Final answer:
Using the principle of inclusion-exclusion, it's calculated that 25% of the teachers surveyed had neither high blood pressure nor heart trouble.
Explanation:
To find the percentage of teachers who had neither high blood pressure nor heart trouble, we can use the principle of inclusion-exclusion in set theory. We begin by adding the number of teachers with each condition, then subtract those counted twice because they have both conditions.
The formula we will use is:
Total surveyed - (High blood pressure + Heart trouble - Both) = Neither condition
Substituting the numbers from the survey, we get:
120 - (70 + 40 - 20) = 120 - (90) = 30
So, 30 teachers had neither high blood pressure nor heart trouble.
To find the percentage, we divide the number of teachers with neither condition by the total surveyed and then multiply by 100:
(30 / 120) * 100 = 25%
Therefore, 25% of the teachers surveyed had neither high blood pressure nor heart trouble.
A grain silo has a cylindrical shape. Its radius is 9 ft, and its height is 53 ft. What is the volume of the silo?
Use the value 3.14 forn, and round your answer to the nearest whole number.
Be sure to include the correct unit in your answer.
Answer:
13487 ft³
Step-by-step explanation:
Volume of a Cylinder: 2πr²*h
π = 3.14
r = 9 ft
h = 53 ft
Volume = 2(3.14)(9)²*53 = 13486.86 ft³
Rounded to nearest whole number
Volume of the Cylindrical Water tank is 13487 ft³
The volume of the cylindrical grain silo is found using the formula V = πr²h, where r is the radius and h is the height. Using the specifications of the silo (r=9 feet, h=53 feet), we find that the volume of the grain silo is about 13480 cubic feet.
Explanation:The student is trying to find the volume of a cylinder. The volume V of a cylinder can be found using the formula: V = πr²h where r is the radius of the base, h is the height and π is about 3.14.
To find the volume V of the grain silo, first, square the radius r, which is 9 feet: 81 square feet. Then multiply the result by the height h, which is 53 feet: 4293 cubic feet. Lastly, multiply the result by π, which we should approximate as 3.14: 13480 cubic feet rounded to the nearest whole number.
So, the volume of the grain silo is about 13480 cubic feet.
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A total of 517 tickets were sold for the school play. They were either adult tickets or student tickets. There were 67 more student tickets sold than adult tickets. How many adult tickets were sold?
The number of adult tickets sold for the school play was 225.
Explanation:This is a problem of simple algebra. Let's denote the number of adult tickets sold as a. It is stated in the problem that 67 more student tickets were sold than adult tickets. Therefore, we can denote the number of student tickets sold as a + 67. The problem also tells us that a total of 517 tickets were sold. Hence, we can form an equation: a + a + 67 = 517. Simplifying this equation gives us 2a + 67 = 517. And solving for a (the number of adult tickets) we subtract 67 from both sides to get 2a = 450, then divide by 2, gives us a = 225. So, 225 adult tickets were sold.
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XYZ company uses "Continuous Review System (Q, ROP)" for an item. Lead-time is currently one week. The average demand during the week is 100 units with a standard deviation of 20 units. If the supplier increases lead-time to 4 weeks, what will be the standard deviation of lead-time demand?
a.40 80
b.17.89
c.44.72
d.120
Answer:
The demand value of time lead is
a) 40
Step-by-step explanation:
X Y Z company Uses "Continuous Review System for an item
Currently demand = 100 units
standard deviation = 20 units
lead time increase = 4 weeks
Apply Z statistic we get the value of standard deviation.
For every 60 phone calls that Linda made in a month, she received 70 phone calls. What is the ratio in simplest form of the number of calls made to the number of calls received by Linda that month?
Ans6:7
wer:
Step-by-step explanation:
Greatest Common Factornof 60 and 70 is 10.
