A recipe calls for 1 1/2 cups of sugar. Alexis only has measuring cups that measuring cups that measure 1/4 cup. how many times will alexis have to fill the measuring cup?

Answers

Answer 1

Change 1 1/2 into improper faction

1 1/2 = 3/2

Change 3/2 to quarters

3/2 = 6/4

1 measure cups = 1/4 cup

To get 6/4 cups
6/4 ÷ 1/4 = 6/4 x 4/1 = 6

He needs to fill in 6 times

Related Questions

What are the zeros of the quadratic function f(x) = 8x2 – 16x – 15? x = –1 – and x = –1 + x = –1 – and x = –1 + x = 1 – and x = 1 + x = 1 – and x = 1 +

Answers

To find the zeros of the quadratic function [tex]$ f(x) = 8x^2 - 16x - 15 $[/tex], you need to solve for [tex]$ x $ when $ f(x) = 0 $[/tex].

So, you set $ f(x) $ equal to zero:

[tex]\[ 8x^2 - 16x - 15 = 0 \][/tex]

To solve this quadratic equation, you can use the quadratic formula:

[tex]\[ x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}} \]where $ a = 8 $, $ b = -16 $, and $ c = -15 $.[/tex]

Plugging these values into the quadratic formula:

[tex]\[ x = \frac{{-(-16) \pm \sqrt{{(-16)^2 - 4(8)(-15)}}}}{{2(8)}} \]\[ x = \frac{{16 \pm \sqrt{{256 + 480}}}}{{16}} \]\[ x = \frac{{16 \pm \sqrt{{736}}}}{{16}} \][/tex]

Now, you simplify the expression under the square root:

[tex]\[ \sqrt{736} = \sqrt{16 \times 46} = 4\sqrt{46} \][/tex]

So, the expression becomes:

[tex]\[ x = \frac{{16 \pm 4\sqrt{46}}}{{16}} \][/tex]

Now, you can simplify further:

[tex]\[ x = \frac{{4(4 \pm \sqrt{46})}}{{4 \times 4}} \]\[ x = \frac{{4 \pm \sqrt{46}}}{{4}} \][/tex]

This gives you two solutions:

[tex]\[ x = \frac{{4 + \sqrt{46}}}{{4}} \]\[ x = \frac{{4 - \sqrt{46}}}{{4}} \][/tex]

These are the zeros of the quadratic function [tex]$ f(x) = 8x^2 - 16x - 15 $.[/tex]

Complete question :

What are the zeros of the quadratic function f(x) = 8x2 - 16x - 15?

x/10=2/4?
or x over 10
equals to 2 over 4

Answers

The answer is: " x = 5 " .
_______________________________________________
Note the following:
_______________________________________________

2/4 = 1/2 ;

1/2 = (1*5) / (2*5) = 5/10 ;

2/4 = 1/2 = 5 / 10 .

or: 2/4 = 1/2 = 0.5 = 5/ 10 .

The answer: " x = 5 " .
___________________

Or: x/ 10 = 2/4 ;

Cross-multiply:

4x = (2)(10) ;

4x = 20 ;

Divide each side by "4" ;

4x / 4 = 20/4 ;

" x = 5 " ;
_____________________
Or: x/10 = 2/4 ;

Note: "2/4 = 1/2" ; so rewrite as:

x/10 = 1/2 ; and cross-multiply:

2x = (10)(1) ;

2x = 10 ;

Divide each side of the equation by "2" ;

2x / 2 = 10 / 2 ;

" x = 5 " .
______________________________________

Scarlett is trying to find the height of a dam. She stands 90 meters away from the dam and records the angle of elevation to the top of the dam to be 26º. Scarlett's height is 1.65 meters, so the height of the dam is meters. NextReset

Answers

the height of a dam:
h = x + 1.65 m,
where:
x = 90 m · tan 26°
x = 90 · 0.4877
x = 43.90
h = 43.90 m + 1.65 m = 45.55 m
Answer:
The height of the dam is 45.5 m.

Answer:

The height of dam =45.5 m.

