A study of long-distance phone calls made from General Electric's corporate headquarters in Fairfield, Connecticut, revealed the length of the calls, in minutes, follows the normal probability distribution. The mean length of time per call was 3.6 minutes and the standard deviation was 0.40 minutes.

(a) What fraction of the calls last between 3.6 and 4.2 minutes? (Round z-score computation to 2 decimal places and your final answer to 4 decimal places.)
(b) What fraction of the calls last more than 4.2 minutes? (Round z-score computation to 2 decimal places and your final answer to 4 decimal places.)
(c) What fraction of the calls last between 4.2 and 5 minutes? (Round z-score computation to 2 decimal places and final answer to 4 decimal places.)
(d) What fraction of the calls last between 3 and 5 minutes? (Round z-score computation to 2 decimal places and your final answer to 4 decimal places.)
(e) As part of her report to the president, the director of communications would like to report the length of the longest (in duration) 4% of the calls. What is this time? (Round z-score computation to 2 decimal places and your final answer to 2 decimal places.)

Answers

Answer 1

Answer:

a) 0.4332 = 43.32% of the calls last between 3.6 and 4.2 minutes

b) 0.0668 = 6.68% of the calls last more than 4.2 minutes

c) 0.0666 = 6.66% of the calls last between 4.2 and 5 minutes

d) 0.9330 = 93.30% of the calls last between 3 and 5 minutes

e) They last at least 4.3 minutes

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

[tex]\mu = 3.6, \sigma = 0.4[/tex]

(a) What fraction of the calls last between 3.6 and 4.2 minutes?

This is the pvalue of Z when X = 4.2 subtracted by the pvalue of Z when X = 3.6.

X = 4.2

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{4.2 - 3.6}{0.4}[/tex]

[tex]Z = 1.5[/tex]

[tex]Z = 1.5[/tex] has a pvalue of 0.9332

X = 3.6

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{3.6 - 3.6}{0.4}[/tex]

[tex]Z = 0[/tex]

[tex]Z = 0[/tex] has a pvalue of 0.5

0.9332 - 0.5 = 0.4332

0.4332 = 43.32% of the calls last between 3.6 and 4.2 minutes

(b) What fraction of the calls last more than 4.2 minutes?

This is 1 subtracted by the pvalue of Z when X = 4.2. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{4.2 - 3.6}{0.4}[/tex]

[tex]Z = 1.5[/tex]

[tex]Z = 1.5[/tex] has a pvalue of 0.9332

1 - 0.9332 = 0.0668

0.0668 = 6.68% of the calls last more than 4.2 minutes

(c) What fraction of the calls last between 4.2 and 5 minutes?

This is the pvalue of Z when X = 5 subtracted by the pvalue of Z when X = 4.2. So

X = 5

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{5 - 3.6}{0.4}[/tex]

[tex]Z = 3.5[/tex]

[tex]Z = 3.5[/tex] has a pvalue of 0.9998

X = 4.2

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{4.2 - 3.6}{0.4}[/tex]

[tex]Z = 1.5[/tex]

[tex]Z = 1.5[/tex] has a pvalue of 0.9332

0.9998 - 0.9332 = 0.0666

0.0666 = 6.66% of the calls last between 4.2 and 5 minutes

(d) What fraction of the calls last between 3 and 5 minutes?

This is the pvalue of Z when X = 5 subtracted by the pvalue of Z when X = 3.

X = 5

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{5 - 3.6}{0.4}[/tex]

[tex]Z = 3.5[/tex]

[tex]Z = 3.5[/tex] has a pvalue of 0.9998

X = 3

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{3 - 3.6}{0.4}[/tex]

[tex]Z = -1.5[/tex]

[tex]Z = -1.5[/tex] has a pvalue of 0.0668

0.9998 - 0.0668 = 0.9330

0.9330 = 93.30% of the calls last between 3 and 5 minutes

(e) As part of her report to the president, the director of communications would like to report the length of the longest (in duration) 4% of the calls. What is this time?

