A tank holds 17 3/5 gallons after losing 36 2/3 gallons, 4 5/6 gallons,and 27 1/12 gallons in 3
Consecutive days. If at the beginning the tank was 20 3/4 gallons short of capacity. What is the capacity of the tank? NEED HELP PLSSS ASAP

Answer:

4 ropes.

Step-by-step explanation:

There are 100 cms in a meter.

So 10 meters = 10* 100

= 1000 cms.

1000 / 210 = 4  ropes with  160 cms remaining.

Answer:

the answer is A

Step-by-step explanation:

always multiply by the 1.8% (or .018) and then add it to the number you multiplied the .018 to

start with the 950 * .018 = 171.00

950 + 171.00 = 1121.00

then you follow this process

1121.00 * .018 = 201.78

1121.00 + 201.78 = 1322.78

The answer is A

Always multiply by the 1.8% (or .018) and then add it to the number you multiplied the .018 to

Start with the 950 *.018 = 171.00

950 + 171.00 = 1121.00

Then you follow this process

1121.00 * .018 = 201.78

1121.00 + 201.78 = 1322.78

Problem-solving is the act of defining a problem; figuring out the purpose of the trouble; identifying, prioritizing, and selecting alternatives for an answer; and imposing an answer.

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Answer:

25,5 miles

Step-by-step explanation:

4.25 inch on map

4.25/0.5 = 8,5

8,5 * 3 = 25,5 miles

Final answer:

To find the actual distance between two towns on a map, set up a proportion using the given scale. By solving the proportion, you can determine the real distance between the towns.

Explanation:

To find the actual distance between the two towns, we can set up a proportion using the given scale:

The formula for the volume of a pyramid, V = 1/3 BH, can be rearranged to solve for the height, 'H', by multiplying both sides of the equation by 3 and then dividing by 'B'. This gives the formula H = 3V/B.

The formula for the volume of a pyramid can be rearranged to solve for the height, 'H' as follows:

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Answer:

D

Step-by-step explanation:

Given the 2 equations

2x + 3y = 11 → I(1)

y = x - 3 → (2)

Substitute y = x - 3 into (1)

2x + 3(x - 3) = 11 ← distribute parenthesis and simplify left side

2x + 3x - 9 = 11

5x - 9 = 11 ( add 9 to both sides )

5x = 20 ( divide both sides by 5 )

x = 4

Substitute x = 4 into (2) for corresponding value of y

y = 4 - 3 = 1

Solution is (4, 1 ) → D

The correct ordered pairs for the equations 2x+3y=11, y=x-3 is (4,1)

In the substitution method we have to calculate the value of one variable by  putting the value of another variable in terms of first variable.

We are having two equations

2x+3y=11.......1

y=x-3........2

Put the value of y from2 in 1

2x+3(x-3)=11

2x+3x-9=11

5x=20

x=4

put the value of x=4 in 2

y=4-3

y=1

Hence the ordered pairs becomes (4,1)

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Answer:

Option 1

Step-by-step explanation:

Tri means 3. An expression which has 3 terms and the terms are separated by plus or minus:

c^2+c+6

Thus option 1 is correct....

For this case we have that by definition, a trinomial is an algebraic expression formed by the sum or difference of three terms or monomials.

Example:

[tex]ax ^ 2y + cx + dy[/tex]

Thus, the correct option is option 1.

[tex]c ^ 2 + c + 6[/tex]

Three terms are observed.

Answer:

Option 1

Answer: Choice C

x represents time and x is positive; y value is 45 times more than the x value

==================================

Explanation:

The inequality y > 45x is the same as y > 45*x

We have y greater than 45*x meaning that y is 45 times more than the x value.

As an example, if x = 2, then 45*x = 45*2 = 90 meaning that y must be larger than 90 if you picked x = 2. In this scenario, x = 2 means that if you traveled for 2 hours then you must have gone more than 90 miles in total distance.

Answer:

[tex]y+1=\dfrac{1}{3}(x+2)[/tex] - point-slope form

[tex]f(x)=\dfrac{1}{3}x-\dfrac{1}{3}[/tex] - function notation

Step-by-step explanation:

The point-slope form of an equation of a line:

[tex]y-y_1=m(x-x_1)[/tex]

m - slope

The formula of a slope:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

From the graph we have the points (-2, -1) and (1, 0).

