A student determines that according to the reaction N2(g) + 3H2(g) --> 2NH3(g), if 34g of nitrogen gas is reacted with excess hydrogen, 41g of ammonia can be produced. When the actual reaction was complete, only 38g of ammonia formed. Determine the percent yield for the reaction.

Answer:

Its chemical structure can be described as a hexagon ring with alternating double bonds

Explanation:

Answer: The distillation flask being heated in a heating mantle. The vapors condense and drip from the condenser into the flask. As the distillate begins to drop from the condenser, the temperature observed on the thermometer should be changing steadily.

Explanation:

answer above

Answer:

Option (C) is correct.

Explanation:

Decomposition reaction: [tex](NH_{4})_{2}CO_{3}\rightarrow 2NH_{3}+CO_{2}+H_{2}O[/tex]

Molar mass of [tex]CO_{2}[/tex] = 44.01 g/mol

No. of moles = (mass)/(molar mass)

So, 6.52 g of [tex]CO_{2}[/tex] = [tex]\frac{6.52}{44.01}[/tex] moles of [tex]CO_{2}[/tex] = 0.148 moles of [tex]CO_{2}[/tex]

According to balanced equation-

1 mol of [tex]CO_{2}[/tex] is produced from decomposition of 1 mol of [tex](NH_{4})_{2}CO_{3}[/tex]

So, 0.148 mol of [tex]CO_{2}[/tex] is produced from decomposition of 0.148 mol of [tex](NH_{4})_{2}CO_{3}[/tex]

Hence, option (C) is correct.

Answer:

11

Explanation:

I scoured across many websites to finally get this answer. And it is right, I just did the Instruction.

Answer:

11

Explanation:

e2020

Answer:

Potassium has less ionization energy because it does not take much energy to remove its single outer electron. Most elements want to have a complete outer shell, so since it has a lone electron in its outer shell, it will easily give up the electron to become more stable.

The atomic structure indicates the number of protons, neutrons, and electrons in an atom.

In the atomic structure, the protons and the neutrons are positioned at the center of the nucleus while the electrons are located at the outer region of the atom.

The ionization energy is the amount of needed to eliminate a single electron from the outermost shell of an atom or a molecule.

Factors affecting the ionization energy includes:

On the periodic table, Potassium (K) is the 19th element and Calcium is the 20th element.

Postassium is located on Group 1 and period 4 while Calcium is located on the Group 2 and period 4 on the periodic table.

Now, as we move from left - right on the periodic table across the period, the ionization energy increases from left to right as a result of the size of the atom.

Here, the size of the atom of Calcium(Ca) is larger by a single electron compared to the size of Potassium(K).

Also, the positive nuclear charge on Calcium(Ca) is greater than that of Potassium(K) because from left - right on the periodic table, the nuclear charge increases,thereby increasing attraction of the outermost electron, thus more energy is needed to remove an electron.

Thus, since Calcium(Ca) tends to have a larger size of atom and a greater +ve nuclear charge than Potassium(K), then:

The first ionization energy of K will be lesser than that of Ca.

Therefore, from the above explanation, we can conclude that we've understood why the first-ionization energy K is less than that of Ca.

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Answer:

The answer to your question is 164 g

Explanation:

Data

molar mass of Na₃PO₄ = ?

Molar mass is also known as molecular weight, it is the result of the sum of the total mass in grams of all the atoms that make up a mole of a particular molecule.

For Sodium phosphate the molar mass if

Na₃PO₄ = (23 x 3) + (31 x 1) + (16 x 4)

             = 69 + 31 + 64

             = 164 g

The molar mass or molecular weight of any substance is defined as the mass of 1 mole of that substance. Molar mass of [tex]Na_3PO_4[/tex] is 164g.

By using the periodic table we can check the molar mass of sodium, phosphorus, and oxygen which are Na=23, P=31, and O=16.

In [tex]Na_3PO_4[/tex] there are 3 molecules of Na (sodium), 1 molecule of P(phosphorus), and  4 molecules of  O (oxygen).

