A radioactive substance decays by x % each day. After 8 days half of the substance has decayed. Find the value of x. Give your answer to 1 decimal place.

Answers

Answer 1

Answer:

8.3

Step-by-step explanation:

Let Ao be the original amount and A the amount after t days.

Then we have the exponential function

     A = Ao(1 - x)^t or

A/Ao = (1 - x)^t

When t = 8, A/Ao = 0.5

         0.5 = (1 - x)^8

(0.5)^(1/8) = 1 - x

     0.917 = 1 - x

            x = 1 - 0.917 = 0.083 = 8.3 %

The substance decays by 8.3 % each day.


Related Questions

I need help with this problem.

Answers

I’m pretty sure that the slope of that function is 5/8

Problem: Same y intercept as x+4y=16, through (4,5)

Y intercept is when x=0 so 4y=16, y=4, y intercept (0,4)

Slope of line through (0,4) and (4,5) is change in y over change in x,

m = (5 - 4)/(4 - 0) = 1/4

Answer: slope 1/4

Check:

The new line is y = (1/4) x + 4

because the y intercept is still (0,4)

Let's check it's through (4,5)

(1/4) (4) + 4 = 5 check

Assume that by continuing your education, you increased your yearly earning potential from $21,484 to $39,746. If the additional education costs $18,000, in about how many years will it pay for itself?

Answers

Answer:

By continuing my education I increased my earning potential from $21,484 to $39,746 a year. That's a difference of $18262 a year.

If the additional education costs $18,000, then in one year it will pay for itself.

Answer:

The answer is 1 year.

Step-by-step explanation:

You increased your yearly earning potential from $21,484 to $39,746.

The difference is : [tex]39746-21484=18262[/tex] dollars

This difference is in a year.

So, if the additional education costs $18,000, then in about 1 year it will pay for itself.

Hence, the answer is 1 year.

Felicity set the thermostat of her refrigerator to 37°F. The refrigerator temperature t in degrees Fahrenheit h hours after the temperature sensor in the refrigerator is activated satisfies t=1cos(1.05h)+37 . Determine the period of the function and explain what it represents. Include the maximum and minimum temperatures in your answer.

Answers

Answer:

Period=6

Step-by-step explanation:

Given:

t=1cos(1.05h)+37

Using acos(bx-c)+d to find the period of the given function

amplitude= a

period= 2π/Bb

phase shift=c (positive is to the left)

vertical shift=d

comparing with t=1cos(1.05h)+37, we get

a=1

b=1.05

c=0

d=37

period= 2π/b

          =2π/1.05

          =5.983

          =6

Period of function is 6, after every 6 hours the refrigerator sensor will reach its maximum temperature and the cycle will move towards reducing temperature i.e it'll reach the minimum temperature then again the cycle will move upwards raising the temperature to maximum and so one period will be completed!

Answer:

6

Step-by-step explanation:

Felicity set the thermostat of her refrigerator to 37°F. The refrigerator temperature t in degrees Fahrenheit h hours after the temperature sensor in the refrigerator is activated satisfies t=1cos(1.05h)+37. Therefore, the period of the function is 6.

Rahm used a payment plan to purchase wood for a home project. The wood he bought cost $500. The clerk at the store offered him this payment plan instead.

Answers

Answer: 210

Step-by-step explanation:

55×12=660-500=160+50(down payment)=210

The total amount(interset+down payment) is $210 if the Rahm used a payment plan to purchase wood for a home project. The wood he bought cost $500.

What is a payment plan?

Paying down any outstanding debt, or occasionally more than one obligation, by consolidation into a structured payment schedule is referred to as a payment plan.

We have the wood he bought cost $500.

Here some data are missing, so we are assuming the monthly payment is $55 and duration is 1 year

= 55×12   (1 year = 12 months)

= $660

= 600 – 500

= $160

Down payment = $50

Total amount = 160+50 = $210

Thus, the total amount(interset+down payment) is $210 if the Rahm used a payment plan to purchase wood for a home project. The wood he bought cost $500.

Learn more about the payment plan here:

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In the equation x=y^3 - 10, is y a function of x?

Answers

Final Answer:

Yes, y is a function of x in the given equation x = y³ - 10.

