A swimming pool is in the shape of a regular decagon. One edge of the pool is directly against the outside wall of a house. Find the measure x of the angle between the house and the pool.

Answers

Answer 1

Answer:

36 degrees.

Step-by-step explanation:

Total Sum of the Exterior Angle of a Regular Polygon[tex]=360^0[/tex]

One Exterior Angle of a n-sided regular polygon[tex]=\dfrac{360^0}{n}[/tex]

A decagon has 10 sides.

One Exterior Angle of a decagon[tex]=\dfrac{360^0}{10}=36^0[/tex]

Therefore, the measure x of the angle between the house and the pool is 36 degrees.

Answer 2

Final answer:

To find the measure x of the angle between the house and a pool shaped as a regular decagon, calculate the exterior angle of the decagon, which is 36 degrees. This is the angle measure sought in the question.

Explanation:

The question involves finding the measure x of the angle between the house and the pool, where the pool is in the shape of a regular decagon.

First, let's recall that a regular decagon is a ten-sided polygon with all sides and angles equal. The sum of the interior angles of any polygon can be calculated using the formula (n-2) × 180, where n is the number of sides. For a decagon, n = 10, so the sum of the interior angles is (10-2) × 180 = 1440 degrees. Since all angles in a regular decagon are equal, each interior angle measures 1440 ° / 10 = 144 °.

Now, to find the measure x of the angle between the house and the pool, we need to understand that the exterior angle of the decagon will be involved, as this is the angle made between one side of the decagon (lying against the house) and an extension of an adjacent side. The measure of an exterior angle of a regular polygon is 360 ° / n. For our decagon, this is 360 ° / 10 = 36 °.

Therefore, the measure x of the angle between the house and the pool is 36 °, which is the measure of the exterior angle of the regular decagon.


Related Questions

what is 81,007-26,318?

Answers

Answer:

54689

Step-by-step explanation:

You have inherited land that was purchased for $40,000 in 1990. The value of the land
increased by
approximately 5% per year. Which relationship would represent the value of the land in the
year 2020

Answers

Answer:

[tex]A(30)=40000(1.05)^{30}[/tex]

Step-by-step explanation:

Given that the land was purchased  for $40,000 in 1990, the initial amount/principal =$40,000

Since its value increases by approximately 5% per year, we can model this growth using the compound interest formula:

[tex]A=P(1+r)^n[/tex]

P=$40,000, r=5%=0.05, n=2020-1990=30 Years

Therefore, we have the value of the land in 30 years time to be:

[tex]A=40000(1+0.05)^{30}\\A(30)=40000(1.05)^{30}[/tex]

Since the options are not available, the relationship which represents the value of the land in the year 2020 is:

[tex]A(30)=40000(1.05)^{30}[/tex]

An experiment is carried out 400 times the possible outcomes are void fail and success if the frequency of void is 96 and the relative frequency is 0.24 then how much is the frequency of fail and success

Answers

the frequency of success is 244.

part b's answer is 240.

The relative Frequency of Fail is 0.15The relative Frequency of Success is 0.61 What is relative Frequency?

A relative frequency distribution shows the proportion of the total number of observations associated with each value or class of values and is related to a probability distribution, which is extensively used in statistics.

Relative frequency can be defined as the number of times an event occurs divided by the total number of events occurring in a given scenario. The relative frequency formula is given as:

Relative Frequency = Subgroup frequency/ Total frequency.

1. Frequency of success

=400 - 96 - 60

=244

relative frequency of fail

=60/400= 0.15

Relative Frequency of success

=1-0.15 - 0.24

=0.61

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A grocery store has an average sales of $8000 per day. The store introduced several advertising campaigns in order to increase sales. To determine whether or not the advertising campaigns have been effective in increasing sales, a sample of 64 days of sales was selected. It was found that the average was $8300 per day. From past information, it is known that the standard deviation of the population is $1200. The correct null hypothesis for this problem is

Answers

Answer:

We need to conduct a hypothesis in order to check if the true mean for sales is significantly higher than 8000, the system of hypothesis would be:  

Null hypothesis:[tex]\mu \leq 8000[/tex]  

Alternative hypothesis:[tex]\mu > 8000[/tex]  

[tex]z=\frac{8300-8000}{\frac{1200}{\sqrt{64}}}=2[/tex]    

[tex]p_v =P(z>2)=0.0228[/tex]  