Mass of 3 molecules of Na (sodium)=  23×3.

Mass of 1 molecule of P(phosphorus) =  31×1.

Mass of 4 molecules of  O (oxygen) = 16×4.

So, the total molar mass of [tex]Na_3PO_4[/tex] is =  23×3 + 31×1 + 16×4 =164g.

Molar mass of [tex]Na_3PO_4[/tex] is 164g.

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Answer:

gas molecules scatter short wavelengths of light (blue and violet) more than long (red and orange) so the sky looks blue. at sunrise and sunset, the light passes through thicker atmosphere and blue light is scattered more, so mostly red and orange light is visible.

Explanation:

hope it helps

Answer:

C-The thick atmosphere scatters all but longer wavelengths.

Explanation:

Light travels through more atmosphere, leaving long wavelengths at sunrise/sunset

Answer:

35.7%

Explanation:

The percent yield is calculated by the formula:

[(actual yield) / (theoretical yield)] * 100

In this case, the actual yield is 0.15 grams, and the theoretical yield is 0.42 grams. So, putting these values into the equation, we have:

[tex]\frac{0.15}{0.42} *100=0.357*100=35.7[/tex]

Thus, the percent yield of [tex]H_2[/tex] is 35.7%.

Hope this helps!

The percentage yield of a reaction is calculated using the equation: (Actual Yield / Theoretical Yield) * 100. In this case, the percentage yield of the reaction that produced H2 is approximately 35.7%.

The subject of this question is the percentage yield of a chemical reaction. In chemistry, the percentage yield is a measure of the efficiency of a reaction. It's calculated by dividing the actual yield (the amount of product actually produced) by the theoretical yield (the maximum amount of product that could be produced) and then multiplied by 100 to convert it to a percentage.

Given in the question, the theoretical yield of H2 is 0.42 grams and the actual yield is 0.15 grams. So, to calculate the percentage yield, we would use the formula: (Actual Yield / Theoretical Yield) * 100

Substituting the given amounts, the calculation would look like this: (0.15 / 0.42) * 100 = 35.7%.

So, the percentage yield of H2 in this reaction is approximately 35.7%.

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lanation:

It has to be 30 degrees

Answer:

The new pressure of the pump is 26.05 atm or 2639.4 kPa

Explanation:

Step 1: Data given

Volume of the bicycle tire pump = 252 mL = 0.252 L

Pressure of air = 995 kPa = 9.81989 atm

The volume of the pump is reduced to 95.0 mL = 0.095 L

Step 2: Calculate the new pressure

V1*P1 = V2*P2

⇒with V1 = the initial volume of the bicycle tire pump = 0.252 L

⇒with P1 = the initial pressure of the pump = 9.81989 atm = 995 kPa

⇒with V2 = the reduced volume of the pump = 0.095 L

⇒with P2 = the new pressure = TO BE DETERMINED

0.252 L * 9.81989 atm = 0.095 L * P2

P2 = 26.05 atm

The new pressure is 26.05 atm

OR

0.252 L * 995 = 0.095 L * P2

P2 = 2639.4 kPa

The new pressure of the pump is 26.05 atm or 2639.4 kPa

Answer:

[tex]p_2=2639.4kPa[/tex]

Explanation:

Hello,

In this case, we notice a relationship between the volume and pressure of a gas, accounting for the Boyle's law which has the following form:

[tex]p_1V_1=p_2V_2[/tex]

In this case, we asked to find the pressure after the pump is pushed down, it means [tex]p_2[/tex] as shown below:

[tex]p_2=\frac{p_1V_1}{V_2} =\frac{252mL*995kPa}{95.0mL}\\ \\p_2=2639.4kPa[/tex]

Such pressure increase accounts for a compression process at which the volume is decreased at the same time.

Best regards.

48.70 is the volume, in liters, occupied by 1.73 moles of Nitrogen gas at 0.992 atm pressure and a temperature of 75º C.

