Answer: Probability that she attended class regularly given that she receives A grade is 0.9286.
Step-by-step explanation:
Since we have given that
Probability of those who attend regularly receive A's in the class = 35%
Probability of those who do not regularly receive A's in the class = 5%
Probability of students who attend class regularly = 65%
We need to find the probability that she attended class regularly given that she receives an A grade.
Let E be the event of students who attend regularly.
P(E) = 0.65
And P(E') = 1-0.65 = 0.35
Let A be the event who attend receive A in the class.
So, P(A|E) = 0.35
P(A|E') = 0.05
So, According to question, we have given that
[tex]P(E|A)=\dfrac{P(E)P(A|E)}{P(E)P(A|E)+P(E')P(A|E')}\\\\P(E|A)=\dfrac{0.65\times 0.35}{0.65\times 0.35+0.35\times 0.05}\\\\P(E|A)=\dfrac{0.2275}{0.2275+0.0175}=\dfrac{0.2275}{0.245}=0.9286[/tex]
Hence, Probability that she attended class regularly given that she receives A grade is 0.9286.
Final answer:
The probability that a student attended class regularly given they received an A is approximately 0.9286, or 92.86% when rounded to four decimal places, calculated using Bayes' theorem.
Explanation:
To solve the problem, we need to calculate the conditional probability that a student attended class regularly given they received an A grade. To do this, we'll use Bayes' theorem, which allows us to reverse conditional probabilities.
Let's denote Attendance as the event that a student attends class regularly and A as the event of a student receiving an A grade. According to the question:
P(Attendance) = 0.65 (65% of students attend class regularly)P(A|Attendance) = 0.35 (35% of regular attendants receive A's)P(A|Not Attendance) = 0.05 (5% of irregular attendants receive A's)The overall probability of receiving an A, P(A), is computed as follows:
P(A) = P(A|Attendance) × P(Attendance) + P(A|Not Attendance) × P(Not Attendance)
= 0.35 × 0.65 + 0.05 × (1 - 0.65)
= 0.2275 + 0.0175
= 0.2450
Now we use Bayes' theorem to find P(Attendance|A), the probability of attendance given an A:
P(Attendance|A) = (P(A|Attendance) × P(Attendance)) / P(A)
= (0.35 × 0.65) / 0.245
= 0.2275 / 0.245
≈ 0.9286
Therefore, the probability that a student attended class regularly given that they received an A grade is approximately 0.9286, or 92.86% when rounded to four decimal places.
Verify that y1 = x and y2 = x ln x are solutions to x 2y ′′ − xy′ + y = 0. b) Use the Wronskian to show that y1 and y2 are linearly independent. c) Find the particular solution to the differential equation with initial conditions y(1) = 7, y′ (1) = 2
a. Substitute the given solutions and their derivatives into the ODE.
[tex]y_1=x\implies {y_1}'=1\implies{y_1}''=0[/tex]
[tex]x^2y''-xy'+y=-x+x=0[/tex]
[tex]y_2=x\ln x\implies{y_1}'=\ln x+1\implies{y_1}''=\dfrac1x[/tex]
[tex]x^2y''-xy'+y=x-x(\ln x+1)+x\ln x=0[/tex]
Both solutions satisfy the ODE.
b. The Wronskian determinant is
[tex]\begin{vmatrix}x&x\ln x\\1&\ln x+1\end{vmatrix}=x(\ln x+1)-x\ln x=x\neq0[/tex]
so the solutions are indeed independent.
c. The ODE has general solution [tex]y(t)=C_1x+C_2x\ln x[/tex]. Then with the given initial conditions, the constants satisfy
[tex]y(1)=7\implies 7=C_1[/tex]
[tex]y'(1)=2\implies2=C_1+C_2\implies C_2=-5[/tex]
So the ODE has the particular solution,
[tex]\boxed{y(t)=7x-5x\ln x}[/tex]
Final answer:
The functions y1 = x and y2 = x ln x are verified as solutions to the differential equation x^2y'' - xy' + y = 0. They are confirmed to be linearly independent through a non-zero Wronskian. Lastly, the particular solution is found to be y = 7x - 5x ln x using given initial conditions.
Explanation:
To verify that y1 = x and y2 = x ln x are solutions to the differential equation x2y'' - xy' + y = 0, we need to substitute each function into the equation and show that the left-hand side reduces to zero.
For y1 = x, its derivatives are y1' = 1 and y1'' = 0. Substituting these into the equation gives x2(0) - x(1) + x = 0, which simplifies to 0, confirming that y1 is a solution.