Substitute:

[tex]m=\dfrac{0-(-1)}{1-(-2)}=\dfrac{1}{3}[/tex]

[tex]y-(-1)=\dfrac{1}{3}(x-(-2))[/tex]

[tex]y+1=\dfrac{1}{3}(x+2)[/tex] - point-slope form

[tex]y+1=\dfrac{1}{3}(x+2)[/tex]          use the distributive property

[tex]y+1=\dfrac{1}{3}x+\dfrac{2}{3}[/tex]           subtract 1 = 3/3 from both sides

[tex]y=\dfrac{1}{3}x-\dfrac{1}{3}[/tex]

Answer:

1. 3rd option

2. 2nd option

Step-by-step explanation:

Answer:

This is an obtuse, isosceles triangle.

Step-by-step explanation:

The largest angle is greater than 90 degrees (obtuse), and two sides are equal as you can tell by two equal angles (isosceles).

The given triangle can be classified as isosceles and acute triangle.

A triangle is a two dimensional figure which consist of three vertices, three edges and three angles.

Sum of the interior angles of a triangle is 180 degrees.

Given is a triangle.

The three angles of the triangle are 41°, 41° and 98°.

That is, two angles of the triangle are equal. So the sides opposite these two angles are also equal.

So this is an isosceles triangle.

Obtuse triangle has one of the angles greater than 90°.

Acute triangle has all the angles less than 90°.

Here all the angles are less than 90°.

So it is acute.

Hence the given triangle is acute and isosceles triangle.

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if EF ≅ WV and JK is intersecting both at a right-angle, the distances OK = JP and likewise PG = GO, namely

[tex]\bf 2(4x-3)-8=4+2x\implies 8x-6-8=4+2x\implies 8x-14=4+2x \\\\\\ 6x-14=4\implies 6x=18\implies x=\cfrac{18}{6}\implies x=3[/tex]

Answer:

(2,0) was already given so (-1,0) is the other one.

Step-by-step explanation:

So we are asked to use the quadratic formula.

To find the x-intercepts (if they exist) is use:

[tex]\text{ If } y=ax^2+bx+c \text{ then the } x-\text{intercepts are } (\frac{-b \pm \sqrt{b^2-4ac}}{2a},0)[/tex].

Let's start:

Compare the following equations to determine the values for [tex]a,b, \text{ and }c [/tex]:

[tex]y=ax^2+bx+c[/tex]

[tex]y=4x^2-4x-8[/tex]

So

[tex]a=4[/tex]

[tex]b=-4[/tex]

[tex]c=-8[/tex]

We are now ready to enter into our formula:

[tex]x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}[/tex]

[tex]x=\frac{4 \pm \sqrt{(-4)^2-4(4)(-8)}}{2(4)}[/tex]

[tex]x=\frac{4 \pm \sqrt{16+16(8)}}{8}[/tex]

[tex]x=\frac{4 \pm \sqrt{16(1+8)}}{8}[/tex]

[tex]x=\frac{4 \pm \sqrt{16}\sqrt{1+8}}{8}[/tex]

[tex]x=\frac{4 \pm 4\sqrt{9}}{8}[/tex]

[tex]x=\frac{ 4 \pm 4(3)}{8}[/tex]

[tex]x=\frac{4 \pm 12}{8}[/tex]

[tex]x=\frac{4(1\pm 3)}{8}[/tex]

[tex]x=\frac{1(1\pm 3)}{2}[/tex]

[tex]x=\frac{1 \pm 3}{2}[/tex]

[tex]x=\frac{1+3}{2} \text{ or } \frac{1-3}{2}[/tex]

[tex]x=\frac{4}{2} \text{ or } \frac{-2}{2}[/tex]

[tex]x=2 \text{ or } -1[/tex]

So the x-intercepts are (2,0) and (-1,0).

(2,0) was already given so (-1,0) is the other one.

Answer:

x = -3 or x = 2

Step-by-step explanation:

It is given a quadratic equation,

(x + 3)(x - 2) = 0

To find the solution of given equation

Let  (x + 3)(x - 2) 0

⇒ either (x + 3) = 0 or (x - 2) = 0

If (x + 3) = 0 then  x = -3

If (x - 2) = 0 then x = 2

Therefore the solution of given equation are

x = -3 or x = 2

Answer:

1) The profit of the company dropped by -15% compared to last year.

