A quadrilateral with two sets of parallel sides and four right angles is a
parallelogram
rhombus
rectangle
trapezoid

The baker's prediction had a 17.39% error.

To calculate the percent error of the baker's prediction, we use the formula:

Percent Error = (|Actual Value - Predicted Value| / Actual Value) * 100%

In this case, the Actual Value is the number of cupcakes actually sold, 115. The Predicted Value is the number the baker predicted to sell, 95.

So, the computation will be:

Percent Error = (|115 - 95| / 115) * 100%

Percent Error = (20 / 115) * 100

Percent Error = 0.1739 * 100%

Percent Error = 17.39%

Answer:  The required equation of the line is [tex] y=-\dfrac{5}{2}x-1.[/tex]

Step-by-step explanation:  We are given to find the equation of the line that is parallel to the following line and passes through the point (-2, 4) :

[tex]5x+2y=12~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]

We know that

the slope-intercept form of the equation of a straight line is given by

[tex]y=mx+c,[/tex]

where m is the slope of the line.

From equation (i), we have

[tex]5x+2y=12\\\\\Rightarrow 2y=-5x+12\\\\\Rightarrow y=-\dfrac{5}{2}x+6.[/tex]

So, the slope of line (i) is given by

[tex]m=-\dfrac{5}{2}.[/tex]

We know that the slopes of two parallel lines are equal. So, the slope of the new line will be

[tex]m=-\dfrac{5}{2}.[/tex]

Since the line passes through the point (-2, 4), so its equation will be

[tex]y-4=m(x-(-2))\\\\\\\Rightarrow  y-4=-\dfrac{5}{2}(x+2)\\\\\\\Rightarrow y-4=-\dfrac{5}{2}x-5+4\\\\\\\Rightarrow y=-\dfrac{5}{2}x-1.[/tex]

Thus, the required equation of the line is [tex] y=-\dfrac{5}{2}x-1.[/tex]

To navigate to page 35 of a report, you can use the 'find' function in a web browser with CONTROL or COMMAND + F, utilize the table of contents with hyperlinks, or enter the page number in a navigator window's spin box, depending on the device and format.

To quickly navigate to page 35 of a report, you have several options depending on the format and the device you are using. If you are viewing the report on a web browser, you can usually press CONTROL or COMMAND and the letter F to open the 'find' function and type '35' to jump to page 35. Alternatively, if the document has a table of contents with hyperlinks, you can click on the relevant section to navigate quickly. For documents with a navigator window, enter '35' in the spin box to jump straight to that page. In a mobile reading environment, you may find a Contents button at the top of the screen; clicking this can allow you to select and jump to the desired page or section.

The range of possible side lengths for the square is from slightly more than 47 inches to slightly less than 49.5 inches. This is found by dividing the given perimeters by 4, using the formula p=4s.

In this problem, we need to find the range of possible side lengths of a square where the perimeter is more than 188 inches but less than 198 inches. Remember that the perimeter of a square is found by multiplying the length of one side by 4 (p=4s).

First, let's find the side length for a square with a perimeter of 188 inches. We do this by dividing the perimeter by 4: 188 / 4 = 47 inches. So, any square with side lengths greater than 47 inches would have a perimeter more than 188 inches.

Next, we find the side length for a square with a perimeter of 198 inches. Similarly, we divide the perimeter by 4: 198 / 4 = 49.5 inches. So any square with side lengths less than 49.5 inches would have a perimeter less than 198 inches.

Therefore, the range of possible side lengths that satisfy these conditions is from slightly more than 47 inches to slightly less than 49.5 inches.

