¿A shaker of salt substitute contains 1.6 oz of K. What is the activity, in milliCuries, of the potassium in the shaker? The activity is 7 microcuries (µCi)

Answers

Answer 1
We know K-40 (potassium having atomic mass 40 g) is radioactive and its natural abundance is 0.012% 
So for 1 mol of potassium contains 0.00012 mol of K-40 
Now 1.6 oz of K = 45.36 g of K
average atomic weight of K = 39.1 g
so 45.36 g of K contains:
(45.36 / 39.1) * 0.00012 * 6.022 x 10²³ (atoms of K-40)
= 8.4 x 10¹⁹ atoms of K-40
We know, activity A is:
A = 0.693 / t1/2 N₀
[t1/2 : half life time and N₀ : initial number of atoms]
t1/2 of K-40 = 1.28 x 10⁹ years
    = 4.04 x 10¹⁶ seconds
So A = (0.693 / 4.04 x 10¹⁶) * (8.4 x 10¹⁹ ) = 1441 cps
A = 141 x (1/3.7 x 10¹⁰)   because 3.7 x 10¹⁰ cps = 1 Ci
A = 3.9 x 10⁻⁸ Ci  = 3.9 x 10⁻⁵ millicurie


Related Questions

Which substance yields hydroxide ion as the only negative ion in aqueous solution?

Answers

Missing question:
a. Mg(OH)2.
b. CH3Cl.
c. MgCl2 .
d. C2H4(OH)2.
Answer is: a. Mg(OH)₂.
An Arrhenius base is a substance that dissociates in water to form hydroxide ions (OH⁻).
In this example magnesium hydroxide is an Arrhenius base:
Mg(OH)₂(aq) → Ba²⁺(aq) + 2OH⁻(aq).
CH₃Cl and C₂H₄(OH)₂ are organic compound and will not give hydroxide ions in water, MgCl₂ is neutral salt and it will give Cl⁻ ions.


The standard reduction potential for I2/I –is +0.54V, and the standard reduction potential for Br2/Br -is +1.07V. Which reaction occurs when bromine is added to an aqueous solution of iodide ions?
1. 2I –+ 2Br –→ I2+ Br2
2. I2+ 2Br –→ Br2+ 2I –
3. I2+ Br2→ 2I –+ 2Br –
4. 2I –+ Br2→ I2+ 2Br –

Answers

The reduction potential for Bromine is stronger than the one for Iodine, as seen by its larger charge. This means that Bromine can oxidize something else (by reducing itself) better than Iodine can, so Bromine gets reduced in the equation. This eliminates 1 and 2, because in these, Bromine is being oxidized (going from -1 to 0), rather than being reduced.

Number 3 doesn’t work because both Iodine and Bromine are being reduced in the equation, and that’s not how things work in the wonderful world of chemistry - one must be reduced and the other must be oxidized.

Therefore, 4 is the correct answer, as seen by the reduction of Bromine and the oxidation of Iodine.

Final answer:

When bromine is added to an aqueous solution of iodide ions, the reaction that occurs is the oxidation of iodide ions to iodine and the reduction of bromine to bromide ions, as bromine has a higher standard reduction potential and will thus be reduced. Hence, the reaction that occurs is 2I⁻ + Br₂ → I₂ + 2Br⁻.

Explanation:

To determine which reaction will occur when bromine is added to an aqueous solution of iodide ions, we can compare the standard reduction potentials of the Br₂/Br⁻ and I₂/I⁻ couples. The standard reduction potential for Br₂/Br⁻ is +1.07V, and for I₂/I⁻ it is +0.54V. Given that a higher potential indicates a greater tendency to gain electrons (undergo reduction), we can infer that Br₂ will be reduced (gain electrons) rather than I₂.

Therefore, iodide ions (I-) will be oxidized by bromine (Br₂) to form iodine (I₂) and bromide ions (Br⁻). The balanced half-reactions are:

Br₂ + 2e⁻ → 2Br− (Reduction)2I− → I₂ + 2e− (Oxidation)

Overall, the reaction that occurs is 2I⁻ + Br₂ → I₂ + 2Br⁻, which correlates to option 4 in the list provided by the student. This is because the reaction can only occur in the direction that allows bromine to be reduced since it has a higher reduction potential.

The mineral enargite is 48.41% cu, 19.02% as, and 32.57% s by mass. what is the empirical formula of enargite?

