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Related Questions
A ball is tossed from an upper-story window of a building. the ball is given an initial velocity of 7.90 m/s at an angle of 18.0° below the horizontal. it strikes the ground 4.00 s later. (a) how far horizontally from the base of the building does the ball strike the ground? 30.04 correct: your answer is correct. m (b) find the height from which the ball was thrown. incorrect: your answer is incorrect. work only with the vertical components of these quantities. this part of the problem is then a 1-dimensional free-fall example. m (c) how long does it take the ball to reach a point 10.0 m below the level of launching? s
Answers
[tex]S_x(t)=v_0 cos (\alpha )t[/tex]
[tex]S_y(t)=v_0 sin (\alpha ) t+ \frac{1}{2}gt^2 [/tex]
where [tex]g=9.81 m/s^2[/tex] is the gravitational acceleration.
(a) To find the distance covered by the ball horizontally, we must simply calculate Sx at the time the ball hits the ground (t=4.0 s):
[tex]S_x(4.0s)= 7.9 m/s \cdot cos (18^{\circ}) \cdot 4.0s=30.05 m[/tex]
(b) The height from which the ball was thrown is the value of Sy at 4.0s, which is the distance covered by the ball before hitting the ground:
[tex]S_y(4.0 s)=7.9 m/s \cdot sin(18^{\circ}) \cdot 4.0s + \frac{1}{2}(9.81 m/s^2)(4.0s)^2=88.24 m [/tex]
(c) To calculate how long does it take to the ball to reach 10.0 m below the initial point, we have to find the time at which Sy(t)=10.0 m. This means we must solve the following equation:
[tex]10.0m = v_0 sin (\alpha ) t + \frac{1}{2} gt^2 [/tex]
Using the data of the problem, we can solve this equation. We find two solutions for t: one is negative, so we can neglect it. The second one, which is the solution of the problem, is t=1.19 s.
In 1665 Sir Isaac Newton proposed the fundamental law of gravitation as a universal force of attraction between any two bodies. What does this theory state about the force that makes an apple fall and the force that keeps the moon in its orbit?
Answers
Newton's universal law of gravitation states that the force that makes an apple fall and the force that keeps the moon in its orbit are both caused by gravity. The force of gravity is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.
Explanation:Newton's universal law of gravitation states that every object in the universe attracts every other object with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. This means that the force that makes an apple fall and the force that keeps the moon in its orbit are both caused by gravity. In both cases, the force of gravity is acting between two bodies and is dependent on their masses and the distance between them.
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A proton beam in an accelerator carries a current of 130 μa. if the beam is incident on a target, how many protons strike the target in a period of 17.0 s?
Answers
[tex]I= \frac{Q}{\Delta t} [/tex]
We know the current, [tex]I=130 \mu A=130 \cdot 10^{-6} A[/tex], and the time interval, [tex]\Delta t=17 s[/tex], so we can find the total charge:
[tex]Q=I \Delta t= 2.21 \cdot 10^{-3}C [/tex]
The total charge Q is the product between the number of protons N and the charge of each protons, e, which is [tex]e=1.6 \cdot 10^{-19}C[/tex]:
[tex]Q=Ne[/tex]
we can re-write the equation solving for N, so we can find the number of protons striking the target in 17 s:
[tex]N= \frac{Q}{e}= \frac{2.21 \cdot 10^{-3}C}{1.6 \cdot 10^{-19}C} =1.38 \cdot 10^{16} [/tex]
Final answer:
Using the formula relating current, charge, and time, approximately 1.38 × 10^16 protons strike a target when 130 μA of current is directed at the target for 17.0 seconds.
Explanation:
To determine how many protons strike the target in 17.0 seconds with a current of 130 μA (microamperes), we must understand the relationship between electric current, charge, and the quantity of charged particles. Current (I) is defined as the amount of charge (Q) passing through a point in a circuit per unit of time (t), mathematically described by the equation I = Q/t. Given that each proton carries a charge of approximately 1.6 × 10-19 C (coulombs), we can find the total charge that strikes the target over 17.0 seconds and subsequently calculate the number of protons involved.