Explanation:

In the equation x = y³ - 10, y is indeed a function of x. To determine whether y is a function of x, we need to check if each x-value corresponds to a unique y-value. In this case, for every x, there exists only one corresponding y. Let's consider the equation step by step.

The given equation x = y³ - 10 implies that y³ = x + 10. To solve for y, we take the cube root of both sides, yielding y = [tex](x + 10)^(^1^/^3^)[/tex]. This expression defines y explicitly in terms of x, confirming that for every x, there is a unique y. Thus, the equation satisfies the criteria for a function.

Examining the nature of the equation further, we observe that the term[tex](x + 10)^(^1^/^3^)[/tex] represents a real-valued function. The cube root of any real number is a single-valued function, ensuring that y is indeed uniquely determined by x. Therefore, we can confidently conclude that y is a function of x in the given equation x = y³ - 10.

One canned juice drink is 15​% orange​ juice; another is 5​% orange juice. How many liters of each should be mixed together in order to get 10 L that is 14​% orange​ juice?

Answers

x = amount of liters of the 15% OJ

y = amount of liters of the 5% OJ

let's recall that

[tex]\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}[/tex]

so then, the amount of juice in the 15% solution will be (15/100)*x, or 0.15x

and the amount of juice in the 5% solution will be (5/100)*y or 0.05y.

we know our mixture must be 10 liters at 14% or namely 14/100, which will give in juice (14/100)*10 or 1.4 liters or pure juice in the solution with water making the OJ.

[tex]\bf \begin{array}{lcccl} &\stackrel{liters}{quantity}&\stackrel{\textit{\% of }}{juice}&\stackrel{\textit{liters of }}{juice}\\ \cline{2-4}&\\ \textit{15\% OJ}&x&0.15&0.15x\\ \textit{5\% OJ}&y&0.05&0.05y\\ \cline{2-4}&\\ mixture&10&0.14&1.4 \end{array}~\hfill \begin{cases} x+y=10\\ \boxed{y}=10-x\\ \cline{1-1} 0.15x+0.05y=1.4 \end{cases} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\bf \stackrel{\textit{substituting on the 2nd equation}}{0.15x+0.05\left( \boxed{10-x} \right)}=1.4\implies 0.15x+0.5-0.05x=1.4 \\\\\\ 0.10x+0.5=1.4\implies 0.10x=0.9\implies x=\cfrac{0.9}{0.10}\implies \blacktriangleright x = 9 \blacktriangleleft \\\\\\ \stackrel{\textit{since we know that}}{y=10-x}\implies y=10-9\implies \blacktriangleright y=1 \blacktriangleleft[/tex]

I need help with these removable discontinuities.

Answers

Answer:

First problem: a (2,0)

Second problem: b. none of these; the answer is (4, 5/3) which is not listed.

Third problem: b. none of the above; there are no holes period.

Step-by-step explanation:

First problem:  The hole is going to make both the bottom and the top zero.

So I start at the bottom first.

[tex]x^2-3x+2=0[/tex]

The left hand expression is factorable.

Since the coefficient of [tex]x^2[/tex] is 1, you are looking for two numbers that multiply to be 2 and add to be -3.

Those numbers are -2 and -1 since (-2)(-1)=2 and -2+(-1)=-3.

The factored form of the equation is:

[tex](x-2)(x-1)=0[/tex].

This means x-2=0 or x-1=0.

We have to solve both equations here.

x-2=0

Add 2 on both sides:

x=2

x-1=0

Add 1 on both sides:

x=1

Now to determine if x=2 or x=1 is a hole, we have to see if it makes the top 0.

If the top is zero when you replace in 2 for x, then x=2 is a hole.

If the top is zero when you replace in 1 for x, then x=1 is a hole.

Let's do that.

[tex]x^2-4x+4[/tex]

x=2

[tex]2^2-4(2)+4[/tex]

[tex]4-8+4[/tex]

[tex]-4+4[/tex]

[tex]0[/tex]

So we have a hole at x=2.

[tex]x^2-4x+4[/tex]

x=1

[tex]1^2-4(1)+4[/tex]

[tex]1-4+4[/tex]

[tex]-3+4[/tex]

[tex]1[/tex]

So x=1 is not a hole, it is a vertical asymptote.  We know it is a vertical asymptote instead of a hole because the numerator wasn't 0 when we plugged in the x=1.

