A solution is made by mixing 48.0 ml of ethanol, c2h6o, and 52.0 ml of water. assuming ideal behavior, what is the vapor pressure of the solution at 20 °c?

Answers

Answer 1
The mass of ethanol = 0.789 g/ml (48) = 37.872 g
Number of moles of ethanol = 37.872 g/ 46g/mol = 0.8233 moles
Mass of water = 52 x 1g/ml = 52 g
Number of moles of water = 52 / 18 g/mol = 2.889 moles of water
We can calculate the mole fraction;
Mole fraction of ethanol =  0.8233/3.712 = 0.2218
Mole fraction of water  = 2.889/3.712= 0.7782
But P°(1) Vapor pressure of pure water = 17.5 torr
while P°(2) vapor pressure of pure ethanol = 43.9 torr
P(1) = 0.7782 × 17.5 = 13.6185
P(2) =0.2218 ×43.9 = 9.7370
Therefore, the P(s) = 23.3555

Answer 2

The question is incomplete, here is the complete question:

A solution is made by mixing 45.0 mL of ethanol, [tex]C_2H_6O[/tex], and 55.0 mL of water. Assuming ideal behavior, what is the vapor pressure of the solution at 20 °C?

Constants @ 20°C:  

ethanol = 0.789 g/mL (Density) & 43.9 Torr (Vapor Pressure)

water = 0.998 g/mL (Density) & 17.5 Torr (Vapor Pressure)

Answer: The vapor pressure of the solution at 20°C is 23.4 Torr

Explanation:

To calculate the mass of substance, we use the equation:

[tex]\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}[/tex]     ......(1)

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]     .....(2)

Mole fraction of a substance is given by:

[tex]\chi_A=\frac{n_A}{n_A+n_B}[/tex]     ......(3)

For ethanol:

Density of ethanol = 0.789 g/mL

Volume of ethanol = 48.0 mL

Putting values in equation 1, we get:

[tex]0.789g/mL=\frac{\text{Mass of ethanol}}{48.0mL}\\\\\text{Mass of ethanol}=(0.789g/mL\times 48.0mL)=37.9g[/tex]

Given mass of ethanol = 37.9 g

Molar mass of ethanol = 46 g/mol

Putting values in equation 2, we get:

[tex]\text{Moles of ethanol}=\frac{37.9g}{46g/mol}=0.824mol[/tex]

For water:

Density of water = 0.998 g/mL

Volume of water = 52.0 mL

Putting values in equation 1, we get:

[tex]0.998g/mL=\frac{\text{Mass of water}}{52.0mL}\\\\\text{Mass of water}=(0.998g/mL\times 52.0mL)=51.9g[/tex]

Given mass of water = 51.9 g

Molar mass of water = 18 g/mol

Putting values in equation 2, we get:

[tex]\text{Moles of water}=\frac{51.9g}{18g/mol}=2.88mol[/tex]

Calculating the mole fractions by using equation 3:

Mole fraction of ethanol, [tex]\chi_{ethanol}=\frac{n_{ethanol}}{n_{ethanol}+n_{water}}=\frac{0.824}{0.824+2.88}=0.222[/tex]

Mole fraction of water, [tex]\chi_{water}=\frac{n_{water}}{n_{ethanol}+n_{water}}=\frac{2.88}{0.824+2.88}=0.778[/tex]

To calculate the total pressure of the mixture of the gases, we use the equation given by Raoult's law, which is:

[tex]p_T=\sum_{i=1}^n(p_{i}\times \chi_i)[/tex]

[tex]p_T=(p_{ethanol}\times \chi_{ethanol})+(p_{water}\times \chi_{water})[/tex]

Putting values in above equation, we get:

[tex]p_T=(43.9\times 0.222)+(17.5\times 0.778)\\\\p_T=23.4Torr[/tex]

Hence, the vapor pressure of the solution at 20°C is 23.4 Torr


Related Questions

Explain, in detail, how you convert grams of one substance to grams of something else. Be specific and include each step

Answers

I will present a simple reaction so we can do this conversion:

2H₂ + O₂ → 2H₂O

We will assume we have 32 g of O₂ and we want to find the amount of water, assuming this reaction goes to completion. We must first convert the initial mass to moles, which we do using the molar mass in units of g/mol. The molar mass of O₂ is 32 g/mol.