First, convert the current from microamperes to amperes: 130 μA = 130 × 10-6 A. Then, use I = Q/t to find the total charge Q: Q = I × t = (130 × 10-6 A) × 17.0 s = 2.21 × 10-3 C. Finally, calculate the number of protons by dividing the total charge by the charge of a single proton: Number of protons = Q / charge of one proton = (2.21 × 10-3 C) / (1.6 × 10-19 C/proton) ≈ 1.38 × 1016 protons.
Therefore, approximately 1.38 × 1016 protons strike the target in a period of 17.0 seconds.
The use of air bags in cars reduces the force of impact by a factor of 110.(The resulting force is only as great.) What can be said about how the airbag changed the duration of the collision?
Answers
[tex]\Delta p = F \Delta t[/tex]
[tex]\Delta p [/tex] does not change whether the car has an airbag or not, because
[tex]\Delta p = m\Delta v[/tex]
and 1) the mass of the car is always the same 2) the change in velocity of the car is always the same,
so if [tex]\Delta p[/tex] is constant and F is reduced by a factor 110, then [tex]\Delta t[/tex] (the duration of the collision) must be increased by a factor 110 with the airbag.
the answer is C. it increases by a factor of 110, i got 100 on the test
At 600.0 k the rate constant is 6.1× 10–8 s–1. what is the value of the rate constant at 785.0 k?
Answers
C4H8(g) --> 2C2h4(g)
At 600.0 K the rate constant is 6.1× 10–8 s–1. What is the value of the rate constant at 785.0 K?"
To solve the exercise, we can use Arrhenius equation:
[tex]\ln( \frac{K_2}{K_1} ) = \frac{Ea}{R} ( \frac{1}{T_1}- \frac{1}{T_2} ) [/tex]
where K are the reaction rates, Ea is the activation energy, R=8.314 J/mol*K and T are the temperatures. Using T1=600 K and T2=785 K, and Ea=262 kJ/mol = 262000 J/mol, on the right side of the equation we have
[tex] \frac{Ea}{R}( \frac{1}{T_1}- \frac{1}{T_2} )=12.38 [/tex]
And so
[tex]\ln( \frac{K_2}{K_1})=12.38 [/tex]
And using [tex]K_1=6.1\cdot 10^{-8} s^{-1}[/tex] , we find K2:
[tex]K_2=K_1 e^{12.38}=0.0145 s^{-1}[/tex]
In Robin’s linguistics class, the teacher and students are discussing how the word “nice” once meant “foolish” and how “awful” used to mean “full of awe.” They are most likely discussing ______
A.
morphemes
B.
semantics
C.
phonemes
D.
syntax
Answers
Semantics means the study of words and their meanings.
Hope this helped!
When mass m is tied to the bottom of a long, thin wire suspended from the ceiling, the wire's second-harmonic frequency is 180 hz . adding an additional 1.2 kg to the hanging mass increases the second-harmonic frequency to 270 hz . part a what is m?
Answers
Given second-harmonic frequencies and added mass, solve [tex]\(1.5^2 = \frac{m + 1.2}{m}\) to find \( m = 0.96 \)[/tex] kg.
To find the mass [tex]\( m \)[/tex] that results in the given second-harmonic frequencies, we will use the formula for the frequency of standing waves on a wire under tension.
The second-harmonic frequency for a wire is given by:
[tex]\[f = \frac{2}{L} \sqrt{\frac{T}{\mu}}\][/tex]
where:
- [tex]\( f \)[/tex] is the frequency,
- [tex]\( L \)[/tex] is the length of the wire,
- [tex]\( T \)[/tex] is the tension in the wire,
- [tex]\( \mu \)[/tex] is the linear mass density of the wire.
The tension [tex]\( T \)[/tex] in the wire is due to the hanging mass [tex]\( m \)[/tex] and is given by:
[tex]\[T = mg\][/tex]
where [tex]\( g \)[/tex] is the acceleration due to gravity (approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex]).
