The new freezing point of the solution is -8.63 °C.
Using the ideal gas law, PV = nRT, we need to convert 4.00 L of gas at 27°C (which is 300 K) and 748 mmHg to moles of gas.
P = 748 mmHg / 760 mmHg atm = 0.984 atm
[tex]n = \frac{PV}{RT} = \frac{0.984 \, \text{atm} \times 4.00 \, \text{L}}{0.0821 \, \text{L atm / K mol} \times 300 \, \text{K}} = 0.160 \, \text{mol}[/tex]
Calculate molality:
Molality (m) = moles of solute / kg of solvent = 0.160 mol / 0.0580 kg = 2.759 m
Calculate freezing point depression (ΔTf):
ΔTf = i * Kf * m
For non-electrolytes, i = 1.
ΔTf = 1 * 5.12 °C/m * 2.759 m = 14.13 °C
Determine the new freezing point:
The freezing point of pure benzene is 5.5 °C.
New freezing point = 5.5 °C - 14.13 °C = -8.63 °C
Thus, the freezing point of the solution is -8.63 °C.
For a solution with an [oh−] of 10−8 m, what would be the value of [h+] , ph and poh, respectively? 1. 106 m, 6, 8 2. 10−6 m, 6, 8 3. 10−6 m, 8, 6 4. 10−14 m, 6, 8 5. 10−6 m, 6, 14 6. 10−14 m, 8, 6
The simplest substances on Earth are called ________.
A. compounds
B. elements
C. solutions
D. molecules
In a future hydrogen-fuel economy, the cheapest source of h2 will certainly be water. it takes 467 kj to produce 1 mol of h atoms from water. what is the frequency, wavelength, and minimum energy of a photon that can free an h atom from water? enter your answers in scientific notation.
The minimum energy of a photon that can produce one hydrogen atom from water is [tex]\boxed{7.755 \times {{10}^{ - 19}}{\text{ J}}}[/tex]
The frequency of the photon is [tex]\boxed{1.17 \times {{10}^{15}}{\text{ }}{{\text{s}}^{ - 1}}}[/tex].
The wavelength of the photon is [tex]\boxed{2.563 \times {{10}^{ - 7}}{\text{ m}}}[/tex].
Further Explanation:
Frequency[tex]\left( \nu \right)[/tex] is defined as number of times n event occurs in unit time. It is generally applied to waves including light, sound, and radio waves. It is denoted by [tex]{\nu }}[/tex] and its SI unit is Hertz (Hz).
Wavelength is the characteristic property of a wave. It is defined as the distance between two successive crests or troughs. A crest is that point where there is maximum displacement of the medium whereas trough is a point that has minimum displacement of the medium. It is represented by [tex]\lambda[/tex] and its SI unit is meter (m).
First, the energy required to produce one hydrogen atom in joule can be calculated as follows:
[tex]E\left({\text{J}}\right)=\frac{{E\left( {{\text{kJ}}}\right)\times\left({\frac{{{{10}^3}{\text{ J}}}}{{{\text{kJ}}}}}\right)}}{{{{\text{N}}_{\text{A}}}}}[/tex] …… (1)
Here, [tex]{{\text{N}}_{\text{A}}}[/tex] is an Avogadro's number and has a value [tex]6.022 \times {10^{23}}{\text{ mo}}{{\text{l}}^{ - 1}}[/tex].
Substitute [tex]467{\text{ kJ/mol}}[/tex] for [tex]E\left( {{\text{kJ}}} \right)[/tex] and [tex]6.022 \times {10^{23}}{\text{ mo}}{{\text{l}}^{ - 1}}[/tex] for [tex]{{\text{N}}_{\text{A}}}[/tex] in equation (1).