So anyways to find the point for which we have the hole, we will cancel out the factor that makes us have 0/0.

So let's factor the denominator now.

Since the coefficient of [tex]x^2[/tex] is 1, all we have to do is find two numbers that multiply to be 4 and add up to be -4.

Those numbers are -2 and -2 because -2(-2)=4 and -2+(-2)=-4.

[tex]f(x)=\frac{(x-2)(x-2)}{(x-2)(x-1)}=\frac{x-2}{x-1}[/tex]

So now let's plug in 2 into the simplified version:

[tex]f(2)=\frac{2-2}{2-1}=\frac{0}{1}=0[/tex].

So the hole is at x=2 and the point for which the hole is at is (2,0).

a. (2,0)

Problem 2:

So these quadratics are the same kind of the ones before. They all have coefficient of [tex]x^2[/tex] being 1.

I'm going to start with the factored forms this time:

The factored form of [tex]x^2-3x-4[/tex] is [tex](x-4)(x+1)[/tex] because -4(1)=-3 and -4+1=-3.

The factored form of [tex]x^2-5x+4[/tex] is [tex](x-4)(x-1)[/tex] because -4(-1)=4 and -4+(-1)=-5.

Look at [tex]\frac{(x-4)(x+1)}{(x-4)(x-1)}[/tex].

The hole is going to be when you have 0/0.

This happens at x=4 because x-4 is 0 when x=4.

The hole is at x=4.

Let's find the point now. It is (4,something).

So let's cancel out the (x-4)'s now.

[tex]\frac{x+1}{x-1}[/tex]

Plug in x=4 to find the corresponding y:

[tex]\frac{4+1}{4-1}{/tex]

[tex]\frac{5}{3}[/tex]

The hole is at (4, 5/3).

Third problem:

[tex]x^2-4x+4[/tex] has factored form [tex](x-2)(x-2)[/tex] because (-2)(-2)=4 and -2+(-2)=-4.

[tex]x^2-5x+4[/tex] has factored form [tex](x-4)(x-1)[/tex] because (-4)(-1)=4 and -4+(-1)=-5.

There are no common factors on top and bottom.  You aren't going to have a hole.  There is no value of x that gives you 0/0.

Write an expression for "the quotient of 2 and 4."

Answers

Answer:

2÷ 4

Step-by-step explanation:

Quotient means division

2÷ 4

A cylindrical water tower with a radius of 11 m and a height of 50 m is filled to a height of h. The volume V of water​ (in cubic​ meters) is given by the function​ g(h) = 121pih. Determine the appropriate domain of the function. Identify the independent and dependent variables.

Answers

Answer:

The domain of the function is 0 ≤ h ≤ 50

Independent and dependent variables are h and g respectively.

Step-by-step explanation:

Given function that shows the volume of the water,

[tex]V=121\pi h[/tex]

Where, h represents the height of water ( in meters ) filled on the water tank,

Since, the height can not be negative,

⇒ 0 ≤ h,

Also, the height of the tower is 50 m,

That is, h can not exceed 50,

⇒ h ≤ 50

By combining the inequalities,

0 ≤ h ≤ 50,

Domain of the given function is the set of all possible value of h,

Hence, Domain for the given function is 0 ≤ h ≤ 50

Now, the variable which is taken for measuring the another variable is called independent variable while the variable which is obtained by independent variable is called dependent  variable,

Here, we take different values of h for finding the different values of g,

Therefore, independent and dependent variables are h and g respectively.

A certain drug is made from only two ingredients: compound A and compound B. There are 3 milliliters of compound A used for every 5 milliliters of compound B. If a chemist wants to make 680 milliliters of the drug, how many milliliters of compound A are needed?

Answers

Answer:

255 milliliters.

Step-by-step explanation:

The fraction of Compound A in the mixture = 3 / (3+ 5) = 3/8.

So the amount of A to make 680 mls of the drug

= (3/8) * 680

=  255 milliliters.

The juniors and seniors at Lawrence High School are required to enroll in one fine arts elective each year. The students' selections are displayed in the two-way relative frequency table.