The second-harmonic frequency is given, so for the initial mass [tex]\( m \)[/tex]:
[tex]\[f_1 = 180 \, \text{Hz}\][/tex]
[tex]\[180 = \frac{2}{L} \sqrt{\frac{mg}{\mu}}\][/tex]
When an additional 1.2 kg is added to the mass, the new mass becomes [tex]\( m + 1.2 \)[/tex] kg and the second-harmonic frequency becomes:
[tex]\[f_2 = 270 \, \text{Hz}\][/tex]
[tex]\[270 = \frac{2}{L} \sqrt{\frac{(m + 1.2)g}{\mu}}\][/tex]
To find [tex]\( m \)[/tex], we will set up the ratio of the two frequencies and solve for [tex]\( m \)[/tex]:
[tex]\[\frac{f_2}{f_1} = \frac{270}{180} = 1.5\][/tex]
Using the ratio of the frequencies:
[tex]\[\frac{270}{180} = \frac{\sqrt{\frac{(m + 1.2)g}{\mu}}}{\sqrt{\frac{mg}{\mu}}}\][/tex]
Squaring both sides to eliminate the square roots:
[tex]\[\left(\frac{270}{180}\right)^2 = \frac{(m + 1.2)g}{mg}\][/tex]
[tex]\[\left(1.5\right)^2 = \frac{(m + 1.2)}{m}\][/tex]
[tex]\[2.25 = \frac{m + 1.2}{m}\][/tex]
Multiplying both sides by [tex]\( m \)[/tex]:
[tex]\[2.25m = m + 1.2\][/tex]
Solving for [tex]\( m \)[/tex]:
[tex]\[2.25m - m = 1.2\][/tex]
[tex]\[1.25m = 1.2\][/tex]
[tex]\[m = \frac{1.2}{1.25}\][/tex]
[tex]\[m = 0.96 \, \text{kg}\][/tex]
Therefore, the mass [tex]\( m \)[/tex] is [tex]\( 0.96 \)[/tex] kg.
An ideal monatomic gas at 300 k expands adiabatically and reversibly to twice its volume. what is its final temperature?
Answers
[tex]TV^{\gamma -1} = cost.[/tex]
where T is the gas temperature, V is the volume and [tex]\gamma[/tex] is the adiabatic index, which is equal to [tex]\gamma = \frac{5}{3} [/tex] for a monoatomic gas.
We can re-write the equation as
[tex]T_1 V_1^{\gamma -1} = T_2 V_2^{\gamma -1}[/tex]
where the labels 1,2 refer to the initial and final conditions of the gas.
Let's rewrite it for [tex]T_2[/tex], the final temperature:
[tex]T_2 = T_1 ( \frac{V_1}{V_2} )^{\gamma-1}[/tex]
We can now substitute the initial temperature, T1=300 K, and [tex]V_2 = 2V_1[/tex], because the final volume is twice the initial one. So we find the value of the final temperature:
[tex]T_2 = 300 K( \frac{1}{2})^{ \frac{2}{3} } =189 K[/tex]
How do the planets Venus and Neptune differ in terms of atmospheric composition?
(A)Venus has carbon dioxide in its atmosphere, while Neptune has methane in its atmosphere.
(B)Venus has oxygen in its atmosphere, while Neptune has carbon monoxide in its atmosphere.
(C)Venus has hydrogen chloride in its atmosphere, while Neptune has helium in its atmosphere.
(D)Venus has nitrogen in its atmosphere, while Neptune has oxygen and hydrogen in its atmosphere.
(E)Venus has sulfur dioxide in its atmosphere, while Neptune has nitrogen dioxide in its atmosphere.
Answers
Answer: The correct option is Option A.
Explanation:
Atmosphere is defined as the layer of gases which form an envelope around a planet.
Venus is the second and Neptune is the last planet of our solar system.
Venus's atmosphere mainly consists of carbon dioxide with trace amounts of nitrogen, argon , helium and neon.
Neptune's atmosphere mainly consists of helium and hydrogen with 2.5 to 3% of methane gas in it.
From the above information, the correct answer comes out to be Option A.
In the process of nuclear fusion, large amounts of energy, at temperatures of approximately 120 million Kelvin, are required to join two nuclei into a single, heavier nucleus. Why does the process of fusion require so much energy in order to take place?