Explanation:

Data given:

number of moles of nitrogen gas = 1.73 moles

pressure of the gas = 0.992 atm

temperature of the gas = 75 degrees or 273.25 + 75 = 348.15 K

R (gas constant) = 0.08206 L atm/molesK

volume of the nitrogen gas under these conditions =?

The formula used is of ideal Gas Law:

PV = nRT

Rearranging the equation to get,

V = [tex]\frac{nRT}{P}[/tex]

putting the values in the equation:

V = [tex]\frac{1.73 X 0.08026 X 348.15}{0.992}[/tex]

  = 48.70 Litres

the volume of the gas is 48.70 litres from the standard values used in the equation.

The volume, in liters, occupied by 1.73 moles of N₂ gas at 0.992 atm pressure and a temperature of 75º C is: [tex]45.81 \text{ L}.[/tex]

The volume occupied by the N₂ gas can be calculated using the ideal gas law, which is given by the equation:

[tex]\[ PV = nRT \][/tex]

where:

- [tex]\( P \)[/tex] is the pressure of the gas,

- [tex]\( V \)[/tex] is the volume of the gas,

- [tex]\( n \)[/tex] is the number of moles of the gas,

- [tex]\( R \)[/tex] is the ideal gas constant, and

- [tex]\( T \)[/tex] is the temperature of the gas in Kelvin.

Given:

- [tex]\( n = 1.73 \)[/tex] moles,

- [tex]\( P = 0.992 \)[/tex] atm,

- [tex]\( T = 75^\circ C \)[/tex], which needs to be converted to Kelvin by adding 273.15 to the Celsius temperature,

- [tex]\( R = 0.08206 \) L\atm/(mol\K).[/tex]

First, convert the temperature from Celsius to Kelvin:

[tex]\[ T(K) = T(^\circ C) + 273.15 = 75 + 273.15 = 348.15 \text{ K} \][/tex]

Now, rearrange the ideal gas law to solve for the volume [tex]\( V \)[/tex]:

[tex]\[ V = \frac{nRT}{P} \][/tex]

Substitute the given values into the equation:

[tex]\[ V = \frac{(1.73 \text{ mol})(0.08206 \text{ L\·atm/(mol\·K)})(348.15 \text{ K})}{0.992 \text{ atm}} \][/tex]

[tex]\[ V = \frac{(1.73)(0.08206)(348.15)}{0.992} \][/tex]

[tex]\[ V = \frac{45.460298}{0.992} \][/tex]

[tex]\[ V \approx 45.81 \text{ L} \][/tex]

Therefore, the volume occupied by 1.73 moles of N2 gas at 0.992 atm pressure and a temperature of 75º C is approximately 45.81 liters.

There is more energy stored in the products as the reaction absorbs energy from its surroundings, hence we call it endothermic reaction.

An endothermic reaction is a type of reaction that absorbs heat from the surrounding.

When you heat the NaHCO3 strongly in order for it to decompose,;

NaHCO3 -> Na2O + 2CO2 + H2O + energy

This reaction shows that there is more energy stored in the products as the reaction absorbs energy from its surroundings, hence we call it endothermic reaction.

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Answer:

The answer to your question is 8.21 g of H₂O

Explanation:

Data

mas of water = ?

mass of hydrogen = 4.6 g

mass of oxygen = 7.3 g

Balanced chemical reaction

                   2H₂  +  O₂  ⇒   2H₂O

Process

1.- Calculate the atomic mass of the reactants

Hydrogen = 4 x 1 = 4 g

Oxygen = 16 x 2 = 32 g

2.- Calculate the limiting reactant

Theoretical yield = H₂/O₂ = 4 / 32 = 0.125

Experimental yield = H₂/ O₂ = 4.6/7.3 = 0.630

From the results, we conclude that the limiting reactant is Oxygen because the experimental yield was higher than the theoretical yield.