Step-by-step explanation:

We are given that Scarlett stands 90 m away from the dam and records the angle of elevation to the top of the dam to be [tex]26^{\circ}p[/tex]

Scarelett's height is 1.65 meters.

We have to find the height of the dam.

Let h be the height of dam

AC=AB+BC

BC=x

h=1.65+x

CD=EB=90 m

In triangle ABE

[tex]\theta=26^{\circ}[/tex]

[tex]tan\theta=\frac{perpendicular\;side}{Base}[/tex]

[tex]tan26^{\circ}=\frac{AB}{90}[/tex]

[tex]0.4877=\frac{x}{90}[/tex]

[tex]x=0.4877\times 90[/tex]

[tex]x=43.893 m[/tex]

Therefore, the height of dam=1.65+43.893=45.543 m

Answer: The height of dam =45.5 m

Find the measure of each angle please?

Answers

Hi!

The measure of angle x is 60 degrees so the measure of angles 2x is 120 degrees.

Each exterior angle measuring 2x forms a linear pair with an interior angle measuring an unknown measure. Angles in a linear pair are supplementary.
Since both interior angles are supplementary to congruent angles, they are congruent.
Let z be the measure of each upper interior angle.

2x + z = 180

z = 180 - 2x

Each upper interior angle measures 180 - 2x.

The sum of the measures of the interior angles of a triangle is 180.

180 - 2x + 180 - 2x + x = 180

-3x + 360 = 180

-3x = -180

x = 60

One interior angle measures x, so it measures 60 deg.
The other two interior angles measure 180 - 2x = 180 - 2(60) = 180 - 120 = 60

Answer: all interior angle measure 60 deg.
The exterior angles shown measure 120 deg each.

Will give brainliest answer!!

Answers

Answer:
5:8

Explanation:
First, we will compute the ratio between the two volumes as follows:
1000 / 4096 = 125 / 512
which is equivalent to 125 : 512

Then, we will get the cubic root of the ratio. This is because volume of cube is computed by cubing its side length.
Therefore, similarity ratio iR³ will be:
125 : 512
(5)³ : (8)³
5 : 8

Hope this helps :)

a(t) = (t - k)(t - 3)(t - 6)(t + 3) is a polynomial function of t, where k is a constant. Given that a(2) = 0, what is the absolute value of the product of the zeros of a?

Answers

If a(2) = 0, then k=2. The product of the zeros is
(2)*(3)*(6)*(-3) = -108

The absolute value of the product of zeros of a(t) is 108.

zeros:
t-k=0, t=k
t-3=0, t=3
t-6=0, t=6
t+3=0, t=-3
abs value of the product= abs value of (t*3*6*-3)=54t

Help please on properties of exponents? will give a medal!

A rectangle has a length of the cube root of 81 inches and a width of 3 to the 2 over 3 power inches. Find the area of the rectangle.

a. 3 to the 2 over 3 power inches squared

b. 3 to the 8 over 3 power inches squared

c. 9 inches squared

d.9 to the 2 over 3 power inches squared

2.)Explain how the Quotient of Powers was used to simplify this expression.

2 to the fifth power, over 8 = 2 to the 2nd power

a.By finding the quotient of the bases to be one fourth and cancelling common factors

b. By finding the quotient of the bases to be one fourth and simplifying the expression

c. By simplifying 8 to 23 to make both powers base two and subtracting the exponents

d. By simplifying 8 to 23 to make both powers base two and adding the exponents

3.)the cube root of 2 to the seventh power

a. 2 to the 3 over 7 power

b. 2 to the 7 over 3 power

c. 2^21

d. 2^4,

Answers

Answer
1) c. 9 inches squared
2) c. By simplifying 8 to 23 to make both powers base two and subtracting the exponents
3) b. 2 to the 7 over 3 power

Explanation.
Question 1
The area of a rectangle is given by
area=l×w
=〖81〗^(1/3)×3^(2/3)
3^(4/3)×3^(2/3)=3^(4/3+2/3)
=3^(6/3)=3^2=9 inches squared

Question 2
Finding the 2^5/8=2^2
The steps for finding this is first to write 8 as 23. Then divide.
2^5/8=2^5/2^3
When dividing exponents with the same base you subtract the powers.
=2^(5-3)=2^2

Question 3
The question wants us to solve, ∛(3^7 ).the cube root of a number can be written as a power of a third.
So,
∛(3^7 )=3^(7×1/3 )
=3^(7/3)

Answer:

Ques 1)

Option: C is the correct answer.

c. 9 inches square.