Step-by-step explanation:

Data given  

[tex]\bar X=8300[/tex] represent the sample mean  for the sales

[tex]\sigma=1200[/tex] represent the population standard deviation

[tex]n=64[/tex] sample size  

[tex]\mu_o =8000[/tex] represent the value that we want to test

z would represent the statistic (variable of interest)  

System of hypothesis

We need to conduct a hypothesis in order to check if the true mean for sales is significantly higher than 8000, the system of hypothesis would be:  

Null hypothesis:[tex]\mu \leq 8000[/tex]  

Alternative hypothesis:[tex]\mu > 8000[/tex]  

The statistic to check this hypothesis is given by:

[tex]z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}[/tex]  (1)  

Calculate the statistic

[tex]t=\frac{8300-8000}{\frac{1200}{\sqrt{64}}}=2[/tex]    

P-value

Since is a one right tailed test the p value would be:  

[tex]p_v =P(z>2)=0.0228[/tex]  

How do I do a triangles heirarchy

Answers

Answer:

measure each side of the triangle and make sure it is right and then graph is out.

Step-by-step explanation:

Suppose that the population mean for income is $50,000, while the population standard deviation is 25,000. If we select a random sample of 1,000 people, what is the probability that sample will have a mean that is greater than $52,000?

Answers

Answer:

Probability that the sample will have a mean that is greater than $52,000 is 0.0057.

Step-by-step explanation:

We are given that the population mean for income is $50,000, while the population standard deviation is 25,000.

We select a random sample of 1,000 people.

Let [tex]\bar X[/tex] = sample mean

The z-score probability distribution for sample mean is given by;

               Z = [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex]  ~ N(0,1)

where, [tex]\mu[/tex] = population mean = $50,000

            [tex]\sigma[/tex] = population standard deviation = $25,000

            n = sample of people = 1,000

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the sample will have a mean that is greater than $52,000 is given by = P([tex]\bar X[/tex] > $52,000)

  P([tex]\bar X[/tex] > $52,000) = P( [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] > [tex]\frac{52,000-50,000}{\frac{25,000}{\sqrt{1,000} } }[/tex] ) = P(Z > 2.53) = 1 - P(Z [tex]\leq[/tex] 2.53)

                                                                    = 1 - 0.9943 = 0.0057

Now, in the z table the P(Z [tex]\leq[/tex] x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2.53 in the z table which has an area of 0.9943.

Therefore, probability that the sample will have a mean that is greater than $52,000 is 0.0057.

The probability that a sample of 1,000 people will have an average income greater than $52,000 is approximately 0.57%, calculated using the standard error and the z-score in a normal distribution.

To calculate the probability that a sample will have a mean that is greater than $52,000, we would use the Central Limit Theorem, which states that the sampling distribution of the sample mean will be normally distributed if the sample size is large enough, even if the population distribution itself is not normal. Since we have a large sample size of 1,000 in this case, we can assume that the sampling distribution of the sample mean is approximately normal.

The first step is to determine the standard error of the mean, which is calculated as the population standard deviation divided by the square root of the sample size. In this case:

Standard Error = 25,000 / √(1,000) = 25,000 / 31.62 ≈ 790.57

Next, we calculate the z-score for the sample mean of $52,000:

Z = (Sample Mean - Population Mean) / Standard Error

Z = (52,000 - 50,000) / 790.57 ≈ 2.5262

Using the z-score value, we find the corresponding probability in a standard normal distribution table or use a calculator with a normal distribution function to find the probability that Z is greater than 2.5262. The area to the right of this z-score represents the probability we're seeking.

Since in standard normal tables we typically find the area to the left, we subtract this value from 1:

P(Z > 2.5262) = 1 - P(Z < 2.5262)

If we assume P(Z < 2.5262) = 0.9943 (from standard normal tables), then:

P(Z > 2.5262) = 1 - 0.9943 = 0.0057

Thus, the probability that the sample mean is greater than $52,000 is approximately 0.57%.

I NEED HELP DUE IN 2 MINS!!

Answers

Answer:Triangle A

Step-by-step explanation: It has one right angle.

Answer:

THE ANSWERS A

Step-by-step explanation:

OMG GOOD LUCK!!! BECAUSE IT HAS THE AREA LAYED OUT HAVE A BLESSED DAY!!!

