A proton beam in an accelerator carries a current of 106 μa. if the beam is incident on a target, how many protons strike the target in a period of 17.0 s?

Answer:

the 10-kg object has higher acceleration

Explanation:

Answer: geometric shape tools

Explanation: plato/edmentum answer.

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Using the principles of energy conservation and kinetic energy, the distance the spring compresses when the block comes to rest is found through the equation x = sqrt((m*v*v)/k), where m is the mass, v is the velocity, k is the spring constant, and x is the distance of compression.

To compute the distance the spring is compressed when the block comes to rest, we need to consider both kinetic energy conservation and energy conservation through potential energy of the spring. Our initial kinetic energy supplied by the block sliding down the plane (K1) will turn into a potential energy in the spring when it's compressed (U2). Hence, we have K1 = U2.

Assuming initial kinetic energy (K1) given by 0.5*m*v*v, and potential energy in the spring (U2) equals to 0.5*k*x*x where x is the distance in which spring is compressed.

From the conservation of energy principle, 0.5*m*v*v = 0.5*k*x*x. By simplifying the equation, we get x = sqrt((m*v*v)/k). This equation provides us the distance the spring is compressed when the block comes to rest.

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With the known value of v (speed of sound in the medium, e.g., 343 m/s) and the desired change in frequency (25% or 0.25), you can calculate the speed you must approach the source of sound to observe a 25% change in frequency.

To observe a 25% change in frequency (Doppler effect) when approaching a source of sound, you need to know the relative velocity between you and the source of sound. The Doppler effect occurs when there is relative motion between the observer and the source of the sound.

The formula for calculating the apparent frequency (f') observed by a moving observer due to the Doppler effect is:

f' = f * (v + vo) / (v - vs)

Where:

f' = Apparent frequency observed by the moving observer

f = Actual frequency of the sound emitted by the source

v = Speed of sound in the medium (approximately 343 meters per second in air at room temperature)

vo = Velocity of the observer (positive if moving towards the source, negative if moving away from it)

vs = Velocity of the source of sound (positive if moving away from the observer, negative if moving towards it)

Since  want to observe a 25% change in frequency, the apparent frequency (f') would be 25% different from the actual frequency (f):

f' = 1.25 * f

Assuming the observer is moving towards the source (vo is positive), we can rewrite the equation as:

1.25 × f = f × (v + vo) / (v - vs)

Now, we can solve for the relative velocity vo:

(v + vo) / (v - vs) = 1.25

Cross-multiply:

v + vo = 1.25 * (v - vs)

Now, isolate vo:

vo = 1.25 × (v - vs) - v

With the known value of v (speed of sound in the medium, e.g., 343 m/s) and the desired change in frequency (25% or 0.25), you can calculate the speed you must approach the source of sound to observe a 25% change in frequency.

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At the top of the giant swing on the gymnastics high bar, candy's total mechanical energy is 1740J.

Given the data in the question;

Candy's total mechanical energy; [tex]M.E_c = \ ?[/tex]

Total Mechanical Energy (M.E) is the sum of both the potential energy and the kinetic energy of an object.

[tex]Mechanical \ Energy = Potential \ Energy + Kinetic \ Energy[/tex]

[tex]M.E = mgh + \frac{1}{2}mv^2[/tex]

Where m is the mass, g is gravitational acceleration( [tex]9.8m/s^2[/tex] ), h is the height and v is the velocity.

We substitute our values into the equation

[tex]M.E_c = ( 50kg * 9.8m/s^2*3.5m) + ( \frac{1}{2}* 50\ *(1m/s)^2)\\\\M.E_c = 1715kg.m^2/s^2 + 25kg.m^2/s^2\\\\M.E_c = 1740 kg.m^2/m^2\\\\M.E_c = 1740J\\[/tex]

Therefore, at the top of the giant swing on the gymnastics high bar, candy's total mechanical energy is 1740J

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For an uniformly accelerated motion, the following relationship is used:

[tex]2 a S=v_f^2 -v_i ^2[/tex] (1)

where a is the acceleration, S the distance covered, and vf and vi the final and initial speeds of the motion.