Answers
[tex]U=k \frac{q^2}{r} [/tex]
And since the range of the nuclear strong interaction is very short, r must be very small, and so the amount of energy required U can be huge.
A baseball is launched horizontally from a height of 1.8 m. The baseball travels 0.5 m before hitting the ground.
How fast is the baseball moving, rounded to the nearest hundredth?
m/s
Answers
Here we’re solving a problem where a ball is projected horizontally from a height of h=1.8 m with a horizontal velocity of Vx. At the impact with the ground, the ball has travelled 0.5 m horizontally.
Solution:
We will need kinematic equations
V1^2-V0^2=2aS ………………….(1)
S=V0*t + (1/2)at^2………………..(2)
Where
S=displacement (distance), m
V0=initial velocity, m/s
V1=final velocity, m/s
a=acceleration, m/s^2
t=time, seconds
At the point of impact, there a vertical velocity (downwards) of Vy.
The horizontal velocity Vx remains constant since projection till impact.
Vertical velocity Vy:
Using equation (1),
V0=0 (projected horizontally, so vertical velocity=0)
S=1.8 m (downwards)
a=9.81 m/s^2 (acceleration due to gravity, downwards)
=>
Vy=V1=sqrt(V0^2+2*a*S)=sqrt90+2*9.81*1.8)=5.9427
Horizontal velocity, Vx:
ball travelled 0.5m in time t it took ball to hit ground.
Using equation (2),
S=1.8m
V0=0
a=9.81
=>
1.8=0*t+(1/2)(9.81)t^2
Solve for t
t=sqrt(2*1.8/9.81)=0.60578 s
Horizontal velocity, Vx = 0.5/0.60578 = 0.82538 s
Speed of ball on impact is the vectorial sum of Vx and Vy:
Speed = sqrt(Vx^2+Vy^2)=sqrt(5.9427^2+0.82538^2)=5.99977 m/s, say 6.0 m/s.
Answer: 0.82
On ED2020
Which theory proposes that the moon was a passing asteroid pulled into orbit by Earth's gravity? impact theory co-formation theory capture theory synchronous theory
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The capture theory is the idea that the moon formed somewhere else in the solar system. The theory proposed that the moon was just an asteroid pulled into orbit by the Earth.
Co-formation is a theory that proposes that the Earth and the moon formed around the same time as each other from a primitive solar nebulae.
The answer to your question then is CAPTURE THEORY.
Final answer:
The capture theory suggests the Moon was a passing asteroid that Earth's gravity pulled into orbit, but this theory is challenged by the Moon's orbit and compositional similarities to Earth. The widely accepted explanation is the giant impact hypothesis.
Explanation:
The theory that proposes the Moon was a passing asteroid pulled into orbit by Earth's gravity is known as the capture theory. However, there are significant challenges with this theory, including the need for a substantial loss of energy for a body to achieve orbit, which is difficult to explain for an object of the Moon's size. Moreover, the capture theory does not account for the nearly circular orbit of our Moon, nor does it explain the compositional similarities between the Earth and the Moon, particularly regarding isotopes of oxygen. The currently accepted explanation for the Moon's origin favoring these evidences is the giant impact hypothesis, which suggests the Moon formed from the debris of a collision between Earth and a Mars-sized body.
What has MOST LIKELY caused a change in the soil in the wheat field shown?
Answers
Erosion removes rocks and soil by wind, water, ice, and gravity.
A particle initially located at the origin has an acceleration of vector a = 2.00ĵ m/s2 and an initial velocity of vector v i = 9.00î m/s.(a) find the vector position of the particle at any time t (where t is measured in seconds).
Answers
To find the vector position of the particle at any time t, use the kinematic equation r(t) = r0 + vit + 0.5at2. Plug in the values for the initial velocity and acceleration to get the position function.
Explanation:Given that at time t, the particle has an acceleration of vector a = 2.00ĵ m/s2 and an initial velocity of vector vi = 9.00î m/s, we can find the vector position of the particle at any time t using the kinematic equations.
The position function is given by:
r(t) = r0 + vit + 0.5at2
Plugging in the values, we have:
r(t) = 0 + (9.00î m/s)(t) + 0.5(2.00ĵ m/s2)(t2)
So, the vector position of the particle at any time t is r(t) = 9.00tî + t2ĵ - t2 km.