32 g O₂ ÷ 32 g/mol = 1 mole O₂.

Now that we have moles of oxygen, we use the molar coefficients to find the ratio of water molecules to oxygen molecules. We can see there are 2 moles of water for every 1 mole of oxygen.

1 moles O₂ x (2 mol H₂O/ 1 mol O₂) = 2 moles H₂O

Now that we have the moles of water, we can convert this amount into grams using the molar mass of water, which is 18 g/mol.

2 moles H₂O x 18 g/mol = 36 g H₂O

Now we have successfully converted the mass of one molecule to the mass of another.

If the Sun were much smaller than its current size, what effect would this have on eclipses?

Answers

Total solar eclipses would be more common, because it would be easier for the moon to cover it, which is a solar eclipse.

The reaction that takes place when iron metal combines with aqueous hydrochloric acid.

Answers

The reaction gives out a yellow showery sparks and produces a black solid. Iron reacts with dilute hydrocloric acid to give iron chloride and hydrogen gas.

2Fe+2Hcl3 = 2FeCl3+H2

An electric current can be conducted by _____. a sugar solution rubbing alcohol methane gas a salt solution

Answers

The answer is salt water.

Salt water can conduct electricity or we can say that an electric current is conducted by salt water as salt water is a good conductor of electricity when salt that is sodium chloride or NaCl is dissolved in water , positively charged sodium (Na⁺) and negatively charged chlorine(Cl⁻) molecules are set apart by the water molecule so that they can float easily and freely. We can define the conductivity of a substance as the mobility or movement of ions. So as in water, sodium and chlorine are set apart and can move freely so it become a electrolyte that can conduct electricity.

An electric current can be conducted by  [tex]\boxed{\text{a salt solution}}[/tex].

Further Explanation:

Electric current:

The movement of charge carriers (electrons or protons) or ions is termed as electric current. In other words, rate of flow of electric charge through a point. SI unit of electric current is Ampere (A).

On the basis of different abilities of substances to conduct electric current, these can be classified as follows:

Conductors:

These materials allow smooth flow of charge carriers without any resistance in their movement and therefore these conduct heat and electricity.

Insulators:

These materials allow resistance to flow of electric charge carriers and therefore act as bad conductors of heat and electricity.

Semiconductors:

These allow movement of electric charge carriers under certain conditions. These have electric conductivity less than that of conductors but more than insulators.

Sugar solution cannot produce any ions in solution. Since no charge carriers are present in sugar solution, it cannot conduct electric current.

Rubbing alcohol does not contain free ions in it and therefore it cannot conduct electric current.

Methane gas is covalent in nature and does not have any free ions in it so it cannot conduct electric current.

Salt solution is nothing but solution of NaCl in water. NaCl is ionic compound so ions are present in salt solution and therefore it conducts electric current.

Therefore electric current can only be conducted by salt solution.

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Answer Details:

Grade: High School

Subject: Chemistry

Chapter: Metals and non-metals

Keywords: sugar solution, rubbing alcohol, methane gas, salt solution, electric current, electric charge carriers, conductors, insulators, semiconductors.

A reaction requires 22.4l of at stp. You have 32.0l of gas at 398k and 105.6 kpa. Will you have enough gas to carry out the reaction? True or false

Answers

Answer: FALSE:

Explanation:

A reaction requires 22.4l of at STP. You have 32.0l of gas at 398k and 105.6 kpa.

1) STP stands for standard temperature and pressure.