Answers

Empirical formula is the simplest ratio of whole numbers of components in a compound. 
Assuming for 100 g of the compound 
                                Cu                                 As                             S
mass                      48.41 g                          19.02 g                      32.57 g
number of moles    48.41 / 63.5 g/mol      19.02 / 75 g/mol        32.57 / 32 g/mol 
                                = 0.762 mol                = 0.2536 mol            = 1.018 mol 
divide by the least number of moles 
                               0.762 / 0.2536             0.2536 / 0.2536         1.018 / 0.2536
                               = 3.00                          = 1.00                         = 4.01
once they are rounded off 
Cu - 3
As - 1
S - 4
therefore empirical formula is Cu₃AsS₄
The empirical  formula  of enargite  is calculated as below

find the moles of each element
that is moles =% composition/molar mass

=Cu = 48.41/63.5 =0.762  moles
As = 19.02/74.9 = 0.254 moles
S =32.57/32.1 = 1.015 moles

find the moles ratio by diving  each  mole with the smallest mole( 0.254 moles)


CU =0.762/0.254 = 3
 As =0.254/0.254 =1
S= 1.015/0.254 = 4

therefore the empirical formula  =Cu3AsS4


An aqueous solution of ____ will produce a basic solution.
a. nh4clo4
b. kbr
c. nacl
d. na2co3
e. nahco3

Answers

Hydrolysis of [tex]NH_{4}ClO_{4}[/tex] is given as:

[tex]NH_{4}ClO_{4}+H_{2}O\rightleftharpoons NH_{4}OH + HClO_{4}[/tex]

Here, [tex]NH_{4}OH[/tex] is a   weak base and [tex]HClO_{4}[/tex] is a strong acid. Thus, solution is more acidic

Hydrolysis of [tex]KBr[/tex] is given as:

[tex]KBr+H_{2}O\rightleftharpoons KOH  +   HBr[/tex]

Here, [tex]KOH[/tex] is a strong base and [tex]HBr[/tex] is a strong acid.Thus, solution is neutral.

Hydrolysis of [tex]NaCl[/tex] is given as:

[tex]NaCl+H_{2}O\rightleftharpoons NaOH  + HCl[/tex]

Here, [tex]NaOH[/tex] is a strong base and [tex]HCl[/tex] is a strong acid.Thus, solution is neutral.

[tex]Na_{2}CO_{3}+2H_{2}O\rightleftharpoons  2NaOH + H_{2}CO_{3}[/tex]

Here, [tex]NaOH[/tex] is a strong base and [tex]H_{2}CO_{3}[/tex] is a weak acid.Thus, solution is basic.      

[tex]NaHCO_{3}+H_{2}O\rightleftharpoons  NaOH + H_{2}CO_{3}[/tex]

Here, [tex]NaOH[/tex] is a strong base and [tex]H_{2}CO_{3}[/tex] is a weak acid.Thus, solution is basic.        

Hence, an aqueous solution of  [tex]NaHCO_{3}[/tex] and [tex]Na_{2}CO_{3}[/tex] will produce a basic solution.





A reactant decomposes with a half-life of 137 s when its initial concentration is 0.165 m. when the initial concentration is 0.722 m, this same reactant decomposes with the same half-life of 137 s.

Answers

First you need to find the order of reaction.
Let the reaction follow a simple nth order rate law:
rate = k∙[A]ⁿ

Half-life t₁₂ initial concentration [A]₀ and rate constant k for such a reaction are related as:
t₁₂ = (2ⁿ⁻¹ - 1) / ( (n - 1)∙k∙[A]₀ⁿ⁻¹ )
except the particular case of first order reactions, i.e. n=1, in which half-life does not depend on initial concentration:
t₁₂ = ln(2)/k

Apparently your reaction is not a first order reaction. When you combine the constant factors in the relation above to a constant K, you can see that half-life of a non-first order reaction is inversely proportional to initial concentration raised to the power (n-1):
t₁₂ = K/[A]₀ⁿ⁻¹
with K=(2ⁿ⁻¹ - 1)/((n - 1)∙k)

K cancels out when you take the ratio of the two given half-lifes:
t₁₂₍₂₎ / t₁₂₍₁₎ = (K/[A]₀₍₂₎ⁿ⁻¹) / (K/[A]₀₍₁₎ⁿ⁻¹) = ([A]₀₍₁₎/[A]₀₍₂₎)ⁿ⁻¹
to find the exponent (n-1) take logarithm
ln(t₁₂₍₂₎/t₁₂₍₁₎) = ln(([A]₀₍₁₎/[A]₀₍₂₎)ⁿ⁻¹) = (n - 1)∙ln([A]₀₍₁₎/[A]₀₍₂₎)
=>
n - 1 = ln(t₁₂₍₂₎/t₁₂₍₁₎) / ln([A]₀₍₁₎/[A]₀₍₂₎)
= ln(229s / 151s) / ln(0.297M / 0.196M )
= 1.00198...
≈ 1
=>
n = 2

With known order n we can compute k from given half-life and initial concentration.
For a second order reaction half-life is given by:
t₁₂ = (2²⁻¹ - 1) / ( (2 - 1)∙k∙[A]₀²⁻¹ ) = 1/(k∙[A]₀)
Hence
k = 1/(t₁₂∙[A]₀)
= 1/(151s ∙ 0.297M)
= 2.23×10⁻² M⁻¹s⁻¹

What are the concentrations of hydrogen ion and hydroxide ion in household ammonia, an aqueous solution of nh3 that has a ph of 11.50?

