Final answer:
To calculate the tangential speed, total acceleration, and angular position of point P on the wheel at t = 2.00 s, we can use the formulas for tangential speed, total acceleration, and angular position. By substituting the given values into these equations, we can find the required values.
Explanation:
To calculate the tangential speed of a point on the wheel, we can use the formula:
Tangential Speed = Angular Velocity x Radius
In this case, the angular velocity is given by the equation:
Angular Velocity = Initial Angular Velocity + (Angular Acceleration x Time)
Substituting the given values and solving the equations, we can find the tangential speed, which is the speed of the point P on the rim at time t = 2.00 s.
To find the total acceleration, we can use the formula:
Total Acceleration = Tangential Acceleration + Radial Acceleration
The tangential acceleration can be calculated using the equation:
Tangential Acceleration = Angular Acceleration x Radius
The radial acceleration can be calculated using the equation:
Radial Acceleration = (Angular Velocity x Angular Velocity) x Radius
By substituting the given values into these equations, we can find the total acceleration at time t = 2.00 s.
To find the angular position of point P at time t = 2.00 s, we can use the equation:
Angular Position = Initial Angular Position + (Initial Angular Velocity x Time) + (0.5 x Angular Acceleration x Time x Time)
Substituting the given values, we can find the angular position of point P at t = 2.00 s.
Coulomb's law and the universal law of gravity describe different forces in similar ways. Which of these are factors that both have in common
Coulomb's law and the universal law of gravity both have inverse-square relationships, involve a proportionality constant, and describe forces between two objects.
Explanation:The factors that Coulomb's law and the universal law of gravity have in common are:
Both laws are inverse-square laws. This means that the force between two objects decreases with the square of the distance between them.Both laws involve a proportionality constant. In Coulomb's law, it is the constant 'k', also known as Coulomb's constant. In Newton's law of universal gravitation, it is the constant 'G', also known as the gravitational constant.Both laws describe forces between two objects. Coulomb's law describes the electrostatic force between charged objects, while the universal law of gravity describes the gravitational force between two masses.A horizontal spring is lying on a frictionless surface. One end of the spring is attaches to a wall while the other end is connected to a movable object. The spring and object are compressed by 0.080 m, released from rest, and subsequently oscillate back and forth with an angular frequency of 12.1 rad/s. What is the speed of the object at the instant when the spring is stretched by 0.041 m relative to its unstrained length
Final answer:
To determine the speed of an object attached to a horizontally lying spring on a frictionless surface at a specific stretch, we apply the law of conservation of energy and calculate the distribution of potential and kinetic energy at that point.
Explanation:
The subject of this question is Physics, and it involves a concept known as simple harmonic motion(SHM). To find the speed of the object at the instant when the spring is stretched by 0.041 m relative to its unstrained length, we can use the law of conservation of energy. In SHM, the total mechanical energy (sum of potential and kinetic energy) is conserved if there is no energy loss due to friction or other non-conservative forces.
At the compressed position (0.080 m from equilibrium), all the energy is potential, given by Ep = 1/2 k x2, where k is the spring constant and x is the displacement from equilibrium. At the position where the spring is stretched by 0.041 m, the energy will be partly potential and partly kinetic. The potential energy at this point is Ep = 1/2 k (0.041 m)2 and the kinetic energy is Ek = 1/2 m v2, where m is the mass and v is the velocity of the object.
Conservation of energy gives us:
1/2 k (0.080 m)2 = 1/2 k (0.041 m)2 + 1/2 m v2.
We can solve this equation for v, the speed at 0.041 m stretch, knowing the values of k, m, and x.
Two uniform cylinders have different masses and different rotational inertias. They simultaneously start from rest at the top of an inclined plane and roll without sliding down the plane. The cylinder that gets to the bottom first is: A) the one with the larger mass B) the one with the smaller mass C) the one with the larger rotational inertia D) the one with the smaller rotational inertia E) neither (they arrive together)
Option (E) is correct
Neither (they arrive together)
Explanation:
Neither of the cylinders gets to the bottom first, they both will arrive together. Every object can gain speed with time if it is pushed, it is called the acceleration of that object. It the acceleration that decides which object reaches the bottom first.
Acceleration = I / mr^2.
In the case of both the cylinders, the acceleration will be the same, with the same acceleration they will reach the bottom at the same time.