2) Standard temperature is 0°C or 273.15 K

3) Standard pressure is 1 atm or 1013.25 kPa

4) use the ideal gas equation for both contidions

pV = n RT

=> n * R = pV /T

at STP n * R = 1031.25 kPa * 22.4 liter / 273.15 K = 84.5

at T = 398 K, p = 105.6 kPa, and V = 3.2.0 liter:

n * R = 105.6 kPa * 32.0 liter / 398 K = 8.49

Since R is a constant (the Universal Gases Constant), it is evident that the number of moles in the 32.0 liter of gas, at T = 398 K and P = 105.6 kPa is less than the number of moles of the 22.4 liter gas at STP.

There is not enough gas to carry out the reaction.

To determine if you have enough gas to carry out a reaction, compare the gas volume at the given conditions to 22.4L at STP.

Whether you have enough gas to carry out the reaction can be determined by comparing the known volume at STP to the volume you have at the given conditions of 398K and 105.6 kPa.

If you have 32.0L of gas at 398K and 105.6 kPa, you need to calculate the volume that gas would occupy at STP using the ideal gas law and compare it to 22.4L, which is the volume needed for the reaction at STP.

If the volume at STP is greater than 22.4L, then you have enough gas to carry out the reaction. Otherwise, you do not have sufficient gas volume.

How many liters of carbon dioxide will be formed from the decomposition of 14.1g of calcium carbonate (at stp)?

Answers

Firstly,  according to Ideal Gas Law the volume of 1 mole of a gas at Standard Temperature and Pressure (STP) is 22.4 [tex] dm^{3} [/tex], ie the value of the molar volume (Vm) is 22.4 [tex] dm^{3} [/tex]/mol.


[tex]CaCO_{3} = CaO + CO_{2} [/tex]


From the reaction, it can be seen that [tex]CaCO_{3} [/tex] and [tex]CO_{2} [/tex]  have the following amount of substance relationship:


[tex]n(CaCO_{3}) = n(CO_{2}) = 1:1[/tex]


From the relationship we can determinate moles of [tex]CO_{2} [/tex] :


[tex]n(CaCO_{3}) = n(CO_{2}) = n/M= 14.1/100=0.141 moles[/tex]


Finally, we can calculate the volume of formed CO2:


V([tex]CO_{2} [/tex] )=nxVm=0.141x22.4=3.16 [tex] dm^{3} [/tex]

Pseudoephedrine elixir contains 30 milligrams per teaspoon. The daily retail sales limit for pseudoephedrine is 3.6 grams. How many ounces of elixir is equivalent to 3.6 grams?

Answers

Answer: 20 ounces

To solve this question, you need to convert the unit multiple times.
Pseudoephedrine elixir contains 30 milligrams per teaspoon and its sales limited to 3.6grams daily. If 1 ounce equal to 6 teaspoons, then 3.6gram will be equal to:
3.6 grams * (1000mg/gram) / (30 mg/teaspoon) / (6 teaspoon/ounce) = 20 ounces

Answer:

Explanation:

Pseudoephedrine elixir contains 30 milligrams per teaspoon. The daily retail sales limit for pseudoephedrine is 3.6 grams. How many ounces of elixir is equivalent to 3.6 grams?

convert 3.6 grams to milligrams

3.6*1000

3600milligrams

but

30mg=1 teaspoon

3600mg=x teaspoon

120 teaspoon

but 1ounce=6 teaspoon

     x=120 teaspoon

x=20 ounce

Therefore the daily limit of Pseudoephedrine elixir will be 20 Ounce

The density of gasoline is 0.65 g/ml. what is the mass in kg of 45.0 l (about 12 gal) of gasoline?'

Answers

45 liter = 45,000 ml x 0.65 gm/ml = 29,250 grams 
454 gms = 1 lb 
29,250 gms = x lb 
x = 64.4 lbs

The mass of a substance can be determined from the density and volume of the substance. The mass of gasoline with 0.65 g/ml density and 45 L volume is 29.25 Kg.

What is density?

Density of a substance is the measure of its mass per volume. Thus it is the ratio of its mass to the volume. Density of a substance depends on the temperature, pressure, bond type etc other than mas and volume.

Mass of the substance is the total amount of the substance expressed in g, kg or mg. The mass multiplied by the gravity experienced by the body is called its weight.

Volume of a substance is the total space occupied by the substance. Volume is expressed in cm³, Liter, milliliter etc.