Answers

Answer is: the concentrations of hydrogen ion and hydroxide ion in household ammonia are 3.16·10⁻¹² M and 3.16·10⁻³ M, respectively.
pH(NH₃) = 11.50.
pH = -log[H⁺].
[H⁺] = 10∧(-pH).
[H⁺] = 10∧(-11.5).
[H⁺] = 3.16·10⁻¹² M.
[H⁺] · [OH⁻] = 10⁻¹⁴ M².
[OH⁻] = 10⁻¹⁴ M² ÷ 3.16·10⁻¹² M.
[OH⁻] = 0.00316 M = 3.16·10⁻³ M.

Note: hydrogen ion concentration = 3.16 x 10⁻¹² M

          hydroxide ion concentration = 3.16 x 10⁻³ M

          pH NH₃ = 11.50

Asked: concentrations of hydrogen ions and hydroxide ions in household ammonia?

Answer: pH (NH₃) = 11.50.

              pH = -log [H⁺]

              [H⁺] = 10∧ (-pH)

              [H⁺] = 10∧ (-11.5)

               [H⁺] = 3.16 · 10⁻¹² M

              [H⁺] x [OH⁻] = 10⁻¹⁴ M²

              [OH⁻] = 10⁻¹⁴ M² ÷ 3.16 x 10⁻¹² M

               [OH⁻] = 0.00316 M = 3.16 x 10⁻³ M

Thus, the concentration of hydrogen ions and hydroxide ions in household ammonia is 3.16 · 10⁻³M

Further Explanation

In chemistry, concentration is a measure that describes the amount of substance in a mixture divided by the total volume of the mixture. There are four kinds of quantitative descriptions of concentration, namely mass concentration, molar concentration, total concentration, and volume concentration. The term concentration can be applied to all types of mixtures, but it is most often used to describe the amount of solute in the solution. Molar concentrations have variations such as normal concentration and osmotic concentration.

Solution Concentration

Concentration is a way to express the quantitative relationship between solute and solvent. Expressing the concentration of the solution there are several types, including:

1. MOL FRACTION

The mole fraction is the ratio between the number of moles of a component with the number of moles of all components contained in a solution.

The mole fraction is denoted by X.

2. PERCENT WEIGHT

Percent weight states the gram weight of the solute in 100 grams of solution.

3. MOLALITY (m)

Molality states the mole of solute in 1000 grams of solvent.

4. MOLARITY (M)

Molarity states the number of moles of solute in 1 liter of solution.

5. NORMALITY (N)

Normality represents the number of moles equivalent of solute in 1 liter of solution. For acids, 1 mole is equivalent to 1 mole of H + ions. For bases, 1 mole is equivalent to 1 mole of OH- ion.

Between Normality and Molarity there is a relationship:

N = M x valence

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At 7 degrees Celsius the volume of gas is 49 liters. At the same pressure its volume is 74 mL at what temperature

Answers

Charle's law gives the relationship between volume and temperature of gas.
It states that at constant pressure, volume of gas is directly proportional to temperature of gas.
V/T = k
where V - volume , T - temperature and k- constant 
[tex] \frac{V1}{T1} = \frac{V2}{T2} [/tex]
parameters for the first instance are on the left side of the equation and parameters for the second instance are on the right side of the equation 
T1 - 7 °C + 273 = 280 K
substituting these values in the equation 
[tex] \frac{49 mL}{280K} = \frac{74 mL}{T} [/tex]
T = 423 K
temperature in Celcius scale - 423 K - 273 = 150 °C

A compound is found to contain 49.5% carbon, 5.19% hydrogen, 16.5% oxygen, and 28.9% nitrogen. its molecular mass is 194.2 g/mol. what is its empirical formula? what is its molecular formula? explain what each of these formulas tells us about the molecule. (lesson 6)

Answers

28.9 uno mum mum mum  yen tab rf  etc wax ohm yen rev wax tab yen umm ism ol, edc 

What concentration of the lead ion, pb2+, must be exceeded to precipitate pbf2 from a solution that is 1.00×10−2 m in the fluoride ion, f−? ksp for lead(ii) fluoride is 3.3×10−8 ?

Answers

Answer is: concentration of Pb²⁺ must be exceeded is 3.3·10⁻⁴ M.

Chemical reaction : Pb²⁺(aq) + 2F⁻(aq) → PbF₂(s).

Ksp(PbF₂) = 3.3·10⁻⁸.
c(F⁻) = 0.01 M.
Ksp(PbF₂) = c(Pb²⁺) · c(F⁻)².
c(Pb²⁺) = Ksp(PbF₂) ÷ c(Cl⁻)².
c(Pb²⁺) = 3.3·10⁻⁸ ÷ (0.01 M)².
c(Pb²⁺) = 0.000000033 M³ ÷ 0.0001 M².
c(Pb²⁺) = 0.00033 M = 3.3·10⁻⁴ M.

The concentration of Pb²⁺ must be exceeded is 3.3 × 10⁻⁴ m.

Ksp value of PbF₂ = 3.3 × 10⁻⁸

Concentration of fluoride ion = 1.00 × 10⁻²

It is required to calculate the concentration of lead ion.

What is a solubility product?

The solubility product constant, Ksp​, is the equilibrium constant for a solid substance dissolving in an aqueous solution.