60÷10 / 70÷10 =6/7
The number of surface flaws in a plastic roll used for auto interiors follows a Poisson distribution with a mean of 0.05 flaw per square foot . Each car contains 10 ft2 of the plastic roll and ten (10) of the cars are sold to a particular rental agency. a) What is the probability that there are no flaws in a given car’s interior
Answer:
0.6065
Step-by-step explanation:
Probability mass function of probability distribution : [tex]P(X=x)=\frac{e^{-\lambda} \times \lambda^x}{x !}[/tex]
a mean of 0.05 flaw per square foot
Each car contains 10 sq.feet of the plastic roll
Mean = 0.05
Mean = [tex]\lambda = 0.05 \times 10=0.5[/tex]
We are supposed to find What is the probability that there are no flaws in a given car’s interior i.e,P(X=0)
Substitute the value in the formula
[tex]P(X=0)=\frac{e^{-0.5} \times (0.5)^0x}{0 !}[/tex]
[tex]P(X=0)=\frac{e^{-0.5} \times (0.5)^0}{1}[/tex]
[tex]P(X=0)=0.6065[/tex]
Hence the probability that there are no flaws in a given car’s interior is 0.6065
A golf-course architect has sixsix linden trees, fourfour white birch trees, and threethree bald cypress trees to plant in a row along a fairway. In how many ways can the landscaper plant the trees in a row, assuming that the trees are evenly spaced?
Answer: There are 60060 ways to do so.
Step-by-step explanation:
Since we have given that
Number of linden trees = 6
Number of white birch trees = 4
Number of bald cypress trees = 3
Total number of trees = 6 +4 +3 =13
So, Number of ways that the landscaper plant that trees are evenly spaced is given by
[tex]\dfrac{13\!}{6!\times 4!\times 3!}\\\\=60060[/tex]
Hence, there are 60060 ways to do so.
university administrators are becoming more and more alarmed at the number of hours students work per week while attending the university. To study this issue, one administrator was assigned to examine the relationship between the number of hours worked per week in a semester and that semester's GPA for a random sample of students.In this study, what is the explanatory variable?
Answer:
The number of hours worked per week
Step-by-step explanation:
To study this issue, one administrator was assigned to examine the relationship between the number of hours worked per week in a semester and that semester's GPA for a random sample of students.
Here the explanatory variable is - the number of hours worked per week.
An explanatory variable or also called an independent variable, is the variable that is manipulated by the researcher based on the variations in the response variable of an experimental study.
The price of an item yesterday was $140. Today, the price fell to $91. Find the percentage decrease.
Answer:
65% decrease
Step-by-step explanation:
65% of 140 = 91
Answer:
The price of an item yesterday was $140. Today, the price fell to $91. The percentage decrease is 35%
Explanation:
To find the percentage decrease of a number we first find the difference between the two given numbers, this difference is called the decrease.So we are given a decrease from $140 to $91 ,
the difference = 140 - 91 = 49
Now to find percent decrease we first divide the difference with the original number i.e 140 and
[tex]\frac{49}{140}=0.35[/tex]
[tex]0.35 \times 100[/tex] = 35%
which is the value of percentage decrease.
Telephone calls arrive at a doctor’s office according to a Poisson process on the average of two every 3 minutes. Let X denote the waiting time until the first call that arrives after 10 a.m.
(a) What is the pdf of X?
(b) Find P(X > 2).
Answer:
a) [tex]f(x)=\frac{2}{3}e^{-\frac{2}{3}x}[/tex] when [tex]x\geq 0[/tex]
[tex]f(x)=0[/tex] otherwise
b) [tex]P(X<2)=0.2636[/tex]
Step-by-step explanation:
First of all we have a Poisson process with a mean equal to :
μ = λ = [tex]\frac{2}{3}[/tex] (Two phone calls every 3 minutes)
Let's define the random variable X.
X : ''The waiting time until the first call that arrives after 10 a.m.''
a) The waiting time between successes of a Poisson process is modeled with a exponential distribution :
X ~ ε (λ) Where λ is the mean of the Poisson process
The exponential distribution follows the next probability density function :
I replace λ = a for the equation.
[tex]f(x)=a(e)^{-ax}[/tex]
With
[tex]x\geq 0[/tex]
and
[tex]a>0[/tex]
[tex]f(x)=0[/tex] Otherwise
In this exercise λ= a = [tex]\frac{2}{3}[/tex] ⇒
[tex]f(x)=(\frac{2}{3})(e)^{-\frac{2}{3}x}[/tex]
[tex]x\geq 0[/tex]
[tex]f(x)=0[/tex] Otherwise
That's incise a)
For b) [tex]P(X>2)[/tex] We must integrate between 2 and ∞ to obtain the probability or either use the cumulative probability function of the exponential
[tex]P(X\leq x)=0[/tex]
when [tex]x<0[/tex]
and
[tex]P(X\leq x)=1-e^{-ax}[/tex] when [tex]x\geq 0[/tex]
For this exercise
[tex]P(X\leq x)=1-e^{-\frac{2}{3}x}[/tex]
Therefore
[tex]P(X>2)=1-P(X\leq 2)[/tex]
[tex]P(X>2)=1-(1-e^{-\frac{2}{3}.2})=e^{-\frac{4}{3}}=0.2636[/tex]
(A) The pdf of X, the waiting time until the first call after 10 a.m., is f(x; 2/3) = (2/3) * e^(-(2/3) * x), and, (B) the probability that X > 2 (the first call arrives more than 2 minutes after 10 a.m.) is approximately 0.264.