[tex]\begin{aligned}E\left( {\text{J}} \right)&=\frac{{\left({467{\text{ kJ/mol}}} \right) \times \left( {\frac{{{{10}^3}{\text{ J}}}}{{{\text{kJ}}}}}\right)}}{{6.022\times {{10}^{23}}{\text{ mo}}{{\text{l}}^{-1}}}}\\&=7.755\times{10^{-19}}{\text{ J}}\\\end{aligned}[/tex]
Thus the energy of a photon that can free one atom of hydrogen is [tex]7.755 \times {10^{ - 19}}{\text{ J}}[/tex].
The expression of frequency and energy is as follows:
[tex]E=hv[/tex] …… (2)
Here, [tex]v[/tex] is a frequency of photon and h is a Plank’s constant and has a value [tex]\left({6.626\times{{10}^{-34}}{\text{ Js}}}\right)[/tex].
Rearrange equation (2) to calculate the frequency of the photon as follows:
[tex]v=\frac{E}{h}[/tex] …… (3)
Substitute [tex]6.626\times{10^{-34}}{\text{ J}}\cdot{\text{s}}[/tex] for h and [tex]7.755 \times {10^{-19}}{\text{ J}}[/tex] for E in equation (3).
[tex]\begin{aligned}v&=\frac{{7.755\times{{10}^{-19}}{\text{ J}}}}{{6.626\times{{10}^{-34}}{\text{ Js}}}}\\&=1.17\times{10^{15}}{\text{}}{{\text{s}}^{-1}}\\\end{aligned}[/tex]
Thus the frequency of photon is [tex]1.17\times{10^{15}}{\text{}}{{\text{s}}^{-1}}[/tex].
The expression to calculate the wavelength from energy of the photon is as follows:
[tex]E = \frac{{h{\text{c}}}}{{\lambda }}}[/tex] …… (4)
Here [tex]{\lambda }}[/tex] is a wavelength of a photon and c is a speed of light.
Rearrange equation (4) to calculate wavelength of the photon as follows:
[tex]{\lambda }}=\frac{{h{\text{c}}}}{E}[/tex] …… (5)
Substitute [tex]6.626 \times {10^{ - 34}}{\text{ J}} \cdot {\text{s}}[/tex] for h, [tex]3.0 \times {10^8}{\text{ m/s}}[/tex] for c and [tex]7.755 \times {10^{ - 19}}{\text{ J}}[/tex] for E in equation (5).
[tex]\begin{aligned}{\lambda}}=\frac{{\left({6.626\times {{10}^{-34}}{\text{ J}}\cdot {\text{s}}} \right)\left( {3.0 \times {{10}^8}{\text{ m/s}}}\right)}}{{\left({7.755\times {{10}^{ - 19}}{\text{ J}}} \right)}}\\=2.563\times {10^{-7}}{\text{m}}\\\end{aligned}[/tex]
Hence wavelength of the photon is equal to [tex]2.563 \times {10^{ - 7}}{\text{ m}}[/tex].
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Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Structure of atom
Keywords: Hydrogen atom, cheapest source of h2, 467 kj, 1 mol of h atom, frequency wavelength.
How much heat is required to raise the temperature of 10.35g of CCl4 from 32.1°c to 56.4°c
Some chemical reactions can proceed in just one direction . True or False ?
What is the noble gas configuration for silicon? [Ne] 3s2 3p1 [Ar] 4s1 [Kr] 5s1 [Ne] 3s2 3p2
Answer: The noble gas notation for silicon atom is [tex][Ne]3s^23p^2[/tex]
Explanation:
Noble gas notation is defined as the notation in which the configuration of an atom is written in terms of previous noble gas.
Silicon is the 14th element of the periodic table having 14 electrons.
The nearest noble gas to this element is neon.
So, the noble gas notation for silicon atom = [tex][Ne]3s^23p^2[/tex]
Write a balanced equation to show the reaction of gaseous ethane,c2h6 with gaseous oxygen to form carbon monoxide gas,co, and water vapor
Answer: The balanced chemical equation is written below.
Explanation:
Combustion reaction is defined as the chemical reaction in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide gas and water molecule.