A chemical reaction between lead ion and fluoride ion occurs as

Chemical reaction :

Pb²⁺(aq) + 2F⁻(aq) → PbF₂(s).

Ksp(PbF₂) = 3.3 × 10⁻⁸

Ksp(PbF₂) = c(Pb²⁺) · c(F⁻)²

c(Pb²⁺) = Ksp(PbF₂) ÷ c(Cl⁻)²

c(Pb²⁺) = 3.3×10⁻⁸ ÷ (0.01 m)²

c(Pb²⁺) = 0.000000033 m³ ÷ 0.0001 m²

c(Pb²⁺) = 0.00033 m = 3.3·10⁻⁴ m

Hence, the concentration of Pb²⁺ must be exceeded is 3.3 × 10⁻⁴ m.

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What type of bond would form between two atoms of phosphorus?
A. Triple covalent bond
B. Single ionic bond
C. Double covalent bond
D. Single covalent bond

Answers

Ans: A. Triple covalent bond.

Hope this helps!

Answer: Option (A) is the correct answer.

Explanation:

Non-metals are the substances which tend to gain electrons from a donor atom in order to attain stability.

For example, atomic number of phosphorous is 15 and its electronic distribution is 2, 8, 5.

As it contains 5 valence electrons electrons therefore, it needs 3 more electrons in order to attain stability.

Hence, when one phosphorous atom combines with another phosphorous atom then it results in sharing of electrons. So, there will be formation a triple bond between the two phosphorous atoms.

Also, there will be one lone pair of electron on each phosphorous atom.

Thus, we can conclude that triple covalent bond would form between two atoms of phosphorus.

How many helium atoms are in a 12.0 g sample?

Answers

Answer: The number of helium atoms present are [tex]18.066\times 10^{23}[/tex]

Explanation:

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

Given mass of helium = 12.0 g

Molar mass of helium = 4 g/mol

Putting values in above equation, we get:

[tex]\text{Moles of helium}=\frac{12.0g}{4g/mol}=3mol[/tex]

According to mole concept:

1 mole of an element contains [tex]6.022\time 10^{23}[/tex]  number of atoms.

So, 3 moles of helium will contain = [tex]3\times 6.022\times 10^{23}=18.066\times 10^{23}[/tex] number of atoms.

Hence, the number of helium atoms present are [tex]18.066\times 10^{23}[/tex]

Final answer:

To find the number of helium atoms in a 12.0 g sample, convert the grams into moles using the molar mass of helium (4 g/mol), then multiply the number of moles by Avogadro's number (6.022 x 10^23). The result is approximately 1.807 x 10^24 helium atoms.

Explanation:

To calculate the number of helium atoms in a 12.0 g sample, you need to use Avogadro's number, which states that one mole of any substance contains 6.022 x 10^23 particles (atoms, molecules, ions, etc.). Molar mass of helium is approximately 4 g/mol. So first, we need to convert the number of grams into moles.

12.0 g / 4 g/mol = 3 moles of helium.

To find out how many atoms this is, we multiply the number of moles by Avogadro's number:

3 moles * 6.022 x 10^23 atoms/mole = 1.807 x 10^24 helium atoms.

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how many molecules of dinitrogen pentoxide are in 1.39 moles of dinitrogen pentoxide

Answers

1 mole of any substance has [tex]6.02*10^{23} particles. So, 1.39 mol N_{2}O_{5} have [/tex]

[tex]1.39 mol * \frac{6.02*10^{23}}{1 mol} =8.37*10^{23} molecules[/tex]

Explanation:

According to Avogadro's number, it is known that there are [tex]6.023 \times 10^{23}[/tex] atoms present in 1 mole of a substance.

Therefore, molecules or atoms present in 1.39 moles will be as follows.

             No. of atoms = no. of moles × Avogadro's number

                                    = [tex]1.39 moles \times 6.023 \times 10^{23}\text{atoms/mol}[/tex]

                                    = [tex]8.37 \times 10^{23}[/tex] atoms

Thus, we can conclude that there are [tex]8.37 \times 10^{23}[/tex] atoms of dinitrogen pentoxide in 1.39 moles.

One of these substances is a liquid at room temperature. which one? one of these substances is a liquid at room temperature. which one? sih4 co2 nh2oh cf4

Answers

Those compounds are said to be liquids at room temperature whose melting point is less than 25 °C and boiling point is greater than 25 °C.

Silane:  (SiH₄)

                      Melting Point  =  -185 °C

                      Boiling Point  =  -112 °C

Carbon Dioxide:  (CO)

                      Melting Point  =  -56.6 °C (Triple Point)

Hydroxylamine:  (NH₂OH)

                      Melting Point  =  33 °C

                      Boiling Point  =  58 °C

Tetrafluoromethane:  (CF₄)

                      Melting Point  =  -183.6 °C

                      Boiling Point  =  -127.8 °C

Result:
           Hence, it can be concluded that none of the given compound is in liquid state at Room temperature. But, approximately speaking we can conclude that comparatively if the day is hot then Hydroxyl Amine (NH₂OH) will exist in liquid state. :)
Final answer:

Among the substances SiH4, CO2, NH2OH, and CF4, it is Hydroxylamine (NH2OH) which is the liquid at room temperature due to its hydrogen bonding.