The purpose of a cell (battery) is to: Question 2 options: store chemical energy and transfer it to thermal energy when a circuit is connected. store chemical energy only when a circuit is connected. store chemical energy and transfer it to electrical energy when a circuit is connected. release chemical energy and absorb thermal energy when a circuit is connected.
Answer:
Store chemical energy and transfer it to electrical energy when a circuit is connected.
Explanation:
A battery (single cell) is a container made of one cell that can produce a particular amount of electrical energy when needed.
It works by converting chemical energy to electric energy which is then used as a power source.
It stores up chemical energy and when connected to an external circuit, it provides electrical energy (through the flow of electrical current) to the circuit.
A battery is usually made up of a positive electrode and a negative electrode.
The speed of a light wave in a certain transparent material is 0.701 times its speed in vacuum, which is 3.00×108 m/s . When yellow light with a frequency of 5.23×1014 Hz passes through this material, what is its wavelength ???? in nanometers?
Answer:
402 nm
Explanation:
First, we find the speed of light in this medium:
v = 0.701 * c
v = 0.701 * 3 * 10^8
v = 2.103 * 10^8 m/s
Speed of a wave is given as the product of wavelength and frequency:
v = λf
Where λ = wavelength
Wavelength, λ, becomes:
λ = v/f
The frequency of the light is 5.23 * 10^14 Hz, therefore, wavelength will be:
λ = (2.103 * 10^8) / (5.23 * 10^14)
λ = 4.02 * 10^(-7) m = 402 nm
The wavelength of the light is 402 nm.
Technician A says that if the yellow warning lamp is illuminated indicating a fault in the electronic brake control system, you should retrieve the diagnostic trouble codes and follow the procedure listed in the service information. Technician B says that once the fault has been corrected, clear the diagnostic code and verify that it does not reset. Who is correct?
A)A only
B)B only
C)Both A and B
D)Neither A nor B
Answer: C) Both A and B
Explanation:
The ABS system is disabled when the ABS yellow warning lamp is on. And when the warning lamp is on the base brake system will work normally but without ABS function
And if the yellow warning lamp is illuminated indicating a fault in the electronic brake control system, you should retrieve the diagnostic trouble codes and follow the procedure listed in the service information. Once the fault has been corrected, clear the diagnostic code and verify that it does not reset
Which two kinds of energy are associated with flames?
Answer: Light and thermal (heat) energy.
Explanation: Flames give off heat and light.
Answer:
Light and thermal (heat) energy are the two kinds of energy associated with flames
Explanation:
The magnitude of the electric field at a distance of two meters from a negative point charge is E. What is the magnitude of the electric field at the same location if the magnitude of the charge is doubled.
Answer:
[tex]E_n = \frac{kQ}{2} = 2E[/tex]
If the charge is doubled, the electric field is also doubled.
Explanation:
Electric field due to the negative charge is given as:
[tex]E = \frac{kQ}{r^2}[/tex]
where k = Coulomb's constant
Q = electric charge
r = distance between charge and point of consideration
At 2 m from the negative charge, the magnitude of the Electric field due to a negative charge -Q is given as E:
[tex]E = |\frac{-kQ}{2^2}| \\\\\\E = \frac{kQ}{4}[/tex]
If the charge is doubled, the new charge becomes -2Q and the new electric field becomes:
[tex]E_n = |\frac{-2kQ}{4}| \\\\\\E_n = |\frac{-kQ}{2}|[/tex]
[tex]E_n = \frac{kQ}{2} = 2E[/tex]
If the charge is doubled, the electric field is also doubled.
Answer:
E'=(1/4)E
Explanation:
The magnitude of the electric force is given by:
[tex]E=k\frac{q}{r^2}[/tex]
where k is the Coulomb constant (8.89*10^{9}Nm^2/C^2).
When the distance is r=2m we have:
[tex]E=k\frac{q}{(2m)^2}=k\frac{q}{4m^2}[/tex]
when the distance is doubled we obtain:
[tex]E'=k\frac{q}{(4m)^2}=k\frac{q}{16m^2}=\frac{1}{4}k\frac{q}{4m^2}=\frac{1}{4}E[/tex]
Hence, the new electric field is a quarter of the first electric field.
hope this helps!