If supply of oxygen gas is limited, it is known as incomplete combustion and carbon monoxide gas is also produced as a product.
The chemical equation for this reaction of ethene and oxygen gas follows:
[tex]2C_2H_6+5O_2\rightarrow 4CO+6H_2O[/tex]
By Stoichiometry of the reaction:
2 moles of ethene gas reacts with 5 moles of oxygen gas to produce 4 moles of carbon monoxide gas and 6 moles of water vapor.
Hence, the balanced chemical equation is written above.
Our good friend and pseudo scientist, homer simpson, attempts to analyze 300 mg of an unknown compound containing only c and h by burning it in excess oxygen. 540 mg of h2o is produced. you may assume that all the hydrogen in the compound ended up as water.
) determine the theoretical yield and the percent yield if 21.8 g of k2co3 is produced from reacting 27.9 g ko2 with 29.0 l of co2 (at stp). the molar mass of ko2 = 71.10 g/mol and k2co3 = 138.21 g/mol.
Answer : The theoretical yield of [tex]K_2CO_3[/tex] = 27.089 g
The percent yield of [tex]K_2CO_3[/tex] is, 80.47 %
Explanation : Given,
Mass of [tex]KO_2[/tex] = 27.9 g
Volume of [tex]CO_2[/tex] = 29.0 L (At STP)
Molar mass of [tex]KO_2[/tex] = 71.10 g/mole
Molar mass of [tex]CO_2[/tex] = 44 g/mole
Molar mass of [tex]K_2CO_3[/tex] = 138.21 g/mole
First we have to calculate the moles of [tex]CO_2[/tex] and [tex]KO_2[/tex].
At STP,
As, 22.4 L volume of [tex]CO_2[/tex] present in 1 mole of [tex]CO_2[/tex]
So, 29.0 L volume of [tex]CO_2[/tex] present in [tex]\frac{29.0}{22.4}=1.29[/tex] mole of [tex]CO_2[/tex]
[tex]\text{Moles of }KO_2=\frac{\text{Mass of }KO_2}{\text{Molar mass of }KO_2}=\frac{27.9g}{71.10g/mole}=0.392mole[/tex]
Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
[tex]4KO_2+2CO_2\rightarrow 2K_2CO_3+3O_2[/tex]
From the balanced reaction we conclude that
As, 4 moles of [tex]KO_2[/tex] react with 2 mole of [tex]CO_2[/tex]
So, 0.392 moles of [tex]KO_2[/tex] react with [tex]\frac{2}{4}\times 0.392=0.196[/tex] moles of [tex]CO_2[/tex]
From this we conclude that, [tex]CO_2[/tex] is an excess reagent because the given moles are greater than the required moles and [tex]KO_2[/tex] is a limiting reagent and it limits the formation of product.
Now we have to calculate the moles of [tex]K_2CO_3[/tex].
As, 4 moles of [tex]KO_2[/tex] react to give 2 moles of [tex]K_2CO_3[/tex]
So, 0.392 moles of [tex]KO_2[/tex] react to give [tex]\frac{2}{4}\times 0.392=0.196[/tex] moles of [tex]K_2CO_3[/tex]
Now we have to calculate the mass of [tex]K_2CO_3[/tex].
[tex]\text{Mass of }K_2CO_3=\text{Moles of }K_2CO_3\times \text{Molar mass of }K_2CO_3[/tex]
[tex]\text{Mass of }K_2CO_3=(0.196mole)\times (138.21g/mole)=27.089g[/tex]
The theoretical yield of [tex]K_2CO_3[/tex] = 27.089 g
The actual yield of [tex]K_2CO_3[/tex] = 21.8 g
Now we have to calculate the percent yield of [tex]K_2CO_3[/tex]
[tex]\%\text{ yield of }K_2CO_3=\frac{\text{Actual yield of }K_2CO_3}{\text{Theoretical yield of }K_2CO_3}\times 100=\frac{21.8g}{27.089g}\times 100=80.47\%[/tex]
Therefore, the percent yield of [tex]K_2CO_3[/tex] is, 80.47 %
The theoretical yield of K₂CO₃ is 54.17 g and the percent yield is 40.24%.