3.- Calculate the mass of water

                   32 g of O₂ ---------------- 36 g of water

                   7.3 g of O₂ ---------------   x

                          x = (7.3 x 36) / 32

                          x = 262.8 / 32

                          x = 8.21 g of H₂O

1) 2P

2) Average speed does not change

Explanation:

1)

To solve the first part of the problem, we can use Boyle's Law, which states that:

"For a fixed mass of an ideal gas kept at constant temperature, the pressure of the gas is inversely proportional to its volume"

Mathematically:

[tex]pV=const.[/tex]

where

p is the pressure of the gas

V is its volume

For the Xe gas in this problem we can write

[tex]p_1 V_1 = p_2 V_2[/tex]

where:

[tex]p_1 = P[/tex] is the initial pressure

[tex]V_1=V[/tex] is the initial volume

[tex]V_2=\frac{V}{2}[/tex] is the final volume

Solving for p2, we find the final pressure:

[tex]p_2=\frac{P V_1}{V_2}=\frac{pV}{V/2}=2P[/tex]

So, the pressure has doubled.

2)

The average speed of the atoms/molecules in the gas is given by the formula

[tex]v_{rms}=\sqrt{\frac{3RT}{M}}[/tex]

where

R is the gas constant

T is the absolute temperature (in Kelvin) of the gas

M is the molar mass of the gas

[tex]v_{rms}[/tex] is known as rms speed of the particles in the gas

From the formula, we see that the speed of the atoms in the gas depends only on the temperature of the gas.

In the Xe(g) gas in this problem, the temperature is kept constant; therefore, since nothing changes in the formula, this means that the average speed also does not change.

The pressure of the gas is doubled and the average speed of the gas molecules does not change.

According to Boyle's law, the volume of a given mass of gas is inversely proportional to the pressure at constant temperature. Now;

Initial pressure of the gas (P1) = P

Initial volume of the gas(V1) = V

Final volume of the gas (V2) = V/2

Final pressure of the gas (P2) = ?

Using the relation of Boyle's law;

P1V1 = P2V2

P2 =  P1V1/V2

P2 = P × V/V/2

P2 = 2P

The pressure is doubled

Regarding the average speed of gas molecules, the average speed of a gas molecules depends on the temperature from the relation;

[tex]vrms = \sqrt{\frac{3RT}{M} }[/tex]

If the temperature is held constant, the average speed of gas molecules is does not change.

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Final answer:

When a helium atom gains energy, its electrons can be excited from the 1s subshell to a higher energy level. The most likely energy level for the first electron jump when energy is absorbed, according to many electron transitions, is the second energy level. So the correct option is B.

Explanation:

When a helium atom gains energy, its electrons can move from the first energy level to a higher one. Initially, both electrons in helium fill the 1s subshell, meaning it is in its lowest energy state or ground state. According to the energy levels in an atom, when an electron gains energy it can move to a higher energy level. Therefore, when a helium atom gains enough energy, one of the electrons can be excited to the second energy level (n=2). It cannot remain in the first energy level (option A) and will not stay in the same energy level either (option D). Without additional energy amounts specific to helium, options for the third energy level (option C) or higher are less probable for the first energy jump for helium's electron. Therefore, the most likely answer is B, the second energy level.

Answer:

1.86% NH₃

Explanation:

The reaction that takes place is:

We calculate the moles of HCl that reacted, using the volume used and the concentration:

The moles of HCl are equal to the moles of NH₃, so now we calculate the mass of NH₃ that was titrated, using its molecular weight:

The weight percent NH₃ in the aliquot (and thus in the diluted sample) is:

Now we calculate the total mass of NH₃ in the diluted sample:

Diluted sample total mass = Aqueous waste Mass + Water mass = 23.495 + 72.311 = 95.806 g

Finally we calculate the weight percent NH₃ in the original sample of aqueous waste:

Answer : The number of molecules of nitrogen, oxygen, carbon dioxide and argon is, [tex]1.88\times 10^{23}[/tex], [tex]5.03\times 10^{23}[/tex], [tex]1.19\times 10^{20}[/tex] and [tex]2.23\times 10^{21}[/tex] respectively.

Explanation :

First we have to calculate the total moles of mixture of gas by using ideal gas equation.