A balloon is rising vertically above a level, straight road at a constant rate of 4 ft divided by sec4 ft/sec. Just when the balloon is 7272 ft above the ground, a bicycle moving at a constant rate of 1212 ft divided by secft/sec passes under it. How fast is the distance s (t )s(t) between the bicycle and balloon increasing 66 seconds later?
Answer:
12.27 ft/s
Explanation:
At 72 ft above the ground, the balloons height increases at a rate of 4ft/s. For 66s, vertical distance moved, y = 4ft/s × 66 s = 264 ft. When the balloon is at 72 ft above the ground, just below it, the bicycle which moves at a rate of 12 ft/s in 66 s, covers a horizontal distance, x = 12ft/s 66 = 792 ft.
The distance between the bicycle and the balloon 66 s later is given by
s = √(x² + (y + 72)²) = √(792² + (264 + 72)²) = √(792² + 336²) = √740160 ft = 860.33 ft
From calculus
The rate of change of the distance between the balloon and bicycle s is obtained by differentiating s with respect to t. So,
ds/dt = (1/s)(xdx/dt + ydy/dt)
dx/dt = 12 ft/s, x = 792 ft, dy/dt = 4 ft/s, y = 264 ft, s = 860.33. These are the values of the variables at t = 66 s.
So, substituting these values into ds/dt, we have
ds/dt = (1/860.33)(792 ft × 12 ft/s + 264 ft × 4ft/s) = (1/860.33)(9504 + 1056) = 10560/860.33 = 12.27 ft/s
Try to have the equipotential lines equally spaced in voltage. Then, use an E-Field Sensor to measure the electric field at a few points while looking at the relationship between the electric field and the equipotential lines.
Which of the following statements is true?
1.The electric field strength is greatest where the voltage is the smallest.
2.The electric field strength is greatest where the equipotential lines are very close to each other.
3.The electric field strength is greatest where the voltage is the greatest.
Answer:
2 The electric field strength is greatest where the equipotential lines are very close to each other.
Explanation:
Equipotential lines are contour lines which trace the lines of identical altitudes. In physics, they trace out lines of equal electric potential or voltage.
Equipotential lines are always perpendicular to the electric field. The closer the equipotential lines to each other, the greater the strength of the electric field.
At t=0 a grinding wheel has an angular velocity of 28.0 rad/s. It has a constant angular acceleration of 25.0 rad/s2 until a circuit breaker trips at time t = 1.90 s. From then on, it turns through an angle 436 rad as it coasts to a stop at constant angular acceleration.
(a) Through what total angle did the wheel turn between t= 0 and the time it stopped?
(b) At what time does the wheel stop?
(c)What was the wheel's angular acceleration as it slowed down? Express your answer in radians per second per second.
Answer:
(a) 534.324 rad
(b) 13.45 s
(c) -6.45 rad/s2
Explanation: Please see the attachments below
Final answer:
The grinding wheel's total angle of turn, time to stop, and angular acceleration are calculated using its initial angular velocity, time accelerated, and the angle it turned while coasting.
Explanation:
Calculating Angular Motion of a Grinding Wheel
A grinding wheel starts with an angular velocity of 28.0 rad/s and accelerates for 1.90 s at a constant angular acceleration of 25.0 rad/s2. After a circuit breaker trips, it coasts to a stop through 436 rad.
To find the total angle the wheel turns, calculate the angle turned during the acceleration phase and add the 436 rad it turns while coasting.
The time for the wheel to stop is found by calculating the time from start to when the circuit breaker trips plus the time it takes to coast to a stop.
The angular acceleration during the deceleration phase is determined using the kinematic equations of rotational motion.
A 1.0 m long piece of coaxial cable has a wire with a radius of 1.1 mm and a concentric conductor with inner radius 1.3 mm. The area between the cable and the conductor is filled with a dielectric. If the voltage drop across the capacitor is 6000 V when the line charge density is 8.8 μC/m, find the value of the dielectric constant. (k = 1/4πε₀ = 8.99 × 109 N · m²/C²)A) 4.8
B) 5.3
C) 4.4
D) 5.7
Answer:
C) 4.4
Explanation:
The potential of a cylindrical capacitor is given by the formula:
[tex]V=\frac{2kq}{L\epsilon}ln(\frac{a}{b})\\\\\epsilon=\frac{2kq}{LV}ln(\frac{a}{b})[/tex]
where:
k : Coulomb Constant
L : length of the capacitor
a : outer radius
b : inner radius
V : potential
By replacing we obtain:
[tex]\epsilon=\frac{2(8.89*10^{9}N/m^2C^2)(8.8*10^{-6}C)}{(1m)(6000V)}ln(\frac{1.3mm}{1.1mm})=4.35[/tex]
Hence, the answer is C) 4.4 (4.35 is approximately 4.4)
hope this helps!!