At least X minutes

X is the 100-4 = 96th percentile, which is found when Z has a pvalue of 0.96. So X when Z = 1.75.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]1.75 = \frac{X - 3.6}{0.4}[/tex]

[tex]X - 3.6 = 0.4*1.75[/tex]

[tex]X = 4.3[/tex]

They last at least 4.3 minutes


Related Questions

Luke puts 3 apples in each bag. How many apples does he put in 4 bags

Answers

Answer:

12

Step-by-step explanation:

3x4=12

Answer:

12

Step-by-step explanation:

Multiply the number of bags times the apples per bag

4*3 = 12

He needs 12 apples

Danika is making pizza. She has 1/3 cup of cheese and knows this is only enough for 2/5 of the recipe. How much cheese does the recipe call for?

Answers

Answer:

2/15 cups of cheese

Step-by-step explanation:

Because you are eating 2/5 of the recipe you have to multiply the values

2/5*1/3 = 2/15

a line contains the points (-3 -2) and (7,2) determine whether the slope of this line is positive or negative

Answers

Answer:

Positive. From those two points the line would slant upwards. Going left to right it would be going up, therefore it's a positive slope

Step-by-step explanation:

The slope of the given lines with two points is positive.

How to find the slope?

Slope of a line or straight object is the ratio of how much amount of rise occurs in correspondence to the increment in the run.

Thus, we get:

Slope = rise/ run

y-y₁ = m(x-x₁)

We are given that;

The points =(-3 -2) and (7,2)

Now,

For this line, let’s use (-3, -2) and (7, 2) as the two points. Plugging these values into the formula, we get:

m = (2 - (-2)) / (7 - (-3)) = 4 / 10 = 0.4

Therefore, the slope of this line is 0.4.

A positive slope means that the line goes up from left to right3. A negative slope means that the line goes down from left to right3.

Since 0.4 is a positive number,

Therefore, the slope of this line will be positive.

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Gabriellas school is selling tickets to a fall musical. On the dirst day of ticket sales the school sold 10 senior citizen tickets and 14 student tickets for a total of $212. Tje school took in$232 on the second day by selling 12 senior citizen tickets and 14 student tickets. What is the price each of one senior citizen tickets and one student ticket?

Answers

A senior ticket costs $10, while a student ticket costs $8. You can solve this system of equations by the elimination method.

We can use x as the variable for the senior tickets, and y as the variable for the student tickets and represent it with these equations:
10x+12y=212 and 12x+14y=232

Next, multiply each entire equation by a variable so they can eliminate each other. I used 12 and -10 here so it would be 120x-120x to eliminate that variable.
12(10x+14y=212) and -10(12x+14y=232)

Our new equations are:
(120x +168y= 2544) and (-120x-140y=-2320)

You can then subtract one of the equations from the other leaving you with 28y=224 and solve it for y to get 8.
So the price of a student ticket is 8.

Pick any of the original equations and by replacing y with 8, you can solve to find x. (X is the variable we assigned for senior tickets)
10x+14(8)=212
10x+112=212
10x=212-112
10x= 100
1x=10

shayna had $22 to spend on six notebooks. After buying them she had $10. How much did each notebook cost ? solving equations: application
equation and a solution

Answers

Answer:

Each notebook costs $2

Step-by-step explanation:

We have to find the amount she spent on each notebook.

22-10=12

We know she spent $12 on six notebooks

We need to divide to find the answer

12/6=2

Each notebook costs $12

Answer:

$2

Step-by-step explanation:

First subtract 10 from 22 to get the price she spent on notebooks which is $12.

Then divide 12 by 6 to get the price she spent on each which is, $2

Find 2.4% of $109. Show work.

Answers

Answer:

$2.62

Step-by-step explanation:

[tex]2.4\% \: of \: \$109 \: \\ \\ = \frac{2.4}{100} \times 109 \\ \\ = 0.024 \times 109 \\ \\ = \$2.616 \\ \\ \approx \: \$2.62[/tex]

4x-6 + 2x = 18
What’s the answer

Answers

Answer:

x=4

Step-by-step explanation:

4x-6 + 2x = 18

Combine like terms

6x -6 = 18

Add 6 to each side

6x-6+6 =18+6

6x = 24

Divide each side by 6

6x/6 = 24/6

x =4

One side of a square has a value of 3x+2, find the perimeter of the square

Answers

Answer:

P = 12x +8

Step-by-step explanation:

The perimeter of a square is given by

P = 4s  where s is the side length

P = 4(3x+2)

Distribute

P = 12x +8

Answer:

[tex]12x+8[/tex]

Step-by-step explanation:

[tex]3x+2[/tex] for one side of a square, for a perimeter for the square we need 4 times the side length, so we need:

[tex]4(3x+2)=12x+8[/tex]

suppose you deposit $3000 in a savings account that pays interest at an annual rate of 4%. if no other money is added or withdrawn from the account how much will be in the account after 10 years?