2) The temperature of Alaska was -5 degrees yesterday.

3) John had 1,000$ dollars deposited in the bank, and then made a poor investment, causing him to owe the bank 5,000$, making his account -4,000$

Step-by-step explanation:

With each scenario you have to try to find a new way to express a negative number which is primarily through loss. In which ways can you unique express loss of a value below zero in real world is the question, and you can do so with examples like money and temperature.

5)

[tex]\bf \begin{array}{|cc|cccc|ll} \cline{1-6} sodas&x&\underline{24}&28&\underline{32}&36\\ \cline{1-6} cost&y&\underline{18}&21&\underline{24}&27\\ \cline{1-6} \end{array}~\hspace{9em} (\stackrel{x_1}{24}~,~\stackrel{y_1}{18})\qquad (\stackrel{x_2}{32}~,~\stackrel{y_2}{24}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{24-18}{32-24}\implies \cfrac{6}{8}\implies \cfrac{3}{4}[/tex]

6)

[tex]\bf \begin{array}{|cc|cc|ll} \cline{1-4} year&x&0&12\\ \cline{1-4} \$&y&720&1080\\ \cline{1-4} \end{array}~\hspace{10em} (\stackrel{x_1}{0}~,~\stackrel{y_1}{720})\qquad (\stackrel{x_2}{12}~,~\stackrel{y_2}{1080}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1080-720}{12-0}\implies \cfrac{360}{12}\implies \cfrac{30}{1}\implies 30[/tex]

7)

slope as you should already know is rise/run, or how much something moves in relation something else, namely how much the y-axis go up as the x-axis moves sideways, one moves, the other follows, but the increments will be different, sometimes the same, but usually different.

the y-intercept means, when the graph of the equation touches or intercepts the y-axis, and when that happens x = 0, or the horizontal distance is at bay.

for the slope on  6), 30 or 30/1 means, for every 1 year(x) passed, the worth(y) increased by 30, or jumped by 30 units, so as the x-axis moved 1, the y-axis moved 30.  After 12 years 30 * 12 = 360, and we add the initial 720 and we end up with 1080.

the y-intercept, well, as aforementioned is when x = 0, is year 0.

Answer:

Top:

The rate change is 4.

Bottom:

The rate change is 3.

Step-by-step explanation:

24+4= 28     28+4=32  (and)  32+4=36

18+3=21  21+3=24    (and)  24+3=27

I will get back to you on the rest>

Hope this helped tho! :3

Answer:

  AC = 26

Step-by-step explanation:

AD = DC . . . . . .these segments are marked congruent

8x-1 = 6x+9 . . . substitute the given expressions

2x = 10 . . . . . add 1-6x

x = 5

__

AC = 2·AB = 2(3x-2) = 2(3·5-2) . . . . substitute into expression for AB

AC = 26

The feline expanded in weight compared with the canine's underlying weight which is steady with the data given.

The allocation of weights to the important variables that produce the calculation's optimum is referred to as a direct consequence.

Let c be the feline's unique weight. Let c* be the feline's new weight.

Let d be the canine's unique weight. The d* be the canine's new weight.

The equation is given as,

c = 1.2 c

d = .9 d

c = d

The other equation is given as,

p = (d - c)/d = 1 - c/d

We know that the given condition,

c = d = 0.9 d

Then the equation is written as,

p = 1 - 0.9d/d

p = 1 - 0.9

p = 0.1 or 10%.

Hence, toward the beginning, the rate contrast compared with the canine was,

q = (d - c)/d = 1 - 0.75 = 0.25 or 25%.

That is, the feline weighed not exactly like the canine toward the beginning. Since p < q, the feline expanded in weight compared with the canine's underlying weight — which is steady with the data given.

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Answer:

Leg side along the wall = x ft = 8 ft

The other leg side = 7+x ft = 7+8=15 ft

The Hypotenuse =9+x ft = 9+8 = 17 ft

Step-by-step explanation:

In the question, the shape of the pool is right triangle.