The electric potential inside a parallel-plate capacitor __________.
Answer:
[tex]\Delta V=\frac{Q d}{A \epsilon_0}[/tex]
Explanation:
for the calculation of the electric potential inside a parallel plate capacitor you can use the formula for the electric field inside the capacitor.
[tex]\Delta V=V(d)-V(0)=\int_0^dEdx[/tex]
where d is the distance between plates and E is the electric field, which is given by:
[tex]E=\frac{\sigma}{\epsilon_0}[/tex]
By replacing you obtain:
[tex]\Delta V=E\int_0^ddx=Ed=\frac{\sigma d}{\epsilon_0}=\frac{Qd}{A\epsilon_0}[/tex]
where Q is the charge stored by the capacitor and A is the area of the plates.
hence, the answer is Qd/Ae0
The electric potential inside a parallel-plate capacitor is directly proportional to the amount of charge on the capacitor.
Explanation:The electric potential inside a parallel-plate capacitor is directly proportional to the amount of charge on the capacitor. The magnitude of the electrical field between the plates is directly proportional to the charge, which means that the electric potential is also directly proportional to the charge.
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What is the electric potential energy of a charge that experiences a force of 3.6 × 10–4 N when it is 9.8 × 10–5 m from the source of the electric field?
Answer:
3.528×10⁻⁸ V.
Explanation:
Electric Potential: This can be defined as the work done in an electric field in moving a unit charge from infinity to any point. The S.I unit of electric potential is Volt (V) or J/C.
From the question,
V = Fd................ Equation 1
Where V = Electric Potential, F = force experienced by the charge, d = distance.
Given: F = 3.6×10⁻⁴ N, d = 9.8×10⁻⁵ m.
Substitute into equation 1
V = 3.6×10⁻⁴( 9.8×10⁻⁵)
V = 3.528×10⁻⁸ V.
What is true in every balanced chemical equation?
A. Mass has to be conserved.
B. The reaction does not give off any energy.
C. All coefficients have to be an even number.
D. Atoms are created when products are formed.
Answer:
B
Explanation:
Changing the direction of current flow, will or will not affect the strength of an electromagnet? Pick one: Will or Will Not
Answer:
Will not.
Explanation:
just got the question correct.
Answer:
will not .
Explanation:
A 375-g stone hangs from a thin light string that is wrapped around the circumference of a pulley with a moment of inertia of 0.0125 kg ∙ m2 and a radius of 26 cm. When the stone is released, the stone accelerates downward and the pulley rotates about its axis as the string unwinds. What is the magnitude of the acceleration of the stone in m/s2 ?
Answer:
The magnitude of the acceleration of the stone is 19.87 m/s²
Explanation:
Given;
mass of stone, m = 375 g = 0.375 kg
moment of inertia, I = 0.0125 kg.m²
radius of the pulley, r = 26 cm = 0.26 m
Torque generated by the pulley on the stone is given as;
τ = F x r = Iα
where;
F is applied force on the stone due to its weight
r is the radius of the pulley
I is moment of inertia
α is angular acceleration (rad/s²)
Force, F = mg = 0.375 x 9.8 = 3.675 N
Torque, τ = F x r
τ = 3.675 x 0.26
τ = 0.9555 N.m
τ = Iα
Angular acceleration, α = τ / I
α = 0.9555 / 0.0125
α = 76.44 rad/s²
Finally, determine linear acceleration, a, in m/s²
a = αr
a = 76.44 x 0.26
a = 19.87 m/s²
Therefore, the magnitude of the acceleration of the stone is 19.87 m/s²
The stone's acceleration, calculated using Newton's second law for rotational and linear systems, and the relationship between linear and angular acceleration for a non-slip condition, is 3.53 m/s².
Explanation:To determine the magnitude of the acceleration of the stone, we need to apply Newton's second law for rotational and linear systems. Specifically, we should set up equations for torque and force.
