A sample of gas occupies 280 mL when the pressure is 560.00 mm Hg . If the temperature remains constant , what is the new pressure if the volume changes to 560.0 mL?

Answers

Answer 1

Answer : The new pressure if the volume changes to 560.0 mL is, 280 mmHg

Explanation :

According to the Boyle's, law, the pressure of the gas is inversely proportional to the volume of gas at constant temperature and moles of gas.

[tex]P\propto \frac{1}{V}[/tex]

or,

[tex]P_1V_1=P_2V_2[/tex]

where,

[tex]P_1[/tex] = initial pressure = 560.00 mmHg

[tex]P_2[/tex] = final pressure = ?

[tex]V_1[/tex] = initial volume = 280 mL

[tex]V_2[/tex] = final volume = 560.0 mL

Now put all the given values in the above formula, we get:

[tex]560.00mmHg\times 280 mL=P_2\times 560.0 mL[/tex]

[tex]P_2=280mmHg[/tex]

Therefore, the new pressure if the volume changes to 560.0 mL is, 280 mmHg


Related Questions


The diagram shows a pump. Which labels can replace
X and the Y in the diagram?
X: potassium, Y: sodium
X: sodium, Y potassium
X: sodium, Y: calcium
X: calcium, Y: potassium ​

Answers

Answer: The Answer is B. X: Sodium, Y: Potassium

Explanation: No Explanation I just Guessed. Hope This Help's Someone

Answer:

The answer is

X:Sodium Y:Potassium

Explanation:

I took the course and got it right

Some farmers leave a strip of land around the edge of each field which they do
not spray with chemicals.

Suggest two reasons why this will lead to an increase in the number of partridges
on these farms.

Answers

Answer:

There are no caterpillars on the oak tree in winter. ... Some farmers spray their crops with chemicals to kill insects and weeds. ... Some farmers leave a strip of land around the edge of each field which they do not spray with chemicals.

Explanation:

Hope this help ;)

Final answer:

Farmers leaving unsprayed strips of land can increase partridge numbers due to safer habitats free from pesticides and better provision of food and nesting areas.

Explanation:

Leaving a strip of land around the edge of each field unsprayed with chemicals will likely increase the number of partridges on these farms for two main reasons.

Pesticide avoidance provides a safe habitat for partridges and other wildlife, reducing mortality rates from chemical exposure. Habitat provision enhances the availability of food sources and nesting areas, encouraging the proliferation of partridge populations.

Crop rotation is also a practice that allows farmers to improve soil fertility, diversify their crops, and reduce pesticide costs by breaking the cycle of weeds, insects, and diseases naturally.

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The specific heat capacity of an unknown metal is 0.343 J/(g•°C). Calculate the energy required to raise the temperature of 224 g of this metal by 71°C.

Answers

Answer:

Preceding accumulative aggregate of energy indispensable is disseminated as 5455 J.

Explanation:

Allotted the contiguous information:

Q: Not identified.

M: 224 g

S: 0.343 J/g°C

Final thermodynamics: 71°C

Initial thermodynamics: 0°C

ΔT = 71°C

We can equate as imminent:

Q = 224 g · 0.343 J/g°C · 71°C

Q ⇒ 5455 J

Hence, the pertaining preeminent albeit paramount indispensable consignment or quantity of energy obligated, concerning an augmentation in thermodynamics subject to the undisclosed metal by 71°C is 5,455 J.

Final answer:

The energy required to raise the temperature of the metal is 5365.256 J.

Explanation:

To calculate the energy required to raise the temperature of a substance, we use the formula:

q = m * c * ΔT

The energy required to raise the temperature of a substance can be calculated using the formula: q = mcΔT where q is the energy in joules, m is the mass in grams, c is specific heat capacity in J/(g•°C), and ΔT is the change in temperature in °C.

Given that the mass (m) of the metal is 224 g, the specific heat capacity (c) is 0.343 J/(g•°C), and the temperature change (ΔT) is 71°C, you can substitute these values into the formula:

Plugging in the values given:

q = (224 g) * (0.343 J/(g•°C)) * (71°C)

Simplifying the equation gives:

q = 5365.256 J

Therefore, the energy required to raise the temperature of 224 g of this metal by 71°C is 5365.256 J.