Percent yield is the percent ratio of actual yield to the theoretical yield. It is calculated to be the experimental yield divided by theoretical yield multiplied by 100%. If the actual and theoretical yield are the same, the percent yield is 100%
In chemistry, yield is a measure of the quantity of moles of a product formed in relation to the reactant consumed, obtained in a chemical reaction, usually expressed as a percentage.
Given,
Mass of K₂O = 27.9g
Molar Mass of K₂O = 71.1 g/mol
Mass of CO₂ = 29.01g
The reaction can be written as -
K₂O + CO₂ = K₂CO₃
Moles of K₂O = 27.9 / 71.1 = 0.392 moles
Moles of CO₂ = 29 / 22.4 = 1.29 moles
Since moles of K₂O is lesser, it is the limiting reagent.
From the reaction, 1 mole of K₂O gives 1 mole of K₂CO₃
so, 0.392 moles of K₂CO₃ is produced.
Theoretical yield of K₂CO₃ = 0.392 × 138.21 = 54.17 g
Actual yield = 21.8 g
Percent yield = (21.8 / 54.17) × 100
= 40.24%
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a section of the periodic table is shown below which of the following statements is true?
Which equilibrium reaction will experience a shift towards the products in equilibrium position when the concentration of ni2+ is increased? view available hint(s) which equilibrium reaction will experience a shift towards the products in equilibrium position when the concentration of is increased? ni2+(aq)+6nh3(aq)⇌[ni(nh3)6]2+ [ni(h2o)6]2+(aq)+3en(aq)⇌[ni(en)3]2+(aq)+6nh3(aq) ni(oh)2(s)⇌ni2+(aq)+2oh−(aq) nis(s)⇌ni2+(aq)+s2−(aq)?
Answer is
Ni²⁺(aq)
+ 6NH₃(aq)
⇌ [Ni(NH₃)₆]²⁺
The molecular mass of methyl ethanoate is 75.1 amu . calculate the molecular mass of propanoic acid, an isomer of methyl ethanoate. express your answer with the appropriate units.
Final answer:
The molecular mass of propanoic acid, an isomer of methyl ethanoate, is 74.09 amu, calculated by the sum of atomic masses of carbon, hydrogen, and oxygen in its molecular formula, C3H6O2.
Explanation:
To calculate the molecular mass of propanoic acid, an isomer of methyl ethanoate, we need to first understand that isomers are compounds with the same molecular formula but different structures, and hence, the same molecular mass. Propanoic acid's molecular formula is C3H6O2. Using the atomic masses of carbon (12.01 amu), hydrogen (1.01 amu), and oxygen (16.00 amu), we calculate the molecular mass as follows:
(3 × 12.01 amu) + (6 × 1.01 amu) + (2 × 16.00 amu) = 36.03 amu + 6.06 amu + 32.00 amu = 74.09 amu
Therefore, the molecular mass of propanoic acid is 74.09 amu.
What is the percent of MgSO4 in magnesium sulfate heptahydrate
The ______________of matter depends upon how close the individual particles are together. A) identity B) mass C) state D) temperature
Answer:
State
Explanation:
The state of matter depends on the closeness of the particles. Gases have particles that are very far apart and solids are close together. This is determined by the strength of attraction of these particles to one another.
When 0.400 mole of potassium reacts with excess water at standard temperature and pressure as shown in the equation above, the volume of hydrogen gas produced is: 2 k (s) 2 h2o (l) → 2 k (aq) 2 oh- (aq) h2 (g)?
Identify the missing daughter nucleus in the β– emission decay of 106ru below.
Nuclear reaction: ¹⁰⁶Ru → ¹⁰⁶Rh + e⁻(electron) + ve(electron antineutrino).