(a) To find the probability density function (pdf) of X, we first need to understand the arrival rate of the calls, which follows a Poisson process. In our case, the arrival rate (λ) is two calls every 3 minutes, which could also be expressed as 2/3 of a call per minute.
For a Poisson process, the waiting times between arrivals are exponentially distributed. Therefore, the pdf for X, the waiting time until the first call, is given by the exponential distribution function.
The exponential distribution has the following pdf:
f(x; λ) = λ * e^(-λ * x)
In our case, substituting λ = 2/3 (the arrival rate per minute), the pdf of waiting time X becomes:
f(x; 2/3) = (2/3) * e^(-(2/3) * x)
(b) The second part of the question asks for the probability that the waiting time until the first call, X, is greater than 2 minutes.
For an exponential distribution, the cumulative distribution function (CDF), which gives the probability that a random variable is less than or equal to a certain value, is as follows:
F(x; λ) = 1 - e^(-λ * x)
We need P(X > 2), but it's easier to compute P(X <= 2), and then subtract that from 1.
So, we first find the cumulative probability that the waiting time is 2 minutes or less, using our given λ and x = 2:
P(X <= 2) = F(2; 2/3) = 1 - e^(-(2/3) * 2)
After calculating, this probability is approximately 0.736.
Therefore, the probability that waiting time X is greater than 2 minutes, P(X > 2), is simply 1 minus this result, which approximately equals to 0.264.
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Plz explain your answer.
Answer:
[tex]\overline{BD}\ and\ \overline{AC}[/tex] bisect each other is sufficient to Prove Δ ABE ≅ Δ CDE
Step-by-step explanation:
Given: (if it is given)
[tex]\overline{BD}\ and\ \overline{AC}[/tex] bisect each other, i.e
AE ≅ CE
BE ≅ DE
To Prove:
Δ ABE ≅ Δ CDE
Proof:
In Δ ABE and Δ CDE
AE ≅ CE …………..{ BD and AC bisect each other at E}
∠ AEB ≅ ∠ CED ………….{Vertically opposite angles are equal}
BE ≅ DE ……….{ BD and AC bisect each other at E}
Δ ABC ≅ Δ PQR ….{Side-Angle-Side test} ......PROVED
Suppose that 7 female and 5 male applicants have been successfully screened for 5 positions. If the 5 positions are filled at random from the 12 finalists, what is the probability of selecting
a. 3 females and 2 males?
b. 4 females and 1 male?
c. 5 females?
d. at least 4 females?
a. ~0.442, b. ~0.221, c. 0, d. ~0.221. Calculated using combinations: [tex]\( \frac{C(n, k)}{C(12, 5)} \)[/tex].
To solve this problem, we can use the concept of combinations, which is a way to calculate the number of possible outcomes when order doesn't matter.
Let's define:
- [tex]\( n \)[/tex] as the total number of finalists (12 in this case)
- [tex]\( k \)[/tex] as the number of positions to be filled (5 in this case)
- [tex]\( n_F \)[/tex] as the number of female finalists (7 in this case)
- [tex]\( n_M \)[/tex] as the number of male finalists (5 in this case)
We'll use the formula for combinations:
[tex]\[ C(n, k) = \frac{n!}{k!(n - k)!} \][/tex]
where [tex]\( n! \)[/tex] represents the factorial of [tex]\( n \)[/tex], which is the product of all positive integers up to [tex]\( n \)[/tex].