For y2 = x ln x, its first derivative is y2' = ln x + 1, and the second derivative is y2'' = 1/x. Substituting these into the equation gives x2(1/x) - x(ln x + 1) + x ln x = 0, which also simplifies to 0, confirming that y2 is a solution.
To demonstrate that y1 and y2 are linearly independent, we must calculate the Wronskian, W(y1,y2), and show that it is non-zero. The Wronskian is:
W(y1,y2) = y1y2' - y1'y2 = x(ln x + 1) - (x ln x) = x.
Since the Wronskian is not zero for all x
e 0, y1 and y2 are linearly independent.
For the particular solution of the differential equation with initial conditions y(1) = 7, y'(1) = 2, we express y as a linear combination of y1 and y2:
y = c1y1 + c2y2 = c1x + c2x ln x.
Applying the initial conditions, we get two equations:
1) y(1) = c1(1) + c2(1 ln 1) = 7
2) y'(1) = c1 + c2(ln 1 + 1) = 2
Simplifying these equations gives us c1 = 7 and c2 = -5, therefore the particular solution is y = 7x - 5x ln x.
A hacker is trying to guess someone's password. The hacker knows (somehow) that the password is 3 digits long, and that each digit could be a number between 0 and 4. Assume that the hacker makes random guesses. What is the probability that the hacker guesses the password on his first try? Round to six decimal places.
Answer:
.008000
Step-by-step explanation:
The first digit is either 0,1,2,3,4
P( right guess) = 1/5
The second digit is either 0,1,2,3,4
P( right guess) = 1/5
The third digit is either 0,1,2,3,4
P( right guess) = 1/5
Since they are independent
P( right,right,right) = 1/5*1/5*1/5 = 1/125 =.008
To six decimal places = .008000
To solve the problem, let's consider each piece of information step by step:
1. The password is 3 digits long.
2. Each digit can be any number from 0 to 4.
Since there are 5 choices for each digit (0, 1, 2, 3, or 4), we calculate the total number of distinct combinations possible for a 3-digit password where each digit has 5 possibilities.
For each place of the three digits, we have 5 choices, which gives us a total combination count using the Multiplication Principle:
- First digit: 5 choices (0-4)
- Second digit: 5 choices (0-4)
- Third digit: 5 choices (0-4)
To find the total number of different password combinations, we multiply the number of choices for each digit:
Total combinations = 5 (choices for the first digit) × 5 (choices for the second digit) × 5 (choices for the third digit) = \( 5^3 = 125 \) possible password combinations.
Each of these combinations is equally likely if the hacker guesses at random. Hence, the probability that the hacker guesses the correct password on the first try is 1 out of the total number of combinations.
Therefore, the probability is:
\( P(\text{correct on first try}) = \frac{1}{125} \)
Let's convert this probability to a decimal and then round it to six decimal places:
\( P(\text{correct on first try}) = \frac{1}{125} = 0.008 \)
When rounded to six decimal places, the probability is:
\( P(\text{correct on first try}) \approx 0.008000 \)
So, the probability that the hacker guesses the password correctly on the first try is approximately 0.008000.
Mike deposited $850 into the bank in July. From July to December, the amount of money he deposited into the bank increased by 15% per month. What's the total amount of money in his account after December? Round your answer to the nearest dollar. Show your work. 4.
Answer:
$1.710
Step-by-step explanation:
Mike deposited $850 into the bank in July.
In August his balance will be: $850×1.15 = $977.5
In September his balance will be: $977.5×1.15 = $1124.125
In October his balance will be: $1124.125×1.15 = $1292.74375
In November his balance will be: $1292.74375×1.15 = $1.486,6553125
In December his balance will be: $1.486,6553125×1.15 = $1.709,653609375
Therefore, the amount of money he will have after december will be $1.710
15. The formula for the surface area of a rectangular solid is S 2HW + 2LW + 2LH, where S, H, W, and L represent surface area, height, width, and length, respectively. Solve this formula for W.
Answer:
The answer is
[tex]W=\frac{S-2LH}{2H+2L}[/tex]
Step-by-step explanation:
The formula for the area of a solid rectangle is
[tex]S = 2HW+2LW+2LH[/tex]
Solve it for W
[tex]2HW+2LW=S-2LH\\\\W(2H+2L)=S-2LH\\\\W=\frac{S-2LH}{2H+2L}[/tex]
Express the answers to the following calculations in scientific notation, using the correct number of significant figures. (a) 145.75 + (2.3 × 10−1) × 10 (b) 79,500 / (2.5 × 102) × 10 (c) (7.0 × 10−3) − (8.0 × 10−4) × 10 (d) (1.0 × 104) × (9.9 × 106) × 10
Each calculation has been evaluated, taken all significant figures into consideration, and results have been presented in scientific notation. Special attention was given to rules related to multiplying numbers in scientific notation.