Here the density of the substances is given 0.65 g/ml and volume is 45 liter or 45000 ml. Mass can be calculated by multiplying density with volume.

Mass = density × volume.

         =  0.65 g/ml ×  45000 ml

         = 29250 g

         = 29.25 g.

Hence, mass of the substance is 29.25 g.

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What would the products of a double-replacement reaction between ca3n2 and al2o3 be?

Answers

The equation for the reaction between Ca3N2 and Al2O3 wiil be; 
  Al2O3 + Ca3N2 = 2AIN +3CaO
Thus, the products of the reaction will be Aluminium Nitride and Burnt lime(Calcium oxide). A double displacement reaction, also known as a double replacement reaction or metathesis, is a reaction where two compounds react, and the positive ions and the anions switch places, forming two new compounds or products.

By what factor does [h+ ] change for each ph change? (a) 3.20 units

Answers

Final answer:

The hydrogen ion concentration [H+] changes by a factor of 10 for each unit change in pH. Therefore, a pH change of 3.20 units results in a 10^3.20 (approximately 1,585-fold) change in [H+].

Explanation:

The pH scale is a logarithmic scale used to measure the acidity or basicity of an aqueous solution. The pH value is calculated by taking the negative logarithm of the hydrogen ion concentration ([H+]). For each unit change in pH, the hydrogen ion concentration changes by a factor of 10.

When considering a pH change of 3.20 units, you calculate the change in hydrogen ion concentration by raising 10 to the power of the pH change. Therefore, for each pH change of 1 unit, the [H+] changes by a factor of 10. Hence, for a change of 3.20 units:

A change of 1 unit corresponds to a 10-fold change in [H+].A change of 2 units corresponds to a 102 or 100-fold change in [H+].A change of 3 units corresponds to a 103 or 1,000-fold change in [H+].A change of 3.20 units corresponds to a 103.20 or approximately 1,585-fold change in [H+].

For each pH change of 3.20 units, the [H⁺] concentration changes by a factor of approximately 1584.89.

A change of one unit on the pH scale represents a change in the [H⁺] concentration by a factor of 10. Consequently, a change of two units represents a change in the [H⁺] concentration by a factor of 100. For a change of 3.20 units, the factor is 103.20.

Calculating this, we get:

103.20 = 1584.89

Therefore, the [H⁺] concentration changes by a factor of approximately 1584.89 for a pH change of 3.20 units.

A certain object has a volume of 25.0 mL and a mass of 100 g. What is the density of the object?

Answers

Density = mass/volume

Since there was no condition of unit attached to the question...

Density = 100g/25.0ml

Density = 4g/mL.......

What mass of ammonia, NH3, is necessary to react with 2.1x10^24 molecules of oxygen in the following reaction?
4NH3(g)+7O2(g)+4NO2(g)

Answers

Final answer:

Approximately 1.998 moles of NH3 are required to react with 2.1x10^24 molecules of O2.

Explanation:

The balanced chemical equation for the reaction is:
4NH3(g) + 7O2(g) → 4NO2(g) + 6H2O(g)
From the equation, we can see that 4 moles of NH3 react with 7 moles of O2. Therefore, in order to find the mass of NH3 required to react with 2.1x10^24 molecules of O2, we need to convert the number of O2 molecules to moles and then use the mole ratio to calculate the moles of NH3 required.

Step 1: Convert 2.1x10^24 O2 molecules to moles:
Moles of O2 = (2.1x10^24 molecules) / (6.022x10^23 molecules/mol) = 3.49 moles O2

Step 2: Use the mole ratio from the balanced equation to find the moles of NH3 required:
4 moles NH3 / 7 moles O2 = (3.49 moles O2) * (4/7) = 1.998 moles NH3

Therefore, approximately 1.998 moles of NH3 are required to react with 2.1x10^24 molecules of O2.

The atoms and molecules in a liquid are in constant motion. As temperature decreases, what is true of the particles in the liquid? the rate of particle movement decreases the distance between the particles increases the attraction between the particles decreases the potential energy of the particles increases

Answers

a) The rate of particle movement decreases as temperature decreases, causing the atoms and molecules in the liquid to move less energetically.