a. Probability of selecting 3 females and 2 males:
[tex]\[ P(3 \text{ females, } 2 \text{ males}) = \frac{C(7, 3) \times C(5, 2)}{C(12, 5)} \][/tex]
[tex]\[ = \frac{\frac{7!}{3!4!} \times \frac{5!}{2!3!}}{\frac{12!}{5!7!}} \][/tex]
[tex]\[ = \frac{\frac{7 \times 6 \times 5}{3 \times 2 \times 1} \times \frac{5 \times 4}{2 \times 1}}{\frac{12 \times 11 \times 10 \times 9 \times 8}{5 \times 4 \times 3 \times 2 \times 1}} \][/tex]
[tex]\[ = \frac{35 \times 10}{792} \][/tex]
[tex]\[ = \frac{350}{792} \][/tex]
[tex]\[ \approx 0.442\][/tex]
b. Probability of selecting 4 females and 1 male:
[tex]\[ P(4 \text{ females, } 1 \text{ male}) = \frac{C(7, 4) \times C(5, 1)}{C(12, 5)} \][/tex]
[tex]\[ = \frac{\frac{7!}{4!3!} \times \frac{5!}{1!4!}}{\frac{12!}{5!7!}} \][/tex]
[tex]\[ = \frac{\frac{7 \times 6 \times 5}{3 \times 2 \times 1} \times \frac{5}{1}}{\frac{12 \times 11 \times 10 \times 9 \times 8}{5 \times 4 \times 3 \times 2 \times 1}} \][/tex]
[tex]\[ = \frac{35 \times 5}{792} \][/tex]
[tex]\[ = \frac{175}{792} \][/tex]
[tex]\[ \approx 0.221\][/tex]
c. Probability of selecting 5 females:
Since there are only 7 female finalists, it's impossible to select 5 females out of them for 5 positions. So, the probability is 0.
d. Probability of at least 4 females:
This includes the cases of selecting 4 females and 5 females.
[tex]$\begin{aligned} & P(\text { at least } 4 \text { females })=P(4 \text { females, } 1 \text { male })+P(5 \text { females }) \\ & =\frac{175}{792}+0 \\ & =\frac{175}{792} \\ & \approx 0.221\end{aligned}$[/tex]
So, the probabilities are:
a. Approximately 0.442
b. Approximately 0.221
c. 0
d. Approximately 0.221
A force of 7 pounds is required to hold a spring stretched 0.4 feet beyond its natural length. How much work (in foot-pounds) is done in stretching the spring from its natural length to 0.7 feet beyond its natural length?
Final answer:
Using Hooke's Law, the spring constant is calculated from the given force and stretch, which is then used to calculate the work done for a larger stretch. The work done in stretching the spring from its natural length to 0.7 feet is approximately 4.29 foot-pounds.
Explanation:
To solve this problem, we need to use Hooke's Law, which says that the force needed to stretch or compress a spring is directly proportional to the distance the spring is stretched or compressed from its natural length. The formula for the force on a spring is F = kx, where k is the spring constant and x is the stretch from the natural length.
First, we can find the spring constant using the information given: a force of 7 pounds to stretch the spring 0.4 feet beyond its natural length.
Calculate the spring constant k: k = F / x = 7 lb / 0.4 ft = 17.5 lb/ft.Next, we use the work done by a spring force equation: Work = (1/2)kx2. To find the work done in stretching from 0 to 0.7 feet, substitute x with 0.7 in the equation.Compute the work done: Work = (1/2)(17.5 lb/ft)(0.7 ft)2 = 4.2875 foot-pounds.Therefore, the work done in stretching the spring from its natural length to 0.7 feet is approximately 4.29 foot-pounds.
Parallelograms ABCD and EFGH are similar figures because angles A, B, C, and D are congruent to angles E, F, G, and H, respectively. If DA equals 8 units, AB equals 11 units, and HE equals 32 units, what does EF equal?
Answer:
It is 44
Step-by-step explanation:
If a total are of the chessboard is 144 square inches. What is the area of one shaded square. What is the total area of all the shaded squares and total area of all the white squares.
Answer: The area of one shaded square is 1 inch^2
The total area of all the shaded squares is 144/2 = 72 inches square
The total area of all the white squares is also 72 inches square
Step-by-step explanation:
If a total area of the chessboard is 144 square inches. The length of both sides are equal because it is a square. The formula for area is length ^2
The length of one side = √area
The length of one side = √144 = 12 inches
This means that both sides of the chessboard is 12 inches. Each side is divided into 12 partitions measuring 1 inch each. This forms a smaller square whose area is
1 inch by 1 inch. Therefore,
The area of one shaded square is
1 inch^2
The total area of the white squares and the shaded squares is 144. Therefore,
The total area of all the shaded squares is 144/2 = 72 inches square
The total area of all the white squares is also 72 inches square
Isabelle proves that the triangles are congruent by using the parallel lines to determine a second set of angles are congruent. What statement and reason could she have used? ∠ABC ≅ ∠BAC; corresponding angles of parallel lines are congruent. ∠CAB ≅ ∠DCB; alternate interior angles of parallel lines are congruent ∠ABC ≅ ∠DCB; alternate interior angles of parallel lines are congruent ∠ACD ≅ ∠ABD; corresponding angles of parallel lines are congruent.