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how is temperature related to the physical change of a substance ?

Answers

Physical conditions like temperature and pressure affect state of matter. ... When thermal energy is added to a substance, its temperature increases, which can change its state from solid to liquid (melting), liquid to gas (vaporization), or solid to gas (sublimation).

Answer: Temperature is a measure of the kinetic energy of particles in a substance. As temperature increases, the atoms or molecules in a substance gain energy. As temperature decreases, the particles lose energy. A change in the energy of particles causes a change in their arrangement. A change in the arrangement of particles can lead to a physical change.

Explanation:

Which element will have the following property in the periodic table 1)Largest atomic size 2) Highest electron affinity 3) lowest ionisation enthalpy in group II 4) gaseous form at room temperature

Answers

In the periodic table, Francium has the largest atomic size, Chlorine has the highest electron affinity, Barium has the lowest ionization enthalpy in Group II, and gaseous elements at room temperature include noble gases and some non-metals like Fluorine and Oxygen.

The periodic table organizes elements in such a way that we can predict their properties based on their position. These properties, including atomic size, electron affinity, and ionization enthalpy, show clear patterns or trends within the table. As a tutor from the Brainly platform, let's address the specific properties asked in the question.

The element with the largest atomic size is typically found at the bottom left of the periodic table. Francium (Fr) is generally considered to have the largest atomic radius because it belongs to Group 1 and is the heaviest alkali metal. The atomic size increases down a group and decreases across a period from left to right.Highest electron affinity is generally observed in halogens. Chlorine (Cl), being very eager to gain an electron to achieve a noble gas electron configuration, has one of the highest electron affinities.The element with the lowest ionization enthalpy in Group II is expected to be at the bottom of the group. Barium (Ba), being at the lower part of Group II, has lower ionization energy compared to its counterparts up the group.Gases at room temperature from Group II are notable as they are non-existent; however, elements that are in gaseous form at room temperature from the periodic table include the noble gases such as Radon (Rn), Xenon (Xe), Krypton (Kr), Argon (Ar), Neon (Ne), Helium (He), and some non-metals like Fluorine (F), Chlorine (Cl), Oxygen (O), Nitrogen (N), and Hydrogen (H).

Chemistry: Gas Laws Problems!

Answers

Answer : The final volume at STP is, 1000 L

Explanation :

According to the Boyle's, law, the pressure of the gas is inversely proportional to the volume of gas at constant temperature and moles of gas.

[tex]P\propto \frac{1}{V}[/tex]

or,

[tex]P_1V_1=P_2V_2[/tex]

where,

[tex]P_1[/tex] = initial pressure = 1520 mmHg = 2 atm    (1 atm = 760 mmHg)

[tex]P_2[/tex] = final pressure at STP = 1 atm

[tex]V_1[/tex] = initial volume = 500.0 L

[tex]V_2[/tex] = final volume at STP = ?

Now put all the given values in the above formula, we get:

[tex]2atm\times 500.0L=1atm\times V_2[/tex]

[tex]V_2=1000L[/tex]

Therefore, the final volume at STP is, 1000 L

The volume of the gas at STP is [tex]\(1000.0 \, \text{L}\)[/tex].

1. Convert initial pressure to atm:

  [tex]\[ P_1 = \frac{1520 \, \text{mm Hg}}{760 \, \text{mm Hg/atm}} = 2 \, \text{atm} \][/tex]

2. Apply the Combined Gas Law:

  [tex]\[ \frac{P_1 \cdot V_1}{T_1} = \frac{P_2 \cdot V_2}{T_2} \][/tex]

  Given:

  [tex]\[ V_1 = 500.0 \, \text{L} \][/tex]

  [tex]\[ P_1 = 2 \, \text{atm} \][/tex]

  [tex]\[ P_2 = 1 \, \text{atm} \][/tex]