The atoms and molecules in a liquid are in constant motion. As temperature decreases, the kinetic energy of these particles decreases as well.

This is because temperature is directly related to the average kinetic energy of the particles in a substance. Therefore, as the temperature drops, the particles move more slowly.

Here's a step-by-step explanation:

The decrease in the temperature of a liquid leads to a reduction in the thermal energy provided to the particles.

Kinetic energy, the energy of motion, is directly proportional to temperature, which measures the average kinetic energy of particles, indicating a decrease in temperature.

Particles' movement decreases with less kinetic energy, resulting in slower and slower particles.

The distance between particles may decrease due to stronger attractive forces at lower kinetic energies, but option b (distance increases) is incorrect as particles come closer together as they lose energy.

The attraction between particles decreases with decreased kinetic energy, causing them to pull closer together, contradicting option c.

Particles' potential energy decreases as they move closer in a stable configuration at lower temperatures.

Correct Question:

The atoms and molecules in a liquid are in constant motion. As temperature decreases, what is true of the particles in the liquid?  

a) the rate of particle movement decreases  

b) the distance between the particles increases  

c) the attraction between the particles decreases  

d) the potential energy of the particles increases

What might you expect to observe from this double-displacement reaction: CoCl2(aq) + Na2SO4(aq) ---> CoSO4 + 2NaCl?
Edit
A. CoSO4 precipitate will form.
B. NaCl precipitate will form.
C. one of these products will bubble out as a gas.
D. There will be no chemical change because there will be no chemical reaction; the ions will remain suspended in the water solution.

Answers

To decide the outcome of this reaction, we need to know the state of the products, as in if they are solid, liquid, gaseous, aqueous, etc. The proper reaction is as follows:

CoCl₂ (aq) + Na₂SO₄ (aq) → CoSO₄ (aq) + 2NaCl (aq)

If we were to look up the species CoSO₄ and NaCl, we would find that both of these species are also aqueous. Therefore, neither CoSO₄ or NaCl will precipitate from the solution, so we can ignore options A and B. Neither species formed is gaseous either, therefore, it cannot be option C. That leaves us with option D as the answer.

D is the correct answer because the product of the double displacement is the formation of two more aqueous species which will remain dissociated in the aqueous solution leading to no chemical reaction overall.

Which is part of the hydrosphere? lightning plants clouds squirrels

Answers

Clouds I believe because hydro means water and clouds are made of water
If i'm correct I think the answer is plants. Hope this helps 

In the Lewis dot structure for NH3, the central atom of the molecule has three atoms bonded to it and one lone pair of electrons. mc006-1.jpg The shape of an NH3 molecule is

Answers

The shape of NH3 is trigonal pyramidal.

Answer:

Trigonal pyramidal

Explanation:

Edge

A. 50 g of nitrogen (n2) has a volume of ___ liters at stp.

Answers

Answer:

39.98 liters

Explanation:

The first you should know:  At STP , 1 mole of any  gas takes up 22.4 Liters of volume.

After, you will find the molecular weight (MW) of N2 with help of a periodic table.

Then N= 14,007 g      

So:  

N2 = 14,007 * 2      

MW =28,014 g/ mol N2  

Now you will start with the data of 50 grams of N2 and you obtain:    

50 g N2  x 1 mol N2    x  22.4 L N2      =  39.98 L at STP                                 28,014 g N2        1 mol N2      

50 g of nitrogen, N₂ has a volume of 40 L at standard temperature and pressure (stp)

We'll begin by calculating the number of mole in 50 g of N₂. This can be obtained as follow:

Mass of N₂ = 50 g

Molar mass of N₂ = 2 × 14 = 28 g/mol

Mole of N₂ =?