Explanation:The given calculations require us to use scientific notation and proper treatment of significant figures. We are using the fundamentals of arithmetic with scientific notation, which is based on the rules of exponents. Each calculation is treated as follows:
(a) For the expression 145.75 + (2.3 × 10−1) × 10 = 147.05. This result has five significant figures, but to write numbers in scientific notation, we should round off to two significant figures as the lowest number of significant figures is 2 (in 2.3). Therefore, 147.05 becomes 1.47 × 10² in scientific notation. (b) For the expression 79,500 / (2.5 × 10²) × 10 = 3180. This is in turn expressed in scientific notation with three significant figures (since 2.5 has 3 significant figures) as 3.18 × 10³. (c) For the expression (7.0 × 10−3) − (8.0 × 10−4) × 10 = 6.2 × 10-3. Converting to scientific notation using two significant figures (based on original values), get 6.2 × 10⁻³. (d) For the expression (1.0 × 10⁴) × (9.9 × 10⁶) × 10 = 9.9 × 10¹¹ based on the rule of multiplying the numbers out front and adding up the exponents. Learn more about Scientific Notation and Significant Figures here:
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Please help me with this
Answer:
Yes;Each side of triangle PQR is the same length as the corresponding side of triangle STU
Step-by-step explanation:
You can observe the sides of both triangles to see if this property holds
Lets check the length of AB
A(0,3) and B(0,-1)
[tex]AB=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\\\\\\\AB=\sqrt{(0-0)^2+(-1-3)^2} \\\\\\\\AB=\sqrt{0^2+-4^2} \\\\\\AB=\sqrt{16} =4units[/tex]
Now check the length of the corresponding side DE
D(1,2) and E(1,-2)
[tex]DE=\sqrt{(1-1)^2+(-2-2)^2} \\\\\\DE=\sqrt{0^2+-4^2} \\\\\\DE=\sqrt{16} =4units[/tex]
The side AB has the same length as side DE.This is also true for the remaining corresponding sides.
For each of the squences below, find a formula that generates the sequence.
(a) 10,20,10,20,10,20,10...
Answer:
[tex]a_{n}=15 + (-1)^n * 5[/tex]
Step-by-step explanation:
First, we notice that the when n is odd, [tex]a_{n}[/tex] = 10. And when n is even, [tex]a_{n}[/tex] = 20.
The average of 10 and 20 is [tex](10+20)/2 = 15[/tex]. So, the distance between 15 and 10 is the same that between 15 and 20.
That distance is 5.
From 15, we need to subtract 5 to get 10 when n is odd and we need to add 5 to get 20 when n is even.
The easiest way to express that oscilation is using [tex](-1)^n[/tex], because it is (-1) when n is odd and 1 when is even. And when multiplied by 5, it will add or subtract 5 as we wanted.
Find the time required for an investment of 5000 dollars to grow to 6400 dollars at an interest rate of 7.5 percent per year, compounded quarterly. Your answer is t = _____
Answer:
t= 3.322 years
Step-by-step explanation:
investment made= $5000 (Principal)
amount obtained after a specific time= $6400
rate %= 7.5% per year compounded quarterly which means
r= 7.5/(100*4)= 0.01875
time = 4t ( compounded quarterly)
we know that Amount obtained is given by
[tex]A= P(1+r)^{4t}[/tex]
[tex]6400= 5000(1+0.01875)^{4t}[/tex]
[tex](1.01875)^{4t}=1.28[/tex]
taking log on both sides and solving we get
t= 3.322 years
hence my answer t= 3.322 years
The response to a question has three alternatives: A, B, and C. A sample of 120 responses provides 64 A, 23 B, and 33 C responses. Show the frequency and relative frequency distributions (use nearest whole number for the frequency column and 2 decimal for the relative frequency column).
Frequency--
It is the number of times an outcome occurs while performing an experiment some " n " number of times.
Relative frequency--
It is the ratio of the frequency of an outcomes to the total number of times an experiment is been performed.
Here there are TOTAL : 120 responses and three outcomes A , B and C.
The frequency table is given as follows:
Outcome A B C
Frequency 64 23 33
and the Relative frequency table is given as follows:
Outcome A B C
Relative frequency 64/120 23/120 33/120
i.e. the Relative frequency table is given by:
Outcome A B C
Relative frequency 0.53 0.19 0.28
The frequency distribution for the given sample is: A: 64, B: 23, C: 33. The relative frequency distribution is: A: 0.53, B: 0.19, C: 0.28.