  [tex]\[ T_1 = T_2 \][/tex] (temperature does not change)

  Substituting the values, we get:

  [tex]\[ \frac{(2 \, \text{atm} \cdot 500.0 \, \text{L})}{T} = \frac{(1 \, \text{atm} \cdot V_2)}{T} \][/tex]

3. Solve for [tex]\(V_2\)[/tex]:

  Cross-multiply and solve for [tex]\(V_2\)[/tex]:

  [tex]\[ 2 \cdot 500.0 = 1 \cdot V_2 \][/tex]

  [tex]\[ V_2 = \frac{2 \cdot 500.0}{1} \][/tex]

  [tex]\[ V_2 = 1000.0 \, \text{L} \][/tex]

Consider the equation ; N₂ + 3 H₂ → 2 NH₃ What is the mole ratio of hydrogen to ammonia (NH₃)?
1. 1:1
2. 1:2
3. 3:2
4 5:4

Answers

Answer:

3. 3:2

Explanation:

in the reactants, 3 is the coefficient for the hydrogen atoms.

In the products, 2 is the coefficient for the ammonia atoms.

The reduction potential (E0′) of a substance reflects its tendency to donate or accept electrons. The larger the difference (ΔE0′) between the reduction potentials of the electron donor and the electron acceptor, __________.A) the greater the change in free energy (ΔG0′), and the less energy is releasedB) the closer the substances are on the electron towerC) the more enzymes will be required to catalyze the reaction(s)D) the greater the change in free energy (ΔG0′), and the greater the energy released

Answers

Answer:

The greater the change in free energy (ΔG0′), and the greater the energy released

Explanation:

Recall that the change in free energy is given by:

∆G°'= nFE°'

But E° is given by E°acceptor - E°donor

Hence the greater the difference between E°acceptor and E°donor, the greater the value of E° and consequently the greater the value of ∆G° and the energy released.

Note: E°acceptor and E°donor refer to reduction potentials of donor and acceptor

The heat of combustion of propane, C3H8, is 2220 kJ/mol. The specific heat of copper is 0.385 J/g°C. How many grams of propane must be burned to raise the temperature of a 10.0 kg block of copper from 25.0°C to 65.0°C, assuming none of the heat is lost to the surroundings?

Answers

Answer:

Explanation:

q = (mass) (temp change) (specific heat)

q = (10000 g) (40 °C) (0.385 J/g⋅°C) = 154000 J = 154 kJ

154 kJ / 2220 kJ/mol = 0.069369369 mol

0.069369369 mol times 44.0962 g/mol = 3.06 g (to three sig figs)

answer choice 4

The heat of combustion ([tex]\Delta[/tex]Hc0) is the amount of energy released as heat when a compound completely burns with oxygen under standard conditions.

3.05988g. grams of propane must be burned to raise the temperature of a 10.0 kg block of copper from 25.0°C to 65.0°C.

What is meant by heat of combustion?The heat of combustion ([tex]\Delta[/tex]Hc0) is the amount of energy released as heat when a compound completely burns with oxygen under standard conditions. In most cases, a hydrocarbon reacts with oxygen to produce carbon dioxide, water, and heat.The heat of combustion of a substance is the amount of energy released when a specific amount (e.g., 1 mol, 1g, 1 L) of the substance completely burns in oxygen. The heat of combustion is typically measured at 298K (25 C) and 101.3kPa.The energy released when a substance X completely burns with an excess of oxygen under standard conditions (25°C and 1 bar). It is the inverse of the enthalpy change for the combustion reaction in thermodynamic terms.

q=m*c*(change of T)

q=10000g(0.385J/g*c)*(65.0C-25.0C)or (338.2 K-298.2K)

q=154000J

154000J*(1 mol/2220 KJ)=69.36936 x [tex]10 ^-3[/tex] mol

here's where I'm stuck

0.069369 mol

and i know that for every 1 mol there is 44.11g of C3H8.

0.069369 mol* (44.11g C3H8)/1mol = 3.05988g.

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How many dots should be shown in the Lewis dot diagram of carbon?