1. Sum of forces in the vertical direction (y-axis): T - mg = ma, where T is the tension in the string, m is the mass of the stone (0.375 kg), g is the acceleration due to gravity (9.81 m/s²), and a is the linear acceleration of the stone.
2. Sum of torques about the pulley's axis: τ = Iα, where I is the moment of inertia of the pulley (0.0125 kg · m²), α is the angular acceleration, and τ is the torque due to the tension (T·r, with r being the radius of the pulley).
Because the string unwinds without slipping, we have a relationship between linear and angular acceleration: a = αr.
Combining the equations, we can solve for the acceleration 'a' of the stone:
T = Iα/r = Ia/r²
So, T - mg = ma becomes:
Ia/r² - mg = ma
And by solving for 'a', we get:
a = (mg)/(m + I/r²)
Substituting the given values:
a = (0.375 kg × 9.81 m/s²)/(0.375 kg + 0.0125 kg m²/ (0.26 m)²) = 3.53 m/s²
Thus, the stone's acceleration is 3.53 m/s².
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Most people can detect frequencies as high as 20 000 Hz. Assuming the speed of sound in air is 345 m/s, determine the wavelength of the sound corresponding to this upper range of audible hearing.
Wavelength = speed / frequency
(345 m/s) / (20,000 Hz) = 0.017 m
Formula to solve for the wavelength: w = s/f
w = wavelength
s = speed
f = frequency
Solve using the given values.
w = 345/20000
w = 0.01725
Round if necessary.
0.0173
Therefore, the wavelength is approximately 0.0173 meters.
Best of Luck!
Why are metals good conductors of both heat and electricity?
Answer:
The outer shell electrons in metals are free to move from atom to atln
Explanation:
An electron is accelerated from rest by a potential difference of 412 V. It then enters a uniform magnetic field of magnitude 188 mT with its velocity perpendicular to the field. Calculate (a) the speed of the electron and (b) the radius of its path in the magnetic field.
Explanation:
Given that,
Potential difference, V = 412 V
Magnitude of magnetic field, B = 188 mT
(a) The potential energy of electron is balanced by its kinetic energy as :
[tex]eV=\dfrac{1}{2}mv^2[/tex]
v is speed of the electron
[tex]v=\sqrt{\dfrac{2eV}{m}} \\\\v=\sqrt{\dfrac{2\times 1.6\times 10^{-19}\times 412}{9.1\times 10^{-31}}} \\\\v=1.2\times 10^7\ m/s[/tex]
(b) When the charged particle moves in magnetic field, it will move in circular path. The radius of the circular path is given by :
[tex]r=\dfrac{mv}{eB}\\\\r=\dfrac{9.1\times 10^{-31}\times 1.2\times 10^7}{1.6\times 10^{-19}\times 188\times 10^{-3}}\\\\r=3.63\times 10^{-4}\ m[/tex]
Hence, this is the required solution.
The specialized capillary bed responsible for the pressure that drives filtration is the
Answer: GLOMERULUS
Explanation:
The specialized capillary bed responsible for the pressure that drives filtration is the
GLOMERULUS.
The kidney is an organ responsible for the excretion of nitrogenous wastes from the human body and osmoregulation of the blood and body fluids. The structure which is responsible for formation of urine is the nephron( kidney tubule). The GLOMERULUS are found within the Bowman's capsule of the nephrons. It is made up of specialised bundle of capillary beds which are the only capillary beds that are not surrounded by interstitial fluid in the body. In the glomerulus, blood pressure is high because an arteriole enters and exists the capillary beds which is responsible for the pressure that drives filtration.
The glomerulus, a specialized capillary bed in the kidney nephrons, creates pressure driving filtration, a process important for maintaining body homeostasis.
Explanation:The specialized capillary bed responsible for the pressure that drives filtration is the glomerulus. This structure, located within the nephrons of the kidney, creates a pressure high enough to force substances such as water, glucose, and electrolytes out of the blood and into the nephron tubule, beginning the process of urine formation. The glomerular filtration process is an essential part of maintaining bodily homeostasis, i.e., keeping a stable internal environment in the body.
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Which description best explains a molecular bonding?