[tex]PV=nRT[/tex]

where,

P = Pressure of mixture of gas = 1.59 atm

V = Volume of mixture of gas = 6.51 L

n = number of moles mixture of gas = ?

R = Gas constant = [tex]0.0821L.atm/mol.K[/tex]

T = Temperature of mixture of gas = [tex]43^oC=273+43=316K[/tex]

Putting values in above equation, we get:

[tex]1.59atm\times 6.51L=n\times (0.0821L.atm/mol.K)\times 316K[/tex]

[tex]n=0.399mol[/tex]

Now we have to calculate the moles of nitrogen, oxygen, carbon dioxide and argon.

Moles of nitrogen = [tex]78.08\% \times 0.399=\frac{78.08}{100}\times 0.399=0.312mol[/tex]

Moles of oxygen = [tex]20.94\% \times 0.399=\frac{20.94}{100}\times 0.399=0.0836mol[/tex]

Moles of carbon dioxide = [tex]0.0500\% \times 0.399=\frac{0.0500}{100}\times 0.399=0.000199mol[/tex]

Moles of argon = [tex]0.930\% \times 0.399=\frac{0.930}{100}\times 0.399=0.00371mol[/tex]

Now we have to calculate the number of molecules of nitrogen, oxygen, carbon dioxide and argon.

As, 1 mole of nitrogen contains [tex]6.022\times 10^{23}[/tex] number of molecules of nitrogen.

So, 0.312 mole of nitrogen contains [tex]0.312\times 6.022\times 10^{23}=1.88\times 10^{23}[/tex] number of molecules of nitrogen.

and,

As, 1 mole of oxygen contains [tex]6.022\times 10^{23}[/tex] number of molecules of oxygen.

So, 0.0836 mole of oxygen contains [tex]0.0836\times 6.022\times 10^{23}=5.03\times 10^{23}[/tex] number of molecules of oxygen.

and,

As, 1 mole of carbon dioxide contains [tex]6.022\times 10^{23}[/tex] number of molecules of carbon dioxide.

So, 0.000199 mole of carbon dioxide contains [tex]0.000199\times 6.022\times 10^{23}=1.19\times 10^{20}[/tex] number of molecules of carbon dioxide.

and,

As, 1 mole of argon contains [tex]6.022\times 10^{23}[/tex] number of molecules of argon.

So, 0.00371 mole of argon contains [tex]0.00371\times 6.022\times 10^{23}=2.23\times 10^{21}[/tex] number of molecules of argon.

Therefore, the number of molecules of nitrogen, oxygen, carbon dioxide and argon is, [tex]1.88\times 10^{23}[/tex], [tex]5.03\times 10^{23}[/tex], [tex]1.19\times 10^{20}[/tex] and [tex]2.23\times 10^{21}[/tex] respectively.

To calculate the number of molecules of each gas in the sample, use the ideal gas law equation and the percent composition given. Then, calculate the number of molecules using Avogadro's number.

To calculate the number of molecules of each gas in the sample, we need to use the ideal gas law equation, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

To calculate the number of moles for each gas, we can use the percent composition given in the question and assume the sample contains 100 moles of total gas. From there, we can calculate the number of molecules using Avogadro's number, which is approximately 6.022 x 10^23 molecules/mole.

The number of molecules of nitrogen (N₂) in the sample is (78.08/100) x 100 moles x 6.022 x 10^23 molecules/mole, and similarly, the number of molecules of oxygen (O₂), carbon dioxide (CO₂), and argon (Ar) can be calculated.

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Answer:

15.0 moles of silver chloride are produced from 15.0 mol of silver nitrate.

The number of mole of silver chloride, AgCl produced from the reaction is 15 moles.

AgNO₃ + NaCl —> NaNO₃ + AgCl

From the balanced equation above,

1 mole of AgNO₃ reacted to produce 1 mole of AgCl.

With the above information, we can obtain the number of mole of AgCl produced by the reaction of 15 moles of AgNO₃. This can be obtained as follow:

From the balanced equation above,

1 mole of AgNO₃ reacted to produce 1 mole of AgCl.