1
2
3
4

Answers

Answer:

Im 90% sure its 3.

Explanation:

Answer:

4

Explanation:

Liquid A has a vapor pressure of 7.37 kPa at 40C. Liquid B has a vapor pressure of 18.04kPa at 40C. Which liquid would evaporate faster at 40C? Explain your answer.

Answers

Answer:

Liquid B because of its higher vapor pressure due to the fact that evaporation rate is directly proportional to vapor pressure

Explanation:

The vapor pressure of  liquid at equilibrium is a function to the liquid's rate of evaporation. The evaporation rate and hence the vapor pressure is a measure of the propensity of the particles  of the liquid to leave the surface of the liquid and exist as vapor directly above the liquid. As high evaporation rate leads to high vapor pressure, a liquid with a higher vapor pressure will evaporate faster than one with a lower vapor pressure at the same temperature and pressure.

Therefore, liquid B with a vapor pressure of 18.04 kPa at 40° C will evaporate faster than liquid A with a lower vapor pressure of 7.37 kPa at the same 40°C.

Final answer:

Liquid B with a higher vapor pressure of 18.04 kPa at 40°C would evaporate faster than liquid A with 7.37 kPa, as higher vapor pressure indicates that the liquid is more volatile and its molecules can more easily escape into the gas phase.

Explanation:

At 40°C, between liquid A with a vapor pressure of 7.37 kPa and liquid B with a vapor pressure of 18.04 kPa, liquid B would evaporate faster. This is because vapor pressure is a measure of the tendency of molecules to escape from a liquid and enter the gas phase. A higher vapor pressure indicates that molecules can break away from the surface of the liquid more easily, which is indicative of a more volatile liquid. Therefore, liquid B, with its higher vapor pressure at the same temperature, is the more volatile and will evaporate more rapidly than liquid A.

Vapor pressure of a liquid is directly related to its intermolecular forces; liquids with weaker intermolecular forces have higher vapor pressures, and hence they evaporate faster. Conversely, greater intermolecular forces result in a lower vapor pressure and slower evaporation rate. For volatile liquids in a mixture, adding their partial pressures yields the total vapor pressure of the mixture

You purchase several rolls of fiberglass insulation and pay extra for installation. Have you purchased a product or a service?

Answers

Both bc your buying the product and a service of them installing it

You purchase several rolls of fiberglass insulation and pay extra for installation. This is a service.

What is fiberglass insulation?

The majority of homes include fibreglass, an insulation substance made of incredibly thin glass fibres. It is frequently used in two forms of insulation: loose-fill and batts and rolls. Additionally, rigid boards or duct insulation are both options.

In accordance with the U.S. Department of Energy, manufacturers already make medium- and high-density fibreglass batt insulation materials with a little better R-Value than regular batts. Unfinished floors, ceilings, and walls can all be filled with fibreglass. It is set in place between beams, joists, and studs. You purchase several rolls of fiberglass insulation and pay extra for installation. This is a service.

Therefore, fiberglass insulation is a service.

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A 48.4-g sample of glucose (a nondissociated, nonvolatile solute with the formula c6h12o6) is dissolved in 151.2 g of water. what is the vapor pressure of this solution at 100°c?

Answers

Answer:

Vapor pressure of solution is 736mmHg

Explanation:

Vapor pressure of an ideal solution follows Raoult's law:

[tex]P_{solution} = X_{solvent}P_{solvent}[/tex]

Where P is vapor pressure and X is mole fraction

Moles of glucose are:

48.4g × (1mol / 180.156g) = 0.2687mol glucose

Moles of water:

151.2g × (1mol / 18.1g) = 8.354 mol water

Thus, mole fraction of water (Solvent) is:

8.354 mol / (8.354 mol + 0.2687mol) = 0.9688

Vapor pressure of a solvent at boiling point is equal to atmospheric pressure (760mmHg). Replacing in Raoult's law:

[tex]P_{solution} = 0.9688*760mmHg[/tex]

Vapor pressure of solution is 736mmHg

The vapor pressure of the solution will be "736 mmHg".