Let the leg side along the wall to be the x ft

Let the other leg side  to be 7+x ft

Let the longest side/hypotenuse to be x+9 ft

Apply the Pythagorean relationship where the sum of squares of the legs equals the square of the hypotenuse

This means;

[tex]x^2 +(x+7)^2=(x+9)^2\\\\[/tex]

Expand the terms in brackets

[tex]x^2+(x+7)^2=(x+9)^2\\\\\\x^2+x^2+14x+49=x^2+18x+81[/tex]

collect like terms

[tex]x^2+x^2-x^2=18x-14x+81-49\\\\\\x^2=4x+32\\\\\\x^2-4x-32=0[/tex]

solve for x in the quadratic equation by factorization

[tex]x^2-4x-32=0\\\\\\x^2-8x+4x-32=0\\\\\\x(x-8)+4(x-8)=0\\\\\\(x+4)(x-8)=0\\\\\\x+4=0,x=-4\\\\x-8=0,x=8[/tex]

Taking the positive value of x;

x=8ft

Finding the lengths

Leg side along the wall = x ft = 8 ft

The other leg side = 7+x ft = 7+8=15 ft

The Hypotenuse =9+x ft = 9+8 = 17 ft

Answer:

45ml of pure water to obtain 135ml of the desired 30% solution

Step-by-step explanation:

45% of 90 = 40.5

So, 40.5ml of alcohol in 90ml

We want 30% and therefore need a ratio of 3:7

40.5÷3=13.5

so one part of our ratio is 13.5

we then times this by 7

13.5 x 7 = 94.5

so, 94.5ml of water

to work out how much we already have, we should do 90ml- 40.5ml = 49.5ml

and then 94.5- 49.5 = 45ml

We need 45ml of water and the total mo of the desired solution will be 90+45=135ml

To dilute a 45% alcohol solution to a 30% alcohol solution by adding pure water, you will need to add 45 mL of pure water to the initial 90 mL to achieve a total volume of 135 mL with the desired 30% alcohol concentration.

To dilute a 45% alcohol solution to a 30% alcohol solution using pure water, we can use the concept of concentration dilution in chemistry. This involves calculating the amount of diluent (in this case, water) to add to an existing solution to achieve a desired concentration.

Let's denote the amount of pure water to add as x mL. The initial volume of the alcohol solution is 90 mL with a 45% concentration, meaning it contains 40.5 mL of pure alcohol. Since adding water doesn't change the amount of alcohol, the final mixture's alcohol volume remains at 40.5 mL.

To find the final volume of the solution and the amount of water needed, we use the formula for the final concentration: Final Concentration = (Volume of Solute) / (Final Volume of Solution). Substituting the given and desired values gives us 30% = 40.5 mL / (90 mL + x).

Rearranging and solving for x gives: x = (40.5 / 0.3) - 90 = 135 - 90 = 45 mL. Therefore, 45 mL of pure water must be added to the original solution to get a 30% alcohol solution.

In conclusion, adding 45 mL of pure water to the 90 mL of 45% alcohol mixture yields a total volume of 135 mL of the desired 30% solution.

Answer:

One side is 10

Step-by-step explanation:

10*10 is equal to 100

Answer:

6

Step-by-step explanation:

54=2x3x3x3

12=2x2x3

common factors are 2 and 3 so 2x3=6

Answer:

I think that the answer is A.

Answer:

No options is correct.    

Step-by-step explanation:

Given : The product of -4 and 3.

To find : Which expression could be used to determine the product ?

Solution :

The product of -4 and 3 is [tex]-4\times 3=-12[/tex]

To know which expression we solve each options and get whose result is same as ours,

A) [tex](-4)(3)\times (-4)(\frac{1}{4})[/tex]

Solve,

[tex](-4)(3)\times (-4)(\frac{1}{4})= -12\times -1=12[/tex]

B) [tex](-4)(3)+(-4)(\frac{1}{4})[/tex]

Solve,

[tex](-4)(3)+(-4)(\frac{1}{4})= -12+(-1)=-13[/tex]

C) [tex](3)(-4)\times (3)(\frac{1}{4})[/tex]

Solve,

[tex](3)(-4)\times (3)(\frac{1}{4})=-12\times\frac{3}{4}=-9[/tex]

D) [tex](3)(-4)+(3)(\frac{1}{4})[/tex]

Solve,

[tex](3)(-4)+(3)(\frac{1}{4})=-12+\frac{3}{4}=-11.25[/tex]

From the given options, No options will get the product.

Answer:

(9,7)

Step-by-step explanation:

The goal is to write in standard form for a circle.

