A reason that one typically does not notice a blind spot in the visual field is that

Answer:

V = 9.33 m/s

Explanation:

Given that,

Mass of the batsman, [tex]m_1=91\ kg[/tex]

Mass of the boat, [tex]m_2=510\ kg[/tex]                            

Initial speed of the boat, v = 11 m/s

Let V is the velocity of the boat after Batman lands in it. The net momentum of the system remains constant. Using the conservation of linear momentum to find it as :

[tex]510\times 11=(91+510)V[/tex]

[tex]V=\dfrac{510\times11}{(91+510)}[/tex]

V = 9.33 m/s

So, the velocity of the boat after Batman lands in it 9.33 m/s. Hence, this is the required solution.                                                          

When Batman lands in the boat, it causes a change in the boat's velocity due to the force exerted by Batman. Using the principle of conservation of momentum, we can find the final velocity of the boat. The final velocity of the boat is 10.0 m/s, moving in the opposite direction at an angle of 26.6° to a line drawn across the river.

When Batman jumps into the boat, he exerts a force on the boat due to his mass and acceleration. According to Newton's third law of motion, the boat exerts an equal and opposite force on Batman. This force causes a change in the velocity of the boat.

To find the final velocity of the boat, we can use the principle of conservation of momentum. The initial momentum of the boat-criminal system is equal to the final momentum of the system after Batman lands in the boat. Using the equation for momentum, we can find the final velocity of the boat.

After plugging in the given values, we find that the velocity of the boat after Batman lands in it is 10.0 m/s. The boat moves in the opposite direction, at an angle of 26.6° to a line drawn across the river.

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Answer:

Not possible.

Explanation:

Exoplanets are an active area of modern research. The article states that the outermost planet (Planet C) goes all the way around its star in less time than the innermost planet (Planet A). Which is not possible as it will violet Kepler's third law of planetary motion.  Which says that the square of orbital period of a planet is proportional to the cube of its semi-major axis of its orbit.

Answer:

Explained

Explanation:

Your tutor is completely wrong here. Ampere and volt are both completely different concept. Ampere measure current in circuit, whereas volt measure the potential difference across two points in circuit. It is due to this difference in the potential that leads to flow of current in the circuit. The potential difference is the cause and current is the effect.

An ampere measures electric current, while a volt measures electrical potential difference, and they are critical in understanding electrical circuits. Ammeters are used to measure current and are wired in series, while voltmeters, which include an internal resistor, measure voltage and are connected in parallel. Confusing these concepts suggests a serious misunderstanding of basic electrical principles, thus getting a different tutor would be recommended.

If your tutor tells you that an ampere (A) and a volt (V) measure the same thing and suggests that these terms complicate a simple concept, it would be wise to consider finding a different tutor. This is because an ampere and a volt actually measure two fundamentally different electrical properties. The ampere measures electric current, which is the flow of electric charge, and is analogous to how much water flows through a pipe. In contrast, a volt measures electrical potential difference, or voltage, which is the energy available to move the charge, akin to the height from which water falls. When using tools to measure these properties, we use an ammeter to measure current, placing it in series so that all the current flows through it, and a voltmeter to measure voltage, connecting it in parallel to get a reading without significantly altering the flow of current.

Additionally, the internal design of a voltmeter includes an internal resistor and when connected in a circuit, it effectively creates a parallel resistance arrangement with the component across which the voltage is being measured. Therefore, to accurately measure and understand electrical circuits, one must recognize the difference between amperes and volts and use the appropriate measurement tools accordingly.

The new level of sound β2 = β1 + 10 log10(f).

Suppose that a sound has initial intensity level β1 measured in decibels.

This sound now increases in intensity level by a factor f. What is the new level of sound β2?

Formula to calculate the new sound intensity β2 = β1 + 10 log10(f)

The new level of sound β2 can be calculated using the formula β2 = β1 + 10 log10(f)

Here,β1 is the initial sound intensity levelβ2 is the new sound intensity level if is the factor by which the sound intensity level is increased by.

Sound intensity, also known as acoustic intensity, is defined as the power carried by sound waves per unit area in a direction perpendicular to that area.

The SI unit of intensity, which includes sound intensity, is the watt per square meter (W/m2)

Hence, The new level of sound β2 = β1 + 10 log10(f).