Explanation:To find the frequency distribution, we simply count the number of occurrences of each response. For the given sample of 120 responses, we have:
A: 64 responses
B: 23 responses
C: 33 responses
To find the relative frequency distribution, we divide the frequency of each response by the total number of responses (120). The relative frequencies, rounded to two decimal places, are:
A: 0.53
B: 0.19
C: 0.28
An estimator receives an average quote fora traffic control subcontractor of $1570 for the job duration. If the lowest bid is 4 % under average, and the highest bid is 12% above average, what is the cost difference between lowest and highest bid?
Answer:
The cost difference between lowest and highest bid $ 251.20
Step-by-step explanation:
Given,
The average quote for the traffic control subcontractor = $ 1570,
Also, the lowest bid is 4 % under average,
That is, lowest bid = average quote - 4% average quote
= 1570 - 4% of 1570
[tex]=1570-\frac{4\times 1570}{100}[/tex]
[tex]=1570-\frac{6280}{100}[/tex]
[tex]=1570-62.80[/tex]
[tex]=\$1507.2[/tex]
While, the highest bid is 12% above average,
That is, the highest bid = average quote + 12% average quote
= 1570 + 12% of 1570
[tex]=1570+\frac{12\times 1570}{100}[/tex]
[tex]=1570+\frac{18840}{100}[/tex]
[tex]=1570+188.4[/tex]
[tex]=\$1758.4[/tex]
Hence, the cost difference between lowest and highest bid = $ 1758.4 - $ 1507.2 = $ 251.20
Ethan is playing in a soccer league that has 6 teams (including his team). Each team plays every other team twice during the regular season. The top two teams play in a final championship game after the regular season. In this league, how many soccer games will be played in all? 7.
Answer:
There are going to be 31 matches played in the soccer league.
Step-by-step explanation:
The soccer league has 6 teams, so if every team plays against the others twice, there are going to be played 30 matches:
-Team 1: v Team 2 (2), v Team 3 (2), v Team 4 (2), v Team 5 (2), v Team 6 (2)
-Team 2: v Team 3 (2), v Team 4 (2), v Team 5 (2), v Team 6 (2)
-Team 3: v Team 4 (2), v Team 5 (2), v Team 6 (2)
-Team 4: v Team 5 (2), v Team 6 (2)
-Team 5: v Team 6 (2)
-Team 6: -
If there is a final championship game after the 30 regular season matches, there are going to be 31 matches played in the league.
I NEED THIS DONE IN AN EXCEL SPREADSHEET WITH SOLUTIONS
The following probabilities for grades in management science have been determined based on past records:
Grade Probability
A 0.1
B 0.2
C 0.4
D 0.2
F 0.10
The grades are assigned on a 4.0 scale, where an A is a 4.0, a B a 3.0, and so on.
Determine the expected grade and variance for the course.
Answer:
Expected Grade=2 i.e., C
Variance=1.2
Step-by-step explanation:
[tex]Expected\ value=E\left [ x \right ]=\sum _{i=1}^{k} x_{i}p_{i}[/tex]
The x values are
A = 4
B = 3
C = 2
D = 1
F = 0
Probability of each of the events
P(4)=0.1
P(3)=0.2
P(2)=0.4
P(1)=0.2
P(0)=0.1
[tex]E\left [ x \right ]=4\times 0.1+3\times 0.2+2\times 0.4+1\times 0.2+0\times 0.1\\\therefore E\left [ x \right ]=2[/tex]
Variance
[tex]Var\left ( x\right)=E\left [ x^2 \right ]-E\left [ x \right ]^2[/tex]
[tex]E\left [ x^2 \right ]=4^2 \times 0.1+3^2 \times 0.2+2^2 \times 0.4+1^2 \times 0.2+0^2 \times 0.1\\\Rightarrow E\left [ x^2 \right ]=5.2\\E\left [ x \right ]^2=2^2=4\\\therefore Var\left ( x\right)=5.2-4=1.2\\[/tex]
find the gcd and lcm of 20 and 56
By gcd, I think you mean gcf ( Greatest Common Factor).
To find the gcf find all the factors of each number:
Factors of 20: 1, 2, 4,5 ,10 , 20
Factors of 56: 1, 2, 4, 7, 8, 14, 28, 56
The largest common factor is 4.
LCM = Least Common Multiple
This is the smallest number that both numbers divide into evenly
Find the prime factors of each number:
Prime factors of 20: 2 * 2 * 5
Prime factors of 56: 2 * 2 * 2 * 7
To find the LCM, multiply all prime factors the most number of times they occur.