Mole = mass / molar mass

Mole of N₂ = 50 / 28

Mole of N₂ = 1.786 mole

Finally, we shall obtain the volume occupied by 1.786 mole of N₂ at STP. This can be obtained as follow:

At standard temperature and pressure (STP)

1 mole of N₂ = 22.4 L

Therefore,

1.786 mole of N₂ = 1.786 × 22.4

1.786 mole of N₂ = 40 L

Therefore, 50 g of N₂ occupies 40 L at standard temperature and pressure (STP).

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Calculate the volume of 76.2 mole of propane gas,C3H8, if the molar volume is 55.0L/mol.

Answers

Answer is: the volume of propane gas is 4191 liters.
n(C₃H₈) = 76,2 mol.
Vm = 55,0 L/mol.
V(C₃H₈) = ?
V(C₃H₈) = n(C₃H₈) · Vm.
V(C₃H₈) = 76,2 mol · 55 L/mol.
V(C₃H₈) = 4191 L.
n(C₃H₈) - amount of substance of propane gas.

The ka of propanoic acid (c2h5cooh) is 1.34 × 10-5. calculate the ph of the solution and the concentrations of c2h5cooh and c2h5coo– in a 0.193 m propanoic acid solution at equilibrium.

Answers

Final answer:

The pH and concentrations of C2H5COOH and C2H5COO– in a 0.193 M propanoic acid solution at equilibrium can be calculated using the given Ka and the formula for pH. The initial, change and equilibrium concentrations are used for these calculations.

Explanation:

To calculate the pH and concentrations of C2H5COOH and C2H5COO– in a 0.193 M propanoic acid solution at equilibrium, we start by setting up the ICE (initial, change, equilibrium) table for the reaction. Ka = [H3O+][C2H5COO-] / [C2H5COOH], where H3O+, C2H5COO-, and C2H5COOH are equilibrium concentrations. Since the Ka for propanoic acid is given as 1.34 × 10-5, we can say that [H3O+] = sqrt(1.34 × 10-5 * 0.193).

We perform this calculation to find [H3O+], from which we find the pH = -log[H3O+]. The concentrations of C2H5COOH and C2H5COO– are both equal to 0.193 M in a 0.193 M solution of propanoic acid at equilibrium, as propanoic acid is a weak acid and partially ionizes in solution, leading to the same concentration at equilibrium.

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Calculate the percent composition of bromine in kBr

Answers

Kalium bromide molecule is made by 1 atom of Kalium and 1 atom of Bromine. Since the molecular weight of KBr is 119.02 g/mol and Bromine atomic mass is 79.904g/mol, the percent composition of bromine would be: (79.904g/mol) / (119.02 g/mol ) * 100% = 67.13%

Final answer:

To calculate the percent composition of bromine in KBr, find the atomic mass of bromine and potassium, add them to get the formula mass of KBr, and divide the atomic mass of bromine by the total mass, then multiply by 100% to get the percentage.

Explanation:

To calculate the percent composition of bromine in KBr, you need to know the atomic masses of both potassium (K) and bromine (Br). KBr is made up of one potassium atom and one bromine atom. The atomic mass of potassium is approximately 39.10 amu (atomic mass units), and the atomic mass of bromine averages about 79.90 amu, accounting for its natural isotopic abundance.

The formula to find the percent composition is (mass of the element in one mole of the compound/mass of one mole of the compound) × 100%.

The total mass of one mole of KBr is the sum of the mass of potassium and the mass of bromine, which equals 39.10 + 79.90 = 119.00 amu. The percentage of bromine in KBr can be calculated as follows:

([tex]\frac{Mass of bromine}{Total mass of KBr}[/tex]) × 100% = ([tex]\frac{79.90 amu}{ 119.00 amu}[/tex]) × 100% ≈ 67.14%

Therefore, the percent composition of bromine in KBr is approximately 67.14%.

If the compound has a molar mass of 156 g/mol, what is its molecular formula?

Answers

The molecular formula of the compound is C10H20O.

The question is incomplete, the complete question is;

Menthol, the substance we can smell in mentholated cough drops, is composed of C, H, and O. A 0.1005-g sample of menthol is combusted, producing 0.2829 g of CO2 and 0.1159 g of H2O. What is the empirical formula  for menthol?  If the compound has a molar mass of 156 g/mol, what is its molecular formula?