A monatomic ideal gas expands slowly to twice its original volume, doing 370 j of work in the process. part a find the heat added to the gas if the process is isothermal.
Answers
[tex]\Delta U = Q-W[/tex]
The variation of internal energy of a gas is:
[tex]\Delta U = \frac{3}{2} n R \Delta T [/tex]
As it can be seen, it depends only on the variation of temperature [tex]\Delta T[/tex]. Since for an isothermal process [tex]\Delta T=0[/tex], then [tex]\Delta U=0[/tex]. This means that the first law of thermodynamics becomes
[tex]Q=W[/tex]
and since the work done is 370 J, then the amount of heat is also 370 J: [tex]Q=370 J[/tex].
What is most likely to happen to light that hits an opaque object?
A. All of the light passes through the object.
B. None of the light passes through the object.
C. Most of the light disappears.
D. Some of the light passes through the object.
Answers
C is not correct because the light is actually reflected off of an opaque object.
When the light hits an opaque object, none of the light will pass through the object. Hence, option B is correct.
What is light?Electromagnetic radiation that the human eye can detect as light. From radio waves with wavelengths measured in meters to gamma rays with wavelengths shorter than roughly 1 1011 meter, electromagnetic radiation occurs throughout a very broad range of wavelengths.
The wavelengths of light that are visible to humans fall into a very small range within that wide spectrum, ranging from about 700 nanometers for red light to roughly 400 nm for violet light.
Infrared and ultraviolet are two spectral bands that are close to the visible region and are repeatedly alluded to as light as well.
Anything that doesn't let any light through is opaque. Instances of opaque materials include concrete, wood, and metal.
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ampere. What is the resistance of the radio A radio operating at 3.0 volts and a constant temperature draws a current of 1.8 x 10 -4 circuit?
Answers
The resistance of the radio circuit is 16.7 kΩ.
To calculate the resistance of the radio circuit when it operates at 3.0 volts and draws a current of 1.8 x 10-4 amperes, we can use Ohm's Law, which states that Resistance (R) equals Voltage (V) divided by Current (I), or R = V/I. Plugging in the given values, R = 3.0 V / (1.8 x 10-4 A), we find that the resistance is approximately 16,666.67 Ω, or 16.7 kΩ when rounded to three significant digits. When dealing with electrical circuits, it is important to understand concepts like resistance, voltage, and current, as they are fundamental to analyzing and predicting the behavior of the circuit.
The top of the pool table is 0.810 m from the floor. the placement of the tape is such that 0 m is aligned with the edge of the table (as shown). the winner of the competition wants to know if he has broken the world record for the break shot of 32 mph (about 14.3 m/s). if the winner\'s ball landed a distance 4.65 m from the table edge, calculate his break shot speed.
Answers
y = gt²/2
0.810 m = (9.81 m/s²)(t)²/2
t = 0.4064 s
whereas the horizontal motion is computed by:
x = (vx)t
4.65 m = (vx)(0.4064 s)
4.65 m/ 0.4064s = (vx)
(vx) = 11.44 m / s
So look for the final vertical speed.
(vy) = gt
(vy) = (9.81 m/s²)(0.4064 s)
(vy) = 3.99 m/s
speed with which it hit the ground:
v = sqrt[(vx)² + (vy)²]
v = sqrt[(11.44 m/s)² + (3.99 m/s)²]
v = 12.12 m / s
You make a u turn in your car, what provides the centripetal force on the car and on you
Answers
The correct answer is the frictional force.
In fact, the centripetal force is the force that keeps the car in circular motion, and it points toward the centre of the circular trajectory. The frictional force between the tyres of the car and the road provides the centripetal force that keeps the car in the turn: in fact, without the friction (e.g. on an icy road), the car would not be able to make the turn at the same speed.
Two large parallel conducting plates are 17 cm apart and have charges of equal magnitude and opposite sign on their facing surfaces. an electrostatic force of 2.9 ✕ 10-15 n acts on an electron placed anywhere between the two plate (neglect fringing). (a) find the electric field at the position of the electron.