Answer:
C
Step-by-step explanation:
The true statement is that proves the congruence of both triangles is:
∠ABC ≅ ∠DCB; alternate interior angles of parallel lines are congruent How to prove that angles are congruentFrom the complete question, we have the following highlights
Angles B and C are alternate interior anglesThe triangles are bounded by parallel linesThe above highlights mean that:
Angles ABC and DCB are congruent, by the theorem of alternate interior angles of parallel lines
Hence, the true statement is (c)
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This past weekend Miss Thomas did some hallelujah shopping. She bought three presents and says that she has 30% of her shopping finished. How many presents does she have left to purchase?
Answer: the number of presents that she has left to purchase is 6
Step-by-step explanation:
Let x represent the total number of presents that she has to purchase.
She bought three presents and says that she has 30% of her shopping finished. This means that she has finished (1/3 × x) = x/3 shopping. This is equivalent to 3 presents. Therefore,
x/3 = 3
x = 3×3 =9
She had 9 shopping to do
The number of shopping left will be total shopping that she has to do minus the shopping that she has done. It becomes
9 - 3 = 6
A model for the density δ of the earth’s atmosphere near its surface isδ=619.09−0.000097pwhere p (the distance from the center of the earth) is measured in meters and δ is measured in kilograms per cubic meter. If we take the surface of the earth to be a sphere with radius 6370 km, then this model is a reasonable one for:6.370×106≤p≤6.375×106 Use this model to estimate the mass of the atmosphere between the ground and an altitude of 5 km.
Final answer:
The mass of the Earth's atmosphere from the surface up to an altitude of 5 km can be estimated by integrating the given density model over the surface area of a spherical shell between the radii corresponding to the Earth's surface and the 5 km altitude.
Explanation:
We will use the given model for the density of the Earth's atmosphere near the surface, δ = 619.09 - 0.000097p, to estimate the mass of the atmosphere up to an altitude of 5 km. The radius of the Earth is 6370 km, which is 6.370×106 meters. The altitude of 5 km is 5,000 meters, so we are considering the range of p from 6.370×106 meters to 6.370×106 meters + 5,000 meters.
To estimate the mass of the atmosphere between these two altitudes, we need to integrate the density function δ(p) over the surface area of the sphere at each value of p. For a thin spherical shell, the volume dV is given by the surface area 4πp2 times a small change in radius dp. Therefore, the mass dm contained in a shell is δ(p) * 4πp2 * dp.
To find the total mass, we integrate this expression between the two radii, resulting in:
M = ∫ 6.370×1066.375×106 δ(p) * 4πp2 * dp
Upon performing this integration, we would obtain the estimated total mass of the atmosphere between the ground level and 5 km of altitude.
integral_(6.37×10^6)^(6.375×10^6) (619.09 - 0.000097 p) 4 (π p)^2 dp = 767*10^18
write the slope-intercept form of the equation for the line that passes through (4,9) and is parallel to the graph of the equation 5x-4y=8
Answer:
y=1.25x+4
Step-by-step explanation:
Two equations are paralell if they have the same slope.Then to find the paralell equation to [tex]5x-4y=8[/tex], we can do the following: clear out y as a function of x, to get the intercept and the slope that accompanies x.To do this, we follow the next steps: 1) subtract 5x both sides of the equation (which results in [tex]-4y=8-5x[/tex]; 2) divide both sides by (-4), would yield [tex]y=1.25x-2[/tex].Now we have an clear expression of y as a function of x, and can find a parallel line that passes through (x,y)=(4,9). This new equation shall be an expression that meets the following: 9=1.25 (4)+h, where we do not know the value of h, and the values of (x,y) have been replaced by the point required.If we solve the equation above, we obtain the value of h (intercept) for our parallel equation: h=4.Then, the parallel equation that passes through (4,9) is y=1.25x+4 (to verify this is ok, replace x=4 in this equation, and you will get y=9, which is what we were lloking for: a parallel equation to y=1.25x-2 that passes through (4,9)he brain volumes (cm cubedcm3) of 20 brains have a mean of 1103.81103.8 cm cubedcm3 and a standard deviation of 121.9121.9 cm cubedcm3. Use the given standard deviation and the range rule of thumb to identify the limits separating values that are significantly low or significantly high. For such data, would a brain volume of 1367.61367.6 cm cubedcm3 be significantly high?