Answers

$3000 x .04 =$120
$120 x 10 =$1200
$3000+1200= $4200 Total

If no other money is added or withdrawn from the account how much will be in the account after 10 years is $4,440.73.

Simple interest

Using this formula

Amount=Principla(1+Interest rate)^ Time

Let plugm in the formula]

Amount=$3,000(1+0.04)^10

Amount=$3,000(1.04)^10

Amount-$3,000(1.4802442849)

Amount=$4,440.73

Therefore how much will be in the account after 10 years is $4,440.73.

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The Information Technology Department at a large university wishes to estimate the proportion of students living in the dormitories, p, who own a computer with a 99% confidence interval. What is the minimum required sample size the IT Department should use to estimate the proportion p with a margin of error no larger than 5 percentage points

Answers

Answer:

[tex]n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16[/tex]  

And rounded up we have that n=385

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by [tex]\alpha=1-0.99=0.01[/tex] and [tex]\alpha/2 =0.005[/tex]. And the critical value would be given by:

[tex]z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58[/tex]

The margin of error for the proportion interval is given by this formula:  

[tex] ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex]    (a)  

And on this case we have that [tex]ME =\pm 0.05[/tex] and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

[tex]n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}[/tex]   (b)  

We can use as an estimator for p [tex]\hat p =0.5[/tex]. And replacing into equation (b) the values from part a we got:

[tex]n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16[/tex]  

And rounded up we have that n=385

What is the area of a triangle with a base of 23 feet and a height of 6 feet

Answers

Answer:

A= 69

Step-by-step explanation:

A= h*b/2= (6*23)/2=69

Answer:

A = 69 [tex]ft^{2}[/tex]

Step-by-step explanation:

The formula utilised to determine the area of a triangle is:

A = [tex]\frac{1}{2}[/tex] * b * h

The base and height are given, and thus, can easily be substituted for in the formula to find the area.

A = [tex]\frac{1}{2}[/tex] * 23 * 6

A = 69 [tex]ft^{2}[/tex]

A college admissions director wishes to estimate the mean age of all students currently enrolled. In a random sample of 20 students, the mean age is found to be 22.9 years. From past studies, the standard deviation is known to be 1.5 years, and the population is normally distributed. Construct a 90% confidence interval of the population mean age.

Answers

Answer:

90% confidence interval: (22.35,23.45)

Step-by-step explanation:

We are given the following in the question:

Sample mean, [tex]\bar{x}[/tex] = 22.9 years

Sample size, n = 20

Alpha, α = 0.10

Population standard deviation, σ = 1.5 years

90% Confidence interval:

[tex]\bar{x} \pm z_{critical}\dfrac{\sigma}{\sqrt{n}}[/tex]

Putting the values, we get,

[tex]z_{critical}\text{ at}~\alpha_{0.05} = \pm 1.64[/tex]

[tex]22.9 \pm 1.64(\dfrac{1.5}{\sqrt{20}} )\\\\ = 22.9 \pm 0.55 \\\\= (22.35,23.45)[/tex]

(22.35,23.45) is the required 90% confidence interval for population mean age.

Final answer:

The 90% confidence interval for the population mean age, from the given data, is approximated to be between 22.46 years and 23.34 years.

Explanation:

To construct a 90% confidence interval of the population mean age, we will use the formula for the confidence interval, which is sample mean ± Z-score * (Standard deviation/ sqrt (sample size)), where the Z-score is based on the confidence level. For 90%, the Z-score is 1.645.

So in this case, the sample mean is 22.9 years, the known standard deviation is 1.5 years, and the sample size (n) is 20. Plugging these values into the formula gives:

22.9 ± 1.645 * (1.5 / sqrt (20))

When you calculate, it will give an interval of about 22.46 years to 23.34 years. Hence the 90% confidence interval for the population mean age is 22.46 years to 23.34 years.