In the prime factor of 56, 2 appears 3 times and 7 appears once.
In the prime factor of 20 5 appears once.
LCM = 2 * 2 *2 * 7 * 5 = 280
At the beginning of 1990, 21.7 million people lived in the metropolitan area of a particular city, and the population was growing exponentially. The 1996 population was 25 million. If this trend continues, how large will the population be in the year 2010
Final answer:
To calculate the population in the year 2010 based on exponential growth from 1990, use a growth rate factor and the known population figures from the given years.
Explanation:
Population Growth Calculation:
Determine the growth rate factor from 1990 to 1996: 25 million / 21.7 million = 1.152
Apply the growth rate to find the population in 2010: 21.7 million * (1.152)¹⁴ (14 years from 1996 to 2010) = 48.9 million
Problem 2 Consider three functions f, g, and h, whose domain and target are Z. Let fx)x2 g(x)=2x (a) Evaluate fo g(0) (b) Give a mathematical expression for f o g
Answer:
a) 0; b) 4[tex]x^{2}[/tex]
Step-by-step explanation:
a) To compute f o g (0), first evaluate g(x) for x=0 and then evaluate f for x=g(0).
[tex]f \circ g (0)=f(2 \cdot 0)=f(0)=0^2[/tex]
b) To compute a mathematical expression for f o g do the same but instead of 0 use x,
[tex]f \circ g (x) = f( 2 \cdot x)= (2 \cdot x )^2[/tex]
In the question, f(x) = x², g(x) = 2x. We need to determine the value of function f composed with function g at 0 (f o g(0)), and the general expression for f o g(x). f o g(0) = 0 and (f o g)(x) = 4x².
Explanation:To solve this problem, we first need to understand that 'f o g' denotes the composition of function f and function g, defined as (f o g)(x) = f(g(x)). In this case, function f(x) = x^2 and function g(x) = 2x.
(a) To evaluate f o g at 0, we substitute x = 0 into g(x), giving us g(0) = 2*0 = 0. Substituting g(0) into f(x), we get f(g(0)) = f(0) = 0. So, f o g(0) = 0.
(b) For a general form of f o g, we substitute g(x) = 2x into f(x), resulting in (f o g)(x) = f(2x) = (2x)^2 = 4x^2.
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If the profit is $8000 and the profit % is 4%, what are net sales?
Answer:
8000/4*100 = $200'000
Step-by-step explanation:
help please? even if someone gave me the steps to figure the answer myself, that'd be great
Answer:
The height is 28.57 cm.
The surface area is 9,628 cm^2.
Step-by-step explanation:
I assume the cooler is shaped like a rectangular prism with length and width of the base given, and with an unknown height.
volume = length * width * height
First, we convert the volume from liters to cubic centimeters.
60 liters * 1000 mL/L * 1 cm^3/mL = 60,000 cm^3
Now we substitute every dimension we have in the formula and solve for height, h.
60,000 cm^3 = 60 cm * 35 cm * h
60,000 cm^3 = 2,100 cm^2 * h
h = (60,000 cm^3)/(2,100 cm^2)
h = 28.57 cm
The height is 28.57 cm.
Now we calculate the internal surface area.
total surface area = area of the bases + area of the 4 sides
SA = 2 * 60 cm * 35 cm + (60 cm + 35 cm + 60 cm + 35 cm) * 28.57 cm
SA = 9,628 cm^2
The surface area is 9,628 cm^2.
Installment Buying TV Town sells a big screen smart HDTV for $600 down and monthly payments of $30 for the next 3 years. If the interest rate is 1.25% per month on the unpaid balance, find (a) the cost of the TV (b) the total amount of interest paid
Answer:
a) $ 1465.418
b) $ 214.582
Step-by-step explanation:
Since, the monthly payment formula of a loan is,
[tex]P=\frac{PV(r)}{1-(1+r)^{-n}}[/tex]
Where, PV is the principal amount of the loan,
r is the monthly rate,
n is the total number of months,
Here, P = $ 30, r = 1.25 % = 0.0125, n = 36 ( since, time is 3 years also 1 year = 12 months )
Substituting the values,
[tex]30=\frac{PV(0.0125)}{1-(1+0.0125)^{-36}}[/tex]
By the graphing calculator,
[tex]PV=865.418[/tex]
a) Thus, the cost of the TV = Down Payment + Principal value of the loan
= $ 600 + $ 865.418
= $ 1465.418
b) Now, the total payment = Monthly payment × total months
= 30 × 36
= $ 1080
Hence, the total amount of interest paid = total payment - principal value of the loan
= $ 1080 - 865.418
= $ 214.582.