In our problem we are dealing with a rotational motion. Initially, the salad spinner has constant angular speed, which is given by

[tex]\omega _i = 2 \pi f[/tex]

where f is the rotational frequency, which is the number of revolutions per second:

[tex]f=  \frac{20 rev}{5 s}=4 Hz [/tex]

so the initial angular speed is

[tex]\omega _i = 2 \pi (4 Hz)=25.2 rad/s[/tex]

Then, the salad spinner starts to decelerate with constant deceleration [tex]\alpha[/tex], and during its deceleration it spins for other 6 revolutions, so covering a total angle of

[tex]\theta = 2 \pi (6 rev)=37.7 rad[/tex]

until it stops, so until it reaches a final speed of [tex]\omega _f=0[/tex].

To find the angular acceleration, we can use the equivalent of equation (1) for angular motions:

[tex]2 \alpha \theta = \omega_f^2 - \omega_i^2[/tex]

and so, since the final speed is [tex]\omega _f=0[/tex]:

[tex]\alpha = -  \frac{\omega _i^2}{2 \theta}=- \frac{(25.2 rad/s)^2}{2\cdot 37.7 rad}=-8.4 rad/s^2  [/tex]

where the negative sign means the salad spinner is decelerating.

Answer:

[tex] \alpha = -\frac{(25.132 rad/s)^2}{2* 37.7 rad}= -8.377 rad/s^2[/tex]

And we can convert this into degrees like this:

[tex] \alpha= -8.377 rad/s^2 * (\frac{180}{\pi rad}) =-479.967 rad/s^2[/tex]

Explanation:

For this case we assume that the angular acceleration is constant and the spinner slows down and come to rest at the end

We can calculate the distance traveled each revolution with this formula:

[tex] \theta= 20 rev * \frac{2\pi rad}{1 rev}= 40 \pi rad[/tex]

And since we know that the time to reach the velocity 0 is 5 s we can find the angular velocity like this:

[tex] w_o= \frac{\theta}{t}= \frac{40 \pi rad}{5 s}= 25.132 rad/s[/tex]

We know that the spinner rotates 6 more times before come rest, so the total distance traveled is:

[tex] \theta= 6* 2\pi = 37.699 rad[/tex]

[tex] w_f = 0 rad/s[/tex]

And we have the following formula :

[tex] w^2_f = w^2_i + 2\alpha \theta[/tex]

Since we know that the final angular velocity is 0 we can solve for [tex] \alpha[/tex] the angular acceleration and we got:

[tex] \alpha = -\frac{w^2_o}{2 \theta}[/tex]

And replacing the values that we found before we have this:

[tex] \alpha = -\frac{(25.132 rad/s)^2}{2* 37.7 rad}= -8.377 rad/s^2[/tex]

And we can convert this into degrees like this:

[tex] \alpha= -8.377 rad/s^2 * (\frac{180}{\pi rad}) =-479.967 rad/s^2[/tex]

The fulcrum in a hammer when removing a nail is at the part where the hammer pivots.

By applying effort to the handle of a claw hammer, the output force at the nail puller end is increased due to the lever principle. Understanding these concepts aids in efficiently removing nails from wood.

Answer: Option (B) is the correct answer.

Explanation:

It is known that oxygen, sulfur and selenium are all group 16 elements.

The electronic configuration of oxygen is as follows.

     [tex]1s^{2}2s^{2}2p^{4}[/tex]

The electronic configuration of sulfur is as follows.

     [tex]1s^{2}2s^{2}2p^{6}3s^{2}3p^{4}[/tex]

The electronic configuration of selenium is as follows.

     [tex]1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{10}4p^{4}[/tex]

Hence, we can see that on moving down the group there is increase in energy levels of the atoms from 2p to 4p.

Therefore, we can conclude that when traveling from oxygen to sulfur to selenium, through this group in the periodic table, change is that the number of energy levels increases.

Final answer:

The change in potential energy of the spring is 152.19 J.

Explanation:

The potential energy of a spring is given by the equation PE = (1/2)kx², where k is the spring constant and x is the displacement of the spring. In this case, the change in length of the spring is 0.53 m (0.79 m - 0.26 m). We can calculate the potential energy change using the formula and given values:

PE = (1/2)(1140 N/m)(0.53 m)² = 152.19 J

Therefore, the change in potential energy of the spring is 152.19 J.