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(1,4) (6,-1) what is the y intercept of the line and how did you find it?

Answers

Answer:

Step-by-step explanation:

(1,4) (6,-1)

1-6= -5

6--1= 7 its 7 because 6 minus negative 1 would be 7

-5/7  would be your slope

---------------------------------------------------

y=mx+b

y= -5/7x+b

-1= -5/7(6)+b

-1= 6[tex]\frac{-5}{7}[/tex]+b

you take those two numbers and subtract

5 [tex]\frac{-5}{7}[/tex] is y intercept

y=[tex]\frac{-5}{7}[/tex]x+5[tex]\frac{-5}{7}[/tex]

5-2+12÷4
use the order of operations

Answers

Step-by-step explanation:

= 5- 2 + 12 /4

= 5 -2 + 3

= 8- 2

= 6

Answer:

6

Explanation:

What you do is you take 12 divided by 4 and you get 3. The equation is now 5-2+3, you subtract 2 from 5 and get 3. Now you have 3 plus 3 which gets you 6.

g The Enigma machine was used by Germany in World War II to send coded messages. It has gained fame because it was an excellent coding device for its day and because of the ultimately successful efforts of the British (with considerable aid from the Poles) to crack the Enigma code. The breaking of the code involved, among other things, some very good mathematics developed by Alan Turing and others. One part of the machine consisted of three rotors, each containing the letters A through Z. To read an encrypted message, it was necessary to determine the initial settings of the three rotors (e.g., PDX or JJN). This is only the beginning of the problem of deciphering the Enigma code. Other parts of the machine allowed for many more initial settings. How many different initial settings of the three rotors are there

Answers

Answer:

17576

Step-by-step explanation:

Each of the three rotors contained the letters A through Z.

For the first rotor: There are 26 Possible Initial Settings

(A,B,...Z)

For the second rotor: There are 26 possible initial combination with the first rotor likewise.

For the third rotor:There are also 26 possible combinations with the first and second rotors.

Therefore:

Number of Possible Initial Setting of the three rotor=26*26*26=17576

What is the volume of this rectangular prism? 2 cm 1/4 cm 2 cm

Answers

Answer:

1 cm cubed

Step-by-step explanation:

The volume of a rectangular prism is found by the equation: [tex]V=lwh[/tex] , where [tex]l[/tex] is the length, w is the width, and h is the height.

Here, our dimensions are 2 by 1/4 by 2. So: [tex]l=2,w=1/4,h=2[/tex].

Substituting these into the equation, we have:

[tex]V=2*(1/4)*2=1[/tex]

Thus, the volume is 1 cm cubed.

Hope this helps!

Answer:

1

Step-by-step explanation:

2*2=4

4*1/4=1

multiplying 1/4 is the same as dividing by 4

he amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and standard deviation 1.4 minutes. Suppose that a random sample of n equals 47 customers is observed. Find the probability that the average time waiting in line for these customers is

Answers

Complete question:

He amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and standard deviation 1.4 minutes. Suppose that a random sample of n equals 47 customers is observed. Find the probability that the average time waiting in line for these customers is

a) less than 8 minutes

b) between 8 and 9 minutes

c) less than 7.5 minutes

Answer:

a) 0.0708

b) 0.9291

c) 0.0000

Step-by-step explanation:

Given:

n = 47

u = 8.3 mins

s.d = 1.4 mins

a) Less than 8 minutes:

[tex]P(X<8) = P \frac{X'-u}{s.d/ \sqrt{n}} < \frac{8-8.3}{1.4/ \sqrt{47}}][/tex]

P(X' < 8) = P(Z< - 1.47)

Using the normal distribution table:

NORMSDIST(-1.47)

= 0.0708

b) between 8 and 9 minutes:

P(8< X' <9) =[tex] [\frac{8-8.3}{1.4/ \sqrt{47}}< \frac{X'-u}{s.d/ \sqrt{n}} < \frac{9-8.3}{1.4/ \sqrt{47}}][/tex]

= P(-1.47 <Z< 6.366)

= P( Z< 6.366) - P(Z< -1.47)

Using normal distribution table,

[tex] NORMSDIST(6.366)-NORMSDIST(-1.47) [/tex]

0.9999 - 0.0708

= 0.9291

c) Less than 7.5 minutes:

P(X'<7.5) = [tex] P [Z< \frac{7.5-8.3}{1.4/ \sqrt{47}}] [/tex]

P(X' < 7.5) = P(Z< -3.92)

NORMSDIST (-3.92)

= 0.0000

What is the equation of the line that goes through the points (1,2) and (2,1)?