Explanation:

Among the substances SiH4, CO2, NH2OH, and CF4, it is NH2OH (Hydroxylamine) which is a liquid at room temperature. This is due to the variations in the intermolecular forces among these substances:

SiH4(Silane) and CF4(Tetrafluoromethane) are gases at room temperature because their molecules are held together by weak Van der Waals' forces which require less thermal energy to overcome. CO2 (Carbon Dioxide) is well known to be a gas at room temperature and atmospheric pressure. NH2OH(Hydroxylamine) on the other hand, exhibits hydrogen bonding (a strong type of dipole-dipole interaction). This bonding causes an increased boiling point, making it a liquid at room temperature.

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According to the balanced chemical equation, how many atoms of silver will be produced from combining 100 g of copper with 200 g of silver nitrate?

Answers

The balance chemical equation is as follow,

                    Cu  +  2 AgNO₃    →    Cu(NO₃)₂  +  2 Ag

First calculate for 200 g of AgNO₃,
According to equation,

              339.74 g (2 mole) AgNO₃ produced  =  215.7 g (2 mole) of Ag
So,
                         200 g of AgNO₃ will produce  =  X g of Ag

Solving for X,
                              X  =  (200 g × 215.7 g) ÷ 339.74 g

                              X  =  126.97 g Ag

Next calculate for 100 g of Cu,
According to equation,

              63.52 g (1 mole) Cu produced  =  215.7 g (2 mole) of Ag
So,
                       100 g of Cu will produce  =  X g of Ag

Solving for X,
                              X  =  (100 g × 215.7 g) ÷ 63.52 g

                              X  =  339.57 g Ag
Result:
          As 200 g of AgNO₃ is producing Ag in less amount (126.97 g) as compared to 100 g of Cu, it means that AgNO₃ is in limited amount and will consume first till the production of 126.97 g of Ag. So, the maximum amount of Ag production is 126.97 g.

Final answer:

The balanced chemical equation reveals that 100g of copper reacting with 200g of silver nitrate yields 6.022 × 10^23 atoms of silver.

Explanation:

The balanced chemical equation for the reaction between copper (Cu) and silver nitrate (AgNO3) is:

Cu (s) + 2AgNO₃ (aq) → Cu(NO₃)² (aq) + 2Ag (s)

From the equation, when 100g of copper reacts with 200g of silver nitrate, it will produce 6.022 × 10²³ atoms of silver.

How much heat is evolved in converting 1.00 mol of steam at 155.0 ∘c to ice at -50.0 ∘c? the heat capacity of steam is 2.01 j/(g⋅∘c) and of ice is 2.09 j/(g⋅∘c)?

Answers

When the specific heat capacity of the water is 4.18 J/g.°C so, we are going to use this formula to get the heat for cooling three  phases changes from steam to liquid and from liquid to ice (solid) :

when Q = M*C*ΔT 

Q is the heat in J

and M is the mass in gram = 1 mol H2O * 18 g/mol(molar mass) = 18 g

C is the specific heat J/g.°C

ΔT is the change in temperature

Q = Mw *[ ( Csteam * ΔTsteam)+(Cw*ΔTw) + (Cice  * ΔT ice)]

    = 18 g * [(2.01 * (155-100°C)) + (4.18 * (100-0°C)) + (2.09 * (0 - 55 °C))]

∴Q = 7444.8 J

and when we know that the heat of fusion for water = 334J/g

and heat of vaporization for water =  2260J/g


∴Q for the two phases changes = M * (2260+334) 

                                                      = 18 * (2260+334)

                                                      = 46692 J 

∴ Q total = 7444.8 + 46692 = 54136.8 J

Jaina just got home from a difficult workout. She is complaining of muscle soreness and cramps. Which waste product of fermentation caused the soreness and cramps?

Answers

The answer is lactic acid/lactate. This is caused by anaerobic respiration in muscles especially during strenuous physical activity due to low oxygen supply to muscles in respect to the demand. When there is sufficient oxygen in the muscles, pyruvate is broken down aerobically in the Kreb’s cycle. However, it is converted to lactate in the anaerobic pathway. Lactic-acidosis occurs when lactic acid accumulates in tissues and slows down metabolic pathways




Which of the following would be expected to form ionic solutions in water?

CO2
C
NaI
CCl4
O2

Answers

I believe your best answer would be sodium iodide. (Nal) 
Answer;

NaI-Sodium Iodide

Explanation;Ionic solutions are solutions that are formed when ionic compounds dissolve in a solvent such as a water.Ionic compounds are compounds that are formed as a result of transfer of electrons between non metal atoms and metal atoms, thus forming an ionic bond. When an ionic compound such as sodium iodide dissolves in water, it dissociates into cations, sodium ions, and anions, iodide ions.