Therefore,

15 moles of AgNO₃ will also react to produce 15 moles of AgCl.

Thus, 15 moles of AgCl were obtained from the reaction.

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Answer:

To a certain extent absolutly. They can impact human health for the worse and more.

Answer:

Invasive species are those specie that is not specific to a certain location, and it spread to a degree and is harmful for human economy.

Explanation:

For e.g. Green Crab

Invasive species can affect human in a way that they threaten biodiversity and alter the ecosystem. It greatly involve in loss of human economy, its function. It also affect human health as well. It is also harmful for our natural resources.

Malaria is caused also by invasive species.

Answer : The volume of the balloon at the new location is, 591.3 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]

where,

[tex]P_1[/tex] = initial pressure of gas = 0.995 atm

[tex]P_2[/tex] = final pressure of gas = 0.720 atm

[tex]V_1[/tex] = initial volume of gas = 500 L

[tex]V_2[/tex] = final volume of gas = ?

[tex]T_1[/tex] = initial temperature of gas = [tex]32.0^oC=273+32=305K[/tex]

[tex]T_2[/tex] = final temperature of gas = [tex]-12^oC=273+(-12)=261K[/tex]

Now put all the given values in the above equation, we get:

[tex]\frac{0.995atm\times 500L}{305K}=\frac{0.720atm\times V_2}{261K}[/tex]

[tex]V_2=591.3L[/tex]

Therefore, the volume of the balloon at the new location is, 591.3 L

Answer:

The answer to your question is 3

Explanation:

Chemical reaction

               AlBr₃  +  K₂SO₄  ⇒   KBr  +  Al₂(SO₄)₃

             Reactants       Elements         Products

                   1               Aluminum               2

                   3               Bromine                  1

                   1                Sulfur                      3

                  2                Potassium              1

                  4                 Oxygen                 12    

Balanced chemical reaction

             2AlBr₃  +  3K₂SO₄  ⇒   6KBr  +  Al₂(SO₄)₃

             Reactants       Elements         Products

                   2               Aluminum               2

                   6               Bromine                  6

                   3                Sulfur                      3

                  6                Potassium               6

                 12                 Oxygen                 12    

The coefficient for K₂SO₄ will be 3

Answer:

Aluminum has 13 electrons in a neutral atom. The 1S2, 2S2 and 2P6 shells are full, and so is the 3S2. The 3P1 shell has one electron in it (in Al's neutral atom) and that gives aluminum one lone valence electron and two "semi-valence" electrons which can be loaned out.

Explanation:

The number of valence electrons that a neutral atom of aluminum has is 3 valence electrons.

Valence electrons are those electrons in the outermost parts of elements that can be combined or loned to other elements during chemical reactions. Aluminum has three electrons in the valence shell.

The total number of electrons that aluminum has is 13 and the 3P1 shell has three electrons. So, this is the number of valence electrons.

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Answer: Calcium element will form an ionic bond with carbon.

Explanation:

An ionic bond is defined as the bond formed due to transfer of electrons from one atom to another.

Elements which are able to donate their valence electrons are the ones which tend to form an ionic bond. Metals are the species which form ionic bonds when they chemically combine with non-metals.

For example, [tex]CaC_{2}[/tex] is calcium carbide and in this compound calcium forms an ionic bond with carbon atom by donating its valence electrons.

A covalent bond is defined as the bond formed due to sharing of electrons between the two elements.

Thus, we can conclude that calcium element will form an ionic bond with carbon.

Answer:

0.0488 L

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

CaCl2(aq) + Na2CO3(aq) —> CaCO3(s) + 2NaCl(aq)

Step 2:

Determination of the number of mole of Na2CO3 in 0.0650 L of 1.50 M Na2CO3 solution.

Volume of solution = 0.0650 L

Molarity of Na2CO3 = 1.50 M

Mole of solute (Na2CO3) =?

Molarity = mole of solute /Volume of solution

1.50 = mole of solute/0.0650

Cross multiply to express in linear form.