Answers

Answer:

y = -x+3

Step-by-step explanation:

We have two points so we can find the slope

m =(y2-y1)/(x2-x1)

    (1-2)/(2-1)

    -1/1

 The slope is -1

We can use the slope intercept form of the equation

y = mx+b where m is the slope and b is the y intercept

y = -x+b

Substitute a point into the equation to find b

2 = -1 +b

Add 1 to each side

2+1 =-1+1 +b

3 =b

y = -x+3

I have 3 Sisters each
Sister has 3 sisters. How
many of us are there?​

Answers

Answer:

4 sisters

Step-by-step explanation:

-This is a logic question.

-Given that she has 3 sisters, it only means that the 4 are siblings of the same family.

-As such, eaxh sister can correctly claim to have 3 sisters.

Hence, there is a total of 4 sisters.

ten times a number increased by 150

Answers

Hey there!

"A number" is referred to an unknown number so we can say it is labled as

[tex]x[/tex]

"Increased" means you're going up/ adding

ten = 10

150 stays the same

"Ten times a number" =

[tex] \bf{10x}[/tex]

"Increased by 150" =

[tex] \bf{ + 150}[/tex]

Thus your answer should look like this:

[tex] \bf{10x + 150}[/tex]

Good luck on your assignment and enjoy your day!

~

[tex] \frak{loveyourselffirst }[/tex]

Final answer:

To solve this problem, we can use the algebraic expression 10x + 150, where 'x' represents the number.

Explanation:

To solve the problem, we can translate the given phrase into an algebraic expression. Let's assume the number is represented by the variable 'x'. 'Ten times a number increased by 150' can be written as 10x + 150. This expression represents ten times the number 'x' plus 150.

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A company that makes shampoo wants to test whether the average amount of shampoo per bottle is 16 ounces. The standard deviation is known to be 0.20 ounces. Assuming that the hypothesis test is to be performed using 0.10 level of significance and a random sample of n = 64 bottles, how large could the sample mean be before they would reject the null hypothesis? Question 50 options: 16.2 ounces 16.041 ounces 15.8 ounces 16.049 ounces

Answers

Answer:

The correct option is 16.041 ounces.

Step-by-step explanation:

A single mean test can be used to determine whether the average amount of shampoo per bottle is 16 ounces.

The hypothesis can be defined as:

H₀: The average amount of shampoo per bottle is 16 ounces, i.e. μ = 16.

Hₐ: The average amount of shampoo per bottle is different from 16 ounces, i.e. μ ≠ 16.

The information provided is:

[tex]n=64\\\sigma=0.20\\\alpha =0.10[/tex]

We can compute a 90% confidence interval to determine whether the population mean is 16 ounces or not.

Since the population standard deviation is known we will compute the z-interval.

The critical value of z for 90% confidence interval is:

[tex]z_{0.05}=1.645[/tex]

*Use a z-table.

Compute the 90% confidence interval for population mean as follows:

[tex]CI=\bar x\pm z_{\alpha/2}\times\frac{\sigma}{\sqrt{n}}\\[/tex]

Since the sample size is quite large, according to the law of large numbers the on increasing the sample size, the mean of the sample approaches the whole population mean.

So, the 90% confidence interval estimate for sample mean is:

[tex]CI=\mu\pm z_{\alpha/2}\times\frac{\sigma}{\sqrt{n}}\\=16\pm 1.645\times \frac{0.20}{\sqrt{64}}\\=16\pm0.041125\\=(15.958875, 16.041125)\\\approx (15.959, 16.041)[/tex]

Thus, the correct option is 16.041 ounces.

g Suppose that the number of bacteria in a certain population increases according to a continuous exponential growth model. A sample of 3000 bacteria selected from this population reached the size of 3145 bacteria in one and a half hours. Find the hourly growth rate parameter. Note: This is a continuous exponential growth model. Write your answer as a percentage. Do not round any intermediate computations, and round your percentage to the nearest hundredth.