Answer: We can say that brain volume of 1367.6 cubic cm would be significantly high.
Step-by-step explanation:
Since we have given that
n = 20 brains
Mean = 1103.8 cubic. cm
Standard deviation = 121.9 cubic. cm
According to range rule of thumb, the usual values must lie within 2 standard values from the mean.
So, it becomes,
[tex]\bar{x}-2\sigma\\\\=1103.8-2\times 121.9\\\\=1103.8-243.8\\\\=860[/tex]
and
[tex]\bar{x}+2\sigma\\\\=1103.8+2\times 121.9\\\\=1103.8+243.8\\\\=1225.7[/tex]
We can see that 1376.6 does not lie within (860,1225.7).
So, we can say that brain volume of 1367.6 cubic cm would be significantly high.
Simplify x^2+3x+2/x+1
A. X+2
B. X-2
C. X^2+1
D. X^2-1
Auto insurance Insurance companies collect annual pay-ments from drivers in exchange for paying for the cost of accidents.a) Why should you be reluctant to accept a $1500 pay-ment from your neighbor to cover his automobile accidents in the next year?b) Why can the insurance company make that offer
Answer:
Step-by-step explanation:
a) Because you are only receiving $1500 and in exchange you would have to cover for this accident damage in the next year, which could be up to hundred of thousands of dollar. Sure there's a chance the your neighbor might drive safely, but the odds are far more in his favor than yours.
b) The insurance company collect payments from hundred of thousands buyers, making their cash flow up to tens of million dollar. Sure the expected value of accidents might be high but as a company they surely have capital to cover a handful of cases, if their calculation done right.
Final answer:
One should be reluctant to accept a $1500 payment to cover a neighbor's car accidents due to the potential for costs to exceed this amount. Insurance companies, with their risk-pooling model, accumulate enough in premiums to cover accidents across a large customer base and manage risk effectively.
Explanation:
You should be reluctant to accept a $1500 payment from your neighbor to cover his automobile accidents for the next year because the cost of a potential accident could far exceed the amount collected. If your neighbor is involved in an accident, the resulting expenses for vehicle repairs, medical bills, or other damages could be much greater than $1500, leaving you responsible for the remainder of the costs.
On the other hand, an insurance company can make such an offer because they operate on a system of pooled risk. If each of the 100 drivers pays a $1,860 premium each year, the insurance company will collect a total of $186,000. This amount is calculated to cover the expected costs of accidents across their entire customer base, using statistics and probability to spread the risk among many policyholders. While some drivers may have no accidents, others may have expensive claims, but the total premiums collected can cover the aggregate cost of the accidents that occur.
Additionally, insurance companies can classify people into risk groups and adjust the premiums accordingly. For example, drivers with a good driving record may pay less than those with a history of accidents. This allows the company to minimize their risk while ensuring that those who are less likely to file a claim aren't subsidizing those with higher risks.
Melissa is purchasing a $160,000 home and her bank is offering her a 30-year mortgage at a 4.9% interest rate. In order to lower her monthly payment, Melissa will make a 20% down payment and will purchase 3 points. What will her monthly mortgage payment be?
Answer:650.46
Step-by-step explanation:
To calculate Melissa's monthly mortgage payment, we multiply the loan amount by the monthly interest rate, divide it by (1 - (1 + monthly interest rate) raised to the power of negative loan term in months), and finally substitute the values to get the monthly payment.
Explanation:To calculate Melissa's monthly mortgage payment, we need to consider the loan amount, interest rate, and loan term. Since she is making a 20% down payment on a $160,000 home, her loan amount will be 80% of $160,000, which is $128,000. Next, we need to calculate the monthly interest rate by dividing the annual interest rate by 12. For a 4.9% annual interest rate, the monthly interest rate is 0.049 divided by 12. Finally, we can use the formula for calculating the monthly payment on a mortgage:
Monthly Payment = (Loan Amount * Monthly Interest Rate) / (1 - (1 + Monthly Interest Rate)^(-Loan Term in Months))
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Select all irrational numbers
[tex]
\sqrt{9}=3\notin\mathbb{I} \\
\sqrt{12}=2\sqrt{3}\in\mathbb{I} \\
\sqrt{16}=4\notin\mathbb{I} \\
\sqrt{20}=2\sqrt{5}\in\mathbb{I} \\
\sqrt{25}=5\notin\mathbb{I}
[/tex]
Hope this helps.