Vapor pressure

According to the question,

Sample of glucose = 48.4 g

Mass of water = 151.2 g

Temperature = 100°C

Now,

Moles of glucose will be:

= 48.4 × ([tex]\frac{1 \ mol}{180.156}[/tex])

= 0.2687 mol

Moles of water will be:

= 151.2 × ([tex]\frac{1 \ mol}{18.1}[/tex])

= 8.354 mol

Water's moles fraction will be:

= [tex]\frac{Moles \ of \ water}{Moles \ of \ water +Glucose}[/tex]

By substituting the values,

= [tex]\frac{8.354}{8.354+0.2687}[/tex]

= 0.9688

hence,

By using Raoult's Law,

→ [tex]P_{solution}[/tex] = [tex]X_{solvent} P_{solvent}[/tex]

By substituting the values,

                = 0.9688 × 760

                = 736 mmHg

Thus the above solution is correct.55

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What volume of a 3.70 M NaCl solution is needed for a reaction that requires 118 g of NaCl?

Answers

Answer:

volume of solution L =0.54 L

Explanation:

Given data:

Molarity of NaCl solution = 3.70 M

Mass of NaCl = 118 g

Solution:

First of all we will calculate the number of moles.

Number of moles = mass/ molar mass

Number of moles = 118 g/ 58.5 g

Number of moles = 2 mol

Now we will calculate the volume from molarity formula:

Molarity = number of moles / volume of solution L

3.70 M = 2 mol / volume of solution L

volume of solution L = 2 mol / 3.70 M

volume of solution L =0.54 L

Ag2O(s) → 2Ag(s) + ½ O2(g) ΔH° = 31.05 kJ Which statements concerning the reaction above are true? (1) heat is released (2) heat is absorbed (3) reaction is exothermic (4) reaction is endothermic (5) products have higher enthalpy content than reactants (6) reactants have higher enthalpy content than products A) 1, 3, and 5 B) 1, 3, and 6 C) 2, 4, and 6 D) 2, 4, and 5

Answers

Answer:

D) 2, 4, and 5

Explanation:

In order to fully comprehend the answer choices we must take a close look at the value of ΔH° = 31.05. The enthalpy change of the reaction is positive. A positive value of enthalpy of reaction implies that heat was absorbed in the course of the reaction.

If heat is absorbed in a reaction, that reaction is endothermic.

Since ∆Hreaction= ∆H products -∆H reactants, a positive value of ∆Hreaction implies that ∆Hproducts >∆Hreactants, hence the answer choice above.

Answer:

D

Explanation:

Ozone reacts completely with NO, producing NO2 and O2. A 13.0 L vessel is filled with 1.30 mol of NO and 1.30 mol of O3 at 401.0 K. Find the partial pressure of each product and the total pressure in the flask at the end of the reaction.

Answers

Answer:

6.58 atm total

3.29 atm NO2

3.29 atm O2

Explanation:

Balanced equation:

O3 + NO → NO2 + O2

There are equal numbers of moles of both reactants, so neither is in excess and either could be considered the limiting reactant.

( 1.30 mol NO) x (1 mol NO2 / 1 mol NO) =  1.30 mol NO2

( 1.30 mol NO) x (1 mol O2 / 1 mol NO) =  1.30 mol O2

Total pressure by using the formula;

P = nRT / V

= ( 1.30 mol +  1.30 mol) x (0.08205746 L atm/K mol) x (401.0 K) / (13.0 L)  

= 6.58 atm

Partial pressure for NO2;

(6.58 atm) x (1.30 mol NO2) / (1.30 mol + 1.30 mol)

= 3.29 atm NO2

Partial pressure for O2

6.58 atm total - 3.29 atm NO2

= 3.29 atm O2

1. The partial pressure of nitrogen dioxide ([tex]NO_2[/tex]) is equal to 3.29 atm.

2. The partial pressure of oxygen gas ([tex]O_2[/tex]) is equal to 3.29 atm.

3. The total pressure in the flask at the end of the chemical reaction is 6.58 atm.

Given the following data:

Volume of flask = 13.0 LitersNumber of moles of NO = 1.30 moles.Number of moles of [tex]O_3[/tex] = 1.30 moles.Temperature = 401.0 K.