Answers
[tex]F=qE[/tex]
where E is the electric field's intensity.
In our problem, the particle is an electron, so its charge is [tex]q=e=-1.6 \cdot 10^{-19}C[/tex]. We know the intensity of the force, so we can find the magnitude of the electric field at the point where the electron is located:
[tex]E= \frac{F}{q}= \frac{2.9\cdot 10^{-15}N}{-1.6 \cdot 10^{19}C}=-1.8 \cdot 10^4 N/C [/tex]
where the negative sign means that the force and the electric field have opposite direction, because the charge is negative.
A ferris wheel of radius r speeds up with angular acceleration α starting from rest. part a find an expression for the velocity of a rider after the ferris wheel has rotated through angle δθ.
Answers
[tex]\alpha = \frac{\Delta \omega}{\Delta t} [/tex]
where [tex]\Delta \omega = \omega-\omega _0[/tex] is the variation of the angular velocity, with [tex]\omega _0[/tex] being the starting velocity (which in our problem is zero), and [tex]\Delta t[/tex] being the time interval. So we can write the angular velocity after an angle [tex]\delta \theta[/tex] as
[tex]\omega (\delta \theta) = \alpha \Delta t[/tex]
We also know the relationship between tangential velocity, v, and the angular velocity v:
[tex]v=\omega r[/tex]
with r being the radius of the wheel. Substituting [tex]\omega[/tex] into the previous equation, we can write an expression for v:
[tex]v(\delta \theta )= \alpha r \Delta t [/tex]
The expression for the velocity of a rider on the Ferris wheel after it has rotated through an angle [tex]\( \delta \theta \)[/tex] is given by:
[tex]\[ v = r \sqrt{2 \alpha \delta \theta} \][/tex]
To find the expression for the velocity of a rider after the Ferris wheel has rotated through an angle [tex]\( \delta \theta \)[/tex], we can use kinematic equations for rotational motion.
The kinematic equation relating angular displacement [tex](\( \delta \theta \))[/tex], initial angular velocity [tex](\( \omega_0 \))[/tex], angular acceleration [tex](\( \alpha \))[/tex], and time [tex](\( t \))[/tex] is:
[tex]\[ \delta \theta = \omega_0 t + \frac{1}{2} \alpha t^2 \][/tex]
Since the Ferris wheel starts from rest, [tex]\( \omega_0 = 0 \)[/tex], so the equation simplifies to:
[tex]\[ \delta \theta = \frac{1}{2} \alpha t^2 \][/tex]
We're interested in finding the angular velocity [tex](\( \omega \))[/tex] after the Ferris wheel has rotated through an angle [tex]\( \delta \theta \)[/tex]. To find [tex]\( \omega \)[/tex], we can use the kinematic equation relating angular displacement, initial angular velocity, angular acceleration, and final angular velocity:
[tex]\[ \omega^2 = \omega_0^2 + 2 \alpha \delta \theta \][/tex]
Since [tex]\( \omega_0 = 0 \)[/tex], this equation simplifies to:
[tex]\[ \omega^2 = 2 \alpha \delta \theta \][/tex]
Taking the square root of both sides:
[tex]\[ \omega = \sqrt{2 \alpha \delta \theta} \][/tex]
This gives us the angular velocity of the Ferris wheel after it has rotated through an angle [tex]\( \delta \theta \)[/tex].
However, to find the velocity of a rider at a particular point on the Ferris wheel, we need to convert this angular velocity to linear velocity. The linear velocity [tex](\( v \))[/tex] is related to the angular velocity [tex](\( \omega \))[/tex] by the equation:
[tex]\[ v = r \omega \][/tex]
Where:
- v is the linear velocity.
- r is the radius of the Ferris wheel.
So, substituting the expression for [tex]\( \omega \)[/tex] into this equation:
[tex]\[ v = r \sqrt{2 \alpha \delta \theta} \][/tex]
This is the expression for the velocity of a rider after the Ferris wheel has rotated through an angle [tex]\( \delta \theta \)[/tex].
A large jet flying overhead is low enough so that a man on the ground can hear its engines. The man sees the jet before he hears the engines because
Answers
Which phrase best describes matter? A. Matter is made of atoms and is too small to see. B. Matter is solid and heavy. C. Matter has mass and takes up space. D. Matter has volume and takes up space.