Beta decay is radioactive decay in which a beta ray and a neutrino are emitted from an atomic nucleus.There are two types of beta decay: beta minus and beta plus.
In beta minus decay, neutron is converted to a proton and an electron and an electron antineutrino.Twice bill's number added to 17 is 7. What is his number
What is the change in atomic mass when an atom emits an alpha particle? A. decreases by 2 B. decreases by 1 C. decreases by 4 D. remains the same
using the chart, translate the mRNA into amino acids. (amino acids abbreviations plz)
A 5.018 gram sample of a certain hydrate of magnesium sulfate, mgso4•xh2o, is heated until all the water is driven off. the resulting anhydrous compound weighs 2.449 grams. what is the formula of the hydrate?
Which of the following is produced when magnesium (Mg) combusts?A. CO2
B. MgO
C. O2
D. H2O
The half life of carbon is 5700 years. if you started with 100g of carbon 14 how much would remain after 4 half lives
At 350°c, keq = 1.67 × 10-2 for the reversible reaction 2hi (g) ⇌ h2 (g) + i2 (g). what is the concentration of hi at equilibrium if [ h2 ] is 2.44 × 10-3 m and [ i2 ] is 7.18 × 10-5 m?
The equilibrium constant expression for the reaction 2HI (g) ⇌ H₂ (g) + I₂ (g) and given concentrations of H₂ and I₂ , we calculated the concentration of HI at equilibrium to be approximately 3.24 × 10⁻³ M. We used the equilibrium constant Keq = 1.67 × 10⁻² to solve for [HI].
To find the concentration of HI at equilibrium for the reaction 2HI (g) ⇌ H₂. (g) + I₂ (g) given Keq, [H₂] and [I₂], we can use the equilibrium constant expression:
Keq = [H2][I₂] / [HI]₂Given data:
Keq = 1.67 × 10⁻²[H₂] = 2.44 × 10⁻³M[I₂] = 7.18 × 10⁻⁵ MPlug these values into the equilibrium expression and solve for [HI]:
Keq = [H₂][I₂] / [HI]₂1.67 × 10⁻² = (2.44 × 10⁻³)(7.18 × 10⁻⁵) / [HI]₂First, calculate the numerator:
(2.44 × 10⁻³)(7.18 × 10⁻⁵) = 1.75192 × 10⁻⁷Now plug this back into the equation:
1.67 × 10⁻² = 1.75192 × 10⁻⁷ / [HI]₂Solving for [HI]₂ :
[HI]₂ = 1.75192 × 10⁻⁷ / 1.67 × 10⁻² ≈ 1.0496 × 10⁻⁵Taking the square root to find [HI]:
[HI] = √(1.0496 × 10⁻⁵) ≈ 3.24 × 10⁻³ M
Correct question is: At 350°C , keq = 1.67 × 10⁻² for the reversible reaction 2HI (g) ⇌ H₂ (g) + I₂ (g). what is the concentration of hi at equilibrium if [ H₂ ] is 2.44 × 10⁻³ m and [ I₂ ] is 7.18 × 10⁻⁵ m?
Are the statements about hydrogen bonding of the compound below with water true or false? this compound can act as a hydrogen-bond donor. this compound can act as a hydrogen-bond acceptor
Methanol (CH₃OH) can act as both a hydrogen bond donor and acceptor due to its hydrogen atom bonded to electronegative oxygen and the oxygen's two lone pairs of electrons. This enables methanol to form a network of hydrogen bonds with water, affecting its physical properties.
The compound that can act as both a hydrogen bond donor and a hydrogen bond acceptor is methanol (CH₃OH). It contains a hydrogen atom attached to oxygen (making it a hydrogen bond donor) and two lone pairs of electrons on the oxygen (making it a hydrogen bond acceptor). A substance, like methanol, that can both donate a hydrogen atom and accept a hydrogen bond due to these features can participate in hydrogen bonding with water.