Ques 2)

Option: c

c. By simplifying 8 to 2^3 to make both powers base two and subtracting the exponents.

Ques 3)

Option: b

b. 2 to the 7 over 3 power

Step-by-step explanation:

Ques 1)

A rectangle has a length of the cube root of 81 inches and a width of 3 to the 2 over 3 power inches.

i.e. let 'l' and 'b' denote the length and width of the rectangle.

i.e.[tex]l=\sqrt[3]{81}\\\\l=(3^4)^{\dfrac{1}{3}}\\\\l=3^{\dfrac{4}{3}[/tex]

since,

[tex](a^m)^n=a^{mn}[/tex]

and

[tex]w=3^{\dfrac{2}{3}}[/tex]

Hence, the area of rectangle is given by:

[tex]Area=l\times w\\\\\\Area=3^{\dfrac{1}{3}}\times3^{\dfrac{4}{3}}\\\\\\Area=3^({\dfrac{1}{3}+\dfrac{4}{3}})\\\\\\Area=3^{\dfrac{6}{3}}\\\\\\Area=3^2\\\\\\Area=9\ square\ inches[/tex]

As we know that:

[tex]a^m\times a^n=a^{m+n}[/tex]

Hence, Area=9 square inches.

Ques 2)

2 to the fifth power, over 8 = 2 to the 2nd power

i.e. we need to prove that:

[tex]\dfrac{2^5}{8}=2^2[/tex]

As we know that:

[tex]\dfrac{2^5}{8}=\dfrac{2^5}{2^3}=2^{5-3}=2^2[/tex]

( since

[tex]\dfrac{a^m}{a^n}=a^{m-n}[/tex] )

Hence, the correct answer is: Option: c

Ques 3)

The cube root of 2 to the seventh power.

i.e.

[tex]\sqrt[3]{2^7}\\\\=(2^7)^{\dfrac{1}{3}}\\\\=2^{\dfrac{7}{3}}[/tex]

Since,

[tex]\sqrt[n]{x}=x^{\dfrac{1}{n}}[/tex]

and

[tex](a^m)^n=a^{mn}[/tex]

Hence, the correct answer is: option: b

help please

integral of sqrt (x^2+6x) dx

Answers

The integral of (x^2 + 6x)dx is 1/3x^3 + 3x^2 + c.
Because this is not an integration with specific bounds, you must include a constant at the end. In general, to integrate, add 1 to the exponent of x and then whatever number is the exponent of x, divided the number in front of x by that.

Two 6-sided dice are rolled. what is the probability that the sum of the two numbers on the dice will be greater than 9?

Answers

What combination of numbers are needed in order to get a sum of 9?
It can be:
• First die is 6 , second die is 3
• First die is 3 , second die is 6
• First die is 4 , second die is 5
• First die is 5 , second die is 4

How many possible combinations are made? Yep, 4 possible combinations.

Recall the formula for probability
[tex]Probability = \frac{Number of desired outcomes}{Number of all possible outcomes} [/tex]

There are 4 desired number of outcomes.
How about the total possible outcomes?
• How many numbers are possible to appear when the first die is rolled?
Answer: 6
• What about the second die?
Answer: Also 6
• Therefore, total possible outcomes = 6 * 6 = 36 outcomes

You can now solve for the probability.