Donates electrons
Shares electrons
Charged ions attract
Occurs between metals
Answer:
Shares electrons
A village maintains a large tank with an open top, containing water for emergencies. The water can drain from the tank through a hose of diameter 6.60 cm. The hose ends with a nozzle of diameter 2.20 cm. A rubber stopper is inserted into the nozzle. The water level in the tank is kept 7.50 m above the nozzle. (a) Calculate the friction force exerted on the stopper by the nozzle. (b) The stopper is removed. What mass of water flows from the nozzle in 2.00 h
Answer:
(A) Frictional force will be equal to 27.92 N
(B) Mass is equal to 33120 kg
Explanation:
(A) Diameter of nozzle d = 2.20 cm
So radius [tex]r=\frac{d}{2}=\frac{2.20}{2}=1.10cm[/tex]
eight h = 7.5 m
Density of water [tex]\rho =1000kg/m^3[/tex]
Acceleration due to gravity [tex]g=9.8m/sec^2[/tex]
Pressure on the rubber stopper
[tex]P=\rho hg[/tex]
[tex]p=1000\times 7.5\times 9.8=73500Pa[/tex]
Area of cross section [tex]A=\pi r^2[/tex]
[tex]A=3.14\times 0.01^2=3.799\times 10^{-4}m^2[/tex]
So force [tex]F=PA[/tex]
[tex]F=73500\times 3.799\times 10^{-4}=27.92N[/tex]
(B) Speed of the water through nozzle
[tex]v=\sqrt{2gh}[/tex]
[tex]=\sqrt{2\times 9.8\times 7.5}=12.12m/sec[/tex]
Volume of water flow
[tex]V=vA=12.12\times 3.799\times 10^{-4}=0.0046m^3/sec[/tex]
Mass of water flow per sec
[tex]m=\rho V=1000\times 0.0046=4.6kg[/tex]
Total time t = 2 hour = 2×3600 = 7200 sec
So total mass flow
[tex]m=4.6\times 7200=33120kg[/tex]
To calculate the friction force exerted on the stopper by the nozzle, use Bernoulli's equation for fluid flow. To calculate the mass of water that flows from the nozzle, use the equation Q = A * V.
Explanation:To calculate the friction force exerted on the stopper by the nozzle, we can use Bernoulli's equation for fluid flow. The pressure at the top of the tank is atmospheric pressure, and the pressure at the nozzle is also atmospheric pressure. The friction force can be calculated by the equation F = P * A, where P is the pressure difference and A is the cross-sectional area of the stopper.
First, calculate the pressure difference between the top of the tank and the nozzle using the equation P = ρ * g * h, where ρ is the density of water, g is the acceleration due to gravity, and h is the height difference.Next, calculate the cross-sectional area of the stopper using the equation A = π * (r^2), where r is the radius of the stopper.Finally, multiply the pressure difference by the cross-sectional area to calculate the friction force exerted on the stopper.To calculate the mass of water that flows from the nozzle in 2.00 hours, we can use the equation Q = A * V, where Q is the volumetric flow rate, A is the cross-sectional area of the nozzle, and V is the velocity of the water.
First, calculate the cross-sectional area of the nozzle using the equation A = π * (r^2), where r is the radius of the nozzle.Next, calculate the volumetric flow rate using the equation Q = A * V.Finally, multiply the volumetric flow rate by the time to calculate the mass of water that flows from the nozzle in 2.00 hours.Learn more about Fluid Flow here:https://brainly.com/question/34457794
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"The smallest insects that a bat can detect are approximately the size of one wavelength of the sound the bat makes. What is the minimum frequency of sound waves required for a bat to detect an insect that is 0.0057 m long? (assume the speed of sound is 340 m/s.)"
Answer:
Frequency, f = 59.6 kHz
Explanation:
Given that,
Speed of sound, v = 340 m/s
The bat can detect an insect that is 0.0057 m long, [tex]\lambda=0.0057\ m[/tex]
We need to find the minimum frequency of sound waves required for a bat to detect an insect. The speed of a wave is given by :
[tex]v=f\lambda\\\\f=\dfrac{v}{\lambda}\\\\f=\dfrac{340\ m/s}{0.0057\ m}\\\\f=59649.12\ Hz[/tex]
or
f = 59.6 kHz
So, the frequency detected by the bat is 59.6 kHz.