If the speed of an object increases, then its kinetic energy will increase proportionally because speed and kinetic energy have a linear relationship when graphed.

just got it right...

The question involves physics and vector subtraction to determine the wind's speed and direction affecting an airplane's travel based on its heading and ground velocity.

The student is asking about determining the wind's speed and direction based on an airplane's velocity relative to the ground and its intended heading. To solve for this, we need to use vector subtraction since the airplane's ground velocity can be thought of as a combination of its own speed and the wind's influence. Given that the airplane is heading north at 45.0 m/s and its ground speed is 38.0 m/s at an angle west of north, the wind's speed and direction are the vectors that need to be added to the airplane's heading to equal the ground speed vector. A vector diagram would need to be drawn, and trigonometry would be used to calculate the magnitude of the wind's vector and its angle relative to the west.

U=1/2QV

U=1/2CV^2

U=Q^2/2C

Layer masks are a non-destructive image editing technique that allows changes to be applied without altering the original image data, providing safety and flexibility in editing.

One accurate fact about layer masks in image editing is that they are non-destructive. This means that when Jack works with layer masks, he is not directly altering or damaging the original image data. Instead, layer masks allow him to apply changes, such as hiding or revealing parts of the layer, without permanently affecting the image. These masks can be edited at any time to adjust the visibility of different portions of the layer. If a mistake is made, Jack can simply edit the mask to correct the issue, rather than having to restore the original image from a separate file. Therefore, layer masks provide flexibility and safety for image editing, ensuring the original data remains intact.

The critical angle is the smallest incident angle at which light is no longer refracted into water, but instead is totally internally reflected. This can be calculated using Snell's law, where the sine of the critical angle is the ratio of the indices of refraction for water and glass.

The smallest value of the incident angle θa for which none of the ray refracts into water, and instead exhibits total internal reflection, is known as the critical angle. To find this critical angle, we can apply Snell's law (n1 × sin(θa) = n2 × sin(θb)), where θa is the incident angle and θb is the refracted angle when θb is 90°, the angle of refraction is at the maximum and therefore indicates the critical angle condition. Using the indices of refraction for glass (n1) and water (n2), we can solve for the critical angle which will indicate the threshold above which light will not refract into water but instead be totally internally reflected.

Sir Isaac Newton is the primary contributor to the universal law of gravitation, with his precise mathematical formula that unified terrestrial and celestial phenomena. Johannes Kepler's laws of planetary motion were foundational for Newton's work, and Albert Einstein expanded on these ideas with his theory of general relativity.

Several prominent individuals contributed to the discovery and understanding of the universal law of gravitation. Sir Isaac Newton is the most well-known figure associated with the law, as he defined the gravitational force, proposing that it was a universal force that explained both why objects fall to Earth and the motions of celestial bodies. He was the first to provide a precise mathematical formula for the law of gravitation.

Before Newton, Johannes Kepler discovered three laws of planetary motion, which Newton found crucial for his own work, as they showed gravitation's effects on planetary orbits. Moreover, Albert Einstein expanded upon the concept of gravitation with his theory of general relativity which showed that there is more to the gravity story than Newton's law suggested. Although their contributions were indirect, scientists such as Galileo Galilei and Robert Hooke, also helped set the stage for Newton's discoveries through their work on planetary motions and gravitational investigations respectively.

Final answer:

The calculation of energy required to move an object to an altitude twice the Earth's radius involves understanding and applying principles of gravitational potential energy and the universal law of gravitation.

Explanation:

The question involves calculating the energy required to move a 1350 kg object from the Earth's surface to an altitude twice the Earth's radius. To solve this, we use the formula for gravitational potential energy (GPE), which is GPE = mgh at close distances to Earth's surface, and the universal law of gravitation for larger distances.

However, at distances far from the surface, the formula shifts to GPE = -G * (m1*m2)/r, where G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between their centers. Since the altitude is twice the Earth's radius, the effective distance r would be 3 times the Earth's radius. This question requires integration of both concepts and understanding of physics to solve comprehensively.

A 7 L sample of gas has a pressure of 1.1 atm at a temperature of 285 K. If the pressure decreases to 0.6 atm, causing the volume to increase to 10 L, what is the new temperature? Round your answer to the nearest tenth.

Answer: 222.1K