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The new level of the sound, β2, can be found by using the property of logarithms. The formula to calculate the new level is β2 = β1 + 10 log10(f). If one sound is twice as intense as another, it has a sound level about 3 dB higher.

The new level of the sound, β2, can be found by using the property of logarithms. When the intensity of a sound increases by a factor of f, the sound level increases by 10 times the logarithm (base 10) of f. So, in this case, if the initial sound has intensity β1, the new level of sound β2 can be obtained by:

β2 = β1 + 10 log10(f)

For example, if the initial sound has intensity β1 = 60 dB and it increases by a factor of f = 2, then:

β2 = 60 + 10 log10(2) = 60 + 3 = 63 dB

Answer: 150.427 K

Explanation:

The complete question is as follows:

The robot HooRU is lost in space, floating around aimlessly, and radiates heat into the depths of the cosmos at the rate of [tex]14.5 W[/tex] . HooRU's surface area is [tex]1.79 m^{2}[/tex] and the emissivity of its surface is [tex]0.279[/tex]. Ignore the radiation HooRU absorbs from the cold universe. What is HooRU's temperature?

This problem can be solved by the Stefan-Boltzmann law for real radiator bodies:  

[tex]P=\sigma A \epsilon T^{4}[/tex] (1)

Where:

[tex]P=14.5 W[/tex] is the energy radiated by HooRU

[tex]\sigma=5.6703(10)^{-8}\frac{W}{m^{2} K^{4}}[/tex] is the Stefan-Boltzmann's constant.  

[tex]A=1.79 m^{2}[/tex] is the Surface of the robot

[tex]\epsilon=0.279[/tex] is the robot's emissivity

[tex]T[/tex] is the effective temperature of the robot (its surface absolute temperature) in Kelvin

So, we have to find [tex]T[/tex] from (1):

[tex]T=(\frac{P}{\sigma A \epsilon})^{\frac{1}{4}}[/tex] (2)

[tex]T=(\frac{14.5 W}{(5.6703(10)^{-8}\frac{W}{m^{2} K^{4}}) (1.79 m^{2}) (0.279)})^{\frac{1}{4}}[/tex]

Finally:

[tex]T=150.427 K[/tex]

Answer: 1010.92 m/s

Explanation:

According to Newton's law of universal gravitation:

[tex]F=G\frac{Mm}{r^{2}}[/tex] (1)

Where:

[tex]F[/tex] is the gravitational force between Earth and Moon

[tex]G=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}[/tex] is the Gravitational Constant

[tex]M=5.972(10)^{24} kg[/tex] is the mass of the Earth

[tex]m=7.349(10)^{22} kg[/tex] is the mass of the Moon

[tex]r=3.9(10)^{8} m[/tex] is the distance between the Earth and Moon

Asuming the orbit of the Moon around the Earth a circular orbit, the Earth exercts a centripetal force on the moon, which is equal to [tex]F[/tex]:

[tex]F=m.a_{C}[/tex] (2)

Where [tex]a_{C}[/tex] is the centripetal acceleration given by:

[tex]a_{C}=\frac{V^{2}}{r}[/tex] (3)

Being [tex]V[/tex] the orbital velocity of the moon

Making (1)=(2):

[tex]m.a_{C}=G\frac{Mm}{r^{2}}[/tex] (4)

Simplifying:

[tex]a_{C}=G\frac{M}{r^{2}}[/tex] (5)

Making (5)=(3):

[tex]\frac{V^{2}}{r}=G\frac{M}{r^{2}}[/tex] (6)

Finding [tex]V[/tex]:

[tex]V=\sqrt{\frac{GM}{r}}[/tex] (7)

[tex]V=\sqrt{\frac{(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(5.972(10)^{24} kg)}{3.9(10)^{8} m}}[/tex] (8)

Finally:

[tex]V=1010.92 m/s[/tex]

To find the moon's speed, we use Newton's law of universal gravitation and the formula for centripetal acceleration, substituting the Earth's mass and Earth-Moon distance to solve for the moon's orbital speed.

Calculating the Speed of the Moon from Earth-Moon Distance

To find the speed of the moon in its orbit using Newton's law of universal gravitation, we apply the formula for gravitational force, F, which is given by F = (G * m1 * m2) / r^2, where G is the gravitational constant, m1 and m2 are the masses of two objects, and r is the distance between their centers. For the Earth and Moon, we use Earth's mass (m2) and the Earth-Moon distance (r).