Fine Arts Course Selections
Art Band Choir Drama Total
Juniors 0.02 0.27 0.24 0.05 0.58
Seniors 0.12 0.04 0.05 0.21 0.42
Total 0.14 0.31 0.29 0.26 1

Which observation is supported by the data?

A.
Art is the most popular elective among seniors.
B.
Choir is the most popular elective among seniors.
C.
Band is the most popular elective among juniors.
D.
Drama is the most popular elective among juniors.

Answers

Answer:

C. Band is the most popular elective among juniors.

Step-by-step explanation:

Let's just arrange your table:

                   Art      Band      Choir      Drama      Total

Juniors:     0.02      0.27        0.24       0.05        0.58

Seniors:     0.12      0.04       0.05       0.21         0.42

Total:         0.14       0.31         0.29        0.26          1

What you see here are portions or percentages of the people who chose under each category.

Here's another way to look at it.

                   Art      Band      Choir      Drama      Total

Juniors:        2%      27%        24%        5%           58%

Seniors:       12%      4%           5%         21%         42%

Total:            14%      31%        29%        26%   100%

If you read it horizontally, you are looking at it based on Juniors and Seniors.

If you read it vertically, you're looking at it based on the elective class.

The totals show how the group looks as a whole. And it gives you an idea of how much of the population chose each elective class.

Let's go back to your choices.

A is wrong, because as you can see, only 12% of the population that are Seniors chose Art. The most popular was actually Drama with 21%.

B. Is wrong as well because  only 5% of the population that are seniors chose Choir.

C. Is true because the as you can see, 27% of the population that are juniors chose Band.

D is wrong because of the above statement.

Now you do not have to make them into percentages to do this. You can also interpret the same thing by looking for the highest relative frequency to determine which one is most popular.

Answer:

C. Band is the most popular elective.

Step-by-step explanation:

Ntoine and Tess have a disagreement over how to compute a 15% gratuity on $46.00. Tess says, "It is easy to find 10% of 46 by moving the decimal point one place to the left to get $4.60. Do that twice. Then add the two amounts to get $4.60 + $4.60 = $9.20 for the 15% gratuity." How should Antoine respond to Tess's method?

Answers

Answer:

Ntoine and Tess have a disagreement over how to compute a 15% gratuity on $46.00.

This in real becomes :

[tex]0.15\times46=6.90[/tex] dollars

But, Tess  says, "It is easy to find 10% of 46 by moving the decimal point one place to the left to get $4.60. Do that twice. Then add the two amounts to get $4.60 + $4.60 = $9.20

So, Tess is wrong. Rather she should have done 10% of $46 giving $4.6 and then half of 4.6 that is 2.3 dollars. Getting a total of [tex]4.6+2.3=6.9[/tex] dollars which is the real amount.

Answer:

Ntoine and Tess have a disagreement over how to compute a 15% gratuity on $46.00.

This in real becomes :

dollars

But, Tess  says, "It is easy to find 10% of 46 by moving the decimal point one place to the left to get $4.60. Do that twice. Then add the two amounts to get $4.60 + $4.60 = $9.20

So, Tess is wrong. Rather she should have done 10% of $46 giving $4.6 and then half of 4.6 that is 2.3 dollars. Getting a total of  dollars which is the real amount.

Step-by-step explanation:

trust me

Write the equation of the following circle with the marked radius if it is centered at the origin.

Answers

Answer:

x² + y² = 42.25

Step-by-step explanation:

The equation of a circle centred at the origin is

x² + y² = r² ← r is the radius

here r = 6.5, hence

x² + y² = 6.5², that is

x² + y² = 42.25 ← equation of circle

Answer: [tex]x^2 + y^2 = 42.25[/tex]

Step-by-step explanation:

The equation of a circle in center-radius form is:

[tex](x - h)^2 + (y - k)^2 = r^2[/tex]

Where the center is at the point (h, k) and the radius is "r".