For a lottery game, a player must match a sequence of three repeatable numbers, ranging from 0 to 9, in exact order. With a single ticket, what is the probability of matching the three winning numbers?
Answer:[tex]\frac{1}{1000}[/tex]
Step-by-step explanation:
For the lottery game three numbers must match in exact order
From 0 to 9 total 10 numbers are there
Therefore selecting exactly same numbers as of winner is
=[tex]^{10}C_1\times ^{10}C_1\times ^{10}C_1 [/tex]
Since numbers are repeatable therefore each time we have a choice of choosing 1 number out o 10
=[tex]10\times 10\times 10[/tex]
Probability of winning=[tex]\frac{1}{1000}[/tex]
In a lottery game where the player must match a repeatable sequence of three numbers ranging from 0-9, the probability of a single ticket having the winning sequence is 1/1000, or 0.1%.
Explanation:The subject of this problem is probability in Mathematics, specifically in a lottery context. Each digit in the sequence can be any number from 0 to 9. Because these numbers are repeatable, this means there are 10 possible numbers for each of the three digits in the sequence. Therefore, to find the total number of possible sequences, you multiply the ten options for the first digit by the ten for the second and the ten for the third, which comes to 10 * 10 * 10 = 1000 total possible sequences.
Since you are only looking for one specific sequence being the winning number, that means there’s only 1 favorable outcome out of 1000. Therefore, the probability of your ticket having the winning number sequence is 1/1000, or 0.001 in decimal form or 0.1% in percentage form.
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An urn contains 11 numbered balls, of which 6 are red and 5 are white. A sample of 4 balls is to be selected. How many samples contain at least 3 red balls?
Answer:
The total number of samples that contain at least 3 red balls is 115.
Step-by-step explanation:
Total number of balls = 11
Total number of red balls = 6
Total number of white balls = 5
A sample of 4 balls is to be selected that contain at least 3 red. It means either 3 out of 4 balls are red or 4 out of 4 ball are red.
[tex]\text{Total ways}=\text{Three balls are red}+\text{Four balls are red}[/tex]
[tex]\text{Total ways}=^6C_3\times ^5C_1+^6C_4\times ^5C_0[/tex]
Combination formula:
[tex]^nC_r=\frac{n!}{r!(n-r)!}[/tex]
Using this formula we get
[tex]\text{Total ways}=\frac{6!}{3!(6-3)!}\times \frac{5!}{1!(5-1)!}+\frac{6!}{4!(6-4)!}\times \frac{5!}{0!(5-0)!}[/tex]
[tex]\text{Total ways}=20\times 5+15\times 1[/tex]
[tex]\text{Total ways}=115[/tex]
Therefore the total number of samples that contain at least 3 red balls is 115.
Using the combination formula, it is found that 115 samples contain at least 3 red balls.
The balls are chosen without replacement, which is why the combination formula is used.
Combination formula:
[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by:
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
In this problem, the outcomes with at least 3 red balls are:
3 red from a set of 6 and 1 white from a set of 5.4 red from a set of 6.Hence:
[tex]T = C_{6,3}C_{5,1} + C_{6,4} = \frac{6!}{3!3!}\frac{5!}{1!4!} + \frac{6!}{4!2!} = 20(5) + 15 = 100 + 15 = 115[/tex]
115 samples contain at least 3 red balls.
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What is another name for validity in qualitative research? a. objectivity b. bias c. trustworthiness d. reliability
Answer:
(d) reliability
Step-by-step explanation:
mostly we see that validity and reliability is the key aspects of all research they help in differentiation between good and bad research so both are very necessary aspects of any research so the another name for validity in quantity research is reliability.