Answers

Answer:

The hourly growth rate is of 3.15%

Step-by-step explanation:

The population of bacteria after t hours can be modeled by the following formula:

[tex]P(t) = P(0)e^{rt}[/tex]

In which P(0) is the initial population and r is the hourly growth parameter, as a decimal.

A sample of 3000 bacteria selected from this population reached the size of 3145 bacteria in one and a half hours. Find the hourly growth rate parameter.

This means that [tex]P(0) = 3000, P(1.5) = 3145[/tex]

We use this to find r.

[tex]P(t) = P(0)e^{rt}[/tex]

[tex]3145 = 3000e^{1.5r}[/tex]

[tex]e^{1.5r} = \frac{3145}{3000}[/tex]

[tex]\ln{e^{1.5r}} = \ln{\frac{3145}{3000}}[/tex]

[tex]1.5r = \ln{\frac{3145}{3000}}[/tex]

[tex]r = \frac{\ln{\frac{3145}{3000}}}{1.5}[/tex]

[tex]r = 0.0315[/tex]

The hourly growth rate is of 3.15%

Arlin has 9 dollars and 37 cents. Lauren has 6 dollars and 63 cents. How much money does Arlin need to give Lauren so that each of them has the same amount of money?

Answers

Answer:

Arlin has to give lauren 1.37

Step-by-step explanation:

9.37 + 6.63 / 2 = 16 / 2 = 8

9.37 - 8 = 1.37

Answer:

$1.37

Step-by-step explanation:

I would start by adding up the total money between them. $9.37 + $6.63 = $16.00. They want the same amount of money, so divide the total by two.

$16.00/2 = $8.00.

Now take the difference between how much Arlin had ($9.37) and how much she has now ($8.00).

$9.37 - $8.00 = $1.37

An ethanol railroad tariff is a fee charged for shipments of ethanol on public railroads. An agricultural association publishes tariff rates for​ railroad-car shipments of ethanol. Assuming that the standard deviation of such tariff rates is ​$1250​, determine the probability that the mean tariff rate of 350 randomly selected​ railroad-car shipments of ethanol will be within ​$110 of the mean tariff rate of all​ railroad-car shipments of ethanol. Interpret your answer in terms of sampling error.

Answers

Answer:

The probability that the mean is less than 110

P(x⁻<110) =0.5

Step-by-step explanation:

Explanation:-

Given the standard deviation of the Population' σ' = 1250

Given sample size 'n' = 350

The standard error of the mean determined by

                                                                             [tex]S.E = \frac{S.D}{\sqrt{n} }[/tex]

                                             Standard error = [tex]\frac{1250}{\sqrt{350} } = 66.8153[/tex]

  by using normal distribution    [tex]z = \frac{x -mean}{S.E}[/tex]

                                         [tex]z = \frac{x^{-} -110}{66.8}[/tex]

                                   cross multiplication  66.8z = x⁻-110

                                                                         x⁻  =  66.81Z+110

P(x⁻<110)=P(66.81Z+110<110)

             = P(66.81Z < 110-110)

            = P(66.81Z<0)

           = P(Z<0)

           = 0.5- A(z₁)

          = 0.5 - A(0)  (here z₁=0)

         = 0.5 -0.00

        =0.5

                                     

Conclusion:-                            

The probability that the mean is less than 110

P(x⁻<110) =0.5

Suppose the allowable increase and decrease for an objective coefficient of a decision variable that has a current value of $50 are $25 (increase) and $10 (decrease). If the coefficient were to change from $50 to $60, the optimal value of the objective function would not change.

1.True
2.False

Answers

I think it’s true. I remember learning about it but I think it’s TRuE

Jamie places fifteen 1 inch cubes in the bottom of a box. She adds 4 more layers of the same number of cubes to completely fill the box. What is the volume of the box?