Given the circle with radius 6.5 and centered at the origin, you can identify that:

 [tex]h=0\\y=0\\r=6.5[/tex]

Then, substituting values into [tex](x - h)^2 + (y - k)^2 = r^2[/tex], you get:

[tex](x - 0)^2 + (y - 0)^2 = (6.25)^2[/tex]

[tex]x^2 + y^2 = 42.25[/tex]

URGENT PLEASE ANSWER THIS MATH QUESTION ABOUT FINDING AREA

Answers

you do base times height and so it 9.6 • 10.4 = 99.84

Joan makes a base salary of $275 per week and a commission of 4% of sales over $1000. If she sells $1250 of merchandise this week, calculate the amount of her paycheck for the week.

Answers

Joan makes $275/week.

In addition to $275, she also makes 4 percent on sales over $1000.

So, 1250 - 1000 = 250.

Then 250(0.04) = 10.

Let t = amount of her paycheck for the week.

t = $275 + $10

t = $285

Module 8 Pre-Cal DBA Help? (!!!!!!!IMPORTANT!!!!!!!)
I have a DBA tomorrow, 7-20-19 and I have to tell my teacher 3 things I learned. I havent learned a single thing and I dont understand most of it.
The module consists of Parabolas, Ellipses, Hyperbolas, Parametric Equations. and Polar Coordinates. What are a few things that I can say I learned about these specific topics?

Answers

Answer:

Heres the truth.

Step-by-step explanation:

If you haven't learned anything and you need to do a DBA. Just tell your teacher this, "Even though I've completed the Module... I still don't fully understand the concepts throughout the module. Is there anyway you can help me go over, review, and workout specific things that i understand and don't understand?"

It's best to actually do the work instead of submiting questions for others to answer on here. You should ask for help from a teacher, or go to the online tutoring.

Hashem was studying for his upcoming math test. On Monday, he studied for 2 over 3 of an hour. On Tuesday, he studied for 5 over 6 the amount of time he studied on Monday. What fraction of an hour did Hashem study on Tuesday? _____ of an hour

Answers

2/3(5/6)= 10/18= 5/9

Hashem studies 5/9 of a hour on Tuesday.

Hope this helps!

Express cos5mcos(-3m) as a sum or difference.

-1/2cos2m + 1/2cos2m
1/2cos2m - 1/2cos8m
1/2cos8m - 1/2cos2m
1/2cos8m + 1/2cos2m

Answers

Answer:

D

Step-by-step explanation:

Using the product to sum formula

• 2cosAcosB = cos(A+B) + cos(A - B)

note that cos(- 3m) = cos 3m, hence

cos5m cos(- 3m)

= cos 5m cos3m ← A = 5m and B = 3m

= [tex]\frac{1}{2}[/tex] ( 5m + 3m) + cos(5m - 3m) ]

= [tex]\frac{1}{2}[/tex] cos 8m + [tex]\frac{1}{2}[/tex] cos 2m

The expression of cos5mcos(-3m) as a sum or difference results in  1/2cos2m + 1/2cos8m.

To express cos5mcos(-3m) as a sum or difference, we can use the trigonometric identity cos(A)cos(B) = 1/2[cos(A+B) + cos(A-B)].

Applying this identity to the given expression, we get 1/2[cos(5m - 3m) + cos(5m + 3m)] = 1/2[cos(2m) + cos(8m)].

Therefore, the given expression cos5mcos(-3m) can be simplified to 1/2cos2m + 1/2cos8m.

Amy read on the internet that spraying plants with diluted coffee will kill any aphids that are on the plants. Amy wants to know if this is true. Which of these is an appropriate hypothesis for Amy to test? If plants infested with aphids are sprayed with diluted coffee then the aphids will die. Aphids sprayed with diluted coffee will not infest plants. Plant sprayed with diluted coffee will not be infested by aphids. If plants with bug infestations are sprayed with diluted coffee then the bugs will die

Answers

Answer:

If plants infested with aphids are sprayed with diluted coffee then the aphids will die.

Step-by-step explanation:

"Aphids sprayed with diluted coffee will not infest the plants" doesn't explain what happens to the aphids. (For example: they die, etc.)

"Plant sprayed with diluted coffee will not be infested by aphids" doesn't explain why it will not be infested by aphids.

"If plants with bug infestations are sprayed with diluted coffee then the bugs will die" doesn't say what type of bug, not all bugs will die from diluted coffee on plants.