The moon's orbital speed (v) can be related to the gravitational force (F) since the force providing the moon's centripetal acceleration (a_c) required for circular motion is the same as the gravitational force exerted by Earth. That is, a_c = (v^2)/r. Setting the expression for gravitational force equal to mass times centripetal acceleration (F = m * a_c), and solving for v, we find v = sqrt(G * m2 / r).

We are given the distance between the Earth and Moon (r = 3.9 × 10^8 m) and the Earth's mass. Substituting these values into the equation, we can solve for the orbital speed of the Moon.

Answer:

The  maximum kinetic energy of the ejected electron=[tex]3.53\times 10^{-10} J[/tex]

Explanation:

We are given that

Frequency of light source=[tex]5.32\times 10^{23}[/tex] Hz

Work function of arsenic=[tex]7.67\times 10[/tex] eV

We have to find the maximum kinetic energy of ejected electron.

We know that the maximum kinetic energy of ejected electron

[tex]K.E=h\nu-w_o[/tex]

Where h=Plank's constant=[tex]6.63\times 10^{-34} J.s[/tex]

[tex]\nu[/tex] =Frequency of light source

[tex]w_o[/tex]=Work function

Substitute the values in the given formula

Then, the maximum kinetic energy of ejected electron

[tex]K.E=6.63\times 10^{-34}\times 5.32\times 10^{23}-7.67\times 10\times 1.6\times 10^{-19}[/tex]

Because 1 e V=[tex]1.6\times 10^{-19} J[/tex]

[tex]K.E=35.2716\times 10^{-11}-12.272\times 10^{-18}[/tex]

[tex]K.E=3.53\times 10^{-10}[/tex] J

Hence, the maximum kinetic energy of the ejected electron=[tex]3.53\times 10^{-10} J[/tex]

Answer:

infinity

Explanation:

Given that

Resistance = R

Resistivity = ρ

Length = L

Diameter = d

The resistance of wire R given as

[tex]R=\rho\dfrac{L}{A}[/tex]

A=Area

[tex]A=\dfrac{\pi d^2}{4}[/tex]

Now by putting the value of A

[tex]R=\rho\dfrac{L}{\dfrac{\pi d^2}{4}}[/tex]

[tex]R=\rho\dfrac{4L}{\pi d^2}[/tex]

When d tends to infinity then d² will also tends to infinity.

So when d tends to zero then the resistance tends to infinity.

Therefore answer is ---

infinity

Answer:

d

Explanation:

Answer:Image will be located at 2F on the other side of the lens.

Explanation:

Answer:

2 f

Explanation:

The main important characteristic that distinguishes meteorites and terrestrial rocks is the presence of fusion crust and the presence of iron metal alloys.

Meteorites are usually covered with dark, pitted crust resulting from their fiery passage through the atmosphere. Terrestrial rock usually has a metal content and can able to attract the magnet.

Meteorite has rare earth element such as iridium, and terrestrial rocks do not have rare earth elements. Meteorite has a dark crust from burning Earth's atmosphere. A fusion crust is present only in meteorites whereas terrestrial rock doesn't.

Meteorites have high metal content and it has different isotope ratios of the particular elements. The terrestrial rocks do not have isotope and metal content.

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Final answer:

A meteorite is distinguished from a terrestrial rock primarily by its composition and origin, with meteorites often containing metallic elements and coming from asteroids. Primitive and differentiated are two main categories of meteorites, providing insight into the early solar system and respective parent bodies’ structures.

Explanation:

The characteristic that distinguishes a meteorite from a terrestrial rock is mainly its origin and composition. Meteorites are typically fragments from asteroids and are often rich in metallic elements, unlike many terrestrial rocks. A key distinction between meteoritic and terrestrial rocks can be made on the basis of whether they are primitive or differentiated. Primitive meteorites are composed of materials that have not been altered by heat or pressure since their formation and provide insights into the early solar system. On the other hand, differentiated meteorites are remnants of larger parent bodies that experienced molten states, allowing materials to separate by density, similar to the process on Earth but with different conditions. Examples of differentiated meteorites include irons and stony-irons, which come from the metal cores or mantle-core boundaries of their parent bodies.

Typical stony meteorites closely represent the terrestrial crust or mantle, while typical iron meteorites have compositions akin to the Earth's core. Scientists use various methods, including chemical and mineralogical analysis, to distinguish meteorites from terrestrial material. Lunar meteorites, for instance, can be identified by their unique chemical properties compared to Earth rocks. By studying meteorites, scientists gain valuable knowledge about the history and formation of the solar system.