Answers
Hopes it helped you.
-Charlie
The absolute pressure below the surface of a freshwater lake is 3.51 x 10^5 Pa. At what depth does this pressure occur? Assume that atmospheric pressure is 1.01 x 10^5 Pa. and the density of the water is 1.00 x 10^3 kg/m^3
Answers
[tex] P_{total} = P_{atm} + (rgh)[/tex]
Where: [tex] P_{total} [/tex] = Absolute pressure
[tex] P_{atm} [/tex] = atmospheric pressure
r = density
g = [tex] 9.8 \frac{m}{{s^2}} [/tex]
h = depth
We can use this formula to derive our formula for h:
[tex] P_{total} = P_{atm} + (rgh)[/tex] transpose atmospheric pressure
[tex] P_{total} - P_{atm} [/tex] = [tex](rgh)[/tex] transpose r and g
[tex] P_{total} [/tex] - [tex] P_{atm} [/tex]
------------------------- = h
rg
Now let us input our given into our new formula:
3.52 x [tex] 10^{5}[/tex] - 1.01 x [tex] 10^{5}[/tex]
---------------------------------------- = h
1.00 x [tex] 10^{3} [/tex] x 9.8 [tex] \frac{m}{ s^{2} } [/tex]
[tex] \frac{2.51 x {10^5}}{9.8 x {10^3} \frac{m}{s^2}} = h [/tex]
[tex] 25.61 m = h [/tex]
The depth at which the pressure below the surface of a freshwater lake is 3.51 x 10^5 Pa is 24.29 meters.
Explanation:The depth at which the pressure below the surface of a freshwater lake is 3.51 x 10^5 Pa can be calculated using the formula:
Pressure = atmospheric pressure + density of water * gravitational acceleration * depth
In this case, the atmospheric pressure is 1.01 x 10^5 Pa, the density of water is 1.00 x 10^3 kg/m^3, and the gravitational acceleration is 9.8 m/s^2. We can rearrange the equation to solve for depth:
Depth = (pressure - atmospheric pressure) / (density of water * gravitational acceleration)
Plugging in the values, we get:
Depth = (3.51 x 10^5 Pa - 1.01 x 10^5 Pa) / (1.00 x 10^3 kg/m^3 * 9.8 m/s^2)
Depth = 24.29 meters
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Determine the tension developed in the cable ab required to support the traffic light, which has a mass of 19 kg . take h = 3.5 m.
Answers
Final answer:
The tension in the cable AB required to support the traffic light with a mass of 19 kg is equal to the weight of the traffic light, calculated as 186.2 N by multiplying the mass by the acceleration due to gravity.
Explanation:
To determine the tension in the cable AB required to support the traffic light with a mass of 19 kg, we need to use the concept that the tension must balance the weight of the traffic light. Since the traffic light is in equilibrium (not moving), the net force acting on it must be zero.
The weight of the traffic light (W) can be calculated using the formula W = m × g, where m is the mass of the traffic light and g is the acceleration due to gravity (which is approximately 9.8 m/s2 on the surface of the Earth).
Calculating the weight: W = 19 kg × 9.8 m/s2 = 186.2 N.
Now, since we are dealing with a situation where only one cable is mentioned and there are no angles provided, we assume the cable is vertical, and therefore, the tension in cable AB is simply the weight of the traffic light, which is 186.2 N.
Maglev trains, like the one shown in the picture, use magnet fields to travel up to 600 miles per hour. Magnets on the bottom of the train and on the tops of the rails have similar magnetic poles. Based on properties of magnets, how do these magnets affect the train?
Answers
In fact, magnets with same polarity repel each other. So, the magnets on the tops of the rails repel the magnets on the botton of the train: this repulsive force is strong enough to win the weight of the train, and the train levitates in air. As a consequence, the frictional forces acting on the train are very small compared to the forces experienced by normal trains (that should win the frictional forces of the railway), and therefore this Maglev train can reach a huge speed.
the 2 magnetic fields repel eachother
You are walking in the forest and see a bear. According to the Cannon-Bard theory, what happens next?