Final answer:

The hypothesis best suited for Amy's test is 'If plants infested with aphids are sprayed with diluted coffee then the aphids will die', because it directly tests the claim Amy read online and is measurable through an experiment.

Explanation:

The appropriate hypothesis for Amy to test in order to determine whether spraying plants with diluted coffee will kill aphids is: 'If plants infested with aphids are sprayed with diluted coffee then the aphids will die'.

This hypothesis directly addresses the question Amy has and can be tested through an experiment where plants infested with aphids are sprayed with a diluted coffee solution. If the aphids die after being sprayed, the hypothesis would be supported. Conversely, if the aphids do not die, the hypothesis would need to be revised.

Learn more about Formulating Hypothesis

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In a parade, 36 members of the color guard are to march in front of 120 members of the high school marching band. Both groups are to have the same number of students in each row. What is the greatest number of students that could be in each row? How many rows will each group have?

Answers

Final answer:

The greatest number of students that could be in each row is 12, which is the greatest common divisor of 36 and 120. The color guard will have 3 rows, and the high school marching band will have 10 rows.

Explanation:

To determine the greatest number of students that could be in each row and the number of rows each group will have, we need to find the greatest common divisor (GCD) of the two numbers representing the members in each group, 36 and 120. The greatest common divisor is the largest number that divides both numbers without leaving a remainder. Calculate this by listing the factors of each number or using the Euclidean algorithm.

Factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36

Factors of 120: 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, 120
The greatest common divisor is the largest factor both numbers share, which is 12. Therefore, the greatest number of students per row is 12.

Now, to find the number of rows for each group, divide the total number of members in each group by the number of students per row:

Color guard: 36 members \/ 12 members per row = 3 rowsMarching band: 120 members \/ 12 members per row = 10 rows

So, there will be 3 rows of color guard members and 10 rows of marching band members.

PLEASE HELP ME WITH THIS MATH QUESTION

Answers

Answer:

44°

Step-by-step explanation:

The arc of DC in degrees is the same as the angle of DOC. So it is 44°

Can someone please help me, I need to know the missing side length (x) using trigonometric ratios.

Answers

Answer:

x=6/cos(72) is the exact answer.

[tex]x \approx 19.416[/tex].

Step-by-step explanation:

Sine

opposite

hypotenuse

Cosine

adjacent

hypotenuse

Tangent

opposite

adjacent

Soh Cah Toa is an abbreviation used to help remember the trigonometric ratios.

We see we have the angle measurement 72 degrees given at the bottom. I'm going to label my sides with respect to that angle.

The hypotenuse is x.

The adjacent is 6.

We don't have anything about the opposite side but we don't need it to find x.

So anyways we have this:

The hypotenuse is x and

the adjacent is 6.

If you look at the ratios we want to use cosine.

[tex]\cos(72)=\frac{6}{x}[/tex]

or

[tex]\frac{\cos(72)}{1}=\frac{6}{x}[/tex]

We are going to cross multiply.

x cos(72)=1 (6)

cos(72) * x=6

Now we are going to divide both sides by cos(72) giving us:

x=6/cos(72)

x=6/cos(72) is the exact answer.

Let's put it into our calculator now:

[tex]x \approx 19.416[/tex].

Bryan hits a golf ball whose path is given by the function f(d) = -0.01d2 + 3d, where d is the distance the ball travelled in feet and f(d) is the height of the ball. The height of the golf ball when it was hit was feet and the ball reached a maximum height of feet.

Answers

Answer:

0 ft225 ft

Step-by-step explanation:

h(0) = -.01·0² +3·0 = 0 . . . . . the height when the ball was hit

The function can be factored as ...

  f(d) = -0.01d(d -300)

This has zeros at d=0 and d=300, so the maximum will be halfway between, at d=150.

  f(150) = -0.01·150(150 -300) = -1.5(-150) = 225

The height of the ball when hit was 0 feet, and the ball reached a maximum height of 225 feet.

Bryan hits a golf ball whose path is given by the function f(d) = -0.01d2 + 3d, where d is the distance the ball travelled in feet and f(d) is the height of the ball. The height of the golf ball when it was hit was feet and the ball reached a maximum height of feet.


