Chemistry College

If a titration of hcl with naoh took 15.25ml of a 0.1250 m naoh solution, how many moles of naoh was used

Answers

Answer 1
The  moles   of NaOh  used is  calculated  as  follows

moles  = molarity  x volume  in liters

volume in  liters = 15.25/1000  = 0.01525  L

molarity =0.1250  x0.02525 = 1.906 x10^-3  moles
Answer 2

Answer:

[tex]n_{HCl}=1.906x10^{-3}molHCl[/tex]

Explanation:

Hello,

Titration is widely used to determine the neutralized moles of either an acid or base. In this case, the idea is to titrate (neutralize) hydrochloric acid with sodium hydroxide based on the following reaction:

[tex]NaOH+HCl-->NaCl+H_2O[/tex]

Thus, one computes the neutralized moles of hydrochloric acid (equivalence of moles) as long as the mole ratio between the acid and the base is 1 to 1 and the moles of both of them must be equal for the neutralization to be successfully carried out as shown below:

[tex]n_{HCl}=n_{NaOH}\\n_{HCl}=0.1250mol/L*0.01525L\\n_{HCl}=1.906x10^{-3}molHCl[/tex]

Best regards.

Related Questions

How many grams of glucose are needed to prepare 400. g of a 2.00% (m/m) glucose solution g?

Answers

Final answer:

To create 400 grams of a 2% mass/mass glucose solution, you need 8 grams of glucose.

Explanation:

You're trying to find out how many grams of glucose are needed to prepare a 400 gram 2% mass/mass glucose solution. A 2% w/w glucose solution means that for every 100 grams of solution, 2 grams are glucose. Therefore, if you have 400 grams of solution, the amount of glucose required will be 2% of 400 grams.

To calculate this, you will multiply 400 grams by 0.02 (which is the decimal equivalent of 2%). So, 400 grams * 0.02 = 8 grams. Therefore, you need 8 grams of glucose to prepare 400 grams of a 2% w/w glucose solution.

Learn more about Glucose Solution Preparation here:

https://brainly.com/question/29067484

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