To assess whether a compound can act as a hydrogen bond donor or acceptor, one should look for a hydrogen atom bonded to a highly electronegative atom like oxygen, nitrogen, or fluorine; this structure facilitates hydrogen bond donation. For a compound to act as an acceptor, one should identify the presence of lone pairs of electrons on a highly electronegative atom, which can attract the hydrogen atom from another molecule.
Methanol's ability to act in both capacities allows it to form a network of hydrogen bonds with water molecules, thus affecting properties such as the boiling point and solubility. When drawing the hydrogen-bonded structure, we would show lines or dotted lines between the hydrogen of one methanol molecule and the oxygen of another methanol molecule or of a water molecule to represent the hydrogen bonds.
) what is the mass percent of a solution prepared by dissolving 18.9 grams of an unknown solid into 39.5 grams of water?
Answer:
32.4%
Explanation:
Step 1: Given data
Mass of the solute = 18.9 g
Mass of the solvent = 39.5 g
Mass of the solution = Mass of the solute + Mass of the solvent = 58.4 g
Step 2: Calculate the mass percent of the solute in the solution
We use the following expression.
[tex]\% m/m =\frac{mass\ of\ the\ solute}{mass\ of\ the\ solution} \times 100\%=\frac{18.9g}{58.4g} \times 100\% =32.4\%[/tex]
Which state of matter is most likely represented in the diagram shown below?
A square is shown with the title State of Matter. An array of circles arranged neatly in rows and columns is shown. Tiny single arcs are shown near some circles near the outer edge of the array
Gas
Solid
Liquid
Plasma
its defiantly a solid, because the particles are packed in close together and it has a definite shape and volume. water is lose and not packed in like this. and with gas, the particles would juts fly everywhere and plasma is electricity and a wild card. so its definitely a solid, trust me
A galvanic (voltaic) cell contains a copper cathode immersed in a copper(ii) chloride solution and a nickel anode immersed in a nickel(ii) chloride solution. the two solutions are connected with a salt bridge. write the balanced equation for the galvanic cell. phases are optional.
The overall reaction for the galvanic cell has been [tex]\rm Cu^2^+\;+\;Ni\;\rightarrow\;Ni^2^+\;+\;Cu[/tex].
The galvanic cell has been given as the electrochemical cell that converts chemical energy of the reaction into electrical energy.
Balanced equation for the Galvanic cellThe galvanic cell has anode as the oxidizing electrode, whee the loss of electrons takes place, and cathode as the reducing electrode where the gain of electrons takes place.
The cathodic reaction in the cell has been:
[tex]\rm Cu^2^+\;\rightarrow\;Cu\;(s)[/tex]
The anodic reaction in the cell has been:
[tex]\rm Ni\;(s)\;\rightarrow\;Ni^2^+[/tex]
The overall reaction for the galvanic cell has been:
[tex]\rm Cu^2^+\;+\;Ni\;\rightarrow\;Ni^2^+\;+\;Cu[/tex]
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In which set are the substances arranged in order of decreasing solubility in water? (a) (c) al(oh)3 > mg(oh)2 > naoh cac03 > nahc03 > na2c03 (b) (d) bas04 > cas04 > mgs04 agcl > agbr > agl?
HELPPPP PLEASE ASAP!!!
It is found that doubling the concentration of a quadruples the reaction rate and tripling the concentration of b triples the reaction rate. what is the overall order of the reaction?
The reaction is second order with respect to reactant A and first order with respect to reactant B, giving an overall reaction order of 3.
To determine the overall order of a reaction, we need to find the individual orders with respect to each reactant.
1. Doubling the concentration of reactant A increases the reaction rate by a factor of four. This indicates that the reaction is second order with respect to A, because 2² = 4.
2. Tripling the concentration of reactant B increases the reaction rate by a factor of three. This means the reaction is first order with respect to B, because 3¹ = 3.
Therefore, the overall order of the reaction is the sum of the orders with respect to each reactant:
Order with respect to A: 2Order with respect to B: 1The overall order = 2 + 1 = 3.