First we have to obtain the mass/moles of each element;

Mass of C;

0.2829 g/44g/mol * 12 g/1 mol  = 0.077 g of C

Number of moles of C =  0.077 g of C/ 12 g/mol = 0.0064 moles

Mass of H;

0.1159 g/18g/mol * 2g/1mol = 0.0129 g of H

Number of moles of H = 0.0129 g of H/1 g/mol = 0.0129 moles

Mass of O = 0.1005 g - (0.077 g + 0.0129 g)

Mass of O = 0.1005 g - 0.0899

= 0.0106 g

Number of moles of O =  0.0106 g/ 16 g/mol = 0.000663 moles

Dividing through by the lowest number of moles;

C - 0.0064/0.000663      H - 0.0129/0.000663    O - 0.000663/0.000663

C - 10                               H - 20                               O - 1

Empirical formula; C10H20O

Since the molecular formula is 156 g/mol

(C10H20O)n = 156

Where n is the number of each atom in the compound

(120 + 20 + 16)n = 156

156n = 156

n = 1

Hence the molecular formula of the compound is C10H20O.

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The rate constant is found to be 3.9 x 10-5 M-1 s-1. Calculate the rate of formation of ozone when the concentration of oxygen atoms is 3.0 x 10-14 molar and the concentration of diatomic oxygen is 1.3 x 10-14 molar.

Answers

The answer is 1.5 X 10 ^32 M/s.

Determine the Chemical reaction:

O + O₂ → O₃

Note:

The Ozone is formed when an oxygen atom collides with a molecule of oxygen.

Given: 

k = 3.9 x 10-5 M-1 s-1

Solution:

c(O) = 3.0 x 10⁻¹⁴ M

c(O₂) = 1.3 x 10⁻¹⁴ M

Required:

Find the rate of formation

rate of formation = k·c(O)·c(O₂)

rate of formation = (3.9 x 10⁻⁵ M⁻¹·s⁻¹) (1.3 x 10⁻¹⁴ M) (3.0 x 10⁻¹⁴ M)

rate of formation of ozone = 1.5 x 10⁻³² M/s
Answer: 1.5x10⁻³² M/s


Explanation:


1) The ozone is formed when oxygen atoms (O) react with oxygen diatomic molecules (O₂)


2) The chemical equation for the formation of ozone is:


O + O₂ → O₃


3) The rate of the formation is:


rate = k[O][O2]


4) You are given the three values k ,[O] and [O2], so just plug in and calculate:

rate = 3.9·10⁻⁵ M⁻¹·s⁻¹ · 1.3·10⁻¹⁴ M · 3.0·10⁻¹⁴ M. = 1.5x10⁻³² M/s

Minerals are grouped into mineral classes primarily on a basis of _____. the number of cleavage directions present chemistry, specifically the cations within the chemical formula chemistry, specifically the anions within the chemical formula hardness; hard, soft, and medium are the three primary classes

Answers

I think minerals are grouped into mineral classes primarily on a basis of specifically the anions within the chemical formula. Anions are the negatively charged ions in a mineral. These anions are larger than cations and are mostly attracted to positive ions.

Carbonyl fluoride, cof2, is an important intermediate used in the production of fluorine-containing compounds. for instance, it is used to make the refrigerant carbon tetrafluoride, cf4 via the reaction 2cof2(g)⇌co2(g)+cf4(g), kc=8.90 if only cof2 is present initially at a concentration of 2.00 m, what concentration of cof2 remains at equilibrium?

Answers

Final answer:

To find the equilibrium concentration of COF2, we use the equilibrium constant Kc = 8.90 and set up a quadratic equation based on the initial concentration of COF2. Solving this gives us the concentration of COF2 remaining at equilibrium, which is approximately 1.58 M.