[tex]Probability = \frac{4}{36} = \frac{1}{9} [/tex] or approximately 11.11%

HELP:
Whic reformer was not a journalist who investigated corruption in business or government?
(Points : 3)
Ray Stannard Baker

Upton Sinclair

Lincoln Steffens

William Booth

i wend with D

Answers

The correct answer is William Booth. He was the founder of the Salvation Army and a preacher, not a journalist. The other three examples were indeed journalists and writers who were Â¨muckrakersÂ¨, a term used to describe journalists in the Progressive Area who were dedicated to exposing corruption in institutions or of different community leaders, businessman, politicians and the like.

why is 5 a rational number?

Answers

Every integer is a rational number, since each integer n can be written in the form n/1. For example 5 = 5/1 and thus 5 is a rational number. i hope this helps you

A rational number is any number that can be written as a ratio of two integers (hence the name!). In other words, a number is rational if we can write it as a fraction where the numerator and denominator are both integers.

5 is a rational number because it can be expressed as the quotient of two integers: 5÷ 1

Hope this helps!! ;))
Have a grat day!! <3

Andrew has a coupon for $2.80 puppy treats. One bag of treats usually costs $9.94 and contains 42 of the treats. If Andrew uses his coupon what will be the price per puppy treats

Answers

Here are the given facts of this question:

1. The regular price for a bag of treats $9.94
2. There are 42 treats in a box
3. The coupon worths $2.80

In order to find out how much it would be per puppy treats
You will have to do the following steps:

Step1 find out how much it would be after the discount:

Regular price 9.94 － The worth of the coupon 2.80 = $7.14
Now know how much it would be after the discount we'll have to find out how much it would be per puppy treat.

Step2 dividing the # of treats and the price after discount

The discount price 7.14 / The amount of treats per bag 42 = $0.17 per treat

So it would be $0.17 for each treat.

Hope this helps!

Andrew's price per puppy treat, after using a $2.80 coupon on a $9.94 bag that contains 42 treats, will be $0.17.

Andrew has a coupon that will reduce the price of puppy treats. Without the coupon, one bag of treats costs $9.94 and contains 42 treats. To find the price per treat after using the $2.80 coupon, we first subtract the coupon value from the original price of the bag. This gives us the discounted price of the bag:

Discounted Price = Original Price - Coupon Value = $9.94 - $2.80 = $7.14

Next, we find the price per treat by dividing the discounted price of the bag by the number of treats in the bag:

Price per Treat = Discounted Price ÷ Number of Treats = $7.14 ÷ 42 = $0.17 (rounded to two decimal places)

After using the coupon, the price per puppy treat will be $0.17.

1) when to use the median to describe the measure of center of a data set, 2) what measures of spread can we find when using box-plots, 3) what measure of spread is most appropriate to describe symmetrical data sets, 4) how does an outlier affect the mean of data set and give an example,

Answers

1. You should use the median to describe the measure of center of a data set when an outlier is present in a data set. Having an outlier will skew the mean of the data. This means it will adjust the average to be smaller or greater than what the actual numbers are showing. The median should be used as the measure of center in these circumstances.

2) Using a box plot, you can find the range and interquartile range. The range is the distance from the smallest number to the largest. The interquartile range is the distance from the first quartile to the third quartile. All these values are found on a box plot.

3)The best measure of spread to describe symmetrical data sets is the mean absolute deviation. This tells us how far on average the numbers are spread out from the mean.

4) See the answer given in #1 for the explanation. An example would be a student who scores 8, 9, 10, 9, 10, 2 on 6 quizzes. The mean would be an average of 8, which is not a good number to represent the score this student normally gets. The median of 9 is a better number to show how this student normally performs.

Answer:

what the dude above me put he wrong

Step-by-step explanation:

John rolls a number cube twice. What is the probability that the sum of the 2 rolls is less than 7, given that the first roll is a 1?

one over six
one over three
one over two
five over six

Answers

The probability would be 5/6.

There are 6 ways we can roll two dice and have the first number be a 1:
1, 1
1, 2
1, 3
1, 4
1, 5
1, 6

Out of these, 5 possibilities give us a sum less than 7:
1, 1
1, 2
1, 3
1, 4
1, 5

Thus we have 5/6.

Answer: The correct option is (d) five over six.