Scientific data:

Ideal gas constant, R = 0.0821L⋅atm/mol⋅K

To determine the partial pressure of each product and the total pressure in the flask at the end of the chemical reaction:

First of all, we would write a balanced chemical equation for the chemical reaction as follows:

                                  [tex]O_3 + NO \rightarrow NO_2+O_2[/tex]

Since the numbers of moles of reactants are equal, the total number of moles of products is:

[tex]n=1.3+1.3[/tex]

n = 2.6 moles

Now, we can find the total pressure in the flask at the end of the chemical reaction by using the ideal gas law equation;

[tex]PV=n RT[/tex]

Where;

P is the pressure.V is the volume.n is the numbers of moles of gas.R is the ideal gas constant.T is the temperature.

Making P the subject of formula, we have;

[tex]P=\frac{nRT}{V}[/tex]

Substituting the parameters into the formula, we have;

[tex]P=\frac{2.6 \times 0.0821 \times 401}{13}\\\\P=\frac{85.597}{13}[/tex]

Total pressure, P = 6.58 atm.

Next, we would determine the partial pressure of each product:

[tex]Molefraction \;of \;a \;substance =\frac{No.\; of \; moles \;of \;substance}{Total \;no. \;of \; moles \;of \;substances}[/tex]

[tex]Molefraction \;of \;a \;substance =\frac{1.3}{2.6} \\\\Molefraction \;of \;a \;substance =0.5[/tex]

For [tex]NO_2[/tex]:

[tex]Partial \;pressure = Molefraction \times Total\;pressure\\\\Partial \;pressure = 0.5 \times 6.58[/tex]

Partial pressure of [tex]NO_2[/tex] = 3.29 atm.

For [tex]O_2[/tex]:

[tex]Partial \;pressure = Molefraction \times Total\;pressure\\\\Partial \;pressure = 0.5 \times 6.58[/tex]

Partial pressure of [tex]O_2[/tex] = 3.29 atm.

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What volume of water should be used to dissolve 19.6 g of LiF to create a 0.320 M solution?

Answers

Answer:

2.4 L

Explanation:

Given data:

Mass of LiF = 19.6 g

Molarity of solution = 0.320 M

Volume of water used = ?

Solution:

Number of moles = mass/molar mass

Number of moles = 19.6 g/ 26 g/mol

Number of moles = 0.75 mol

Volume required:

Molarity = number of moles/ volume in L

0.320 M = 0.75 mol /  volume in L

Volume in L = 0.75 mol  /0.320 M

      M = mol/L

Volume in L = 2.4 L

For a reaction system at equilibrium, LeChatelier's principle can be used to predict the A) activation energy for the system B) type of bonds in the reactants C) effect of a stress on the system D) polarity of the product molecules

Answers

For a reaction system at equilibrium, LeChatelier's principle can be used to predict the "effect of a stress on the system".

Option: C

Explanation:

Le Chatelier's theory can be implemented to forecast a system's behavior due to variations in pressure, temperature, or concentration that will lead in predictable and contested variations in the system adjustments to establish a new state of equilibrium. This means that adding heat to a process would favor the endothermic path of a reaction, because this decreases the amount of heat generated in the system.

Here shift in equilibrium take place when volume increase, the total pressure decreases, which have potential to reverse the reaction, while on increasing pressure of system, the total volume decreases of the gaseous system, which can shift an equilibrium in the direction of the fewer molecules.

For a reaction system at equilibrium, the Le principle can be used to predict the effect of a stress on the system.

The Le principle is an observation about chemical equilibria of reactions. Le principle can be used to predict the effect of a stress like changing concentration of a substance has on a reaction system at equilibrium.

If the concentration of a reaction species is increased at constant Temperature and Volume, the equilibrium system will shift in the direction that reduces the concentration of that substance so we can conclude that the Le principle can be used to predict the effect of a stress on the system.