Of the numbers shown, only √12 and √20 are irrational.
Here's why:
* Rational numbers: A rational number can be expressed as a fraction `p/q`, where `p` and `q` are integers and `q ≠ 0`.
* Irrational numbers: An irrational number cannot be expressed as a fraction `p/q`. It has a decimal representation that continues infinitely without repeating.
* √9 = 3: 3 is a rational number because it can be expressed as the fraction 3/1.
* √12: The square root of 12 cannot be simplified as a fraction. Its decimal representation is non-repeating and infinite (approximately 3.464), making it irrational.
* √16 = 4: 4 is a rational number because it can be expressed as the fraction 4/1.
* √20: The square root of 20 cannot be simplified as a fraction. Its decimal representation is non-repeating and infinite (approximately 4.472), making it irrational.
* √25 = 5: 5 is a rational number because it can be expressed as the fraction 5/1.
Therefore, the only irrational numbers in the image are √12 and √20.
A team of seven workers started a job, which can be done in 11 days. On the morning of the fourth day, several people left the team. The rest of team finished the job in 14 days. How many people left the team? Show your work in an equation
Number of workers left on fourth days is 3 after which the remaining workers completed the work in 14 days
Solution:Given that
A team of seven workers started a job, which can be done in 11 days.
On the morning of the fourth day, several people left the team. The rest of team finished the job in 14 days.
Need to determine how many people left the team.
Let say complete work be represented by variable W.
=> work done by 7 workers in 11 days = W
[tex]\Rightarrow \text {work done by } 1 \text { worker in } 11 \text { days }=\frac{\mathrm{W}}{7}[/tex]
[tex]\Rightarrow \text {work done by } 1 \text { worker in } 1 \text { day }=\frac{W}{7} \div 11=\frac{W}{77}[/tex]
As its given that for three days all the seven workers worked.
Work done by 7 worker in 3 day is given as:
[tex]=7 \times 3 \times \text { work done by } 1 \text { worker in } 1 \text { day }[/tex]
[tex]=7 \times 3 \times \frac{W}{77}=\frac{3W}{11}[/tex]
Work remaining after 3 days = Complete Work - Work done by 7 worker in 3 day
[tex]=W-\frac{3 W}{11}=\frac{8 W}{11}[/tex]
It is also given that on fourth day some workers are left.
Let workers left on fourth day = x
So Remaining workers = 7 – x
And these 7 – x workers completed remaining work in 14 days
[tex]\begin{array}{l}{\text { As work done by } 1 \text { worker in } 1 \text { day }=\frac{W}{77}} \\\\ {\text { So work done by } 1 \text { worker in } 14 \text { days }=\frac{W}{77} \times 14=\frac{2 \mathrm{W}}{11}} \\\\ {\text { So work done by } 7-x \text { worker in } 14 \text { days }=\frac{2 \mathrm{W}}{11}(7-x)}\end{array}[/tex]
As Work remaining after 3 days = [tex]\frac{8W}{11}[/tex] and this is the same work done by 7- x worker in 14 days
[tex]\begin{array}{l}{\Rightarrow \frac{\mathrm{8W}}{11}=\frac{2 \mathrm{W}}{11}(7-x)} \\\\ {=>4=7-x} \\\\ {=>x=7-4=3}\end{array}[/tex]
Workers left on fourth day = x = 3
Hence number of workers left on fourth days is 3 after which the remaining workers completed the work in 14 days.
equation:
4=7-x
answer:
3 people left the team.
Tristan and Ronna are collecting clothes for a clothing drive. Ronna collected 3 times as many clothes as Tristan did. If Tristan collected 4 1/4 bags of clothes, how many bags of clothes did Ronna collect?