Step-by-step explanation: Given that John rolls a number cube twice. We are to find the probability that the sum of the 2 rolls is less than 8 given that he first roll is a 1.

The sample space of an event of rolling a cube is

S = {1, 2, 3, 4, 5, 6}.

That is, n(S) = 6.

Now, let 'A' be the event that the sum of the two rolls is less than 7, then

A = {1, 2, 3, 4, 5}.

That is, n(A) = 5.

So, the probability of happening of event A is given by

[tex]P(A)=\dfrac{n(A)}{n(S)}=\dfrac{5}{6}.[/tex]

Thus, the required probability is five over six.

Option (d) is correct.

If AB is a tangent then point b must be the point of tangency true or false

Answers

False. If AB is a tangent, it must intersect in only of its 1 point.

Find two numbers that multiply to make the first number and add to make the second number. (I understand how to do it, I’m just having some issues. It’s not registering.)

Answers

Let
x-----------> the first number
y-----------> the second number

we know that
x*y=x-----------> y=x/x----------> y=1
and x+y=y------> x=y-y---------> x=0

the answer is
the first number is 0
the second number is 1

The student's question pertains to solving a system of equations to find two numbers that multiply to a given product and add to a given sum. The solution involves testing pairs of factors of the product until the pair that also sums to the required number is found, for example, finding that 3 and 8 multiply to 24 and add to 11.

The student is looking to solve a classic problem in algebra: finding two numbers that, when multiplied together, result in a given number (the product), and when added together, sum to another given number (the sum). This is often related to factoring a quadratic equation or finding the roots of a polynomial. The solution involves setting up a system of equations based on the given conditions and solving for the two unknown numbers. This process typically requires identifying the correct pair of numbers that satisfy both the multiplication and addition conditions. Let's take an example:

Suppose we need to find two numbers that multiply to make 24 and add to make 11. We can denote these numbers as x and y, leading to the following equations:

x . y = 24 (multiplication condition)x + y = 11 (addition condition)

By systematically testing pairs of factors of 24 (e.g., 1 and 24, 2 and 12, 3 and 8, 4 and 6), we find that 3 and 8 satisfy both conditions, because 3 . 8 = 24 and 3 + 8 = 11. Therefore, the two numbers are 3 and 8.

What is the simplified form of (3 / x^3) / (1 / x^2) ?

Answers

The simplified form of (3/x^3) / (1/x^2) is 3/x

Find m∠A given ΔABC where a=4, b=6, c=3.

Answers

For this question, we're going to use the law of cosines.
The law of cosines is the following equation:

[tex]a^2=b^2+c^2-2(b)(c) \cos(A)[/tex]

We know the values of a, b, and c. We want to find the measure of angle A.
[tex]a=4[/tex]
[tex]b=6[/tex]
[tex]c=3[/tex]

Now, plug in these values into the equation.

[tex]4^2=6^2+3^2-2(3)(6) \cos(A)[/tex]
[tex]16=45-36 \cos(A)[/tex]

Add both sides by [tex]36 \cos(A)[/tex] and subtract both sides by 16

[tex]36 \cos(A)=29[/tex]

Divide both sides by 36

[tex]\cos(A)= \dfrac{29}{36}[/tex]

Take the inverse cosine, or arc cosine, of both sides.
Using a calculator, you'll get the following result.

[tex]A \approx 36.3^O[/tex]

The measure of angle A should be 36.3 degrees. Hope this helps! :)

A population has size 25 at time t = 0, with t measured in years. (a) if the population decreases by 4 people per year, find a function for the population size, p, at time t. enter your answer as an equation with p on the left side, and an expression involving t on the right

Answers

First we define the variables:
p = population
t: time in years
The equation that best fits this problem is a linear equation of the form:
p = -4t + 25
Note that for t = 0 the value of p is 25, which represents the initial population.
Answer:
a function for the population size, p, at time t is:
p = -4t + 25

Tyler is 9 years old his sister Olivia is 6 years less than twice his age writ a numerical expression for Olivia’s age

Answers

Hello there!