Answers
for the whole quiz of intro to psychology ;)
1. Stimulus--> Physiological changes--> emotion
2. Darwin
3.You experience physiological changes and a feeling of fear simultaneously
4. Cannon-Bard theory
5. James-Lange theory
6. David G. Myers
7. Happiness
8. Acting happy
9. negative and dysfunctional aspects of emotion and behavior.
10. an aspect of consciousness characterized by a certain physical arousal involving facial and bodily changes, brain activation, and tendencies toward action, all shaped by cultural rules.
I do this cause i wished someone did this for me. So stress no more from falling behind and Ace that quiz. your welcome comrades
-10/11/18
According to the Cannon-Bard theory, physiological changes and the feeling of fear occur simultaneously.
What is Cannon-Bard theory?The Cannon–Bard theory is also called the thalamic theory of emotion which is related to the thalamus. It is a part of the brain that deals with sensory and motor functions. The main concepts of this theory are that emotional expression arises from the function of hypothalamic structures while emotional feeling arises from stimulation of the dorsal thalamus.
This theory states that the lower part of the brain controls the experience of emotion while the upper part of the brain, called the cortex, controls the expression of emotion. These two parts of the brain react together
In this theory, stimulating events trigger emotions and physiological responses that occur at the same time. For example, seeing a bear in the woods can cause both a feeling of fear (an emotional response) and a faster heartbeat (a physical response).
Thus, according to the Cannon-Bard theory, physiological changes and the feeling of fear occur simultaneously.
Learn more about Cannon-Bard theory, here:
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what are the inner planets relative distance from the Sun
Answers
There are two types of planets as classifieds by astronomers in our solar system.
The classification is based on the asteroid belt present in our solar system.
These are named as - [1] inner planets
[2]outer planets
The inner planets are the planets which are very close to the sun and present before the asteroid belt starting from sun.
The outer planets which are present after the asteroid belt are Jupiter,Uranus,Neptune and Pluto[if we consider Pluto as a planet]
There are four planets considered as inner planets. These are arranged from closest to the farthest as Mercury,Venus,Earth ad Mars.
The distance of Mercury from the sun is 57.91 million km
The distance of Venus from sun is 108.2 million km
The distance of Earth from sun is 149.6 million km
Finally the distance of Mars from the sun is 227.9 million km
What must the charge (sign and magnitude) of a particle of mass 1.42 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 610 n/c ? use 9.81 m/s2 for the magnitude of the acceleration due to gravity. view available hint(s)?
Answers
In order to keep the particle in equilibrium, F must point upward. The direction of F depends on the sign of the charge. The electric field's direction is downward, so if we want F to point upward, the charge q must have negative sign.
Then, to find the magnitude of the charge, we should require that the intensity of the two forces acting on the particle is equal:
[tex]mg=qE[/tex]
from which we find q:
[tex]q= \frac{mg}{E} = \frac{(1.42 \cdot 10^{-3}kg)(9.81 m/s^2)}{610 N/C}=2.28 \cdot 10^{-5}C [/tex]
Two identical charges are separated by a distance d. If the distance between them is increased to 3d, what will happen to the force of repulsion between them? A) It will be one-ninth the original force. B) It will be one-third the original force. C) It will be nine times the original force. D) It will be three times the original force.
Answers
Answer:
A
Explanation:
If the distance between them is increased to 3d then the force of repulsion between them is, It will be one-ninth the original force
What is electric force ?The force of repulsion between two identical charges is given by Coulomb's law, which states that the force between two charges is proportional to the product of the charges and inversely proportional to the square of the distance between them. Mathematically, it can be expressed as:
F = k x (q₁ x q₂) / d²
where F is the force of repulsion, q₁ and q₂ are the magnitudes of the charges, d is the distance between the charges, and k is the Coulomb constant.
When the distance between the charges is increased to 3d,
the force of repulsion will decrease,
since the denominator in the above equation will increase.
Specifically, the force will become one-ninth the original force, since the square of 3 is 9.
So the answer to the question is (A) It will be one-ninth the original force.
To know more about electric force check:
https://brainly.com/question/29141236
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