Ronna collected [tex]12\frac{3}{4}[/tex] bags of clothes
Step-by-step explanation:
Tristan and Ronna are collecting clothes for a clothing drive
Ronna collected 3 times as many clothes as TristanTristan collected [tex]4\frac{1}{4}[/tex] bagsWe need to find how many bags of clothes Ronna collected
∵ Ronna collected 3 times as many clothes as Tristan did
- That means Ronna collected 3 × the amount that Tristan did
∵ Tristan collected [tex]4\frac{1}{4}[/tex] bags
- Multiply the amount of Tristan by 3 to find the amount of Ronna
∴ Ronna collected = 3 × [tex]4\frac{1}{4}[/tex]
Change the mixed number to improper fraction
∵ [tex]4\frac{1}{4}[/tex] = [tex]\frac{(4*4)+1}{4}=\frac{17}{4}[/tex]
∴ Ronna collected = 3 × [tex]\frac{17}{4}[/tex]
∴ Ronna collected = [tex]\frac{51}{4}[/tex]
Change the improper fraction to mixed number by divide 51 by 4
∵ 51 ÷ 4 = 12 and reminder 3 (4 × 12 = 48 and 51 - 48 = 3)
∴ [tex]\frac{51}{3}=12\frac{3}{4}[/tex]
∴ Ronna collected = [tex]12\frac{3}{4}[/tex] bags of clothes
Ronna collected [tex]12\frac{3}{4}[/tex] bags of clothes
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A cattle rancher is going to sell one of his prize bulls at an auction and would like to make $36,400 after paying a 9% commission to the auctioneer. For what selling price will the rancher make this amount of money?
Answer:
$40,000
Step-by-step explanation:
Let x represent the selling price of the bull.
We have been given that a cattle rancher would like to make $36,400 after paying a 9% commission to the auctioneer.
The commission would be 9% of selling price, that is [tex]\frac{9}{100}x=0.09x[/tex].
The profit of the rancher can be counted after paying off the commission that would be [tex]x-0.09x[/tex].
Since rancher wants to make $36,400 after paying a 9% commission, so we can represent this information in an equation as:
[tex]x-0.09x=36,400[/tex]
[tex]0.91x=36,400[/tex]
[tex]\frac{0.91x}{0.91}=\frac{36,400}{0.91}[/tex]
[tex]x=40,000[/tex]
Therefore, for a selling price of $40,000 the rancher will make the required amount of money.
Chen is keeping track of mileage to find out how many miles per gallon he gets in his truck. If he puts in 12 gallons of gas and has driven 212.4 miles since his last fill-up, how many miles per gallon does his truck get, to the nearest tenth?
Answer: 17.7
Step-by-step explanation:
212.4÷12 = 17.7
Answer: 17.7 miles per gallon
Step-by-step explanation:
Hi, to answer this question we have to divide the number of miles (212.4) by the number of gallons used (12).
Mathematically speaking:
212.4 /12 = 17.7 miles per gallon
17.7 is already rounded to the nearest tenth.
His truck gets 17.7 miles per gallon
Feel free to ask for more if needed or if you did not understand something.
What is the difference between an inscribed and a circumscribed shape?
Answer:
An inscribed shape is drawn inside of another shape . A circumscribed shape is the shape drawn on the outside or around another shape .
The box of a well-known breakfast cereal states that one ounce of the cereal contains 113 Calories (1 food Calorie = 4186 J). If 2.51% of this energy could be converted by a weight lifter's body into work done in lifting a barbell, what is the weight of the heaviest barbell that could be lifted a distance of 2.12 m?
Answer:
F = 49,56 Kgs
Step-by-step explanation:
We Know that 113 calories = 4186 J
Joules ( energy unit in MKS system meter, kilograms , second)
and 2,51 % of 4186 is 0,0251 * 4186 = 105.07 J
That the energy available
Work is W = F * d
where F is the force you have to apply and d is traveled distance
in this case F is the weight of the barbell
Then
F = W / d ⇒ F = 105.7 / 2.12 ⇒ F = 49,56 Kgs
Lucy goes to a department store and spends $90 on clothing.She buys a dress for $30,a hat for $12, and also buys a jacket.How much does the jacket cost?
Answer:
$48
Step-by-step explanation:
$30+$12=$42
$90-$42=$48
Answer: she spent $48 on the jacket
Step-by-step explanation:
Lucy goes to a department store and spends $90 on clothing. This means that all the money she spent at the store is $90
She buys a dress for $30,a hat for $12, and also buys a jacket.
Let $x = the cost of the jacket. Therefore, total amount spent at the store = amount spent on dress + amount spent on hat + amount spent on jacket. It means that
90 = 12 + 30 + x
x = 90 - 12 -30 = $48