Explanation:

Equilibrium Calculation for Carbonyl Fluoride Reaction

To determine the concentration of COF2 that remains at equilibrium, we'll use the equilibrium constant and the initial concentration. The chemical equilibrium reaction is:

2COF2(g) ⇌ CO2(g) + CF4(g)

The equilibrium constant (Kc) for this reaction is 8.90. If only COF2 is present initially at a concentration of 2.00 M, let's define the change in concentration for COF2 at equilibrium as 'x'. This means at equilibrium, the concentration of COF2 will be (2.00 - 2x), and the concentrations of CO2 and CF4 will both be 'x' because they are produced in a 1:1 ratio.

The equilibrium expression is:

Kc = [CO2][CF4] / [COF2]2

Substituting the known values and expressions for equilibrium concentrations, we get:

8.90 = (x)(x) / (2.00 - 2x)2

This is a quadratic equation in the form of ax2 + bx + c = 0. By solving this quadratic equation, we can find the value of 'x' and therefore the equilibrium concentration of COF2. After calculation, the concentration of COF2 remaining at equilibrium is approximately 1.58 M.

Suppose you want to make 100 grams of water, what is the molar mass of water

Answers

The molar mass of water is the molecular weight in grams per 1 mole.
18gH2O/1mole
100g × 1mole/18g = 50/9 moles = 5.67 moles H2O

What PROPERTIES of elements visibly show periodic trends when their values are graphed?

Answers

Final answer:

Properties of elements that visibly show periodic trends when their values are graphed include atomic size, ionization energy, and electron affinity.

Explanation:

The properties of elements that visibly show periodic trends when their values are graphed include atomic size, ionization energy, and electron affinity.

Atomic size, or atomic radius, generally increases as you move down a group (vertical column) in the periodic table. This is because additional energy levels or electron shells are added as you move down, resulting in larger atomic size.

On the other hand, ionization energy, which is the energy required to remove an electron from an atom, generally increases as you move across a period (horizontal row) from left to right in the periodic table. This is because the atomic size decreases and the attraction between the positively charged nucleus and the negatively charged electron increases, making it more difficult to remove an electron.

Lastly, electron affinity, which is the energy change when an atom gains an electron, also shows periodic trends. Electron affinity generally becomes more negative (increases) as you move across a period from left to right, except for a few exceptions. This is because atoms on the right side of the periodic table have a higher effective nuclear charge, which makes it easier for them to attract and gain electrons.

In an exothermic reaction, energy may be released to the surroundings in the form of

Answers

In the form of heat.

Explanation:

A reaction in which energy is released in the form of heat is known as exothermic reaction.

General reaction equation for exothermic reaction is as follows.

          [tex]Reactants \rightarrow Products + Energy[/tex]

For example, lightening a candle is an exothermic reaction.

Thus, we can conclude that in an exothermic reaction, energy may be released to the surroundings in the form of heat.

The philosopher Socrates was executed using which poison?

Answers

The philosopher Socrates was condemned to death for impiety. He was executed via Hemlock Poisoning. Hemlock is a flowering plant, related to carrots. It is known to affect the nervous system resulting to paralysis. The paralysis includes the paralysis of respiratory muscles which will impede respiration and result in death. The most potent part of the plant is the seeds and roots.

Answer:

Hemlock poison is your answer

Select the correct text in the passage. Which sentence incorrectly describes the formation of petroleum

About 300 million years ago, the seas and oceans were inhabited by tiny plants and other organisms. These organisms died and were buried on the ocean floor. Over time, their bodies were covered with silt and mud that was rich in organic material, forming layers of organic matter. This matter was subjected to high temperature and pressure. In such conditions, oxygen was available in abundance. Over a period of many years, the matter decomposed and formed oil and gas.

Answers

Answer is: In such conditions, oxygen was available in abundance. 
Because in such conditions there was no or very little oxygen. If there was oxygen the organic matter would not decomposed and formed oil and gas, because there would be reaction of oxidation.
Petroleum is used primarily as a fuel in combustion engines.

the answer is: in such conditions, oxygen was available in abundance.

2. This graph can best be described as a


a. Bar graph


b. Exponential graph


c. Logistic growth graph


d. Line graph

Answers

d is the answee your welcome
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