A certain compound is made up of one carbon (c) atom, two bromine (br) atoms, and one oxygen (o) atom. what is the chemical formula of this compound

Answers

Answer:
           Chemical Formula  =  COBr₂

           Structural Formula  =  Attached Below

           IUPAC Name  =  Carbonic Dibromide

           Common Name  =  Bromophosgene

As we know Carbon has the tendency to form four covalent bonds, Oxygen can form two covalent bonds and Bromine can form a single bond. Keeping this in mind we can say that in given compound carbon is forming two single bonds with two bromine atoms and a double bond with oxygen atom. Therefore, the valencies of all elements in the given compound are satisfied and completed.

Answer:

The chemical formula of the compound will be COBr2.

Further details:

The chemical formula of the compound is COBr2.

• The IUPAC name is Carbonic Dibromide

• The common name of the compound is Bromophosgene

As we know Carbon has the propensity to form four covalent bonds, Oxygen can form two covalent bonds and Bromine can form a single bond. Keeping this in mind we can say that in given compound carbon are making two single bonds with two bromine atoms and a double bond with oxygen atom. So, the valencies of all essentials in the given compound are fulfilled and accomplished.

Formation of Carbon dibromide:

Carbonyl bromide is made when carbon tetrabromide is melted and concentrated sulfuric acid is added.

In compare to phosgene, carbonyl bromide cannot be twisted efficiently from carbon monoxide and bromine. A complete alteration is not possible due to thermodynamic causes. Additionally, the reaction

                            CO + Br2 ⇌ COBr2

Answer details:

Subject: Chemistry

Level: College

Keywords:

Carbon dibromideFormation of carbon dibromideCarbon Bromine Oxygen

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Which of the following statements is true?
A. Delocalized electrons conduct electricity poorly.
B. There is a strong attraction between positively charged metal ions and the sea of electrons.
C. Metals with a delocalized electron sea break apart when struck instead of bending.
D. Metals have high melting points and low boiling points.

Answers

B. There is a strong attraction between positively charged metal ions and the sea of electrons.  - true

Answer:  B. There is a strong attraction between positively charged metal ions and the sea of electrons.

Explanation:  Delocalized electrons conduct electricity with high potentil as the electrons are not localized in on place. Thus statement A is wrong.

Metals with a delocalized electron sea doesnot break apart when struck instaed of bending. Thus statement C is also wrong.

Metals donot have high melting point rather they have low melting point.

Statement B is true as there is a strong attraction beween positively charged metal ions and the sea of electrons.

Sodium is an atom represented as na+. what does the "+" represent?

Answers

Final answer:

The '+' in Na+ represents a positive charge which indicates that the sodium atom has lost one electron and has become a sodium cation with more protons than electrons.

Explanation:

The "+" in a sodium atom represented as Na+ signifies that the atom has lost an electron and, therefore, has a net positive charge. In its neutral state, a sodium atom has 11 protons and 11 electrons, giving it no overall charge. However, when a sodium atom loses an electron, as in the case of the sodium cation (Na+), it then has one more proton (11) than electrons (10), resulting in an overall positive charge, which is indicated by the plus sign. This positively charged sodium is referred to as a sodium cation.

Sodium cations are common in many chemical reactions and play significant roles in biological systems, such as in nerve impulse transmission and muscle contraction. The propensity for sodium to lose an electron and form a Na+ cation is due to the energy consideration that it's easier for sodium to lose one electron from its outermost shell than to gain seven more in order to fill it.

What is formed from 2 pieces of different metals stuck together lengthwise?

Answers

Final answer:

An alloy, such as brass or bronze, is formed when two pieces of different metals are stuck together lengthwise. These materials combine the properties of the constituent metals, often resulting in superior characteristics.

Explanation:

When two pieces of different metals are stuck together lengthwise, the resulting material is known as an alloy. An alloy is a mixture composed of two or more elements, with at least one being a metal. Some common examples of alloys include brass (an alloy of copper and zinc) and bronze (an alloy of copper and tin). These combinations of metals result in a material with properties that are superior to the pure metals themselves. For example, bronze, first used around 2400 B.C., is harder and more durable than either of its constituent metals, copper and tin.

Final answer:

The material formed from sticking two different metals together lengthwise is called an alloy. Alloys like bronze and brass are mixtures of two or more elements that possess improved properties compared to the pure component metals.

Explanation:

When two pieces of different metals are stuck together lengthwise, the material formed is known as an alloy. An alloy is a mixture composed of two or more elements, at least one of which is a metal. Alloys are designed to have properties superior to those of the pure metals from which they are made. For example, bronze is a well-known alloy consisting mainly of copper and tin. The creation of alloys like bronze and brass, which is an alloy of copper and zinc, exemplifies how metals can be combined to achieve desired physical and chemical properties for various applications, from tools and weapons to musical instruments.