so the reliability will be the correct answer
so option (d) will be correct option
Solving Quadratic Equations by completing the square:
z^2 - 3z - 5 = 0
Answer:
[tex](z-\frac{3}{2} )^2-\frac{29}{4}[/tex]
Step-by-step explanation:
We are given the following quadratic equation by completing the square:
[tex]z^2 - 3z - 5 = 0[/tex]
Rewriting the equation in the form [tex]x^2+2ax+a^2[/tex] to get:
[tex]z^2 - 3z - 5+(-\frac{3}{2} )^2-(-\frac{3}{2} )^2[/tex]
[tex]z^2-3z+(-\frac{3}{2} )^2=(z-\frac{3}{2} )^2[/tex]
Completing the square to get:
[tex] ( z - \frac{ 3 } { 2 } )^ 2 - 5 - ( - \frac { 3 } { 2 } ) ^ 2[/tex]
[tex](z-\frac{3}{2} )^2-\frac{29}{4}[/tex]
Answer: [tex]z_1=4.19\\\\z_2=-1.19[/tex]
Step-by-step explanation:
Add 5 to both sides of the equation:
[tex]z^2 - 3z - 5 +5= 0+5\\\\z^2 - 3z = 5[/tex]
Divide the coefficient of [tex]z[/tex] by two and square it:
[tex](\frac{b}{2})^2= (\frac{3}{2})^2[/tex]
Add it to both sides of the equation:
[tex]z^{2} -3z+ (\frac{3}{2})^2=5+ (\frac{3}{2})^2[/tex]
Then, simplifying:
[tex](z- \frac{3}{2})^2=\frac{29}{4}[/tex]
Apply square root to both sides and solve for "z":
[tex]\sqrt{(z- \frac{3}{2})^2}=\±\sqrt{\frac{29}{4} }\\\\z=\±\sqrt{\frac{29}{4}}+ \frac{3}{2}\\\\z_1=4.19\\\\z_2=-1.19[/tex]
Explain why a positive times a negative is a negative number.
Explanation:
This can be explained by thinking numbers on the number line as:
Lets take we have to multiply a positive number (say, 2) with a negative number say (-3)
2×(-3)
Suppose someone is standing at 0 on the number line and to go to cover -3 , the person moves 3 units in the left hand side. Since, we have to compute for 2×(-3), The person has to cover the same distance twice. At last, he will be standing at -6, which is a negative number.
A image is shown below to represent the same.
Thus, a positive times a negative is a negative number.
A sample of 100 wood and 100 graphite tennis rackets are taken from the warehouse. If 15 wood and 14 graphite are defective and one racket is randomly selected from the sample, find the probability that the racket is wood or defective.
Answer:
The probability that the racket is wood or defective is 0.57.
Step-by-step explanation:
Let W represents wood racket, G represents the graphite racket and D represents the defective racket,
Given,
n(W) = 100,
n(G) = 100,
⇒ Total rackets = 100 + 100 = 200
n(W∩D) = 15,
n(G∩D) = 14,
⇒ n(D) = n(W∩D) + n(G∩D) = 15 + 14 = 29,
We know that,
n(W∪D) = n(W) + n(D) - n(W∩D)
= 100 + 29 - 15
= 100 + 14
= 114,
Hence, the probability that the racket is wood or defective,
[tex]P(W\cup D) = \frac{114}{200}[/tex]
[tex]=0.57[/tex]
Convert 141 to base seven.
Answer:
(141)₁₀→(241)₇
Step-by-step explanation:
(141)₁₀→(?)₇
for conversion of number from decimal to base 7 value we have to
factor 141 by 7
which is shown in the figure attached below.
from the attached figure we can clearly see that the colored digit will
give the conversion
we will write the digit from the bottom as shown in figure
(141)₁₀→(241)₇
6. Use the element method and proof by contradiction to prove that for any sets A,B and C, if B nCCA, then (C - A) n (B - A)=0.
Answer:
Suppose,
(C - A) ∩ (B - A) ≠ ∅
Let x is an element of (C - A) ∩ (B - A),
That is, x ∈ (C - A) ∩ (B - A),
⇒ x ∈ C - A and x ∈ B - A
⇒ x ∈ C, x ∉ A and x ∈ B, x ∉ A
⇒ x ∈ B ∩ C and x ∉ A
⇒ B ∩ C ⊄ A
But we have given,
B ∩ C ⊂ A
Therefore, our assumption is wrong,
And, there is no common elements in (C - A) and (B-A),
That is, (C - A) ∩ (B - A) = ∅
Hence proved...
The root of the equation f(x) = 0 is found by using the Secant method. The initial guesses are x-1 = 3.6 and x0 = 1.5. Given that f(3.6) = 7.1 and f(1.5) = 3.9, the angle the secant line makes with the x axis is ___ (Report your answer in in degrees ; keep 4 decimal places.)
Answer:
Angle made by secant line equals[tex]56.7251^{o}[/tex]
Step-by-step explanation:
Solpe of a line joining points [tex](x_{1},y_{1}),(x_{2},y_{2})[/tex] is given by
[tex]tan(\theta)=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
where [tex]y_{i}=f(x_{i})[/tex]
Applying values we get
[tex]tan(\theta)=\frac{7.1-3.9}{3.6-1.5}\\\\\theta =tan^{-1}\frac{32}{21}\\\\\theta=56.7251^{o}[/tex]
Determine whether the vectors (2, 3, l), (2, -5, -3), (-3, 8, -5) are linearly dependent or linear independent. If the vectors are linearly dependent, express one as a linear combination of the others. (Solutions of homogeneous differential equations form a vector space: it is necessary to confirm whether given functions/vectors are linearly dependent or linearly independent, chapter 4).