Complete Question:
Two uniform spheres,each of mass 0.260kg are fixed at points A and B

A.)Find the magnitude of the initial acceleration of a uniform sphere with mass 0.010 kg if released from rest at point P and acted on only by forces of gravitational attraction of the spheres at A and B.

B.) Find the direction of the initial acceleration of a uniform sphere with mass 0.010 kg.

Answer:

[tex]P = 444[/tex] mm of Hg

Explanation:

As we know that volume is constant so by ideal gas equation we have

[tex]PV = nRT[/tex]

now for constant volume condition we have

[tex]\frac{P_1}{P_2} = \frac{T_1}{T_2}[/tex]

here we know that

[tex]P_1 = 325[/tex] mm of Hg

[tex]T_1 = 273 K[/tex]

[tex]T_2 = 373 K[/tex]

now from above equation

[tex]\frac{325}{P} = \frac{273}{373}[/tex]

[tex]P = 444[/tex] mm of Hg

Final answer:

In Physics, using the properties of a constant-volume gas thermometer, the pressure at the normal boiling point of water can be calculated knowing the pressure at the triple point, by using the direct proportionality between pressure and temperature for an ideal gas.

Explanation:

The subject of this question is Physics, specifically relating to the topic of thermodynamics and how temperature affects the pressure of gases at constant volume. The gas in question is mercury, and its pressure readings at two significant points are being discussed: the triple point and the normal boiling point of water. According to the information provided, the thermometer registers a pressure of 325 mm of mercury at the triple point of water.

The relation between pressure and temperature for an ideal gas, which forms the basis for a constant-volume gas thermometer, implies that at a constant volume, the pressure is directly proportional to the temperature in Kelvin. When considering the normal boiling point, one must remember that it is defined at the atmospheric pressure of 760 mm Hg. Since the triple point is 273.16 K and has a given pressure of 325 mm Hg, the pressure at the boiling point of 373.16 K (the normal boiling point of water) can be found using the direct proportionality of pressure and temperature.

Assuming ideal behavior, the pressure at the boiling point can be calculated using

Pboiling = (PTP \/ TTP) \ imes Tboiling

Where PTP is the pressure at the triple point, TTP is the temperature at the triple point, and Tboiling is the temperature at the normal boiling point.

The pressure at the normal boiling point is therefore:

Pboiling = (325 mm Hg \/ 273.16 K) \ imes 373.16 K

By doing the calculation, we find the pressure that the constant-volume gas thermometer will read at the boiling point.

Answer:

[tex]\lambda'=\dfrac{1}{2}\times \lambda[/tex]

Explanation:

The number of oscillation per unit time is called frequency of a wave while the distance between two consecutive crests and the trough is called its wavelength.

The wavelength of a wave is given by :

[tex]\lambda=\dfrac{v}{f}[/tex]

If frequency is doubled, f' = 2f

[tex]\lambda'=\dfrac{v}{f'}[/tex]

[tex]\lambda'=\dfrac{v}{2f}[/tex]

[tex]\lambda'=\dfrac{1}{2}\times \dfrac{v}{f}[/tex]

[tex]\lambda'=\dfrac{1}{2}\times \lambda[/tex]

So, when the frequency is doubled the wavelength of a wave on the string becomes half.

Answer:

new moon

Explanation:

A solar eclipse take place at new moon phase, when the moon passes between the earth and the sun and its shadows fall on the Earth's surface which by definition a solar eclipse.

The moon must be in the new moon phase for a solar eclipse to occur.

The moon must be in the new moon phase for a solar eclipse to occur. During the new moon phase, the moon is located between the Earth and the Sun, causing the moon to cast a shadow on Earth and block the Sun's light.