Balance the reactions which form ions. Choose "blank" if no other coefficient is needed. Writing the symbol implies "1."
1) (NH4)2CO3 ____ NH4 +_____ + CO3 -2
2) PbI2 _____ Pb+2 +______ I+1
3) (NH4)3PO4 ______ NH4 + _____ + PO4 +3

Answers

Following are the Balanced Reactions,

Reaction 1:


                            (NH₄)₂CO₃     →    2 NH₄⁺  +  CO3⁻²

Reaction 2:

                                     PbI₂    →    Pb⁺²  +  2 I⁻¹

Reaction 3:

                              (NH₂)₃PO₄     →     3 NH₄⁺  +   PO₄⁻³
The answers are the following:
1) (NH4)2CO3 2 NH4 +→ + CO3 -2
2) PbI2 →1 Pb+2 +2 I+1
3) (NH4)3PO4 →3NH4 + 3 + PO4 +

What volume of chlorine is required to produce 25.4?

Answers

from this reaction equation:

Cu + Cl2 → CuCl2

so 1 mol CuCl2 will produce from 1 mol Cl2

when the moles of CuCl2 = mass / molar mass 

                                            = 25.4 g / 134.45 g/mol

                                            = 0.189 moles 

∴0.189 moles of CuCl2 will produce from 0.189 moles Cl2

∴ Volume of 0.189 moles of Cl2 is :

 V = nRT/P

when n is the number of moles = 0.189 moles

R is ideal gas constant = 0.0821 

T temperature in Kelvin = 18 + 273 = 291 K

P is the pressure = 2.13 atm

by substitution:

∴ V = 0.189 * 0.0821 * 291 / 2.13

    = 2.12 L

A 90.00 mL solution of NaCl and ethyl alcohol has 7.83 g of salt dissolved in the alcohol. Calculate the molar concentration of the solution. Remember to use significant digit rules.

Answers

The  molar  concentration  of the solution  is calculated as  follows

find the moles of NaCl used  to  make the solution

moles =  mass/molar  mass
mass =7.83  g
molar  mass =58.5  g/mol
moles = 7.83 g/ 58.5 g/mol = 0.134 moles

molarity (  concentration  in mol/l) =  number  of moles/volume  in  liters

volume  in liters =  90ml/1000 =0.09  liters

molarity  is  therefore = 0.134  moles/0.09 L =1.49   M


Answer:

The  molar  concentration  of the solution  is calculated as  follows

find the moles of NaCl used  to  make the solution

moles =  mass/molar  mass

mass =7.83  g

molar  mass =58.5  g/mol

moles = 7.83 g/ 58.5 g/mol = 0.134 moles

molarity (  concentration  in mol/l) =  number  of moles/volume  in  liters

volume  in liters =  90ml/1000 =0.09  liters

molarity  is  therefore = 0.134  moles/0.09 L =1.49   M

Explanation:

How much energy is required to vaporize 185 g of butane at its boiling point? the heat of vaporization for butane is 23.1 kj/mol?

Answers

Answer is: 73.52 kJ of energy is required to vaporize butane.
m(C₄H₁₀) = 185 g.
n(C₄H₁₀) = m(C₄H₁₀) ÷ M(C₄H₁₀).
n(C₄H₁₀) = 185 g ÷ 58.12 g/mol.
n(C₄H₁₀) = 3.18 mol; amount of butane.
Hvap = 23.1 kJ/mol; the heat of vaporization for butane.
Q = Hvap · n(C₄H₁₀).
Q = 23.1 kJ/mol · 3.18 mol; energy.
Q = 73.52 kJ.

Final answer:

Approximately 73.5 kJ of energy is required to vaporize 185 g of butane at its boiling point.

Explanation:

The amount of energy required to vaporize a substance can be calculated using the formula Q = n * ΔHvap, where Q is the amount of energy required, n is the number of moles of the substance, and ΔHvap is the heat of vaporization. To calculate the number of moles of butane, we divide the mass of butane by its molar mass. Using the given heat of vaporization for butane (23.1 kJ/mol), we can calculate the amount of energy required. First, we calculate the number of moles of butane:

n = 185 g / 58.12 g/mol = 3.18 mol

Next, we calculate the amount of energy required:

Q = 3.18 mol * 23.1 kJ/mol ≈ 73.5 kJ

Therefore, approximately 73.5 kJ of energy is required to vaporize 185 g of butane at its boiling point.

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Based on conductivity values, classify the compounds in each set of solutions as molecular, ionic, or acids. what is the level of dissociation (complete, varying, or none) of each set

Answers

Electrolytic conductivity is measure of ability of solution to conduct electricity. It is also as specific conductance. Electrolytic conductivity is different as compared to electrical conductivity. Electrolytic conductivity increase with temperature, while electrical conductivity decreases with increasing temperature. Further, electrolytic conductivity occurs because of presence of ions in solutions, while electrical conductivity occurs due to presence of valence electrons.

In current context, number of ions present in solutions depends on dissociation constant values. For molecules, which donot under dissociation in solvent, no electrolytic conductivity will be observed. Generally, ionic compounds undergo complete dissociation in solution, hence they will display maximum conductance. In case of acids, conductivity values will vary depends upon dissociation constant values. Weak acid are characterized by lower dissociation constant values, hence they have lower conductivity as compared to strong acids.  

Calculate the equilibrium constant for the reaction between fe2+(aq) and zn(s) under standard conditions at 25∘c.

Answers

Final answer:

The equilibrium constant for the reaction between Fe2+(aq) and Zn(s) under standard conditions at 25∘C is equal to 1.