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How many miles of C5H12 are there in 362.8 grams of the compound?

Answers

Answer:

5.03 moles

Explanation:

Find the molar mass of C5H12 and you will get 72.17 g/mol

Next to find the number of moles, you divide 362.8 by the molar mass and you get

(362.8 g)/(72.17 g/mol)= 5.03 moles

Which word equation shows lithium oxide being formed from the reaction between oxygen and lithium? oxygen + lithium oxide Right arrow. Lithium lithium + oxygen Right arrow. Lithium oxide oxygen + lithium Right arrow. Lithium + oxide lithium oxide Right arrow. Lithium + oxygen

Answers

Answer: lithium + oxygen Right arrow. lithium oxide

lithium + oxygen proper arrow. lithium oxide This equation indicates lithium oxide is formed from the reaction between oxygen and lithium.

what is lithium oxide used for?

Lithium oxide is used as a flux in ceramic glazes and creates blues with copper and pinks with cobalt. Lithium oxide reacts with water and steam, forming lithium hydroxide, and needs to be isolated from them.

wherein is Lithium Oxide found?

Lithium Oxide is an extraordinarily insoluble thermally stable Lithium source suitable for glass, optic, and ceramic programs. Lithium oxide is a white stable also referred to as lithia, it is produced whilst lithium metallic burns inside the presence of oxygen.

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which solution contains phenolphthalein pink?

Answers

Any liquid with a pH above 8.2.

Phenolphthalein is naturally colorless but turns pink in alkaline solutions. The compound remains colorless throughout the range of acidic pH levels but begins to turn pink at a pH level of 8.2 and continues to a bright magenta at pH 10 and above.
If hydrogen ions (H+, as found in an acid) were added to the pink solution, the equilibrium would switch, and the solution would be colorless. Adding hydroxide ions (OH-, as found in bases) will change the phenolphthalein into its ion and turn the solution pink.
Chemical formula: C20H14O4
Solubility in water: 400 mg/L
GHS precautionary statements: P201, P281, P308+313

A neutral solution has a pH =
When a solution is basic, the pH is always greater than
When a solution is basic, the pOH is always less than

Answers

Answer:

7.

Explanation:

A neutral solution has a pH=7.

A basic solution has a pH>7.

An acidic solution has a pH<7.

Answer:

7,7,7

Explanation:

At room temperature, which answer is the most compressible?

one liter of water, a liquid
one liter of oxygen, a gas
one liter of iron, a solid
one liter of mercury, a liquid

Answers

Answer:

i think its 1 liter of oxygen , a gas

Final answer:

One liter of oxygen gas is the most compressible among the options given, due to the significant spaces between gas molecules allowing for easier compression.

Explanation:

When considering the compressibility of various substances at room temperature, gases such as oxygen are the most compressible due to the large spaces between their molecules. In comparison, liquids like water and mercury are less compressible because their molecules are closer together, but they still offer some degree of compressibility. Solids like iron, however, are much less compressible because their atoms are tightly packed in a lattice structure. Of the options provided, one liter of oxygen gas would be the most compressible, as the spacing between gas molecules allows them to be pushed closer together far more easily than molecules in a liquid or atoms in a solid.

Heat transfer focuses on transfers between the system and _____
A. accessories
B. universe
C. phases
D. surroundings

Answers


i think it should be D
The answer is c. Thank you

How many grams of sodium bromide must be dissolved in 400.0 g of water to produce a 0.500 molal solution?

Answers

Answer:

The answer is 20.6 grams.

Explanation:

Molality describes the concentration of a solution. It can be defined as the number of moles of a solute dissolved in 1 kilogram of solvent. Then it is equal to the moles of solute (the substance that dissolves) divided by the kilograms of solvent (the substance used to dissolve):

[tex]Molality=\frac{number of moles of solute}{kilogram of solvent}[/tex]

The molality is expressed in units ([tex]\frac{moles}{kg}[/tex]).