10. If 15 - x = 4, then x =
A. -21
B. -11
C. 1
D. 11

Answers

Answer:

D

Step-by-step explanation:

15-x=4

Subtract 15 from both sides

leaves you with

-x=-11

x=11

Hey there! :)

15 - x = 4

Subtract 15 from both sides.

-x = 4 - 15

Simplify.

-x = -11

Divide both sides by -1.

-x ÷ -1 = -11 ÷ -1

x = 11

Therefore, your answer is D. 11

~Hope I helped! :)

Courier charges for packages to a certain destination are 65 cents for the first 250 grams and 10 cents for each additional 100 grams of part thereof. What could be the weight in grams of a package for which the charge is $1.55?

Answers

Answer:

  1050 g < weight ≤ 1150 g

Step-by-step explanation:

Let w represent the weight of the package in grams. The the number of 100-gram increments after the first 250 grams is given by ...

  ⌈(w-250)/100⌉ . . . . . . . where ⌈ ⌉ signifies the ceiling function

and the charges for a package exceeding 250 grams will be ...

  0.65 + 0.10⌈(w -250)/100⌉ = 1.55

  0.10⌈(w -250)/100⌉ = 0.90 . . . . . . . . subtract 0.65

  ⌈(w -250)/100⌉ = 9 . . . . . . . . . . . . . . . divide by 0.10

  8 < (w-250)/100 ≤ 9 . . . . . . . . . . . . . . meaning of ceiling function

  800 < w -250 ≤ 900 . . . . . . . . . . . . . multiply by 100

  1050 < w ≤ 1150 . . . . . . . . . . . . . . . . . add 250

The weight in grams could be greater than 1050 and at most 1150 for a charge of $1.55.

Consider the quadratic function f(x)=8x2−7x+6. What is the constant of the function?

−7
6
7
8

Answers

Answer:

6

Step-by-step explanation:

The 8 is the leading coefficient, the -7 is the linear term, and the 6 is the constant.

Answer:

the constant term is 6.

Second option is correct.

Step-by-step explanation:

The quadratic function is [tex]f(x)=8x^2-7x+6[/tex]

The general form of a quadratic function is [tex]y=ax^2+bx+c[/tex]

Here c is the constant term and a can't be zero.

On comparing the given equation with the general form, we get

a = 8

b = -7

c = 6

Therefore, the constant term is 6.

Second option is correct.

Suppose that 12% of people own dogs. If two people are randomly chosen, what is the probability that they both own a dog? Write your answer as a percent and round to the nearest hundredth of a percent.

Answers

Rounded to the nearest hundredth of a percent, the probability that both chosen people own a dog is approximately 1.44%.

We have,

The probability of the first person owning a dog is 12%, or 0.12.

Given that the first person owns a dog, the probability of the second person also owning a dog (assuming independence) remains 12%, or 0.12.

To find the probability that both of them own a dog, you multiply these probabilities:

Probability = 0.12 * 0.12 = 0.0144

To express this as a percentage, multiply by 100:

Probability = 0.0144 * 100 = 1.44%

Thus,

Rounded to the nearest hundredth of a percent, the probability that both chosen people own a dog is approximately 1.44%.

Learn more about probability here:

https://brainly.com/question/14099682

#SPJ12

The probability that both randomly chosen people own a dog is 1.44%.

To find the probability that both randomly chosen people own a dog, we multiply the probability that the first person owns a dog by the probability that the second person also owns a dog.

Given:

- Probability that a person owns a dog [tex]\( P(\text{dog}) = 12\% = 0.12 \)[/tex]

Since the events (ownership of dogs by two different people) are independent, we use the multiplication rule for independent events.

[tex]\[ P(\text{both own a dog}) = P(\text{person 1 owns a dog}) \times P(\text{person 2 owns a dog}) \][/tex]

[tex]\[ P(\text{both own a dog}) = 0.12 \times 0.12 \][/tex]

[tex]\[ P(\text{both own a dog}) = 0.0144 \][/tex]

Now, convert the decimal to a percentage:

[tex]\[ P(\text{both own a dog}) = 0.0144 \times 100\% = 1.44\% \][/tex]

How many phone numbers can be made if the rst digit must be 1, the second digit must be a number in the range 3-5, the third digit must be a number in the range (6-9), and the last seven digits can be any single digit number 0-9?