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Answer:

Height reached by the ball, h = 3.57 meters

Explanation:

It is given that,

Mass of the disk, m = 42 kg

Diameter of the disk, d = 3.2 m

Radius, r = 1.6 m

Angular speed of the disk, [tex]\omega=4.27\ rad/s[/tex]

The kinetic energy of the disk is equal to its potential energy. Using the conservation of energy as :

[tex]\dfrac{1}{2}mv^2+\dfrac{1}{2}I\omega^2=mgh[/tex]

[tex]\dfrac{1}{2}mv^2+\dfrac{1}{2}(mr^2/2)\omega^2=mgh[/tex]

[tex]\dfrac{1}{2}v^2+\dfrac{1}{2}(r^2/2)\omega^2=gh[/tex]

[tex]\dfrac{1}{2}(r\omega)^2+\dfrac{1}{2}(r^2/2)\omega^2=gh[/tex]

[tex]\dfrac{1}{2}(1.6\times 4.27)^2+\dfrac{1}{2}(1.6^2/2)\times 4.27^2=gh[/tex]

[tex]h=\dfrac{35.0071}{9.8}[/tex]

h = 3.57 meters

So, the solid disk will reach to a height of 3.57 meters.

The height attained by the disk on the hill is 3.57 m.

The given parameters;

The height attained by the disk is calculated by applying the law of conservation of energy as follows;

[tex]\frac{1}{2}mv^2 + \frac{1}{2}I \omega ^2 = mgh\\\\mv^2 + I \omega ^2 = 2mgh\\\\mv^2 + (\frac{mr^2}{2} ) \omega ^2 = 2mgh\\\\v^2 + \frac{1}{2} r^2 \omega ^2 = 2gh\\\\(\omega r)^2 + 0.5(\omega r )^2 = 2gh\\\\1.5 (\omega r)^2 = 2gh\\\\h = \frac{1.5 (\omega r)^2}{2g} \\\\h = \frac{1.5 \times (4.27 \times 1.6)^2 }{2\times 9.8} \\\\h = 3.57 \ m[/tex]

Thus, the height attained by the disk on the hill is 3.57 m.

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Final answer:

To find the spring constant of the car's springs, we use Hooke's Law and the given information about the car's mass, maximum amplitude, and speed. The spring constant is approximately 92638 N/m.

Explanation:

To find the spring constant of the car's springs, we need to use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement from its equilibrium position. The formula for Hooke's Law is F = -kx, where F is the force, k is the spring constant, and x is the displacement.

In this case, the car bounces up and down with the maximum amplitude when traveling at 5.7 m/s. The maximum amplitude of the oscillation is half the distance between bumps, so it is 4.9 m/2 = 2.45 m. We can use this information to solve for the spring constant k using the formula:

k = mω²

where m is the mass of the car and ω is the angular frequency, which can be calculated using the formula:

ω = 2πf

where f is the frequency, which is the reciprocal of the period T.

Given that the bumps are spaced 4.9 m apart, the period of the oscillation is the time it takes the car to travel one bump, which is T = 4.9 m / 5.7 m/s = 0.859 s.

The frequency is the reciprocal of the period, so f = 1 / T = 1 / 0.859 s = 1.164 Hz.

Plugging the values into the formulas, we have:

ω = 2π(1.164) ≈ 7.294 rad/s

k = (1800 kg)(7.294 rad/s)² ≈ 92638 N/m

Therefore, the spring constant of the car's springs is approximately 92638 N/m.

The answer involves comparing the centripetal force exerted by the turntable on the coin to the static and kinetic friction forces that resist the coin's motion.

The situation involves a coin on a turntable where rotation is causing a force. The physics principles at play here are centripetal force and the forces of static and kinetic friction. The centripetal force needed to keep the coin rotating can be calculated using the equation F = mrω², where m is the mass of the coin, r is the distance from the coin to the center of the rotation, and ω is the angular speed of the rotation.

The static friction force is what keeps the coin from sliding as the turntable speeds up. Static friction can be calculated using the equation fs = µsmg, where µs is the coefficient of static friction, m is the mass, and g is acceleration due to gravity. If the force of static friction is less than the centripetal force, the coin will start to slide, and kinetic friction will come into play. Kinetic friction can be calculated with f = µkmg.

By calculating these forces, we can compare and determine if the centrifugal force from the turntable's acceleration would overcome the friction between the coin and the turntable, causing the coin to slide off.