The following will show you

T = tyler

O = olivia

O = 2t - 6

when you include numbers, it is represented by:

O = (2 * 9) - 6

Now, let's solve this to find out just how old Olivia is.

2 * 9 = 18

18 - 6 = 12

Olivia is 12

This means that olivia is 3 years older than tyler

I hope I helped!

~ Fire

MATH HELP PLEASE WILL GIVE BRAINLIEST!!!
This figure shows circle A with inscribed ∠RSQ .

m∠RSQ=24°

What is the measure of RSQ?

Answers

the measure of RSQ is 24 degrees

For a better understanding of the solution and the explanation given here please go through the diagram in the file attached.

By definition, measure of an arc is the angle subtended by the arc at the centre of the circle. Thus, the measure of the arc [tex] \overarc {RSQ} [/tex] is the measure of the [tex] \angle RAQ [/tex] (in red) which the arc [tex] \overarc {RSQ} [/tex] subtends at the center.

Now, in order to find the measure of the [tex] \angle RAQ [/tex] (in red) we will have to use the information given in the question. We have been told that [tex] m\angle RSQ=24^{\circ} [/tex]. Now, we know that the double angle theorem says that, the angle subtended at the centre of a circle is double the size of the angle subtended at the circumference from the same two points. Therefore, applying this theorem we get:

[tex] \angle RAQ =2\times 24^{\circ}=48^{\circ} [/tex]

Thus if [tex] \angle RAQ [/tex] (in red)=[tex] 48^{\circ} [/tex], then [tex] \angle RAQ [/tex] (in green) will be equal to measure of the arc [tex] \overarc {RSQ} [/tex]. Now, [tex] \angle RAQ [/tex] (in green) will obviously be:

[tex] \angle RAQ [/tex] (in green)=[tex] 360^{\circ}-\angle RAQ [/tex] (in red)

[tex] \angle RAQ [/tex] (in green)=[tex] 360^{\circ}-48^{\circ} [/tex]

[tex] \angle RAQ [/tex] (in green)=[tex] 312^{\circ} [/tex]

Thus, the measure of arc [tex] \overarc {RSQ} [/tex]=[tex] 312^{\circ} [/tex]

20 POINTS! What is the slope of the line through the points (2, 5) and (6, 13)?

Answers

Slope can be found using the formula [tex] \frac{y2-y1}{x2-x1} [/tex].

[tex] \frac{13-5}{6-2} [/tex]
[tex] \frac{8}{4} [/tex]
Slope = 2

So the slope of the line that passes through that point is 2.

Hope this helps :)

your answer is 2. have a great day

The sum of two numbers is 58 . the smaller number is 10 less than the larger number. what are the numbers?

Answers

X+Y=58
X-Y=18 ADD
----------------
2X=76
X=76/2

X=38 ANS. FOR THE LARGER NUMBER.
38+Y=58
Y=58-38
Y=20 ANS. FOR THE SMALLER NUMBER.
PROOF:
38-20=18
18=18

Use the equation and type the ordered-pairs.

y = 3^x

(-1,__), (0,__), (1,__), (2,__), (3,__), (4,__)

Answers

See the attachment for a table. Of course, the first ordered pair is (-1, 1/3).

Answer: [tex](-1,\frac{1}{3}),\ (0,1),\ (1,3),\ (2,9),\ (3,27),\ (4,81)[/tex]

Step-by-step explanation:

The given exponential function :

[tex]y=3^x[/tex]

At x = -1, we get

[tex]y=3^{-1}=\dfrac{1}{3}[/tex]

At x = 0, we get

[tex]y=3^{0}=1[/tex]

At x = 1, we get

[tex]y=3^{1}=3[/tex]

At x = 2, we get

[tex]y=3^{2}=9[/tex]

At x = 3, we get

[tex]y=3^{3}=27[/tex]

At x = 4, we get

[tex]y=3^{4}=81[/tex]

Hence, the completed ordered pairs are : [tex](-1,\frac{1}{3}),\ (0,1),\ (1,3),\ (2,9),\ (3,27),\ (4,81)[/tex]

1. Add or subtract.

a. (x^2 - 4 x + 5) + (7x^2 + 2x + 3)

b. (7x^2 + 4x - 6) - (2x^2 - 3x + 1)

Answers

1a.