Answers

The total number of phone numbers that can be made is 1,200,000.

To find the number of possible phone numbers given the conditions:

The first digit must be 1.The second digit must be a number in the range 3-5.The third digit must be a number in the range 6-9.The last seven digits can be any single-digit number 0-9.

We can calculate as follows:

For the second digit, there are 3 options (3, 4, or 5).For the third digit, there are 4 options (6, 7, 8, or 9).For the last seven digits, there are 10 options for each digit.

Therefore, the total number of phone numbers that can be made is [tex]1 x 3 x 4 x 10^7[/tex] = 1,200,000.

The amount of a sample remaining after t days is given by the equation P(t)=A(1/2)^t/h where A is the initial amount of the sample and h is half-life, in days, of the substance.

Answers

Answer:

2.5 mg

Step-by-step explanation:

Substitute the givens into the equation. A is the initial amount, 16 mg. H is the halflife, 8 days. T is the time in days that has passed, 16 days. So we get P(t)= 10(1/2)^(16/2). This ends up being 10(1/2)^2. 1/2^2 is 1/4. 10(1/4)=2.5 mg

To understand how to use the equation P(t) = A(1/2)^(t/h), let's break down each part of the formula and see how it applies to a real-world situation.
P(t): This represents the remaining amount of the substance at time t, where t is measured in days.
A: This is the initial amount of the substance before any decay has started.
(1/2): This factor represents the principle of half-life, which, in this context, means that the substance is reduced to half its previous amount after each half-life period passes.
t: This is the time that has passed, measured in days.
h: This is the half-life of the substance, which is the amount of time it takes for half of the substance to decay.
The half-life formula can be used to calculate the amount of substance that will remain after a certain amount of time has passed. Here is how you use it:
1. Start by determining the initial amount A of the substance. This is how much of the substance you begin with.
2. Determine the half-life h of the substance, which is usually provided by scientific data or an experiment.
3. Choose the time period t that you are interested in. This is how many days from the start time you want to know the remaining amount of the substance for.
4. Plug the values of A, h, and t into the formula P(t) = A(1/2)^(t/h).
5. Calculate (1/2)^(t/h). This requires you to raise (1/2) to the power of the fraction t/h. This fraction is the number of half-lives that have passed in the time period t.
6. Multiply the initial amount A by the result from step 5 to get P(t), the amount of the substance that remains after t days.
Let's go through an example to make it clear:
Example:
If the initial amount A is 100 grams and the half-life h is 10 days, how much of the substance will remain after 20 days?
Using the formula:
1. A = 100 grams (initial amount)
2. h = 10 days (half-life)
3. t = 20 days (time passed)
Plug the values into the formula:
P(t) = A(1/2)^(t/h)
P(20) = 100(1/2)^(20/10)
Calculate the exponent:
(1/2)^(20/10) = (1/2)^2 = 1/4
Multiply the initial amount by the result of the exponent:
P(20) = 100 * 1/4
P(20) = 25 grams
So after 20 days, 25 grams of the substance would remain.

The equation below is equivalent to which of the following quadratic equations?

(1/(a+x))+(1/(b+x))=(1/(c+x))

a. ax^2+bc+c=0
b. x^2+2cx+bc+ac-ab=0
c. 2x^2+(b+c-a)x+b(c+a)=0
d. (x^2/a^2)+(b^2/c^2)=((b+c)/(a+c))

an explanation would be appreciated! :)

Answers

Answer:

  b.  x^2 +2cx +bc+ac-ab = 0

Step-by-step explanation:

It's a matter of what I would describe as tedious algebra. You have to multiply by the least common denominator, then simplify to standard form.

After multiplying the equation by (x+a)(x+b)(x+c) and subtracting the right side, you have ...

  (x +b)(x +c) +(x +a)(x +c) -(x +a)(x +b) = 0

Expanding each factor pair gives ...

  (x² +(b+c)x +bc) +(x² +(a+c)x +ac) -(x² +(a+b)x +ab) = 0

Collecting terms gives ...

  x²(1 +1 -1) +x(b+c +a+c -a -b) +(bc +ac -ab) = 0

  x² +2cx +bc +ac -ab = 0 . . . . . matches selection B

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