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Answer:

option E

Explanation:

given,

decibel level of a busy freeway = 100 dB

when flow is = 100 car/minutes

traffic flow= 20 car/minute

Intensity factor =[tex]\dfrac{I}{I_0}[/tex]

                         =[tex]\dfrac{20}{100}[/tex]

                         =[tex]\dfrac{1}{5}[/tex]

[tex]\Delta \beta = 10 log\dfrac{I}{I_0}[/tex]

[tex]\Delta \beta = 10 log\dfrac{1}{5}[/tex]

[tex]\Delta \beta = - 6.989\ dB[/tex]

The late night decibel level

       = 100 - 6.989

       = 93

The correct answer option E

Final answer:

To calculate the pressure after a temperature change, use the equation PV = nRT, and simplifying it to P1/T1 = P2/T2. Rearranging the equation, the final pressure (P2) can be calculated as P2 = P1 * (T2 / T1). In this case, the pressure after the temperature has risen to 35.0ºC is approximately 7.33 × 10^5 Pa.

Explanation:

To calculate the pressure after the temperature change, we can use the equation PV = nRT, where P represents pressure, V represents volume, n represents the number of moles, R represents the ideal gas constant, and T represents temperature. Since the volume and moles remain constant in this scenario, we can simplify the equation to P1/T1 = P2/T2, where P1 and T1 represent the initial pressure and temperature, and P2 and T2 represent the final pressure and temperature. Rearranging the equation, we get P2 = P1 * (T2 / T1). Therefore, the pressure after the temperature has risen to 35.0ºC can be calculated as:

P2 = 7.00 × 10^5 Pa * (35.0 + 273.15) / (21.0 + 273.15)

P2 = 7.00 × 10^5 Pa * 308.15 / 294.15

P2 = 7.33 × 10^5 Pa

Answer:

Technical director.

Explanation:

The answer is the Technical director.

This is very important for every company or organization to manage the activity in a technical way. Because if we did not follow the good technique and did not use a proper technical method then definitely the task will not be completed in the specified time limit.

Answer:

d = 25.51 m

Explanation:

the law of the conservation of energy says that:

[tex]E_i - E_f = W_f[/tex]

where [tex]E_i[/tex] is the inicial energy, [tex]E_f[/tex] is the final energy and [tex]W_f[/tex] is the work of the friction.

so:

[tex]E_i[/tex] = [tex]\frac{1}{2} MV^2[/tex]

[tex]E_f = 0[/tex]

where M is the mass and V the velocity.

also,

[tex]W_f = U_kNd[/tex]

where [tex]U_k[/tex] is the coefficient of kinetic frictio, N is the normal force and d is the distance.

therefore:

[tex]\frac{1}{2}MV^2=U_kNd[/tex]

also, N is equal to the mass of the hockey puck multiplicated by the gravity.

replacing:

[tex]\frac{1}{2}m(5)^2=(0.05)(m(9.8))(d)[/tex]

canceling the m:

[tex]\frac{1}{2}5^2=0.05(9.8)(d)[/tex]

solving for d:

[tex]d = \frac{\frac{1}{2}5^2 }{0.05(9.8)}[/tex]

d = 25.51 m

The distance which the hockey puck slide before coming to rest is equal to  25.51 meters.

Given the following data:

We know that the acceleration due to gravity (g) of an object on planet Earth is equal to 9.8 [tex]m/s^2[/tex].

To find how far (distance) the hockey puck slide before coming to rest, we would use the law of conservation of energy:

According to the law of conservation of energy:

[tex]K.E_i - K.E_f = W_f[/tex]

The final kinetic energy of the hockey puck is zero (0) because it came to rest or stop.

[tex]K.E_i - 0 = W_f\\\\K.E_i = W_f\\\\\frac{1}{2}mv_i^2 = umgd\\\\\frac{1}{2}v_i^2 = ugd\\\\v_i^2 = 2ugd\\\\d = \frac{v_i^2}{2ug}[/tex]

Substituting the given parameters into the formula, we have;

Distance, d = 25.51 meters

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Answer:

mass of the baryon = [tex]\frac{(qRB)^{2} }{2K}[/tex]

speed of the baryon = [tex]\frac{2K}{qRB}[/tex]

Explanation:

For any body to move in a circular path, there must be a centripetal force which is directed towards the center of the circle. Here, the centripetal force is provided by the magnetic Lorentz force that acts on the baryon. Therefore we can equate the magnitudes of centripetal force and magnetic Lorentz force.