That is write in this form: [tex](x-h)^2+(y-k)^2=r^2[/tex] where [tex](h,k)[/tex] is the center and [tex]r[/tex] is the radius.

So you have

[tex]x^2+y^2-18x-14y+124=0[/tex]

Reorder so you have your x's together, your y's together, and the constant on the other side:

[tex]x^2-18x+y^2-14y=-124[/tex]

Now we are going to complete the square using

[tex]x^2+bx+(\frac{b}{2})^2=(x+\frac{b}{2})^2[/tex].

This means we are going to add something in next to the x's and something in next to y's.  Keep in mind whatever you add on one side you must add to the other.

[tex]x^2-18x+(\frac{-18}{2})^2+y^2-14y+(\frac{-14}{2})^2=-124+(\frac{-18}{2})^2+(\frac{-14}{2})^2[/tex]

The whole reason we did is so we can write x^2-18x+(-9)^2 as (x-9)^2 and y^2-14y+(-7)^2 as (y-7)^2.  We are just using this lovely thing I have I already mentioned: [tex]x^2+bx+(\frac{b}{2})^2=(x+\frac{b}{2})^2[/tex].

[tex](x-9)^2+(y-7)^2=-124+81+49[/tex]

[tex](x-9)^2+(y-7)^2=6[/tex]

Comparing this to [tex](x-h)^2+(y-k)^2=r^2[/tex] tells us

[tex]h=9,k=7,r^2=6[/tex]

So the center is (9,7) while the radius is [tex]\sqrt{6}[/tex].

Answer: (9,7)

Step-by-step explanation:

The equation of the circle in Center-radius form is:

 [tex](x - h)^2 + (y - k)^2 = r^2[/tex]

Where the center is at the point (h, k) and the radius is "r".

To rewrite the given equation in Center-radius form, we need to complete the square:

1. Move 124 to the other side of the equation:

[tex]x^2+y^2-18x-14y+124=0\\\\x^2+y^2-18x-14y=-124[/tex]

2. Group terms:

[tex](x^2-18x)+(y^2-14y)=-124[/tex]

3. Add [tex](\frac{-18}{2})^2=81[/tex] to the group of the variable "x" and to the right side of the equation.

4. Add [tex](\frac{-14}{2})^2=49[/tex] to  the group of the variable "y" and to the right side of the equation.

Then:

[tex](x^2-18x+81)+(y^2-14y+49)=-124+81+49[/tex]

5. Finally,  simplify and convert the left side to squared form:

[tex](x-9)^2+(y-7)^2=6[/tex]

You can identify that the center of the circle is at:

[tex](h,k)=(9,7)[/tex]

Answer:

75 yd^2.

Step-by-step explanation:

If the width = x yards, the length will be 3x yards.

The perimeter = 2 * length + 2 * width

= 2* 3x + 2*x = 40

6x + 2x = 40

8x = 40

x = 5

So the width is 5 and the length is 15 yards.

The area = 5 * 15 = 75 yd^2.

Answer:

75

Step-by-step explanation:

x=breadth

3x=length

perimeter=2(x+3x)=8x

40=8x

x=5

length=15

breadth=5

area=15*5=75

Answer:

[tex]\large\boxed{4x^4\sqrt[3]{2x^2}}[/tex]

Step-by-step explanation:

[tex]\sqrt[3]{2x^5}\cdot\sqrt[3]{64x^9}\qquad\text{use}\ \sqrt[n]{ab}=\sqrt[n]{a}\cdot\sqrt[n]{b}\\\\=\sqrt[3]{2}\cdot\sqrt[3]{64}\cdot\sqrt[3]{x^5x^9}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=\sqrt[3]2\cdot4\cdot\sqrt[3]{x^2x^3x^9}\\\\=4\sqrt[3]2\cdot\sqrt[3]{x^2x^{12}}\\\\=4\sqrt[3]2\cdot\sqrt[3]{x^2x^{4\cdot3}}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=4\sqrt[3]2\cdot\sqrt{x^2(x^4)^3}\\\\=4\sqrt[3]2\cdot\sqrt[3]{x^2}\cdot\sqrt[3]{(x^4)^3}\qquad\text{use}\ \sqrt[n]{a^n}=a\\\\=4\sqrt[3]{2x^2}\cdot x^4\\\\=4x^4\sqrt[3]{2x^2}[/tex]

Answer: it's c to put it simply

Step-by-step explanation:

Your answer is the third option, x = -2 and x=6

We can see this because the solutions of x^2/2 - 8 = 2x - 2 are going to be where the lines y = x^2/2 - 8 and y = 2x - 2, because this is where the two equations are equal to each other.

