from year 5 to year 6:
[tex]\[ Difference = Payment_{Year6} - Payment_{Year5} \][/tex]
[tex]\[ Difference = 1985.09 - 1645.80 \][/tex]
[tex]\[ Difference \approx 339.29 \][/tex]
So, the difference in payments from year 5 to year 6 is approximately $339.29.
Therefore, the closest answer is C. $369.32 .
The function graphed approximates the height of an acorn, in meters, x seconds after it falls from a tree.
After about how many seconds is the acorn 5 m above the ground?
The equation of the parabola is y = – 5x² + 20. The time when an acorn is 5 m above the ground in 1.7 seconds. Then the correct option is C.
What is the parabola?It is the locus of a point that moves so that it is always the same distance from a non-movable point and a given line. The non-movable point is called focus and the non-movable line is called the directrix.
The function graphed approximates the height of an acorn, in meters, x seconds after it falls from a tree.
We know that the equation of the parabola will be given as
y = a(x - h)² + k
where (h, k) is the vertex of the parabola and a is the constant.
We have
(h, k) = (0, 20)
Then
y = ax² + 20
The parabola is passing through (2, 0), then we have
0 = 4a + 20
a = -5
Then we have
y = – 5x² + 20
The time in seconds when the acorn is 5 m above the ground.
–5x² + 20 = 5
–5x² = –15
x = 1.7
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Which foundation drawing matches this orthographic drawing? ( just tell me what picture)
PLEASE HELP ASAP
EXTRA POINTS
Sheila places a 54 square inch photo behind a 12-inch-by-12-inch piece of matting.
The photograph is positioned so that the matting is twice as wide at the top and bottom as the sides.
Write an equation for the area of the photo in terms of x.
A square is cut out of a circle whose diameter is approximately 14 feet. What is the approximate area of the remaining portion of the circle in square feet?
A square is cut from a circle with a 14-foot diameter. Remaining circle area ≈ 53.86 sq ft here nearest round off option is c. 50 square feet.
To find the area of the remaining portion of the circle after a square with a side of 10 feet is cut out,
Find the area of the square:
Area of square
= side × side
= 10 feet × 10 feet
= 100 square feet
Find the radius of the circle:
The diameter is approximately 14 feet, so the radius is half of that:
Radius = 14 feet / 2 = 7 feet
Find the area of the entire circle:
Area of circle = π × radius²
Area of circle
= π × (7 feet)²
≈ 153.86 square feet (using π ≈ 3.14)
Subtract the area of the square from the area of the circle to find the remaining portion:
Remaining area = Area of circle - Area of square
Remaining area
≈ 153.86 square feet - 100 square feet
≈ 53.86 square feet
Therefore, the approximate area of the remaining portion of the circle is approximately 53.86 square feet nearest option is c. 50 square feet.
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The above question is incomplete , the complete question is:
A square is cut out of a circle whose diameter is approximately 14 feet. What is the approximate area of the remaining portion of the circle in square feet?
Attached figure