So, you can apply the following rule of three with the solution being 0.5 molal: if in 1 kg of solution there are 0.5 moles of solute, in 0.4 kg (400 g, being 1kg = 1000g) how many moles of solute are there?

[tex]moles=\frac{0.4 kg*0.5 moles}{1 kg}[/tex]

moles=0.2 moles

Now, you know:

Na: 23 g/moleBr: 80 g/mole

Then, The molar mass of sodium bromide NaBr is

NaBr= 23 g/mole + 80 g/mole= 103 g/mole

Now a new rule of three applies, if in 1 mole of sodium bromide there are 103 grams, in 0.2 mole how much mass is there?

[tex]mass=\frac{0.2 moles*103 grams}{1 mole}[/tex]

mass= 20.6 grams

The answer is 20.6 grams.

How many moles are there in 24.00 g of NaCl

Answers

Answer:

The answer to your question is 0.41 moles

Explanation:

Data

moles of NaCl = ?

mass of NaCl = 24 g

Process

To solve this problem just calculate the molar mass of NaCl, and remember that the molar mass of any substance equals to 1 mol.

1.- Calculate the molar mass

NaCl = 23 + 35.5 = 58.5 g

2.- Use proportions and cross multiplication

               58.5 g of NaCl ------------------- 1 mol

               24.0 g               ------------------- x

                     x = (24 x 1) / 58.5

                     x = 0.41 moles

Which process is used to determine the concentration of an acid?

Answers

Answer:

testing

Explanation:

some scientist somewhere made acid and probably forgot the recipe/ingredients so they kept making it and used plastic to see if it would melt it

HgO + Cl2 → HgCl + O2

A. Double Replacement
B. Single Replacement
C. Combustion
D. Decomposition
E. Synthesis

Answers

Answer:

B. Single Replacement

Explanation:

Single replacement:

It is the reaction in which one elements replace the other element in compound.

AB + C → AC + B

Chemical equation:

2HgO + Cl₂ → HgCl + O₂

This is the single replacement reaction. In this reaction chlorine replace the oxygen from mercury oxide and form mercury chloride.

Other options are incorrect because,

Decomposition reaction:

It is the reaction in which one reactant is break down into two or more product.

AB → A + B

Synthesis reaction:

It is the reaction in which two or more simple substance react to give one or more complex product.

A + B → AB

Double replacement:

It is the reaction in which two compound exchange their ions and form new compounds.

AB + CD → AC +BD

The decomposition of sulfonyl chloride, SOCl2 is a first order reaction with a half life of 8.75 hours. Calculate the concentration of SOCl2 after 17.0 hours have passed in an experiment where the initial concentration of sulfonyl chloride was .0837M.

Answers

Answer:

      [tex][SOCl_2]=0.0218M[/tex]

Explanation:

The equations for a first order reaction are:

      [tex]\dfrac{d[A]}{dt}=-k[A][/tex]

      [tex][A]=[A_0]e^{-kt}[/tex]

      [tex]t\frac{1}{2}=\dfrac{\ln 2}{k}[/tex]

1. Calculate the constant of reaction, k:

Use the equation

                                [tex]t\frac{1}{2}=\dfrac{\ln 2}{k}[/tex]

     [tex]8.75h=\dfrac{\ln 2}{k}[/tex]

     [tex]k=\dfrac{\ln 2}{8.75h}[/tex]

     [tex]k\approx 0.0792168h^{-1}[/tex]

2. Calculate the concentration after 17.0 hours

Use the equation

                               [tex][A]=[A_0]e^{-kt}[/tex]

      [tex][SOCl_2]=0.0837M\cdot e^{-0.0792168h^{-1}\times 17.0h}[/tex]

      [tex][SOCl_2]=0.0218M[/tex]

If 0.545J of heat leads to a 0.892 degree C change, what mass of water is present?

Answers

Answer:

I got .146 g of water

Explanation:

Refer to this equation:

Q= mcΔt

Q= .545 J

c= 4.186 J/g

Δt= .892

plug in values:

.545 J = m(4.186 J/g)(.892°C)

simplify:

.545 J = m(3.734 J/g°C)

.146 g

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