Mole of solute = 1.5 x 0.0650

Mole of solute (Na2CO3) = 0.0975 mole

Step 3:

Determination of the number of CaCl2 that reacted.

CaCl2(aq) + Na2CO3(aq) —> CaCO3(s) + 2NaCl(aq)

From the balanced equation,

1 mole of CaCl2 reacted with 1 mole Na2CO3.

Therefore, 0.0975 mole of CaCl2 will also react with 0.0975 mole of Na2CO3.

Step 4:

Determination of the volume of CaCl2 that reacted.

Mole of solute (CaCl2) = 0.0975 mole

Molarity of CaCl2 = 2.00 M

Volume of solution =?

Molarity = mole of solute /Volume

2 = 0.0975/volume

Cross multiply to express in linear form

2 x Volume = 0.0975

Divide both side by 2

Volume = 0.0975/2

Volume = 0.0488 L

Therefore, the volume of CaCl2 that is 0.0488 L

Answer:

We need a volume of 48.75 mL of CaCl2 to react

Explanation:

Step 1: Data given

Molarity of calcium chloride = 2.00 M

Volume of Na2CO3 = 0.0650 L

Molarity of Na2CO3 = 1.50 M

Step 2: The balanced equation

CaCl2 (aq) + Na2CO3(aq) → CaCO3 + 2NaCl

Step 3: Calcumate moles Na2CO3

Moles Na2CO3 = molarity Na2CO3 * volume

Moles Na2CO3 = 1.50 M * 0.0650 L

Moles Na2CO3 = 0.0975 moles

Step 4: Calculate moles CaCl2 neede to react

For 1 mol CaCl2 we need 1 mol Na2CO3 to produce 1 mol CaCO3 and 2 moles NaCl

For 0.0975 moles Na2CO3 we need 0.0975 moles CaCl2

Step 5: Calculate volume of CaCl2 solution

Volume = moles CaCl2 / molarity CaCl2

Volume = 0.0975 moles / 2.00 M

Volume = 0.04875 L = 48.75 mL

We need a volume of 48.75 mL of CaCl2 to react

Answer:

The answer to your question is 4

Explanation:

Chemical reaction

                C₂H₆  +  O₂  ⇒  CO₂  +  H₂O

           Reactants    Elements    Products

                  2            Carbon              1

                  6            Hydrogen         2

                  2            Oxygen             3

Balanced chemical reaction

                2C₂H₆  +  7O₂  ⇒  4CO₂  +  6H₂O

           Reactants    Elements    Products

                  4            Carbon             4

                 12            Hydrogen       12

                 14            Oxygen           14

When the reaction is balanced the coefficient for CO₂ is 4.

Answer:

the reactants and products

Explanation:

There are two parts to a chemical equation. The reactants are the elements or compounds on the left side of the arrow (-->). The elements and compounds to the right of the arrow are the products

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Answer:

the reactants and products

i got 6 points not 12

Answer:

Flammability is a chemical property

Explanation:

It can only be observed or measured during a chemical change known as combustion

Answer:

flammability is a chemical process

Explanation:

burning of something is causing a chemical reaction. for example a physical property is changing the way it looks, not its chemical structure (ex. ripping up paper)

Answer:

Reproduction is asexual and occurs at a rapid rate.

Answer: Reproduction is asexual and occurs at a rapid rate.

Explanation:i did the quiz

The scale model of the Mars rover and landscape is a good model as it is based on scientific principles, can make predictions, and be analyzed for reliability.

This rover model created by the scientists has several factors that make it a good model for the Martian landscape. B. It is based on sound scientific principles: This model is created using scientific facts and principles about the Mars terrain and the rover itself, ensuring it is a legitimate representation of the actual conditions on Mars. C. It can be used to make predictions: The scientists can use this model to test different circumstances and see how the rover would behave, allowing them to predict any problems that might be encountered on the actual planet. D. It can be analyzed and shown to be reliable or un-reliable: After running tests, the model's representation of reality can be assessed. If it accurately predicts the rover's action in the real Martian environment, it can be considered reliable. If not, it is seen as unreliable.

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