Therefore, we can just look on the graph at where the two lines intersect, and see that it happens when x = -2 and x = 6.

I hope this helps!

Answer:

x=-2 and x=6

Step-by-step explanation:

The solution to a graph would be where the two lines intersect. When you look at the graph you plot where they connect

(-2, -6), (6, 10)

The x value is the very first variable in an ordered pair. Therefore, the solution to this graph would be x=-2 and x=6.

Answer:

the cost of rib eye steak dinner = $22.47

the cost of grilled salmon dinners= $10.57 .....

Step-by-step explanation:

Let x be the rib eye steak dinner.

Let y be the grilled salmon dinner.

According to the first given statement:

12x+27y= $554.98    (equation 1)

According to the second statement:

26x+9y=$584.36      ( equation 2)

Lets take a look at the 1st equation:

12x+27y= $554.98

12x=$554.98- 27y

x=$554.98- 27y/12

Now substitute the value of x in 2nd equation:

26x+9y=$584.36

26($554.98- 27y/12)+9y=$584.36

26(554.98- 27y)+9y=584.36*12

14429.48-702y=7012.32

-702y=7012.32-14429.48

-702y= -7417.16

y= 7417.16/702

y=$10.57

Now substitute the value of y in equation 1:

12x+27y= $554.98

12x+27(10.57)=554.98

12x+285.39 = 554.98

Move the constant to the R.H.S

12x=554.98-285.39

12x=269.59

Divide both the terms by 12

12x/12=269.59/12

x=$22.47

Thus the cost of rib eye steak dinner = $22.47

the cost of grilled salmon dinners= $10.57 .....

Answer:

B+

Step-by-step explanation:

Grades earned in five subjects are;

A,C+,A-,B- and B+

Remaining subject is biology

Total number of subjects will be=6

3.2 gpa as a percentile =86

For her to maintain 3.2 gpa total sum of percentile in the 6 subjects should be at least

6×86=516

Emily total sum of subjects in percentile is 93+77+90+80+87=427

Find the difference , 516-427=89

89 is grade B+

Emily should earn a grade of B+ to keep her 3.2 gpa

Answer: 3

Step-by-step explanation: I jus got it right on a pex

Answer:

see explanation

Step-by-step explanation:

Using the exact values of the trigonometric ratios

sin60° = [tex]\frac{\sqrt{3} }{2}[/tex], cos60° = [tex]\frac{1}{2}[/tex]

sin45° = cos45° = [tex]\frac{1}{\sqrt{2} }[/tex]

Using the sine ratio on the right triangle on the left

sin60° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{a}{4\sqrt{3} }[/tex] = [tex]\frac{\sqrt{3} }{2}[/tex]

Cross- multiply

2a = 4[tex]\sqrt{3}[/tex] × [tex]\sqrt{3}[/tex] = 12 ( divide both sides by 2 )

a = 6

Using the cosine ratio on the same right triangle

cos60° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{c}{4\sqrt{3} }[/tex] = [tex]\frac{1}{2}[/tex]

Cross- multiply

2c = 4[tex]\sqrt{3}[/tex] ( divide both sides by 2 )

c = 2[tex]\sqrt{3}[/tex]

------------------------------------------------------------------------------------------

Using the sine/cosine ratios on the right triangle on the right

sin45° = [tex]\frac{a}{b}[/tex] = [tex]\frac{6}{b}[/tex] = [tex]\frac{1}{\sqrt{2} }[/tex]

Cross- multiply

b = 6[tex]\sqrt{2}[/tex]

cos45° = [tex]\frac{d}{b}[/tex] = [tex]\frac{d}{6\sqrt{2} }[/tex] = [tex]\frac{1}{\sqrt{2} }[/tex]

Cross- multiply

[tex]\sqrt{2}[/tex] d = 6[tex]\sqrt{2}[/tex] ( divide both sides by [tex]\sqrt{2}[/tex] )

d = 6

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a = 6, b = 6[tex]\sqrt{2}[/tex], c = 2[tex]\sqrt{3}[/tex], d = 6

Answer:

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