Magnitude of Centripetal force = [tex]\frac{mv^{2} }{R}[/tex]

Magnitude of Magnetic Lorentz force =  qvB

where,

m = mass of the baryon

v = velocity of the baryon

Thus,

[tex]\frac{mv^{2} }{R}[/tex] = qvB

[tex]\frac{mv}{R}[/tex] = [tex]qB[/tex] (cancelling v on both sides)

v = [tex]\frac{qRB}{m}[/tex]

We know, Kinetic energy, K = [tex]\frac{1}{2} mv^{2}[/tex]

Substituting v in the above equation we get,

K = [tex]\frac{1}{2} m(\frac{qRB}{m} )^{2}[/tex]

K = [tex]\frac{(qBR)^{2} }{2m}[/tex] (simplifying)

Thus,

m = [tex]\frac{(qRB)^{2} }{2K}[/tex]

We already got that

v = [tex]\frac{qRB}{m}[/tex]

substituting the value of m in this equation gives,

[tex]v = \frac{qRB}{\frac{(qRB)^{2} }{2K}}[/tex]

v = [tex]\frac{2K}{qRB}[/tex] (simplifying)

Thus,

mass of the baryon = [tex]\frac{(qRB)^{2} }{2K}[/tex]

velocity of the baryon = [tex]\frac{2K}{qRB}[/tex]

The angular acceleration of a ceiling fan with a net torque of 2.1 N · m and blades having a moment of inertia of 0.19 kg · m² is approximately 11.05 rad/s².

The subject of this question is Physics, specifically rotation dynamics. In rotation dynamics, angular acceleration is defined by the equation α = τ / I, where α is the angular acceleration, τ is the net torque, and I is the moment of inertia. In the given problem, a net torque of 2.1 N · m is applied to a ceiling fan with blades having a total moment of inertia of 0.19 kg · m². Substituting the given values into the equation, we can solve for the angular acceleration: α = 2.1 N · m / 0.19 kg · m² = approximately 11.05 rad/s². Hence, the angular acceleration of the ceiling fan's blades is approximately 11.05 rad/s².

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The angular acceleration of the ceiling fan blades, given a net torque of 2.1 N·m and a moment of inertia of 0.19 kg·m², is calculated using Newton's second law for rotation. The resulting angular acceleration is 11.05 rad/s².

The student's question is related to the field of Physics, specifically rotational kinematics and dynamics. The key concept here is Newton's second law for rotation, which can be expressed as τ = Iα, where τ represents the net torque, I is the moment of inertia, and α is the angular acceleration.

Given that the net torque (τ) is 2.1 N·m and the moment of inertia (I) is 0.19 kg·m², we can find the angular acceleration (α) by rearranging the equation α = τ / I. Substituting the given values into this equation: α = 2.1 N·m / 0.19 kg·m² = 11.05 rad/s². Hence, the angular acceleration of the blades of the ceiling fan is 11.05 rad/s².

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Answer:

Q = 230.36 C

Explanation:

Given

R = 3.54 Ω

t = 30'45" = (30')*(60"/1') + 45" = 1845 s

V = 442 mV = 442*10⁻³V

Q = ?

We can use Ohm's Law in order to get I as follows

V = I*R   ⇒    I = V / R

⇒    I = 442*10⁻³V / 3.54 Ω = 0.1248 A

Finally we use the formula

I = Q / t     ⇒    Q = I*t = (0.1248 A)(1845 s)

⇒    Q = 230.36 C

Answer:

Power, P = 560 W

Explanation:

Given that,

Weight of the student, F = 700 N

Distance, d = 8 m

Time taken, t = 10 s

To find,

The average power expended by the student.

Solution,

Let P is the power. The work done per unit time is called its power. It is given by :

[tex]P=\dfrac{W}{t}[/tex]

[tex]P=\dfrac{F\times d}{t}[/tex]

[tex]P=\dfrac{700\ N\times 8\ m}{10\ s}[/tex]

P = 560 W

So, the  average power expended by the student to overcome gravity is most nearly 5670 watts.

The average power expended by the  student to overcome gravity =

( 5.) P = 560 W

The formula for Power is given by the equation (1)  

[tex]Power = \dfrac{Work}{Time}[/tex]...........(1)

Also the formula for Work is given by equation (2)

[tex]Work = Force \times Distance[/tex]............(2)

(Considering magnitude of Displacement)

From equation (1) and (2) we can get

[tex]Power = \dfrac{Force \times Distance}{Time}[/tex].......(3)

Also   [tex]Speed= \dfrac{ Distance}{Time}[/tex]....(4)

From equation (2) , (3) and (4)

So [tex]Power= Force \times Speed[/tex]

Given

Weight of the Student = 700 N

Height of the rope  = 8 m

Time taken  to climb the rope = 10 s.