The minimum required frequency of the sound wave is 59.65 kHz
Determining frequency:Given information:
speed of sound, v = 340 m/s
the wavelength of insect that the bat can detect, λ = 0.0057 m
The wavelength, frequency, and speed are related as follows:
v = fλ
The minimum frequency of sound wave required is:
f = v/λ
where f is the frequency of the sound
f = 340/0.0057 s⁻¹
f = 59649 Hz
or,
f = 59.65 kHz
So the frequency comes out to be 59.65 kHz
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What would you be most likely to find if you returned to the solar system in 10 billion years?
Answer:
a white dwarf
Explanation:
A white dwarf, is otherwise known as a degenerate dwarf, it is a stellar core remnant which is mostly composed of electron-degenerate matter. A white dwarf is very dense, and has a mass which is comparable to that of the Sun, while its volume is comparable to that of Earth. It faint luminosity comes from the emission of stored heat energy; and no fusion takes place in a white dwarf
In 10 billion years, the solar system would be unrecognisable. The Sun would have become a white dwarf after expanding as a red giant.
If you returned to the solar system in 10 billion years, you'd likely find a vastly different environment from today. Given the current understanding of stellar evolution, the Sun, which is currently a main-sequence star, would have exited this phase. After going through a red giant phase, where it would have engulfed the inner planets, the Sun would have lost most of its outer material, leaving behind a white dwarf. This white dwarf would eventually cool and fade over time, becoming a black dwarf. Surrounding planetary bodies might be destroyed, transformed, or ejected from the solar system altogether due to the Sun's changes and the gravitational influences of other celestial bodies over such a vast period.
In this older universe, new star systems may have formed within the Milky Way from the abundant materials available in the galaxy. However, it's challenging to predict the exact state of the solar system due to numerous factors including potential asteroid impacts, close encounters with passing stars, or even interactions with interstellar objects. One thing is certain: the solar system as we know it will have undergone significant changes.
How many times does lightning strike the empire state building
Answer:
Lightning strikes the empire state building at an average of about 23 times a year.
Explanation:
The Empire State Building is one of the tallest buildings in New York. Because of how high it stretches up into the sky, lightning strikes are quite common to it. This is because part of the building touches the clouds which are usually charged during thunder storms.
According to weather reports, and the Empire State Building website, lightning strikes the empire state building about 23 times a year on the average.
Which kind of storm do you think would cause damage over a larger area A cyclone or a tornado why
Answer:
becuase it is big
Explanation:
Which sentences describe the advantage of using a hydrogen fuel cell instead of burning fossil fuels?
A. The reaction of hydrogen and oxygen conveniently takes place inside a fuel cell.
B. The combustion reaction of hydrogen and oxygen has very low efficiency.
C. Someday, it may be possible to produce hydrogen fuel using sunlight and water.
D. The reaction of hydrogen and oxygen doesn’t create products that negatively affect the environment.
Answer:
A C and D
Explanation:
Answer:
A C D
Explanation:
Two people are sitting on playground swings. One is pulled back 4 degrees from the vertical and the other is pulled back 8 degrees. They are both released at the same instant. Will they both come back to their starting points at the same time
Answer:
They will come back at the same time.
Explanation:
The angular velocity equation of ω[tex]= \frac{V}{r}[/tex] where ω is the frequency of the movement, dependent on the angle. But since swings are simple pendulums and their angles of 8 and 4 degrees are small, they will come back to their starting points at the same time.
I hope this answer helps.
Answer:
The bodies will not come back to their starting point at he same time.
Explanation:
Since they are both pulled back at an angle to the vertical, there is a tangential component of acceleration a = gsinθ
When θ = 4 , a = 9.8sin4 = 0.684 m/s²
When θ = 8 , a = 9.8sin8 = 1.364 m/s²
Using s = ut + 1/2at². Where s is the distance covered and t = time taken, u = initial speed = 0 (assumed since they are both released at the same time)
So s = 0 × t + 1/2at² = 1/2at²
s = 1/2at²
t = √2s/a. Now, since s is the same for both swings, it follows that
t ∝ 1/a. Since their accelerations are different, the bodies will not come back to their starting point at he same time.
An object that completes 100 vibrations in 5 seconds has a period of
Answer:
The answer of the question is None.
Answer:
Period is 1/20 of a second.
Explanation:
Frequency is 20 vibrations per second. Period and frequency are reciprocals (period = 1/f). Period is 1/20 of a second.