Answers

Answer:

60

Step-by-step explanation:

15cubes assuming 3rows of 5 cubes in one layer so volume of first layer is 3x5x1 =15

4 layers means 4 times or 4 inch in height, either way 4x15 = 60

Answer:

75

Step-by-step explanation:

what is 943 divide by 4

Answers

Answer:

235.75

Step-by-step explanation:

Answer:

Math answers to fraction 943 divided by 4 can be calculated as follows.

943/4 math problems division = 235.75. Therefore 235.75 to 2 decimal places= 235.75

943/4 divided by 2 » (943/4) ÷ 2 » 235.75 ÷ 2 = 117.875 .

Step-by-step explanation:

if i have 5 blue pens and 3 black pens, What fraction of the number of black pens is the number of blue pens?

Answers

Answer:

the answer to the question is 3/5

A certain pen has been designed so that true average writing lifetime under controlled conditions (involving the use of a writing machine) is at least 10 hr. A random sample of 18 pens is selected, the writing lifetime of each is determined, and a normal probability plot of the resulting data support the use of a one-sample t test. The relevant hypotheses are H0: µ = 10 versus Ha: µ < 10.(a) If t = -2.4 and = .05 is selected, what conclusion is appropriate?a. Rejectb. Fail to reject(b) If t = -1.83 and = .01 is selected, what conclusion is appropriate?a. Rejectb. Fail to reject(c) If t = 0.57, what conclusion is appropriate?a.Rejectb. Fail to reject

Answers

Answer:

(a) We reject our null hypothesis.

(b) We fail to reject our null hypothesis.

(c) We fail to reject our null hypothesis.

Step-by-step explanation:

We are given that a certain pen has been designed so that true average writing lifetime under controlled conditions (involving the use of a writing machine) is at least 10 hr.

A random sample of 18 pens is selected.

Let [tex]\mu[/tex] = true average writing lifetime under controlled conditions

So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu \geq[/tex] 10 hr   {means that the true average writing lifetime under controlled conditions is at least 10 hr}

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] < 10 hr    {means that the true average writing lifetime under controlled conditions is less than 10 hr}

The test statistics that is used here is one-sample t test statistics;

                           T.S. = [tex]\frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }[/tex]  ~ [tex]t_n_-_1[/tex]

where, [tex]\bar X[/tex] = sample mean

             s = sample standard deviation

             n = sample size of pens = 18

          n - 1 = degree of freedom = 18 -1 = 17

Now, the decision rule based on the critical value of t is given by;

If the value of test statistics is more than the critical value of t at 17 degree of freedom for left-tailed test, then we will not reject our null hypothesis as it will not fall in the rejection region.If the value of test statistics is less than the critical value of t at 17 degree of freedom for left-tailed test, then we will reject our null hypothesis as it will fall in the rejection region.

(a) Here, test statistics, t = -2.4 and level of significance is 0.05.

Now, at 0.05 significance level, the t table gives critical value of -1.74 at 17 degree of freedom.

Here, clearly the value of test statistics is less than the critical value of t as -2.4 < -1.74, so we reject our null hypothesis.

(b) Here, test statistics, t = -1.83 and level of significance is 0.01.

Now, at 0.051 significance level, the t table gives critical value of -2.567 at 17 degree of freedom.

Here, clearly the value of test statistics is more than the critical value of t as -2.567 < -1.83, so we fail to reject our null hypothesis.

(c) Here, test statistics, t = 0.57 and level of significance is not given so we assume it to be 0.05.

Now, at 0.05 significance level, the t table gives critical value of -1.74 at 17 degree of freedom.

Here, clearly the value of test statistics is more than the critical value of t as  -1.74 < 0.57, so we fail to reject our null hypothesis.

What is the effect of visualizing the hole as bigger A taking longer to play golf B worse golf scores C selecting larger circles D better golf score

Answers

Answer:

better golf scores

Step-by-step explanation:

i did the quiz just a few secs ago

According to the excerpt, seeing the "hole as bigger" has the benefit of improving gold scores. The right answer is D.

How can imagining larger gaps in scores help?

Visualization is the capacity to create mental images of situations and things using one's imagination.

Visualization enhanced results in the excerpt provided.

Golfers typically earned better gold scores when they saw the golf hole as larger circles.

The result of seeing the "hole as greater" is that you will receive better gold scores.

Learn more about visualization at:

brainly.com/question/1569390

#SPJ6

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