Answer is 8x² - 2x + 8

(x² - 4x + 5) + (7x² + 2x + 3)

The parentheses can go away since this is all addition (associative property of addition)

x² - 4 x + 5 + 7x² + 2x + 3

Combine like terms.

(x^2 + 7x²) + (-4x + 2x) + (5 + 3) = 8x² - 2x + 8

======

1b.

Answer is 5x^2 + 7x - 7

(7x² + 4x - 6) - (2x² - 3x + 1)

Distribute the negative into the right parentheses.

(7x² + 4x - 6) - (2x² - 3x + 1)

= 7x² + 4x - 6 - 2x² + 3x - 1

= (7x² - 2x²) + (4x + 3x) + (-6 - 1)

= 5x^2 + 7x - 7

Look Ray 0.45 hour to rake the leaves and 3/4 hour to mow the lawn how many minutes did it take him to do both tasks

Answers

0.45*60=27
0.75*60=45
27+45=72
The answer is 72 minutes

**NEED HELP!!!

Bo’s gross annual income is $45,408. He is paid semimonthly and has 6% deducted from his paychecks for his 403(b). His employer matches his deduction, up to 3%.

How much is deposited into Bo’s 403(b) each payday?

Answers

Answer:

170.28

Step-by-step explanation:

I just took the test and am reviewing the correct answers.

If a family has three children draw a tree diagram representing the possible outcomes for the genders of the children and then list the sample space

Answers

Each child has a 50/50 chance of being boy or girl whether the other child was a boy or girl. The possible chances are BBG, BBB, BGG, GGG

HELP PLEASE
Find the value of x, if you know the hypotenuse is 10 and 1 of the sides is 5. X is the other side.

Answers

We can use Pythagorean's Theorem to solve for the unknown side:
[tex]a^2+b^2=c^2[/tex]

Solve for b (c is the hypotenuse and it doesn't matter which side is a or b):
[tex]b = \sqrt{c^2-a^2} = \sqrt{10^2-5^2} = \sqrt{100-25} = \sqrt{75} [/tex]

We can simplify this:
[tex] \sqrt{75} = \sqrt{25*3} = 5 \sqrt{3} [/tex]

So, your answer is, b = [tex]5 \sqrt{3} [/tex]

Hey there! :)

For questions like these, where you are given the hypotenuse & one side of a triangle, then we can very simply use the Pythagorean Theorem to find x.

Pythagorean Theorem : a² + b² = c²

Where :

a = side length
b = another side length
c = hypotenuse

Since we are given 10 as the hypotenuse and 5 as a side length, we can very simply plug these into the Pythagorean theorem.

a² + b² = c²

We'll plug 10 into 'c' and 5 into 'a.'

(5²) + b² = (10²)

Simplify.

25 + b² = 100

Now, subtract 25 from both sides.

b² = 100 - 25

Simplify.

b² = 75

Now, find the square root of b² and 75.

[tex] \sqrt{b^2} = \sqrt{75} [/tex]

Simplify.

[tex]b = 5 \sqrt{3} [/tex]

Therefore, our final side length is : [tex]5 \sqrt{3} [/tex]

~Hope I helped!~

Order the group of quadratic functions from widest to narrowest graph. y = 6x2, y = −4.5x2, y = −x2

Answers

To solve this problem you must keep on mind the following information: By definition, a quadratic function has the following form:
[tex] y=ax^{2}+bx+c [/tex]
Where [tex]a [/tex] is the leading coefficient.
If the leading coeficient is closer to zero, the parabola is widest,if it has a larger positive or negative value, the parabola is narrowest.
Therefore, by knowing the information above, you have that the answer is:
[tex]y=- x^{2} \\ y=-4.5 x^{2} \\ y=6 x^{2} [/tex]

y = 6x2, y = −4.5x2, y = −x2

This should be correct answer:) He got it mixed up in his answer below when graphing.:)

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