So from equation (3)  we can get

Average Power expended by the student to overcome gravity = (700)[tex]\times[/tex] (8)/(10) = 560 W.

Hence option 5 is correct.

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Explanation:

Given that, the height of the tide measured at a seaside community varies according to the number of hours t after midnight. The height is given by the equation as :

[tex]h=-\dfrac{1}{2}t^2+6t-9[/tex]

When the tide first be at 6 ft, put h = 6 ft in above equation as :

[tex]-\dfrac{1}{2}t^2+6t-9=6[/tex]

[tex]-t^2+12t-18=0[/tex]

On solving the above equation to find the value of t. It is equal to :

t = 3.551 seconds

or

t = 8.449 seconds

So, the tide of 6 ft is at  3.551 seconds and 8.449 seconds. Hence, this is the required solution.

Answer:

Frequency will be 485 Hz

So option (c) will be the correct option

Explanation:

We have given frequency f = 500 Hz

Velocity of observer [tex]v_o=20m/sec[/tex]

Velocity of source [tex]v_s=10m/sec[/tex]

When both observer and source are moving then frequency is given by

[tex]f'=\frac{v-v_o}{v-v_s}\times f[/tex] , here v is the velocity of sound

So [tex]f'=\frac{340-20}{340-10}\times 500=485Hz[/tex]

So option (c) will be the correct option

The change in angular velocity of the bicycle tire is -5.40 rad/s, indicating a change in direction. The average angular acceleration during this time period was -2.84 rad/s2, also reflected by the negative sign representing a change in direction.

This question pertains to physics, specifically focusing on angular velocity and angular acceleration. For the bicycle tire spinning counterclockwise at 2.70 rad/s to stop and spin in the clockwise direction at the same angular velocity, its total change in angular velocity (∆ω) is a combination of the initial and final angular velocities, given by ∆ω = ω_final - ω_initial. Since the tire goes from spinning counterclockwise (considered positive) to clockwise (considered negative), ∆ω = (-2.70 rad/s) - (2.70 rad/s) = -5.40 rad/s.

Next, to find the average angular acceleration (∆av), we use the formula ∆av = ∆ω / ∆t. Substituting in the time given (1.90 s) along with our calculated ∆ω, ∆av = -5.40 rad/s / 1.90 s = -2.84 rad/s2. Note that the negative sign indicates a change in direction.

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Answer:

60 ft

Explanation:

The tree man and their shadow system forms two similar right angle triangles.

the figure is in the attachment.

let ∠BAC= θ

Therefore, in triangle ABC

tanθ = BC/AC= 35/75= 7/15

now in ΔAEF also

tanθ = EF/AE = 7/75-x= 7/15

solving we get x=60 ft

Now AC and FA are the shadows of the tree and the man respectively.

now FA =75-x=75-60= 15 ft

Therefore, the man must stand at a distance of 60 ft from the tree can you stand and still be completely in the shadow of the tree

A person 7 feet tall can stand 60 feet away from a 35-foot tree casting a 75-foot shadow to be completely in the shadow of the tree.

To solve for how far away from the tree a person can stand and still be completely in the shadow of the tree, we can use similar triangles. Since the tree is 35 feet tall and casts a 75-foot shadow, and a person is 7 feet tall, the height ratio between the tree and the person is 5:1 (35 feet : 7 feet). Therefore, the length of the shadow that the person will cast will also be 5 times shorter than the length of the tree's shadow.

We calculate the length of the person's shadow as follows:

Length of person's shadow = Length of tree's shadow / Height ratio

Length of person's shadow = 75 feet / 5

Length of person's shadow = 15 feet

The total distance from the tree at which the person can stand and still be completely in the shadow is the length of the tree's shadow minus the length of the person's shadow.

Total distance from the tree = Length of tree's shadow - Length of person's shadow

Total distance from the tree = 75 feet - 15 feet

Total distance from the tree = 60 feet

Answer:

option B.

Explanation:

The correct answer is option B.

The phenomenon of the curtains to pull out of the window can be explained using Bernoulli's equation.

According to Bernoulli's Principle when the speed of the moving fluid increases the pressure within the fluid decrease.

When wind flows in the outside window the pressure outside window decreases and pressure inside the room is more so, the curtain moves outside because of low pressure.