Explanation:

The equilibrium constant for the reaction between Fe2+(aq) and Zn(s) under standard conditions at 25∘C can be calculated by using the formula:

Kc = ([Fe2+]/[Zn])

Since Fe2+ is an aqueous ion and Zn is a solid, their concentrations are not included in the equation. Therefore, the equilibrium constant is equal to 1.

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The equilibrium constant for the reaction between Fe²+(aq) and Zn(s) at 25°C is approximately 7.06 x 10¹⁰.

Step-by-Step Explanation:

1. Write the overall balanced redox reaction:

Fe²⁺(aq) + Zn(s) → Fe(s) + Zn²⁺(aq)

2. Determine the standard reduction potentials (E°) for each half-reaction:

Fe²⁺(aq) + 2e⁻ → Fe(s), E° = -0.44 V Zn²⁺(aq) + 2e⁻ → Zn(s), E° = -0.76 V

3. Calculate the standard cell potential (E°cell):

E°cell = E°cathode - E°anode = (-0.44 V) - (-0.76 V) = 0.32 V

4. Use the Nernst equation to relate E°cell to the equilibrium constant (K):

E°cell = (RT/nF) * ln(K)

Where R = 8.314 J/(mol·K), T = 298 K, n = 2 (number of electrons transferred), F = 96485 C/mol.

5. Rearrange and solve for K:

0.32 V = (8.314 J/(mol·K) * 298 K / (2 * 96485 C/mol)) * ln(K) 2477.172 * ln(K) = 61870.4 ln(K) ≈ 24.98K = [tex]e^{24.98[/tex] ≈ 7.06 x 10¹⁰

Thus, the value of equilibrium constant comes out to be 7.06 x 10¹⁰

___ + ___ = H2O + LiBrO3 Complete and balance the equation representing neutralization reaction.

Answers

when an acid reacts with a base its called a neutralisation reaction and products of the reaction are salt and water.
this is called neutralisation as hydrogen ions in acid react with hydroxide ions in base and form water. 
the cation in base reacts with anion in acid and forms a salt.
In the reaction given the salt formed is LiBrO₃
in the salt formed the cation is Li⁺ and anion is BrO₃⁻
therefore base is LiOH and acid is HBrO₃
neutralisation reaction is therefore 
LiOH + HBrO₃ ---> LiBrO₃ + H₂O
Final answer:

The complete and balanced neutralization reaction is HBrO₃(aq) + LiOH(aq) → H₂O(l) + LiBrO₃(aq), where hydrobromic acid reacts with lithium hydroxide to produce water and lithium bromate.

Explanation:

The student's question pertains to completing and balancing a chemical equation for a neutralization reaction. In a neutralization reaction, an acid and a base react to form water and a salt. To complete and balance the given equation ___ + ___ = H₂O + LiBrO₃, we need to identify the acid and the base that will produce lithium bromate (LiBrO₃) and water.

The balanced equation for this reaction is:

HBrO₃(aq) + LiOH(aq) → H₂O(l) + LiBrO3(aq)

Here, hydrobromic acid (HBrO₃) reacts with lithium hydroxide (LiOH), producing water (H₂O) and lithium bromate (LiBrO₃). This equation is balanced as written, with one mole of HBrO₃ reacting with one mole of LiOH to produce one mole of water and one mole of LiBrO₃.

List the following compounds in decreasing electronegativity difference. cl2 hcl nacl

Answers

Based on Pauling Scale, electro negativity of Cl = 3.2, Na = 0.9 and H = 2.1

Thus, Electronegativity difference  in [tex] Cl_{2} [/tex] = 3.2 -3.2 = 0
Electronegativity difference  in NaCl = 3.2-0.9 = 2.3
Similarly, Electronegativity difference  in HCl = 3.2 - 2.1 = 1.1

Thus, among the listed molecules following is the decreasing order of electronegativity difference: NaCl> HCl > [tex] Cl_{2} [/tex]
Final answer:

The decreasing electronegativity difference in the compounds is NaCl > HCl > Cl2. NaCl has the highest electronegativity difference, forming an ionic compound, then HCl forms a polar covalent bond, and Cl2, made of two identical atoms, has no electronegativity difference.

Explanation:

The compounds Cl2, HCl, and NaCl possess varying degrees of electronegativity difference depending on the atoms involved. Electronegativity is the ability of an atom to attract shared electrons in a bond. In NaCl (sodium chloride), the electronegativity difference is very high as it consists of a metal (sodium) and a non-metal (chlorine).

This forms an ionic compound, which is generally formed when there is a high electronegativity difference. On the other hand, Cl2 (chlorine gas) possesses no electronegativity difference as it is a molecule composed of two identical atoms. Finally, HCl (hydrogen chloride) has a considerable but not extreme electronegativity difference because it consists of two non-metals. This forms a polar covalent bond.

In summary, the decreasing electronegativity difference would be: NaCl > HCl > Cl2.

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which element does not contain neutrons

iron
carbon
oxygen
hydrogen

Answers

The correct answer is:  [D]:  " hydrogen " .
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