Based on these tables, what can you determine about the students in this class? Check all that apply.
There are 35 students in the class.
11 of the students are boys who have summer birthdays.
19 of the students are boys.
There is not enough information shown to determine how many girls have summer birthdays.

Answers

Answer:

Step-by-step explanation:

It’s 1 3,and 4

Answer:

1,3,4

Step-by-step explanation:

Consider rolling two number cubes, each of which has its faces numbered
from 1 to 6. The cubes will be rolled and the sum of the numbers landing
face up will be recorded. Let the event E represent the event of rolling a sum
of 5. How many outcomes are in the collection for event E?

Answers

Answer: 4 outcomes

Step-by-step explanation:

For two number cubes, the total possible outcomes are:

6 events for the first and 6 events for the second, then the total number of combinations is 6*6 = 36

If the dice are different, the possible outcomes are:

Dice 1 = 3, Dice 2 = 2

Dice 1 = 2, Dice 2 = 3

Dice 1 = 4, Dice 2 = 1

Dice 1 = 1, Dice 2 = 4

Then we have 4 outcomes in the collection for event E.

Answer:

4

Step-by-step explanation:

I did it on college board

3x+5=3 solve this equation​

Answers

Answer:

-3/2

Step-by-step explanation:

Answer:  x = -2/3 = -0.667

part of a $3,600 bonus was invested at 9% annual simple interest. The rest was invested at %8 annual simple interest. The total interest at the end of one year was $312. How much was invested in the %9 account?

Answers

Answer:

  $2400

Step-by-step explanation:

Let x represent the amount invested at 9%. (3600-x) will be the amount invested at 8%. The total interest earned is then ...

  312 = 0.09x +0.08(3600 -x)

  24 = .01x . . . . subtract 288, simplify

  2400 = x . . . . divide by .01

$2400 was invested in the 9% account.

The population in the city of Millstone was approximately 2 million in 2010 and 2.2 million in 2015. What is the percent increase from 2010 to 2015

Answers

Answer:

10%

Step-by-step explanation:

Percentage increase for any change is calculated by formula

{(Final value - initial value)/initial value} * 100

Given

population in 2010 = 2 million ----------->initial value

population in 2015 = 2.2 million ----------->Final value

[tex]Percentage \ \ increase = {(2.2 - 2)/2} *100= (0.2/2)*100 = 10%[/tex]

Answer:

10%

Step-by-step explanation:the population in 2010 - 2015 is grown though 10%

as a percent incease the number willl incease in increase will increase and increase until the number can increase to 2.2 million or 2 millions and also the population would probably decrease

An Individual Retirement Account​ (IRA) has ​$17 comma 000in​ it, and the owner decides not to add any more money to the account other than interest earned at 4​%compounded daily. How much will be in the account 30years from now when the owner reaches retirement​ age?

Answers

Answer: The owner reaches at Rs. 56438.28 after 30 years.

Step-by-step explanation:

Since we have given that

Sum = Rs. 17000

Rate of compounded daily = 4%

Number of years = 30 years

So, Using "compound interest formula" we get that :

[tex]A=P(1+\dfrac{r}{n})^{nt}\\\\A=17000(1+\dfrac{0.04}{365})^{365\times 30}\\\\A=17000(1.000109589)^{10950}\\\\A=56438.28[/tex]

Hence, The owner reaches at Rs. 56438.28 after 30 years.

Choose all that are correct. Choosing the brainliest.

Answers

Answer: A, B, F

Explanation:
- A is true because (1/2 x 6 x 8) x 2 is equivalent to 48 square inches.
- B is true because (18 x 6) x 3 is equivalent to 324 square inches.
- F is true because 324 + 48 is equivalent to 372 square inches.

NOTE: I hope this helped, a brainliest would be much appreciated! :)

Answer:

A, B and F

Step-by-step explanation:

Area of 2 triangles:

2(½ × 6 × 8)

48 in²

Area of 3 rectangles:

3(18 × 6)

324 in²

Total surface area:

324 + 48

372 in²

Directions for questions 4 & 5: We selected a random sample of 100 StatCrunchU students, 67 females and 33 males, and analyzed their responses to the question, "What is the total amount (in dollars) of credit card debt you have accrued to date?" With more than 30 in each random and independent sample, conditions are met for modeling the distribution of differences in sample means using a T-model. Therefore, we will proceed with finding a confidence interval to estimate the gender difference in credit card debt for StatCrunchU students. Summary statistics for CC Debt: Group by: Gender Gender Mean Std. dev. n Female 2577.75 1916.29 67 Male 3809.42 2379.47 33 Use StatCrunch to find the 95% confidence interval estimating the difference µ1 – µ2, where µ1 is the mean credit card debt for all female StatCrunchU students and µ2 is the mean credit card debt for all male StatCrunchU students. (directions) Since the numbers are dollars, round to two decimal places when you enter your answer. Flag this Question Question 42 pts The lower limit on the confidence interval is

Answers

Final answer:

The lower limit of the 95% confidence interval for the difference in mean credit card debt between female and male students can be calculated by formula using sample means, standard deviations, sample sizes, and accounting for the t-value associated with 95% confidence.

Explanation:

To calculate the 95% confidence interval for the difference between the mean credit card debt of female and male StatCrunchU students, we use the given information: µ1 (mean credit card debt of females) = 2577.75, µ2 (mean credit card debt of males) = 3809.42, std. dev. of females = 1916.29, std. dev. of males = 2379.47, number of females = 67, number of males = 33.

To calculate the confidence interval, we will use the t-model formula for confidence intervals for difference in means, which is:

(µ1-µ2) ± t*(sqrt([std. dev.1/sqrt(n1)] + [std. dev.2/sqrt(n2)]))

After plugging in the objective values, we would get the confidence range. The lower limit will be (µ1-µ2) - t*(sqrt([std. dev.1/sqrt(n1)] + [std. dev.2/sqrt(n2)])).

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Can someone please answer these for me?

Answers

Answer:

base : ¼

three points : (¼,1), (1,0), (4,–1)

domain : x>0

range : all real number

asymptote : x=0

Answer:

your answer would be x=0

Step-by-step explanation:

I nee to write a 5-paragraph eassy, so please help me it is base on an article name "Schools in Maryland Allow Elementary Students to Carry Cellphones, by Amanda Lenhart, The Washington Post" here are some pic. I just need help writing two paragraph. I already have my Introduction, Body Paragraph #1 and my Body paragraph #2 just need my Body paragraph #3 and my Conclusion I will give brainlis and 30 pnt.

Prompt:

Write an argumentative essay answering the questions: Should students be allowed to carry cellphones on campus? You must support your claim with evidence from the text. You may also use relevant examples from your own experience, observations, and other readings.

Directions:

Before you begin, read the text below, which presents information about the advantages and disadvantages of carrying a cell phone at school. Use the Student Writing Checklist on the back of this page to plan and write a multi-paragraph essay that addresses the prompt. Use your own words, except when quoting directly from the text.

PLEASE DONT WAST THEM

Find the volume of the cone

Answers

Answer:

209.467mm³

Step-by-step explanation:

the explanation is in the picture

hope this helps<3

please like and Mark as brainliest

Lines q and r are parallel.


Parallel lines q and r are cut by transversals s and t. The angles formed by the intersection of lines q, s, and t, clockwise from top left, are blank, 53 degrees, blank, 57 degrees, blank, blank; formed by s and r are blank, 5 x degrees, blank, blank.


What is the value of x?

14

22

53

70

Answers

Answer:

x=22

Step-by-step explanation:

The value of x is 14.

What is Coordinate System?

Arrangement of reference lines or curves used to identify the location of points in space.

Given that Parallel lines q and r are cut by transversals s and t.

The angles formed by the intersection of lines q, s, and t, clockwise from top left, are blank, 53 degrees, blank, 57 degrees,

We need to find the value of x.

The unknown angle between 53 and 57 be u

53+57+u=180

110+u=180

u=70

Now this angle is corresponding to 5x

5x=70

Divide both sides by 5

x=14

Hence, the value of x is 14.

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Suppose that $2n$ tennis players compete in a round-robin tournament. Every player has exactly one match with every other player during $2n-1$ consecutive days. Every match has a winner and a loser. Show that it is possible to select a winning player each day without selecting the same player twice. \\ \\ \textit{Hint: Remember Hall's Theorem}

Answers

Answer:

Step-by-step explanation:

given that Suppose that $2n$ tennis players compete in a round-robin tournament. Every player has exactly one match with every other player during $2n-1$ consecutive days.

this is going to be proved by contradiction

Let there be a winning player each day where same players wins twice, let n = 3there are 6 tennis players and match occurs for 5daysfrom hall's theorem, let set n days where less than n players wining a day let on player be loser which loses every single day in n days so, players loose to n different players in n daysif he looses to n players then , n players are winnerbut, we stated less than  n players are winners in n days which is contradiction.so,we can choose a winning players each day without selecting the same players twice.