Answer:
So the vectors are linearly independent.
Step-by-step explanation:
So if they are linearly independent then the following scalars in will have the condition a=b=c=0:
a(2,3,1)+b(2,-5,-3)+c(-3,8,-5)=(0,0,0).
We have three equations:
2a+2b-3c=0
3a-5b+8c=0
1a-3b-5c=0
Multiply last equation by -2:
2a+2b-3c=0
3a-5b+8c=0
-2a+6b+10c=0
Add equation 1 and 3:
0a+8b+7c=0
3a-5b+8c=0
-2a+6b+10c=0
Divide equation 3 by 2:
0a+8b+7c=0
3a-5b+8c=0
-a+3b+2c=0
Multiply equation 3 by 3:
0a+8b+7c=0
3a-5b+8c=0
-3a+9b+6c=0
Add equation 2 and 3:
0a+8b+7c=0
3a-5b+8c=0
0a+4b+13c=0
Multiply equation 3 by -2:
0a+8b+7c=0
3a-5b+8c=0
0a-8b-26c=0
Add equation 1 and 3:
0a+0b-19c=0
3a-5b+8c=0
0a-8b-26c=0
The first equation tells us -19c=0 which implies c=0.
If c=0 we have from the second and third equation:
3a-5b=0
0a-8b=0
0a-8b=0
0-8b=0
-8b=0 implies b=0
We have b=0 and c=0.
So what is a?
3a-5b=0 where b=0
3a-5(0)=0
3a-0=0
3a=0 implies a=0
So we have a=b=c=0.
So the vectors are linearly independent.
Final answer:
To find out if the vectors (2, 3, l), (2, -5, -3), and (-3, 8, -5) are linearly dependent or independent, set up a linear system with the vectors and look for non-trivial solutions.
Explanation:
To determine whether the vectors (2, 3, l), (2, -5, -3), and (-3, 8, -5) are linearly dependent or linearly independent, we set up the equation a(2, 3, l) + b(2, -5, -3) + c(-3, 8, -5) = (0, 0, 0), where a, b, and c are scalars.
If only the trivial solution exists, where a = b = c = 0, then the vectors are linearly independent. If a non-trivial solution exists, then the vectors are linearly dependent.
Let's solve the system of linear equations generated from the above equation:
2a + 2b - 3c = 0,3a - 5b + 8c = 0,al - 3b - 5c = 0.Using the methods for solving systems of linear equations, such as Gaussian elimination, we can determine whether a unique solution exists.
If the determinant of the coefficients matrix is non-zero, the system has a unique solution, indicating linear independence. Otherwise, a non-unique solution indicates linear dependence, and we can express
Suppose the lifetime of a computer memory chip may be modeled by a Gamma distribution. The average lifetime is 4 years and the variance is 16/3 years squared. What is the probability that such a chip will have a lifetime of less than 8 years?
Final answer:
To find the probability that a computer memory chip will have a lifetime of less than 8 years, we can use the properties of the Gamma distribution.
Explanation:
To find the probability that a computer memory chip will have a lifetime of less than 8 years, we can use the properties of the Gamma distribution. The average lifetime of the chip is given as 4 years, which corresponds to the mean. The variance is given as 16/3 years squared, which is equal to the mean squared.
Using these values, we can determine the shape and rate parameters of the Gamma distribution. The shape (α) is equal to the mean squared divided by the variance, which in this case is 16/3. The rate (β) is equal to the mean divided by the variance, which in this case is 4/(16/3).
To find the probability that the chip will have a lifetime of less than 8 years, we can calculate the cumulative distribution function (CDF) of the Gamma distribution with the shape and rate parameters we obtained.
Professor N. Timmy Date has 31 students in his Calculus class and 17 students in his Discrete Mathematics class.
(a) Assuming that there are no students who take both classes, how many students does Professor Date have?
(b) Assuming that there are five students who take both classes, how many students does Professor Date have?
Answer: a) 48
b) 43
Step-by-step explanation:
Given : The number of students Professor Date has in his Calculus class = 31
The number of students Professor Date has in his Discrete Mathematics class = 17
(a) If we assume that there are no students who take both classes, then the total number of students Professor Date Has = 31+17=48
(b) If we assume that there are five students who take both classes, then the total number of students Professor Date Has = 31+17-5=43