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Answer:

the person up is wrong

Step-by-step explanation:

i got it wrong on the test rn

The quadratic equation is y = x^2 - 8x + 16

From the question, we have:

x = 4

Since the graph only touches x = 4 and it does not cross it, then it means that the graph has a multiplicity of 2 at x = 4

The equation is then represented as:

y = (x - 4)^2

Expand

y = x^2 - 8x + 16

Hence, the quadratic equation is y = x^2 - 8x + 16

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[tex]2m^2-7m-13=-10\ \ \ |+10\\\\2m^2-7m-3=0[/tex]

[tex]a=2;\ b=-7;\ c=-3\\\\b^2-4ac=(-7)^2-4\cdot2\cdot(-3)=49+24=73\\\\m_1=\dfrac{-b-\sqrt{b^2-4ac}}{2a};\ m_2=\dfrac{-b+\sqrt{b^2-4ac}}{2a}\\\\m_1=\dfrac{-(-7)-\sqrt{73}}{2\cdot2}=\dfrac{7-\sqrt{73}}{4}\\\\m_2=\dfrac{-(-7)+\sqrt{73}}{2\cdot2}=\dfrac{7+\sqrt{73}}{4}[/tex]

Answer:

-1/3

Step-by-step explanation:

We need a c number that:

5/6x + cx = 1/2x

We clear the equation:

cx = 1/2x -5/6x

c = 1/2 -5/6

c= -2/6 = -1/3

Answer:

Yes because the relative difference between y-values and x-values is the same no matter what which pairs of (x,y) values you use to calculate it

Step-by-step explanation:

Yes, this set of ordered pairs have been generated by a linear function because the relative difference between y-values and x-values is the same no matter which pairs of (x, y) values you use to calculate it.

The correct option is (B)

Graph is a mathematical representation of a network and it describes the relationship between lines and points.

Given are ordered pairs are: (-3,0) (-2,4)(-1,8)(0,12)(1,16)(2,20).

It can be seen that the there only unit increase in x coordinates and units increase in consecutive y- coordinates.

Now, if we set up the equation of line as:

Here, m =4 and b = 12

So the relationship is linear and represented by the equation

y=4x+12

Hence, the relative difference between y-values and x-values is the same no matter which pairs of (x, y) values you use to calculate it.

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The ends of the graph of the function f(x) = 3x^5 + 6x will display the behavior described in option c. This is due to the highest power of x in the equation being an odd number and the coefficient being positive. As such, the left end of the graph will start down at a large negative and the right end will go upwards.

The behavior of the ends of the graph of the function f(x) = 3x^5 + 6x is determined by the highest power of x in the equation, which is 5 in this case. The coefficient of x^5 is positive, so as x approaches positive infinity, f(x) also approaches positive infinity. Conversely, as x approaches negative infinity, the value of f(x) would approach negative infinity. We can describe this behavior as the left end of the graph starting at a large negative and the right end going upwards. Thus, answer c. 'the left end will start down at a large negative and the right end will go upwards' is correct.

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Answer:

25

Step-by-step explanation:

The answer is B or the purple one

Answer:

The image B with purple figures is correct.

Step-by-step explanation:

We are given the figure DEF and we are required to find the figure which is obtained after reflecting it.

Now, reflection of a figure means to flip the figure over a line.

In the green figure, the points D and E are interchanged which is not possible in reflection.

In the blue figure, there is no change.

In the purple figure, the triangle is flipped over the line DE and so it is the correct answer.

Hence, the purple figure is obtained after reflecting the figure DEF.

Answer:

The Triangle Drawn by ,Yu-Xi,has measure of two angles ,79° and 23°.

All the Basic Learners who knows Math ,that,sum of Measures of three Interior angles of Triangle is 180°.

→79°+23°+Third Angle =180°

→102°+Third Angle =180°

→Third Angle =180° -102°

Third Angle =78°

Final answer:

The length of line CF is 20 units.

Explanation:

Let's analyze the given information step by step:

Since line EB is perpendicular to line BF, triangle EBF is a right triangle. Let's assume the length of line BF is x units. Using the area of a triangle formula, we have:

Area of triangle EBF = (1/2) * base * height

20 = (1/2) * x * 2

Simplifying the equation, we get:

20 = x

Therefore, the length of line BF (or CF) is 20 units.