In a certain region, 15% of people over the age of 50 didn’t graduate from high school. We would like to know if this percentage is the same among the 25-50 year age group. What is the minimum number of 25-50 year old people who must be surveyed in order to estimate the proportion of non-grads to within 6% of the true parameter with 99% confidence?

Answers

Answer:

235 people

Step-by-step explanation:

Given:

P' = 15% = 0.15

1 - P' = 1 - 0.15 = 0.85

At 99% confidence leve, Z will be:

[tex] \alpha [/tex] = 1 - 99%

= 1 - 0.99 = 0.01

[tex] \alpha /2 = \frac{0.01}{2} = 0.005 [/tex]

[tex] Z\alpha/2 = 0.005 [/tex]

Z0.005 = 2.576

For the minimum number of 25-50 year old people who must be surveyed in order to estimate the proportion of non-grads to within 6%, we have:

Margin of error, E = 6% = 0.06

sample size = n = [tex] (\frac{Z\alpha /2}{E})^2 * P* (1 - P) [/tex]

[tex] = (\frac{2.576}{0.06}) ^2 * 0.15 * 0.85 [/tex]

= 235.02 ≈ 235

A number of 235 people between 25-30 years should be surveyed .

Answer:

n = 236

Step-by-step explanation:

Solution:-

- The proportion of people over the age of 50 who didn't graduate from high school are, p = 0.15 - ( 15 % )

- We are to evaluate the minimum sample size " n " from the age group of 25-50 year in order to estimate the proportion of non-grads within a standard error E = 6% of the true proportion p within 99% confidence.

-  The minimum required sample size " n " for the standard error " E " for the original proportion p relation is given below:

                             [tex]n = \frac{(Z_\alpha_/_2)^2 * p* ( 1 - p )}{E^2}[/tex]

- The critical value of standard normal is a function of significance level ( α ), evaluated as follows:

                            significance level ( α ) = ( 1 - CI/100 )

                                                                 = ( 1 - 99/100 )

                                                                 = 0.01

- The Z-critical value is defined as such:

                           P ( Z < Z-critical ) = α / 2

                           P ( Z < Z-critical ) = 0.01 / 2 = 0.005

                          Z-critical = Z_α/2 = 2.58

- Therefore the required sample size " n " is computed as follows:

                           [tex]n = \frac{(2.58)^2 * 0.15* ( 1 - 0.15 )}{0.06^2}\\\\n = \frac{6.6564 * 0.1275}{0.0036}\\\\n = \frac{0.848691}{0.0036}\\\\n = 235.7475\\[/tex]

Answer: The minimum sample size would be next whole number integer, n = 236.

           

Paulo works at the United Nations. He researched what percent of the world's population lives on each continent. He surveys a sample of employees at the United Nations about their continent of origin to see if the distribution in the sample agrees with the percentages he researched.

Which of these inference procedures is most appropriate?

Answers

Answer:

confidence interval using a  two sample t test between percents

Step-by-step explanation:

confidence interval using a  two sample t test between percents This can be used to compare percentages drawn from two independent samples in this case employees. It is used to compare two sub groups from a single sample example the population on the planet

A random sample of 28 plastic items is obtained, and their breaking strengths are measured. The sample mean is 7.142 and the sample standard deviation is 0.672. Conduct a hypothesis test to assess whether there is evidence that the average breaking strength is not 7.000.

Answers

Answer:

The test statistic t = 1.126 <  1.703 of '27' degrees of freedom at 0.05 level of significance.

null hypothesis(H₀ ) is accepted

There is evidence that the average breaking strength is  7.000.

Step-by-step explanation:

Step 1:-

Given random sample size (n) =28 <30

small sample size n= 28

The sample mean (x⁻) = 7.142

sample standard deviation (S) =0.672

Step 2:-

Null hypothesis :- there is evidence that the average breaking strength is  7.000.

H₀ : μ =7

Alternative hypothesis:-there is evidence that the average breaking strength is  7.000.

H₁ : μ ≠7

The test statistic [tex]t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }[/tex]

Substitute all values and simplification ,

[tex]t = \frac{7.142 -7}{\frac{0.672}{\sqrt{28} } } = \frac{0.142 }{0.1269}[/tex]

t = 1.126

Calculated value is t = 1.126

The degrees of freedom γ = n-1 = 28-1 =27

The tabulated value t= 1.703 at degrees of freedom at 0.05 level of significance.

since  calculated t < tabulated value 't' value of 27 degrees of freedom at 0.05 level of significance.

null hypothesis(H₀ ) is accepted

There is evidence that the average breaking strength is  7.000.

A recent study reported that 18- to 24-year-olds average 192 restaurant visits per year. Assume that the standard deviation for number of visits per year for this age group is 56.5. To validate these findings, a random sample of forty 18- to 24-year-olds was selected and found to average 212 restaurant visits per year. Which of the following statements is correct

A.)The interval that contains 95% of the sample means is 170.3 and 213.7 visits. Because the sample mean is between these two values, we have support for the results of the May 2011 study.

B.)The interval that contains 95% of the sample means is 170.3 and 213.7 visits. Because the sample mean is between these two values, we do not have support for the results of the May 2011 study.

C.)The interval that contains 95% of the sample means is 174.5 and 209.5 visits. Because the sample mean is not between these two values, we have support for the results of the May 2011 study.

D.)The interval that contains 95% of the sample means is 174.5 and 209.5 visits. Because the sample mean is not between these two values, we do not have support for the results of the May 2011 study.

Answers

Answer:

Option C) is the correct answer.

Step-by-step explanation:

We are given the following in the question:

Mean = 192

Sample mean, [tex]\bar{x}[/tex] = 212

Sample size, n = 40

Alpha, α = 0.05

Population standard deviation, σ = 56.5

95% Confidence interval:

[tex]\mu \pm z_{critical}\dfrac{\sigma}{\sqrt{n}}[/tex]

Putting the values, we get,

[tex]z_{critical}\text{ at}~\alpha_{0.05} = 1.96[/tex]

[tex]192 \pm 1.96(\dfrac{56.5}{\sqrt{40}} ) = 192 \pm 17.5 = (174.5,209.5)[/tex]

Thus, the correction answer is

Option C)

"The interval that contains 95% of the sample means is 174.5 and 209.5 visits. Because the sample mean is not between these two values, we have support for the results of the May 2011 study."

For problems 13-17 find a particular solution of the nonhomogeneous equation, given that the functions y1(x) and y2(x) are linearly independent solutions of the corresponding homogeneous equation. x^2y''+xy'-4y=x(x+x^3)

Answers

Answer:

y_g(x) = C1*x^2 + C2*x^-2 +  x^4 / 12

Step-by-step explanation:

Given:-

- The following second order ODE :

                                  x^2y''+xy'-4y=x*(x+x^3)  

Find:-

Find a particular solution of the nonhomogeneous equation    

Solution:-

- First note that the ODE given is a Cauchy Euler ODE. The order of derivative of independent and dependent variables are similar. The general form of Cauchy Euler ODE is:

                           a*x^n y^(n) + b*x^n-1 y^(n-1) + c*x^n-2 y^(n-2) + ... + d*y = f(x)

- We will use the following Auxiliary Equation to find the complementary solutions - Solving Homogeneous part of ODE.

                           am*(m-1) + bm + c = 0

Where, a,b,c are constants such that:

                            x^2y'' + xy' - 4y = 0

                            a = 1 , b = 1 , c = -4

- Solve the Auxiliary equation for (m) as follows:

                            m*(m-1) + m - 4 = 0

                            m^2 - 4 = 0

                            m = +/- 2  ...... ( Real and distinct roots )

- The complementary solutions to the Real and distinct roots from Auxiliary Equation is:

                            yc(x) = y1(x) + y2(x)

                            yc(x) = C1*x^2 + C2*x^-2   .... ( Complementary Solution ).

- Now for the non-homogeneous part of ODE. The function f(x) is defined as:

                            f(x) = x*( x + x^3 ) = x^2 + x^4

- We see that (x^2) term is common to both f(x) and complementary solution yc(x). So when we develop a particular solution, we have to make sure that the solution is independent from complementary solution. If not we multiply the particular solution with (x^n). Where n is the smallest possible integer for which the solution is independent. So in our case ( Using undetermined Coefficient method ) :

                           y_p (x) = A*x^4 + B*x^3 + C*x^2 + D*x + E

- To make the solution independent we multiply y_p by (x^3) where n = 3.

                          y_p (x) = A*x^7 + B*x^6 + C*x^5 + D*x^4 + E*x^3

- Take first and second derivatives of the y_p(x) as follows:

                          y'_p(x) = 7A*x^6 + 6B*x^5 + 5C*x^4 + 4D*x^3 + 3E*x^2

                          y''_p(x) = 42Ax^5 + 30Bx^4 + 20Cx^3 + 12Dx^2 + 6Ex

- Substitute y_p(x) , y'_p(x) and y''_p(x) into the ODE given:

                     42Ax^7 + 30Bx^6 + 20Cx^5 + 12Dx^4 + 6Ex^3

              +       7Ax^7  + 6B*x^6  + 5C*x^5 + 4D*x^4 + 3E*x^3

              -      ( 4Ax^7 +  4B*x^6 +  4C*x^5 +  4D*x^4 + 4E*x^3 )

              --------------------------------------------------------------------------------

                       45Ax^7  + 32Bx^6 + 21Cx^5 + 12Dx^4 + 5Ex^3  

              ---------------------------------------------------------------------------------

            45Ax^7  + 32Bx^6 + 21Cx^5 + 12Dx^4 + 5Ex^3 = x^2 + x^4

- Compare the coefficients:

                                           A = B = C = E = 0

                                           D = 1 / 12.

The particular solution is:

                                          y_p(x) = x^4 / 12

- The general solution is as follows:

                                     y_g(x) = yc(x) + y_p(x)

                                     y_g(x) = C1*x^2 + C2*x^-2 +  x^4 / 12

Answer:

The particular solution to the differential equation

x²y'' + xy' - 4y = x(x + x³)

is

y_p = (1/12)x^4 - x²/2 - x/3

Step-by-step explanation:

Given the differential equation:

x²y'' + xy' - 4y = x(x + x³)...............(1)

First, we solve the homogeneous part of (1)

x²y'' + xy' - 4y = 0...........................(2)

Let x = e^z

=>z = lnx

Let D = d/dz

dz/dx = (1/x)

dy/dx = (dy/dz).(dz/dx)

= (1/x)(dy/dz)

dy/dz = xdy/dx = xy' = Dy

d²y/dx² = (-1/x²)(dy/dz) + (1/x)(d²y/dx²)(dz/dx)

= (1/x²)(d²y/dx² - dy/dz) = (1/x²)(D² - D)y

Using these, (2) becomes

(D² - D)y + Dy - 4y = 0

(D² - 4)y = 0

The auxiliary equation is

m² - 4 = 0

(m - 2)(m + 2) = 0

m1 = 2, m2 = -2

The complementary function is

y = C1e^(2z) + C2e^(-2z)

But z = lnx

y_c = C1x² + C2/x² ...........................(3)

Now we solve (1) using the method of undetermined coefficients.

The nonhomogeneous part is

x(x + x³) = x² + x^4

So, we assume a particular solution of the form

y_p = Ax^4 + Bx³ + Cx² + Dx + E

y'_p = 4Ax³ + 3Bx² + 2Cx + D

y''_p = 12Ax² + 6Bx + 2C

Using these in (1)

x²y''_p + xy'_p - 4y_p = x²(12Ax² + 6Bx + 2C) + x(4Ax³ + 3Bx² + 2Cx + D) - 4(Ax^4 + Bx³ + Cx² + Dx + E)

= x² + x^4

12Ax^4 + 6Bx³ + 2Cx + 4Ax^4 + 3Bx³ + 2Cx² + Dx - 4Ax^4 - 4Bx³ - 4Cx² - 4Dx - 4E = x² + x^4

Comparing the coefficients of various powers of x, we have

12A + 4A - 4A = 1

12A = 1

=> A = 1/12

6B + 3B - 4B = 0

5B = 0

=> B = 0

2C - 4C = 1

-2C = 1

=> C = -1/2

2C + D - 4D = 0

2C - 3D = 0

2C = 3D

2(-1/2) = 3D

=> D = -1/3

-4E = 0

=> E = 0

(A, B, C, D, E) = (1/12, 0, -1/2, -1/3, 0)

y_p = Ax^4 + Bx³ + Cx² + Dx + E

= (1/12)x^4 - (1/2)x² - (1/3)x

The general solution is

y = y_c + y_p

= C1x² + C2/x² + (1/12)x^4 - x²/2 - x/3

Find the arc length of the following curve on the given interval. x equals 8 t minus 7 comma y equals 15 t minus 6x=8t−7, y=15t−6​, 0 less than or equals t less than or equals 40≤t≤4 The length of the curve is nothing. ​(Type an integer or a​ fraction.)

Answers

Answer:

  612

Step-by-step explanation:

Both x and y are linear functions of t, so for each increment of t, the x- and y-coordinates will increment by 8 and 15, respectively. The length of a line segment joining points 8 units in the horizontal direction and 15 units in the vertical direction is given by the Pythagorean theorem as ...

  d = √(8² +15²) = 17

From t=4 to t=40, there are 36 increments in t, so the length of the line segment defined by the given functions is ...

  36×17 = 612 . . . units

1 poir
Elizabeth's tablet has a combined total of 20 apps and movies. Let x
represent the number of apps and y represent the number of movies.
Which of the following could represent the number of apps and movies on
Elizabeth's tablet? Select all that apply.​

Answers

The given options are:

(A)x+y = 20 (B)7 apps and 14 movies (C)x-y= 20 (D)y=-x+ 20 (E)8 apps and 12 movies (F)xy= 20

Answer:

(A)x+y = 20 (D)y=-x+ 20 (E)8 apps and 12 movies

Step-by-step explanation:

If Elizabeth has a combined total of 20 apps and movies.

Where:

Number of apps=x

Number of Movies =y

Then:

Their total,

x+y=20 (Option A)

If we subtract x from both sides

x+y-x=-x+20

y=-x+20 (Option D)

In Option E

8 apps and 12 movies  add up to 20. Therefore, this could also apply.

Braydon, a scuba diver, has a tank that holds 6 liters of air under a pressure of 220 pounds per square inch (psi).


Write the equation that relates pressure, P, to volume, V.


If the pressure increases to 330 psi, how much air is held in Braydon’s tank?

Answers

Answer: 4 litres of air is held in Braydon’s tank.

Step-by-step explanation:

The law relating pressure to volume is the Boyle's law. It states that the volume of a given mass of gas is inversely proportional to its pressure as long as temperature remains constant. It is expressed as

P1V1 = P2V2

Where

P1 and P2 are the initial and final pressures of the gas.

V1 and V2 are the initial and final volumes of the gas.

From the information given,

V1 = 6 litres

P = 220 psi

P2 = 330 psi

Therefore,

6 × 220 = 330V2

V2 = 1320/330 = 4 litres

Answer:

V=1320/p

the tank holds 4 liters

Step-by-step explanation:

For which survey is a sample not necessary?
What percentage of Colorado residents support planting more trees in the community?
Which electronic gadget will be the most popular among middle school students this year?
Do your classmates prefer warm or cool places to travel for vacation?
How many car accidents involve air bag malfunctions?

Answers

Answer:

c

Step-by-step explanation:

Answer:

Do your classmates prefer warm or cool places to travel for vacation?

Step-by-step explanation:

B is located at (−5, 2).

If B is reflected across the y-axis, the coordinates will be .


If B is reflected across the x-axis, the coordinates will be .

Answers

Answer:

the first one is 5,2 and the second one is -5,-2 on edge 2020!

Answer:

5,2 and -5,-2

Step-by-step explanation:

The radius of a circle is 4 yards. What is its circumference?

Answers

Answer:

See answer below

Step-by-step explanation:

Hi there,

To get started, recall the circumference formula.

[tex]C = \pi r^{2}[/tex] where π is the irrational number 3.14159... and r is the radius of the circle. Circumference is like perimeter but for a circle; it is the distance around the boundary.

[tex]C = \pi (4 \ yd)^{2}= 16\pi \ yd^{2} = 50.27 \ yd^{2}[/tex] (approximately)

thanks,

Answer:

C≈25.13yd

Step-by-step explanation:

The circumference of a circle can be found by multiplying pi ( π = 3.14 ) by the diameter of the circle. If a circle has a diameter of 4, its circumference is 3.14*4=12.56. If you know the radius, the diameter is twice as large.

Hope that was helpful.Thank you!!!

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